What will be printed ?
int i = 16, j = 5;
while(i != 0 && j != 0){
i = i/j;
j = (j-1)/2;
System.out.println(i + " " + j + " ");
}
What will be printed ?
for(int i = 1; i <= 2; i++){
for(int j = 1; j <= 3; j++){
for(int k = 1; k <= 4; k++){
System.out.print("*");
}
System.out.print("!");
}
System.out.println();
}

Answer:

The relief valve will open as pressure caused by a downstream load or backpressure increases high enough to force the poppet or spool open against its spring.

Explanation:

True. 300-5(F) of the National Electric Code (NEC) specifies the requirements for backfill used for underground wiring.

According to this section, the backfill material used must not damage the wiring method, contribute to the corrosion of the raceway, or prevent compaction of the fill. This is important to ensure the long-term safety and reliability of the electrical system, as damage or corrosion to the wiring method can increase the risk of electrical hazards, such as shocks, fires, or explosions. By using an appropriate backfill material that meets the NEC requirements, the wiring method can be protected from damage and corrosion, and the overall safety and reliability of the electrical system can be maintained.

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Answer:

a. T-V and P-V diagram are included

b. State 1: Specific volume = 0.0811753 m³/kg

State 2: Specific volume = 0.0811753 m³/kg

State 3: Specific volume = 0.0804155 m³/kg

c. Z = 51.1

d. Quality for state 1 = 100%

Quality for state 2 = 63.47%

Quality for state 3 = 100%

Explanation:

a. T-V and P-V diagram are included

b. State 1: Water vapor

P₁ = 3.0 MPa = 30 bar

T₁ = 300°C = 573.15

Saturation temperature = 233.86°C Hence the steam is super heated

Specific volume = 0.0811753 m³/kg

State 2:

Constant volume formula is P₁/T₁ = P₂/T₂

Specific volume = 0.0811753 m³/kg

T₂ = 200°C = 473.15

Therefore, P₂ = P₁/T₁ × T₂ = 3×473.15/573.15 = 2.4766 MPa

At T₂ water is mixed water and steam and the \(v_f\) = 0.00115651 m³/kg

\(v_g\) = 0.127222 m³/kg

State 3:

P₃ = 2.5 MPa

T₃ = 200°C

Isothermal compression P₂V₂ = P₃V₃

V₃ = P₂V₂ ÷ P₃ = 2.4766 × 0.0811753/2.5 = 0.0804155 m³/kg

Specific volume = 0.0804155 m³/kg

2) Compressibility factor is given by the relation;

\(Z = \dfrac{PV}{RT} = \dfrac{3\times 10^6 \times 0.0811753 }{8.3145 \times 573.15} = 51.1\)

Z = 51.1

3) Gas quality, x, is given by the relation

\(x = \dfrac{Mass_{saturated \, vapor}}{Total \, mass} = \dfrac{v - v_f}{v_g - v_f}\)

Quality at state 1 = Saturated quality = 100%

State 2 Vapor + liquid Quality

Gas quality = (0.0811753 - 0.00115651)/ (0.127222-0.00115651) = 63.47%

State 3: Saturated vapor, quality = 100%.

Answer: The solar irradiance is measured in watt per square metre (W/m2) in SI units. Solar irradiance is often integrated over a given time period in order to report the radiant energy emitted into the surrounding environment (joule per square metre, J/m2) during that time period.

Explanation: hope that helped!

This question is incomplete, the complete question is;

An individual eats fish from a river contaminated with benzene. What concentrations of benzene in water (mg/L) would produce a lifetime cancer risk of 10⁻⁶ to an individual who eats 2 meals of fish per week for 30 years if the BCF for benzene is 10⁺³?

Answer:

0.021 mg/L concentration of benzene in water  would produce a lifetime cancer risk 10⁻⁶ to an individual who eats 2 meals of fish per week for 30 years if the BCF for benzene is 10⁺³

Explanation:

Chronic daily intake (CDI) =(C/W) (Intake rate/ lifetime) ( Exposure)

values from EPA Exposure Factors Table)

CDI = [ (5.2 L/d × C mg/L  0.054 kg/d) / 70 kg] [30/70] [350/365]

CDI = 1.65 × 10⁻³C

Now concentration of benzene;  ( RISK) = CDI × pF

= 10⁻⁶ = [2.9× 10⁻² / (MG/kg-d)] ( 1.65 × 10⁻³C)

C = 0.021 mg/L

Therefore 0.021 mg/L concentration of benzene in water  would produce a lifetime cancer risk 10⁻⁶

These five sources of authority were named as coercive, rewarding, legitimate, referent, and expert.

French and Raven (1959) proposed five power dynamics (or bases of power): referent, expert, legitimate, reward, and coercive. Coercive power, expert power, legitimate power, referent power, and reward power are the five types of power that can be seen in organizational behavior. The authority that stems from an organization and gives the leader the ability to exercise power are the bases of power. Power originates from five different system: referent, expert, legitimate, coercive, and reward. Each partnership has its own unique power dynamics at any given time. Because each party has enough negotiating power to ensure mutually beneficial outcomes, mutually dependent relationships frequently produce exceptional value addition.

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Your Answer would be A I believe.

Answer:

there are no attachments

Explanation:

The recognized national standard in the United States for safety in welding is known as the American National Standards Institute/American Welding Society (ANSI/AWS) Z49.1, Safety in Welding, Cutting, and Allied Processes.

ANSI/AWS Z49.1 is a safety standard established jointly by the American Welding Society (AWS) and the American National Standards Institute (ANSI).

It specifies procedures and methods for safely welding, cutting, and other allied processes.

The standard outlines general safe practices for all welding operations, as well as specific requirements for welding and cutting particular types of materials. It also defines personnel safety and training, protective equipment, ventilation, and other safety requirements for welding processes

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The recognized national standard in the United States for safety in welding. It provides a comprehensive guide to safe welding operations, including requirements for welding procedures, protective equipment, and personnel qualifications.

Welding is the procedure of joining two metals together by heating them to a melting point and joining them by pressing, hammering, or rolling the metals together when they cool and solidify.

Welding is a prevalent industrial operation that can pose significant health and safety hazards to welders and others nearby, such as skin burns, eye damage, inhalation of fumes and gases, and hearing loss. Many safety precautions are needed to avoid these risks.The American National Standard Institute (ANSI) is a national organization that sets rules and standards for a variety of products and services, including welding safety.  It details the guidelines and best practices for safe welding operations to prevent harm to welders, bystanders, and the environment.

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The height specific of the wall should be measured numerous times throughout its length by the engineer, who should average the results.

A wall's height may vary by several centimeters at various spots along its length, making it challenging to measure with a millimeter ruler. The engineer should measure the wall numerous times along its length and average the data to assure accuracy. The height of the wall should be measured numerous times throughout its length by the engineer, who should average the results. This will provide a more accurate measurement of the wall's height while taking any variations into consideration. In order to obtain the most precise reading, the engineer should measure the wall at spots that are spaced as evenly as possible. The most precise result is obtained by taking several measurements and averaging them.

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Answer:

do you have to make the right decisions to be a person who has been a member who is not the first time a great person who has a job in a day of his life or

Answer:

the third anwser is right on edgeinuity

Explanation:

Answer:

Technology can pull students’ focus away from their tasks.

Explanation:

Answer:

Reflection

Explanation:

The specific behavior of light that will be essential to ensure the success of your design is "Reflection". This is because light maze makes use of a mirror and it's the light that is reflected that we see with our eyes. Also, the manner in which light is reflected off objects will affect the colors that are reflected as well.

Using the knowledge in computational language in JAVA it is possible to write a code that  produces an error when trying to retrieve the formContext object by using the getFormContext method.

function commonEventHandler(executionContext) {

   var formContext = executionContext.getFormContext();    

   var telephoneAttr = formContext.data.entity.attributes.get('telephone1');

   var isNumberWithCountryCode = telephoneAttr.getValue().substring(0,1) === '+';

   // telephoneField will be a form control if invoked from a form OnChange event;

   // telephoneField will be a editable grid GridCell object if invoked from editable grid OnChange event.

   var telephoneField = telephoneAttr.controls.get(0);

   if (!isNumberWithCountryCode) {

       telephoneField.setNotification('Please include the country code beginning with '+'.', 'countryCodeNotification');

   }

   else {

       telephoneField.clearNotification('countryCodeNotification');

   }

}

function onstop(executionContext) {

   var formContext = executionContext.getFormContext();

   var stop = formContext.getAttribute("abs_onstop").getValue();

   if (stop == true)

   {

       formContext.ui.setFormNotification("This account has been placed ON STOP!", "WARNING", "OnStop");

   }

   else

   {

       formContext.ui.clearFormNotification("OnStop");

   }

}

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Answer:

The answer is "\(I = 0.0085106383 \ A\)"

Explanation:

Given:

\(R= 470 \ \Omega \\\\V= 4 \ v\)

Formula:

\(\to V=IR\\\\\to I = \frac{V}{R}\\\\\)

      \(= \frac{4}{470}\\\\ = 0.0085106383 \ A\)

Using  Bernoulli equation we can say that the pressure required at the nozzle inlet, meaning P1, to yield an exit speed of 50 m/s is 1.48 kPa.

equations that control:

\(\frac{p_{1}}{\rho}+\frac{V_{1}^{2}}{2}+g z_{1}=\frac{p_{2}}{\rho}+\frac{V_{2}^{2}}{2}+g z_{2}\)

Continuity for incompressible and uniform flow:

\(\sum_{\mathrm{CS}} \vec{V} \cdot \vec{A}=0\)

We know that  

1)   Steady flow.

(2) Incompressible flow.

(3) Frictionless flow.

(4) Flow along a streamline.

(5)\(z_{1}=z_{2}\)

(6) Uniform flow at sections (1) and (2).

The maximum speed of 50 m/s is well below 100 m/s, which corresponds to Mach number M≈0.3 in standard air. Hence, the flow may be treated as incompressible.

Apply the Bernoulli equation along a streamline between points (1) and (2) to evaluate \(p_{1}\)

p1 − patm = p1 − p2 = ρ/2  (V2^2 −V1^2)

-ρV₁A₁ + ρV₂A₂ = 0 or V₁A₁ =  V₂A₂

V₁ = V₂A₂/A₁ = 50 x 0.02/0.10 = 10 m/s

Since air at standard condition , ρ = 1.23 kg/m³

p1 − patm = ρ/2. (V₂²^2−V₁^²)

= 1/2 × 1.23 x (50² −10²)

= 1.48kPa

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Answer:

section view in a general plan.

Explanation:

In Engineering, it is a standard and common practice to use drawings and models in the design and development of buildings, tools or systems that are being used for proffering solutions to specific problems in different fields such as banks, medicine, telecommunications and industries.

Hence, an architect or design engineer make use of drawings such as pictorial drawings, sketches, or architectural (technical) drawing to communicate ideas about a plan (design) to others, record and retain informations (ideas) so that they're not forgotten and analyze how different components of a plan (design) work together.

Architectural drawing is mainly implemented with computer-aided design (CAD) software and it's typically used in plans and blueprints that illustrates how to construct a building or an object.

Additionally, architectural drawings such as a section view in a general plan, show in detail how the areas of a building relate to each other, as well as accurately illustrating the actual (true) shape and size of a building in the design and development process.

In this scenario, Bruce wants to present to his client an architectural drawing that shows the exact details of a living room, kitchen, bedroom and stairs in relation to other areas of the house. Thus, the type of architectural drawings Bruce should use is a section view in a general plan.

A section view presents a vertical perspective or view by slicing through the building; revealing the exact details of wall construction, floor-to-floor construction, height and thickness of beam, and other support systems with respect to the living room, kitchen, bedroom, etc., in the building.

The maximum number of IPsec tunnels that can be associated with a tunnel interface on a Palo Alto Networks firewall varies based on the specific model and software version.

When configuring a Palo Alto Networks firewall, administrators can associate up to 1,000 IPsec tunnels with a tunnel interface. This limit determines the number of secure connections that can be established between the firewall and other network devices using IPsec protocols.

It is important to consider this limitation while designing and implementing VPN (Virtual Private Network) solutions or connecting remote sites securely.

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A genetic algorithm is an approach to solving problems based on the:

b. theory of evolution

A genetic algorithm is a problem-solving approach that uses the principles of natural selection and genetics to find optimized solutions. It is based on the idea that the fittest individuals are more likely to survive and pass on their genes to the next generation. Therefore, a genetic algorithm generates a population of potential solutions, evaluates their fitness, selects the fittest individuals, and uses them to produce the next generation of solutions through crossover and mutation. This process is repeated until an optimal solution is found.

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The velocity when the cable becomes taut can be obtained by assuming

that the tugboat collides with a barge moving in the same direction.

Response (approximate value):

Weight of the tugboat, m₁ = 240–ton

Speed of the tugboat, v₁ = 6 ft./s

Weight of the barge, m₂ = 100–ton

Rate at which the towing cable is being unwound, v₂ = 5.4 ft./s

Required:

Velocity of the tugboat after the cable becomes taut.

Solution:

m₁ = 240 ton = 240,000 kg

m₂ = 100 ton = 100,000 kg

The velocity of the barge at rest is assumed to be the rate at which the cable is being unwound, and in the direction of the tugboat.

According to the law of conservation of linear momentum, we have;

m₁ × v₁ + m₂ × v₂ = (m₁ + m₂) × v₃

Which gives;

240 × 6 + 100 × 5.4 = (240 + 100) × v₃

1980 = 340 × v₃

Which gives;

\(v_3 = \dfrac{1980}{340} = \dfrac{99}{17} = 5\frac{14}{17} \approx \mathbf{ 5.824}\)

The velocity of the tugboat after the rope becomes taut is 5.824 ft./s

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Answer:

Gear Y would turn Counter-Clockwise do to the opposite force created from gear X.

                          Hope this helped!  Have a great day!

Answer:

there is no illustration ..

i guess it reminds me of nothing since nothings there ..

Explanation:

When using Scrum, a Sprint should last one month. The Sprint time frame for Scrum projects typically ranges from two weeks to a maximum of four weeks.

Scrum is a flexible framework for product development that helps teams work together to create quality results. Scrum uses the empirical approach, which is based on three pillars: transparency, inspection, and adaptation. These three pillars work together to help teams deliver better-quality products faster.

The non-value-added work is defined as Process essential tasks that do not add value to the customer. It involves steps that do not contribute to the product's design, creation, or distribution. In a value stream, value-added activities are those that contribute to the product's creation or distribution, whereas non-value-added activities do not contribute to the product's value.The greatest concern about an excessive amount of inventory is excess storage costs. Holding inventory is necessary for the smooth operation of many businesses, but excessive inventory can be problematic.

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The deformation at the point of B is 1.09 mm

Deformation refers to the change in shape or size of a material due to the application of external forces or stress. It is a common phenomenon in materials science and engineering, and it plays an important role in the behavior and performance of materials under various conditions.

E = 70 Gpa

P = 90 KN

For every section

A and B

125 - 90

= 35

For B and C

75 + 50 = 125

For C and D

50

we have

\(\frac{35*10^3*1.75}{800*10^6*70*10^9}\)

= \(\frac{61250}{800000000 * 5.6*10^1^9}\)

= 1.09 mm

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The steel pipe with an inner diameter of 2.75 inches and an outer diameter of 3 inches is fixed at point C and subjected to a horizontal 60-lb force applied at the end of a pipe wrench handle. The state of stresses at point A, located on the outer surface of the pipe, needs to be determined, including the principal stresses.

Since the pipe is fixed at point C, the force applied at the end of the pipe wrench handle will induce stresses in the pipe. Considering the symmetry of the pipe, the stresses can be assumed to be uniform around its circumference.

To determine the state of stresses at point A, we can analyze the situation using basic principles of mechanics. The force applied by the pipe wrench handle will induce a tensile stress on the outer surface of the pipe and a compressive stress on the inner surface. Due to the applied force, there will also be a shearing stress acting tangentially to the pipe's circumference.

To calculate the stresses more precisely, we can utilize the concept of stress concentration factor. The change in pipe diameter from 2.75 inches to 3 inches will result in stress concentration at point A. By using appropriate formulas and equations, the actual magnitudes of tensile and compressive stresses at point A can be determined.

To find the principal stresses at point A, we need to determine the maximum and minimum stresses acting on the pipe. The principal stresses occur when the shearing stress is zero. By applying stress transformation equations and solving for the principal stresses, we can determine the values and their orientation relative to the applied force.

In conclusion, by analyzing the given parameters and employing principles of mechanics, the state of stresses in the steel pipe at point A, including the principal stresses, can be determined.

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Answer:

I think its A

Explanation: