What’s the correct answer for this?

Answer: x = √-6 - 4

Step-by-step explanation:

x^2+8x+22=0

(x+4)^2 - 16 + 22 = 0

(x+4)^2 + 6 = 0

(x+4)^2 = -6

√(x+4)^2 = √-6

x = √-6 - 4            

√6 = 2.449

Answer:

is it just that one graph

Step-by-step explanation:

Answer:hmm

Step-by-step explanation:

Jane has 6 - 14 - 12 = -20 boxes of beads left.

Jane initially had 6 boxes of beads.

She used 14 of those boxes to make face mask holders and gave 12 boxes to her sister.

To find out how many boxes of beads she has left, we need to subtract the boxes used and given away from the initial number.

First, let's calculate the total number of boxes used and given away:

Total boxes used and given away = Boxes used for face mask holders + Boxes given to sister

Total boxes used and given away = 14 + 12

Total boxes used and given away = 26

Next, we can subtract the total boxes used and given away from the initial number of boxes Jane had:

Boxes left = Initial number of boxes - Total boxes used and given away

Boxes left = 6 - 26

Boxes left = -20

The result is -20, which implies that Jane has a deficit of 20 boxes of beads.

This means she doesn't have any boxes of beads left; she has a shortage of 20 boxes based on the activities she performed.

It's important to note that having a negative value indicates that Jane doesn't have enough boxes to fulfill her activities.

If the result were positive, it would represent the number of boxes remaining.

However, in this case, Jane has used and given away more boxes than she initially had, resulting in a negative value.

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Answer: 2 dolls

Step-by-step explanation: got it right

Answer:

24:26 and 36:39 are two ratios that are equivalent to 12:13.

Step-by-step explanation:

Answer:

Prove what is similar?????

Answer:

Mr.Lim had 19610 dollars, and Mr.Tay had 11480 dollars at first.

Step-by-step explanation:

Mr. Lim had 19610 dollars at first.

Given:

Mr. Lim and Mr. Tay had $31 090 at first.

Mr. Lim donated $2390 of his money and

Mr. Tay spent half of his money on a holiday trip.

Mr. Lim had 3 times as much money as Mr. Tay.

Step 1:

Let Mr. Tay had x

Let Mr. Lim had y

x + y=31090………..(1)

Step 2:

Mr. Tay spent on holiday = x + 2390/2

Money left with Mr. Lim = y - 2390

Given,

y - 2390 = 3(x + 2390/2) .............(2)

Step 3:

Equating equation (1) and (2)

we get,

x = 11480

y = 19610

Hence, Mr. Lim has $19610, and Mr. Tay had $11480 dollars at first.

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Answer:

548 > 373

Step-by-step explanation:

548 is greater than 373 because when we compare the digits from left to right, we find that the first digit of 548 (5) is greater than the first digit of 373 (3). Therefore, we can conclude that 548 is greater than 373.

The ">" symbol is used to represent "greater than" in mathematical comparisons.

Hope this helps!

Answer:

The correct answer is C.

Step-by-step explanation:

There are 8 slots on Spinner B.

3 of those slots have squares.

Hence out of all the slots, 3/8 of them have squares.

Hope this helps:) Goodluck!

Answer:

Choice C true

Step-by-step explanation:

The Probability is found by  good/total

Spinner A

P(square) = 1/4 - choice A not true

Spinner A

P(circle) = 1/4

Spinner B

P(circle) = 3/8

1/4 does not equal 3/8  Choice B not true

Spinner B

P(square) = 3/8 = Choice C true

Answer: \(7.39466666\)

Step-by-step explanation:

Setting \(x=2.2\) and \(n=3\),

\(e^{2.2} \approx \sum^{3}_{k=0} \frac{2.2^{k}}{k!}=\frac{2.2^0}{0!}+\frac{2.2^1}{1!}+\frac{2.2^2}{2!}+\frac{2.2^3}{3!} \approx 7.39466666\)

Answer:

7.39466667 (8 d.p.)

Step-by-step explanation:

We can approximate the value of eˣ for any x using the following sum formula:

\(\boxed{e^{x} \approx \displaystyle \sum^n_{k=0}\dfrac{x^k}{k!}}\)

To approximate \(e^{2.2}\) with n = 3, substitute x = 2.2 and n = 3 into the given sum formula:

\(e^{2.2} \approx \displaystyle \sum^3_{k=0}\dfrac{2.2^k}{k!}\)

To calculate the sum, substitute k with each value from 0 to 3 and add the results together:

\(\begin{aligned}e^{2.2} &\approx \displaystyle \sum^3_{k=0}\dfrac{2.2^k}{k!}\\\\&= \dfrac{2.2^0}{0!}+\dfrac{2.2^1}{1!}+\dfrac{2.2^2}{2!}+\dfrac{2.2^3}{3!}\\\\&= \dfrac{1}{1}+\dfrac{2.2}{1}+\dfrac{4.84}{2}+\dfrac{10.648}{6}\\\\&= 1+2.2+2.42+1.774666666...\\\\&=7.39466667\; \sf (8\;d.p.)\end{aligned}\)

Therefore, the approximate value of \(e^{2.2}\) is:

\(\large \textsf{$e^{2.2}$}=\boxed{7.39466667}\; \sf (8\;d.p.)}\)

Note: To obtain a more accurate approximate value, increase the value of n.

Answer

is a vertical line, as shown above. The slope of the line is undefined.

Answer: (x+6)(x-3)

Step-by-step explanation:

y=x^2+3x-18

(x+6)(x-3 )

Answer:

Here's your answer

Step-by-step explanation:

Answer:

12/20

Step-by-step explanation:

\(\displaystyle \frac{3}{5}=\frac{3}{5}\cdot\frac{4}{4}=\frac{12}{20}\)

The answer is:

In-depth-explanation:

The denominator of 3/5 is 5. To get from 5 to 20, we multiply it by 4.

We need to multiply both the numerator and the denominator by 4, so we do this:

\(\sf{\dfrac{3\times4}{5\times4}}\)

\(\sf{\dfrac{12}{20}}\)

Using the distance formula, the length of segment PQ is:

C. √68 units

The distance formula is given as:

d = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\).

Segment PQ has the following endpoints:

P(-2, 3)

Q(6, 1)

To find the length of segment PQ using the distance formula, we can apply the formula, where:

\((x_1, y_1)\)are the coordinates of point P

\((x_2, y_2)\) are the coordinates of point Q.

Given:

P(-2, 3) = \((x_1, y_1)\)

Q(6, 1) = \((x_2, y_2)\)

Let's substitute the values into the formula:

PQ = √[(6 - (-2))² + (1 - 3)²]

PQ = √[(8)² + (-2)²)

PQ = √(64 + 4)

length of segment PQ = √68 units

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\( \Large{\boxed{\sf | \sf z| = \sf \sqrt{40} = 2\sqrt{10} }} \)

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We are given a complex number in algebraic form, and we would like to find its modulus, |z|.

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Let's recall that a complex number in algebraic form is written as \( \sf z = a + ib \) , where a is its real part and b is its imaginary part.

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The modulus of said complex number is calculated as follows:

\( \sf | \sf z| = \sqrt{a^2 + b^2} \)

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\( \hrulefill \)

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Let's identify our values:

\( \sf z = -2 - 6i \Longleftrightarrow z = \underbrace{\sf -2}_{\sf a} + (\underbrace{\sf -6}_{\sf b})i \)

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Now, substitute these values into our formula:

\( \sf | \sf z | = \sqrt{(-2)^2 + (-6)^2} = \sqrt{4 + 36} = \boxed{\sf \sqrt{40}} \)

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While this may be optional, the result can be simplified by using the following property:

\(\green{\begin{gathered}\begin{gathered} \\ \boxed { \begin{array}{c c} \\ \blue{ \star \: \sf{\boxed{ \sf Product \: rule \: of \: square \: roots\text{:}}}} \\ \\ \sf{ \diamond \: \sqrt{ab} = \sqrt{a} \times \sqrt{b} } \\ \end{array}}\\\end{gathered} \end{gathered}}\)

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\( \sf \sqrt{40} = \sqrt{4 \cdot 10} = \sqrt{4} \cdot \sqrt{10} = \boxed{\boxed{\sf 2\sqrt{10}}} \)

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\( \hrulefill \)

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Answer:

X ~ (350, 0.5)

0.00009

Step-by-step explanation:

Given that:

Daily passenger volume = 350

Since both airlines A and B have equal probability ;

p = 0.5

n = 350

X ~ (n, p)

X ~ (350, 0.5)

B.)

Mean, m= np = 350 * 0.5 = 175

Standard deviation, s = sqrt(np(1-p)) = sqrt(350*0.5*0.5) = sqrt(87.5)

Obtaining standardized score, Z

Z = (x - m) / s

x = 210

Z = (210 - 175) / sqrt(87.5)

Z = 35 / sqrt(87.5)

Z = 3.74

P(Z > 3.74) = 0.00009 (Z probability calculator)

Answer:

25000

Step-by-step explanation:

Answer:

Therefore, you need 2600 pounds of 35% supplement and 1300 - 2600 = -1300 pounds of 10% ration.

Step-by-step explanation:

The unknown variable is x, which is the amount of 35% supplement needed. The other expressions are derived from the given information and the fact that the total amount of solution is 1300 pounds.

The equation from the fourth column is:

0.35x + 0.10(1300 - x) = 0.25(1300)

Solving for x, we get:

x = (0.25(1300) - 0.10(1300)) / (0.35 - 0.10) x = 650 / 0.25 x = 2600

Answer:

x=-3, That is the x value of the vertex, and it is a vertical parabola.

Answer:

80/100

Step-by-step explanation:

i know that .....

Answer:

L x W (original)

(L+3) x w     (one dimension changed)

(L+3)(W+3)   (both dimensions changed)  

Step-by-step explanation:

Rectangle when one dimension increase 3 units, area will change from original (L and w are its two sides)

L x W to (L+3) x w

If both dimension increase 3 units, the area will become

(L+3)(W+3)

The x-intercepts are (-2, 0) and (2, 0), the minimum is at (0, -3), and the line of symmetry is x = 0 if the equation of the parabola is y = x²—4

It is defined as the graph of a quadratic function that has something bowl-shaped.

Here the graph or equation is not given:

So we are assuming the equation for the parabola is:

y = x²—4

If we plot the graph of the parabola, we can say:

Thus, the x-intercepts are (-2, 0) and (2, 0), the minimum is at (0, -3), and the line of symmetry is x = 0 if the equation of the parabola is y = x²—4

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Slope is the change in y over the change in x.

Using the first and last value, the change in x would be the change from -4 to 4 which is 8

The change y y would be the change from -16 to 24 which is 40

The slope would be 40/8 which reduces to 5

The answer is 5

Answer Key:

1. Since the question says Mr. Smith runs 2.7 miles every day of the week, you will need to multiply it with 365, the days of the year. The total answer you would get D. 985.5 miles.

| I just want to help you with #2 anyway