What type of social engineering targets particular?.

Explanation:

In this series, the professionals at the B.O.L.D. Company will take you through the process of building a custom home in the Greater Cincinnati – Northern Kentucky area. From plan and lot selection, to mortgage approval, to the actual construction, we’ll take you behind-the-scenes each week for an inside look at a different part of the process.

During  propagation step of a free-radical chain-growth polymerization does the polymer actually grow or chain extend.

What is radical chain-growth polymerization?

What distinguishes step growth polymerization from chain growth polymerization?

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Answer:

xcvjchjcnjkkhjmklk heyyyy biiiiiiiittcccchhh

Mechanical systems have some limitations which can pose challenges in terms of efficiency, maintenance and durability.

Mechanical systems have inherent disadvantages as they tend to be less energy-efficient compared to newer technologies because they rely on mechanical processes that may generate friction and heat, leading to energy loss.

This systems require regular maintenance to ensure they continue to operate effectively and any malfunction can result in significant downtime and repair costs. They are also prone to wear and tear over time which can lead to reduced performance.

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Answer:

Answer:

True

Explanation:

Name me brainiest

An implication is the compound statement of the form “if p, then q.” It is denoted p⇒q, which is read as “p implies q.” It is false only when p is true and q is false, and is true in all other situations.

Answer:

d. is applied after the ceiling joists are

installed.

Answer:

55%

Explanation:

hot reservoir = 1100 K

cold reservoir = 500 K

This is a Carnot system

For a Carnot system, maximum efficicency of the system is given as

Eff = 1 - \(\frac{Tc}{Th}\)

where Tc = temperature of cold reservoir = 500K

Th = temperature of hot reservoir = 1100 K

Eff = 1 - \(\frac{500}{1100}\)

Eff = 1 - 0.45 = 0.55 or 55%

Lean production works best with standardized and repeatable processes. Lean production is a manufacturing technique that frequently aims to cut down on wait times for both suppliers' and customers' .

Lean manufacturing seeks to improve processes so that they use less energy, time, and resources overall. For some businesses than others, lean tools may be a better fit. But among the most helpful lean tools are Kaizen, 5S, Kanban, Value Stream Mapping, and Focus PDCA. Value, the value stream, flow, pull, and perfection are the five cornerstones of lean manufacturing, respectively. These are now the cornerstones on which lean is implemented. 1. Value: Value is established from the viewpoint of the customer and relates to the price point at which they are willing to purchase goods or services. Lean production is a manufacturing strategy that frequently aims to cut down on wait times for both suppliers' and customers' responses as well as those inside the manufacturing machine.

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The function isPositive is a boolean function that takes an integer parameter In both cases, the function returns true for any positive integer and false for any non-positive integer (zero or negative).

It checks if the integer is greater than zero, and if it is, it returns true. If the integer is less than or equal to zero, it returns false. Here's an example implementation in C++: bool isPositive(int num) {    if(num > 0) { return true; else { return false.


Note that the function only checks for positive integers and does not include zero. If you want to include zero as a positive integer, you can modify the function as follows: bool is Positive (int  num)    if(num >= 0) { return true else  return false}.

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Answer:

10.5

Explanation:

Convert to an equation for example P%* X=Y

P is 7.5% X is 140, so the equation Is 7.5 percent * 14= Y

convert 7.5% Into a decimal by removing the percent sign and deviding by 7.5/100= 0.075

Substitute 0.075 for 7.5% in the equation: 7.5%*140=Y becomes 0.075*140= 10.5

Answer:

A hammer and a wrench

Explanation:

Answer:

building a bridge

Explanation:

you would have to sketch ideas to see what the bridge would look like and you need to know what to add to it to enhance the percentage of it working. if you sketch it you would have an idea of the process also

Building a bridge is an occasion in which an explanatory sketch would be used.

Sketches of explanations are created to demonstrate form, structure, and function. They accurately and objectively communicate a design, placing more emphasis on explanation than pitch. Outside of the design team, explanation sketches must be understandable.

Exploratory sketches, often referred to as thinking drawings, are a type of personal communication that frequently serve as the starting point for brand-new product concepts.

During a brainstorming session or for personal usage in a design notebook, these quick sketches are meant to quickly capture ideas. Exploratory research aims to study the important aspects of a topic that hasn't gotten much attention.

Thus, it is Building a bridge.

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a. To find the compression of the spring needed to launch the rock horizontally at 35 mph, we can use conservation of energy. The potential energy stored in the compressed spring is equal to the kinetic energy of the rock when it leaves the spring:

1/2 k x^2 = 1/2 m v^2

where k is the spring constant, x is the compression distance, m is the mass of the rock, and v is the velocity of the rock.

Converting the velocity to meters per second:

35 mph = 15.6 m/s

Plugging in the values and solving for x:

1/2 (23,000 N/m) x^2 = 1/2 (13 kg) (15.6 m/s)^2

x = sqrt[(13 kg) (15.6 m/s)^2 / (23,000 N/m)] = 0.263 m

Therefore, the spring must be compressed by 0.263 meters.

b. To find the maximum height the rock will reach when the spring is oriented vertically, we can again use conservation of energy. The potential energy stored in the compressed spring is converted into gravitational potential energy of the rock when it leaves the spring:

1/2 k x^2 = m g h

where g is the acceleration due to gravity and h is the maximum height reached by the rock.

Plugging in the values and solving for h:

1/2 (23,000 N/m) (0.5 m)^2 = (13 kg) (9.8 m/s^2) h

h = (1/2) (23,000 N/m) (0.5 m)^2 / (13 kg) (9.8 m/s^2) = 0.605 m

Therefore, the rock will reach a height of 0.605 meters above the ground.

c. To find the compression distance when the rock is dropped onto the spring from a height of 14 meters, we need to consider both the potential energy of the rock and the energy absorbed by the spring. When the rock hits the spring, it will come to a stop, so all of its initial potential energy will be converted into potential energy stored in the compressed spring:

m g h = 1/2 k x^2

where h is the initial height of the rock and x is the compression distance of the spring.

Plugging in the values and solving for x, we get a quadratic equation:

1/2 (23,000 N/m) x^2 - (13 kg) (9.8 m/s^2) (14 m) = 0

Simplifying and solving for x using the quadratic formula:

x = sqrt[(13 kg) (9.8 m/s^2) (14 m) / (23,000 N/m)] = 0.473 m

Therefore, the spring will compress by 0.473 meters before the rock comes to a stop.

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a. To find the compression of the spring needed to launch the rock horizontally at 35 mph, we can use conservation of energy. The potential energy stored in the compressed spring is equal to the kinetic energy of the rock when it leaves the spring:

1/2 k x^2 = 1/2 m v^2

where k is the spring constant, x is the compression distance, m is the mass of the rock, and v is the velocity of the rock.

Converting the velocity to meters per second:

35 mph = 15.6 m/s

Plugging in the values and solving for x:

1/2 (23,000 N/m) x^2 = 1/2 (13 kg) (15.6 m/s)^2

x = sqrt[(13 kg) (15.6 m/s)^2 / (23,000 N/m)] = 0.263 m

Therefore, the spring must be compressed by 0.263 meters.

b. To find the maximum height the rock will reach when the spring is oriented vertically, we can again use conservation of energy. The potential energy stored in the compressed spring is converted into gravitational potential energy of the rock when it leaves the spring:

1/2 k x^2 = m g h

where g is the acceleration due to gravity and h is the maximum height reached by the rock.

Plugging in the values and solving for h:

1/2 (23,000 N/m) (0.5 m)^2 = (13 kg) (9.8 m/s^2) h

h = (1/2) (23,000 N/m) (0.5 m)^2 / (13 kg) (9.8 m/s^2) = 0.605 m

Therefore, the rock will reach a height of 0.605 meters above the ground.

c. To find the compression distance when the rock is dropped onto the spring from a height of 14 meters, we need to consider both the potential energy of the rock and the energy absorbed by the spring. When the rock hits the spring, it will come to a stop, so all of its initial potential energy will be converted into potential energy stored in the compressed spring:

m g h = 1/2 k x^2

where h is the initial height of the rock and x is the compression distance of the spring.

Plugging in the values and solving for x, we get a quadratic equation:

1/2 (23,000 N/m) x^2 - (13 kg) (9.8 m/s^2) (14 m) = 0

Simplifying and solving for x using the quadratic formula:

x = sqrt[(13 kg) (9.8 m/s^2) (14 m) / (23,000 N/m)] = 0.473 m

Therefore, the spring will compress by 0.473 meters before the rock comes to a stop.

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Answer:

The right solution is "2625 kN".

Explanation:

According to the question,

The average pressure will be:

= \(density\times g\times \frac{h}{2}\)

By putting values, we get

= \(1000\times 9.8\times \frac{12.2}{2}\)

= \(1000\times 9.8\times 6.1\)

= \(59780\)

hence,

The average force will be:

= \(Pressure\times Area\)

= \(59780\times 3.6\times 12.2\)

= \(2625537 \ N\)

Or,

= \(2625 \ kN\)

According to the question, the given statement of conductors at the point where the branch circuit originates is true.

What is conductors?
Conductors are materials that allow the flow of electrical energy. They are typically made of materials that contain free electrons, such as metals, that can move around freely when an electrical charge is applied. Conductors are essential for the functioning of electrical circuits and are used in a variety of applications from electrical wiring to power transmission. In addition to metals, other materials like semiconductors, graphite, and liquids can also be used as conductors. Conductors have a wide range of uses and are necessary for any type of electrical device or system. They are also used in various fields like engineering, telecommunications, physics, and computer science.

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The material property does the Charpy test determine is:(d) Toughness.

The Charpy impact test is utilized to determine the toughness of a material, specifically its ability to absorb energy when subjected to an impact load. Toughness, in this case, is defined as the ability of a material to resist the propagation of cracks or other flaws when subjected to dynamic or impact loading. In materials science, toughness is often described as the area under the stress-strain curve of a material up to its point of failure.  A pendulum hammer is used to hit the sample at the notched part with a specific amount of force.

The amount of energy absorbed by the sample is calculated by measuring the height difference between the point at which the pendulum starts to fall and the point where it swings up to after striking the sample. The energy absorbed during the fracture is proportional to the reduction in the height of the pendulum and is used to determine the toughness of the material. Therefore, the Charpy test is mainly used to determine the toughness of a material, making the correct option (d) Toughness.

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The Charpy test determines the toughness of a material.What is the Charpy test.The Charpy test is a test that measures a material's resistance to brittle fracture.

The test's results are critical in determining a material's serviceability in cold temperatures or environments where impact loading is possible. It is mostly used to assess the resistance of a material to impact loading. It involves striking a notched specimen with a swinging pendulum to produce a fracture and then measuring the amount of energy absorbed by the specimen.What is toughness,Toughness is the ability of a material to resist cracking when subjected to high-stress conditions. Toughness is defined as the amount of energy a material can absorb before it breaks. In general, materials with higher toughness are more durable. Toughness is critical in the construction of buildings, bridges, airplanes, ships, and other structures subjected to sudden and unpredictable impact forces.What material property does the Charpy test determine.The Charpy test determines the toughness of a material. The Charpy test is a common method for determining a material's toughness. The test is frequently used in construction and engineering to assess the impact resistance of materials. The toughness of a material, measured in joules, can be determined using the Charpy test.

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Answer:

3.52×10⁶ atoms of Si and 7.05×10⁶ atoms of O

Explanation:

It is all about unit conversions.

The area of our MOS is 1 mm². So, we know that the thickness is 160 nm. This data can give us the volume. We convert nm to mm.

160 nm . 1×10⁻⁶ mm /1nm = 1.6×10⁻⁴ mm

By the way, now we can determine the volume of MOS, in order to work with density.

1.6×10⁻⁴ mm . 1 mm² = 1.6×10⁻⁴ mm³

But density is mg/m³, so we convert mm³ to m³

1.6×10⁻⁴ mm³ . 1×10⁻⁹ m³/mm³ = 1.6×10⁻¹³ m³

Now, we apply density to determine the mass of MOS

Density = mass /volume → Density . volume = mass

1.6×10⁻¹³ m³ . 2.20mg/m³ = 3.52×10⁻¹³ mg

To make more easier the calculate, we convert mg to g.

3.52×10⁻¹³ mg . 1g /1000mg = 3.52×10⁻¹⁶ g

To count the atoms, we determine molar mass of SiO₂ → 60.08 g/mol

We need to know moles of Si and O₂ in the MOS

Firstly, we determine amount of MOS: 3.52×10⁻¹⁶ g / 60.08 g/mol = 5.86×10⁻¹⁸ moles

1 mol of SiO₂ has 1 mol of Si and 2 mol of O so:

5.86×10⁻¹⁸ mol of SiO₂ may have:

(5.86×10⁻¹⁸ . 1) /1 = 5.86×10⁻¹⁸ moles of Si

(5.86×10⁻¹⁸ .2) /1 =  1.17×10⁻¹⁷ moles of O₂

Let's count the atoms (1 mol of anything contain NA particles)

5.86×10⁻¹⁸ mol of Si . 6.02×10²³ atoms/ mol = 3.52×10⁶ atoms of Si

1.17×10⁻¹⁷ mol of O₂  . 6.02×10²³ atoms/ mol = 7.05×10⁶ atoms of O

The number of Si and O atoms present per mm² of the oxide layer are respectively; 3.52 × 10⁶ atoms of Si and 7.05×10⁶ atoms of O

We are given;

Area of MOS device; A = 1 mm²

Thickness of layer; t = 160 nm = 1.6 × 10⁻⁴ mm

Formula for volume is;

V = Area * thickness

V = 1.6 × 10⁻⁴ mm × 1 mm² = 1.6 × 10⁻⁴ mm³

Converting volume to m³ gives;

V = 1.6 × 10⁻¹³ m³

Now, to get the mass of MOS, we will use the formula;

Mass = Density * volume

we are given density = 2.20mg/m³

Thus;

Mass = 1.6 × 10⁻¹³ m³ × 2.20mg/m³

Mass = 3.52 × 10⁻¹³ mg = 3.52×10⁻¹⁶ g

From periodic table, the molar mass of SiO₂ = 60.08 g/mol

Then;

Number of moles of MOS = (3.52 × 10⁻¹⁶ g)/60.08 g/mol

Number of moles of MOS = 5.86 × 10⁻¹⁸ moles

Now, 1 mol of SiO₂  is formed from 1 mol of Si and 2 mol of O. Thus;

5.86×10⁻¹⁸ mol of SiO₂ will have;

5.86×10⁻¹⁸ moles of Si

and (5.86×10⁻¹⁸ .2) =  11.72 × 10⁻¹⁸ moles of O₂

From Avogadro's number that 1 mol equals 6.02×10²³ atoms , we can say that;

5.86 × 10⁻¹⁸ mol of Si × 6.02 × 10²³ atoms/mol = 3.52 × 10⁶ atoms of Si

11.72 × 10⁻¹⁸ mol of O₂ × 6.02 × 10²³ atoms/mol = 7.05×10⁶ atoms of O

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A securid key chain fob from RSA Security generates a password that changes every 60 seconds.

The SecurID key chain fob from RSA Security generates a password that changes every 60 seconds. This key chain fob is a security device that provides two-factor authentication, commonly used by organizations to protect access to their systems and networks. The fob displays a unique password that is synchronized with a server, ensuring that only authorized individuals with the fob can access the protected resources.

The password generated by the fob changes automatically every minute, adding an additional layer of security to the authentication process. This frequent password rotation makes it significantly more challenging for unauthorized users to guess or intercept the password.

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These equations provide the force acting on a current-carrying wire at different angles with the magnetic field.

(a) The equation for the force acting on a current-carrying wire when the angle between the magnetic field and the current is 60.0° can be determined using the formula:

Force (N) = Current (A) × Length of Wire (m) × Magnetic Field Strength (T) × Sin(θ)

where θ is the angle between the magnetic field and the current. In this case, θ = 60.0°. Therefore, the equation for the force acting on the wire would be:

Force = Current × Length × Magnetic Field Strength × Sin(60.0°)

(b) When the angle between the magnetic field and the current is 90.0°, the force acting on the current-carrying wire can be calculated using the same equation as mentioned above. However, since the Sin(90.0°) is equal to 1, the equation simplifies to:

Force = Current × Length × Magnetic Field Strength

(c) Similarly, when the angle between the magnetic field and the current is 120°, the force equation remains the same. The Sin(120°) is equal to √3/2, resulting in the equation:

Force = Current × Length × Magnetic Field Strength × (√3/2)

These equations provide the force acting on a current-carrying wire at different angles with the magnetic field.

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We are given the mean and standard deviation as 14.6 in. and 0.9 in., respectively.To find P95 (the hip breadth for men that separates the smallest 95% from the largest 5%), we need to use the z-score formula, which is given as:z = (x - μ) / σwhere x is the observed value, μ is the mean, and σ is the standard deviation.

Since we want to find the value that separates the smallest 95%, we need to find the z-score for the top 5%. We can find this value from the standard normal distribution table, which gives the area to the left of a given z-score. Using the table, we find that the z-score corresponding to an area of 0.05 in the right tail is 1.645.
Therefore,z = 1.645, x = μ + zσ = 14.6 + (1.645)(0.9) = 16.2 in.This means that 95% of all males have hip breadths less than or equal to 16.2 in. Hence, the hip breadth for men that separates the smallest 95% from the largest 5% is P95= 16.2 in.

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Answer: iy had around 5000 R

Explanation:

Answer:

the clothing you wear, what's in the air (gases), surrounding and weather

A contractor has a job that should be completed in 100 days. At present, he has 80 men on the job and it is estimated that they will finish the work in 130 days. Of the 80 men, 50 are each paid ₱120.00 a day, 25 at ₱180.00 a day, and 5 at ₱250.00 a day. For each day beyond the original 100 days, a contractor has to pay ₱500.00.

liquidated damages.(a) How many more men should the contractor add so that he would complete the work on time?In the first case, we see that the contractor already has 80 men and they are working for 130 days to complete the job. So, we can use the following formula to determine the additional number of workers required to finish the work in 100 days.

b) If of the additional men, 2 are paid ₱180.00 a day, and the rest at ₱120.00 a day, would the contractor save money by employing more men and not paying the fine Let’s assume that the contractor adds 440 workers, of which 2 are paid ₱180.00 a day and the rest are paid ₱120.00 a day.

The total cost of the new workers is, therefore, ₱9600.00 + ₱4500.00 + ₱49800.00 = ₱63,900.00.The cost of liquidated damages would be calculated as follows:  $$LD = (130-100) \cdot 500 = ₱15,000.00$$.

Therefore, the contractor would save money if he employs more men and not pays the fine. The contractor’s savings would be:$$Savings = LD - Additional cost$$$$= 15000.00 - 63900.00 $$$$= -48900.00$$

Thus, we can see that the contractor would save ₱48,900.00 by employing more men and not paying the fine.

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A straightforward fix is to eliminate each subsequence one at a time and determine whether the remaining string is a palindrome or not. This solution has exponential time complexity.

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The maximum pressure that the water in the smaller pipe can have is 362.5 kPa.

We have given:

Water temperature (T1) = 20°C

Water pressure (P1) = 500 kPa

Diameter of pipe (D1) = 50mm

The velocity of water (V1) = 6 m/s

Diameter of pipe (D2) = 25mm Using Bernoulli’s equation, we can relate the pressure in the larger diameter pipe to the pressure in the smaller diameter pipe as:

(1/2)*ρ*V1² + P1 + ρ*g*h1 = (1/2)*ρ*V2² + P2 + ρ*g*h2, where h1 = h2; z1 = z2; ρ = Density of fluid and g = acceleration due to gravity.

Where P2 is the pressure in the smaller diameter pipe.

Hence, (1/2)*ρ*V1² + P1 = (1/2)*ρ*V2² + P2 ∴ P2 = P1 + (1/2)*ρ*(V1² - V2²)

The continuity equation states that the mass flow rate is constant across the two sections of the pipe. It can be written as A1*V1 = A2*V2, where A1 and A2 are the cross-sectional areas of the larger diameter pipe and the smaller diameter pipe, respectively.

Rearranging this equation to get V2:V2 = (A1 / A2) * V1V2 = (π/4) * D₁² * V1 / ((π/4) * D₂²)V2 = D₁² * V1 / D₂²∴ V2 = (50mm)² * 6 m/s / (25mm)² = 288 m/s

Plugging this value in the above expression for P2: P2 = 500 kPa + (1/2) * 1000 kg/m³ * (6 m/s)² * [1 - (25/50)²]P2 = 362.5 kPa

Therefore, the maximum pressure that the water in the smaller pipe can have is 362.5 kPa.

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Answer:

True ...................

Answer:

True

Explanation:

Took da quiz 100%

The thickness of the boundary layer will be 0.436m. Distance downstream of the leading edge where this Reynolds number occur will be 3.08mm. The shear stress on the plate on this point is 1.055 N/m².

Laminar or turbulent fluid flow is identified using the Reynolds number, abbreviated as Re. In all viscous flows, where a numerical model is chosen in accordance with pre-calculated Reynolds number, it is one of the primary regulating parameters.

Given, Reynolds number, Re = 500000

  length = 0.7 m

  width = 1.5m

   velocity, u = 1.5 m/s

the thickness of the boundary layer, Re = u×x/v

                                                            x = Re × v/u

                                                             x = 500000×1.31×10∧(-6)/1.5

                                                             x = 0.436m

distance downstream of the leading edge where this Reynolds number occur, δ = 5x/\(\sqrt{Re}\)

          δ = 5×0.436/√500000

          δ = 3.08 mm

The shear stress on the plate on this point,

τ = 0.332v(u/x)×√Re

τ = 0.332×1.31×10∧(-3) (1.5/0.436) √500000

τ = 1.055 N/m²

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The complete question is,

A thin plate 0.7 m long and 1.5 m wide is submerged and held stationary in a stream of water (T = 10°C) that has a velocity of 1.5 m/s. What is the thickness of the boundary layer on the plate for Re, 500,000 (assume the boundary layer is still laminar), and at what distance downstream of the leading edge does this Reynolds number occur? What is the shear stress on the plate on this point?