Answer:
2440 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 976 × 2.5
We have the final answer as
2440 NHope this helps you
Graph. See text version for more detail.
The graph above represents the nuclear decay of a radioactive element, measured using a radiation-detecting device. What is the half-life, in days, of this hypothetical element?
If the half-life of a given substance is 65 days, how long will it take for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining?
If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope? Hint: First, determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.
If a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years, what is the half-life of technetium-99?
The half-life of hypothetical element technetium-99 is 210,936 years.
Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.
Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.
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Using the same cost and time estimates, consider any trade-offs that Drehex Corporation may have to make to complete the project. Camilla John Nora Oracio Cost per Hour $40 $30 $20 $15 Time to Complete Job 20 hours 30 hours 40 hours 50 hours Ideally, the process of technological design should be cost-effective and time-effective. However, sometimes this is simply not possible and trade-offs are necessary. Explain the trade-offs Drehex Corporation may have to make to complete the project.
Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.
Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:
Cost vs. Time: The corporation may need to decide whether to prioritize completing the project quickly or keeping the costs low. If they want to minimize costs, they might opt for a longer completion time by choosing a team member with a lower cost per hour. Conversely, if time is crucial, they might choose a team member with a higher cost per hour to expedite the process.Expertise vs. Cost: The team members have different levels of expertise, as indicated by their respective costs per hour. Drehex Corporation may need to evaluate the trade-off between the level of expertise required for the project and the associated cost. They might decide to invest more in a highly skilled team member to ensure the quality and efficiency of the project, even if it means incurring higher costs.Resource Allocation: The corporation will need to allocate resources effectively among the team members to ensure a balanced workload. They may need to assign tasks and responsibilities based on individual strengths and expertise, considering the trade-off between utilizing the most capable team members and maintaining a fair distribution of work.Quality vs. Time/Cost: The trade-off between project quality and time/cost is a common consideration. If Drehex Corporation wants to deliver a high-quality output, they might need to allocate more time and resources to ensure thoroughness and attention to detail. Conversely, if time or cost constraints are significant factors, they may need to compromise on certain aspects of quality to meet project deadlines or budget limitations.Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.
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Answer:
Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.
Explanation:
A pipe drips at 155 mL/min.
Express this is units of gallons/day.
1. 2.34 gal/day
2. 15.7 gal/day
3. 942 gal/day
4. 58.9 gal/day
5. 223 gal/day
6. 377 gal/day
7. 0.223 gal/day
We have that the total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is
\(X=58.96gal/day\)
From the Question we are told that
Pipe Drip\(=155 mL/min.\)
Generally
We have that for mL to gallons conversion
\(1mL=0.000264172\)
And
A minute to day con version is
\(1min=0.000694444\)
Therefore
\(X=155 mL/min.\)
\(X=155(\frac{0.000264172}{0.000694444})\)
\(X=58.96gal/day\)
In conclusion
The total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is \(X=58.96gal/day\)
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A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400Joules of work is done, how much force must have been applied?
4000 N
1600 N
800 N
100 N
The amount of force that must have been applied is 100 N.
option D is the correct answer.
What is the amount force applied to overcome the load?
The amount of force applied to overcome the load is calculated by applying the formula for work done as shown below.
Mathematically, the formula for work done is given as;
W = Fd
where;
F is the applied forced is the distance moved by the force or effortIf the distance moved by the effort arm is 10 meters, the amount of effort or force applied to overcome the load is calculated as follows;
F = W / d
F = ( 400 J ) / 4 m
F = 100 N
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a concave mirror has a focal length of 12cm the object is [laced at 24cm. What type, orientation,location and magnification does the image have?
To obtain the type, orientation, location and magnification of the image, we shall first obtain the location (i.e distance) of the image from the mirror. Details below:
The location i.e distance of the image can be obtained as follow:
Focal length (f) = 12 cmObject distance (u) = 24 cmImage distance (v) =?1/f = 1/v + 1/u
Rearrange
1/v = 1/f - 1/u
v = (f × u) / (u - f)
v = (12 × 24) / (24 - 12)
v = 288 / 12
v = 24 cm
Thus, the the location of the image is 24 cm
Since the location of the image is positive (i.e 24 cm). Thus,
The type of image is realThe orientation of the image is invertedNow, we shall obtain the magnification of the image. Details below:
Object distance (u) = 24 cmImage distance (v) = 24 cmMagnification (m) = ?Magnification = image distance (v) / object distance (u)
Magnification = 24 / 24
Magnification = 1
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A force of 255 N is applied to a stationary car of mass 500 kg for 18.3 s, the distance traveled by the car is
Answer:
170 m
Explanation:
force = ma
here a acceleration is unknown
but a = velocity/time = distance/(time)^2
255 = 500*d/(18.3)^2
d = 170 m
A car accelerates from a standstill of 70 km/hr in 10 seconds. What is the
car's acceleration? *
11
Match the following wave to the correct wave type. **You may use some answers more than once and some not at all*
The following are the correct matches for the waves in Column A and the wave types in Column B:
A - d. mechanical wave - longitudinalB - b. electromagnetic waveC - a. mechanical wave - transverseD - e. spring waveWhat are the wave types?A mechanical wave is a wave that requires a medium to travel through. The two types of mechanical waves are transverse waves and longitudinal waves. A transverse wave is a wave in which the particles of the medium move perpendicular to the direction of the wave. A longitudinal wave is a wave in which the particles of the medium move parallel to the direction of the wave.
An electromagnetic wave is a wave that does not require a medium to travel through. Electromagnetic waves are made up of electric and magnetic fields that oscillate perpendicular to each other.
A matter wave is a wave that describes the probability of finding a particle at a given location. Matter waves are associated with all particles, including electrons, protons, and neutrons.
A spring wave is a type of mechanical wave that travels through a spring. The particles of the spring move back and forth along the length of the spring.
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A ballast bag is dropped from a balloon that is 300 m above the ground and rising at 13 m/s. For the bag, find (a) the maximum height reached, (b) its position and velocity 5.0 s after it is released, and (c) the time at which it hits the ground.
308.6 m the maximum height reached.
Define velocity
The main determinant of an object's location and rate of motion is its velocity. It can be explained as the distance an object travels in one measure of time. The displacement of the item in a given amount of time is referred to as velocity.
The distance a person travels in a predetermined amount of time is referred to as speed.
Vi is the starting speed.
Vf is final speed
A=acceleration and Y=displacement
When the bag is freed, its Vi equals that of a balloon traveling at 13 m/s upward.
At the moment of release, choose up as positive y=0.
Vf=0 when it is maximum. Using the equation 2Vf=2Vi+2ay,
0=(13m/s)2+2(9.81m/s2)y, and y=8.6m
300 + 8.6 = 308.6 m is the highest point.
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A metallic circular plate with radius r is fixed to a tabletop. An identical circular plate supported from above by a cable is fixed in place a distance dd above the first plate. Assume that dd is much smaller than r. The two plates are attached by wires to a battery that supplies voltage V.1) What is the tension in the cable? Neglect the weight of the plate.Express your answer in terms of the variables d, r, V, and constants ϵ0, pi.F=2) The upper plate is slowly raised to a new height 2d. Determine the work done by the cable by integrating ∫d to 2d F(z)dz, where F(z) is the cable tension when the plates are separated by a distance z.Express your answer in terms of the variables d, r, V, and constants ϵ0,pi.W=3) Compute the energy stored in the electric field before the top plate was raised.Express your answer in terms of the variables d, r, V, and constants ϵ0, pi.U=4) Compute the energy stored in the electric field after the top plate was raised.Express your answer in terms of the variables d, r, V, and constants ϵ0, pi.U=5) is the work done by the cable equal to the change in the stored electrical energy? If not, why not?The work done in separating the plates is equal to energy change in the plates.The work done in separating the plates is equal to the magnitude of the energy change in the plates. This does not mean that the work done is equal to the change in the energy stored in the plates. The work done on the plates is positive but the plates lose energy. The plates are connected to the battery, so the potential difference across them remains constant as they are separated. Therefore charge is forced off of the plates through the battery, which does work on the battery.
An electrical charge and electrical energy are stored in a capacitor. Typically, capacitors have two electrical conductors that are spaced apart.
(Note that although these electrical conductors are frequently called "electrodes," they are actually "capacitor plates.") A capacitor is referred to as a "vacuum capacitor" if the distance between capacitors is merely a vacuum. However, a dielectric, an insulating substance, is typically used to fill the void. (In the sections on dielectrics later in this chapter, you will learn more about dielectrics.) You will learn more about the capacitance property of capacitors a little bit later in this section. Capacitance is what determines how much storage a capacitor can hold.
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Vector G and H lie in the xy plane with magnitudes of 45 meters and 66 meters respectively, as shown in the following diagram. What is the vector product (or “cross" product) of G × H ? G has 55 degrees H has 70 degrees
If Vector G and H lie in the xy plane with magnitudes of 45 meters and 66 meters respectively. the cross product of G and H is a vector that has a magnitude of approximately 364.6 square meters and points in the negative z direction.
What is the vector product ?In this case, since G and H lie in the xy plane, their cross product will be a vector that points in the z direction (perpendicular to the xy plane). To determine the magnitude of this vector, we can use the formula:
|G × H| = |G| |H| sin(θ)
where θ is the angle between the two vectors. Since G and H make angles of 55 degrees and 70 degrees, respectively, with the positive x-axis, the angle between them is 70 - 55 = 15 degrees.
Plugging in the given magnitudes and angle, we get:
|G × H| = (45 m) (66 m) sin(15°) ≈ 364.6 m^2
Therefore, the magnitude of the cross product is approximately 364.6 square meters. To determine the direction, we use the right-hand rule as described above. Since G makes an angle of 55 degrees with the positive x-axis, we can write it as:
G = 45 cos(55°) i + 45 sin(55°) j
Similarly, H can be written as:
H = 66 cos(70°) i + 66 sin(70°) j
Using these expressions and the right-hand rule, we find that the direction of the cross product is in the negative z direction, so the resulting vector is:
G × H = -364.6 k
where k is the unit vector in the positive z direction. Therefore, the cross product of G and H is a vector that has a magnitude of approximately 364.6 square meters and points in the negative z direction.
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What is the wavelength of a photon of EMR with a frequency of 5.02x10¹0Hz?5.98x10-3 m1.67x10² Hz1.51x1019 m5.98x10-3 m
The frequency of the photon is:
\(f=5.02\times10^{10}Hz\)The speed of the photon is:
\(v=3.0\times10^8\text{ m/s}\)The wavelength is calculated below
\(\begin{gathered} v=\lambda f \\ \\ \lambda=\frac{v}{f} \\ \\ \lambda=\frac{3\times10^8}{5.02\times10^{10}} \\ \\ \lambda=5.98\times10^{-3}m \end{gathered}\)How is the acceleration of a falling object calculated
Answer:
F=w=ma OR by using equations of motions vf=vi-at : a=vf-vi/t eq 1 s=vit+1/2at squre eq 2 2as=vf squre - vi squre eq 3
Explanation:
where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.
A physics book slides off a horizontal tabletop with a speed
of 1.10 m/s. It strikes the floor in 0.480 s. Ignore air resistance.
What is the height of the tabletop above the floor in meters.
A physics book slides off a horizontal tabletop with a speed of 1.10 m/s. It strikes the floor in 0.480 s. The height of the tabletop above the floor is 0.264 m.
Given data:
Speed = 1.10 m/s
Time taken to strike the floor = 0.480 s
We are supposed to find the height of the tabletop above the floor in meters.
We can use the formula of distance to calculate the height of the tabletop above the floor.
We also need to make use of kinematic equations to find out the distance fallen by the book.
Let us first calculate the distance fallen by the book.
Let the height of the table be ‘h’.
From the kinematic equations of motion, we know thats = ut + 1/2 at²Here, u = 1.10 m/s, a = acceleration due to gravity = 9.8 m/s², t = 0.480 s
Putting these values in the above equation, we get:s = 1.10 × 0.480 + 1/2 × 9.8 × (0.480)² = 0.264 m
Now, we can find the height of the tabletop using the formula of distance.d = h + sHere, d = distance fallen by the book = h, s = 0.264 m
Putting these values in the above equation, we get: h = d = s = 0.264 m
Therefore, the height of the tabletop above the floor is 0.264 m.
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3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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Pls help. Ill give 10 pts each for the other 3 questions i asked. look at my account and the other three questions will increase in pts by 5.
Answer:
a = 0.273 m/s²
Explanation:
I would assume that the rider starts at 0m/s.
a = average acceleration
v = final velocity = 3 m/s
v0 = initial velocity = 0 m/s
t = time = 11 s
a = (v-v0)/t
a = (3m/s - 0m/s) / 11s
a = 0.273 m/s²
I am not sure how many decimals I should round it to, so I just gave three. If your teacher has instructions on that, do so accordingly.
If you were to hit a Ping Pong ball of mass 0.0029 gg with the same force that caused a 0.058-gg tennis ball to move with an acceleration of 10 m/s2m/s2 , what would the acceleration aaa of the Ping Pong ball be
Answer:
the acceleration of the Ping Pong ball is 200 m/s²
Explanation:
Given;
mass of Ping Pong ball, m = 0.0029 g = 2.9 x 10⁻⁶ kg
mass of tennis ball, m = 0.058 g = 5.8 x 10⁻⁵ kg
acceleration of the tennis ball, a = 10 m/s²
The force applied to the tennis ball is calculated as;
F = ma
F = 5.8 x 10⁻⁵ x 10
F = 5.8 x 10⁻⁴ N
The acceleration of the Ping Pong ball is calculated as;
a = F/m
a = ( 5.8 x 10⁻⁴ N) / (2.9 x 10⁻⁶)
a = 200 m/s²
Therefore, the acceleration of the Ping Pong ball is 200 m/s²
You dip your finger into a pan of water twice each second, producing waves with crests that are separated by 0.19 m. (a) Determine the frequency of the water waves. Hz (b) Determine the period of the water waves. s (c) Determine the speed of the water waves.
Answer:
a) The frequency of the waves are = 2 Hz (since you are making two pulses every second)
b)The period of the waves is 0.19 m (as the consecutive crests are separated by 0.19 m)
c) V = L x f
v = 0.19 m x 2 S-1 (Hz is actually per second)
v = 0.38 ms-1
pe nis
As a person pushes a box across a floor, the energy from the person's moving arm is transferred to the box, and the box
and floor become warm. During this process, energy is
-increased
-conserved
-destroyed
-decreased
Answer:
-increased
Explanation:
Answer:
Increased
Explanation:
Which of the following describes how agricultural effects on forests differ from the oil industry’s effects on forests?Agricultural use leads to more damage from forest fires.Agricultural use does more harm to animal life in forests.Agricultural use requires the clearing of forest land for human’s needs.Agricultural use damages forest areas more slowly over a longer time period.
Agricultural use requires the clearing of forest land for human's needs.
Because oil damages the forest area over time due to pollution, agricultural use does not leads to more damage from forest fires and agricultural use does not harm animal life in forest. Therefore, third option is the correct one.
Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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Is a measurement is precuse it must also be accurate
A 750 kg race car accelerates to the right. The engine applies a force of
+7000 N to the car. The total friction on the car in the opposite
direction is -200 N.
Find the net force on the car then use 'Fnet = m a' to find the
acceleration.
O a
b
Oc
Od
12.4 m/s2
10.5 m/s2
8.0 m/s2
9.1 m/s2
In the Skycoaster amusement park ride, riders are suspended from a tower by a long cable. A second cable then lifts them until they reach the starting position indicated in (Figure 1). The lifting cable is then released, and the riders swing down the circular arc shown. If the four riders have a total mass of 330 kg
, what is the tension in the left cable just before release?
Tension in the left cable is 4395.9 N.
What is meant by tension ?Tension is defined as a pulling force that acts along the length of a flexible medium like rope or cables.
Here,
The total mass of the riders is given, m = 330 kg
Let the tension in the left cable be T₁ and that in the right cable be T₂.
From the figure,
T₁ cos 15 = T₂ cos 26
T₁ = T₂ cos 26/cos 15
Also,
T₁ sin15 + T₂ sin 26 = mg
Substituting values,
(T₂ cos 26/cos 15) sin 15 + T₂ sin 26 = 330x 9.8
0.241 T₂ + 0.438 T₂ = 3234
0.679 T₂ = 3234
T₂ = 4762.8 N
Therefore, Tension in the left cable, T₁ = 0.930x 4762.8
T₁ = 4395.9 N
Hence, The tension in the left cable is 4395.9 N
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Your question was incomplete. Attaching the image here.
What is the period so of a 5004m wave that is moving at 450,312m/s
wave
\(\tt v=\dfrac{\lambda}{T}\\\\T=\dfrac{\lambda}{v}=\dfrac{5004}{450.312}=11.112~s\)
A transformer consists of 340. primary windings and 980. secondary windings. If the emf of the primary coil is 30.0 V, what is the emf across the secondary coil? 34.7 Ω
Answer:
86.47 V
Explanation:
It will be multiplied by the ratio of the windings
980/340 * 30 = 86.47 v
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A 4.0-kg mass is moving to the right at 3.0 m/s. An 8.0 kg mass is moving to the left at 2.0 m/s. If after collision the two
masses join together, what is their velocity after collision?
O-0.33 m/s
O-0.20 m/s
O +1.4 m/s
O +2.3 m/s
Answer:
- 0.33 m/s
Explanation:
An illustration is shown above,
In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,
m1u1 - m2u2 = (m1 + m2)v
Where,
m1 = mass of the first object
u1 = initial velocity of the first object
v1 = final velocity of the first object
m2 = mass of the second object
u2 = initial velocity of the second object
v2 = final velocity of the second object
Therefore,
(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v
12 - 16 = 12v
-4 = 12v
Divide both sides by 12,
-4 / 12 = 12v / 12
-1 / 3 = v
v = -0.33 m/s
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Two lenses with focal lengths 10cm and 20cm and made of same material are placed coaxially
separated by distance d. The value of d such that the system is achromatic is
A) 20 om
) 30cm
C) 10 cm
D) 15 cm
At night, the moon appear smaller when is overhead then when it is on the horizon. This is an example of
Answer:
the brain's size-distance mechanism changes its perceived size and makes the moon appear very large.
Explanation:
the moon is changing its apparent position in depth while the light stimulus remains constant
(1,-5) perp to y=⅛×+2
The slope of a line perpendicular to y = 1/8x + 2 is -8.
The equation of a line in point-slope form is y - y1 = m (x - x1), where m is the slope and (x1, y1) is a point on the line.
What is line in point-slope form?The point-slope form of a line is given by y - y1 = m (x - x1), where (x1, y1) is a point on the line and m is the slope of the line.
In this equation, y1 and x1 are the coordinates of a point on the line, and m is the slope of the line.
So, given a point on the line, and the slope, you can use this form to write the equation of the line.
So, the equation of the line through point (1, -5) and perpendicular to y = 1/8x + 2 is y + 5 = -8(x - 1) => y = -8x + 13.
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