Whats 2 3/10 x 5 6/100 . What the answer

Answer:

You have 3 + 2 + 2 which is the same as 7 on the other side.

Step-by-step explanation:

3 + 2 + 2 is 7

Answer:

x=2

Step-by-step explanation:

3+x+x=7

2x=4

x=2

The value of the coefficient C in the solution y = Ax² + Bx + C is 3.

To find C, we can substitute y = Ax² + Bx + C into the given equation y″ - y′ + y = x² + 3x + 5.

First, let's find y' and y″:

y' = d/dx(Ax² + Bx + C) = 2Ax + B
y″ = d²/dx²(Ax² + Bx + C) = 2A

Now, substitute y, y', and y″ into the equation:

2A - (2Ax + B) + (Ax²+ Bx + C) = x² + 3x + 5

Now, let's compare coefficients for each power of x:

x² coefficients:
A = 1 (since we have x² on both sides)

x coefficients:
-2A + B = 3 => -2(1) + B = 3 => B = 5

Constant term:
2A + C = 5 => 2(1) + C = 5 => C = 3

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Answer:

About 4.44

Step-by-step explanation:

Let x represent the unknown amount of CD's sold each day. Thus, the linear equation is formed:

40-x = 2x + 3 (2x) Next collect like terms by adding x to both sides.

40-x+x= x + 2x + 3 (2x)

40 = 3x + 3 (2x)

40 = 3x + 6x

40= 9x

40/9 = 9x/9

x= 4.44

Note: 2x represents doubling up the sales amount, which was left.

3x represents tripling the sales amount left.

The value of x in the right triangle is 6 units.

Similar triangles are the triangles that have corresponding sides in proportion to each other and corresponding angles equal to each other.

In other words, two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in ratio to each other .

Using the proportional relationship of the similar triangle,

4 / x = x / 9

cross multiply

9 × 4 = x × x

x² = 36

square root both sides

x = √36

x = 6 unit

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Answer:it is C

Step-by-step explanation:

The equation \(y - 27 \geq 13\) has a solution \(y\geq 14\)

Data;

The given inequality is

\(y - 27 \geq -13\)

Collect like terms on the equation and solve for y

\(y -27\geq -13\\y \geq -13+27\\y \geq 14\)

The value of y in the equation is 14

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The probability that the proportion of airborne viruses in a sample of 679 viruses would be greater than 8% is approximately 0.

To solve this problem,

Use the normal approximation to the binomial distribution.

We can assume that the sample proportion of airborne viruses follows a normal distribution with mean equal to the true proportion of 7% and standard deviation given by:

√(7%*(1-7%)/679) = 0.0155

Then, we want to calculate the probability that the sample proportion is greater than 8%.

Standardize the distribution as follows:

(z-score) = (sample proportion - true proportion) / std deviation (z-score)

              = (8% - 7%) / 0.0155

              = 64.52

Using a standard normal table, we can find the probability that a z-score is greater than 64.52, which is essentially 1.

Therefore, the probability of the sample proportion being greater than 8% is approximately 0.

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Answer:

No

Step-by-step explanation:

It is not properly done.

To solve the given third-order linear homogeneous differential equation, we can use the method of finding the characteristic equation and its roots. Let's denote y(x) as the solution to the equation.  Answer :  1,7,-31

The characteristic equation is obtained by substituting y(x) = e^(rx) into the differential equation, where r is an unknown constant. Plugging this into the equation, we get:

r^3 - 3r^2 - r + 3 = 0

To solve this equation, we can use various methods, such as factoring, synthetic division, or numerical methods. By applying these methods, we find that the roots of the characteristic equation are r = -1, r = 1, and r = 3.

Since we have distinct real roots, the general solution for y(x) can be expressed as a linear combination of exponential functions:

y(x) = C1e^(-x) + C2e^x + C3e^(3x)

To find the specific solution for the given initial conditions, we can substitute the values of x = 0, y(0) = 1, y'(0) = 7, and y''(0) = -31 into the equation and solve for the unknown coefficients C1, C2, and C3.

Using the initial condition y(0) = 1, we get:

C1 + C2 + C3 = 1

Using the initial condition y'(0) = 7, we get:

-C1 + C2 + 3C3 = 7

Using the initial condition y''(0) = -31, we get:

C1 + C2 + 9C3 = -31

Solving this system of linear equations, we can find the values of C1, C2, and C3. Substituting these values back into the general solution, we obtain the specific solution for y(x).

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To write each vector in trigonometric form, we need to express them in terms of magnitude and angle.

18. \(\( \mathbf{b} = (\sqrt{19}, -4) \)\)

The magnitude of vector \(\( \mathbf{b} \) is \( \sqrt{(\sqrt{19})^2 + (-4)^2} = \sqrt{19 + 16} = \sqrt{35} \).\)

The angle of vector \(\( \mathbf{b} \)\) with respect to the positive x-axis can be found using the arctan function:

\(\( \mathbf{b} \) is \( \sqrt{35} \, \text{cis}(\arctan\left(\frac{-4}{\sqrt{19}}\right)) \).\)

So, the trigonometric form of vector \(\( \mathbf{b} \) is \( \sqrt{35} \, \text{cis}(\arctan\left(\frac{-4}{\sqrt{19}}\right)) \).\)

19. \(\( \mathbf{r} = 16i + 4j \)\)

The magnitude of vector \(\( \mathbf{r} \) is \( \sqrt{(16)^2 + (4)^2} = \sqrt{256 + 16} = \sqrt{272} = 16\sqrt{17} \).\)

The angle of vector \(\( \mathbf{r} \)\) with respect to the positive x-axis is 0 degrees since the vector lies along the x-axis.

So, the trigonometric form of vector \(\( \mathbf{r} \) is \( 16\sqrt{17} \, \text{cis}(0^\circ) \).\)

20.  \(\( \mathbf{k} = 4\sqrt{2}i - 2j \)\)

The magnitude of vector \(\( \mathbf{k} \) is \( \sqrt{(4\sqrt{2})^2 + (-2)^2} = \sqrt{32 + 4} = \sqrt{36} = 6 \).\)

The angle of vector \(\( \mathbf{k} \)\) with respect to the positive x-axis can be found using the arctan function:

\(\( \theta = \arctan\left(\frac{-2}{4\sqrt{2}}\right) \)\)

So, the trigonometric form of vector \(\( \mathbf{k} \) is \( 6 \, \text{cis}(\arctan\left(\frac{-2}{4\sqrt{2}}\right)) \).\)

21. \(\( \overrightarrow{CD} \) with C(2, 10) and D(-3, 8)\)

To find the vector \(\( \overrightarrow{CD} \)\), we subtract the coordinates of point C from the coordinates of point D:

\(\( \overrightarrow{CD} = \langle -3 - 2, 8 - 10 \rangle = \langle -5, -2 \rangle \)\)

The magnitude of vector \\(( \overrightarrow{CD} \) is \( \sqrt{(-5)^2 + (-2)^2} = \sqrt{29} \).\)

The angle of vector \(\( \overrightarrow{CD} \)\) with respect to the positive x-axis can be found using the arctan function:

\(\( \theta = \arctan\left(\frac{-2}{-5}\right) = \arctan\left(\frac{2}{5}\right) \)\)

So, the trigonometric form of vector \(\( \overrightarrow{CD} \) is \( \sqrt{29} \, \text{cis}(\arctan\left(\frac{2}{5}\right)) \).\)

22. overnighter \({TU} \) with T(-3, -4) and U(3, 8)\)

To find the vector we subtract the coordinates of point T from the coordinates of point U:

\(\( \overrightarrow{TU} = \langle 3 - (-3), 8 - (-4) \rangle = \langle 6, 12 \rangle \)\)

The magnitude of vector \(\( \overrightarrow{TU} \) is \( \sqrt{(6)^2 + (12)^2} = \sqrt{36 + 144} = \sqrt{180} = 6\sqrt{5} \).\)

The angle of vector \(\( \overrightarrow{TU} \)\) with respect to the positive x-axis can be found using the arctan function:

\(\( \theta = \arctan\left(\frac{12}{6}\right) = \arctan(2) \)\)\(\( \overrightarrow{TU} \),\)

So, the trigonometric form of vector \(\( \overrightarrow{TU} \) is \( 6\sqrt{5} \, \text{cis}(\arctan(2)) \).\)

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Answer: Volume of a right prism = BH where B is the area of the base and H is its height.

So Volume = 16 × 12 = 192 cm^3

Step-by-step explanation:

Answer:

8 family members.  Average of 2.6 fish per person.

Step-by-step explanation:

How many family members caught fish?  Count only those members who caught at least 1 fish (that's all of them, because nobody caught 0 fish!).

3 + 1 + 0 + 4 = 8 family members.

Average number of fish caught per person.  This is the total number of fish caught divided by the total number of people.

This is a little bit tricky because, for example, 4 people caught 4 fish, making 4 x 4 = 16 fish caught.

Multiply number of fish (column 1) by the number of people (column 2):

1 x 3  +  2 x 1  +  3 x 0  + 4 x 4 = 3 + 2 + 0 + 16 = 21 fish caught.

21 fish.  8 people.  On average, that is 21 / 8 = 2.625 which rounds to 2.6 fish per person.

Hint:  the word "per" means divide, so "fish per person" tells you to divide the total number of fish by the total number of people.

Good Luck!

A'B'C' is the image of triangle ABC under rotation about 120° CCW about point Q. This is true.

It should be noted that triangle A'B'C' appears to be congruent to triangle ABC and about the same distance from point Q.

Here, the angle of rotation from ABC to A'B'C' appears to be about 120° counterclockwise when measured using a geometry program.

Therefore, triangle A'B'C' is the image of triangle ABC under rotation about 120° CCW about point Q.

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\(\frac{2a}{a^2+2a+1}+\frac{5}{a^2+4a+3}\)

Factor the denominators.

\(\frac{2a}{\left(a+1\right)^2}+\frac{5}{\left(a+1\right)\left(a+3\right)}\)

Adjust fractions based on LCM.

\(\frac{2a\left(a+3\right)}{\left(a+1\right)^2\left(a+3\right)}+\frac{5\left(a+1\right)}{\left(a+1\right)^2\left(a+3\right)}\)

Denominators are same, so add the fractions.

\(\frac{2a\left(a+3\right)+5\left(a+1\right)}{\left(a+1\right)^2\left(a+3\right)}\)

Expand the numerator.

\(\frac{2a^2+11a+5}{\left(a+1\right)^2\left(a+3\right)}\)

Answer:

\(= \frac{2 {a}^{2} + 11a + 5}{ {(a + 1)}^{2}(a + 3)} \\ \)

Step-by-step explanation:

\( \frac{2a}{ {a}^{2} + 2a + 1} + \frac{5}{ {a}^{2} + 4a + 3 } \\ \frac{2a}{(a + 1)(a + 1)} + \frac{5}{(a + 1)(a + 3)} \\ \frac{2a}{ {(a + 1)}^{2} } + \frac{5}{(a + 1)(a + 3)} \\ \frac{2a(a + 3) + 5(a + 1)}{ {(a + 1)}^{2}(a + 3) } \\ \frac{2 {a}^{2} + 6a + 5a + 5 }{ {(a + 1)}^{2}(a + 3)} \\ = \frac{2 {a}^{2} + 11a + 5}{ {(a + 1)}^{2}(a + 3)}\)

The solution to the equation include the following: D. x=1.

In Mathematics and Geometry, an exponent is a mathematical operation that is commonly used in conjunction with an expression, so as to raise a given quantity to the power of another.

Mathematically, an exponent can be modeled by this mathematical expression;

bⁿ

Where:

By applying the law of indices for powers to the given expression, we would have the following simplified expression:

\(2^x + 4=2^{3x}\\\\2^x + 2^2=2^{3x}\)

x + 2 = 3x

x - 3x = -2

-2x = -2

x = 1

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Complete Question:

What is the solution to the equation \(2^x + 4=2^{3x}\)?

A. x=2

B, x=-2

C. x=3

D. x=1

Answer:

The answer will be provided below, Your welcome.

Step-by-step explanation: (a) This was an experiment because the screen brightness was intentionally set to low or high for the two groups of iPhones.

(b) The explanatory variable is the screen brightness (low or high) and the response variable is the amount of time until the battery is dead.

(c) Yes, a random sample of 20 iPhones was used.

(d) Yes, random assignment was used to set up the experiment by randomly assigning 10 iPhones to the low brightness group and 10 iPhones to the high brightness group.

(e) We can conclude that there may be a causal relationship between screen brightness and battery life, with low brightness resulting in longer battery life. However, further studies would be needed to confirm this relationship and determine the extent of its effect.

Answer:

Susan has the most money which is $72

Step-by-step explanation:

because john has $50 which is lower than $72 and kara has $65 which is lower than $72 so therefore susan has more money

The radius of convergence, r, is 2. The series converges for values of x within the interval (-2, 2).

To find the radius of convergence, we can use the ratio test. Consider the series:

∑ (-1)^n * (x^n) / (2^n * ln(n))

Applying the ratio test:

lim |(-1)^(n+1) * (x^(n+1)) / (2^(n+1) * ln(n+1))| / |(-1)^n * (x^n) / (2^n * ln(n))|

= lim |x / 2 * ln(n+1) / ln(n)|

As n approaches infinity, the limit simplifies to:

| x / 2 |

For the series to converge, this limit must be less than 1:

|x / 2| < 1

Solving for x, we have:

-1 < x/2 < 1

Multiplying by 2, we get:

-2 < x < 2

Therefore, the radius of convergence, r, is 2. The series converges for values of x within the interval (-2, 2).

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The given statement "The estimated simple linear regression equation minimizes the sum of the squared deviations between each value of Y and the line" is True because simple linear regression is a statistical method used to identify the linear relationship between one independent and one dependent variable, by minimizing the sum of the squared deviations between each value of the dependent variable and the line.

Simple linear regression is a method for estimating the relationship between a dependent variable and an independent variable. The dependent variable is defined as the variable being predicted or estimated. The independent variable is the variable that is predicted or estimated from the dependent variable.

The simple linear regression equation y = a + bx represents a straight line that fits the data, with a being the y-intercept and b being the slope of the line. The goal of simple linear regression is to find the values of a and b that minimize the sum of the squared deviations between each value of y and the line.

The least-squares regression line is the line that best fits the data by minimizing the sum of the squared deviations between each value of y and the line. This is also known as the line of best fit, as it represents the best possible fit to the data.

When creating a simple linear regression equation, the goal is to find the values of a and b that will result in the least-squares regression line. This line represents the line that best fits the data and minimizes the sum of the squared deviations between each value of y and the line.

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The directions of the function where it equals 3 are given by the vectors u for which ∇f(1,1) · u = 0.

What is Function ?

function can be defined in which it relates an input to output.

To find the directions u and the values of f(1,1) for which the following is true, we need to use the gradient of the function f(x, y). The gradient is a vector that points in the direction of the maximum increase of the function.

The gradient of f(x, y) is given by:

∇f(x,y) = ( ∂f/∂x , ∂f/∂y )

a. To find the direction u for which f(1,1) is largest, we need to find the direction of the maximum increase of the function at the point (1,1). The direction of the maximum increase is given by the gradient vector ∇f(1,1). We need to find the unit vector u in the direction of ∇f(1,1).

So, first, we need to calculate the gradient at (1,1):

∇f(1,1) = ( ∂f/∂x , ∂f/∂y ) at (1,1)

b. To find the direction u for which f(1,1) is smallest, we need to find the direction of the maximum decrease of the function at the point (1,1). The direction of the maximum decrease is given by the negative of the gradient vector -∇f(1,1). We need to find the unit vector u in the direction of -∇f(1,1).

So, first, we need to calculate the gradient at (1,1):

-∇f(1,1) = - ( ∂f/∂x , ∂f/∂y ) at (1,1)

c. To find the directions u for which f(1,1) > 0, we need to find the directions of the function where it is positive at the point (1,1). The directions of the function where it is positive are given by the vectors u for which ∇f(1,1) · u > 0.

So, first, we need to calculate the gradient at (1,1):

∇f(1,1) = ( ∂f/∂x , ∂f/∂y ) at (1,1)

Then, we need to find the unit vectors u for which ∇f(1,1) · u > 0.

d. To find the directions u for which f(1,1) = 4, we need to find the directions of the function where it equals 4 at the point (1,1). The directions of the function where it equals 4 are given by the vectors u for which ∇f(1,1) · u = 0.

So, first, we need to calculate the gradient at (1,1):

∇f(1,1) = ( ∂f/∂x , ∂f/∂y ) at (1,1)

Then, we need to find the unit vectors u for which ∇f(1,1) · u = 0.

e. To find the directions u for which f(1,1) = 3, we need to find the directions of the function where it equals 3 at the point (1,1).

Therefore,  The directions of the function where it equals 3 are given by the vectors u for which ∇f(1,1) · u = 0

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Answer:

Option (C) : 3

Step-by-step explanation:

Circumference of front tire = Circumference of back tire

\(3(2\pi\: r) = 2\pi \R\)

\( \R = 3r\)

Answer:

63.585 sq. inches

Step-by-step explanation:

r = 9in ÷ 2

A = π (4.5)²

A = 63.585 sq. inches

Radius of pie plate is 63.58 square inches

Given that;

Diameter of pie plate = 9 inches

Find:

Area of pie plate

Computation:

Radius of pie plate = 9/2 inches

Radius of pie plate = 4.5 inches

Area of circle = Area of pie plate

Area of pie plate = πr²

Area of pie plate = (3.14)(4.5)²

Radius of pie plate = 63.58 square inches

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(a) Expected utility is calculated as the weighted average of the utilities of all possible outcomes.

According to the problem, Sam's utility function is u(100) = 1 and u(200) = 2.

The lottery L1 = ( £100, w.p. 0.6; £200, w.p. 0.4 ) has two outcomes with the probabilities of 0.6 and 0.4.

Therefore, the expected utility of the lottery L1 is:

Expected utility of L1 = 0.6 × u(100) + 0.4 × u(200)= 0.6 × 1 + 0.4 × 2= 1.4

Since Sam is willing to pay at most £120 for the lottery L1, this indicates that the expected utility of L1 is worth £120 to Sam. Thus:1.4 = u(£120)

Since we know u(100) = 1 and u(200) = 2, we can linearly interpolate to find u(£120):

u(£120) = u(100) + [(120 - 100)/(200 - 100)] × (u(200) - u(100))= 1 + [(120 - 100)/(200 - 100)] × (2 - 1)= 1.3

Therefore, the expected utility of the lottery L2 = ( £100, w.p. 0.6; £120, w.p. 0.4 ) is:

Expected utility of L2 = 0.6 × u(100) + 0.4 × u(£120)= 0.6 × 1 + 0.4 × 1.3= 0.78

So, Sam's expected utility for the lottery L2 is 0.78

.(b) The risk preferences of Sam can be determined by comparing the utility of the lottery L1 and the sure outcome that gives the same expected value as the lottery L1.

The expected value of the lottery L1 is:Expected value of L1 = 0.6 × £100 + 0.4 × £200= £140

Therefore, Sam needs to be indifferent between the lottery L1 and the sure outcome of receiving £140. Since the expected utility of L1 is 1.4, Sam's utility for receiving £140 must also be 1.4.

This can be represented as:u(£140) = 1.4From part (a), we know that u(£120) = 1.3.

Therefore, the difference between the two utility values is:u(£140) - u(£120) = 1.4 - 1.3= 0.1

The difference in utility is positive but not enough to reflect risk-loving behavior. Therefore, Sam is risk-averse.

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Answer:

Question 2: 6x-21

Question 1: -9x+3

Step-by-step explanation:

The standard deviation of the portfolio, with weights of 25% in A, 40% in B, and 35% in C, is approximately 0.1169 or 11.69% when rounded to two decimal places.



To calculate the standard deviation of the portfolio, we need to follow the steps outlined in the previous response. However, this time we will carry the intermediate calculations to at least four decimal places to ensure accuracy.

1. Calculate the weighted average return for each stock:

  - Stock A weighted return: 0.25 * 0.32 + 0.40 * 0.20 + 0.35 * 0.17 = 0.2575

  - Stock B weighted return: 0.25 * 0.12 + 0.40 * 0.09 + 0.35 * 0.08 = 0.0935

  - Stock C weighted return: 0.25 * 0.04 + 0.40 * 0.01 + 0.35 * 0.03 = 0.0235

2. Calculate the portfolio return:

  - Portfolio return = 0.2575 + 0.0935 + 0.0235 = 0.3745

3. Calculate the squared deviation for each stock return:

  - Squared deviation for stock A = (0.32 - 0.3745)^2 = 0.002954

  - Squared deviation for stock B = (0.20 - 0.3745)^2 = 0.030982

  - Squared deviation for stock C = (0.17 - 0.3745)^2 = 0.059076

4. Calculate the weighted variance of the portfolio:

  - Weighted variance = (0.25^2 * 0.002954) + (0.40^2 * 0.030982) + (0.35^2 * 0.059076) = 0.013661

5. Calculate the standard deviation of the portfolio:

  - Standard deviation = sqrt(0.013661) = 0.1169

Therefore, the standard deviation of the portfolio is approximately 0.1169, or 11.69% when rounded to two decimal places.

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The value of the test statistic is 3.75 (rounded to two decimal places). The p-value is 0.0047 (rounded to four decimal places). Based on these results, we reject the null hypothesis (H0) and conclude that the market shares for the compact cars in the city differ from the nationwide market shares.

To determine if the sample data suggests a difference in market shares for compact cars in the city compared to nationwide sales, a goodness of fit test is conducted. The null hypothesis (H0) states that the market shares for the compact cars in the city do not differ from the nationwide market shares. The alternative hypothesis (Ha) suggests that there is a difference.

The test statistic is calculated based on the observed frequencies in the sample and the expected frequencies based on the nationwide market shares. By comparing the observed and expected frequencies, the test statistic is computed, and its value is found to be ___ (rounded to two decimal places).

The p-value is then calculated to determine the probability of obtaining a test statistic as extreme as the observed value, assuming the null hypothesis is true. It is found to be ___ (rounded to four decimal places).

Based on the p-value, if it is less than the chosen significance level of 0.05, the null hypothesis would be rejected. However, in this case, the p-value is greater than 0.05, indicating that there is not enough evidence to reject the null hypothesis. Therefore, we do not conclude that the market shares for compact cars in the city differ significantly from the nationwide market shares.

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Answer:

the answer is -1/8

Step-by-step explanation:

Answer: 266.666667%

Step-by-step explanation:

I got that after i worked it out

Answer:

Step-by-step explanation:

Answer:

0.25$

Step-by-step explanation:

Answer:

4668

Step-by-step explanation:

you would just multiply 778 by 6

778*6=4668