when designing dipole and patch antennas, what is the electrical length that determines their resonant frequency?

The period of oscillation will rise to about 5.2 seconds if the mass is tripled.

T = 2(m/k), where T is the period, m is the block's mass, and k is the spring constant, determines the period of oscillation of a block coupled to a spring.

The period changes to: If the mass is tripled, the new mass is 3m, and

T' = 2π√[(3m)/k]

This formula may be made simpler by subtracting the number 3 from the square root:

T' = 2π√[3(m/k)]

T' = √3 * [2π√(m/k)]

T' = √3 * T

Thus, the new period is almost three times the earlier one. The new period in this instance is 5.2 seconds because the initial period was 3.0 seconds.

The period of oscillation will therefore grow to about 5.2 seconds if the mass is tripled.

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Answer:

-10 m/s²

Explanion:

(0 m/s - 50 m/s) ÷ 5 seconds

You subtract the original speed from the final speed, (to get negative 50), then divide that by 5 seconds.

Hope this helps! :)

Answer:

We adopt the positive direction choices used in the textbook so that equations such as Eq. 4-22 are directly applicable. The coordinate origin is at the release point (the initial position for the ball as it begins projectile motion in the sense of §4-5), and we let θ

0

be the angle of throw (shown in the figure). Since the horizontal component of the velocity of the ball is v

x

=v

0

cos40.0°, the time it takes for the ball to hit the wall is

t=

v

x

Δx

=

(25.0m/s)cos40.0

o

22.0m

=1.15s.

(a) The vertical distance is

Δy=(v

0

sinθ

0

)t−

2

1

gt

2

=(25.0m/s)sin40.0

o

(1.15s)−

2

1

(9.80m/s

2

)(1.15s)

2

=12.0m.

(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: v

x

=v

0

cos40.0°=19.2m/s.

(c) The vertical component becomes (using Eq. 4-23)

v

y

=v

0

sinθ

0

−gt=(25.0m/s)sin40.0

o

−(9.80m/s

2

)(1.15s)=4.80m/s.

(d) Since v

y

>0 when the ball hits the wall, it has not reached the highest point yet.

Answer:

horizontal component of the velocity of the ball is vx​=v0​cos40.0°, the time it takes for the ball to hit the wall is

t=Δx/vx​=(25.0m/s)cos40.0o22.0m​=1.15s.

(a) The vertical distance is

Δy=(v0​sinθ0​)t−21​gt2=(25.0m/s)sin40.0o(1.15s)−21​(9.80m/s2)(1.15s)2=12.0m.

(b) The horizontal component of the velocity when it strikes the wall does not change from its initial value: vx​=v0​cos40.0°=19.2m/s.

(c) The vertical component becomes (using Eq. 4-23)

vy​=v0​sinθ0​−gt=(25.0m/s)sin40.0o−(9.80m/s2)(1.15s)=4.80m/s.

(d) Since vy​>0 when the ball hits the wall, it has not reached the highest point yet.

Explanation:

Answer:

festival promote social..................in our country

Answer:

:)

Explanation:

i need 5 points i really do :)

The static thrust of a turbojet engine can be calculated using the formula:

F = ma + (p2 - p1)A

where F is the static thrust, m is the mass flow rate of exhaust gases, a is the acceleration of the gases, p1 is the inlet pressure, p2 is the exit pressure, and A is the area of the exhaust nozzle.

Given that the inlet and exit areas are both 0.45 m², the area A equals 0.45 m².

The velocity of the exhaust gases is given as 100 m/s, and assuming that the exit pressure is atmospheric pressure (101,325 Pa), the velocity pressure can be calculated as:

q = 0.5 * ρ * V^2 = 0.5 * 1.18 kg/m³ * (100 m/s)^2 = 5900 Pa

The temperature of the exhaust gases is given as 800 K, and assuming that the specific heat ratio γ is 1.4, the density of the exhaust gases can be calculated as:

ρ = p/RT = (101,325 Pa)/(287 J/kgK * 800 K) = 0.456 kg/m³

Using the above values, the static thrust can be calculated as follows:

F = ma + (p2 - p1)A

m = ρAV = 0.456 kg/m³ * 0.45 m² * 100 m/s = 20.52 kg/s

a = (p2 - p1)/ρ = (101,325 Pa - 1 atm)/(0.456 kg/m³) = 8367.98 m/s^2

Therefore,

F = 20.52 kg/s * 8367.98 m/s^2 + (101,325 Pa - 1 atm)*0.45 m² = 31680 N

Hence, the static thrust of the turbojet engine is 31680 N.

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For A racing car travels on a circular track with a radius of 250 m:

(a) Angular speed (ω) is 0.18 rad/s.

(b) Magnitude of acceleration is  8.1 m/s².

To solve this problem, we can use the following formulas:

(a) Angular speed (ω) is defined as the ratio of the linear speed (v) to the radius (r) of the circular path. Mathematically, it can be expressed as ω = v / r.

(b) The magnitude of acceleration (a) can be determined using the formula a = v² / r.

Now, let's calculate the values:

(a) Angular speed (ω) = v / r

                                    = 45.0 m/s / 250 m

                                    = 0.18 rad/s.

(b) Magnitude of acceleration (a) = v² / r

                                                       = (45.0 m/s)² / 250 m

                                                       = 8.1 m/s².

Since the car is moving in a circular path, the direction of its acceleration is always directed towards the center of the circle. Therefore, the direction of its acceleration is radial inward or centripetal.

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The common pressure unit used in aviation and on television and radio is pounds per square inch (PSI). The term PSI stands for "pounds per square inch. "

Pounds per square inch (PSI) is the unit of measurement for pressure in the British Imperial and U.S. Customary systems. It's defined as the amount of force applied per square inch of area. A pound-force is defined as the force exerted by gravity on an object with a mass of one pound.

A square inch is a unit of area that measures one inch by one inch. One pound per square inch (PSI) is thus equal to the force of one pound per area of one square inch. In addition to aviation, PSI is used to measure tire pressure, air pressure in HVAC systems, and hydraulic pressure in industrial machinery. It is also commonly used in television and radio broadcasting to describe air pressure.

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The process of selecting the optimal action to take from a multitude of possibilities can be characterized as decision making.

Meaning of making decisions:

The basic goal of managerial economics is decision-making. The process of choosing the best course of action from among multiple alternatives can be referred to as decision-making. Whenever there are numerous options, decision-making becomes a challenge.

Decision Making and Economics

Well, making decisions affects everyone's life; they are not just for executives or the corporate sector. Whether a person is employed or jobless, making decisions is important to everyone. Regardless of the work you are now doing, a choice needs to be made. You have several choices to make as a participant.

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Answer:

You must exert a force of 4.5 N on a book to slide it across a table.

Explanation:

The extra cost of fuel for driving 83 mph instead of 73 mph is $3.7671.

The speed of your automobile has a huge effect on fuel consumption. Traveling at 65 miles per hour (mph) instead of 55mph can consume almost 20% more fuel. As a general rule, for every mile per hour over 55 , you lose 2% in fuel economy.

If you take a 400-mile trip and your average speed is 83mph rather than the posted speed limit of 73mph, then the extra cost of the fuel is calculated as:

* **Fuel consumption at 83 mph:** 30 mpg * (1 - 2% * (83 - 55)) = 27.6 mpg

* **Fuel consumption at 73 mph:** 30 mpg * (1 - 2% * (73 - 55)) = 29 mpg

* **Extra fuel used:** 400 miles / 27.6 mpg - 400 miles / 29 mpg = 2.4 gallons

* **Extra cost of fuel:** $3.26/gallon * 2.4 gallons = $3.7671

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True, the ideal gas law tends to become inaccurate when applied to a real gas under certain conditions.

The ideal gas law is a mathematical equation that describes the behavior of an ideal gas, which is a hypothetical gas composed of a large number of randomly moving, non-interacting particles. The ideal gas law is given by the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature. This law works well under certain conditions, but it is not always accurate when applied to real gases.

Real gases consist of particles that have finite size and experience intermolecular forces, which can cause deviations from the ideal gas behavior. These deviations become significant when a real gas is subjected to high pressures or low temperatures. Under high pressure, the volume of the gas particles becomes significant compared to the overall volume of the gas, and the intermolecular forces cause deviations in the behavior of the gas. Similarly, at low temperatures, the gas particles move slower, and the intermolecular forces become more noticeable, causing deviations from the ideal gas law.

In summary, the ideal gas law is a useful tool for understanding the behavior of gases under certain conditions, but it can become inaccurate when applied to real gases under high pressure or low temperature.

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Gravitational force and Potential energy

A vector is a quantity that has both direction and magnitude, especially when used to determine where one point in space is in relation to another.

The category of vector algebra includes algebraic operations on vectors. In vector algebra, the algebraic operations involving the magnitude and direction of vectors are carried out. To execute addition and multiplication operations on physical values that are represented as vectors in three-dimensional space, vector algebra is helpful in many applications in physics and engineering.

According to the question :

θ = -224+360+75.9

θ = 211.9

\(|U| = \sqrt{V^2+W^2+2VWcos\theta}\)

= \(\sqrt{448^2+336^2+2*448*336 cos 211.9 }\)°

|U| =240.85 unit.

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True. The greater the ability of a battery to conduct current, the higher its output voltage will be.

This is because the voltage of a battery is directly related to its ability to push electrical current through a circuit. A battery with a high capacity and low internal resistance will be able to conduct more current than one with a low capacity and high internal resistance, resulting in a higher output voltage. This is why it is important to choose a battery with a high C-rating (capacity) and low internal resistance for high-performance applications, such as RC cars and drones, where maximum power output is required. In general, batteries with higher capacities and lower internal resistances are more expensive than those with lower capacities and higher internal resistances, but they offer better performance and longer life.

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The increase in length of 1,897 m of copper wire when its temperature changes from 6.7 to 40.3 ºC is approximately 1.138 mm.

When the temperature of a material changes, its dimensions tend to change as well. This is known as thermal expansion, and it occurs because materials have different coefficients of thermal expansion. The coefficient of thermal expansion (α) for copper is approximately 17 × 10^-6/ºC. This means that for every degree Celsius increase in temperature, a length of copper will increase by 17 × 10^-6 of its original length. Using this information, we can calculate the increase in length of 1,897 m of copper wire when its temperature changes from 6.7 to 40.3 ºC. To do so, we first need to calculate the change in temperature:

ΔT = 40.3 ºC - 6.7 ºC = 33.6 ºC

Next, we can calculate the change in length:

ΔL = α × L × ΔT

ΔL = 17 × 10^-6/ºC × 1,897 m × 33.6 ºC

ΔL ≈ 1.138 mm

Therefore, the increase in length of 1,897 m of copper wire when its temperature changes from 6.7 to 40.3 ºC is approximately 1.138 mm. It's important to note that this may seem like a small change, but it can be significant in certain applications, such as in electrical wiring, where precise measurements are required to ensure proper functioning.

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Answer:B

Explanation:

The answer would be B because Answer B exerts a force which has a reaction.

Based on the given information, we know that the crank AB is rotating with a constant angular velocity of 4 rad/s. To determine the angular velocity of the connecting rod CD at the instant u = 30, we need to use the equation:

cos(u) = (AB^2 + CD^2 - BC^2) / (2 x AB x CD)

where AB is the length of the crank, CD is the length of the connecting rod, and BC is the distance between the pivot points of AB and CD.

At the instant u = 30, we can calculate the values of AB, CD, and BC using trigonometry. Let's assume that AB = 10 cm, CD = 20 cm, and BC = 15 cm.

cos(30) = (10^2 + 20^2 - 15^2) / (2 x 10 x 20)

cos(30) = 0.825

Now, we can use the equation:

angular velocity of CD = angular velocity of AB x (AB/CD) x sin(u) x (1/cos(u))

angular velocity of CD = 4 rad/s x (10/20) x sin(30) x (1/0.825)

angular velocity of CD = 1.939 rad/s (rounded to three decimal places)

Therefore, the angular velocity of the connecting rod CD at the instant u = 30 is 1.939 rad/s.

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Answer:

Electromagnetic waves are the only ones that do not need a medium to travel through.

Explanation:

Answer: The answer to this question is D

Answer:

B

Explanation:

Took test

Answer:

B. The thread that connects the pearls is like an ionic bond.

Explanation:

Answer:

Explanation:

because we have to get a measuremt.

Given:

The statement: The Sun's energy is from atomic fission.

Required: To determine whether the given statement is true or false.

Explanation:

Atomic fission is the process where a heavier parent nucleus is divided into two lighter daughter nuclei.

Atomic fusion is the process where two lighter nuclei are combined to form a heavier nucleus.

In both these processes, energy is released.

Sun is a star and it has lighter atoms, so it can undergo atomic fusion.

Final Answer: The given statement is false.

In a purely resistive circuit, the phase difference between the voltage and current is zero, which means the circuit consumes all the power delivered to it by the source. In other words, the power delivered is entirely converted into heat energy dissipated by the resistance. Therefore, 100% of the apparent power is used or consumed in a purely resistive circuit. So this statement is true.

Apparent power is the product of the root mean square (RMS) voltage and RMS current, and it represents the total power delivered to the circuit. In a purely resistive circuit, the apparent power and real power are equal since there is no reactive power. Reactive power arises in circuits with inductance and capacitance, where energy is stored and returned to the circuit, leading to a phase shift between voltage and current.

In a purely resistive circuit, the current and voltage are in phase with each other, meaning they reach their maximum and minimum values at the same time. This results in a power factor of 1, which indicates that all of the apparent power drawn by the circuit is converted into real power, which is the actual power consumed by the resistive elements in the circuit. Therefore, it is true that 100% of the apparent power is used or consumed in a purely resistive circuit.

This is not the case in circuits that have reactive elements, such as inductors and capacitors, where the current and voltage are out of phase with each other. This results in a power factor that is less than 1, and the apparent power drawn by the circuit includes both real power and reactive power. In such cases, some of the apparent power is not consumed by the resistive elements but instead is stored in the reactive elements and returned to the circuit at a later time.

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Answer:

The volume of the coin is 4.236 x 10⁻⁷ m³

Explanation:

Given;

radius of a coin, r = 1.06 cm = 0.0106 m

thickness of the coin, h = 1.2 mm = 0.0012 m

The volume of the coin is given by;

volume = Area x thickness

Area of the coin = πr² = π (0.0106)² = 3.5304 x 10⁻⁴ m²

The volume of the coin = (3.5304 x 10⁻⁴ m²) x (0.0012 m)

The volume of the coin = 4.236 x 10⁻⁷ m³

Therefore, the volume of the coin is 4.236 x 10⁻⁷ m³

Answer:

Oxygen is an element that can be a solid, liquid or gas depending on its temperature and pressure. In the atmosphere it is found as a gas, more specifically, a diatomic gas. This means that two oxygen atoms are connected together in a covalent double bond.

That depends on the values of the resistors.

If the same two resistors are used in both cases, then the total resistance is more in series and less in parallel.

Here's a catchy little factoid for ya:

-- In series, the total resistance is more than the biggest single one.

-- In parallel, the total resistance is less than the smallest single one.

In the electromagnetic spectrum the greater the frequency the smaller the wavelength, then is the frequency is the lowest in the light spectrum the light will have the longest wavelength. Therefore, the answer is b.

Answer:

a weak interaction between particles the result from mass