what type of axle is also a part of the drivetrain system?

The temperature of the gas in the tank is the ratio of heat capacities times the temperature of gas in the constant pressure line.

It should be noted that temperature simply means the measure of hotness and coldness in a body

From the given information, H is the enthalpy of gas on the constant pressure line, m is the mass flow rate and U is the internal energy of gas.

Here, the temperature of the gas in the tank is the ratio of heat capacities times the temperature of gas in the constant pressure line.

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Answer:

When a switch is in the "off" position the circuit is open. Electric charges cannot flow when a switch is in the off position.

Explanation:

A switch that can open or close an electric circuit can be used to stop the flow of current.

A switch can be defined as an electrical component (device) that is typically designed and developed for interrupting the flow of current or electrons in an electric circuit.

This ultimately implies that, a switch that can open or close an electric circuit can be used to stop the flow of current.

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Answer: Increase in minimills

Explanation:

Answer:

Motorcyclist Fatality and Injury Rates per Vehicle Miles Traveled, 1998-2008. 10. 9. Fatalities in School Transportation Related Crashes,. 1998-2008.

Explanation:

Answer:

Sole Proprietorship, General Partnership , Limited Partnership, corporation

Explanation:

Business in something that an individual or a group of people do for a living and produce products and services that benefits the society and the people. There are several entities that can be common in business. Some common form of entities are :

Sole Proprietorship : One to one

-- here there is only one owner in the business and he maintains and manages the entire business functions under his control.

Limited Partnership : many to one

-- here two or more than two partners establish business and runs it but only one or more is liable to the amount of the investments.

General Partnership : many to many

-- It is a business partnership where all the partners shares the profits, the assets, legal liabilities and financial liabilities, etc.

Corporation : many to one

It is a business entity where a group of individual or a group of companies run a single business which is generally authorized by the state.

Some of the typical types of the entities that one may think to be common in term of the business entities are about the relationships that are held within many to many and one to many.

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Answer: To initialize an ArrayList called inventory that stores Car objects in Java, you can use the following code:

import java.util.ArrayList;

public class CarTracker

{

   public static void main(String[] args)

   {

       // Initialize your ArrayList here:

       ArrayList<Car> inventory = new ArrayList<>();

   }

}

The ArrayList is initialized using the ArrayList<Car> syntax, where Car is the type of objects that will be stored in the ArrayList. The ArrayList is then instantiated using the new ArrayList<>() syntax. You can then add Car objects to the ArrayList using the add method. For example, the following code adds a Car object with the name "Ford", model "Fiesta", and cost $15,000 to the inventory ArrayList:

// Add a Car object to the inventory ArrayList

Car car1 = new Car("Ford", "Fiesta", 15000);

inventory.add(car1);

You can add as many Car objects to the inventory ArrayList as you need. To retrieve a Car object from the ArrayList, you can use the get method and specify the index of the Car object you want to retrieve. For example, the following code retrieves the first Car object in the inventory ArrayList:

// Get the first Car object in the inventory ArrayList

Car car = inventory.get(0);

You can then access the fields of the Car object using the dot notation, as shown in the following code:

// Print the name, model, and cost of the Car object

System.out.println("Name: " + car.name);

System.out.println("Model: " + car.model);

System.out.println("Cost: $" + car.cost);

This code would output the name, model, and cost of the Car object.

True development sustainability understands that human life is dependent on the health of the Earth's natural systems. In addition to natural resources, social and economic resources are vital. The environment provides resources that are both renewable and non-renewable.

Sustainability has several short- and long-term advantages. We cannot preserve our Earth's ecosystems or continue to function as we do until we make more sustainable decisions. If damaging processes continue unabated, humanity will most likely run out of fossil fuels, a large number of animal species will become extinct, and the atmosphere will be irrevocably harmed. Sustainability advantages include clean air and nontoxic atmospheric conditions, increased reliance on resources, and improved water quality and cleanliness.

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The student exerts the greatest force on the floor of the elevator when the elevator is at rest, either starting from the first floor or stopping at the tenth floor. When the elevator is in motion, the student is being acted upon by two forces: their weight, which is acting vertically downward, and the normal force from the floor of the elevator, which is acting vertically upward.

The normal force is equal in magnitude to the weight of the student but acts in the opposite direction. As a result, the net force acting on the student is zero and the student does not exert any significant force on the floor of the elevator.

However, when the elevator comes to a stop, the normal force changes. The sudden change in velocity means that there is a non-zero net force acting on the student, which results in the student exerting a force on the floor of the elevator. The magnitude of this force is equal to the student's weight, which is determined by their mass and the acceleration due to gravity.

In conclusion, the student exerts the greatest force on the floor of the elevator when the elevator is at rest, either starting from the first floor or stopping at the tenth floor. This is because the normal force changes when the elevator comes to a stop, resulting in a non-zero net force acting on the student and a corresponding force being exerted on the floor of the elevator.

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Unprotected sides and edges are where there is no stair rail system in place at a height of 4 inches or higher.

Unprotected sides and edges are regions along stairs, platforms, or elevated surfaces that do not have a protective barrier in situ, such as a stair rail system. Individuals may step off the edge or lose their balance and fall in these situations, posing a possible fall hazard.

The 4-inch barrier was chosen with the notion that a fall from this height or above could result in serious damage. A stair rail system, which includes handrails and guardrails, helps to provide a physical barrier and support for those using the stairs or accessing high locations, lowering the risk of slipping down the unprotected sides or edges.

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Answer:

it's says potential that something not moving.

incorrectly cutting ties or securing devices because

this is so dangerous thing I know because being electrocuted is here this for me.

'Material Handling Injuries' are characterized as the 'injuries caused at work due to the carrying or holding of heavy loads.'

The probable hazards associated with 'materials' in terms of material handling injuries include:

A). Being crushed by machines, falling materials, or improper materials.

C). Being struck by materials or caught in pinch points

D). Improper manual lifting or carrying loads that are too heavy.

E). Incorrectly cutting ties or securing devices.

The probable injury threats to the workers while handling materials include all the above-mentioned situations.

Thus, options A, C, D, and E are the correct answers.

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The initial (v1) and final (v2) specific volumes based on the information will be 0.9354 m3/kg.

From the information, Water at P1 = 200 kPa with a quality of 25% has its temperature raised 20 oC (T2 = T1+20 0C) in a constant pressure process.

For state 1, v = vf + x vfg = 0.001061 + 0.25 × 0.88467 = 0.22223 m3/kg

State 2  at 200 kPa T2 = Tsat + 20 = 120.23 + 20 = 140.23°C

So state is superheated vapor x = undefined v = 0.88573 + (0.95964 – 0.88573) 20/150 - 120.23 = 0.9354 m3/kg

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Answer:

u do the same thing as part B but only add 100 k, I think, cuz I'm still in middle school but I mean if u see it asks u to do the same thing as B but C says that instead, u do it at half pressure and 100 k is higher temp so what its asking is to repeat b but the twist is u do it at half pressure and 100 k is the higher temp

hope this helps :)  

Answer:

Power= Heat energy\ time

heat energy= mc∆T

specific heat of water = 4180

1.5*4180*(60-25)

=219450

time = 10× 60= 600 secs

power = 219450/600

Power= 365.75 Watt

=0.37 KW

Explanation:

the actual has to be bigger because the heater might be required to handle more ...also to accommodate extra energy.

To find the answer to the question, we can use the formula of confidence interval which is given below:$$\bar{x} \pm z_{(α/2)}\frac{σ}{\sqrt{n}}$$Where,$\bar{x}$ is the sample mean. $z_{(α/2)}$ is the $Z$-score for the given level of confidence interval.$σ$ is the population standard deviation. $n$ is the sample size.

If the 98% confidence limits of the population mean are 73 and 80, then we can say that:$$\bar{x} \pm z_{(α/2)}\frac{σ}{\sqrt{n}} = (73, 80)$$Now, we need to find the 95% confidence limits. For this, we have to calculate the Z-score for the 95% confidence interval. The Z-score for 95% confidence interval is calculated as follows:$$Z_{(α/2)} = Z_{(0.025)} = 1.96$$Now, we can use this Z-score in the confidence interval formula as follows:$$\bar{x} \pm z_{(α/2)}\frac{σ}{\sqrt{n}} = (73, 80)$$$$\bar{x} \pm 1.96\frac{σ}{\sqrt{n}} = (73, 80)$$We do not know the value of $\bar{x}$ or $σ$ or $n$, so we can't solve the above equation directly.

However, we can use some logic to find out which of the options is correct. If we consider the option (b), i.e. the 95% confidence limits are 72 and 79, then we can say that the distance between the upper limit of the 98% confidence interval and the upper limit of the 95% confidence interval is 1 unit less than the distance between the lower limit of the 98% confidence interval and the lower limit of the 95% confidence interval. In other words, the difference between the upper limit and the lower limit of the 98% confidence interval is 7, and the difference between the upper limit and the lower limit of the 95% confidence interval is 7-1 = 6. This is possible only if the sample size is very small or the standard deviation of the population is very high. Both of these conditions are unlikely to be true in most cases. Therefore, we can eliminate option (b).

Similarly, we can eliminate option (d) as the difference between the upper and the lower limit of the 98% confidence interval is 5 and the difference between the upper and the lower limit of the 95% confidence interval is 5-1 = 4.This is also unlikely to happen in most cases.

Therefore, we can eliminate option (d) as well.

Now, if we consider option (a), i.e. the 95% confidence limits are 73 and 81, then we can say that the difference between the upper limit of the 98% confidence interval and the upper limit of the 95% confidence interval is 1 unit, and the difference between the lower limit of the 98% confidence interval and the lower limit of the 95% confidence interval is 1 unit as well. This is possible and likely to happen in most cases.

Therefore, we can select option (a) as the correct answer .Finally, the answer to the question is: Option (a), i.e. 73 and 81 could be the 95% confidence limits.

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Answer: At least I’m not the only one looking for answers lol

Explanation:

Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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Answer:

the magnitude of the stress necessary to cause slip to occur on the (111) plane in the \([1 0 \overline 1]\) direction is 4.85 MPa

Explanation:

From the given information;

To determine the angle \(\phi\) between the direction [100] and [111]; we have:

\(\phi = cos ^{-1} [\dfrac{u_1u_2+v_1v_2+w_1w_2}{ \sqrt{(u_1^2+v_1^2+w_1^2) (u_2^2+v_2^2+w_2^2) }}}\)

where;

[u₁,v₁,w₁] and [u₂, v₂, w₂] are directional indices.

replacing 1 for u₁ , 0 for v₁ and 0 for w₁  ;

also replacing 1 for u₂, 1 for v₂ and  1 for w₂ ; we have :

\(\phi = cos ^{-1} [\dfrac{1*1+0*1+0*1}{ \sqrt{(1^2+0^2+0^2) (1^2+1^2+1^2) }}}\)

\(\phi = 54.7^0\)

To determine the angle \(\lambda\) for the slip direction \([1 0 \overline 1]\)

\(\lambda= cos ^{-1} [\dfrac{u_1u_2+v_1v_2+w_1w_2}{ \sqrt{(u_1^2+v_1^2+w_1^2) (u_2^2+v_2^2+w_2^2) }}}\)

replacing 1 for u₁ , 0 for v₁ and 0 for w₁  ;

also replacing 1 for u₂, 1 for v₂ and  -1 for w₂ ; we have :

\(\lambda = cos ^{-1} [\dfrac{1*1+0*0+(0*-1)}{ \sqrt{(1^2+0^2+0^2) (1^2+0^2+(-1^2)) }}}\)

\(\phi = cos ^{-1} [\dfrac{1}{\sqrt{2}}]\)

\(\lambda = 45^0\)

The yield strength  for the slip process \([1 0 \overline 1]\) can now be calculated as:

\(\sigma_x = \dfrac{t_{xr}}{cos \phi \ \ cos \lambda}\)

where

\(t_{xr}\) = 1.98 MPa

\(\sigma_x = \dfrac{1.98}{cos 54.7^0 \ \ cos 45}\)

\(\sigma_x = \dfrac{1.98}{0.5779 *0.7071}\)

\(\mathbf{\sigma _x = 4.85 \ MPa}\)

Hence, the magnitude of the stress necessary to cause slip to occur on the (111) plane in the \([1 0 \overline 1]\) direction is 4.85 MPa

Answer:

80Hays he mm duskish ieksjsj

Answer:

oa

Explanation:

Answer:

safety factor

Explanation:

i got it correct on the test

Answer:

  A

Explanation:

An open circuit has infinite resistance, not 0. A circuit with continuity usually measures a few ohms or less, depending on the length and gauge of the wire and the condition of the connections. Often, on a general-purpose ohmmeter, the reading is very near 0 ohms.

Technician A is correct.

i think it's c. bread.

Answer:I think raw meat because if you eat raw meat you get sick and get stomach aches so always when you cook meat it kill the bacteria

Explanation:what I'm trying to says is stay safe

the percent excess O2 (molar basis) for 25% excess air is 5.10%.

What is a molar basis?

The nth value, expressed on a molar scale, is equal to the quantity of substrate transformed times the stoichiometric generation of hydrogen gas from one mole of the substrate. The number of reactants required to produce the products in a given chemical reaction, based on the molar ratio of the reactants in the balanced chemical reaction, is known as the molar basis for that reaction.

For instance, the balanced chemical reaction in the burning of propane with oxygen is

C3H8 + 5O2 → 3CO2 + 4H2O

No reactants would be left behind after producing the products, which would need 5 moles of oxygen and 1 mole of propane on a molar scale (theoretically). On a molar basis, 5 moles of oxygen are compared to 1 mole of propane.

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An 802.11 frame contains a number of fields. frame control field describes the version of 802.11 that is being used.

Information is conveyed as a byte torrent across a moment in time interconnect called a frame among two or more devices. Upon reaching a significant frame, a package is split into a shorter person.

There are several specializations inside the framing modulation process that are used to characterize the frames and execution. These comprise the 802.11 version that is used by the person and is being processed in the input.  

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Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter.

Explanation:

Mass is the matter that makes up objects

a. The power factor is 0989

b. The average power from the source is 2.125 kW

Power factor is the ratio of the real power absorbed by the load to the apparent power.

a. What is the power factor.

To find the power factor, we nedd to find the equivalent impedance of the circuit.

First, the the 8Ω resistor and -j6 Ω capacitor impedance are in series, their equivalent impedance is Z₁ = 8 Ω+ (- j6) Ω = (8 - j6)Ω.

Now, Z₁ is parallel to the Z₂ = j4 Ω impedance.

So, their equivalent inpedance is

Z₃ = Z₁Z₂/(Z₁ + Z₂)

= (8 - j6)j4 Ω/(8 - j6 + j4)

= (32 - j24)/(8 - j2)

Rationalizing the denominator, we have that

=  (32 - j24)/(8 - j2) × (8 + j2)/(8 + j2)

= [32 × 8 + 32 × j2 - j24 × 8 + (-j42 × -j2)]/(8² + 2)²

= [256 + j64 - 192j + j²84)]/(8² + 2²)

= [256 + j64 - 192j - 84)]/(64 + 4)

= (172 - j128)/68

= (43 - j32)/17

Since the 10 Ω resistor is in series with Z₃, the equivalent impedance is

Z₄ = 10 Ω + (43 - j32)/17 Ω

= (10 + 43/17 - j32/17 )Ω

= (170 + 43)/17 - j32/17

= 213/17 - j32/17

We know that for an impedance Z = a + jb , tanФ = b/a

So, for Z₄, tanФ = b/a

= -32/17 ÷ 213/17

= -32/213

since the trigonometric identity

tan²Ф + 1 = sec²Ф

secФ = ±√(tan²Ф + 1)

So, substituting tanФ into the equation, we have that

secФ = ±√(tan²Ф + 1)

secФ = ±√[(-32/213)² + 1)

= ±√[(1024 + 45369)/45369)]

= ±√[46393/45369)]

= ±215.39/213

Now, the power factor P.F = cosФ

Since secФ = 1/cosФ

cosФ = ±213/215.39

= ±0.989

Since tanФ is negative, Ф is in the fourth quadrant.

So, cosФ = 0.989

So, the power factor is 0989

b. The average power

The average power P = I²R where

Now, I = V/Z₄ where

We know that for an impedance Z = a + jb , tanФ = b/a

So, for Z₄ = , tanФ = b/a

= -32/17 ÷ 213/17

= -32/213

Ф = tan⁻¹(-32/213)

= -8.544

Also, the magnitude of impedance, Z = √(a² + b²)

So, the magnitude of Z = √[(213/17)² + (-32/17)²]

= √[(213)² + (-32)²]/17

= √[45369 + 1024]/17

= 215.39/17

= 12.67

So, Z = 12.67 ∠-8.544

So, the current I = V/Z

= 165 ∠ 0°/ 12.67 ∠-8.544

= 165/12.67 ∠ 0°- (-8.544)

= 13.02 ∠ 8.544° A

So, the average power P = I²R where

so, P = (13.02 A)² × 213/17 Ω

= 169.60 A² × 213/17 Ω

= 36123.754/17 A²Ω

= 2124.93 W

= 2.125 kW

The average power is 2.125 kW

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Answer:

SECTION LEARNING OBJECTIVES

By the end of this section, you will be able to do the following:

Distinguish between static friction and kinetic friction

Solve problems involving inclined planes

Section Key Terms

kinetic friction static friction

Static Friction and Kinetic Friction

Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.

There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.

Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.

Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.

Answer:

Wood is heavy

Explanation: