what tranports oxygen into the cells?​

The electron configuration of the fifth and sixth transition elements in universe L may be slight different than as it is on earth.

The electron configuration shows the distribution of electrons in atoms. In atoms electrons are distributed in orbitals. Different orbitals hold different maximum number of electrons in them.

On earth, the d orbitals are five but in universe L, the d orbitals are six. This implies that d orbitals in universe L can hold a total of twelve electrons.

The fifth transition metal is Manganese. The electron configuration of manganese in universe L is [Ar] 3d6 4s1. The  sixth transition element is iron. The electron configuration of iron in universe L is [Ar] 3d6 4s2.

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Answer:

See explanation below

Explanation:

Let's answer this by parts.

a) As the reaction is naturally exothermic (Exerts heat), increasing temperature means that the reaction will move forward the direction where its absorbing heat

, so the equilibrium will be favored to the reactant side.

b) In this case, the addition of CO, which is a reactant will favor the reaction to the product side. This is because putting more quantity in the reactants will cause that the equilibrium constant K, increase it's innitial value, and this favors the product side.

c) In this case, it happens something similar to case b. This will cause that the reaction will have to work to cover the loss of methanol, therefore, equilibrium will move to the product side too.

d) In this case, we are adding another substance that reacts with CO, so it means that the other reactant is being removed, therefore, the reaction will work to cover this loss but also to cover the adding of the new substance, causing that the K decrease it's value, so equilibrium will be favored to the reactants side.

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Answer:

During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.

The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.

Answer:

Explanation:

like this...Identify oxidation and reduction with their agents:

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The concentration of the CaCl2 would be 0.143 M

Using the dilution equation:

M1V1 = M2V2

That is, the number of moles of solutes in a solution before dilution must be equal to the number of moles of solutes in the solution after dilution.

In this case,

M1 = 0.250, V1 = 100 mL, M2 = ? V2 = 100 + 75 = 175 mL

M2 = M1V1/V2

             = 0.250 x 100/175

                  = 0.143 M

Thus, the diluted solution must have a molarity of 0.143 M

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The amount of heat required to raise the temperature of the 34.2 g sample of aluminum by 34 oC is 1043.52 J.

What is Temperature?

Temperature is a measure of the average kinetic energy of the particles in a substance. It is a physical property that determines the direction of heat flow between two objects or systems in contact with each other. Temperature is measured in degrees Celsius (°C) or Fahrenheit (°F), or in kelvin (K) in the International System of Units (SI).

The amount of heat (q) required to raise the temperature of a substance can be calculated using the formula:

q = m x c x ΔT

Where:

m = mass of the substance (in grams)

c = specific heat of the substance (in J/g oC)

ΔT = change in temperature (in oC)

Plugging in the values given:

m = 34.2 g

c = 0.9 J/g oC

ΔT = 34 oC

q = (34.2 g) x (0.9 J/g oC) x (34 oC)

q = 1043.52 J

Therefore, the amount of heat required to raise the temperature of the 34.2 g sample of aluminum by 34 oC is 1043.52 J.

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Answer:

Position isomerism in C 5 H 11 Br : In the case of C 5 H 11 Br , there are three position isomers namely, Bromopentane, Bromopentane, and Bromopentane.

Explanation:

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This question is incomplete, the complete question is;

You want to plate a steel part having a surface area of 240 in² with a 0.002-in thick layer of silver.

The atomic mass of silver is 107.868 g/mol .

The density of silver is 10.49 g/cm³.

How many atoms of silver are required?

Answer:

4.6 × 10²³ atoms of silver are required

Explanation:

Given the data in the question;

first, we determine the volume of silver layer  

volume of silver layer = surface area × thickness

we substitute

volume of silver layer =  240 in² × 0.002-in = 0.48 in³

we know that 1 in³ = 16.387 cm³

so, volume of silver layer  = 0.48 × 16.387 = 7.87 cm³

Next we calculate mass of silver;

⇒ density × Volume

mass of silver = 10.49 g/cm³ × 7.87 cm³ = 82.5563 g

Now, number of atoms of silver are required will be;

Number of atoms = (mass/atomic mass) × Avogadro number

we know that A.v no. is 6.02214 × 10²³ mol⁻¹

so

Number of atoms = (82.5563 g / 107.868 g/mol . ) × 6.02214 × 10²³ mol⁻¹

= 0.7653 × 6.02214 × 10²³

= 4.6 × 10²³ atoms

Therefore; 4.6 × 10²³ atoms of silver are required

For multiplication and division operations, we perform the operations normally, and the final result must be written with the same number of significant figures as the factor that has the fewest significant figures.

0.34 x 0.568 = 0.19312

The result obtained in the above multiplication must be rounded to two significant figures, which correspond to the number of significant figures of the number 0.34. Therefore, we must round the result, giving as answer 0.19.

Answer: 0.19

Answer:

Explanation:

Here, we want to talk about the heat being trapped by greenhouse gases such as carbon iv oxide.

The sun is the primary source of heat and energy to the earth. The heat from the sun once it hits the earth would be absorbed while part of this heat would also be returned into the atmosphere.

This heat returned into the atmosphere is meant to be evenly distributed among the layers of the atmosphere. However, because of these greenhouse gases, the heat is retained and thus causes global warming.

Also, human activities also release heat into the atmosphere which causes an increase in global warming as this heat can be trapped

Answer:

Two positive aspects of using methane recapture systems are able to generate significant electricity. Another benefit is that the process of anaerobic digestion creates heat that can be used to warm buildings where animals are kept

Answer:  The correct answer is;

Two positive aspects of using methane recapture systems include lowering the impact on greenhouse gasses and the production of energy. Methane is a very potent greenhouse gas that is contributing to global warming. As a result, the recapturing process reduces the methane impacts of global warming by reclaiming and reusing the gas for other purposes. Recaptured methane can be stored and used to generate electricity or used as fuel to power updated vehicles and other engines on the farm. The overall benefits from this combination are reducing impacts causing global warming and lower the cost of electricity or fuel on the farm.

Explanation:  This answer has been confirmed correct.

Answer:

bromine

Explanation:

Answer:

The scientist is observing an intensive property of a superconductor.

Explanation:

An intensive property is a bulk property of matter. This means that an intensive property does not depend on the amount of substance present in the material under study. Typical examples of intensive properties include; conductivity, resistivity, density, hardness, etc.

An extensive property is a property that depends on the amount of substance present in a sample. Extensive properties depend on the quantity of matter present in the sample under study. Examples of extensive properties include, mass and volume.

Resistance of a superconducting material has nothing to do with the amount of the material present hence it is an intensive property of the superconductor.

Answer:

The scientist is observing an intensive property of a superconductor.

Explanation:

its the only one that makes logical sense

Answer:

4 NH3(0) + 3 O2(g) → 2 N2(g) + 6H20() ... How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below.

Missing: 6 ‎H₂O( ‎l)​

Explanation:

Answer:

In this reaction, Ca(OH)2 is a reducing agent. It reacts with hydrogen chloride to form calcium chloride and water. Therefore, the following reaction shows that matter is neither created nor destroyed in a chemical reaction: Ca(OH)2 + 2HCI -> CaCl2 + 2H20. The formation of calcium chloride and water from the hydrolysis of calcium hydroxide is not an example of matter being created or destroyed in a chemical reaction because it does not involve the breaking down of any bonds between atoms.

Explanation:

The standard deviation of the sample is 0.579, rounded to the correct number of significant figures.

To calculate the standard deviation of the sample, we need to follow these steps:

To find the mean, we sum up all the data points and divide by the number of data points. Let's calculate it:

(3.09 + 4 + 2.775 + 2.5 + 3.80) / 5 = 16.165 / 5 = 3.233

To do this, we subtract the mean (3.233) from each data point and square the result:

(3.09 - 3.233)^2 = 0.020049

(4 - 3.233)^2 = 0.586489

(2.775 - 3.233)^2 = 0.209025

(2.5 - 3.233)^2 = 0.537289

(3.80 - 3.233)^2 = 0.323329

To find the variance, we sum up the squared differences from step 2 and divide by the number of data points:

(0.020049 + 0.586489 + 0.209025 + 0.537289 + 0.323329) / 5 = 1.676181 / 5 = 0.3352362

√0.3352362 = 0.579 (rounded to three significant figures)

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Answer:

The correct solution is "3.535 × 1018 molecules".

Explanation:

The given values are:

Molar mass

= 322.0 g/mol

Dioxin constitute to 63 kg individual will be:

= \(0.03 \ mg\times 63\)

= \(1.89 \ mg\)

⇒  \(mole=\frac{mass}{molar \ mass}\)

             \(=\frac{ 1.89\times 10^{-3}}{322}\)

             \(=5.87\times 10^{-6} \ mol\)

So,

The number of molecules will be:

= \(mole\times Na\)

= \(5.87\times 10^{-6}\times 6.022\times 1023\)

= \(3.535\times 1018\) (molecules)

Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes.

Sediment refers to any material that is transported and deposited by water, wind, ice, or gravity. Sediments can be composed of various materials, such as minerals, rocks, organic matter, and even human-made debris.

Sediments can accumulate in different environments, such as rivers, lakes, oceans, and deserts, and can be deposited in layers over time.

Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes. If it has primarily formed through sediment deposition, it is more appropriate to classify it as sediment.

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The volume of the gas at STP would be 23.93 liters.

The volume of gas at STP (Standard Temperature and Pressure), we need to use the Ideal Gas Law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature. First, we need to calculate the number of moles of gas in the initial sample. We can use the formula n = PV/RT, where P is the initial pressure, V is the initial volume, R is the gas constant, and T is the initial temperature.
n = (2.31 atm) x (25.15 L) / [(0.0821 L atm/mol K) x (201 + 273.15 K)]
n = 1.067 moles

Now, we can use the molar volume of gas at STP, which is 22.4 L/mol, to calculate the volume of gas at STP.
V = n x 22.4 L/mol
V = 1.067 moles x 22.4 L/mol
V = 23.93 L
Therefore, the volume of the gas at STP would be 23.93 liters.

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Answer:

A hydrocarbon

Explanation:

The molar mass of the sugar is obtained as  1.43 g/mol.

We know that the boiling point of a substance is one of the properties of the substances that could be called the colligative properties since they can be affected by the number of particles present.

We are told that the mass concentration of the substances w/w of the solution is 17% thus we have 17 g of the compound and 83 g of water. We can now get the number of moles of the substance as;

Number of moles = ?

Mass of the solution = 1000 mL * 1.015 g/mL = 1015 g or 1.015 Kg

Given that;

ΔT = K m i

ΔT = Boiling point elevation

K = Boing constant of water

m = molality of the solution

i = Van't Hoff factor

ΔT = 106 °C - 100°C

= 6 °C

Then;

6 = 0.515 *  17/MM * 1/1.015 * 1

Where MM = molar mass of the sugar

6 = 0.515 * 17/1.015 MM * 1

6 = 0.515 * 17/1.015 MM

6 = 8.755/1.015 MM

6 * 1.015 MM =  8.755

MM =  8.755/6 * 1.015

MM = 1.43 g/mol

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Answer:

The molar density of any ideal gas at STP is:

1 mol / 22.4 L = 0.04464 mol / L

The molar mass of F2 is: 2(19) = 38 g/mol

0.04464 mol / L * (38 g / mol) = 1.70 g/L

Explanation:

Answer:

E) Al³⁺

Explanation:

A reaction involving a gain of electrons is known as a reduction reaction because the oxidation number of the species gaining the electron is reduced.

In the given question, the oxidation number (charge) of particle accepting two electrons will decrease by 2. From the given options;

A. K is a neutral atom with oxidation number of 0. If is accepts two electrons, its oxidation number becomes -2.

K + 2e⁻  ----> K⁻²

B) Fe²⁺ has a charge of +2. If it accepts two electrons, its charge comes 0.

Fe⁺ + 2e⁻  ----> Fe

C) O²⁻ has a charge of -2. if it accepts two electrons, it will have a charge of -4.

O²⁻ + 2e⁻  ---->  O⁴⁻

D) Ne has a charge of zero. If it accepts two electrons, its charge becomes -2.

Ne + 2e⁻   ---->   Ne²⁻

E) Al³⁺ has a charge of +3. If it gains two electrons, its charge becomes +1.

Al³⁺ + 2e⁻   ---->   Al⁺

Answer:

Electrons

Explanation:

A) Ethanol is the Limiting reactant

B) 5.36 grams

The chemical reaction for the chemical combustion of ethanol is expressed as:

Determine the mass of ethanol

Mass of ethanol = density * volume

Mass of ethanol =0.789 * 5.8

Mass of ethanol = 4.58 grams

Determine the mass of Oxygen

Mass of Oxygen = 12.5 grams

Determine the mole of ethanol and oxygen

For the mole of oxygen

Since the mole of ethanol is lower than that of oxygen, hence the limiting reactant is ethanol

Part B: According to stoichiometry, 1mole of ethanol produces 3 moles of water, the mole of water required will be expressed as:

Therefore the theoretical yield of H2O is 5.36grams

Answer:

Object 1 = Moving Towards Earth

Object 2 = Moving Away From Earth

Object 3 = Moving Towards Earth

Explanation:

When you look at emission spectras, look at where the observed lines are in comparison to the element (stationary) lines. Ones that have observed lines closer to the left are moving towards you and ones with observed lines closer to the right are moving away from you.

Answer:

Empirical formula of a compound means that it provides simplest ratio of whole number.

Explanation:

Mass of boron and chlorine is 9.224% and 90.74%

The question is incomplete, here is the complete question:

Consider the following intermediate reactions.

\(CH_4(g)+2O_2\rightarrow CO_2(g)+2H_2O(g);\Delta H_1=-802kJ\)

The overall chemical reaction is as follows:

\(CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(I);\Delta H_{rxn}=-890kJ\)

What is the correct enthalpy diagram using the Hess law for this system? (Image is attached below)

Answer: The correct image is Image A.

Explanation:

According to Hess’s law of constant heat summation, the amount of heat absorbed or evolved in a given chemical equation or system remains the same whether the process occurs in one step or in several steps.

According to this law, the enthalpies of these chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to know the required equation.

It also means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given intermediate reactions are:

\(CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(l);\Delta H_1=-802kJ\)                 ...(1)

\(2H_2O(g)\rightarrow 2H_2O(l);\Delta H_2=-88kJ\)           ....(2)

The final reaction follows:

\(CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(l);\Delta H_{rxn}=-890kJ\)

Negative sign of the enthalpy represents the heat is being released which is represented by the downward arrow in the diagram.

By adding equation 1 and equation 2, we get:

\(\Delta H_{rxn}=\Delta H_1+\Delta H_2\\\\\Delta H_{rxn}=-802+(-88)=-890kJ\)

Hence, the correct image is image A.

Answer:

A

Explanation:

Edg