The two numbers which add to 6 and multiply to 58 are; 3+7i and 3-7i
Simultaneous equations;According to the question;
let the two numbers be; x and y.Hence;
x+ y = 6xy = 58x = 6-y which can the be be substituted into equation (ii) so that we have;(6-y)y = 58
6y -y² = 58
y² - 6y +58 = 0
By solving quadratically; we have;
y = 3 + 7i Or y = 3-7ix = 3 - 7i Or x = 3+7iRead more on complex roots;
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the number 1953125 is equal to 5^9
explain how the infomation above informs that 1953125 is not a square number
Step-by-step explanation:
Given
\(1953125=5^9\)
For a perfect square, its square root must be an integer
The square root of 1953125 i.e. \(\sqrt{1953125}=\sqrt{5^9}\)
or, \(\sqrt{5^9}=5^\frac{9}{2}\)
Clearly, \(\frac{9}{2}\) is not an integer so, \(5^{\frac{9}{2}}\) is also not an integer
Hence, 1953125 is not a square number
Find the dimensions of a rectangle (in m) with perimeter 84 m whose area is as large as possible. (Enter the dimensions as a comma-separated list.)
A. 14, 14 B. 12, 18 C. 10.5, 21 D. 7, 35
The rectangle with dimensions 21 m by 21 m has the largest area among rectangles with a perimeter of 84 m.
To find the dimensions of a rectangle with a perimeter of 84 m that maximizes the area, we need to use the properties of rectangles.
Let's assume the length of the rectangle is l and the width is w.
The perimeter of a rectangle is given by the formula: 2l + 2w = P, where P is the perimeter.
In this case, the perimeter is given as 84 m, so we can write the equation as: 2l + 2w = 84.
To maximize the area, we need to find the dimensions that satisfy this equation and give the largest possible value for the area. The area of a rectangle is given by the formula: A = lw.
Now we can solve the perimeter equation for l: 2l = 84 - 2w, which simplifies to l = 42 - w.
Substituting this expression for l into the area equation, we get: A = (42 - w)w.
To maximize the area, we can find the critical points by taking the derivative of the area equation with respect to w and setting it equal to zero:
dA/dw = 42 - 2w = 0.
Solving this equation, we find w = 21.
Substituting this value of w back into the equation l = 42 - w, we get l = 42 - 21 = 21.
Therefore, the dimensions of the rectangle that maximize the area are l = 21 m and w = 21 m.
In summary, the dimensions of the rectangle are 21 m by 21 m, so the answer is A. 21, 21.
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Some History teachers at Dayton High School are purchasing tickets for students and their adult chaperones to go on a field trip to a nearby museum. For her class, Mrs. Gruber bought 25 student tickets and 28 adult tickets, which cost a total of $984. Mr. Ellison spent $900, getting 25 student tickets and 25 adult tickets. What is the price for each type of ticket?
Answer:
Student Ticket: $8
Adult $28
Step-by-step explanation:
To find out the price of each ticket create 2 equations, then solve for x & y
x = student tickets
y = adult tickets
25x + 28y = 984
25x + 25y = 900
To do this first put x on one side of the equation
25x = 900 - 25y
x = 36 - y
Now substitute this equation in x for the first equation
25(36 - y) + 28y = 984
Now distribute 25 in 36 - y, 900 - 25y + 28y = 984
After this combine like term, then subtract 900 from each side, 3y = 84
Then divide 3 on each side, y = 28
Lastly substitute 28 for y in any equation to solve for x, x = 8
x & y are the price of each ticket
Find the value of x.
B
6
8
А
х
D
x = [?]
Answer:
What's the question is that a good thing
Answer: 3
Step-by-step explanation:
After its first day of life, a baby blue whale started growing. It grew 47.075 inches. If the average baby grows at a rate of 1,5 inches a day, for how many days did the baby whale grow, to the nearest tenth of a day.
Answer:
31 days
Step-by-step explanation:
what i did is divided it
Consider a regular hexagon centered at (3,4). Describe a rotation that
will map this regular hexagon onto itself.
Answer:
36- degree rotation m8
Step-by-step explanation:
mark me brainliest :)
Part 1 - Application
——
100 Points!!!!
——
Hikers walk 3 miles east and then 2 miles north and take a water break. They continue
hiking 4 miles east and a final 2 miles south to their destination. What single
transformation took place from their starting position to their final destination? Use
mathematical language and create a graphic to explain your answer. Be sure to use a
straight edge and grid paper for your graphic to represent this problem.
The single transformation that took place from their starting position to their final destination is (x, y) ⇒ (x + 7, y)
What is transformation?
Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.
Translation is the movement of a point either up, down, left or right in the coordinate plane.
Hikers walk 3 miles east and then 2 miles north and take a water break. Hence:
(x, y) ⇒ (x + 3, y + 2)
They continue hiking 4 miles east and a final 2 miles south to their destination:
(x, y) ⇒ (x + 3 + 4, y + 2 - 2) ⇒ (x + 7, y)
The single transformation that took place from their starting position to their final destination is (x, y) ⇒ (x + 7, y)
Let k ? R and f(x, y-x2 + y2 + kxy. If you imagine the graph changing as k increases, at what values of k does the shape of the graph change qualitatively? Justify your answer.
The shape of the graph changes qualitatively at k = ± 2 and
\(k=\sqrt{(2)\).
The given function is f(x,y) = y-x²+y²+kxy.
The critical points of the function are found by taking the partial derivatives and equating them to zero:
∂f/∂x = -2x + ky = 0
y = 2x/k
∂f/∂y = 2y + kx = 0
y = -kx/2
Substituting y from the first equation into the second equation gives
x = k²x/4, so k² = 4 and k = ± 2.
Therefore, the critical points are (0,0), (2,4), and (-2,4)
We will now examine the critical points to see when the shape of the graph changes qualitatively.
There are two cases to consider:
Case 1: (0,0)At (0,0), the Hessian matrix is
H = [∂²f/∂x² ∂²f/∂x∂y;∂²f/∂y∂x ∂²f/∂y²]
=[ -2 0;0 2].
The determinant of the Hessian matrix is -4, which is negative.
Therefore, (0,0) is a saddle point and the graph changes qualitatively as k increases for all values of k.
Case 2: (±2,4)At (2,4) and (-2,4), the Hessian matrix is
H = [∂²f/∂x² ∂²f/∂x∂y;∂²f/∂y∂x ∂²f/∂y²]
=[ -2k 2k;2k 2].
The determinant of the Hessian matrix is 4k²+8, which is positive when k is greater than √(2).
Therefore, the critical points (2,4) and (-2,4) are local minima when
k > √(2).
Thus, the shape of the graph changes qualitatively at k = ± 2 and
k = √(2).
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plzz answer number B
Answer:
4 hours
Step-by-step explanation:
It drives 240 miles per 2 hours so then 480 will be 2+2 = 4 hours
240+240 = 480
A music stereo is packed in a box shaped like a rectangular prism that measures 18.5 by 32 in by 12.2 in. What is the volume of the box
Okay, let's solve this step-by-step:
* The box is shaped like a rectangular prism
* It has dimensions:
** 18.5 inches long
** 32 inches wide
** 12.2 inches deep
To find the volume of a rectangular prism, we use the formula:
Volume = Length x Width x Depth
So in this case:
Volume = 18.5 inches x 32 inches x 12.2 inches
= 18.5 * 32 * 12.2
= 5796 cubic inches
Therefore, the volume of the box is 5796 cubic inches.
Let me know if you need more details!
Use the Ratio Test or the Root Test to determine if the following series converges absolutely or diverges ⁽⁻⁶⁾ Σ ᴷ⁼¹ ᵏˡ Select the correct choice below and fill in the answer box to complete your choice (Type an exact answer in simplified form) A. The series converges absolutely by the Ratio Test because r = B. The series diverges by the Root Test because p= OC. Both tests are inconclusive because re= and p=
Ratio test:The ratio test is used to find out whether the given series is convergent or divergent. It is applied to series whose terms are positive. the series diverges by the Root Test because p= 1.
And if the limit is exactly equal to 1, then the test is inconclusive. The ratio test is one of the best tests that can be used for the majority of series.The ratio test can be expressed as below Root test:The root test is used to determine whether a series is convergent or divergent. It is a quick method for determining the convergence of an infinite series. This test is an application of the limit comparison test.
The test states that if the limit as n approaches infinity of the nth root of the absolute value of the nth term is less than 1, then the series converges absolutely. If the limit is greater than 1 or infinite, then the series diverges. And if the limit is exactly equal to 1, then the test is inconclusive. It is one of the most useful convergence tests.
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convert 2/5 to per cent
Answer:
40%
Step-by-step explanation:
Answer:
for converting 2/5 in percentage, we have to multiply with 100
________________________________
\( = > \: \frac{2}{5} \times 100 \\ = > \: 2 \times 20 \\ = > \: 40 \: percent\)
−6⋅f(−3)−5⋅g(−7)=graph
Answer:
Slope is -35/18
Graphed (x, y)(0, 0)(18, -35)
Step-by-step explanation:
Hope you get it right!
using the equation y^2=-5/4(x-2), find the equation of the directrix
Answer:
Step-by-step explanation:
since its a horizontal parabola opening to the right we use a formula for the directrix
x=h-p 4p=5/4 p=5
X= -3 v(h,k)=(2,0)
the radius of the circle is 9 meters what is the circles circumfrence
Answer:
c = 18π exact answer
c = 56.52 decimal approximation
Step-by-step explanation:
c = 2πr
c = 2π * 9
c = 18π exact answer
Using 3.14 for π
c = 18 * 3.14
c = 56.52 decimal approximation
Bethesda Mining Company reports the following balance sheet information for 2013 and 2014.
BETHESDA MINING COMPANY Balance Sheets as of December 31, 2013 and 2014
2013 2014 2013 2014
Current assets Current liabilities Cash $21,396 $24,385 Accounts payable $214,414 $192,480
Accounts receivable 51,552 58,318 Notes payable 99,022 134,508
Inventory 121,807 143,615 Total $194,755 $226,318 Total $313,436 $326,988
Long-term debt $271,700 $285,300
Owners' equity COmmon stock and paid-in surplus $200,000 $200,000
Accumulated retained earnings 132,481 171,358
Fixed assets NEt plant and equipment $722,862 $757,328 Total $322,481 $371,358
Total assets $917,617 $983,646 Total liabilities and owners equity $917,617 $983,646
Required:
d. Debt-equity ratio and equity multiplier. Do not round intermediate calculations. Round answers to 2 decimal places.
Debt-equity ratio (times) Equity multiplier (times)
2013 _____________ _____________
2014 _____________ _____________
e. Total debt ratio. Do not round intermediate calculations. Round answers to 2 decimal places.
Total debt ratio (times)
2013 _____________
2014 _____________
Debt to Equity Ratio:
The debt to equity ratio of a business is a measure of the financial leverage of the company. This ratio illustrates the amount of corporate financing that originates from debt.
To calculate the debt-equity ratio, we need to divide the total debt by the owners' equity.
The equation for the debt-equity ratio is:
Debt-equity ratio = Total debt / Owners' equity
Given the balance sheet information for 2013 and 2014:
2013:
Total debt = Long-term debt = $271,700
Owners' equity = Common stock and paid-in surplus + Accumulated retained earnings = $200,000 + $132,481 = $332,481
Debt-equity ratio (2013) = $271,700 / $332,481
2014:
Total debt = Long-term debt = $285,300
Owners' equity = Common stock and paid-in surplus + Accumulated retained earnings = $200,000 + $171,358 = $371,358
Debt-equity ratio (2014) = $285,300 / $371,358
Equity Multiplier:
The equity multiplier is a measure of how much of a company's assets are financed through debt. It is calculated by dividing total assets by owners' equity. The equation for the equity multiplier is:
Equity multiplier = Total assets / Owners' equity
2013:
Total assets = $917,617
Owners' equity = $332,481
Equity multiplier (2013) = $917,617 / $332,481
2014:
Total assets = $983,646
Owners' equity = $371,358
Equity multiplier (2014) = $983,646 / $371,358
Total Debt Ratio:
The total debt ratio is a measure of the proportion of a company's assets that are financed through debt. It is calculated by dividing total debt by total assets. The equation for the total debt ratio is:
Total debt ratio = Total debt / Total assets
2013:
Total debt = Long-term debt = $271,700
Total assets = $917,617
Total debt ratio (2013) = $271,700 / $917,617
2014:
Total debt = Long-term debt = $285,300
Total assets = $983,646
Total debt ratio (2014) = $285,300 / $983,646
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Monroe is gift wrapping a box that has the shape of a right rectangular prism. The box has a length of 20 cm, a width of 7 cm, and a height of 15 cm.
How many square centimeters of gift wrap will Monroe need to cover the entire outside of the box?
Enter your answer in the box. please help
Answer:
2,100
Step-by-step explanation:
You would have to multiply 20 by 7 by 15 to find the area of the box. So when you multiply all those together you get 2,100.
geometry i need help with this assignment this is only the front so make sure to watch for the back
The values of the area of the shaded region are;
1. Area = 36, perimeter = 28
2. Area = 16, perimeter = 16
3. Area = 22, perimeter = 30
4. Area = 29, perimeter = 28
6. Area = 53.9
What is the area of a figure?The area of a figure is the area bounded by the line that serves as the boundary of the figure.
The areas and perimeters of the figures are found as follows;
1. The figure consists of two rectangles
The dimension of the small rectangle at the top are;
Length = 4, Width = 3
Area = 3 × 4 = 12
Dimensions of the larger rectangle are;
Width = 4, Length = 6
Area = 4 × 6 = 12
The area of the composite figure is therefore; A = 3 × 4 + 6 × 4 = 36
The sum of the length of the sides, which is the perimeter, P = 8 + 3 + 4 + 3 + 4 + 6 = 28
2. The figure consists of a right triangle at the top rectangle;
The leg lengths of the right triangle are; 3 and 4
The area of the right triangle = 0.5 × 3 × 4 = 6
The dimension of the rectangle are; Length = 5, width = 2
Area of the rectangle = 5 × 2 = 10
Area of the composite figure is therefore, A = 0.5 × 4 × 3 + 2 × 5 = 16
The perimeter of the composite figure, P = 4 + 3 + 2 + 5 + 2 = 16
3. The figure is a composite figure that is found by subtracting the area of a rectangle from the area of a right triangle as follows;
The dimensions of the triangle are;
Leg lengths; (8 + 4) = 12 and (3 + 2) = 5
Area of the right triangle = 0.5 × (8 + 4) × (3 + 2) = 30
Dimensions of the rectangle left blank are;
Length = 4, width = 2
Area of the rectangle = 4 × 2 = 8
Therefore;
Area of the composite figure = 0.5 × (8 + 4) × (3 + 2) - 4 × 2 = 22
Length of the hypotenuse side = √((8 + 4)² + (3 + 2)²) = 13
The perimeter of the composite figure = 3 + 13 + 8 + 2 + 4 = 30
4. The figure is a composite figure that consist a large rectangle and small rectangle.
Dimensions of the large rectangle are;
Length = 2 + 2 + 3 = 7
Width = 5
Area of the large rectangle = 7 × 5 = 35
Dimensions of small rectangle are;
Length = 3, width = 2
Area of the small rectangle = 3 × 2 = 6
Area of the composite figure = 35 - 6 = 29
The perimeter = 2 × (2 × 2 + 3) + 2 × 5 + 2 × 2 = 28
6. Area of the circle = π × 14²/4
Area of the square = 10 × 10 = 100
The area of the shaded region = π × 14²/4 - 100 ≈ 53.9
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The length of a rectangle is 8cm more than its width the perimeter of the rectangle is 96cm what are the dimensions of the rectangle?
Step-by-step explanation:
96/8=__________ will be the answer
Today 90 students bought lunch from the cafeteria. If this was 60% of the students, how many students are there in total?
Answer: 150 students
Step-by-step explanation:
Let X be the total number of students. We are told that:
0.60X = 90 students
X = (90 students)/0.60
X = 150 students
SOMEBODY HELP ME PLEASEEEEEEE I HAVE 9 more
Answer:
a. every fifth student that enters her classroom
Step-by-step explanation:
I am not for sure, it makes the most sense though because her honors class is all 3 classes, and boys in each of her classes could be biased
factoring trinomials with a leading coefficient. ac method
10p^2-p-2
The factored trinomial expression is (5p + 2)(2p - 1)
How to factor the trinomial expressionFrom the question, we have the following parameters that can be used in our computation:
10p^2-p-2
To factor the trinomial 10p^2 - p - 2, we can use the method of finding two numbers that multiply to -20p^2 and add to -p.
We can use these numbers to write the trinomial as a product of two binomials:
So, we have
10p^2 - p - 2 = 10p^2 - 5p + 4p - 2
Factorize
10p^2 - p - 2 = 5p(2p - 1) + 2(2p - 1)
This gives
10p^2 - p - 2 = (5p + 2)(2p - 1)
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what is the root mean squared speed of he(g) in this room if the temperature of the room is 30.0 oc?
The answer will be 1374.2 m/s using root mean square.
What is root mean square?
The root mean square formula provides the square root of the sum of all squares for each observation's data. The arithmetic mean of the squares of a set of values is known as the root mean square, or RMS, and is denoted by the abbreviation. Quadratic mean is another name for it. An integral of the squares of the instantaneous values during a cycle can be used to define the root mean square value for a function for a function that is continuously changing. The root mean square formula is used to determine the square root of the arithmetic mean of the square of the function that characterises the continuous waveform in this case.
mass of He is = 4 / 6.023*10²³
So Root mean square velocity is = √(3RT/m)
v = √(3*8.31*10³*303/4)
v = 1374.2 m/s
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What is the image of M(11,-4) using the translation (x,y)->(x-17,y+2?
Answer:
(-6, -2)
Step-by-step explanation:
The Supplies account has a balance of $3,306. A year-end inventory shows $1,768 worth of supplies left at the end of the year. The correct adjusting entry is:
The correct adjusting entry is to debit the Supplies Expense account for $1,538 and credit the Supplies account for the same amount. This entry reflects the decrease in the value of supplies used during the year.
The adjusting entry is necessary to accurately reflect the supplies consumed during the year and the remaining supplies on hand. The Supplies Expense account is debited to recognize the expense incurred for the supplies used up during the year.
The credit to the Supplies account reduces its balance to reflect the value of supplies remaining at the end of the year. This adjustment ensures that the financial statements accurately reflect the actual supplies expense for the period and the correct value of supplies on hand.
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The pull of gravity is different on Earth than on the Moon. An object that weighs 25 pounds on Earth weighs about 4 pounds on the Moon. An astronaut, wearing all the necessary gear, weighs 500 pounds on Earth.
How many pounds would the astronaut with gear weigh on the Moon?
pounds
The weight of the astronaut with gear on the moon is 80 pounds.
The pull of gravity is different on Earth than on the Moon as gravity depends on factors such as the mass of the celestial body, the radius of the celestial body, and the density of the celestial body.
The pull of gravity on Earth = 10 m/s²
Thus, Given:
Weight of object on Earth: 25 pounds
Weight is described as the product of mass and the acceleration due to gravity
Thus, 25 = 10 * mass
mass = 2.5 unit
Weight of the object on the Moon: 4 pounds
4 = 2.5 * acceleration due to gravity on the moon
Acceleration due to gravity on the moon = 1.6 m/s²
Weight of astronaut with gear on earth = 500 pounds
500 = mass * 10
mass = 50 units
Weight of astronaut with gear on earth = 50 * 1.6
= 80 pounds
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Cindy had $8,255 in her pocket she spent 9000 on a new iPhone
Input data
Pocket: 8255
Iphone: 9000
Procedure
Total = Pocket - Iphone
Total = 8255 - 9000
Total = -745
Cindy would owe a total of USD 745
Help ASAP !!!
What is the angle of 1
Answer:
100°
Step-by-step explanation:
m L 1 = (180-100) + 20 = 80+20 = 100°
Calculus Consider the function ƒ(x,y) = (x² − 1)e¯(x²+y²). (a) This function has three critical points. Verify that one of them occurs at (0, 0), and find the coordinates of the other two. (b) What type of critical point occurs at (0, 0)?
(a) The critical points of the function ƒ(x, y) = (x² - 1)e^(-x² - y²) are:
1. (0, 0)
2. ((1 + √5)/2, 0)
3. ((1 - √5)/2, 0)
(b) The critical point (0, 0) is a local maximum.
To find the critical points of the function\(f\left(x,\:y\right)\:=\:\left(x^2-\:1\right)e^{-x^2-y^2}\).
we need to find the points where the partial derivatives with respect to x and y are equal to zero.
Let's start by finding the partial derivative with respect to x:
\(\frac{\partial f}{\partial x}\:=\:\left(2x\right)\left(x^2\:-\:1\right)e^{-x^2-y^2}\:+\:\left(-2x\right)e^{-x^2-y^2}\)
Setting this derivative equal to zero and simplifying, we have:
\(\:\left(2x\right)\left(x^2\:-\:1\right)e^{-x^2-y^2}\:+\:\left(-2x\right)e^{-x^2-y^2}=0\)
Factoring out \(e^{-x^2-y^2}\) and dividing by 2x, we get
\(\left(x^2-1-x\right)e^{-x^2-y^2}=0\)
Since \(e^{-x^2-y^2}\) is always positive and nonzero, we have:
(x² - 1 - x) = 0
x² - x - 1 = 0
Using the quadratic formula, we can solve for x:
x = (1 ± √(1 - 4(-1)))/2
x = (1 ± √5)/2
So the x-coordinates of the critical points are (1 + √5)/2 and (1 - √5)/2.
Now, let's find the partial derivative with respect to y:
\(\frac{\partial f}{\partial y}\:=\:\left(-2y\right)\left(x^2\:-\:1\right)e^{-x^2-y^2}\)
Setting this derivative equal to zero, we have:
\(\:\left(-2y\right)\left(x^2\:-\:1\right)e^{-x^2-y^2}=0\)
Since \(e^{-x^2-y^2}\) is always positive and nonzero, we have:
y = 0
Therefore, one of the critical points occurs at (0, 0).
(b) To determine the type of critical point at (0, 0), we can use the second derivative test.
We need to calculate the second partial derivatives and evaluate them at (0, 0).
Taking the second partial derivatives, we have:
\(\frac{\partial ^2f}{\partial x^2}\:=\left(2-4x^2+4x^4\right)\:e^{-x^2-y^2}\)
\(\frac{\partial ^2f}{\partial y^2}\:=\left(x^2-1-2y^2\right)\:e^{-x^2-y^2}\)
\(\frac{\partial ^2f}{\partial x\partial \:y}\:=2xy\)
Evaluating these second partial derivatives at (0, 0), we get:
∂²ƒ/∂x²(0, 0) = 2
∂²ƒ/∂y²(0, 0) = -1
∂²ƒ/∂x∂y(0, 0) = 0
Now, let's compute the discriminant D:
D = ∂²ƒ/∂x²(0, 0) × ∂²ƒ/∂y²(0, 0) - (∂²ƒ/∂x∂y(0, 0))²
= 2 × (-1) - 0²
= -2
Since D < 0 and ∂²ƒ/∂x²(0, 0) > 0, the discriminant test tells us that (0, 0) is a local maximum.
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In the following exercise, find the coordinates of the vertex for the parabola defined by the given quadratic function. \[ f(x)=4 x^{2}+16 x+8 \] The vertex is . (Type an ordered pair.)
The coordinates of the vertex for the parabola defined by the given quadratic function is `(-2, -8)`.
The vertex for the parabola defined by the given quadratic function can be found using the formula `(-b/2a, f(-b/2a))`.
From the question above, the function: `f(x) = 4x² + 16x + 8`
To find the vertex, we need to express it in the standard form `f(x) = a(x - h)² + k`
where (h, k) is the vertex and a is the coefficient of the squared term.
To do this, we can complete the square:
`f(x) = 4(x² + 4x) + 8` `f(x) = 4(x² + 4x + 4 - 4) + 8`
`f(x) = 4((x + 2)² - 4) + 8` `
f(x) = 4(x + 2)² - 8`
Now we have the equation in the standard form, where a = 4, h = -2 and k = -8.
Thus, the vertex is: `(-2, -8)`
Therefore, the coordinates of the vertex for the parabola defined by the given quadratic function is `(-2, -8)`.
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