whats (-1) - (1/3)
please hurry
(in the form of a fraction)
Answers
lollllll
Related Questions
is 7.153153 rational?
Answers
9514 1404 393
Answer:
yes
Step-by-step explanation:
The number has a finite number of digits, so is rational.
__
Additional comment
It would also be rational if it had an infinite number of digits with the decimal fraction ending in a finite-length portion that repeats.
The car travels 440 miles in 8 hours.what is the unit rate
Answers
Answer:
55 Miles Per Hour
Step-by-step explanation:
440 miles / 8 hours = 55 miles per hour.
ANSWER IMMEDIATELY
Which of the following best describes the number of solutions to the system of equations shown below?
2x+y=3
-4x-2y=-6
Answers
Answer:
2*1/2+2=3
-4x-2y=-6 is x=−1/2y+3/2
Step-by-step explanation:
Help plz!! Has to do with concepts
Answers
Answer:
f(2) =4, f(4) =4, x=8, x=3
Step-by-step explanation:
f(2) is asking for what the y value is when x is 2. f(4) is also asking what the y value is when x=4. When y=-2 the x is 8 and when the y=6 x=4. I hope this is helpful.
Let Θ represent an angle in radians. (Don’t worry about converting radians to degrees. Leave everything in radians). The Functions class contains two non static methods: f and g. f takes in a value of Θ and returns a value of sin(2Θ). g takes in a value of Θ returns a value of cos(3Θ).
Display Info only has one NON static functions called printStuff. It will print the values of Θ, sin(2Θ), cos(3Θ), and tan Θ in columns (which should be properly labelled) to the console.
Program.cs puts everything together. In this class you will determine the Θ values to be used. You will prompt the user to type in a lower value for Θ (this will be your first Θ used in the calculation) and an upper value of Θ (this will be your last value of Θ used in the calculation). You will then prompt the user for the number of equally spaced Θ values they would like to have. For examples, if the lower limit of Θ is -5 and the upper limit of Θ is 5 and the user wants 100 equally spaced values of Θ, the Θ values would be -5, -4.9, -4.8, -4.7 ......0 .....4.7, 4.8, 4.9, 5
Remember, the output table should have four columns: one column with θ double precision values ranging from some lower limit (ie -5) to an upper limit (ie 5), a second column with values x=sin(2 Θ),a third column with values y=cos(3 Θ) and z = tan Θ.
Answers
Here is an example implementation of the provided classes and their methods in C#:
```csharp
using System;
public class Functions
{
public double f(double theta)
{
return Math.Sin(2 * theta);
}
public double g(double theta)
{
return Math.Cos(3 * theta);
}
}
public class DisplayInfo
{
public void PrintStuff(double theta, double sin2Theta, double cos3Theta, double tanTheta)
{
Console.WriteLine("θ\t\tsin(2θ)\t\tcos(3θ)\t\ttan(θ)");
Console.WriteLine($"{theta:F2}\t\t{sin2Theta:F2}\t\t{cos3Theta:F2}\t\t{tanTheta:F2}");
}
}
public class Program
{
public static void Main(string[] args)
{
Console.WriteLine("Enter the lower limit of Θ:");
double lowerLimit = double.Parse(Console.ReadLine());
Console.WriteLine("Enter the upper limit of Θ:");
double upperLimit = double.Parse(Console.ReadLine());
Console.WriteLine("Enter the number of equally spaced Θ values:");
int numValues = int.Parse(Console.ReadLine());
double step = (upperLimit - lowerLimit) / (numValues - 1);
double currentTheta = lowerLimit;
Functions functions = new Functions();
DisplayInfo displayInfo = new DisplayInfo();
Console.WriteLine("θ values\t\tsin(2θ)\t\tcos(3θ)\t\ttan(θ)");
for (int i = 0; i < numValues; i++)
{
double sin2Theta = functions.f(currentTheta);
double cos3Theta = functions.g(currentTheta);
double tanTheta = Math.Tan(currentTheta);
displayInfo.PrintStuff(currentTheta, sin2Theta, cos3Theta, tanTheta);
currentTheta += step;
}
}
}
```
When you run the program, it will prompt the user to input the lower limit of Θ, upper limit of Θ, and the number of equally spaced Θ values. It will then calculate the corresponding values for sin(2Θ), cos(3Θ), and tan(Θ) using the given formulae and print them in columns labeled as θ, sin(2θ), cos(3θ), and tan(θ) to the console. The θ values will range from the lower limit to the upper limit with the specified number of equally spaced values.
To run the program, you can compile it and run it in the command prompt or terminal. Or you can use an IDE like Visual Studio or JetBrains Rider to build and run the code.
Here's an example implementation:
csharp
using System;
class Functions
{
public double f(double theta)
{
return Math.Sin(2 * theta);
}
public double g(double theta)
{
return Math.Cos(3 * theta);
}
}
class DisplayInfo
{
public void printStuff(double[] thetas, Functions functions)
{
Console.WriteLine("{0,-10} {1,-10} {2,-10} {3,-10}", "Theta", "sin(2Theta)", "cos(3Theta)", "tan(Theta)");
foreach (double theta in thetas)
{
double x = functions.f(theta);
double y = functions.g(theta);
double z = Math.Tan(theta);
Console.WriteLine("{0,-10:F5} {1,-10:F5} {2,-10:F5} {3,-10:F5}", theta, x, y, z);
}
}
}
class Program
{
static void Main(string[] args)
{
Functions functions = new Functions();
DisplayInfo displayInfo = new DisplayInfo();
Console.Write("Enter lower value for Theta: ");
double lowerLimit = double.Parse(Console.ReadLine());
Console.Write("Enter upper value for Theta: ");
double upperLimit = double.Parse(Console.ReadLine());
Console.Write("Enter number of equally spaced Theta values: ");
int numValues = int.Parse(Console.ReadLine());
double[] thetas = new double[numValues];
double stepSize = (upperLimit - lowerLimit) / (numValues - 1);
for (int i = 0; i < numValues; i++)
{
thetas[i] = lowerLimit + i * stepSize;
}
displayInfo.printStuff(thetas, functions);
}
}
This program defines a Functions class with the f and g methods, a DisplayInfo class with the printStuff method, and a Program class with the main method that prompts the user for input and generates the values of Theta and prints the output table.
To run the program, you can compile it and run it in the command prompt or terminal. Or you can use an IDE like Visual Studio or JetBrains Rider to build and run the code.
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Use the equation to complete the table.
y = 9x + 3
PLS HELP!
Answers
Answer:
39
66
93
Step-by-step explanation:
y= 9x4+3
y=36+3
y=39
y= 9x7+3
y=63+3
y=66
y= 9x10+3
y=90+3
y=93
What is a parallelogram
Answers
Answer:
a four-sided plane rectilinear figure with opposite sides parallel.
Step-by-step explanation:
a decimal number in which a digit or group of digits
repeats without end
Answers
Answer:
that is called a repeating decimal.
Step-by-step explanation:
The model represents a polynomial and its factors. An algebra tile configuration. 4 tiles are in the Factor 1 spot: 1 is labeled x and 3 are labeled negative. 2 tiles are in the Factor 2 spot: 1 is labeled x and 1 is labeled negative. 8 tiles are in the Product spot: 1 is labeled x squared, 4 are labeled negative x, and 3 are labeled. Which equation is represented by the model? x2 â€" 2x â€" 3 = (x â€" 3)(x 1) x2 â€" 4x 3 = (x â€" 3)(x â€" 1) x2 2x 3 = (x 3)(x â€" 1) x2 4x â€" 3 = (x 3)(x 1).
Answers
The model is a representation of the polynomial factors using algebraic
tiles.
The equation represented by the model is the option;
\(\underline{x^2 - 4 \cdot x + 3 = (x - 3) \cdot (x - 1)}\)Reasons:
The parameters of the model of the polynomial and the factors of the
polynomial are;
The number of factors of the polynomial = 2
Number of tiles in the factor 1 spot = 4 tiles, including;
1 of the four tiles is labelled x
3 of the four tiles is labelled -ve
Therefore;
A factor of the polynomial is x-tile, -tile, -tile, -tile = (x tile - 3 tiles) = (x - 3)
Number of tiles in the factor 2 spot = 2 tiles which are;1 of the two tiles is labelled x
1 of the two tiles is labelled -ve
Which gives;
A factor of the polynomial is x, -tile = (x-tile - 1 tile) = (x - 1)
Number of tiles in the Product spot = 8 tilesThe 8 tiles are as follows;
1 of the 8 tiles is labelled x²
4 of the 8 tiles are labelled -x
3 of the 8 tiles are labelled +
Which gives;
The product of the polynomial is; (x²-tile - 4·x-tiles + 3-tiles) = (x² - 4·x + 3)
Multiplying the factors gives;
(x - 3) × (x - 1) = x² - 3·x - x + 4 = x² - 4·x + 3
The correct option is therefore;
\(\underline{x^2 - 4 \cdot x + 3 = (x - 3)\cdot (x - 1)}\)The question options are;
x² - 2·x - 3 = (x - 3)·(x + 1)
x² - 4·x + 3 = (x - 3)·(x - 1)
x² + 2·x + 3 = (x + 3)·(x - 1)
x² + 4·x - 3 = (x + 3)·(x + 1)
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3. Find \( y^{\prime} \) for the following implicit function \( y^{2}-x^{2} y=-2 \)
Answers
The derivative \(\( y' \)\) of the implicit function \(\( y^2 - xy = -2 \)\) is 0, indicating a constant slope with no change in relation to \(\( x \)\).
To find \(\( y' \)\)for the implicit function \(\( y^2 - xy = -2 \)\), we can differentiate both sides of the equation with respect to \(\( x \)\) using the chain rule. Let's go step by step:
Differentiating \(\( y^2 \)\) with respect to \(\( x \)\) using the chain rule:
\(\[\frac{d}{dx}(y^2) = 2y \cdot \frac{dy}{dx}\]\)
Differentiating \(\( xy \)\) with respect to \(\( x \)\) using the product rule:
\(\[\frac{d}{dx}(xy) = x \cdot \frac{dy}{dx} + y \cdot \frac{dx}{dx} = x \cdot \frac{dy}{dx} + y\]\)
Differentiating the constant term (-2) with respect to \(\( x \)\) gives us zero since it's a constant.
So, the differentiation of the entire equation is:
\(\[2y \cdot \frac{dy}{dx} - (x \cdot \frac{dy}{dx} + y) = 0\]\)
Now, let's rearrange the terms:
\(\[(2y - y) \cdot \frac{dy}{dx} - x \cdot \frac{dy}{dx} = 0\]\)
Simplifying further:
\(\[y \cdot \frac{dy}{dx}\) \(- x \cdot \frac{dy}{dx} = 0\]\)
Factoring out:
\(\[(\frac{dy}{dx})(y - x) = 0 \]\)
Finally, solving:
\(\[\frac{dy}{dx} = \frac{0}{y - x} = 0\]\)
Therefore, the derivative \(\( y' \)\) of the given implicit function is 0.
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Evaluate the line integral of \int (3x^2-2y)ds over the line segment from (3,6) to (1,1). Use the...
Answers
The line integral is 32.3110. The process of calculating this has been explained below.
Our line segment has a slope that is given by = m = 6 - 1 / 3 - 1
= m = 5/2
From this, we use a line's point-slope form and write this in the form -
= y−1=5/2(x−1)
= y = 5/2x−3/2
From this, we get x ∈ [3,1]. Now, we will -
= dy/dx = d/dx(5/2x−3/2) =5/2
From this, we can conclude that the line element is going to be -
= ds = \(\sqrt{\frac{dy}{dx}^{2} + 1dx }\)
= ds = \(\sqrt{\frac{5}{2}^{2} + 1dx }\)
= ds = \(\sqrt{29}\)/2 dx
No, we integrate the given integral -
= \(\int\limits^1_3 {[3x^{2} - 2(\frac{5}{2}x - \frac{3}{2} ) ]\frac{\sqrt{29}}{2} } \, dx\)
By integrating this, we get -
= 32.3110
The complete question that you might be looking for is -
Evaluate the line integral of \int (3x^2-2y)ds over the line segment from (3,6) to (1,1). Use the equation of the line (y=mx+b) to solve.
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in a square garden plot (with an area of 400 sq ft)deer fencing priced at $1.50 per foot is to be installed around the plot. if sales tax is 7% how much will fencing price cost? (do not round)
Answers
We have a square garden of 400 square foot.
The area of a square is:
\(A=x^2\)where x: side length.
In this case:
\(\begin{gathered} A=400=x^2 \\ x=\sqrt[]{400}=20\text{ ft} \end{gathered}\)The perimeter of the square is the sum of the lengths of the sides of the square. As they are all equal, we can write:
\(P=4x=4\cdot20=80\text{ ft}\)The fencing is priced at $1.50 per foot. If we add the 7% sales tax to this price we get:
\(C=1.50\cdot(1+0.07)=1.50\cdot1.07=1.605\text{ \$/ft}\)The fencing will be installed in all the perimeter (80 ft).
We can calculate the total cost by multiplying the sales price ($1.605 per foot) and the perimeter (80 ft):
\(F=C\cdot P=1.605\frac{\text{\$}}{\text{ft}}\cdot80\text{ ft}=\$128.40\)Answer: the fencing will cost a total of $128.40
if 2\(\frac{1}{3}\) : 4 \(\frac{1}{3}\) , then 7 : ___
A: 12 B: 13 C: 8\(\frac{2}{3}\) D: 6\(\frac{1}{3}\)
temsuyanger, I don't want your BS answer
Answers
\( \\ \tt \longmapsto 2 \frac{1}{3} \div 4\frac{1}{3} = \frac{7}{x} \\ \\ \tt \longmapsto \frac{7}{3} \div \frac{13}{3} = \frac{7}{x} \\ \\ \tt \longmapsto \frac{7}{3} \times \frac{3}{13} = \frac{7}{x} \\ \\ \tt \longmapsto \frac{7}{13} = \frac{7}{x} \\ \\ \tt \longmapsto 7x = 7 \times 13 \\ \\ \tt \longmapsto 7x = 91 \\ \\ \tt \longmapsto x = \frac{91}{7} \\ \\ \tt \longmapsto x = 13\)
Answer:
\(x = 13\)
Step-by-step explanation:
\( \frac{2 \frac{1}{3} }{4 \frac{1}{3} } = \frac{7}{x} \\ \frac{7}{3} \div \frac{13}{3} = \frac{7}{x} \\ \frac{7}{ 3} \times \frac{3}{13} = \frac{7}{x} \\ \frac{7}{13} = \frac{7}{x} \\ 7x = 13 \times 7 \\ x = \frac{13 \times 7}{7} \\ x = 13\)
need help... so lost
Answers
Answer:
4
Step By Step Explanation:
Hope it helps
Which statement must be true about line TU?
Line TU is parallel to line RS.
Line TU is perpendicular to line RS.
Line TU has no slope.
Line TU has a slope of –5.
Answers
Answer:
line TU is parallel to line RS
Step-by-step explanation:
edg2020
Answer: line TU is parallel to line RS
Step-by-step explanation:
C
M
A
Which set of given
information does not
prove
A CAMA COM?
Answers
Answer:
Step-by-step explanation:
Answer: A. You cannot use any theorem along with option A. For B, you can use SAS. For option C, you can use SAS. For option D, you can use SSS. For option D, you can use ASA. So, the answer is A.
what is the answer to this equation -7 c + 2 = 16?
Answers
Answer:
c=-2
Step-by-step explanation:
Equation: -7c+2=16
-7c=16-2
-7c=14
c=14/-7
c=-2
Answer:
c = - 2
Step-by-step explanation:
Given
- 7c + 2 = 16 ( subtract 2 from both sides )
- 7c = 14 ( divide both sides by - 7 )
c = - 2
I need to make these into algebraic expressions or equations:5 less than the product of 10 and c, 14 more than 6 times t, the sum of x and y is 18, A number minus 12 is 17
Answers
Answer: more than y :
y + 6
3 times a number:
x ← a number
3x
5 less than the product of 10 and c :
10c ← the product of 10 and c
10c - 5
14 more than 6 times t :
6t ← six times t
6t + 14
The sum of x and y is 18:
x+y ← the sum of x and y
x + y = 18
A number minus 12 is y:
x - a number
x - 12 = y
Answer:
See below
Step-by-step explanation:
Here is translation for you
5 less than the product of 10 and c
-5 + 10*c = 10c - 514 more than 6 times t
+14 + 6*t = 6t + 14The sum of x and y is 18
x + y = 18A number minus 12 is 17
n - 12 = 17find the number of units x that produces a maximum revenue r. r = 180x2 − 0.08x3 x = units
Answers
The number of units x = 1500 units produce a maximum revenue r found using the given function.
To find the number of units x that produces a maximum revenue r, we need to differentiate the given revenue function with respect to x.
Then equate the derivative to zero to find the critical points which will be the maximum or minimum point for the function.
r = 180x² - 0.08x³
Let's differentiate the above revenue function with respect to x.
Using the Power Rule and the Chain Rule, we get:
dr/dx = d/dx [180x² - 0.08x³]
dr/dx = 360x - 0.24x²
To find the critical points, we need to solve the equation 360x - 0.24x² = 0
Factorizing x from the above equation, we get:x (360 - 0.24x) = 0x = 0 or 360 - 0.24x = 0
Solving for x, we get:x = 0 or x = 1500
We need to verify whether these critical points correspond to a maximum or minimum value of the function.To find out, we'll take the second derivative of the revenue function.
Using the Power Rule and the Chain Rule, we get:
d²r/dx² = d/dx [360x - 0.24x²]d²r/dx²
= 360 - 0.48x
The second derivative test states that if d²r/dx² > 0, the function has a minimum at that point; and if d²r/dx² < 0, the function has a maximum at that point.
At x = 0, d²r/dx² = 360 which is greater than 0, therefore, the function has a minimum value at x = 0.
At x = 1500, d²r/dx² = 360 - 0.48(1500) = -360 which is less than 0, therefore, the function has a maximum value at x = 1500.
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set the number of flips per sample to 30, and adjust the proposed proportion of heads to 0.50. click flip so you have numbers to look at. you can ignore the shading on the graph for this question. the possible sample proportions are multiples of 1/30, such as 0/30, 1/30, 2/30, etc. (from observing 0, 1, 2, etc. heads out of 30 flips). the probability of observing a proportion of 10/30 or lower (10 or fewer heads) is 0.0494. a. use the binomial distribution to calculate the probability of observing exactly 11 heads (a sample proportion of 0.3667). b. then, calculate the probability of observing exactly 12 heads (a sample proportion of 0.4). c. finally, calculate the cumulative probability of observing 12 or fewer heads (a sample proportion of 0.4 or lower).
Answers
(a) The probability of observing exactly 11 heads is 0.1020.
(b) The probability of observing exactly 12 heads is 0.0687.
(c) The cumulative probability of observing 12 or fewer heads is 0.9531.
How find the probability of observing exactly 11 heads in 30 flips?a. To calculate the probability of observing exactly 11 heads in 30 flips, we can use the binomial distribution with parameters n = 30 (number of flips) and p = 0.50 (proportion of heads):
P(X = 11) = (30 choose 11) * (0.50)^11 * (1 - 0.50)^(30 - 11)
P(X = 11) = 0.1020 (rounded to four decimal places)
Therefore, the probability of observing exactly 11 heads is 0.1020.
How find the probability of observing exactly 12 heads in 30 flips?b. To calculate the probability of observing exactly 12 heads in 30 flips, we can use the same formula:
P(X = 12) = (30 choose 12) * (0.50)^12 * (1 - 0.50)^(30 - 12)
P(X = 12) = 0.0687 (rounded to four decimal places)
Therefore, the probability of observing exactly 12 heads is 0.0687.
How find the cumulative probability of observing 12 or fewer heads?c. To calculate the cumulative probability of observing 12 or fewer heads (a sample proportion of 0.4 or lower), we can sum the probabilities of observing 0, 1, 2, ..., 12 heads:
P(X <= 12) = P(X = 0) + P(X = 1) + ... + P(X = 12)
We can use software or a binomial probability table to calculate these probabilities and then sum them up. Alternatively, we can use the complement rule and subtract the probability of observing 13 or more heads from 1:
P(X <= 12) = 1 - P(X >= 13)
P(X <= 12) = 1 - [P(X = 13) + P(X = 14) + ... + P(X = 30)]
Using a binomial probability table or software, we can find that:
P(X >= 13) = 0.0469 (rounded to four decimal places)
Therefore,
P(X <= 12) = 1 - P(X >= 13) = 1 - 0.0469 = 0.9531
So the cumulative probability of observing 12 or fewer heads is 0.9531.
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3. The system of equations for two liquid surge tanks in series is
A₁ dh'₁/dt = q'ᵢ - 1/R₁ h'₁, q'₁ = 1/R₁ h'₁
A₂ dh'₂/dt = 1/R₁ h'₁ - 1/R₂ h'₂ q'₂ = 1/R₂ h'₂
Using state-space notation, determine the matrices A,B,C, and D assuming that the level deviations are the state variables: h'₁ and h'₂. The input variable is q'ᵢ , and the output variable is the flow rate deviation, q'₂.
Answers
The surge tank is a vital component of a system in which the flow rate fluctuates significantly. The flow rate entering the tank varies significantly, causing the fluid level in the tank to fluctuate as a result of the compressibility of the liquid. The surge tank is utilized to reduce pressure variations generated by a rapidly fluctspace uating pump flow rate. To determine the matrices A,B,C, and D using state-space notation, here are the steps:State representation is given by:dx/dt = Ax + Bu; y = Cx + DuWhere: x represents the state variablesA represents the state matrixB represents the input matrixC represents the output matrixD represents the direct transmission matrixThe equation can be written asA = [ -1/R₁ 0; 1/R₁ -1/R₂]B = [1/A₁; 0]C = [0 1/R₂]D = 0Thus, the matrices A,B,C and D assuming that the level deviations are the state variables: h'₁ and h'₂. The input variable is q'ᵢ, and the output variable is the flow rate deviation, q'₂ are given by A = [ -1/R₁ 0; 1/R₁ -1/R₂]B = [1/A₁; 0]C = [0 1/R₂]D = 0.Hence, the required matrices are A = [ -1/R₁ 0; 1/R₁ -1/R₂], B = [1/A₁; 0], C = [0 1/R₂], and D = 0 using state-space notation for the given system of equations for two liquid surge tanks.
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The Central Fabric Company purchases surplus bolts of fabric from two large textile mills, A and B. These fabrics are then sold to the public through bolts fabric stores, discount stores and direct mail. When Central receives the bolts, it separates them according to the market in which they are sold. Of the fabrics received from the textile mill A, 40 percent are sold to fabric stores, 10 percent in discount stores, and 30 percent by direct mail. The fabric received from textile mill B are 20 percent for fabric stores, 20 percent for discount stores, and 40 percent for direct sales. Of the total purchases made from either mill A or mill B, 20 percent of the bolts are unusable and thrown away. For every 1,000 bolts purchased from mill A, Central Fabric realizes a profit of P8,000; for every 1,000 bolts purchased from mill B, it realizes a profit of P6,000. The sales department forecasts that, at most, 1,600 bolts can be sold through fabric shops, 2,800 through discount stores, and 2,600 through direct mail in the coming year. Determine the most profitable numbers of bolts which Central Fabric should purchase from mills A and B using the graph method.
Answers
Using the graph method, Central Fabric should determine the most profitable numbers of bolts to purchase from mills A and B by considering profit calculations, supply and demand constraints, and plotting a profit graph.
To determine the most profitable numbers of bolts that Central Fabric should purchase from mills A and B using the graph method, we need to create a profit graph based on the given information.
Start by calculating the total available supply for each market channel:
Fabric Stores: (0.40 * Total Bolts from Mill A) + (0.20 * Total Bolts from Mill B)
Discount Stores: (0.10 * Total Bolts from Mill A) + (0.20 * Total Bolts from Mill B)
Direct Mail: (0.30 * Total Bolts from Mill A) + (0.40 * Total Bolts from Mill B)
Determine the maximum number of bolts that can be sold in each market channel:
Fabric Stores: 1,600 bolts
Discount Stores: 2,800 bolts
Direct Mail: 2,600 bolts
Calculate the profit for each combination of bolts purchased from mills A and B:
Profit from Mill A: (0.60 * Total Bolts from Mill A - 0.20 * Total Bolts from Mill A) * P8,000
Profit from Mill B: (0.80 * Total Bolts from Mill B - 0.20 * Total Bolts from Mill B) * P6,000
Plot the profit graph by considering different combinations of Total Bolts from Mill A and Total Bolts from Mill B, while taking into account the constraints of available supply and market demand.
Find the combination of Total Bolts from Mill A and Total Bolts from Mill B that maximizes the profit while satisfying the supply and demand constraints. This point on the graph represents the most profitable numbers of bolts to purchase from mills A and B.
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Major arc BLJ measures 249 degrees. Find the measure in degrees of
angle K.
2490
B
J
L
K?
K
Answers
Answer:
m∠K = 69°
Step-by-step explanation:
"When two tangents or secants intersect outside the circle, exterior angle formed between the tangents of secants is one half the difference of major and minor arcs"
By this theorem,
m(∠K) = \(\frac{1}{2}[m(\widehat{LBJ}-m(\widehat{LJ})]\)
Here, \(m(\widehat{LBJ})\) = 249°
\(m(\widehat{LJ})\) = 360° - 249°
= 111°
m∠K = \(\frac{1}{2}(249-111)\)
= \(\frac{138}{2}\)
= 69°
Therefore, measure of angle K = 69° will be the answer.
Fill in the table based on the following equation:
у – x
у
ол | 1 x
-2
Answers
1st one is x=-2 and y=-2Step-by-step explanation:
It says y - x so whatever x is y has the same value
Peter says, "If you subtract 12 from my number and multiply the difference by −7, the result is −175." What is Peter's number
Answers
Answer:
37
Step-by-step explanation:
let’s say peter’s number is x
(x-12)(-7) = -175
-7x + 84 = -175
-7x = -259
x = 259/7
x = 37
Answer:
The number is 37.
Step-by-step explanation:
-175 ÷ -7 = 25
25 + 12 = 37
You have to work backwards from -175 by doing the reverse of what peter did to get the original number.
What is the GCF of 28?
Answers
Answer fast!!
The diagram represents three statements about teachers: p, q, and r.
For how many teachers are both p ∧ r true and q false?
2
4
5
9
Answers
Answer: 5
Step-by-step explanation:
For how many teachers are both p ∧ r true and q false?
(p ∧ r) ∧ (q')
q' = q complement (not in q)
p intersection r = (p ∧ r) = 9
both p ∧ r true and q false = (8+6) - 9
both p ∧ r true and q false = 14 - 9 = 5
OR
p + r - p ∧ r
8 + 6 - 9 = 14 - 9 = 5
Answer:
The answer is C (5) on Edge.
Step-by-step explanation:
Find the measure of the numbered angle.
m∠6 =
Answers
Answer:
Angle 6 = 140°
Step-by-step explanation:
Angle 5 = 40°
Angles 5 and 6 are supplementary (Their sum is equal to 180°)
180 - 40 = 140°
Angle 6 = 140°
Hope this helps. Have a nice day.
Answer:
∠6 = 140°Step-by-step explanation:
∠6 = 180 - 40
∠6 = 140°
see image below.
a limo company charges a reservation fee of $35 and $2 per mile , however nick has a coupon that gives him a free reservation if he pays for every mile. which equation shows the total cost of a ride in the limo for nick if he uses the coupon SHOW YOU WORK
A.y=35x+2
B.y=35x
C. y=2x
D. 2x+35y=2
Answers
Answer:
c; y = 2x
Step-by-step explanation:
if it was without the coupon the fee would be the $2 per mile (2x) with the $35 which would be
y = 2x + 35
but with the coupon the $35 reservation is removed so only 2x is left
y = 2x
To estimate a particular population parameter you take a sample and based on that find a point estimate of 46 with a standard error of 5.66. Complete the following to construct a 95% confidence interval for this parameter. a) The margin of error for your interval is: ± b) The confidence interval is therefore
Answers
To construct a 95% confidence interval for a population parameter, given a point estimate of 46 and a standard error of 5.66, the margin of error is ±11.32. Therefore, the confidence interval is 34.68 to 57.32.
A confidence interval provides a range of values within which the true population parameter is likely to fall. The margin of error represents the maximum distance between the point estimate and the boundaries of the confidence interval. To calculate the margin of error, we multiply the standard error by the appropriate critical value from the standard normal distribution corresponding to the desired confidence level.
For a 95% confidence level, the critical value is approximately 1.96, as it encompasses the middle 95% of the standard normal distribution. Thus, the margin of error is 1.96 multiplied by the standard error of 5.66, which equals 11.32. This means that we expect the true population parameter to be within 11.32 units (plus or minus) of the point estimate.
To determine the confidence interval, we take the point estimate of 46 and subtract the margin of error from it to obtain the lower bound, which is 46 - 11.32 = 34.68. Similarly, we add the margin of error to the point estimate to get the upper bound, which is 46 + 11.32 = 57.32. Therefore, the confidence interval for the population parameter, based on the given information, is 34.68 to 57.32.
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