What’s the charge of a neutron?

From the chemical equation it is clear that, one mole or 16 g of methane gas gives 2 moles or 36 g of water. Then, 15 g gives 33.7 g of water. The actual yield is 23.8 g. Then the percent yield is 70.6%.

Percent yield of a reaction is the ratio of its actual yield to the theoretical yield multiplied by 100. The theoretical yield is calculated from the balanced chemical equation of the reaction.

molar mass of methane gas = 16 g/mol

molar mass of water = 18 g/mol

16 g of methane gives 2 moles or 36 g of water. Then 15 g of methane will gives:

(15×36)/16 = 33.7g

The actual yield of water = 23.8 g

then,

percent yield = 23.8 g/33.7 g × 100 = 70.6%.

Therefore, the percent yield of water is 70.6%.

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Calcium is expected to form Ca2+ ions, while nitrogen is expected to form N3- ions.

Calcium (Ca) is a Group 2 element with an atomic number of 20. It has two valence electrons in its outermost energy level. In order to achieve a stable electron configuration similar to the nearest noble gas, which in this case is argon (Ar), calcium tends to lose its two valence electrons.

By losing these two electrons, calcium forms a 2+ cation, denoted as Ca2+. The loss of two electrons leaves calcium with a complete octet in its previous energy level, making it more stable.

On the other hand, nitrogen (N) is a Group 15 element with an atomic number of 7. It has five valence electrons in its outermost energy level. In order to achieve a stable electron configuration similar to the nearest noble gas, which in this case is helium (He), nitrogen tends to gain three electrons.

By gaining three electrons, nitrogen forms a 3- anion, denoted as N3-. The acquisition of three electrons allows nitrogen to complete its octet in the previous energy level, resulting in a more stable configuration.

In summary, calcium (z = 20) forms Ca2+ ions by losing two electrons, while nitrogen (z = 7) forms N3- ions by gaining three electrons.

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Answer:

a. CH4+202→CO2+2H2O

b.Zn+2HCl→ZnCl2+H2

c.H2SO4+8HI→H2S+4I2+4H2O

d.4NaCl+2SO2+2H2O+O2→2Na2SO4+4HCl

o-Methylbenzoic acid is a monocarboxylic acid that is derived from benzoic acid by the addition of a methyl group (-CH3) at the ortho position (position 2) of the benzene ring. The chemical formula of o-methylbenzoic acid is C8H8O2, indicating that it contains eight carbon atoms, eight hydrogen atoms, and two oxygen atoms.

The molecular structure of o-methylbenzoic acid is characterized by a planar, aromatic benzene ring that is attached to a carboxyl group (-COOH) and a methyl group (-CH3). The benzene ring is composed of six carbon atoms and six hydrogen atoms, and it has alternating double bonds between the carbon atoms, which make it highly stable and resistant to chemical reactions.

The carboxyl group (-COOH) is attached to the benzene ring at position 1, and it consists of a carbonyl group (C=O) and a hydroxyl group (-OH). The carbonyl group is attached to the carbon atom of the benzene ring, while the hydroxyl group is attached to an oxygen atom. The carboxyl group is acidic, meaning that it can donate a proton (H+) to a base to form a salt.

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(a)

pH = 4.77

; (b)

[

H

3

O

+

]

=

1.00

×

10

-4

l

mol/dm

3

; (c)

[

A

-

]

=

0.16 mol⋅dm

-3

Explanation:

(a) pH of aspirin solution

Let's write the chemical equation as

m

m

m

m

m

m

m

m

l

HA

m

+

m

H

2

O

⇌

H

3

O

+

m

+

m

l

A

-

I/mol⋅dm

-3

:

m

m

0.05

m

m

m

m

m

m

m

m

l

0

m

m

m

m

m

l

l

0

C/mol⋅dm

-3

:

m

m

l

-

x

m

m

m

m

m

m

m

m

+

x

m

l

m

m

m

l

+

x

E/mol⋅dm

-3

:

m

0.05 -

l

x

m

m

m

m

m

m

m

l

x

m

m

x

m

m

m

x

K

a

=

[

H

3

O

+

]

[

A

-

]

[

HA

]

=

x

2

0.05 -

l

x

=

3.27

×

10

-4

Check for negligibility

0.05

3.27

×

10

-4

=

153

<

400

∴

x

is not less than 5 % of the initial concentration of

[

HA

]

.

We cannot ignore it in comparison with 0.05, so we must solve a quadratic.

Then

x

2

0.05

−

x

=

3.27

×

10

-4

x

2

=

3.27

×

10

-4

(

0.05

−

x

)

=

1.635

×

10

-5

−

3.27

×

10

-4

x

x

2

+

3.27

×

10

-4

x

−

1.635

×

10

-5

=

0

x

=

1.68

×

10

-5

[

H

3

O

+

]

=

x

l

mol/L

=

1.68

×

10

-5

l

mol/L

pH

=

-log

[

H

3

O

+

]

=

-log

(

1.68

×

10

-5

)

=

4.77

(b)

[

H

3

O

+

]

at pH 4

[

H

3

O

+

]

=

10

-pH

l

mol/L

=

1.00

×

10

-4

l

mol/L

(c) Concentration of

A

-

in the buffer

We can now use the Henderson-Hasselbalch equation to calculate the

[

A

-

]

.

pH

=

p

K

a

+

log

(

[

A

-

]

[

HA

]

)

4.00

=

−

log

(

3.27

×

10

-4

)

+

log

(

[

A

-

]

0.05

)

=

3.49

+

log

(

[

A

-

]

0.05

)

log

(

[

A

-

]

0.05

)

=

4.00 - 3.49

=

0.51

[

A

-

]

0.05

=

10

0.51

=

3.24

[

A

-

]

=

0.05

×

3.24

=

0.16

The concentration of

A

-

in the buffer is 0.16 mol/L.

hope this helps :)

The equilibrium constant of this reaction is 1.80×10-5

Given data,

pH of solution = 2.873

Number of moles of acetic acid (m) = 0.05 moles

Volume of water (V) =  500 mL = 0.5L

So, concentration (C) = m/V in lit = 0.05/0.5 = 0.1 M

Equilibrium constant ( K ) = \([CH_{3} COO-]\)×\([H+_{} ]\)/\([CH_{3} COOH]\)

Since, acetic acid is weak acid,

So, Equilibrium constant ( K ) = \([H+]^{2}\)/\([CH_{3} COOH]\)   ....(i)

As the pH = 2.873, the \([H+_{} ]\) is antilog of -2.873 or 1.34×10-3 M.

Putting the value of concentration of \(H+_{}\) and \(acetic_{} acid\) in equation (i).

Equilibrium constant ( K ) = 1.80×10-5

The acid which is partially dissociates into ions on dissolving in aqueous solution is called weak acid.

Example: \(acetic_{} acid\).

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1) the mass of an object gives gravity, the more massive an object is the more gravity it has on the things around it

2)the earth's mass is so much greater than our own that we feel it's gravity stronger than say the moon which has a smaller mass than the earth

3) mass and how far away you are from the object

4)as mass increases so does gravity (sorry I do not remeber the equation but there are some specific ones for different situations between two massive objects)

5) when distance increases, gravity decreases (again I do not remeber by how much)

The amount, in grams, of sucrose that will be contained in a 500 mL sample of the solution would be 30.6 grams..

The sucrose solution contains 0.34 moles of sucrose per liter of the solution. We want to determine the grams of sucrose that would be in a 500 mL sample of the solution.

Recall that: molarity = mole/volume. Note that the volume has to be in liters.

500 mL solution = 500/1000

                           = 0.5 liters

Molarity of the solution = 0.34 moles/liter.

Since: molarity = mole/volume

           mole = molarity x volume

                     = 0.34 x 0.5

                      = 0.17 moles

Also, recall: mole = mass/molar mass, thus: mass = mole x molar mass.

The molas mass of glucose is 180 g/mol.

Thus, the mass of 0.17 mol glucose = 0.17 x 180

                                                     = 30.6 grams

In other words, the mass of sucrose in a 500 mL sample of the solution would be 30.6 grams.

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1.  The 4s subshell should be filled before the 3d subshell because the 4s subshell is at lower energy than the 3d subshell.

Electrons fill the subshells in order of increasing energy.

2.  To write the electron configuration for the Na^+ ion, which has ten electrons, follow these steps:
  a. Begin with the lowest energy subshell, which is 1s.
  b. Fill the subshells with electrons in increasing energy order: 1s, 2s, 2p, 3s, and so on.
  c. Stop when you've added ten electrons.
The electron configuration for the Na^+ ion is: 1s^2 2s^2 2p^6

3. To write the electron configuration for the Br^- ion, which has thirty-six electrons, follow the same steps as above, but stop when you've added thirty-six electrons.

The electron configuration for the Br^- ion is: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6

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one negative charge because electrons have a negative charge

Answer: ITS D

Explanation: i was just looking answers for my test and this is my sisters account

The indicate alkanes in terms of e/z stereoisomer configuration is classified.

What is stereoisomer classification?

stereoisomer are the molecule that have the same molecular formula and sequence of bonded atoms.

It have chemical bond but they have different spital arrangments. Stereoisomer have two types

Configurational and conformational.

Sol-

stereoisomer of alkanes A is Z higher priority in each carbon oriented.

Thus the stereochemisty of alkanes C can be classified as Z.

And the stereochemisty of alkanes D is classified as non of either as per the question.

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Answer:

109.5 Degrees

Explanation:

Because CH4 is sp4 hybridized (Carbon is bonded to the 4 Hydrogens), the geometry of the molecule must be tetrahedral. Tetrahedral moleculues have bond angles of 109.5 Degrees.

The combined area of the 30 parks in Caldwell, Idaho is approximately 6,436,686,000 square meters.

There are approximately 100,562.66 square meters of green space per person in Caldwell, Idaho.

Caldwell has adequate green space according to the WHO guidelines, and no additional area is required.

a. To convert the combined area of 1,591,000 acres to square meters, we can use the conversion factor of 4,046 square meters per acre:

1,591,000 acres × 4,046 square meters per acre = 6,436,686,000 square meters

b. To find how many square meters of green space per person there are in Caldwell, Idaho, we can divide the total green space by the population:

6,436,686,000 square meters / 64,000 people ≈ 100,562.66 square meters per person

c. According to the World Health Organization (WHO), the minimum recommended amount of green space per person is 9 square meters, while the suggested area is 50 square meters.

Since Caldwell has approximately 100,562.66 square meters of green space per person, it meets both the minimum and suggested area requirements by a wide margin.

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Answer:

Prejudice

Explanation:

Answer: your answer would be prejudice.

The given statement is true that nonenzymatic E1 reactions can often result in a mixture of more than one alkene product. This is due to the presence of different possible elimination products.

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Spectator ion is the term given to the ions existing solely to maintain charge neutrality over a chemical species.

Spectator ions are ions that only exist to maintain charge neutrality. The presence of these ions is necessary to preserve charge neutrality even if they don't change chemically or physically during a process. Ionic solids are chemical neutral compounds as they have equal amounts of distribution of cations and anions throughout their composition.

When all the charges in a volume total up to zero, charge neutrality happens; it is neutral and neither positive nor negative. In other words, it indicates that a system's total positive charge and total negative charge must be equal.

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Answer:

A and D.

Explanation:

A shows that people continued to use more and more fossil fuels until around the middle of the time period where the cost of certain fossil fuels doubled. This helps show that less people were willing to pay this price and would start looking for other means of fuel. This leeads to D.

As people looked for other fuel sources renewable energy uses reached a high in 2012 which was after the cost of certain fuels had doubled.

Answer:

The answer should be that a constant pressure is applied to both cylinders and they are balanced chemical equations for the reaction between nitrogen oxygen.

Explanation:

128.8 atm is the work in atm done on the gas during this process.

W=pV, W = p V, where W is work, p is pressure, and V is the change in gas volume, can be used to calculate the work performed by a gas under a constant pressure.

The formula Work = Force Distance can be used to compute work. The joule (J) or Newton-meter (N-m) is the SI unit for work. The amount of work required to move an item one meter with one newton of force is equal to one joule.

Work done during a gas's expansion includes:

W = -PΔV

W = -P( Vfinal - Vintial)

w =  -92 ( 2.5 - 1.1 )

w = 128.8 atm

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The Electron geometry is trigonal bipyramid. molecular geometry is Liner

3orbitals are used to keep loan pairs on Rn

2 orbital are used to form two pi  bonds in the chlorine

Total hybridized orbital needed = 5

i.e. S,3p,1s

Hybridization = Sp^3d.

Electron geometry  = trigonal bipyramid

molecular geometry = Liner

We need to understand the Lewis electron dot structure in order to identify the forms of molecules. The Lewis hypothesis is the initial step in predicting molecular shapes, even though it does not itself specify how molecules would look. We can distinguish between bond pairs and lone pairs with the aid of the Lewis structure. We next use the Lewis structure to determine the molecular geometry and the electron-group geometry using the valence-shell electron-pair repulsion (VSPER) theory.

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The isotope effect in superconductivity suggests that the critical temperature decreases as the mass of the positive ions increases due to the changes in phonon dynamics and electron-phonon coupling in the crystal lattice.

The isotope effect in superconductivity refers to the phenomenon where the critical temperature (Tc) of a superconductor decreases as the mass of the positive ions increases.

This effect is observed when isotopes of an element with different masses are substituted into a superconducting material.

One way to argue why the critical temperature should decrease as the mass of the positive ions increases is by considering the effect of mass on the vibrational motion of atoms within the crystal lattice of the material.

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Answer:

The mass of solid object is 20.52 g.

Explanation:

Given data:

Volume of water = 36.1mL

Volume of water with metal cylinder = 43.7 mL

density of metal cylinder = 2.70 g/mL

Mass of solid object  = ?

Solution:

First of all we will calculate the volume of solid object.

Volume of solid object = Volume of water with metal cylinder  - Volume of water

Volume of solid object =  43.7 mL - 36.1mL

Volume of solid object =7.6 mL

Density:

density = mass/ volume

2.70 g/mL = mass / 7.6 mL

mass =  2.70 g/mL × 7.6 mL

mass = 20.52 g

The mass of solid object is 20.52 g.

1.The limiting reagent is O2, and the excess reagent is C2H6. 2. The moles of CO2 produced are 0.698 mol. 3, The grams of H2O produced are 18.87 g.

To determine the limiting reagent, we need to calculate the amount of product that can be formed from each reactant and compare the results.

Calculation of moles of C2H6:

Molar mass of C2H6 = 2(12.01 g/mol) + 6(1.01 g/mol) = 30.07 g/mol

Moles of C2H6 = 10.5 g / 30.07 g/mol = 0.349 mol

Calculation of moles of O2:

Molar mass of O2 = 2(16.00 g/mol) = 32.00 g/mol

Moles of O2 = 8.8 g / 32.00 g/mol = 0.275 mol

According to the balanced equation, the stoichiometric ratio between C2H6 and O2 is 2:7. Therefore, we can calculate the number of moles of O2 required for the given amount of C2H6:

Moles of O2 required = (0.349 mol C2H6) * (7 mol O2 / 2 mol C2H6) = 1.2225 mol

Comparing the moles of O2 available (0.275 mol) to the moles required (1.2225 mol), we can see that O2 is the limiting reagent because it is the reactant that is completely consumed first.

The excess reagent is C2H6 because there is still some remaining after the reaction.

Calculation of moles of CO2 produced:

According to the balanced equation, the stoichiometric ratio between C2H6 and CO2 is 2:4. Therefore, the moles of CO2 produced will be:

Moles of CO2 = (0.349 mol C2H6) * (4 mol CO2 / 2 mol C2H6) = 0.698 mol

Calculation of grams of H2O produced:

According to the balanced equation, the stoichiometric ratio between C2H6 and H2O is 2:6. Therefore, the moles of H2O produced will be:

Moles of H2O = (0.349 mol C2H6) * (6 mol H2O / 2 mol C2H6) = 1.047 mol

To convert moles of H2O to grams, we use the molar mass of H2O:

Molar mass of H2O = 2(1.01 g/mol) + 16.00 g/mol = 18.02 g/mol

Grams of H2O produced = 1.047 mol * 18.02 g/mol = 18.87 g

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The key differentiating factor between a nonpolar covalent bond and a polar covalent bond is the unequal sharing of electrons.

i. Unequal sharing of electrons: In a nonpolar covalent bond, electrons are shared equally between the atoms. This occurs when the atoms have similar electronegativity, meaning they have similar abilities to attract electrons. As a result, there is no significant difference in the electron distribution, and the atoms do not acquire partial charges.

ii. Ions: Ions are charged particles that have gained or lost electrons. Unlike ionic bonds, which involve the complete transfer of electrons, covalent bonds involve the sharing of electrons between atoms. Therefore, the presence of ions does not differentiate between nonpolar and polar covalent bonds.

iii. Atoms of partial charge: In a polar covalent bond, there is an unequal sharing of electrons due to differences in electronegativity between the atoms. One atom has a stronger pull on the shared electrons, resulting in a partial negative charge (δ-) on that atom, while the other atom has a partial positive charge (δ+).

This imbalance in electron distribution creates atoms of partial charge.

Therefore, the key distinguishing characteristic between a nonpolar covalent bond and a polar covalent bond is the unequal sharing of electrons, leading to the development of partial charges on the atoms in a polar covalent bond.

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The bubble in the tip of the burette will lead to an inaccurate final reading of the volume of NaOH at the end point of the titration.

The reading will be biassed high as a result of the bubble. This is so that, without really contributing to the measurement, the bubble will increase the volume of NaOH in the burette.

The bubble is not a component of the measurement, thus any volume it occupies will be added to the final value, making the reading higher than it should be.

As a result, the bubble will produce an unreliable and skewed high reading, which could result in false results.

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The fractional saturation of hemoglobin when po, is (a) 20 torr is 0.279, 40 torr is 0.545 and 60 torr is 0.747.

Y02 = (p02)n / (p50)n + (p02)n

From the given equation, we can estimate the fractional saturation of hemoglobin when PO2 is 20, 40 and 60 torr.

Y02 = (20)n / (p50)n + (20)n

= 0.279

Y02 = (40)n / (p50)n + (40)n

= 0.545

Y02 = (60)n / (p50)n + (60)n

= 0.747

The fractional saturation of hemoglobin for a PO2 of 20 torr is 0.279,

for a PO2 of 40 torr is 0.545,

and for a PO2 of 60 torr is 0.747.

In conclusion, we can say that the fractional saturation of hemoglobin is an important parameter for determining the oxygen-carrying capacity of blood. The above equation helps us to estimate the fractional saturation of hemoglobin when PO2 is given.

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The empirical formula for the ccompound, given the data is C₇H₈

The mass OC carbon in the compound can be obtained as follow:

Mass of C = (12 / 44) × 4.10

Mass of C = 1.118 mg

Mass of H = (2 / 18) × 0.959

Mass of H = 0.107 mg

The empirical formula can be obtained as follow:

Divide by their molar mass

C = 1.118 / 12 = 0.093

H = 0.107 / 1 = 0.107

Divide by the smallest

C = 0.093 / 0.093 = 1

H = 0.107 / 0.093 = 1.15

Multiply through by 7 to express in whole number

C = 1 × 7 = 7

H = 1.15 × 7 = 8

Thus, the empirical formula of the compound is C₇H₈

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a. Silver coin - Element (Silver is a pure element and is not chemically combined with any other element in a silver coin)

b. Air - Mixture (Air is a mixture of gases, primarily nitrogen and oxygen, with trace amounts of other gases and particles)

c. Coffee - Mixture (Coffee is a mixture of various compounds such as water, caffeine, and organic compounds that give it its flavour and aroma)

d. Soil - Mixture (Soil is a mixture of various substances such as minerals, organic matter, water, and air)

My everyday experiences influenced my response because I have come across these examples in my daily life and have been taught about them in science classes. For example, I know that air is composed of different gases and particles, and that soil is made up of a mixture of substances, including minerals and organic matter. Similarly, I know that a silver coin is made of pure silver and that coffee is made of various compounds.

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The treatment requirement (% removal) in the agricultural waste discharge to achieve 50mg/L concentration in the withdrawal location 80 km downstream is 99.57%

a. Control Volume

The schematic diagram of the control volume is given below.

b. Steady-state Phosphate concentration in water withdrawn 90 km downstream

The steady-state phosphate concentration in the water withdrawn 90 km downstream is given by:

C2 = (Q1C1 + Q2C2)/(Q1 + Q2)

Where,

C2 = Concentration of phosphate in the water withdrawn 90 km downstream

C1 = Concentration of phosphate in the upstream water (25 ppm)Q1 = Upstream flow (40 m 3/s)Q2 = Agricultural discharge (2.5 m^3/s)C2 = ((40 x 25) + (2.5 x 1000)) / (40 + 2.5)C2 = 59.3 ppm

Therefore, the steady-state phosphate concentration in the water withdrawn 90 km downstream is 59.3 ppm.c. Treatment requirement (% removal) in the agricultural waste discharge to achieve 50mg/L concentration in the withdrawal location 80 km downstream

The concentration of the waste-stream that will produce 50mg/L downstream concentration is given by:

50 = (Q1C1 + Q2C2)/(Q1 + Q2)C2 = ((40 x 25) + (2.5 x C2))/(40 + 2.5)50 = (1000 x 2.5) / (40 + 2.5) + (40 x 25) / (40 + 2.5)C2 = 4.3 ppm

The % removal from the difference of the influent wastewater concentration with respect to the initial waste-stream concentration is given by:

% removal = (C in - C out) / C in x 100Where,Cin = Influent wastewater concentration (1000 ppm)

C out = Concentration of waste-stream required to produce 50 ppm downstream concentration (4.3 ppm)\% removal = (1000 - 4.3) / 1000 x 100\% removal = 99.57%

Therefore, the treatment requirement ( % removal) in the agricultural waste discharge to achieve 50mg/L concentration in the withdrawal location 80 km downstream is 99.57%.

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Methane molecule is nonpolar and contains a nonpolar covalent bond.

Methane (CH₄) molecule has a tetrahedral shape with the carbon atom at the center and four hydrogen atoms attached to the corners of the tetrahedron. Methane has nonpolar covalent bonds between the carbon and hydrogen atoms because the difference in electronegativity is minimal and therefore the electrons are shared equally.

The molecule is nonpolar due to the symmetric arrangement of the bonds and because the dipole moments of the individual bonds cancel each other out. This means that there is no positive or negative end to the molecule and it cannot dissolve in polar solvents. Methane is a gas at room temperature and is the simplest hydrocarbon, which is the foundation of many organic compounds.

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