When a planet temporarily moves westward in the sky over the course of several weeks or months (instead of eastward, as it typically does), we call it retrograde motion.
In astronomy, retrograde motion refers to a body's actual or apparent motion in the opposite direction from the majority of solar system objects or other astronomical systems having a favored direction of motion.
Planets usually appear to migrate eastward when compared to the fixed stars.
However, on occasion, they appear to briefly stall in their eastward travel and then migrate westward (backward) in front of the stars for a few months.
They then pause once again. They resume their eastward movement after that.
This motion is known as retrograde motion and sometimes it is just an illusion.
Hence, when a planet temporarily moves westward in the sky over the course of several weeks or months (instead of eastward, as it typically does), we call it retrograde motion.
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A box slides down a frictionless ramp, with no initial velocity. If the height of the ramp is 83 meters high, how fast will the box be traveling at the bottom?
How do i solve this?
At the base of the ramp, the box will be moving at a speed of roughly 40.5 m/s.
How do you calculate the rate of acceleration down a smooth ramp?Acceleration on a ramp is equal to the product of gravitational acceleration and the height to length ratio of the ramp. Acceleration on a ramp is equal to gravity acceleration times the sine of the ramp angle.
Due to its height above the ground at the top of the ramp, the box contains potential energy, as determined by:
PE = mgh
where m is the box's mass, g is gravity's acceleration (9.81 m/s2), and h is the ramp's height (83 meters).
This potential energy is changed into kinetic energy when the box descends the ramp by:
KE = (1/2)mv²
where v denotes the box's speed at the base of the ramp.
Energy is conserved, hence we may compare these two statements:
PE = KE
mgh = (1/2)mv²
Solving for v, we get:
v = √(2gh)
Plugging in the given values, we get:
v = √(29.8183) = 40.5 m/s (rounded to two decimal places)
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Visualiza el lanzamiento de un rollo que continene un anuncio de propaganda que cubrirá el lado sur de un edificio. El rollo fue lanzado con una velocidad horizontal de 30.0 m/s, y cayó a una distancia horizontal de 10.0 m de la base del edificio. ¿Cuán alto es el edificio?
Answer:
El edificio tiene una altura de aproximadamente 0.548 m
Explanation:
Podemos utilizar las ecuaciones del movimiento en dos dimensiones para resolver este problema. En primer lugar, podemos descomponer la velocidad inicial en sus componentes horizontal y vertical. Dado que la velocidad inicial es únicamente horizontal, la componente horizontal de la velocidad es de 30.0 m/s, mientras que la componente vertical es cero.
A continuación, podemos utilizar la ecuación de la posición vertical para determinar la altura del edificio. Esta ecuación es:
y = y0 + v0y t + (1/2) a_y t^2
donde y es la posición vertical final, y0 es la posición vertical inicial (en este caso, la altura del lanzamiento), v0y es la componente vertical de la velocidad inicial (en este caso, cero), a_y es la aceleración vertical (en este caso, la aceleración debido a la gravedad, que es de -9.8 m/s^2), y t es el tiempo de vuelo.
La distancia horizontal recorrida durante el vuelo es de 10.0 m, y la componente horizontal de la velocidad es de 30.0 m/s, por lo que podemos calcular el tiempo de vuelo como:
t = d / v0x = 10.0 m / 30.0 m/s = 0.333 s
Sustituyendo este valor en la ecuación de la posición vertical, y teniendo en cuenta que la velocidad vertical final también es cero (ya que el rollo vuelve al nivel del suelo), podemos despejar la altura del edificio:
y = y0 + (1/2) a_y t^2
y = 0 + (1/2) (-9.8 m/s^2) (0.333 s)^2
y = 0.548 m
Por lo tanto, el edificio tiene una altura de aproximadamente 0.548 m.
How does the average pressure f an elephant standing on the ground compared to that exerted by a person standing on the ground? The person weighs 640N. each shoe has an area of about 0.016 m^2 in contact with the floor. The elephant weighs 4.13x10^4N and has four feet, each with an area of about 0.14 m^2 in contact with the ground.
(a) The average pressure exerted by the person is 40,000 N/m².
(b) The average pressure exerted by the elephant is 295,000 N/m².
The average pressure exerted by the elephant is about 7 times greater than the average pressure exerted by the person.
What is average pressure exerted by the elephant and person?The average pressure exerted by each is defined as the force per unit area.
Mathematically, the formula for average pressure is given as;
P = F/A
where;
F is the applied forceA is the area of each objectP = W / A
where;
W is weight of the personA is the area of surface in contactThe average pressure exerted by the person is calculated as follows;
P = (640 N) / (0.016)
P = 40,000 N/m²
The average pressure exerted by the elephant is calculated as follows;
P = (4.13 x 10⁴ N) / (0.14)
P = 295,000 N/m²
Thus, the average pressure exerted by the elephant and the person depends on their weight and area of their shoes.
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Photophores help the animals which zone of the ocean? how do they help?.
what is the angular displacement formula?
Angular displacement is defined as “the angle in radians (degrees, revolutions) through which a point or line has been rotated in a specified sense about a specified axis”.
Formula:
S = rθ
∴ S = arc length
r = distance
θ = angular displacement
when a muscle is stretched by a contraction of the opposing muscles what is is called?
Answer:
Active stretching.
Explanation:
Think about it.
20 points please help and explain thank you so much!!!A car traveling north at a velocity of 15m/s needs to pass a slower moving vehicle. The driver of the car speeds up to 20 meters per second to get around the slower vehicle. The passing time is 5.8 seconds. What is the car's acceleration?
The acceleration of the car when get around the slower vehicle is 0.86m/s².
The initial velocity U of the car is 15m/s.
The final velocity V of the car is 20m/s.
The time taken by the car to overtake the slow vehicle is 5.8 seconds.
To find the acceleration of the car, we can use the equation of motion,
The equation is,
V = U + at
Where,
V is final velocity of object,
U is the initial velocity if the object,
a is the acceleration of the body,
t is the time taken by the body to accelerate,
Putting all the values of find the acceleration a of the car,
V = U + at
20 = 15 + a5.8
5 = a5.8
a = 5/5.8
a = 0.86 m/s².
So, the acceleration of the car is 0.86 m/s
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We think that a star like the Sun lives for about 10 billion years. Using the relationships in your textbook (Chapter 5, "Twinkle, twinkle, little star" and "Stellar ages"), what is the relative luminosity and lifespan of a star that is 10 times more massive? Of a star that is 1/3 as
massive?
Based on the relationship between a star's mass and its luminosity, as described in Chapter 5 of your textbook, we can determine the relative luminosity and lifespan of stars with different masses compared to the Sun.
For a star that is 10 times more massive than the Sun:
According to the mass-luminosity relationship, more massive stars have higher luminosities. Since the star is 10 times more massive than the Sun, we can assume it will have a greater luminosity. However, without specific data on the exact relationship between mass and luminosity, we cannot determine the precise relative luminosity value. As for its lifespan, more massive stars tend to have shorter lifespans than lower-mass stars. Therefore, we can expect the star that is 10 times more massive than the Sun to have a shorter lifespan compared to the Sun's 10 billion years.
For a star that is 1/3 as massive as the Sun:
Similarly, using the mass-luminosity relationship, less massive stars have lower luminosities. If the star is 1/3 as massive as the Sun, we can expect it to have a lower luminosity compared to the Sun. Again, without specific data, we cannot determine the exact relative luminosity value. Regarding its lifespan, less massive stars typically have longer lifespans. Therefore, we can expect the star that is 1/3 as massive as the Sun to have a longer lifespan compared to the Sun's 10 billion years.
In summary, a star that is 10 times more massive than the Sun would likely have a greater luminosity and a shorter lifespan, while a star that is 1/3 as massive as the Sun would likely have a lower luminosity and a longer lifespan.
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Find the work done in lifting the bucket
A 7 lb bucket attached to a rope is lifted from the ground into the air by pulling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work is done lifting the bucket and rope?
Assuming the force required to lift the rope is equal to its weight, find the force function, F(x), that acts on the rope when the bucket is at a height of x ft.
F(x)=
The total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).
To find the work done in lifting the bucket and rope, we need to consider two parts:
Part 1: Work done lifting the bucket (without the rope) 24 ft:
The work done in lifting the bucket can be calculated by multiplying the weight of the bucket by the distance it is lifted.
Given:
Weight of the bucket = 7 lb
Distance lifted = 24 ft
Work done lifting the bucket = Weight of the bucket x Distance lifted
Work done lifting the bucket = 7 lb x 24 ft
Please note that the units need to be consistent for the calculation. In this case, we have pounds (lb) and feet (ft).
Part 2: Work done lifting the rope:
Assuming the force required to lift the rope is equal to its weight, we can calculate the work done lifting the rope by multiplying the weight of the rope by the distance it is lifted.
Given:
Weight of the rope = 0.8 lb
Distance lifted = 24 ft
Work done lifting the rope = Weight of the rope x Distance lifted
Work done lifting the rope = 0.8 lb x 24 ft
Now, we can calculate the total work done in lifting the bucket and rope by summing up the work done in both parts:
Total work done = Work done lifting the bucket + Work done lifting the rope
Please note that the units of work are in foot-pounds (ft-lb).
Now, we can calculate the values:
Work done lifting the bucket = 7 lb x 24 ft = 168 ft-lb
Work done lifting the rope = 0.8 lb x 24 ft = 19.2 ft-lb
Total work done = 168 ft-lb + 19.2 ft-lb = 187.2 ft-lb
Therefore, the total work done in lifting the bucket and rope is 187.2 foot-pounds (ft-lb).
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The complete question is:
Find the work done In lifting the bucket A 7 Ib bucket attached to a rope is lifted from the ground Into the air by puling in 24 ft of rope at a constant speed. If the rope weighs 0.8, how much work done lifting the bucket and rope? Part1 -1 Find the work done lifting the bucket (without the rope) 24 ft . ft-Ib Part-2. Assuming the force required to lift the rope is equal to its weight; find the force function, F(x), that acts on the rope when the bucket is at height of x Ft. Part- 3 Setup the Integral that will give the work required to lift the rope 24 ft. Part -4 The total amount of work done lifting the bucket and ft-Ib.
if heat is transferred from gas which could happen
The relative densities of gold, silver, copper and zinc are given as 19.3, 10.5, 8.9 and 7.1 respectively. A piccc of ornamental metal weighs 0.445 kg and dis- places 5 x 103 m³ when completely immersed in water. The metal is A. zinc B. copper C. silver D. gold
The density of the ornamental metal is closest to the density of copper. The answer is (B) copper
What is the metal?
The density of a substance is given by the mass of the substance divided by its volume:
density = mass / volume
We can use this formula to determine the density of the ornamental metal:
density = mass / volume = 0.445 kg / 5 x 10^3 m^3 = 8.9 x 10^-5 kg/m^3
Next, we can compare this density to the relative densities of gold, silver, copper, and zinc to identify the metal:
Gold: density = 19.3 x 10^3 kg/m^3
Silver: density = 10.5 x 10^3 kg/m^3
Copper: density = 8.9 x 10^3 kg/m^3
Zinc: density = 7.1 x 10^3 kg/m^3
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How come we can see orange? In simple words.
Answer:
When sunlight shines through an orange solution, the violet, blue and green wavelengths are absorbed. The other colors pass through.
What is the average power supplied by a 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s?
Group of answer choices
a. 670 W
b. 560 W
c. 610 W
d. 380 W
A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).
What is power?Power is the work done over a period of time.
A secretary with a mass (m) of 60.0 kg runs up a 4.0 m (d) tall flight of stairs. Given gravity (g) is 9.81 m/s², the work (W) done is:
W = m × g × d = 60.0 kg × 9.81 m/s² × 4.0 m = 2.35 × 10³ J
They do 2.4 × 10³ J of work in 4.2 s (t). The average power (P) is:
P = W / t = 2.35 × 10³ J / 4.2 s = 560 W
A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).
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What is the velocity of a wave with a length of 10 m and frequency of 5hz.
The velocity of the wave is defined by the product of wavelength and frequency. The velocity of a wave with a length of 10 m and frequency of 5hz will be 50 m/sec.
What is the velocity of the wave?The velocity of the wave is defined by the product of wavelength and frequency. It is obtained from the formula of the wavelength which is given by;
\(\rm \lambda=\frac{v}{f} \\\\ \rm v = \lambda \times f \\\\ \rm v = 10 \times 5 \\\\ \rm v = 50\ m/sec\)
Hence the velocity of a wave with a length of 10 m and frequency of 5hz will be 50 m/sec.
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1) Complète les phrases suivantes en remplaçant
chaque numéro par le mot convenable:
• Pour l'oeil 1, l'image est formée en avant de la
rétine, car l'oeil est trop long.
• Pour l'oeil 2, l'image est formée derrière la
rétine, car l'oeil est plus court.
2) Trouve la place de la lentille convergente, ainsi
que les 2 foyers principaux (F) et (F').
Answer:
si?
Explanation:
definition La myopie. L'oeil myope est trop long ou le cristallin trop convergent. L'image d'un objet à l'infini se forme en avant de la rétine. Le punctum remotum est ... i dont know sorry
Vector L is 303 m long in a
205º direction. Vector M is
555 m long in a 105° direction.
Find the magnitude of their
vector sum
Answer:
584.32m
Explanation:
Firstly, we need to find the x and y components of each vector.
x-component for vector L=303cos205°=-274.61
y-component for vector L=303sin205°=-128.05
x-component for vector M=555cos105°=-143.64
y-component for vector M=555sin105°=536.09
Since it's the vector sum, we add the x and y components of each vector.
Resultant vector x-component -274.61+(-143.64)=-418.25
Resultant vector y-component -128.05+536.09=408.04
Now, to find the magnitude, we use the formula \(\sqrt{x^{2}+y^{2}}\)
sqrt(-418.25^2+408.04^2)=584.32m
Check my work for errors just in case.
The same amount of steel used to create eight solid steel balls, each with a radius of 1 inch, is used to create one larger steel ball. What is the radius of the larger ball
Answer:
2 inches
Explanation:
Volume of a sphere = 4/3 pi r^3
for the EIGHT balls total volume = 8 * 4/3 pi (1^3) = 32/3 pi
This is the volume of the made-up ONE ball
4/3 pi r^3 = 32/3 pi
4/3 r^3 = 32/3
r^3 = 32/3 * 3/4
r^3 = 8
r = 2 inches
A force can make an object change direction, SLOW DOWN or SPEED UP Copy the sentence, changing the words in italic to the correct scientific terms
Answer:
friction force is the force that slow down motions
Ross is very proud of his loud speakers in his car. As he drives along, pedestrians often stare due to their hearing his loud, low-pitched booming. How would we characterize the sounds emitting from Ross' car? High frequency, low amplitude Low frequency, low amplitude Low frequency, high amplitute. High frequency, high amplitude I 26 1 point In response to hearing the noise from Ross' car described in the previous question, we would expect a pedestrian to experience maximum displacement of the basilar membrane at its apex. True False 27 Tpoint Maura holds her head still while looking straight ahead while trying to locate the origin of a sound. Which of the following differences in sound localization will be the most difficult for her to detect? Sounds coming from directly in front of her (12 o'clock) from sounds coming directly behind her (6 o'clock) All directions of sound will be impossible to distinguish without moving the head. Sounds coming from her right side (3 o'clock) from sounds coming from her left side (9 o'clock) All directions of sound will be easy to distinguish without moving the head. 28 1 point The human sensory homunculus devotes considerable space to the larger parts of the body, such as the torso and legs. True False
The sounds emitting from Ross' car can be characterized as low frequency, high amplitude.
The question states that pedestrians often stare at Ross' car due to the loud, low-pitched booming sound they hear. From this description, we can infer certain characteristics of the sound.
Low frequency refers to sounds with a lower pitch, such as deep bass notes. These low-pitched sounds are associated with lower frequencies on the sound spectrum.
High amplitude refers to the intensity or loudness of the sound. When a sound is described as loud, it indicates a high amplitude or a greater magnitude of sound waves.
Therefore, the sounds emitting from Ross' car can be characterized as low frequency (low-pitched) and high amplitude (loud). This combination of characteristics results in the loud, low-pitched booming sound that draws the attention of pedestrians.
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If the lead can be extracted with 92.5fficiency, what mass of ore is required to make a lead sphere with a 7.00 cm radius? the density of lead is 11.4 g/c
If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
To find the mass of ore, the given values are,
The radius of the lead sphere is r = 7.0 cm,
The lead can be extracted with, η = 92.5% = 0.925 efficiency.
What is the Density?Density is the substance's mass per unit of volume.
We know the density of lead as,
⇒ p = 11.4 g/cm³ .
The volume of the lead sphere is,
V = 4/3πr³
= 4/3π(7)³
V = 1436.7 cm³.
Mass of the lead present in the lead sphere is,
m = p . V
= 11.4 × 1436.7
= 16379 g
m = 16.379 kg
From the expression of efficiency, we calculate the mass of the ore,
η = Mass of lead obtained / Mass of the ore to be taken
0.925 = 16.379 kg / Mass of the ore to be taken
Mass of the ore to be taken = 17.707 kg
If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
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Here is the Energy and Forces Unit Test answers for Connexus students as of 2/15/2023. Someone gave lots of wrong answers for this on another persons question, so here are the right answers.
1-at least two charged, interacting parts
2-from the electric fields of charged subatomic particles
3-an arrow released from the bow
4-Electrical fields of charged particles interact, bonding those with opposite charges.
5-the interaction of the electric fields of protons and electrons
6-The energy stored in the system increases.
7-Kinetic energy increases because the magnets move in the direction of the field.
8-Iron pieces accelerate toward the magnet, and the energy stored in the system decreases.
9-The energy stored in the field decreases because the magnet moves in the direction of the field.
10-The energy stored increases and then decreases.
11-The wire was not connected to the source.
12-The electromagnet will become more powerful.
`````EXTENDED RESPONSE QUESTIONS`````
(These answers have not been graded. If you choose to use the answers, so not hold it against me if they are wrong. This is just what i put)
13-A particle accelerator is used to move charged particles to a high speed and increase their energy. The accelerator uses the energy provided by an electromagnetic field.
14-When you pull the magnet off the fridge, the potential energy increases because the farther the two charged objects move apart, the more charge they get.
15-One thing is the number of coils. The more coils, and the tighter they are, the stronger the charge. The wire size can also affect it. The shape and size of the core, and the nature of the core are also factors.
there is no actual energy. And it still has a ways to go before it touches the earth, it contains both potential energy and kinetic energy since it is traveling. The brakes of a car heat up as it comes to
What does physics mean by potential energy?
Potential energy in physics is the energy that an item possesses as a result of its position in relation to other objects, internal tensions, electromotive force, or other elements.
What is the potential associated with it?
The gravitational potential, frequently represented by, which corresponds to the unit mass of energy as a function of position, is the associated potential. When two particles of mass M and m are separated by r, their gravitational potential energy is
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Answer:
Thank You So Much!❣️
\(\qquad \qquad\huge \underline{\boxed{\sf Answer}}\)
What's Space X ?
\(\bold{Heya~!}\)
What's Space X ?Space X is that designs, and also. that manufactures and launches the world's most advanced rocket ships, and spacecraft. And the company was that founded in 2002, by "Elon Musk."
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\(\underline{\boxed{\huge{Answer~:}}}}}\)
\(\mathfrak{Dollixna}\)
A physics student is driving his pick-up
truck down Lake Avenue. The pick-up is
equipped with a projectile launcher that
imparts a vertical velocity to a water-filled
rubber projectile. While traveling 20.0 m/s
in an eastward direction, the projectile is
launched vertically with a velocity of 58.8
m/s.
Fill in the table at the right. showing the
horizontal and vertical displacement of the
projectile every second for the first 12
seconds.
TOTAL FLIGHT TIME
Rising Projectile
vi = initial velocity = 58.8 m/s
vf = final velocity = 0
g = gravity acceleration = -9.81 m/s²
t = elapsed time = to be determined
vf = vi + gt
vf - vi = gt
(vf - vi)/g = t
t = (vf - vi)/g
t = (0 - 58.8)/-9.81
t = -58.0/-9.81
t = 5.99 s ≈ 6.00 s
Falling Projectile
vi = initial velocity = 0
vf = final velocity = 58.8 m/s
g = gravity acceleration = 9.81 m/s²
t = elapsed time = to be determined
vf = vi + gt
vf - vi = gt
(vf - vi)/g = t
t = (vf - vi)/g
t = (58.8 - 0)/9.81
t = 58.0/9.81
t = 5.99 s ≈ 6.00 s
t(total) = t(up) + t(down) = 6.00 s + 6.00 s = 12.0 s Total Flight Time
HORIZONTAL DISTANCE TRAVELED
v = velocity, horizontal = 20.0 m/s
d = to be determined
t = elapsed time = 12.0 s
v = d/t
vt = d
d = vt
d = (20.0 m/s)(12.0 s)
d = 240 m Horizontal Distance Traveled
00
The ratio of the potential difference across a conductor to the current in the conductor is called
A) conductivity
B) resistance
C) charge
D) power
Answer:
The ratio of the potential difference across a metallic conductor to the current in the conductor is known as.
B. Resistance.
Explanation:
According to ohms law " the current passing through a conductor is directly proportional to the potential difference between the ends provided the temperature of the wire remains constant".
What is resistance ?
Resistance is a measure of the opposition to current flow in an electrical circuit
what is a resistor ?
a resistor is a n electric conductor which forms resistance to free flow of electric current, the resistance is measured in Ω
The ratio of the potential difference across the conductor to the current is called resistance
What is Resistance?It is defined as the ratio of the potential difference across the conductor to the current. The resistance is measured in Ω.
\(R = \dfrac VI\)
Where,
\(R\) - resistance
\(V\)- voltage (Potential difference)
\(I\) - current
Therefore, the ratio of the potential difference across the conductor to the current is called resistance.
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A motor scooter undergoes acceleration when it O decreases speed. O changes direction. O gains speed.O all of the above
Gains speed because Acceleration is defined as the rate of change of velocity, which can be positive (speed increase) or negative (speed decrease). In the case of a motor scooter, when it gains speed.
What is acceleration explain?Measuring the rate at which a moving entity's speed and direction change over time. When a point or thing accelerates / decelerates, it is moving straight forward. Motion on a circle increases even if the speed is constant because the vector is always changing.
What is the acceleration equation?A = v/t stands for acceleration, which is the product of the alteration in speed (v) and the shift in time (t) (t). You may use this to figure out the variation in velocity in m/s² (metres per second squared).
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80 N and 60 N force act concurrently on a point. find magnitude of the vector sum if the forces pull
-in the same direction
-in opposite direct.
-at right angles to each other
Answer:
140N20N100NExplanation:
In the same direction (add them)80 + 60 = 140N
In the opposite direction (subtract them)80 - 60 = 20N
At right angles to each other (pythagoren theorem)80^2 + 60^2 = c^2
6400 + 3600 = c^2
10000 = c^2
100 = c
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What force must act on a 50.0-kg mass to give it an ancceleration of 0.30 m/s^2?
Pls show your solution
Answer:
15.0 N
Explanation:
see pic
All of the following are types of models EXCEPT
O a theory.
Dan analogy.
Oa physical replica.
O a mathematical representation.
Answer:
A theory
Explanation:
No, the person who answered above is incorrect. I just took the assessment and I can guarantee you the answer is "a theory".
-Lexi
how do scientist check repeatability of results
Answer:
If research results can be replicated, it means they are more likely to be correct.
Answer: There are many things that have to be checked in order to know
Explanation:
For repeatability to be established, the following conditions must be in place: the same location; the same measurement procedure; the same observer; the same measuring instrument, used under the same conditions; and repetition over a short period of time.
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A playground 82 ft long and 54 ft wide is to be resurfaced at a cost of $2.75 per sq ft. What will the resurfacing cost?Round to nearest integer or decimal
ANSWER:
$ 12177
STEP-BY-STEP EXPLANATION:
We must calculate the area of the playground, knowing that the area is equal to length times width, like this:
\(\begin{gathered} A=82\cdot54 \\ A=4428ft^2 \end{gathered}\)Now, knowing the area, we can calculate the total cost, like this:
\(\begin{gathered} C=2.75\cdot4428 \\ C=12177 \end{gathered}\)The resurfacing cost is $ 12177