Answer:
C
Explanation:
People hoping to travel to other worlds are faced with huge challenges. One of the biggest is the time required for a journey. The nearest star is 4.1×1016m 4.1 × 10 16 m away. Suppose you had a spacecraft that could accelerate at 1.5 g g for two thirds of a year, then continue at a constant speed. (This is far beyond what can be achieved with any known technology.)How long would it take you to reach the nearest star to earth?
Answer:
It would take 8.22037 hrs away. Wouldn't it?
Explanation:
Because
4.11016
4.11016
15
= 8.22037
is this right, please answer
The eyes, spinal cord, and brain are all main or key parts of the nervous system.
If 750-nm and 610-nm light passes through two slits 0.50 mm apart, how far apart are the second-order fringes for these two wavelengths on a screen 1.0 m away
The second-order fringes for the 750-nm and 610-nm wavelength are approximately 0.56 mm apart on a screen 1.0 m away.
To find the distance between the second-order fringes for the 750-nm and 610-nm wavelength, we'll use the double-slit interference formula:
\(y = (m * λ * L) / d\)
where:
- y is the fringe distance on the screen
- m is the order of the fringe (in this case, m = 2 for second-order)
- λ is the wavelength of light
- L is the distance from the slits to the screen (1.0 m)
- d is the distance between the slits (0.50 mm or 0.0005 m)
First, find the fringe distance for the 750-nm wavelength:
\(y1 = (2 * 750 * 10^-9 * 1) / 0.0005\)
y1 ≈ 0.003 m
Next, find the fringe distance for the 610-nm wavelength:
\(y2 = (2 * 610 * 10^-9 * 1) / 0.0005\)
y2 ≈ 0.00244 m
Finally, find the distance between the second-order fringes for these two wavelengths:
Δy = y1 - y2
Δy = 0.003 - 0.00244
Δy ≈ 0.00056 m or 0.56 mm
So, the second-order fringes for the 750-nm and 610-nm wavelengths are approximately 0.56 mm apart on a screen 1.0 m away.
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Anyone have the electromagnetic induction lab? help fast pls
Electromagnetic induction is the process of generating an electric current by moving a conductor through a magnetic field. When a conductor moves through a magnetic field, a voltage is induced in the conductor. This is known as Faraday's Law of Electromagnetic Induction.
This voltage can be used to create an electric current in the conductor.To perform an electromagnetic induction lab, you will need materials such as a magnet, a coil of wire, a battery, and a galvanometer. The following are the steps to perform the experiment:
Step 1: Connect the galvanometer to the coil of wire.Step 2: Attach the magnet to the battery.Step 3: Move the magnet back and forth across the coil of wire.Step 4: Observe the reading on the galvanometer.
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A)This part controls the amount of light entering the eyes. A= Iris B= Pupil Give reason for your answer.
Answer:
Iris
Explanation:
Iris can be described as a part of the eyes which regulates the amount of light that enters the eye. The iris is made up of various muscles that control the size of the pupil
When a person is in a well-lighted room, the iris decreases the size of the pupil so that a low amount or medium amount of light is absorbed into the pupil. Also when an individual steps into a dark room the iris increases the size of the pupil so that a high amount of light penetrates the pupil.
Hence without the iris the amount of light that enters the eye cannot be controlled.
A glass window pane is 2.7 m high, 2.4 m wide, and 9.0 mm thick. The temperature at the inner surface of the glass is and at the outer surface 4°C. How much heat is lost each hour through the window?
The window loses approximately 38,080 W, or 38.08 kW, of heat each hour.
The rate of heat loss through a window can be calculated using the formula:
Q/t = kA(∆T/d)
where Q/t is the rate of heat transfer, k is the thermal conductivity of glass, A is the area of the window, ∆T is the temperature difference between the inner and outer surfaces of the glass, and d is the thickness of the glass.
Given that the glass is 9.0 mm thick, or 0.009 m, the area of the window is 2.7 m x 2.4 m =\(6.48 m^2\), the temperature difference is 4°C, and the thermal conductivity of glass is approximately 1.05 W/mK, we can solve for Q/t:
Q/t = \((1.05 W/mK)(6.48 m^2)(4°C)/(0.009 m)\)
Q/t = 38,080 W
Therefore, the window loses approximately 38,080 W, or 38.08 kW, of heat each hour.
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A ____ exerted by an object on another is a force
Answer:
A gravitational force exerted by an object on another is a force.
Explanation:
hope it helps
A ball of mass 2kg is thrown up with a speed of 10m/s. find the kinetic energy of the ball at the time of throwing. Also find the potential energy of the ball at the highest point?
The potential energy of the ball at the highest point is 100.98J
The kinetic energy of the ball at the time of throwing can be calculated using the formula KE = 1/2mv^2, where m is the mass of the ball and v is its velocity. In this case, the mass of the ball is 2kg and the velocity at the time of throwing is 10m/s. Substituting these values into the formula gives:
KE = 1/2 x 2kg x (10m/s)^2
KE = 100J
Therefore, the kinetic energy of the ball at the time of throwing is 100J.
At the highest point of the ball's trajectory, it reaches a point of zero velocity. At this point, all of the kinetic energy of the ball has been converted into potential energy due to its position in the Earth's gravitational field. The potential energy of an object at a height h above the ground can be calculated using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2 near the surface of the Earth), and h is the height of the object above the ground.
At the highest point, the velocity of the ball is zero and its height is at its maximum. Assuming the initial height of the ball was 0, the height of the ball at the highest point can be calculated using the formula h = v^2/2g, where v is the initial velocity of the ball. In this case, the initial velocity is 10m/s, so the height of the ball at the highest point is:
h = (10m/s)^2/2 x 9.8m/s^2
h = 5.1m
Substituting the mass of the ball and the height into the potential energy formula gives:
PE = 2kg x 9.8m/s^2 x 5.1m
PE = 100.98J
Therefore, the potential energy of the ball at the highest point is approximately 101J.
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Oil having a density of 924 kg/m³ floats on
water. A rectangular block of wood 3.18 cm
high and with a density of 965 kg/m³ floats
partly in the oil and partly in the water. The
oil completely covers the block.
How far below the interface between the
two liquids is the bottom of the block?
Answer in units of m.
Explanation:
The bottom of the block is 0.1365 meters (or 13.65 centimeters) below the interface between the two liquids.
What scientific law did Archimedes establish? the law of geometry the law of astronomy the law of lever and balance the law of Earth and universe
Answer:
Archimedes discovered the buoyancy laws
Explanation:
when asked by King Hiero of Syracuse to determine whether his new crown was pure gold (SG = 19.3). Archimedes measured the weight of the crown in air to be 11.8 N and its weight in water to be 10.9 N.
Answer:
The correct answer is C
Explanation:
1. How much heat must be absorbed by 375 grams of water to raise its
temperature by 25° C?(Cp of water is 4.184)
Answer:
39225J
Explanation:
Given parameters:
Mass of water = 375grams of water
Change in temperature = 25°C
Specific heat capacity of water = 4.184J/g°C
Unknown:
Amount of heat absorbed = ?
Solution:
To solve this problem, we use the expression below:
H = m c Ф
H is the heat absorbed
m is the mass
c is the specific heat capacity
Ф is the change in temperature
Insert the parameters and solve;
H = 375 x 4.184 x (25) = 39225J
If an object starts at rest, what is necessary to make it start moving?
It will need a force acceleration
Which of the following is the best thermal conductor?
A. Gasoline
B. Silver
C. Plastic
D. Helium
Answer:
The answer is B. Silver
Explanation:
I took AP3X quiz.
A ‘can-chiller’ is used to make a can of drink colder. The initial temperature of the liquid in the can was 25.0 °C. The can-chiller decreased the temperature of the liquid to 20.0 °C. The amount of energy transferred from the liquid was 6930 J. The mass of liquid in the can was 0.330 kg.
Calculate the specific heat capacity of the liquid. Give the unit.
Please help :)
Answer:
4200 J/°C/kg
Explanation:
The formula for heat transfer is given by :
Q= m*c*ΔT where;
Q= heat transferred = 6930 J
m=mass of the liquid = 0.330 kg
c= specific heat capacity=?
ΔT = 25-20 = 5.0°C
Applying the values in the formula as;
Q= m*c*ΔT
6930 = 0.330 * c * 5
6930 = 1.65 c
6930/1.65 = c
4200 = c
c= 4200 J/°C/kg
If you have a resistor with a brown band, a black band, a brown band and a gold band, what value of resistance does this represent? O a. 1 ohm O b. 10 ohms O c. 100 ohms O d. 1K ohms O e. 10K ohms O f. 100K ohms O g. 1MEG ohms
The resistor with a brown band, black band, brown band, and gold band represents a resistance value of 100 ohms. Therefore, the correct answer is c. 100 ohms.
The color coding on resistors is a standardized system used to represent their resistance values. Each color corresponds to a specific number, and the overall combination of colors determines the resistance value.
In the given resistor with the color bands brown, black, brown, and gold, we can determine the resistance value as follows:
- The brown band represents the first significant digit: 1.
- The black band represents the second significant digit: 0.
- The third band (brown) represents the multiplier : 10¹, or 10.
- The fourth band (gold) represents the tolerance, which indicates the acceptable range of deviation from the nominal value.
In this case, gold represents a tolerance of ±5%.
Combining these values, we have 10 x 1 with a tolerance of ±5%, resulting in a resistance value of 100 ohms.
Therefore, the correct answer is c. 100 ohms.
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The greatest number of thunderstorms occur in the?
mountains
tropics
high latitudes
middle latitudes
Answer:
On the other hand, Florida's Gulf Coast experiences the greatest number of thunderstorms out of any U.S. location. These types of storms occur on average 130 days per year in Florida.
Your friend wants to join the school track team, and has asked for your help to determine how fast she can run. What kind of information would you need to collect to help your friend???
Answer:
you calculate a specific type of run for example 100m and it takes 20 seconds to finish and calculate the time it takes them to finish
hope this helps
have a good day :)
Explanation:
You need th information about the time period she ran and the distance she covered in that time period to analyze her speed.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second.
The generally considered unit for speed is a meter per second.
Your friend wants to join the school track team and has asked for your help to determine how fast she can run the data of her time and the length of the distance she covered in that period of time because the only way to know how fast she runs is to analyze her speed by using the distance and the time.
Thus , you need information about the time period she ran and the distance she covered in that time period to analyze her speed.
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A particle is moving through an electric field. Starting from the origin, it first moves 7.22 cm in the negative y-direction, then it moves 8.05 cm in the positive x-direction. What is the direction of the resultant vector?
41.9 above the negative x-axis
41.9 below the negative x-axis
41.9 above the positive x-axis
41.9 below the positive x-axis
Answer: 41.9 below the negative x-axis.
Explanation: To find the direction of the resultant vector, we need to use some trigonometry and vector addition. Here are the steps:
Draw a diagram of the particle’s motion and label the vectors. The particle starts at the origin and moves 7.22 cm in the negative y-direction, which we can call vector A. Then it moves 8.05 cm in the positive x-direction, which we can call vector B. The resultant vector R is the vector that goes from the origin to the final position of the particle.
Find the components of vector A and vector B. Vector A has a magnitude of 7.22cm and a direction of 270 degrees (or -90 degrees) from the positive x-axis. Vector B has a magnitude of 8.05 cm and a direction of 0 degrees (or 360 degrees) from the positive x-axis. Using trigonometry, we can find the x and y components of each vector as follows:
A_x = A cos(270) = 7.22 cos(270) = 0
A_y = A sin(270) = 7.22 sin(270) = -7.22
B_x = B cos(0) = 8.05 cos(0) = 8.05
B_y = B sin(0) = 8.05 sin(0) = 0
Add the components of vector A and vector B to get the components of vector R. Using vector addition, we can find the x and y components of the resultant vector as follows:
R_x = A_x + B_x = 0 + 8.05 = 8.05
R_y = A_y + B_y = -7.22 + 0 = -7.22
Find the magnitude and direction of vector R using Pythagoras’ theorem and inverse tangent function. The magnitude of vector R is given by the square root of the sum of the squares of its components, and the direction of vector R is given by the inverse tangent of its y component divided by its x component, as follows:
R = sqrt(R_x^2 + R_y^2) = sqrt(8.05^2 + (-7.22)^2) = sqrt(114.81) = 10.71 cm
theta = tan^-1(R_y / R_x) = tan^-1(-7.22 / 8.05) = -41.9 degrees
Adjust the direction of vector R according to its quadrant. Since vector R is in the fourth quadrant, where both x and y are positive, we need to add 360 degrees to its direction to get a positive angle measured counterclockwise from the positive x-axis, as follows:
theta = -41.9 + 360 = 318.1 degrees
Alternatively, we can express the direction of vector R as an angle measured clockwise from the negative x-axis, which is equivalent to subtracting its direction from 360 degrees, as follows:
theta = 360 - (-41.9) = 401.9 degrees
However, since angles are periodic with a period of 360 degrees, we can subtract multiples of 360 degrees from this angle to get an equivalent angle between 0 and 360 degrees, as follows:
theta = 401.9 - 360 = 41.9 degrees
Therefore, the direction of vector R is either 318.1 degrees counterclockwise from the positive x-axis or 41.9 degrees clockwise from the negative x-axis.
Hope this helps, and have a great day! =)
How did people fly before Isaac Newton invented gravity?
Answer:
Isaac Newton did not invent gravity. Gravity is a fundamental force of nature that has always existed. Newton's contribution was to formulate the laws of motion and universal gravitation, which helped to explain the behavior of objects under the influence of gravity.
As for how people flew before the development of powered flight, they relied on a variety of methods, such as gliding, using hot air balloons, and being lifted by the wind in kites. For example, in China, people have been flying kites for more than 2,000 years. In the late 18th century, the Montgolfier brothers developed hot air balloons, which allowed humans to ascend into the air for short periods of time. And in the late 19th and early 20th centuries, pioneers of aviation such as the Wright brothers and their contemporaries developed powered aircraft, which eventually led to modern air travel.
Question 14 (2 points)
Which statement best describes why the universe could be considered an isolated system? (2 points)
Оа
All matter that enters the universe remains contained within the universe.
Ob
Energy and matter are created in the universe; when new energy is created, old energy exits.
In the universe, all energy and matter are contained; no energy or matter enters or exits.
Ос
Od
The universe is a contained system where no energy exits.
Answer:
I believe it is actually C
Explanation:
Matter and energy cannot be created or destroyed so A is incorrect
Since energy cannot be created, B is incorrect
while C and D both sound correct, D does not mention entering while C does so I believe C is correct. When i submit this answer into my quiz, i will add if i am right.
In the universe, all energy and matter are contained; no energy or matter enters or exits - the statement best describes why the universe could be considered an isolated system.
What is isolated system?A thermodynamic system is said to be isolated if it cannot exchange either mass or energy with the outside world. In contrast to a closed system, energy can't move across isolated systems. Energy can move freely within and outside of closed systems; they are only closed to matter.
As both energy and matter can not exit from a universe, we can consider universe as a isolated system.
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A light spring of constant 176 n/m rests vertically on the bottom of a large beaker of water. a 4.63 kg block of wood of density 648 kg/m^3 is connected to the top of the spring and the block-spring system is allowed to come to static equilibrium. what is the elongation ∆l of the spring? the acceleration of gravity is 9.8 m/s^2 answer in units of cm.
We have that in response to the question "A light spring of constant 176 N/m sits vertically on the bottom of a large beaker of water." 8.66 cm is the spring elongation.
How do materials' characteristics impact how they react to stress and strain?The block's weight is determined by:-
W= mg= Vg= Ahg
where m is the block's mass, g is the acceleration brought on by gravity, is the block's density, V is the block's volume, A is its cross-sectional area, and h is its height.
The weight of the block is balanced by the upward force applied by the spring because the block is in static equilibrium:-
F = kΔl
where l is the spring's elongation and k is the spring constant.
When we combine these two forces, we get:
ρAhg = kΔl
When we solve for l, we get:
Δl = ρAhg/k
If we substitute the values provided, we get:
l = (0.176 m2)(9.8 m/s2)(9.8 kg/m3)(176 N/m) 0.0866 m = 8.66 cm
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how many turns of wire would be required to make a 120 mhmh inductance out of a 33.0 cmcm -long air-filled coil with a diameter of 4.1 cmcm ? express your answer using two significant figures.
No. of turns of wire would be required to make a 120 mh inductance out of a 33.0 cm -long air-filled coil with a diameter of 4.1 cm is μ*2740.68 as μ is variable for different types of material.
What is Inductance?An electrical conductor's propensity to resist a change in the flow of current through it is known as inductance. A magnetic field is produced around a conductor by an electric current flowing through it. The magnitude of the current determines the field strength, which follows any changes in current.
The formula of Inductance is L = μN2A/l where L = Inductance (H), μ = Permeability (Wb/Am),N = The coil's number of turns, A = The coil's cross sectional area = π*d²/4, l = Length of coil (m)
Now acc. to the given data
L=120mh
I=33.0cm =0.33m
Diameter=4.1cm
A= π*d²/4 = 3.14*4.12/4
A=13.19cm2or 0.001319m2
Now rearranging the formula for no. of turns we get
N=√LI/μA
So, N=√ 120*0.33/μ*0.001319
N=μ*2740.68
Hence, no. of turns of wire would be required to make a 120 mh inductance out of a 33.0 cm -long air-filled coil with a diameter of 4.1 cm is μ*2740.68 as μ is variable for different types of material.
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How to know which is voltmeter and ammeter from a graph ?
Voltmeters measure voltage, whereas ammeters measure current. Some of the meters in automobile dashboards, digital cameras, cell phones, and tuner-amplifiers .
Both of these devices are used in electric circuits but the major difference between a voltmeter and an ammeter is ammeter comes in handy for measuring the flow of current whereas the voltmeter comes in handy for measuring the voltage or emf across two points in an electric circuit.
Answer: ammeter comes in handy for measuring the flow of current whereas the voltmeter comes in handy for measuring the voltage or emf across two points in an electric circuit.
Explanation: Both of these devices are used in electric circuits but thats the major difference
Un bloque de 3 kg en reposo se deja libre a una altura de 5 m sobre una rampa curva y sin rozamiento. Al pie de la rampa se encuentra un resorte de constante k = 400 N/m, como se muestra en la fig. El objeto desliza por la rampa y llega a chocar contra el resorte comprimiéndolo una distancia x antes de que quede en reposo momentáneamente. Determinar: a) La velocidad con la que el bloque alcanza al resorte. ____________________ b) La distancia x que el bloque comprime al resorte. __________________ c) La velocidad con la que el bloque es expulsado por el resorte. ____________________ d) La altura que alcanza sobre la parte curva. ________________ e) ¿Alcanzará la misma altura si la rampa no está libre de rozamiento? ___________________
Answer:
a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s
b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m
c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s
d) La altura que alcanza el bloque es de 5 metros.
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción
Explanation:
a) Los parámetros dados del bloque son;
La masa del bloque, m = 3 kg
La altura a la que se coloca el bloque, h = 5 m
La constante de resorte, k = 400 N / m
La aceleración debida a la gravedad, g = 9,8 m / s²
La energía potencial de un cuerpo, P.E. = m · g · h
Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;
P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios
P.E. = 147 julios
La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²
Dónde;
v = La velocidad del bloque cuando llega al resorte
Por lo tanto, para el bloque dado tenemos;
K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²
Por el principio de conservación de la energía, tenemos;
El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.
∴ P.E. = K.E.
147 J = 1/2 × 3 kg × v²
v² = 147 J / (1/2 × 3 kg) = 98 m² / s²
v = √ (98 m² / s²) = 7 · √2 m / s
v = 7 · √2 m / s ≈ 9,9 m / s
b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²
Dónde;
k = La constante del resorte = 400 N / m
x = La distancia a la que se comprime el resorte
Por el principio de conservación de la energía, tenemos;
La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.
∴ E = 1/2 · k · x² = P.E.
De lo que tenemos;
E = 1/2 × 400 N / m × x² = 147 julios
x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²
x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m
La distancia a la que se comprime el resorte = x ≈ 0.86 m
c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;
La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²
∴ 1/2 · k · x² = 1/2 · m · v²
∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s
La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s
d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;
P.E. = K.E.
∴ m · g · h = 1/2 · m · v²
v = 7 · √2 m / s
De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción
a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
a) Conforme a la situación de este problema, la energía cinética traslacional final (\(K\)), en joules, es igual a la energía potencial gravitacional inicial (\(U\)), en joules.
\(U = K\) (1)
Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:
\(m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}\) (1)
Ahora despejamos la velocidad de esa ecuación:
\(v = \sqrt{2\cdot g\cdot h}\)
Donde:
\(m\) - Masa del bloque, en kilogramos.\(g\) - Aceleración gravitacional, en metros por segundo al cuadrado.\(h\) - Altura inicial del bloque, en metros.\(v\) - Velocidad final del bloque, en metros por segundo.Si sabemos que \(g = 9.807\,\frac{m}{s^{2}}\) y \(h = 5\,m\), entonces la velocidad final del bloque es:
\(v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}\)
\(v\approx 9.903\,\frac{m}{s}\)
La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:
\(\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}\) (2)
Where:
\(k\) - Constante de resorte, en newtons por metro.\(x\) - Deformación del resorte, en metros.Ahora despejamos la deformación del resorte:
\(x = \sqrt{\frac{m}{k} }\cdot v\) (3)
Si sabemos con \(k = 400\,\frac{N}{m}\), \(m = 3\,kg\) y \(v \approx 9.903\,\frac{m}{s}\), entonces la deformación del resorte es:
\(x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)\)
\(x \approx 0.858\,m\)
El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
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Can someone please help me with this
Answer:
0.71 (c)
Explanation:
T=seconds/# of revolutions
f (frequency)=# of revolutions/seconds
We have to find f.
T=1/f
Fc=mv^2/r
Fc=m(2πr/1/f)^2/r
19.74N=1kg*v^2/1m
19.74m^2/s^2=(2πr/1/f)^2
4.44m/s=2πr/T
2.22m/s=π1m/T
2.22s=π/T
0.706s=1/T
0.706s=1/1/f
or 0.706 (0.71)=f
Nuclei decay from a more stable form to a less stable form.Question 9 options:TrueFalse
ANSWER
False.
EXPLANATION
In radioactive decay (or nuclei decay), an unstable nucleus emits radiation into a nucleus that is table and has less energy and a lower mass.
Therefore, nuclei decay from a less stable form to a more stable form.
The answer is false.
A large rock has a mass of 7.84 x 107 grams. What is this mass inItons. 1 ton = 907.2 kilograms.
The mass of the rock is approximately 86.304 tons.
To convert the mass of the rock from grams to tons, we can use the conversion factor that 1 ton is equal to 907.2 kilograms.
Mass of the rock = 7.84 x 10^7 grams
To convert grams to kilograms, we divide by 1000:
Mass in kilograms = (7.84 x 10^7 grams) / 1000 = 7.84 x 10^4 kilograms
Now, to convert kilograms to tons, we divide by 907.2:
Mass in tons = (7.84 x 10^4 kilograms) / 907.2 = 86.304 tons
Therefore, the mass of the rock is approximately 86.304 tons.
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integers are read from input and stored into a vector until -1 is read. output the negative elements in the vector in reverse order. end each number with a newline.
Loop to print negative elements of the vector in reverse.
Run the loop from the size of the vector to 0, check whether each element is negative, or less than zero then print the element.
for (int i = integerVector.size(); i >=0; i--)
{
if(integerVector[i]<0)
cout<<integerVector[i]<<endl;
}
C++ filled in code for the given program to print negative elements of the vector in reverse order :
#include <iostream>
#include<vector> using namespace std;
int main() { int i; vector<int> integerVector;
int value; cin>>value; while(value!=-1) { integerVector.push_back(value);
cin>>value; } for (int i = integerVector.size(); i >=0; i--) { if(integerVector[i]<0)
cout<<integerVector[i]<<endl; } return 0; }
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As it turns out, Saturn is just a bunch of hype and you decide to fly to Mercury for some quality sunbathing. The absorbed solar radiation on Mercury is 3288Wm −2
. Assume the planet is in radiative equilibrium. What is the equilibrium radiating temperature of Mercury? (
The equilibrium radiating temperature of Mercury is 1102 Kelvin if the absorbed solar radiation on Mercury is \(3288 Wm^{-2}\).
Solar radiation = \(3288 Wm^{-2}\)
To calculate the balanced radiating temperature of Mercury, we can use the Stefan-Boltzmann law, which denotes that the solar energy power emitted by a black body is directly proportional to the fourth power of its temperature. The formula is:
P = σ * A * \(T^{4}\)
3288 = σ * A * \(T^{4}\)
\(T^{4}\) = 3288 / (σ * A)
\(T^{4}\) = 3288 / (5.67 x 10^-8)
\(T^{4}\) = 1.155 x 10^13
T = \((1.155 * 10^{13})^{(1/4)}\)
T = 1102 Kelvin
Therefore, we can conclude that the equilibrium radiating temperature of Mercury is 1102 Kelvin.
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is the following statement about our solar system true or false? jupiter's volume is more than ten times as large as saturn's volume.
Jupiter's volume is more than ten times as large as Saturn's volume. This statement is true. Jupiter is the largest planet in our solar system with a volume of about 1,431,281,810,739 km³ while Saturn is the second-largest planet with a volume of about 827,129,915,150 km³.
Jupiter is approximately 11 times larger than Saturn. The two planets belong to the gas giant category, and they share many similarities such as having a large number of moons. Jupiter is famous for its Great Red Spot and powerful magnetic field, while Saturn is well-known for its stunning ring system. Both planets have been the focus of scientific research and exploration, and they continue to fascinate scientists and stargazers alike. In conclusion, Jupiter's volume is more than ten times as large as Saturn's volume.
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