When a mass M hangs from a vertical wire of length L, waves travel on this wire with a speed V. What will be the speed of these waves (in terms of V) if a) We double M without stretching the wire? b) We replace the wire with an identical one, except twice as long? c) We replace the wire with one of the same length, but three times as heavy? d) We stretch the wire to twice its original length? e) We increase M by a factor of 10, which stretches the wire to double its original length.

Answer:

a) The work done by the force is 136.400 joules.

b) The speed of the mass at the end of the 3.5 meters is approximately 11.679 meters per second.

Explanation:

The correct statement is shown below:

A 2-kg mass is initially at reat on a frictionless surface. A 45 N force acts at an angle of 30º to the horizontal for a distance of 3.5 meters:

a) Find the work done by the force.

b) Find the speed of the mass at the end of the 3.5 meters.

a) Given that a external constant force is acting on the mass on a frictionless surface, the work done by the force (\(W_{F}\)), measured in joules, is:

\(W_{F} = F\cdot \Delta s \cdot \cos \theta\) (1)

Where:

\(F\) - External constant force exerted on the mass, measured in newtons.

\(\Delta s\) - Horizontal travelled distance, measured in meters.

\(\theta\) - Direction of the external force regarding the horizontal, measured in sexagesimal degrees.

If we know that \(F = 45\,N\), \(\Delta s = 3.5\,m\) and \(\theta = 30^{\circ}\), then the work done by the force is:

\(W_{F} = (45\,N)\cdot (3.5\,m)\cdot \cos 30^{\circ}\)

\(W_{F} = 136.400\,J\)

The work done by the force is 136.400 joules.

b) The final speed of the mass at the end ot the 3.5 meter is calculated by means of the Work-Energy Theorem, which means that the work done on the mass is transformed into a translational kinetic energy. That is:

\(W_{F} = \frac{1}{2}\cdot m \cdot (v_{2}^{2}-v_{1}^{2})\) (2)

Where:

\(m\) - Mass, measured in kilograms.

\(v_{1}\), \(v_{2}\) - Initial and final speeds of the mass, measured in meters per second.

If we know that \(W_{F} = 136.400\,J\), \(m = 2\,kg\) and \(v_{1} = 0\,\frac{m}{s}\), then the final speed of the mass is:

\(\frac{2\cdot W_{F}}{m} = v_{2}^{2}-v_{1}^{2}\)

\(v_{2}^{2} =v_{1}^{2}+\frac{2\cdot W_{F}}{m}\)

\(v_{2} =\sqrt{v_{1}^{2}+\frac{2\cdot W_{F}}{m} }\)

\(v_{2} =\sqrt{\left(0\,\frac{m}{s} \right)^{2}+\frac{2\cdot (136.400\,J)}{2\,kg} }\)

\(v_{2} \approx 11.679\,\frac{m}{s}\)

The speed of the mass at the end of the 3.5 meters is approximately 11.679 meters per second.

Answer: Height of object = 29.13475

Hope this helps!

Answer: 29.12 Meters.

Explanation:

Answer:

5.0-5.5 is the answer to your question

The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.

First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:

ΣFy = R − 7 kN − 3 kN

ΣFy = 0

This gives:

R = 10kN

Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:

ΣFx = L

ΣFx = 0

This indicates that there is no horizontal force acting on the structure.

Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

Find out more on reaction of load here: https://brainly.com/question/31992040

#SPJ1

Answer:

The initial velocity of this shark is \(8.0\; \rm m \cdot s^{-1}\). (Assuming that the unit of the acceleration in this question is \(\rm m\cdot s^{-2}\).)

Explanation:

Let \(a\) denote the acceleration of this shark.

Let \(v_0\) denote the initial velocity of this shark.

Assume that the acceleration \(a\) of this shark is constant (as it is in this question.) Over a period of time \(t\), the shark would have travelled a distance of:

\(\displaystyle x = \frac{1}{2}\, a\, t^2 + v_0\, t\).

This question states that:

This question is asking for \(v_0\), the initial velocity of this shark at the beginning of this \(0.8\)-second period. Substitute the three known values into the equation:

\(\displaystyle 11.52 = \frac{1}{2}\times 16\times (0.8)^2 + 0.8\, v_0\).

Solve for \(v_0\):

\(v_0 = \displaystyle \frac{11.52 - (1/2) \times 16 \times (0.8)^2}{0.8} = 8.0\; \rm m \cdot s^{-1}\).

Explanation:

Using Equations of Motion :

\(s = ut + \frac{1}{2} g {t}^{2} \)

Height = 0 * 4 + 4.9 * 16

Height = 78.4 m

Answer:

31.68 m/s

Explanation:

The law of conservation of energy states that energy is not lost or gained it is just converted, in this example, since it is not given any resistance from the wind, you'd have two variables Speed on the Y-axis and on the X-axis, since both of them would result in the same decrease and increase with against gravity, it doesn't matter the value of both.

As the stone continues to go upwards it will continue to lose speed due to de-acceleration from the gravity acting on it, similarly, it will continue to gain Potential energy, instead of kinetic energy, when it reaches its highest point the speed on Y will be "0" and the free fall will start, since the up and down movement will be equal in time the and acceleration would be equal -9.81 m/s and 9.81 m/s because the only acceleration you have is gravity, you only need to calculate how much speed will gain a rock accelerating at 9.81 m/s falling 20 m:

\(H=\frac{1}{2}g*t^{2} \\\frac{20}{1/2*9.81} =t^{2} \\\\t^{2} =4.08\\t=\sqrt{4.08} \\t=2.21\)

Now we just add the time accelerating:

\(Vf=Vo+at\\Vf=10 m/s+ 2.21*9.81\\Vf=10 m/s+21.68\\Vf=31.68 m/s\)

The cyclist's kinetic energy, measured in joules, is 2746.04 J. 125 Joules are the same as the kinetic energy, or (1/2 * 10 kg) * 5 m/s2.

The energy that drives motion is known as kinetic energy (KE). Kinetic energy is the force that drives motion. The mass and speed of an object moving determine how much kinetic energy it has.

According to classical physics, kinetic energy (KE) is determined by multiplying the mass of an item by the square of its velocity, or 1/2*m. As an illustration, consider an object having a mass of 10 kg (m = 10 kg) and a speed of 5 m/s (v = 5 m/s).

To know more about kinetic energy visit;-

https://brainly.com/question/26472013

#SPJ1

Alkali and alkaline earth metals invariably produce cations.

Calcium (Ca2+), potassium (K+), and hydrogen (H+) are a few examples of cations.

Positively charged ions are referred to as cations. Less electrons than protons make up cations. An ion can be made up of a single atom of an element (a monatomic ion, monatomic cation, or monatomic anion) or many atoms that are chemically connected to one another (a polyatomic ion or polyatomic cation or anion)

Alkali and alkaline earth metals always create cations, whereas halogens always produce anions. Most nonmetals normally create anions, while the majority of other metals typically produce cations (such as iron, silver, and nickel) (e.g. oxygen, carbon, sulfur)

To know more about cations visit:-

https://brainly.com/question/28710898

#SPJ13

First, draw a diagram to visualize the situation:

The directions of the forces are shown in the diagram. Remember that charges with opposite sign attract each other, while charges with the same sign repel each other.

Use Coulomb's Law to find the magnitude of each force. Next, find the X and Y components of each force. Next, combine the components to find the components of the net force, and finally, use the components of the net force to find the magnitude of the force on a 1μC charge placed at the center of the square.

The distance between the center of a square with length L and its corner is:

Then, the distance between the charge at the center of the square and the rest of the charges is:

According to Coulomb's Law, the force between two charged particles separated by a distance r is:

Where k is the Coulomb's Constant:

Calculate the magnitude of the force that each charge on the corner of the square creates over the charge at the center:

+12.21μC:

-16.95μC:

-7.62μC:

+13.6μC:

Notice that two pairs of forces act in the same direction, so we can add them arithmetically:

These forces act on the particle at the center according to the following diagram:

As we can see from the diagram, the forces of 8.8N and 13.6N are perpendicular, so the net force turns out to be the diagonal of a rectangle whose sides measure F1 and F2.

Then, instead of finding the vertical and horizontal components of each force, we can see from the Pythagorean Theorem that the magnitude of the net force is given by:

Therefore, the magnitude of the force on a 1microCoulomb charge placed at the center of the square, is approximately 16.24N.

Answer:

0.1707 N

Explanation:

From the question,

Applying Coulombs law

F = kqq'/r²................... Equation 1

Where F = Electric Force, q = First charge, q' = second charge, r = distance between the charges, k = coulomb's constant

Given: q = -6.67×10⁻⁶ C, q' = -5.27×10⁻⁸C, r = 0.43 m

Constant: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation 1

F = [(-6.67×10⁻⁶)(-5.27×10⁻⁸)(8.98×10⁹)]/(0.43)²

F = (315.655×10⁻⁵)/(0.1849)

F = 1707.17×10⁻⁵

F = 1.7072×10⁻²

F = 0.1707 N

The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

for such more questions on electric

https://brainly.com/question/1100341

#SPJ8

The formula for the horizontal component (Fx), which is the angle the force makes with the horizontal, is Ftens•cosine(). Ftens• sine() can be used to compute the upward component (Fy), where is the angle that the force produces with the horizontal.

The portion of a force that works horizontally with regard to a body is known as its horizontal component. Its vertical component is known as its vertical component.

The pulling of the box is with the rope horizontal. When the rope is angled Because Is less than, the horizontal component (= F cos ) is less. As a result, it is the proper response.

To know more about force visit:-

https://brainly.com/question/13191643

#SPJ1

The most logical conclusion to make in light of the facts available is that the electric field is directed to the left. This conclusion may be drawn from the fact that a negative test charge, which is attracted to positive charges and repels other negative test charges, feels a force to the right.

The force applied to the negative test charge suggests the presence of positive charges in the electric field, indicating that the field lines begin with positive charges and end on negative charges since opposing charges attract.

The assumption that electric field lines originate from positive charges and end on negative charges is supported by this deduction. As a result, in this situation, the electric field is directed leftward.

To know more about light :

https://brainly.com/question/29994598

#SPJ1.

Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

The total distance covered by the car is 300 miles.

The total displacement covered by the car is zero.

The average speed of the car is 17.88 m/s.

The average velocity of the car is also zero.

Distance between the points A and B, d = 150 miles

Time taken by the car to travel from A to B, t₁ = 3 hours

Time taken by the car to travel from B to A, t₂ = 5 hours

a) Given that the car travelled from A to B and then back to A.

Therefore, the total distance covered by the car is,

Distance = 2 x d

Distance = 2 x 150

Distance = 300 miles

Since the car is travelling from A to B and then returning back to the initial point A, the total displacement covered by the car is zero.

b) The speed with which the car travelled from A to B is,

v₁ = d/t₁

v₁ = 150/3

v₁ = 50 miles/hr

v₁ = 22.35 m/s

The speed with which the car travelled from B to A is,

v₂ = d/t₂

v₂ = 150/5

v₂ = 30 miles/hr

v₂ = 13.41 m/s

Therefore, the average speed of the car is,

v = (v₁ + v₂)/2

v = (22.35 + 13.41)/2

v = 17.88 m/s

As, the total displacement of the car is zero, the average velocity of the car is also zero.

To learn more about average speed, click:

https://brainly.com/question/10449029

#SPJ1

The apparatus that can used to measure the mass of the wooden block​ by the student is called beam balance.

A beam balance, often referred to as a double-pan balance, is a straightforward tool for determining an object's weight. Two pans or trays are hung from either end of a horizontal beam that is suspended from a pivot point in the middle.

The thing to be weighed is put on one tray, and then the second tray is filled with standard weights until it balances, showing the weight of the object. From little ones used in laboratories to larger ones used in enterprises, beam balances can be found in a variety of shapes and sizes. Because they are precise and operate without electricity or batteries, they are widely used.

To know more about beam balance, visit,

https://brainly.com/question/30386877

#SPJ1

Answer:

I did the assignment and got 100%. I recommend using Quilbot to paraphrase everything and use Prepostseo Plagiarism Checker.

Explanation:

(PDF Attached "Momentum/Force of Impact Portfolio)

Good Luck.

We can do this by designing airbags and seat belts with more stopping power. Instead, we can design brake systems and automobiles that take longer to come to a complete stop, which will minimise the force experienced by the occupants.

A force is an effect that tends to move a stationary object into motion, stop a moving object, alter the speed and direction of a moving object, or alter the size and shape of a body.

From Newton's 2nd law of motion, we can write,

Force = Change in momentum/time.

Hence, force is inversely proportional to the time. So, during collision, we can reduce the force on the driver and passengers by increase the time of impact. We can accomplish this by creating seat belts and airbags with greater stopping force. Instead, we can create brake systems and vehicles that require more time to stop completely, reducing the force felt by the occupants.

To find more about force, refer the link:

https://brainly.com/question/13191643

#SPJ2

Answer: The answer is a because that's where it would be after it bounced

Answer:

Temperature of the air in the balloon = 272°C

Explanation:

Given:

Volume of balloon = 500 m³

Air temperature = 15° C = 273 + 15 = 288 K

Total weight = 290 kg

Density of air = 1.23 kg/m³

Find:

Temperature of the air in the balloon

Computation:

Density of hot air = Density of air - [Total weight / Volume of balloon]

Density of hot air = 1.23 - [290 - 500]

Density of hot air = 0.65 kg/m³

[Density of hot air][Temperature of the air in the balloon] = [Density of air][Air temperature ]

Temperature of the air in the balloon = [(1.23)(288)]/(0.65)

Temperature of the air in the balloon = 544.98

Temperature of the air in the balloon = 545 K

Temperature of the air in the balloon = 545 - 273 = 272°C

Temperature of the air in the balloon to lift a total load of 290 kg is 272°C.

Temperature is the degree of hotness or coldness of the object.

Given is Volume of balloon = 500 m³, Air temperature = 15° C = 273 + 15 = 288 K

Total weight = 290 kg and Density of air = 1.23 kg/m³

Density of hot air = Density of air - [Total weight / Volume of balloon]

Density of hot air = 1.23 - [290 - 500]

Density of hot air = 0.65 kg/m³

Density is inversely proportional to the temperature.

[ρ hot air] x [T air in the balloon] = [ρ air] x [T air ]

Putting the values, we get temperature of the air in the balloon is

T air = [(1.23)(288)]/(0.65)

T air in Kelvin is 545 K

T air in Celcius is  545 - 273 = 272°C.

Thus, the temperature of the air in balloon is 272°C.

Learn more about temperature.

https://brainly.com/question/11464844

#SPJ5

Answer:

Velocity Has vector Quantity

Answer:

number 3

Explanation:

3 represents runoff

Runoff is the water collected after rainfall that drains from the surface area of land. It will be tricky to choose 4 which is likely a smaller waterbody draining to a bigger waterbody

hope it helped

Answer:

0.0552 m/s²

Explanation:

Given:

Δx = 69.0 m

v₀ = 0 m/s

t = 50 s

Find: a

Δx = v₀ t + ½ at²

69.0 m = (0 m/s) (50 s) + ½ a (50 s)²

a = 0.0552 m/s²

The value of  force b if the magnitude the force is 26N is determined as 24 N.

The value of force is calculated by applying the formula for determining the magnitude of a force as shown below;

The magnitude of a force is calculated as;

F = √ x² + y²

where;

The given magnitude of the force = 26 N

The x component of the force = 10

The y component of the force = b

26 = √ ( 10²  + b² )

26² = 10² + b²

676 = 100 + b²

b² = 676 - 100

b² = 576

b = √ 576

b = 24 N

Learn more about force component here: https://brainly.com/question/30491683

#SPJ1

Answer:

34.24 %

Explanation:

Since I₀ is the intensity of the un-polarized light, the intensity I₁ of the light polarized by the 1st sheet is (by the one-half rule) I₁ = I₀/2.

The intensity of polarized light I from a polarized source I' is I = I'cos²Ф where Ф is the angle between the direction of I' and I. Since the second sheet has its transmission axis at 25° with respect °o the 1st sheet, the intensity of light I₂ from the second sheet is I₂ = I₁cos²25°.

Also, the 3rd sheet has its transmission axis 47° with respect to the 1st sheet. So, the angle between the transmission axis of the 2nd sheet and 3rd sheet is 47° - 25° = 22°. So, the intensity I₃ from the 3rd sheet is I₃ = I₂cos²22°

Finally, the 4th sheet has its transmission axis 10° with respect to the 3rd sheet. So, the intensity I₄ from the 4th sheet is I₄ = I₃cos²10°.

So,  I₄ = I₃cos²10°

I₄ = I₂cos²22°cos²10°

I₄ = I₁cos²25°cos²22°cos²10°

I₄ = (I₀/2)cos²25°cos²22°cos²10°

I₄/I₀ = cos²25°cos²22°cos²10°/2

I₄/I₀ = (cos25°cos22°cos10°)²/2

I₄/I₀ = (0.9063 × 0.9272 × 0.9848)²/2

I₄/I₀ = 0.8275²/2

I₄/I₀ = 0.6848/2

I₄/I₀ = 0.3424

So, as a percentage,

I₄/I₀ × 100% = 0.3424 × 100% = 34.24 %

If a particle travels in a straight line while accelerating continuously. Starting at rest, the particle begins to move. The particle accelerates to a speed of 200 m/s² and travels 800 meters in 2 seconds.

We can apply the formula: Initial velocity + acceleration over time equals velocity.

Here, initial velocity is equal to 10 m/s, final velocity is equal to 80 m/s, acceleration is equal to 15 m/s2, and we must determine the time.

Thus, 80 = 10 + 15 x time.

By solving for time, we obtain:

time = (80 - 10)/15, or 4 seconds.

We can apply the formula: (Final velocity - Initial velocity) / Time = acceleration

Here, the initial speed is 40 m/s, the final speed is 4 m/s, and the time is 4 s.

Acceleration is therefore (4 - 40) / 4 = -9.0 m/s2. Remember that the roller coaster is decelerating, hence the acceleration is negative.

Time can be calculated using the formula: distance x speed.

Speed in this case is 110 km/h, and distance is 715 km.

Time therefore = 715 / (110/3600) = 28.7 hours.

To learn more about acceleration visit:

brainly.com/question/21652405

#SPJ9

Answer:

AYE

Explanation:

Answer:

sinco

Explanation:

The decision of the country's highest court may then be appealing to that Supreme Court of both the U. S., but only in cases where the issue involves federal law.

In particular, followers of hip-hop, surfing, and post - punk culture will find their clothing appealing. Every person who appreciates streetwear will discover the ideal item thanks to Supreme's wide range of clothing.

Rebellious and distinctive brand image! Despite giving a venture - capital group a 50% ownership in the company, Supreme has been able to keep its skater roots and fan base. To top it all off, the Supremes' emblem is distinctive, outstanding, and simple to recognize.

To know more about Supreme visit:

https://brainly.com/question/17436247

#SPJ1

The sequence that correctly lists earthquake waves from strongest to weakest is : ( C ) P waves -- S waves-- Surface waves

P waves are the strongest waves because they move more rapidly inside the incompressible earth core sending its energy at a hazardous rate, while the S waves are slower and produces vertical movement of the earth surface.

The weakest waves are the S waves which sweeps across the outer surface of the earth and they are also the slowest of all the waves.

Hence we can conclude that the sequence that correctly lists earthquake waves from strongest to weakest is P waves -- S waves-- Surface waves

Learn more about earth quake : https://brainly.com/question/248561