What theorem shows that l // m

False. if you are given a graph with two shif table lines, the correct answer will always require you to move both lines.

In a graph with two shiftable lines, the correct answer may or may not require moving both lines. It depends on the specific scenario and the desired outcome or conditions that need to be met.

When working with shiftable lines, shifting refers to changing the position of the lines on the graph by adjusting their slope or intercept. The purpose of shifting the lines is often to satisfy certain criteria or align them with specific points or patterns on the graph.

In some cases, achieving the desired outcome may only require shifting one of the lines. This can happen when one line already aligns with the desired points or pattern, and the other line can remain fixed. Moving both lines may not be necessary or could result in an undesired configuration.

However, there are also situations where both lines need to be shifted to achieve the desired result. This can occur when the relationship between the lines or the positioning of the lines relative to the graph requires adjustments to both lines.

Ultimately, the key is to carefully analyze the graph, understand the relationship between the lines, and identify the specific criteria or conditions that need to be met. This analysis will guide the decision of whether one or both lines should be shifted to obtain the correct answer.

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Answer:

  D.  0.391

Step-by-step explanation:

You want the approximate solution to f(x) = x² -3x +1 = 0 on the interval [0, 1] using 5 iterations of the Bisection Method.

The Bisection Method makes one iteration by finding the function value at the midpoint of the interval. The midpoint replaces the end of the interval whose function value has the same sign. At the end of one iteration, the midpoint of the halved interval is calculated.

Start:

  f(0) = 1, f(1) = -1. Interval: [0, 1]; midpoint: 1/2

First iteration:

  f(1/2) < 0. Interval: [0, 1/2]; midpoint: 1/4

Second iteration:

  f(1/4) > 0. Interval: [1/4, 1/2]; midpoint: 3/8

Third iteration:

  f(3/8) > 0. Interval: [3/8, 1/2]; midpoint: 7/16

Fourth iteration:

  f(7/16) < 0. Interval: [3/8, 7/16]; midpoint: 13/32

Fifth iteration:

  f(13/32) < 0. Interval: [3/8, 13/32]; midpoint: 25/64

The approximate solution after 5 iterations is x ≈ 25/64 ≈ 0.391.

__

Additional comments

The approximate solution in the interval to full calculator precision is 0.38196601125. The exact solution is 1.5-√1.25.

You will notice that the function values for the ends of the interval [0, 1] are [positive, negative]. So, when the function value at the midpoint is negative, that point replaces the right end of the interval.

Of course, the midpoint is the average of the interval end values.

On average, it takes about 3.3 iterations to improve the accuracy of the solution by 1 decimal place.

These standardization methods are crucial in chromatography to ensure accurate quantification and comparability of results.

In chromatography, standardization methods are used to ensure accurate and reliable results by establishing reference points or calibration standards. Here are three common methods of standardization in chromatography: External Standardization: In this method, a set of known standard samples with known concentrations or properties is prepared separately from the sample being analyzed. These standards are then analyzed using the same chromatographic conditions as the sample. By comparing the response of the sample to that of the standards, the concentration or properties of the sample can be determined. Internal Standardization: This method involves the addition of a known compound (internal standard) to both the standard solutions and the sample. The internal standard should ideally have similar properties to the analyte of interest but be different enough to be easily distinguished. The response of the internal standard is used as a reference to correct for variations in sample preparation, injection volume, and instrumental response. Internal standardization helps improve the accuracy and precision of the analysis. Standard Addition: This method is useful when the matrix of the sample interferes with the analysis or when the analyte concentration is unknown. It involves adding known amounts of the analyte of interest to different aliquots of the sample. The response of the analyte is then measured, and the concentration is determined by comparing the response with that of the standards. The difference in response between the sample and the standards allows for the determination of the analyte concentration in the original sample.

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Answer:

The mother is 56 years old while her son is 8 years old

Step-by-step explanation:

Let x be the age of the mother

Let y be the age of her son

A mother is currently 7 times older than her son

x = 7y  -------equation 1

In 4 years time, she will be 5 times older than her son

In 4 years, their ages will be

x + 4 ------mother

y + 4 ------son

x + 4 = 5(y+4)

x + 4 = 5y + 20    ----equation 2

Substitute equation 1 to equation 2

7y + 4 = 5y + 20

Transpose

7y - 5y = 20 - 4

2y = 16

y = 16/2

y = 8

Substitute y = 8 to equation 1

x = 7y

x= 7(8)

x = 56

Answer:

b

Step-by-step explanation:

Answer:

The fraction converted into percentage is .68.96551724%

Answer:

68.97%

Step-by-step explanation:

\(\frac{20}{29}*100 = 68.9655172414%\)

You can round up 68.9655172414% into 68.97% for a simpler answer.

I hope this helps you! :D

Answer:

V = 235.5

or V = 75π

Step-by-step explanation:

V=πr^2h

Volume of a cylinder is (pi)(radius)(radius)(height)

V = (3.14)(5)(5)(3)

V = 235.5

Or, since it said you can leave it as pi,

V = 75π

Please let me know if you have questions.

The five friends should pay $21.54 for the meal plus a 20% tip.

Your question seems incomplete; it might be:

Five friends plan to split a restaurant bill evenly. The cost of the meal is about $89.75, and they want to leave a 20% tip. What amount should each friend pay?

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Answer:

\(1\frac{1}{5}\)

~~~~~~~~~~~

4 ÷ 3\(\frac{1}{3}\)

4 ÷ \(\frac{10}{3}\)

4* \(\frac{3}{10}\)

\(\frac{12}{10}\)

\(1\frac{1}{5}\)

Step-by-step explanation:

Answer:

Look at attachment

Step-by-step explanation:

The percentage discount Ryan is offering is 34%.

The percentage increase in passenger travel is 125%.

The sales for the new year is $147,510.

Janice's loss if she cancels one round trip is $41.25.

The number of cancellations that can be expected is 7.

Percent discount = (change in price of round trip / price of a round trip before discount) x 100

Percent discount = ($85 / $250) X 100 = 34%

Percent increase = (change in number of passengers / initial passengers) x 100

(900 - 400) / 400 x 100 = 125%

The sales for the new year = penalty fare for those who cancelled + total revenue from those who do not cancel.

Penalty fare for those who cancelled = 9/10 ( 0.01 x 900) = 8 people would cancel

25/100 x 8 x $165 = $330

Total revenue from those who do not cancel = (900 - 8) X $165 = $147,180

The sales for the new year = $147,180 + $330 = $147,510

Loss = 25/100 x $165 = $41.25

8 - 1 = 7

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Answer:

20.39

Step-by-step explanation:

15% of 29.99 is 4.4985

so

29.99-4.5

=

25.49

subtract the 20%

20% of 25.49

=

5.1

lastly,

25.49-5.1

=

20.39

the left-endpoint sum using four subintervals for the function f(x) = -11 on the interval [4, 5] is -2.75.

To compute the left-endpoint sum using n subintervals, we partition the interval [4, 5] into n equal subintervals of length Δx = (5-4)/n = 1/n. Then, we evaluate the function at the left endpoint of each subinterval and multiply by the width of the subinterval, and finally sum up these values.

For the function f(x) = -11 on [4, 5], we have:

Δx = 1/n

x0 = 4

xi = x0 + iΔx = 4 + i/n, for i = 1, 2, ..., n.

The left endpoint of each subinterval is xi-1, so we have:

L_n = Δx [ f(x0) + f(x1) + ... + f(x_{n-1}) ]

 = Δx [ f(4) + f(4 + 1/n) + f(4 + 2/n) + ... + f(4 + (n-1)/n) ]

 = (1/n) [ -11 + (-11) + ... + (-11) ]   (there are n terms)

 = -11/n

To find L4, we plug in n=4 into the formula we just derived:

L4 = -11/4 = -2.75 (rounded to four decimal places)

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The side is the longest if these are the measures of the angles is AC .

Given :

m∠a = 60°, m∠b = ( 3x − 2 )°, m∠c = ( 2x + 7 )°

First, let's find m∠B and m∠C by solving for x. Since the sum of interior angles in a triangle is 180°, we know that:

60 + 3x - 2 + 2x + 7 = 180

5x + 65 = 180

5x = 115

x = 23° so m∠B = 3(23) - 2 = 67° and m∠C = 2(23) + 7 = 53°. The longest side of a triangle is always opposite to the largest angle of the triangle, and since m∠B is the largest, we know that the side opposite to ∠B is the longest. That side is AC.

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Answer:

1) 8%

2)230%

3)34%

4)105%

5)70%

6)4.9%

Answer:

8%, 230%, 34%, 105%, 70%, 4.9%

Step-by-step explanation:

basically hundredths place is the ones place of a percentage. that is how you figure everything out.

Can I be Brainliest? TYSM

Answer:

0

Step-by-step explanation:

3,000 - 3,000 = 0

Answer:

x = 18/5

Step-by-step explanation:

-5/6 x=-3

Multiply each side by -6/5

-6/5 *-5/6 x=-3*-6/5

x = 18/5

Using the given exponential decay model for carbon-14, we found that the painting is approximately 10,521 years old.

What is meant by exponential functions?

A mathematical function called an exponential function is employed frequently in everyday life. It is generally used to find exponential decay or exponential growth. When the input variable x appears as an exponent in the formula f(x) = axe, an exponential function is indicated. When there is exponential growth, the quantity grows initially extremely slowly and subsequently quickly. Throughout time, the rate of change quickens. As time goes on, the rate of increase accelerates. With exponential decay, the quantity initially falls very quickly and then gradually. Throughout time, the rate of change slows. As time goes on, change happens at a slower rate.

The exponential decay model for carbon-14 is given as:

\(A = A_0e^{(-0.000121t)}\)

where,

A = Percentage remaining

A₀ = Initial amount

t = Time in years

Given,

A = 28% of A₀ = 0.28A₀

Substituting in the above exponential decay model,

\(A = A_0e^{(-0.000121t)}\\\\0.28A_0 = A_0e^{(-0.000121t)}\\\\0.28 = e^{(-0.000121t)}\\\\\)

ln 0.28 = -0.000121t

-1.273 =  -0.000121t

t = 10,520.66 years = 10,521 years

Therefore using the given exponential decay model for carbon-14, we found that the painting is approximately 10,521 years old.

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Answer: 8

Step-by-step explanation:

16 centimeters of tape for 4 presents = 4 centimeters of tape per present.

Since he used 32 centimeters of tape, he wrapped a total of 8 presents.

Answer:

8

Step-by-step explanation:

Explanation:

Step 1. We have a piecewise function defined for certain x value intervals.

for x values between -4 and -1, the definition is:

To graph this, we compare it with the general line function

where m is the slope (the rate of change of the line) and b is the y-intercept. In this case, for f(x)=x+6, the slope is m=1, and the y-intercept is 6, if we were to graph this line in the whole plane, it would look as follows:

But since this is just the definition of the function for the values between -4 and -1, the result is:

Step 3. Now we consider the second definition of the function:

Comparing it with the general line function

where m is the slope (the rate of change of the line) and b is the y-intercept.

Here in f(x)=-2x+7, the slope is m=-2, and the y-intercept is b=7, which means that the line is decreasing at a rate of -2, and that it crosses the y-axis at 7.

If we were to graph this line in the whole plane, it will look as follows (in blue):

But since that is the definition of the function only for the interval from -1 to 5, we only consider the line for that specific x-interval, we represent the point at -1 with an open circle and at 5 with a filled circle to represent that 5 is included in the segment:

Answer:

Hi there!  

»»————-　★　————-««

I believe your answer is:  

\(h =\frac{A}{b}\)

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

\(\boxed{\text{Solving for 'h'...}}\\\\A=bh\\----------\\\rightarrow bh = A\\\\\rightarrow \frac{bh=A}{b}\\\\\rightarrow \boxed{h=\frac{A}{b}}\)

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

The simplified expressions of those given in the problem with the angles in radians and degrees have been calculated:

e)cos(-57° + a) + tan(97° - a) - sin(67° - a) = (√3 + 1)/2 cos(a) + (√3 - 1)/2 sin(a) + tan(97π/180 - a)

d)cos(n + a) - sin " - a) + cos(3n - a) = 1/2

b)tan(80° - a) x cos(150°) = tan(80° - a) x cos(30°) = [tan(80° - a) x sin(30°)] / sin(30°) = [tan(80° - a) x (1/2)] / (1/2)   = 2 tan(80° - a)

c)cos(450° + a) x sin(-a) - tan(a - 180°) + sin(a + 180°) = -sin²(a) - tan(a) + sin(a)

bjcos(-270° + a) + tan(900° - a)  = sin(a) - 2 sin(90° + n)   = sin(a) + 2 cos(n)

Expression e)cos(-57° + a) + tan(97° - a) - sin(67° - a)

Here, 1° = π/180 radian

Putting the values, we get:

cos(-57° + a) = cos(-57π/180 + a) = cos(a - π/3) = cos(a) cos(π/3) + sin(a) sin(π/3)   = 1/2 cos(a) + √3/2 sin(a) (As cos(π/3) = 1/2 and sin(π/3) = √3/2)

Now, tan(97° - a) = tan(97π/180 - a)sin(67° - a) = sin(67π/180 - a) = sin(π/3 - a) = sin(π/3) cos(a) - cos(π/3) sin(a)   = √3/2 cos(a) - 1/2 sin(a) (As cos(π/3) = 1/2 and sin(π/3) = √3/2)cos(-57° + a) + tan(97° - a) - sin(67° - a) = [1/2 cos(a) + √3/2 sin(a)] + tan(97π/180 - a) - [√3/2 cos(a) - 1/2 sin(a)]   = cos(a)/2 + √3/2 sin(a) + tan(97π/180 - a) + √3/2 cos(a) - 1/2 sin(a)   = (√3 + 1)/2 cos(a) + (√3 - 1)/2 sin(a) + tan(97π/180 - a)

Expression d)cos(n + a) - sin " - a) + cos(3n - a)

Here, 1° = π/180 radian

Putting the values, we get:

cos(n + a) - sin " - a) + cos(3n - a) = cos(n) cos(a) - sin(n) sin(a) - cos(a) sin(a) + cos(3n) cos(a) + sin(3n) sin(a)   = [cos(n) + cos(3n)] cos(a) - [sin(n) + sin(3n)] sin(a) - cos(a) sin(a)cos(1200) - sin(-240°) = cos(1200 × π/180) - sin(-240 × π/180) = -1/2 - (-1/2) = 0Now, sin(450°) + cos(900°) = sin(450 × π/180) + cos(900 × π/180) = 1/2 + 0 = 1/2

Expression b)tan(80° - a) x cos(150°) = tan(80° - a) x cos(30°) = [tan(80° - a) x sin(30°)] / sin(30°) = [tan(80° - a) x (1/2)] / (1/2)   = 2 tan(80° - a)

Expression c)cos(450° + a) x sin(-a) - tan(a - 180°) + sin(a + 180°)

Here, 1° = π/180 radian

Putting the values, we get:

cos(450° + a) x sin(-a) - tan(a - 180°) + sin(a + 180°) = [cos(450π/180 + a) x sin(-a)] - tan(aπ/180 - π) + sin(aπ/180 + π)   = [-sin(a) x sin(-a)] - tan(aπ/180 - π) + sin(aπ/180 + π)   = -sin²(a) + tan(aπ/180 + π) + sin(aπ/180) = -sin²(a) - tan(a) + sin(a)

Expression bjcos(-270° + a) + tan(900° - a)

Here, 1° = π/180 radian

Putting the values, we get:

cos(-270° + a) = cos(-270π/180 + a) = sin(a)tan(900° - a) = tan(900π/180 - a) = -tan(a)cos(-270° + a) + tan(900° - a) = sin(a) - tan(a)

Now, cos(90° + a) - sin(180° - n) + cos(540° - n)

Here, 1° = π/180 radian

Putting the values, we get:

cos(90° + a) - sin(180° - n) + cos(540° - n) = sin(a) - sin(π - n) + cos(3π - n)   = sin(a) + sin(n) + cos(n) = sin(a) + (cos(90° - n) - cos(90° + n))   = sin(a) - 2 sin(90° + n)   = sin(a) + 2 cos(n)

Therefore, the given simplified expressions with the angles in radians and degrees have been calculated.

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Zion earn $5025 on a deposit of 10,000 for one year at 5.12% compounded daily.

The formula for daily compounding is :

A = P * \((1 + r/n)^{nt}\)

Principal P =  10,000

Rate of interest r = 5.12%

Time t = 1 years.

number of times compounded n = 365 days.

So,

A = 10,000 * \((1 + 0.0512/365)^{365*1}\)

A = 10,000 * 1.5025

A = 15,025

Interest = A - P

Interest = 15,025 - 10,000

Interest = 5025

Thus, the Zion earn $5025 on a deposit of 10,000 for one year at 5.12% compounded daily.

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Answer:

500

Step-by-step explanation:

If you subtract 10000, 3000, 40, and 2 it would become 500.

Answer:

CORRECT AMONDO

Step-by-step explanation:

Answer:

Rearrange [1] to get an expression for

x

[

3

]

XXXXX

x

=

3

+

3

y

Substitute the expression for

x

from [3] into [2]

[

4

]

XXXXX

2

(

3

+

3

y

)

+

9

y

=

11

Simplify

[

5

]

XXXXX

6

+

6

y

+

9

y

=

11

[

6

]

XXXXX

15

y

=

5

[

7

]

XXXXX

y

=

1

3

Substitute the value of

y

from [7] into [1]

[

8

]

XXXXX

x

−

3

(

1

3

)

=

3

Simplify

[

9

]

XXXXX

x

=

4

The solution is

(

x

,

y

)

=

(

4

,

1

3

)

Step-by-step explanation:

To identify the center, foci, vertices, co-vertices, and lengths of the semi-major and semi-minor axes of an ellipse given its equation, convert the equation to standard form, determine the alignment, and apply the relevant formulas.

To identify the center, foci, vertices, co-vertices, and lengths of the semi-major and semi-minor axes of an ellipse given its equation, follow these steps:

Rewrite the equation of the ellipse in the standard form: ((x-h)^2/a^2) + ((y-k)^2/b^2) = 1 or ((x-h)^2/b^2) + ((y-k)^2/a^2) = 1, where (h, k) represents the center of the ellipse.

Compare the denominators of x and y terms in the standard form equation: if a^2 is the larger denominator, the ellipse is horizontally aligned; if b^2 is the larger denominator, the ellipse is vertically aligned.

The center of the ellipse is given by the coordinates (h, k) in the standard form equation.

The semi-major axis 'a' is the square root of the larger denominator in the standard form equation, and the semi-minor axis 'b' is the square root of the smaller denominator.

To find the vertices, add and subtract 'a' from the x-coordinate of the center for a horizontally aligned ellipse, or from the y-coordinate of the center for a vertically aligned ellipse. The resulting points will be the vertices of the ellipse.

To find the co-vertices, add and subtract 'b' from the y-coordinate of the center for a horizontally aligned ellipse, or from the x-coordinate of the center for a vertically aligned ellipse. The resulting points will be the co-vertices of the ellipse.

The distance from the center to each focus is given by 'c', where c^2 = a^2 - b^2. For a horizontally aligned ellipse, the foci lie at (h ± c, k), and for a vertically aligned ellipse, the foci lie at (h, k ± c).

The lengths of the semi-major axis and semi-minor axis are given by 2a and 2b, respectively.

By following these steps, you can identify the center, foci, vertices, co-vertices, and lengths of the semi-major and semi-minor axes of an ellipse given its equation.

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Given:

The expression is

\(9-3\div \dfrac{1}{3}+1\)

To find:

The value of given expression.

Solution:

We have,

\(9-3\div \dfrac{1}{3}+1\)

BODMAS : Bracket, Order, Division, Multiplication, Addition, and Subtraction.

Using BODMAS, first we need to perform division in the given expression.

\(=9-(3\div \dfrac{1}{3})+1\)

\(=9-(3\times 3)+1\)

\(=9-9+1\)

Now, apply addition.

\(=(9+1)-9\)

\(=10-9\)

Now, apply subtraction.

\(=1\)

Therefore, the value of given expression is 1.

Answer:

total area = 39.6 square units

Step-by-step explanation:

determine the inside angle

360 / 5 = 72°

half of the triangle = 36°

given:

adj = 3.3

Ф = 36°

length of the opp of a small triangle is = adj. tan Ф

opp = 3.3 * tan 36 = 2.4

area of a triangle = 1/2 b * h   x  2 tringles

area =( 1/2 * 2.4 * 3.3  ) * 2

area = 7.92  multiplied by 5 equal shapes

total area = 7.92 * 5

total area = 39.6 square units

hope this helps

mark me as a brill please

good luck

The total area of the regular polygon should be considered as the 39.6 square units.

But before that following things should be calculated

first determine the inside angle i.e.

\(= 360 / 5\)

= 72°

Now

half of the triangle = 36°

Since

adj = 3.3

Ф = 36°

So,

opp =\(3.3 * tan 36\) = 2.4

Now

area of a triangle =\(1/2 b * h * 2\)

\(=( 1/2 * 2.4 * 3.3 ) * 2\\\\= 7.92 * 5\)

= 39.6 square units

hence, The total area of the regular polygon should be considered as the 39.6 square units.

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The function that gives the amount Fred pays as income tax are

$30,000 > x ≥ $22,000 ⇒ $6,000

x ≥ $30,000 ⇒ (x - 30 000)$0.5 + $6000

If Fred pays $6 000 in state income taxes for the first $22 000. this means that when Fred makes up to $22 000 he pays $6 000.

The amount paid as tax in this period is $6 000

When Fred's earns up to $30 000 he pays $0.5 for every additional dollar he made

In the first case his earning is within $30 000 and $22 000 this is when Fred pays only $6 000

$30,000 > x ≥ $22,000 ⇒ $6,000

The second case, Fred earns above $30 000 the tax goes to extra earnings in the amount of $0.5 for every extra earnings.

The extra earning = (x - 30 000)

the tax on extra earning = (x - 30 000)0.5

then add the initial tax for making up to $22 000

(x - $30 000)0.5 + $6000

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