What type of potential energy does a yo-yo have?
Gravitational potential energy
Elastic potential energy
Chemical potential energy

Answers

Answer 1
I think it’s gravitational potential energy
Answer 2

Answer:

gravitational

Explanation:


Related Questions

Sheena can row a boat at 3.00mi/h in still water. She needs to cross a river that is 1.20mi wide with a current flowing at 2.00mi/h. Not having her calculator ready, she guesses that to go straight across, she should head upstream at an angle of 25.0 ′′ from the direction straight across the river. How long does it take her to cross the river?

Answers

It takes her 1 hour and 5 minutes to cross the river.

We have to find the time it will take Sheena to cross the river.

Let's consider the given information. Sheena can row a boat at 3.00mi/h in still water and the river that is 1.20mi wide with a current flowing at 2.00mi/h.

She guesses that to go straight across, she should head upstream at an angle of 25.0 ′′ from the direction straight across the river.

As per the given information, Sheena's boat speed in still water is 3.00mi/h. The current speed is 2.00mi/h. This means, the total effective speed of the boat will be the vector sum of boat speed and current speed. effective speed

= 3.00mi/h - 2.00mi/hcos 25

°≈ 1.10 mi/h

Now we know that the river's width is 1.20 miles. The effective speed of the boat is 1.10 mi/h.

Hence, the time taken to cross the river is 1.20/1.10

≈ 1.09 hours

= 1 hour and 5 minutes.

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If the primary coil of wire on a transformer has less turns of wire than the secondary coil of wire, how will this affect the current observed at the secondary coil

Answers

Answer:

The current pass to the secondary coil will be less due to surface created on the secondary coil

2
A simple circuit contains a battery and a resistor.
Over 3.0 hours, 29 000 C of charge passes through the resistor.
Calculate the current flowing through the circuit during this time.
Give your answer to two significant figures.

Answers

Answer:

Approximately \(2.69\; {\rm A}\).

Explanation:

Ensure that all values are measured in standard units. Charge should be measured in coulombs, while time should be measured in seconds:

\(\begin{aligned}t &= 3.0\; {\rm hr} \times \frac{3600\; {\rm s}}{1\; {\rm hr}} = 10800\; {\rm s}\end{aligned}\).

Electric current \(I\) is the rate of flow of electric charge.

In order to find the electric current, divide electric charge \(q\) by the time \(t\) required to transfer these charge. If charge \(q\!\) is measured in coulombs and time \(t\!\) is measured in seconds, the unit of current \(I\)would be amperes:

\(\begin{aligned}I & = \frac{q}{t} \\ &= \frac{29000\; {\rm C}}{10800\; {\rm s}} \approx 2.69\; {\rm A}\end{aligned}\).

A block of mass =4.20 kg slides along a horizontal table with velocity 0=3.50 m/s . At =0 , it hits a spring with spring constant =26.00 N/m and it also begins to experience a friction force. The coefficient of friction is given by =0.250 . How far has the spring compressed by the time the block first momentarily comes to rest? Assume the positive direction is to the right.

Answers

The distance in which the spring is compressed is 1.065 m.

The given parameters;

mass of the block, m = 4.2 kgvelocity of the block, v = 3.5 m/sspring constant, k = 26 N/mcoefficient of friction, μ = 0.25

Apply the principle of conservation of energy to determine the distance in which the spring is compressed.

\(K.E = W + U\\\\\frac{1}{2} mv^2 = \mu Fx \ + \ \frac{1}{2} kx^2\\\\\frac{1}{2}(4.2)(3.5)^2 = 0.25(4.2 \times 9.8)(x) \ + \frac{1}{2} (26)(x^2)\\\\25.725 = 10.29x \ + \ 13x^2\\\\13x^2 + 10.29x - 25.725 = 0\\\\\)

solve the quadratic equation using formula method;

a = 13, b = 10.29,  c = -25.725

\(x = \frac{-b \ \ +/- \ \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-(10.29) \ \ +/- \ \sqrt{(10.29)^2 \ - \ 4(13\times 25.725)} }{2(13)} \\\\x = 1.065 \ m, \ \ or \ -1.86 \ m\)

choose positive distance, x = 1.065 m.

Thus, the distance in which the spring is compressed is 1.065 m.

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Jackie rides her bike to school every day and enjoys playing beach volleyball on weekends. She also helps with tasks around the house, like pulling weeds in the garden and sweeping the porch. Which of the following describes a possible benefit of Jackie's physical activity? (1 point) a Jackie may be less likely to commit to a healthy future. b Jackie may have an increased chance of disease. c Jackie may maintain healthy body fat levels. d Jackie may require more assistance performing daily tasks.

Answers

Answer:

The correct answer is - C) Jackie may maintain healthy body fat levels.

Explanation:

Jackie has a very active daily and on weekends routine that includes riding the bike, playing volleyball, pushing weeds, and sweeping the porch. The activities that Jackie is performing daily as well as the time that she spends on exercise may help her to maintain body fat levels.

Being physically active helps in maintaining fat levels in the body of an individual, and it is healthy for the individual.

Thus, the correct answer is - C) Jackie may maintain healthy body fat levels.

If an object is dropped from 10 m above the ground, what is the height at which its kinetic energy and potential energy are equal?​

Answers

potential energy is converted to kinetic energy as the ball drops.


they will be equal at the halfway point.


answer: 5 m

Henrietta manages to swing at a softball that was pitched very low - it almost hit the home
plate! Starting from very near the ground, the ball is launched upward at an angle with
amazing speed. 30 m/s upwards and 20 m/s across. 100m away from home plate is the outfield fence that's 24m tall. Will
Hentrietta get a home run?
a) How long will the ball take to get to the top?
b) How far from home plate will the ball be, once it's at the top?
c) Did the ball reach the fence yet, when it gets to the top?
d) How high up is the softball when it's at the top?
e) how long in seconds will it take for the ball to get 100m away from home plate?
F) How high above the ground is the ball when it’s 100m away from home plate?
G) finally, when the ball is 100m away from home plate, how high above the ground is it?

Answers

Answer:

a) The time it takes the ball to reach maximum height is approximately 3.06 seconds

b) The distance of the ball from the home plate once it is at the top is approximately 38.78 m

c) No

d) The height of the ball when it is at the top is approximately 45.92 m

e) The time it takes the ball to travel 100 m horizontally is 5 seconds

F) The height of the ball when it is 100 m away from the home plate is 27.5 m

G) The height of the ball above the ground when it 100 m away from the home plate, is 27.5 m

The height of the ball above the wall at 100 m from home plate is 3.5 m

Explanation:

The given parameters for the motion of the ball are;

The upward (vertical) velocity of the ball, \(u_y\) = 30 m/s

The across (horizontal) velocity of the ball, uₓ = 20 m/s

The distance from the home plate to the outfield fence = 100 m

The height of the outfield fence = 24 m

a) The time, '\(t_{mh}\)', it takes the ball to reach maximum height is by the following kinematic equation of motion;

\(v_y\) = \(u_y\) - g·t

Where;

\(u_y\) = 30 m/s

g = The acceleration due to gravity ≈ 9.8 m/s²

At maximum height, we have;

\(v_y\) = 0 m/s, t = \(t_{mh}\)

∴ 0 m/s = \(u_y\) - g·\(t_{mh}\)

\(u_y\) = g·\(t_{mh}\)

\(t_{mh}\) = \(u_y\)/g

∴ \(t_{mh}\) = \(u_y\)/g = (30 m/s)/(9.8 m/s²) = 150/49 s ≈ 3.06 seconds

The time it takes the ball to reach maximum height, \(t_{mh}\) ≈ 3.06 seconds

b) The horizontal distance travelled by the ball, when it is at maximum height, \(x_{mh}\), is given as follows;

\(x_{mh}\) = uₓ × \(t_{mh}\) = 20 m/s × 150/49 s

\(x_{mh}\) = 20 m/s × 150/49 s = 3000/49 m

\(x_{mh}\) = 3000/49 m

The distance of the ball from the home plate, 'd', once it is at the top (maximum height), is given as follows;

d = 100 m - \(x_{mh}\)

∴ d = 100 m - 3000/49 m = 1900/49 m ≈ 38.78 m

The distance of the ball from the home plate once it is at the top = d ≈ 38.78 m

c) The ball is yet to reach the fence when it gets to the top

The ball has approximately 38.78 meters to reach the fence

d) The height of the ball, \(h_{max}\), when it is at the top is given by the following kinematic equation

\(h_{max}\) = \(u_y\)²/(2·g)

Where;

\(u_y\) = 30 m/s

g = The acceleration due to gravity ≈ 9.8 m/s²

∴ \(h_{max}\) = (30 m/s)²/(2×9.8 m/s²) = 2,250/49 m ≈ 45.92 m

The height of the ball when it is at the top, \(h_{max}\) ≈ 45.92 m

e) The time, t₁₀₀, it will take the ball to get 100 m from home plate is found from the following relationship;

Velocity, u = Distance, x/(time, t)

∴ Time = Distance/(Velocity)

t = x/v

The given distance is the horizontal distance, therefore, we use the horizontal component of the velocity as follows;

v = Horizontal velocity of the softball = uₓ = 20 m/s

x = The given horizontal distance travelled by the ball = 100 m

t₁₀₀ = The time it takes the ball to travel 100 m horizontally

∴ t₁₀₀ = x/(uₓ) = 100 m/(20 m/s) = 5 s

The time it takes the ball to travel 100 m horizontally, t₁₀₀ = 5 seconds

F) The height of the ball above ground when it is 100 m away from the home plate is given as follows;

When the ball is 100 m from the home plate, the time, t₁₀₀ = 5 seconds

The height of the ball at 100m, \(h_{t_{(100 \, m)}}\), is given according to the kinematic equation of motion for vertical height reached by an object as follows;

h = \(u_y\)·t - 1/2·g·t²

∴ \(h_{t_{(100 \, m)}}\) =  \(u_y\)·t₁₀₀ - 1/2·g·t₁₀₀²

Plugging in the known values gives;

\(h_{t_{(100 \, m)}}\) =  30 m/s × 5 s  - 1/2 × 9.8 m/s × (5 s)² = 27.5 m

The height of the ball when it is 100 m away from the home plate, \(h_{t_{(100 \, m)}}\) = 27.5 m.

G) The height of the ball above the ground when it 100 m away from the home plate, is  \(h_{t_{(100 \, m)}}\) = 27.5 m

The height of the ball above the wall at 100 m from the home plate = The height of the ball when it is 100 m away from the home plate - The height of the wall at 100 m away from the home plate

∴ The height of the ball above the wall at 100 m from home plate = 27.5 m - 24 m = 3.5 m.

2. If a 6.2A current flows through a 3.90 resistor, how much voltage is supplied?
a. 20.18V
b. 1.58V
C..18V
d. 24.18V

Answers

Answer:

D

Explanation:

voltage =current × resistor

v= 6,2 × 3,90

v=24,18 V

It’s the letter C................

the specific heat of copper is 0.385 j/g °c. how much thermal energy is required to increase the temperature of a 20g sample of copper from 20°c to 50°c?

Answers

The amount of thermal energy required to increase the temperature of a 20g sample of copper from 20°C to 50°C is 231 J.

What is thermal energy?

The entire quantity of kinetic energy found in the particles of an object or material is referred to as thermal energy. It is a type of energy connected to atomic and molecular motion within a substance. Conduction, convection, and radiation are a few examples of mechanisms that can be used to transmit this energy from one item to another. An object's thermal energy content is inversely related to its temperature, with higher temperatures denoting a higher thermal energy content. Through the transformation of heat energy into mechanical energy, thermal energy is employed in a variety of processes, including heating houses, preparing food, and creating electricity.

The amount of thermal energy required to increase the temperature of a substance can be calculated using the following formula:

Q = m x c x ΔT

Where:

Q = amount of thermal energy in Joules (J)

m = mass of the substance in grams (g)

c = specific heat capacity of the substance in J/g°C

ΔT = change in temperature in °C (final temperature - initial temperature)

Using the values given in the problem, we can calculate the amount of thermal energy required to increase the temperature of a 20g sample of copper from 20°C to 50°C:

Q = 20g x 0.385 J/g°C x (50°C - 20°C)

Q = 20g x 0.385 J/g°C x 30°C

Q = 231 J

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The amount of thermal energy required to increase the temperature of a substance can be calculated using the following formula:

Q = m x c x ΔT

Where:

Q = amount of thermal energy in Joules (J)

m = mass of the substance in grams (g)

c = specific heat capacity of the substance in J/g°C

ΔT = change in temperature in °C (final temperature - initial temperature)

Using the values given in the problem, we can calculate the amount of thermal energy required to increase the temperature of a 20g sample of copper from 20°C to 50°C:

Q = 20g x 0.385 J/g°C x (50°C - 20°C)

Q = 20g x 0.385 J/g°C x 30°C

Q = 231 J

Therefore, the amount of thermal energy required to increase the temperature of a 20g sample of copper from 20°C to 50°C is 231 J.

How does the magnitude of the induced voltage depend on the time rate of change of the magnetic flux? if one wanted to increase or reduce the induced voltage what could one do?

Answers

The magnitude of the induced voltage depends on the time rate of change of the magnetic flux. If one wants to increase or reduce the induced voltage, they can either increase or decrease the rate of change of the magnetic flux.

According to Faraday's law of electromagnetic induction, the magnitude of the induced voltage in a coil is directly proportional to the rate of change of the magnetic flux passing through the coil. The magnetic flux is a measure of the total magnetic field passing through a given area.

When there is a change in the magnetic field strength or the orientation of the magnetic field relative to the coil, the magnetic flux through the coil changes. This change in magnetic flux induces an electromotive force (EMF) or voltage in the coil.

To increase the induced voltage, one can either increase the rate of change of the magnetic flux or increase the number of turns in the coil. This can be achieved by moving the coil in a stronger magnetic field or by increasing the speed of the magnetic field's change.

Conversely, to reduce the induced voltage, one can either decrease the rate of change of the magnetic flux or decrease the number of turns in the coil. This can be achieved by reducing the speed of the magnetic field's change or by shielding the coil from the magnetic field.

In summary, the magnitude of the induced voltage is directly proportional to the rate of change of the magnetic flux. To increase or reduce the induced voltage, one can adjust the rate of change of the magnetic flux by manipulating the magnetic field strength, the speed of change, or the coil configuration.

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How do you find the total number of nodes in a two-source interference pattern?

I know the formula is like Na=d/lambda but apparently, according to my physics teacher, you have to go one step further to find the total number of nodes. But he never showed us how, and I cant find anything online.

Like for example if the distance between the two sources was 20cm and the wavelength was 2cm, then it would be 20/2=10 right? But my teacher said its wrong. And he wont explain why.

I have a test on this tomorrow please help

Answers

The distance between two nodes is HALF the wavelength. So if the wavelength is 2cm the distance between two adjacent nodes is 1 cm. does this help?

A door is part way open (at 20° to its frame). Calculate the turning effect of a force of 10 N applied to open the door. The force is applied perpendicular to the frame. The width of the door is 0.5m. Please show the calculation , thank you :)

A door is part way open (at 20 to its frame). Calculate the turning effect of a force of 10 N applied

Answers

Answer:

2.35 Nm.............. .

The kicker now kicks the ball with the same speed as in the number of 4,but at 60.0°from the horizontal or 30.0° from the vertical. a.What is the time the ball is in the air? b.What is the distance the balls travel before it hits the ground? c.What is the maximum height?

Answers

Answer:

Explanation:

1) The time of flight equation for projectile motion can be used here to find total time in air.

t = 2vsin∅ / g

where v is speed, Ф is launch angle

t = 2×4×sin 60 / 9.8

t = 0.71 seconds

2) Distance where it hit the ground is called as range and has the following standard equation

D = v² sin2Ф/g

D = 4²sin 2×60 / 9.8

D = 1.41m

3) Maximum elevation is maximum time reached

h = v² sin²Ф / 2g

h = 4²sin² 60 / 2*9.8

h = 0.61 m

The human eye is only sensitive to certain wavelengths of light. We call the range of light we can see the visible spectrum. It ranges from the lowest energy color of red to the highest energy of violet. Using the table, what is the range of wavelength of light, in nanometers (nm), that humans can see?


A.

380 - 750


B.

380 - 495


C.

570 - 750


D.

570 – 590

Answers

The range of wavelength of light in nanometers (nm) that humans can see is  380 - 750 nm. So the correct answer is option: A.

This is commonly known as the visible spectrum, which consists of the colors of the rainbow - red, orange, yellow, green, blue, indigo, and violet - each corresponding to a different range of wavelengths within this range. Light with wavelengths shorter than violet are called ultraviolet, while those longer than red are called infrared. Although humans cannot see these wavelengths, they can be detected by special equipment and are used in various applications such as medical imaging, remote sensing, and communications. Hence option A is correct.

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write an experiment to show that black surfaces absorb heat energy more than shiny polished surfaces or white surface​

Answers

Answer: One example of an experiment you can do is find out the heat difference between a white car and a black car using the sun in a hot day.

Explanation: The black car would absorb more heat from the sun and would make the inside of the black car hotter than the white car.

how do the two pieces of aluminum foil interact with each other? you may move the pieces of foil by lifting their respective pieces of tape off the rod. be sure not to touch the foil as you might accidentally discharge it

Answers

Because of the presence of electrostatic charges on their surfaces, two pieces of aluminium foil can interact with one other when placed near together.

If one foil is positively charged and the other is negatively charged, they will be attracted to each other and may even cling together. This is due to the fact that opposing charges attract one other.

If two foils have the same charge (positive or negative), they will repel each other and attempt to move away from each other. This is due to the fact that like charges repel each other.

It is important to note that the charges on the foils can be affected by the presence of other nearby charged objects, such as the rod or any nearby static electricity source. Additionally, touching the foil can transfer charge between the foil and the person's body, which can also affect the interaction between the foils.

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What is the instantaneous velocity of a freely falling object 14 s after it is released from a position of rest

Answers

The instantaneous velocity of the object is 137.2 m/s along the downward direction.

Instantaneous velocity: The velocity of an object at a particular instant of time is called the instantaneous velocity.

Note: The y-axis is taken along the upward direction so acceleration due to gravity will be negative.

Any object that is falling freely is acted upon by gravity. The first equation of motion gives the relationship between initial velocity, the velocity at time t, time, and acceleration. The equation is,

v=u+at

where v is the velocity at time t, u is the initial velocity, t is the time, and g is the acceleration due to gravity. Since the object starts from rest, its initial velocity is zero.

For the given case, u=0, a=-9.8 m/s^2 and t=14 s. Put the values in the equation to get the instantaneous velocity of the object at t=14 s.

v=0+(-9.8)(14)

v=-137.2 m/s

The negative sign indicates the object is falling downward.

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1. What is the electrical isolation method for the input circuit and output circuit of the switching power supply?


2. Is the control circuit of the switching power supply positive feedback control or negative feedback control?


3. Is SG3525 a voltage mode or current mode switching power supply integrated PWM-controller?


4. What is the mainly difference between UC1842 / UC2842 / UC3842?

solve these 4 questions

Answers

1. The method used for electrical isolation of input and output circuits of switching power supply is called as isolation transformer. It uses transformer to separate the input circuit from the output circuit. This is done to avoid the transmission of high voltage spikes from the power input to the output.

2. The control circuit of switching power supply uses negative feedback control. The negative feedback helps to maintain the output voltage in a fixed range by adjusting the duty cycle of the switch based on the output voltage.

3. The SG3525 is a voltage mode switching power supply integrated PWM-controller.

4. The main difference between UC1842, UC2842 and UC3842 are as follows:UC1842 - It is a fixed frequency current mode PWM controllerUC2842 - It is an adjustable frequency current mode PWM controller UC3842 - It is a fixed frequency current mode PWM controller

The UC2842 has the ability to generate a variable frequency which is not present in the UC1842. Similarly, the UC3842 does not have the capability to generate variable frequency.

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All battery powered devices, run off of what type of power?

Answers

Answer:

Electrical energy

Explanation:

electrical energy Essentials. A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

A following interval of _____ seconds provides time to steer out of problem areas on dry surfaces at speeds up to 35 mph.answer choicesa. 10b. 2c. 6d. 4

Answers

On dry surfaces at up to the speed 35 mph, a following gap of two seconds time gives enough time to steer clear of trouble spots. Meaning we can steer clear of the issue.

if there is a two-second time gap on dry surfaces. Distance travelled in a unit of time is referred to as speed. It is the rate of movement of an object. Speed is a scalar quantity and the velocity vector's magnitude. There is no clear direction to it. A faster rate of movement is indicated by a higher speed. Slower movement is indicated by a lower speed. Its speed is zero if it isn't moving at all. In simple words, we define speed or velocity as the distance travelled in a specific amount of time.

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Metal paper clips do not attract or repel each other. When an electromagnet is placed nearby, the paper clips can be observed to move toward it. Which statement describes this phenomenon?
Paper clips turn into permanent magnets after exposure to a magnetic field.
The electromagnet reacts to the strong force of attraction from paper clips.
Electrons flow freely into the magnetic field, causing the paper clips to move.
Magnetic domains within the paper clips align with the magnetic field.

Answers

Magnetic domains within the paper clips align with the magnetic field.

Why is paper not attracted by a  magnet?

Paper is not attracted to a magnet because it does not contain materials that are magnetic. Magnetic materials are those that contain iron, nickel, cobalt, or other elements that have magnetic properties. These materials have an uneven distribution of electrons in their atoms, which creates a magnetic field.

Therefore, when a magnet is brought close to paper, there is no magnetic attraction because the paper does not contain enough magnetic materials to create a magnetic field that can interact with the magnet.

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If you have a frequency of 99Hz what is your period?

Answers

Answer:

frequency=1/time period

99HZ*time period=1

time period=1/99HZ

=0.01 second

Explanation:



During a collision with another car, the occupants of a minivan initially travelling at 4.0 m/s come to a complete stop in 0.5 s. What was the acceleration of the occupants of the minivan?



a) 8.0 m/s2



b) –8.0 m/s2



c) 2.0 m/s2



d) –2.0 m/s2

Answers

Answer: b) - 8.0 \(m/s^{2}\)

Explanation: Acceleration is a vector indicating a rate an object's velocity changes over time:

a = \(\frac{v}{t}\)

and its SI unit is \(m/s^{2}\)

For the minivan to stop, it takes a period of 0.5s:

a = \(\frac{4.0}{0.5}\)

a = 8.0 \(m/s^{2}\)

As a vector, acceleration has magnitude (8\(m/s^{2}\)) and direction. Since it is stopping, the minivan has a direction opposite to the other car, which means acceleration is negative. So: a = \(- 8.0 m/s^{2}\).

On a particular day the atmospheric pressure is 1. 02*100000. The density of mercury is 13600 kg/m3. Calculate the value of h indicated by the barometer

Answers

On a particular day the atmospheric pressure is 1. 02*100000. The density of mercury is 13600 kg/m3. Then the value of h indicated by the barometer is 0.7594 m.

On a particular day the atmospheric pressure is 1.02 * 100000. The density of mercury is 13600 kg/m³. We need to calculate the value of h indicated by the barometer.Let's first understand what is barometer. A barometer is an instrument that is used to measure atmospheric pressure, commonly used in weather forecasting and meteorology. There are two types of barometers: mercury and aneroid barometer.

A mercury barometer uses mercury which is placed in a long glass tube, where one end of the tube is closed and filled with the mercury, and the other end is exposed to the atmosphere. Due to the atmospheric pressure, mercury rises in the tube. The height of the mercury column indicates the atmospheric pressure. Let's apply this concept to solve the given question .h = (p / (ρ * g))where p = atmospheric pressure = 1.02 * 10^5 N/m²ρ = density of mercury = 13600 kg/m³g = acceleration due to gravity = 9.8 m/s²h = (1.02 × 10^5) / (13600 × 9.8)≈ 0.7594 m

Therefore, the value of h indicated by the barometer is 0.7594 m.

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Which of the following statements is NOT correct for eclipses in the SunEarth-Moon system? An eclipse of the Mopn occurs only at full Moon.
An eclipse of the Sun occurs only at new Moon. An ecipse of the Sun occurs at only full Moon Eclipses of Moon and Sun do not occurat quarter Moon phases.

Answers

Answer: An eclipse of the Sun occurs at only full Moon

Explanation:

bats use echolocation to navigate. they can emit ultrasonic waves with frequencies as high as 1.0×10^5 hz. What is the wavelength of such a wave? The speed of sound in air is 340 m/s.

Answers

The wavelength of an ultrasonic wave with a frequency of 1.0×10^5 Hz, given the speed of sound in air as 340 m/s, is approximately 3.4 mm.

The wavelength of a wave can be calculated using the formula λ = v/f, where λ represents the wavelength, v is the velocity or speed of the wave, and f is the frequency of the wave.

In this case, the frequency is given as 1.0×10^5 Hz, and the speed of sound in air is 340 m/s. By substituting these values into the formula, we can determine the wavelength.

λ = 340 m/s / (1.0×10^5 Hz) = 3.4×10^-3 m = 3.4 mm

Therefore, the wavelength of the ultrasonic wave emitted by bats, with a frequency of 1.0×10^5 Hz, is approximately 3.4 mm.

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1: The ball is on the 50 yard line. The ball travels west 5 yards before it's
handed off and ran forward (EAST) 15 yards where they're tackled.
What is the distance the ball traveled?
Your answer
This is a required question
* 1 point

Answers

The ball is on the 50-yard line. The ball travels west 5 yards. The distance ball traveled was 60 yards.

WHAT IS DIFFERENCE BETWEEN DISTANCE AND DISPLACEMENT ?

Distance can be defined as the length of any path between any two locations. Displacement is the direct distance between any two points when calculated via the shortest path between them. When computing distance, the direction is disregarded. The displacement computation takes the direction into consideration.

CALCULATION

The 5 yard gain would bring the ball to the 45 yard line (ball was tackled  at the 50 yard line, so 50 - 5 = 45), but the 15 yards lost due to the tackle and push back would bring ball to the 60 yard line (45 + 15 = 60).

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ASAP! HELP!
A 66.4 kg person sits on the right end of a seesaw, 2.35m from the fulcrum. On the other end, how far from the fulcrum should a 84.2kg person sit to balance the seesaw?
1: 1.92 m
2: 1.85m
3: 2.08m
4: 1.61 m

Answers

Answer:

2. 1.85

Explanation:

the equations weight * distance / other persons weight = distance from fulcrum. so 66.4*2.35/84.2=1.8532 round down to 1.85

The pressure drop over a certain length of horizontal pipe is assumed to be a function of the velocity

Answers

The pressure drop over a certain length of horizontal pipe is assumed to be a function of the velocity is true because of the relationship between fluid flow and pressure, which is described by the Bernoulli's principle.

The pressure drop over a certain length of horizontal pipe is typically related to the flow rate through the pipe, which is in turn related to the velocity of the fluid. This relationship is described by the Darcy-Weisbach equation,

ΔP = f (L/D) (ρV^2/2)

Where ΔP is the pressure drop, L is the length of the pipe, D is the diameter of the pipe, ρ is the density of the fluid, V is the average velocity of the fluid, and f is the friction factor, which depends on the roughness of the pipe surface and the Reynolds number of the flow.

This equation shows that the pressure drop is proportional to the square of the velocity of the fluid, which means that as the velocity increases, the pressure drop will also increase. Therefore, the pressure drop over a certain length of horizontal pipe can be related to the velocity of the fluid flowing through it.

To know more about the pressure drop, here

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In a given chemical reaction the time energy of the products is less than the energy of the reactants which statements is true for this chemical reaction

Answers

Answer:

Energy is released in this reaction possibly in the form of heat thus it is an exergonic and or exothermic reaction.

Explanation:

The energy is sometimes transferred as heat, inflicting the reaction mixture and its surroundings to become hotter. The temperature increase may be detected employing a measuring device. Some samples of exothermic reactions are: Combustion .An chemical reaction may be a chemical process that releases energy by lightweight or heat

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