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Related Questions
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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A man stands on top of a cliff and shouts.
He hears the echo on the third clap when
he claps his hand at the rate of two claps
per second. What is the distance between
man & the obstruction, if the velocity of
sound is 320 m/s
Answers
\( \small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x\)
\( \small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return = \frac{2x}{v} = 1\)
\( \bf \to \: x = \frac{320}{2} m = 160m\)
\( \small \bf \: thus \: the \: distance \: between \: the \: cliffs \: = 160m \times 2 = 320m\)
A 15 kg block rest on a surface of a smooth plane incline at an angle 30 degree to the horizontal. A light in extensible string passing over a small Smooth Pulley at the top of the plane connect to the block to another 13/kg block hanging freely. find the acceleration of the resulting motion and the tension in the string.
If the coeficient of kinetic friction between the plane and the 15kg mass is 0.25. find the acceleration of the resulting motion
Answers
The acceleration of the system is 2.77 m/s² and the tension in the string is 127.4 N, given the provided values.
Given: Mass of the first block (m1) = 15 kgMass of the second block (m2) = 13 kgAngle of the plane (θ) = 30°Coefficient of kinetic friction (μk) = 0.25, Acceleration of the resulting motion (a) = ? Tension in the string (T) = ?First, we need to resolve the weight of the first block into its components perpendicular to and along the plane. Then we can use the component parallel to the plane to find the force of friction acting on the first block. We can then use the net force acting on the first block to find its acceleration. Finally, we can use the acceleration of the first block to find the tension in the string.Resolving the weight of the first block into components parallel to the plane: m1gsinθ = 15 x 9.8 x sin30° = 73.5 N. Perpendicular to the plane: m1gcosθ = 15 x 9.8 x cos30° = 127.5 N. Finding the force of friction acting on the first block: μk = coefficient of kinetic friction = 0.25f = force of friction acting on the first block N = normal force acting on the first block N = perpendicular force acting on the first block = 127.5 Nf = μkN = 0.25 x 127.5 = 31.88 NThe net force acting on the first block:F = maF = m1aF = m1g sinθ - fF = 15 x 9.8 x sin30° - 31.88F = 73.5 - 31.88F = 41.62 N. Acceleration of the first block: a = F/m1a = 41.62/15a = 2.77 m/s². Finding the tension in the string: The tension in the string is the force acting on the second block. We can use the weight of the second block and the acceleration of the first block to find the tension.T - m2g = m1aT = m2g + m1aT = 13 x 9.8 + 15 x 2.77T = 127.4 NTherefore, the acceleration of the resulting motion is 2.77 m/s² and the tension in the string is 127.4 N.For more questions on acceleration
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2 points
13. The law of conservation of mass can be demonstrated by a chemical
reaction. Which of the following models of a chemical reaction best
represents the law of conservation of mass?
A
C
B
D.
8
8.
a.
Ο Ο Ο Ο
Answers
Answer:
A
Explanation:
the mass in the option a is conserved of two elements
A plane's average speed between 2 cities is 800 km/hr. If the trip takes 4.5 hours howfar does the plane fly?
Answers
Considering the average velocity can be written as:
\(v=\frac{\Delta s}{\Delta t}\)We can isolate the distance, and we get:
\(\Delta s=v*\Delta t\rightarrow\Delta s=800*4.5=3600km\)Then, the distance the plane flew is 3600km
Find the x-component of this vector: 12.1 m 48.4° Remember, angles are measured from the +x axis. X-component (m)
Answers
The x component of the vector is determined as 8.03 m.
What is the x -component of the vector?The x component of the vector is calculated by applying the following formula as shown below;
Vx = V cosθ
where;
V is the magnitude of the velocityθ is the angle of inclination of the vectorVx is the x component of the vectorThe x component of the vector is calculated as follows;
Vx = 12.1 m x cos (48.4⁰)
Vx = 8.03 m
Thus, the x component of the vector is determined as 8.03 m.
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Calculate the average velocity of a dancer who moves 5 m toward the left of the stage over the course of 15 s.
Answers
Answer:
divide the distance by the time and get average velocity in units of s. the detection to the left
. If block A has a velocity of 0.6 m/s to the right, determine the velocity of cylinder
Answers
Answer:
As we can see, a string is attached with block A, and three string is folded with ply which is attached with B
x
B
=3x
A
Now differentiate with respect to x
V
B
=3V
A
Given,
V
A
=0.6m/s(totheright)
So,
V
B
=0.6×3
=1.8m/s(downward)
Explanation:
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As we can see, a string is attached with block A, and three string is folded with ply which is attached with
zeugen and yardang differences
Answers
Answer:
Yardangs are formed on vertical strata while zeugen on horizontal strata. ... Yardangs are formed on vertical hard/soft layers of rock, while zeugen (this is its plural form) are formed on horizontal bands of hard/soft rocks giving it a more mushroom-like shape. The Great Sphinx of Giza has been sculpted in a yardang
what role does animals play in carbon cycle? and how does carbon cycle flow through earth?
Answers
A solenoid with 2,781 turns has a radius of 74.7 mm and is 38.4 cm long. If this solenoid carries a current of 68.4 A, what is the magnitude of the magnetic field near the center of the solenoid
Answers
Answer:
B = 0.62 T
Explanation:
Assuming that the solenoid can be treated as of infinite length (as its radius is much smaller than the length) we can consider that the magnetic field created by the current, near the center of it, is constant, and that it's almost zero outside it.Applying Ampere's law to a closed surface that encloses the wire carrying the current, we get:\(B= \mu_{o} *n*I (1)\)
where μ₀ = 4*π*10⁻⁷ T*m/A, n = turns per unit length = 2,781/0.384 m and I = 68.4 AReplacing by the givens in (1) we get:B= 4*π*10⁻⁷ T*m/A* 7242.2 (1 /m) * 68.4 A = 0.62 TB = 0.62 Twho is the father of kinematics ?
explain +)
Answers
Answer:
FRANZ REULEAUX
Late 19th century kinematics and the theory of machines as seen through the contributions of the German engineering scientist, Franz Reuleaux (1829-1905), often called the "father of kinematics". Extremely famous in his time and one of the first honorary members of ASME, Reuleaux was largely forgotten in much of modern mechanics literature in English until the recent rediscovery of some of his work. In addition to his contributions to kinematics, we review Reuleaux's ideas about design synthesis, optimization and aesthetics in design, engineering education as well as his early contributions to biomechanics. A unique aspect of this review has been the use of Reuleaux's kinematic models at Cornell University and in the Deutsches Museum as a tool to rediscover lost engineering and kinematic knowledge of 19th century history of machine.
An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
Answers
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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A 24.0kg dog running at a speed of 3.0 m/s jumps onto a stationary skateboard that has a mass of 3.6 kg. How long will it take a force with a magnitude of 9.0N to stop the skateboard and dog?
Given: ?
Unknown: ?
Solve and show your work
Answers
The time will take a skateboard and dog with force 9N to stop the skateboard and dog is 8 seconds.
The force is defined as the push or pull of an object. The force equals the mass and acceleration of the object obtained from Newton's second law. Acceleration defines the change in velocity by the time taken. The force is defined as the rate of change of momentum and time. Momentum is defined as the product of mass and velocity and the unit of momentum is Kg.m/s.
From the given,
mass of dog (m) = 24 kg
The initial speed of dog (u) = 3 m/s
mass of skateboard and dog = 3 + 24 = 27 kg.
The final speed of dog (v) = 0 m/s
Force = 9N
time =?
F = dp/dt, rate of change of momentum and time.
F(dt) = dp
dt = (dp)/F
=(Pf - Pi)/F
Pf is the final momentum and Pi is the initial momentum.
Pi = m×v = 24×3 = 72 kg.m/s²
Pf = m×v = 27×0 =0 kg.m/s²
dt = (0-72)/9
= 8s
Thus, the time taken to stop the skateboard and dog is 8s.
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What factors would create an ideal circuit?
Answers
An ideal circuit is a theoretical representation of an electrical circuit, where all components are perfect and all parameters such as resistance, capacitance, and inductance are zero.
The ideal circuit also has no energy losses, making it an ideal electrical system. To create an ideal circuit, the following factors must be considered:
1. Perfectly Conductive Wires: The wires and other conductors used in the circuit should be perfect conductors, which means the resistance should be zero. This will ensure that no energy is lost in the form of heat.
2. Zero Inductance: Inductance is a property of a circuit which causes a voltage drop when current flows through it. The ideal circuit should have no inductance so that the current can flow freely.
3. Zero Capacitance: Capacitance is a property in which electric charge builds up when current passes through it. To create an ideal circuit, the capacitance should be zero.
4. Zero Impedance: Impedance is the opposition to the flow of current in an electrical circuit. The ideal circuit should have zero impedance so that the current can flow freely.
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a man is standing near the edge of a cliff 85 meters high. he throws a stone upward vertically with an intial velocity of 10 m/s. the stone clears the cliff edge on the way down and falls all the way to the ground. what is the maximum height of the stone above the ground
Answers
Answer:
h = 90.10 m
Explanation:
Given that,
A man is standing near the edge of a cliff 85 meters high, h₀ = 85 m
The initial speed of the stone, u = 10 m/s
The path followed by the projectile is given by :
\(h(t)=-4.9t^2+10t+85\) ....(1)
For maximum height,
Put dh/dt = 0
So,
\(\dfrac{dh}{dt}=-9.8t+10=0\\\\t=\dfrac{10}{9.8}\\\\=1.02\ s\)
Put the value of t in equation (1).
\(h(t)=-4.9(1.02)^2+10(1.02)+85\\\\=90.10\ m\)
So, the maximum height of the stone is equal to 90.10 m.
What goes up must come down"-if you throw a baseball in the air, it will go upwards and then descend in a _____ curve.
Answers
Answer:
it will come down in a parabola curve
Define angle of deviation ?
Answers
Angle of deviation can be defined as the angle between the incident ray and the emergent ray when light passes through a prism.
What are related terms to Angle of deviation?When speaking of Angle of deviations, the incident ray is the ray of light that hitss the prism, while the emergent ray is the ray of light that emerges from the prism.
The angle of deviation is noted to be always greater than zero, and it can be used to calculate the refractive index of the prism.
The angle of deviation can be calculated using δ = i + r - A
δ is the angle of deviation
i is the angle of incidence
r is the angle of refraction
A is the angle of the prism
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Rasheeda made a model of a plant cell and labeled parts of the cell that are not found in animal cells. Which other part of the cell should Rasheeda label?
A) cytoplasm
B) large central vacuole
C) lysosomes
D) mitochondria
Answers
Answer:
Cytoplasm
Explanation:
6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
Answers
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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eporting results (1) Fifteen measurements of a resistance are quoted here based on approximately 10 repeat measurements. Only three of them obey the five golden rules. Identify the mistakes in the other results. (i) (99.8 ± 0.270) × 103 Ω, (ii) (100±0.3)× 103 Ω, (iii) (100.0±0.3)× 1039, (iv) (100.1 ±0.3) × 103, (v) 97.1 x 103-276Q, (vi) (99.8645 ± 0.2701) × 102 Ω, (vii) 98.6 x 103 ±3 × 10-Q,
Answers
The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.
What are the golden rules for reporting results?The five golden rules for reporting results are:
Always report the uncertainty in the measurement.Report the uncertainty to the same number of decimal places as the measured value.Use the correct units and prefixes.Avoid rounding until the final calculation.Report only the significant figures.Using these rules, identify the mistakes in the given results as:
(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.
(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.
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how to protect the ozone layer?
Answers
Answer:
\(\huge{\purple{\underline{\underline{\bf{\pink{Answer}}}}}}\)
we have to protect ozone layer because it is like blanket for earth . It protects the earth form uv rays that are coming from the sunwe have to take some preventive. measures like
Use ecofriendly things that Doesnot contain (cfc) . It is the major reason for ozone DeplitionEffects of uv rays
Uv rays are very harmful . If it directly comes in contact with human it cause skin cancer , eyes irritation etc.Hope it helps.
PLEASE PROVIDE EXPLANATION.
THANK YOU!!
Answers
Answer:
11,000 kg
(a) 11.2 m/s
(b) 1.6 m/s
Explanation:
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)
132,000 kg km/h = 22,000 kg km/h + m (10 km/h)
110,000 kg km/h = m (10 km/h)
m = 11,000 kg
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)
-mv + 10mv = m v₁ + 2m v₂
9mv = m (v₁ + 2 v₂)
9v = v₁ + 2 v₂
Since the collision is elastic, kinetic energy is also conserved.
½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²
m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²
(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²
mv² + 50mv² = m v₁² + 2m v₂²
51mv² = m (v₁² + 2 v₂²)
51v² = v₁² + 2 v₂²
We know v = 1.60 m/s. So the two equations are:
14.4 = v₁ + 2 v₂
130.56 = v₁² + 2 v₂²
Solve the system of equations using substitution.
130.56 = (14.4 − 2 v₂)² + 2 v₂²
130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²
0 = 6 v₂² − 57.6 v₂ + 76.8
0 = v₂² − 9.6 v₂ + 12.8
v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)
v₂ = 1.6 or 8
If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.
If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.
We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision. Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.
How has Physics improved
or affected our society?
Answers
By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life
From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.
The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.
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65. If Jill was traveling at 300 miles in 4 hours due South what was his velocity in miles per second,
a) 75 miles per hour due south
c) 5 miles per second due south
b) .02 miles per second due south d) 1 mile per hour due south
Answers
The velocity of Jill is 0.02 miles per second due south, the correct option is b.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity.
the mathematical expression for velocity is given by
\(Velocity = \dfrac{Displacement }{Time }\)
1 hour = 3600 seconds
4 hours = 4*3600 seconds
= 14400 seconds
Total displacement covered by the Jill = 300 miles
Total time taken by Jill = 14400 seconds
\(Velocity =\dfrac{300 miles }{14400seconds}\)
The velocity of Jill is 0.02 miles per second due south
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A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 231 kg. A small boy of mass m = 48 kg runs tangentially to the merry-go-round at a speed of v = 2.5 m/s and jumps on.
Answers
Required the moment of inertia of the merry go round.
a. I = 12 MR2 is the formula for the merry-go-moment round's of inertia.
I = ½ * 231 * (1.3 * 1.3)
I = 195.195 kgm2
b. The boy's angular speed is specified as = v/R = 2.5/1.3 = 1.92 rad/s.
c. I' = I + mR2 is the formula for the merry-go-moment round's of inertia following the boy's jump on it.
I’ = 195.195 + 48 * (1.3 * 1.3)
I’ = 276.315 kg/m2
The conservation of angular momentum principle determines the merry-go-angular round's speed. As a result, I (0) + m R = 'I' and = (48 * 1.92* 1.3) / 276.315 = 0.433 rad/s
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find a vector(s) of length √15m in the x-z plane that is perpendicular to the vector A= (2i+3j+k) m
Answers
The vector that is perpendicular to the original vector is vector B = (√3 i - 2√3 k )
What is the vector that is perpendicular to the original vector?The vector that is perpendicular to the original vector is calculated as follows;
Let the vector = B = (xi + 0j + zk)
The dot product of A and B must be equal to zero.
A . B = (2i + 3j + k) . (xi + 0j + zk)
A.B = 2x + z = 0
2x = - z
The product of the vector must be √15 and it is calculated as;
√ (x² + z²) = √15
x² + z² = 15
Substitute the value of x for z;
x² + (-2x)² = 15
x² + 4x² = 15
5x² = 15
x² = 15/5
x² = 3
x = √3
z = - 2x
z = -2√3
The vector B = (√3 i - 2√3 k )
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Calculate the absolute pressure at an ocean depth of 1.0 x 10³ m. Assume that the density of the water is 1.025 x 10³ kg/m³ and that Po = 1.01 x 10^5 Pa.
Answers
The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.
What is hydrostatic pressure?Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.
The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:
P = ρgh + Po
where:
P is the absolute pressure at the given depth
ρ is the density of the water
g is the acceleration due to gravity (assumed to be 9.81 m/s²)
h is the depth of the ocean
Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)
Substituting the given values, we get:
P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa
P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa
P = 1.002 x 10^8 Pa.
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The figure shows four particles, each of mass 30.0 g, that form a square with an edge length of d = 0.900 m. If d is reduced to 0.300 m, what is the change in the gravitational potential energy of the four-particle system?
Answers
The potential energy of the system have been observed as 0.7 J.
What is the change in the gravitational potential energy?We know that the potential energy is the energy that is possessed by an object that is found at a given height. The implication of this is that the potential energy depends on the height of the object.
If we decrease the height of the object then the potential energy of the body would also change. We have been told that the mass of the balls are 30 g each hence a total mass of 120 g or 0.12 Kg.
The change in the potential energy is;
0.12 * 9.8 * (0.9 - 0.3)
= 0.7 J
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What is the mass of a block of lead that is 30cm by 80cm by 60cm?
Answers
Calculating the mass of the block requires a bit of work. The formula for the volume of a rectangular solid is V = l*w*h, where V is the volume, l is the length, w is the width, and h is the height. Using the dimensions given, we can calculate the volume of the block as 30*80*60 = 144000 cubic centimeters.
The density of lead is approximately 11.34 grams per cubic centimeter. To calculate the mass of the block, we can use the formula m = V*d, where m is the mass, V is the volume, and d is the density. Plugging in the values we get m = 144000*11.34 = 1,634,400 grams or approximately 1.63 metric tons.
So, the mass of the block of lead is approximately 1.63 metric tons.