what why did you say you had $80.50 and you add that up

The margin of error for a 95% confidence interval for the true proportion of tongue rollers among students is closest to (d) 0.04

The margin of error is a statistic that describes how much random sampling error there is in survey results.

Given in question,

n = 400

p = 317/400

  = 0.7925

Confidence Level = 95%

                          = 0.95

Formula for margin error, E = \(z\sqrt{\frac{p(1-p)}{n} }\)

Confidence level corresponding to 95 % confidence interval, z = 1.96

Therefore,

Margin Error, E = \(1.96\sqrt{\frac{0.7925(1-0.7625)}{400} }\)

                         = 0.0397

                         ≈ 0.04

Hence, The margin of error for a 95% confidence interval for the true proportion of tongue rollers among students is 0.0397 which is closest to 0.04.

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Answer:

Step-by-step explanation:

\(\frac{d}{dx} [cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)]^4\\\\=4[cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)]^3\; \frac{d}{dx} [cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)] --- eq(1)\)

Lets look at the derivative part:

\(\frac{d}{dx} [cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)] \\\\= \frac{d}{dx}[cos(3x^2) \sqrt[3]{5x^3 -1} ] + \frac{d}{dx}[sin(4x^3)]\\\\=cos(3x^2) \frac{d}{dx}[ \sqrt[3]{5x^3 -1} ] + \sqrt[3]{5x^3 -1}\frac{d}{dx}[ cos(3x^2) ] + cos(4x^3) \frac{d}{dx}[4x^3]\\\\=cos(3x^2) \frac{1}{3} (5x^3 -1)^{\frac{1}{3} -1} \frac{d}{dx}[5x^3 -1] + \sqrt[3]{5x^3 -1} (-sin(3x^2))\frac{d}{dx}[ 3x^2] + cos(4x^3)[(4)(3)x^2]\)

\(=\frac{cos(3x^2) 5(3)x^2}{3(5x^3 - 1)^{\frac{2}{3} }} -\sqrt[3]{5x^3 -1}\; sin(3x^2) (3)(2)x + 12x^2 cos(4x^3)\\\\=\frac{5x^2cos(3x^2) }{(5x^3 - 1)^{\frac{2}{3} }} -6x\sqrt[3]{5x^3 -1}\; sin(3x^2) + 12x^2 cos(4x^3)\)

Substituting in eq(1), we have:

\(\frac{d}{dx} [cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)]^4\\\\=4[cos(3x^2) \sqrt[3]{5x^3 -1} +sin(4x^3)]^3\; [\frac{5x^2cos(3x^2) }{(5x^3 - 1)^{\frac{2}{3} }} -6x\sqrt[3]{5x^3 -1}\; sin(3x^2) + 12x^2 cos(4x^3)]\)

a. In interval notation, Increasing intervals: (12pm, 1pm) U (1pm, 2pm) U (2pm, 3pm). Decreasing intervals: (8am, 9am) U (11am, 12pm). Constant intervals: (9am, 10am) U (10am, 11am)

b. The increase in cost between 12 noon and 3 pm is $2.

c. Yellow Cab has a lower price per 1km than Swift ride at (8am, 9am) (9am, 10am) (2pm 3pm)

Interval notation is used to represent continuous intervals of numbers or values, like ranges on a number line.

The graph shows that from 8-9am, and 11-12pm, the cost from Swift Ride decreases.

We can represent it as (8am, 9am) U (11am, 12pm).

It increases at these times (12pm, 1pm) U (1pm, 2pm) U (2pm, 3pm).

And stays constant at : (9am, 10am) U (10am, 11am)

We simply deduct the 12pm's cost from 3pm's cost.

So, we have

Cost increase = $3.5 - $1.5

Evaluate the difference

Cost increase = $2

Hence, the cost increase is $2

When you plot the points provided for Yellow cab, you'll notice that Yellow Cab has a lower price per 1km than Swift ride at (8am, 9am) (9am, 10am) (2pm 3pm)

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Option D is the correct answer.

From the graph, we can conclude that,

1. The two lines are continuous lines and not broken lines. So, the inequality sign should be either ≤ or ≥.

2. The points on the lines of the shaded region are also included in the solution.

The only option that matches with the above conditions is option D. So, option D is the correct answer.

Let us verify it.

Now, let us consider a point that is inside the shaded region and also on any one line.

Let us take (0, 2).

Plug in 0 for x and 2 for y in each of the options and check which inequality holds true.

Considering the inequalities,

y ≥ 3x - 2

x + 2y ≤ 4

Solving we get,

2 ≥ 3(0) - 2

2 ≥ -2

x + 2y ≤ 4

0 + 2(2) ≤ 4

4 ≤ 4

Here, both inequalities are correct.

So, option D is the correct answer.

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The complete question is =

Which system of linear inequalities is graphed?

A. y < 3x-2

x + 2y ≥ 4

B. y < 3x - 2

x + 2y > 4

C. y > 3x - 2

x + 2y < 4

D. y ≥ 3x - 2

x + 2y ≤ 4

Answer:

so here is the answer hope it helps

The transformation of f(x) to g(x) is :

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = x

g(x) = 1/9x - 2

The graph of the functions f(x) and g(x) are added as an attachment

And we have the transformations to be:

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Answer:

MP = 19

Step-by-step explanation:

17+3y=5y+9

or, 17-9 = 5y-3y

or, 8=2y

so, y = 2

Now,

MP = 5y+9

or, MP = 5×2+9

or, MP = 10+9

so, MP = 19

The value of x when the Richter scale rating is 7.9 is approximately 79432.82

To find the value of x when the Richter scale rating is 7.9, we can follow the steps provided:

Substitute known values into the equation.

R = log(x)

R = 7.9

Raise each side of the equation as the power of the base of the log.

\(10^R = 10^(^l^o^g^(^x^)^)\)

Simplify using the property.

\(10^R = x\)

Now we can substitute the value of R (7.9) into the equation:

\(10^(^7^.^9^) = 79432.82\)

Therefore, the value of x when the Richter scale rating is 7.9 is approximately 79432.82 (rounded to the nearest hundredth

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Differentition of \(y=log_{2}x^{3}.(5x^{4}+2)\) is \(y'=log_{2}x^{3}(20x^{3} )+(5x^{4}+2)\frac{1}{x}\)

A differential equation is an equation that contains one or more functions with its derivatives.

Given,

\(y=log_{2}x^{3}.(5x^{4}+2)\)

We have to differentiate with respect to x.

y'=xy'+yx'

\(x=log_{2}x^{3}\)

\(y=5x^{4}+2\)

\(y'=log_{2}x^{3}(20x^{3} )+(5x^{4}+2)\frac{1}{x^{3}} .3x^{2}\)

\(y'=log_{2}x^{3}(20x^{3} )+(5x^{4}+2)\frac{1}{x}\)

Hence, differentiation of \(y=log_{2}x^{3}.(5x^{4}+2)\) is \(y'=log_{2}x^{3}(20x^{3} )+(5x^{4}+2)\frac{1}{x}\)

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y = 2/3x -6

Conditions for Lines to be parallel

If two straight lines are cut by a transversal, the pair of alternate angles are equal, then two straight lines are parallel to each other. the pair of interior angles on the same side of traversals is supplementary, then the two straight lines are parallel.

Given line

3y – 2x = – 2

passes through (3, –3)

The slope-intercept form is

y =mx+b,

where m is the slope and

b is the y-intercept.

y = mx+b

Divide each term in

3y – 2x = – 2 by -2 and simplify.

-3/2y +x =1

Reorder terms.

y = -(2/3)(x+1)

Using the slope-intercept form, the slope is

2/3.m=2/3

To find an equation that is parallel, the slopes must be equal. Find the parallel line using the point-slope formula.

Use the slope

2/3 and a given point (3, –3)

to substitute for

x1 and y1

in the point-slope form

y−y1=m(x−x1)

which is derived from the slope equation

m=(y2−y1)x2−x1.

y−(-3)=2/3⋅(x−(3))

Simplify the equation and keep it in point-slope form.

y+4=2/3⋅(x-3)

y = 2/3x -6

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Answer:19.26%

Step-by-step explanation: yeah

Answer:

19%

Step-by-step explanation:

There are only 5 steps here they are:

1. Divide 144.77 by 179.30

2. You get the answer 0.80741773...

3. You round it to 0.81.

4. You turn it into a percent by moving the dot(decimal) to the right four times.

5. And then you subtract it from 100 and you get 19% for the discount.

so therefore the answer is 19%

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There is approximately an 89.44% probability that a box of cereal is underfilled by 5 g or more.

To find the probability that a box of cereal is underfilled by 5 g or more, we need to calculate the probability of obtaining a weight measurement below 345 g.

First, we can standardize the problem by using the z-score formula:

z = (x - μ) / σ

Where:

x = the weight value we want to find the probability for (345 g in this case)

μ = the mean weight (350 g)

σ = the standard deviation (4 g)

Substituting the values into the formula:

z = (345 - 350) / 4 = -1.25

Next, we can find the probability associated with this z-score using a standard normal distribution table or a statistical calculator.

The probability of obtaining a z-score less than -1.25 is approximately 0.1056.

However, we are interested in the probability of underfilling by 5 g or more, which means we need to find the complement of this probability.

The probability of underfilling by 5 g or more is 1 - 0.1056 = 0.8944, or approximately 89.44%.

Therefore, there is approximately an 89.44% probability that a box of cereal is underfilled by 5 g or more.

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Answer:

original number = 53

Step-by-step explanation:

In two digits number:

Let the tens place digit be x and units place digit be y.

So,

Original number = 10x + y

Number obtained after reversing the digits = 10y + x

According to the first condition:

x + y = 8.... (1)

According to the second condition:

10y + x = 10x + y - 18

10y + x - 10x - y = - 18

9y - 9x = - 18

-9(x - y) = - 18

x - y = - 18/(-9)

x - y = 2.......(2)

Adding equations (1) & (2), we find

x + y + x - y = 8 + 2

2x = 10

x = 10/2

x = 5

Plug x = 5 in equation (1), we find:

5 + y = 8

y = 8 - 5

y = 3

10x + y = 10*5 +3 = 50 + 3 = 53

Hence, original number = 53

Answer:

8.25 minutes

Step-by-step explanation:

31 minutes-6.25 minutes=24.75 remaining miutes between the last 3 miles so then you take 24.75 minutes÷ 3 miles remaining= 8.25 minutes each last 3 miles

Answer:

Step-by-step explanation:

Put these numbers into their prime factors.

18: 2 * 3 * 3

27: 3 * 3 * 3

12: 2 * 2 * 3

The LCM must have

two 2s

Three 3s

That's it

2*2 * 3 * 3 * 3

LCM = 108

648 might be a multiple of the three, but it's not the smallest one.

108 = 27 * 4

108 = 18 * 6

108 = 12 * 9

Note that in the prompt above, the value of x is given as: 16°

To answer the issue, we will first name all of the points supplied to us on the isosceles triangle, then identify O, and last discover the value of x. See the attached image.

As a result, an isosceles triangle has two equal sides and two equal angles. The term is derived from the Greek words iso (same) and skelos (skull) (leg). An equilateral triangle has all of its sides equal, whereas a scalene triangle has none of its sides equal.

In ΔAOB

OA =  OB = R, the radius of the circle O,

therefore, the ΔAOB is an isosceles triangle, with OA, OB as the congruent sides and AB as the base of the triangle.

Thus, ∠OAB = ∠OBA = 53°

Sum of all the angles of a triangle = 180°

∠O + ∠AOB + ∠OBA = 180°

We know ∠AOB = ∠OBA, therefore,

∠O + 2(∠AOB) = 180°

∠O + 2(53°) = 180°
∠O = 180 - 106

∠O = 74°

In ΔOBC,

BC is the tangent to the circle O, therefore,

∠OBC = 90°

Sum of all the angles of a triangle = 180°

∠O + ∠OBC + ∠OCB = 180°

74° + 90° + ∠OCB = 180°

∠OCB = 180° - 74° - 90°

∠OCB = 16°

Hence, the value of x is 16°.

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Answer:

$-33

Step-by-step explanation:

Andre still owes Billy money. If Andre paid Billy the 39 dollars he has, he would still owe Billy $33, which puts him $33 in the hole.

Answer:

who asked

Step-by-step explanation:

Answer:

its A

Step-by-step explanation:

Answer:

\(1. \: 9tx {}^{2} - 3tx - 2t \\ \\ 2. \: 3tx {}^{2} + 2tx + 2t\)

Step-by-step explanation:

\(1. \: t(9x {}^{2} - 3x - 2) \\ 2. \: 9tx {}^{2} - 3tx - 2t \\ \\ \\ 1. \: t \times 3x {}^{2} + t \times 2x + t \times 2 \\ 2. \: 3tx {}^{2} + t \times 2x + t \times 2 \\ 3. \: 3tx {}^{2} + 2tx + t \times 2 \\ 4. \: 3tx {}^{2} + 2tx + 2t\)

Scale of the model is found to be 1 : 30 using the ratio method.

A model of a car is 4 inches long.

The actual car is 10 feet long.

 4 in. = 10 ft. ( since given )

Divide both sides by 4, we get

∴ 1 in. = 2.5 ft.

We use the ratio here to compare the lengths of the actual car and its model.

A ratio scale is a quantitative measurement scale that is used to compare numbers.

The model is 4 inches long while the actual car is 10 feet long.

One foot is equal to 12 inches. Therefore the car in terms of inches is:

10 feet × 12 inches = 120 inches

The ratio scale is the length of the model of the car : length of the actual car

= 4 : 120

= 1 : 30

Therefore the scale of the model is 1: 30.

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Answer:

=========================

Compare all of the corresponding parts.

All three angles are congruent

Corresponding sides have a ratio of 2.

According to our findings the triangles are similar:

Answer:

ΔABC and ΔDEF are similar triangles as their corresponding angles are the same and their corresponding sides are in proportion.

Step-by-step explanation:

Definitions

Two triangles are said to be congruent if their corresponding angles are the same and their corresponding sides are the same.

Two triangles are said to be similar if their corresponding angles are the same and their corresponding sides are in proportion.

From inspection of the given diagram, the corresponding angles of ΔABC and ΔDEF are the same, but their corresponding sides are in proportion. Therefore, they are similar triangles.

Proof of proportionality:

\(\sf AB = 5, \;\;DE = 10\;\;\implies \dfrac{DE}{AB} = \dfrac{10}{5}=2\)

\(\sf AC = 4, \;\;DF = 8\;\; \implies \dfrac{DF}{AC} = \dfrac{8}{4}=2\)

\(\sf BC = 2, \;\;EF = 4\;\; \implies \dfrac{EF}{BC} = \dfrac{4}{2}=2\)

Therefore, the sides of ΔDEF are twice the length of the sides of ΔABC.

The probability of roll outcome:

1st 2 = 1/6

2nd prime = 1/2, and

3rd more than 4 = 1/3.

Probability is the fraction of the required outcome event divided by the number of possible outcomes of events.

In a fair die, considering the outcomes from the question:

probability of the 1st roll to be 2 = 1/6

probability of 2nd roll to be prime = 3/6

probability of 2nd roll to be prime = 1/2

probability of 3rd roll to be more than 4 = 2/6

probability of 3rd roll to be more than 4 = 1/3

Therefore, the fracions 1/6, 1/2, and 1/3 are the probabilities of the 1st, 2nd, and 3rd rolls outcome respectively.

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Answer:

negative, positive, zero, and undefined

Step-by-step explanation:

The diameter of the tin in the picture is  \(3d/5\) where 'd' is the diameter of the tin in reality.

Determining the diameter of tin:

Since there is no indication of dimensions, represent the diameter with a variable 'd' and find the diameter of the tin according to the given condition in the problem.

Here we have assumed that the diameter of the tin is 'd' in reality and the diameter of the tin picture can be calculated as given below.  

Here we have

A ricoffy tin container with no dimensions indicated

Let d and h be the diameter and height of the tin

Given that the container is 2/5 times smaller than d

then the diameter of the tin in the picture \(= d - 2/5(d)\)

\(= [5d - 2d]/5 = 3d/5\)

Therefore, The diameter of the tin in the picture is  \(3d/5\) where 'd' is the diameter of the tin in reality.

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The requried center and radius of the given circle are (2, -4) and 5.

The standard equation of a circle is given as,
(x - h)² + (y - k)² = r²

Where, (h, k) is the center of the circles and r is the radius of the circle,

The equation of the given circle is,
(x - 2)² + (y + 4)² = 25

Comparing the above equation with the standard equation we have,
(h, k) = (2, -4)

r² = 5²; r =5

Thus, the requried center and radius of the given circle is (2, -4) and 5.

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