When Dylan checks their school lunch account, the
balance is $56.
After buying 8 lunches, the balance is $40.
At Dylan's school, every student starts with a balance
of $80 for school lunches.
How many lunches had Dylan bought when they first
checked their balance?

Answer:

Hello! Your answer would be, C) Divide by 2

Step-by-step explanation:

And plz don't be mean. :(

Hope I helped! Brainiest plz!♥ Have a nice afternoon. Hope you make a 100%! -Amelia

Answer:

n = 6.42105263158

Step-by-step explanation:

324 - 202 = 122

122 ÷ 19 = 6.42105263158

That seems like a very large decimal place for a school related math problem if I'm doing this correctly.  When you say increased by you mean addition right?

Step-by-step explanation:

I would think it is Q but not 100% sure

Answer:

The coordinates of the point X:

Step-by-step explanation:

Let X be the point.

As the point X is in the directed line segment from (-2,-8) to (5,-1) into the ratio of 1 to 6

i.e.

\(\left(x_1,\:y_1\right)\:=\:\left(-2,-8\right)\)

\(\left(x_2,\:y_2\right)=\left(5,-1\right)\)

Rise = y₂ - y₁

       \(= -1 - (-8)\)

       \(= -1 + 8\)

       \(= 7\)

Run = x₂ - x₁

      \(= 5 - (-2)\)

      \(= 5 + 2\)

      \(= 7\)

1 : 6 ratio means the point X lies at

\(\frac{1}{6+1}=\frac{1}{7}=14\%\)

Thus,

rise for X \(=\:7\:\times \:14\%=1\)

run for X \(=\:7\:\times \:14\%=1\)

Thus, coordinates of X will be:

\(x = -2 + 1 = -1\)

\(y = -8 + 1 = -7\)

Therefore, we conclude that:

The coordinates of the point X:

The point (-1, -7) divide the segment from (-2,-8) to (5,-1). in the ratio 1:6.

If a point O(x, y) divides the line segment AB in the ratio of n:m, where the endpoints of the line is A(x₁, y₁) and B(x₂. y₂), the point O is at:

\(x=\frac{n}{n+m}(x_2-x_1)+x_1 \\\\y=\frac{n}{n+m}(y_2-y_1)+y_1\)

Given the ratio 1:6, let O(x, y) divide the segment from (-2,-8) to (5,-1). Hence:

\(x=\frac{1}{1+6}(5-(-2))+(-2)=-1\\\\y=\frac{1}{1+6}(-1-(-8))+(-8)=-7\)

O = (-1, -7)

The point (-1, -7) divide the segment from (-2,-8) to (5,-1) in the ratio 1:6.

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Answer:

x = 10

y= 12

Step-by-step explanation:

We know that TSV = 90 degrees

5x+4x = 90

9x = 90

Divide by 9

9x/9 = 90/9

x = 10

We know that RSU = 180

10y+10 +5x= 180

10y + 10 + 5(10) = 180

10y + 10 +50 = 180

10y +60 = 180

Subtract 60 from each side

10y = 120

Divide by 10

y = 12

========================================================

Explanation:

We'll need to find the LCM of 5, 8 and 10.

List out the prime factorization of the three numbers.

The unique prime factors are 2 and 5. The '1' isn't a prime number, so we can ignore it.

The '2' has an exponent of 3 as the largest exponent, meaning 2^3 is part of the LCM. The '5' has the largest exponent of 1. So 5^1 = 5 is also part of the LCM

LCM = 2^3*5 = 8*5 = 40

List out the multiples of 40

40, 80, 120, 160, ...

The number 80 is the only multiple between 61 and 107

A parallelogram is a geometrical shape such that its adjacent angles are supplementary, in other words, the addition of two angles that are next to one another is equal to 180°.

In the figure, b is next to c, b is next to a and a is next to the 30° angle; therefore:

We have a system of three equations and three unknowns, we can solve it as follows:

Thus, the answers are a=150°, b=30°, c=150°

Answer:

25/4=y

Step-by-step explanation:

Answer:

e) cannot be determined

Step-by-step explanation:

hope this helps!!

Answer:

F.

Step-by-step explanation:

there are 36 tiles overall from where 4 are purple so

\(\frac{4}{36} =\frac{1}{9} =\frac{1}{3} *\frac{1}{3}\)

Using proportions, it is found that the angular velocity at the tip of the blade is of 753.98 radians per minute.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Each revolution has \(2\pi\) radians, hence in one minute, the 120 revolutions will have a measure in radians of:

M = 120 x 2pi = 240pi = 753.98

Hence the angular velocity is of 753.98 radians per minute.

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The dividend in 2018 was $2.95, and it is expected to grow at a rate of 7.4% for the next five years and 2.6% thereafter. With an equity cost of capital of 8.6%, the value per share at the end of 2018 can be calculated.

To calculate the value per share at the end of 2018, we need to discount the expected future dividends using the dividend-discount model. The model assumes that the value of a stock is equal to the present value of all its expected future dividends.

First, we need to calculate the dividends for each year from 2019 to 2023. We start with the dividend in 2018, which was $2.95. We then increase it by 7.4% each year for the next five years:

Dividend in 2019 = $2.95 * (1 + 7.4%) = $3.17

Dividend in 2020 = $3.17 * (1 + 7.4%) = $3.40

Dividend in 2021 = $3.40 * (1 + 7.4%) = $3.65

Dividend in 2022 = $3.65 * (1 + 7.4%) = $3.92

Dividend in 2023 = $3.92 * (1 + 7.4%) = $4.22

After 2023, the dividend is expected to grow at a rate of 2.6% per year. To find the value per share at the end of 2018, we discount the future dividends to their present value using the equity cost of capital of 8.6%.

The present value of the dividends can be calculated as follows:

PV = (D1 / (1 + r)) + (D2 / (1 + r)^2) + ... + (Dn / (1 + r)^n)

where PV is the present value, D1 to Dn are the dividends for each year, r is the equity cost of capital, and n is the number of years.

In this case, n = 5 because we are discounting the dividends for the next five years. Let's calculate the present value:

PV = ($3.17 / (1 + 8.6%)) + ($3.40 / (1 + 8.6%)^2) + ($3.65 / (1 + 8.6%)^3) + ($3.92 / (1 + 8.6%)^4) + ($4.22 / (1 + 8.6%)^5)

PV = $3.17 / 1.086 + $3.40 / 1.086^2 + $3.65 / 1.086^3 + $3.92 / 1.086^4 + $4.22 / 1.086^5

PV ≈ $2.91 + $3.07 + $3.24 + $3.41 + $3.59

PV ≈ $16.22

Therefore, the estimated value per share of Procter and Gamble at the end of 2018 using the dividend-discount model is approximately $16.22.

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The dividend in 2018 was $2.95, and it is expected to grow at a rate of 7.4% for the next five years and 2.6% thereafter. With an equity cost of capital of 8.6%, the value per share at the end of 2018 can be calculated.

To calculate the value per share at the end of 2018, we need to discount the expected future dividends using the dividend-discount model.
The model assumes that the value of a stock is equal to the present value of all its expected future dividends. First, we need to calculate the dividends for each year from 2019 to 2023. We start with the dividend in 2018, which was $2.95. We then increase it by 7.4% each year for the next five years:

Dividend in 2019 = $2.95 * (1 + 7.4%) = $3.17
Dividend in 2020 = $3.17 * (1 + 7.4%) = $3.40
Dividend in 2021 = $3.40 * (1 + 7.4%) = $3.65
Dividend in 2022 = $3.65 * (1 + 7.4%) = $3.92
Dividend in 2023 = $3.92 * (1 + 7.4%) = $4.22

After 2023, the dividend is expected to grow at a rate of 2.6% per year. To find the value per share at the end of 2018, we discount the future dividends to their present value using the equity cost of capital of 8.6%.
The present value of the dividends can be calculated as follows:
PV = (D1 / (1 + r)) + (D2 / (1 + r)^2) + ... + (Dn / (1 + r)^n) where PV is the present value, D1 to Dn are the dividends for each year, r is the equity cost of capital, and n is the number of years.

In this case, n = 5 because we are discounting the dividends for the next five years. Let's calculate the present value: PV = ($3.17 / (1 + 8.6%)) + ($3.40 / (1 + 8.6%)^2) + ($3.65 / (1 + 8.6%)^3) + ($3.92 / (1 + 8.6%)^4) + ($4.22 / (1 + 8.6%)^5)
PV = $3.17 / 1.086 + $3.40 / 1.086^2 + $3.65 / 1.086^3 + $3.92 / 1.086^4 + $4.22 / 1.086^5
PV ≈ $2.91 + $3.07 + $3.24 + $3.41 + $3.59
PV ≈ $16.22
Therefore, the estimated value per share of Procter and Gamble at the end of 2018 using the dividend-discount model is approximately $16.22.

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The mgf reduces to mu(t) = (1 - 2t)^(p/2) det(I - 2tAV^(1/2))^(1/2),

which is the mgf of a chi-squared distribution with p degrees of freedom and scale parameter AV^(1/2).

To find the moment generating function (mgf) of U = XTAX, we first note that X follows a multivariate normal distribution with mean μ and covariance matrix V. Thus, we can write X = μ + Z, where Z ~ Np(0, V).

Using this expression for X, we have U = XTAX = (μ + Z)TA(μ + Z) = ZTAZ + 2μTAZ + μTAμ.

Since Z has a normal distribution, ZTAZ has a chi-squared distribution with p degrees of freedom. Thus, the mgf of ZTAZ is given by

M(t) = E[exp(tZTAZ)] = (1 - 2t)^(p/2) det(I - 2tV^(1/2)AV^(1/2))^(1/2),

where det denotes the determinant of a matrix.Next, we note that μTAZ has a normal distribution with mean 0 and covariance matrix μTAV. Thus, the mgf of μTAZ is given by

M1(t) = E[exp(tμTAZ)] = exp(tμTAμ/2) det(I - 2tAV^(1/2))^(1/2).

Using these expressions, we can find the mgf of U as follows:

mu(t) = E[exp(tU)] = E[exp(tZTAZ + 2tμTAZ + tμTAμ)]

= M(t) * M1(t)

= (1 - 2t)^(p/2) det(I - 2tV^(1/2)AV^(1/2))^(1/2) * exp(tμTAμ/2) det(I - 2tAV^(1/2))^(1/2)

Now, suppose that Aps = 0, i.e., A is orthogonal to the subspace spanned by the columns of V. In this case, we have AV^(1/2) = 0 and hence det(I - 2tV^(1/2)AV^(1/2)) = 1. Moreover, we have μTAμ = μTAVμ = 0 since Aps = 0. Thus, the mgf reduces to

mu(t) = (1 - 2t)^(p/2) det(I - 2tAV^(1/2))^(1/2),

which is the mgf of a chi-squared distribution with p degrees of freedom and scale parameter AV^(1/2).

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Step-by-step explanation:

you mean f^(-1) (x), so the inverse function, right ?

we find the inverse function by going back to the basic definition with a result variable : f(x) = y

and so,

y = x + 9

now we transform this equation, so that we end up with x alone n on one side and everything else in the other side :

y - 9 = x

and now we just rename x to y and y to x to turn this into a "regular" function :

x - 9 = y

or

y = x - 9

and that is the inverse function of the original function.

f^(-1) (x) = x - 9

Answer:

They do not.

Step-by-step explanation:

Even if you add them that will get you 13+5+12=30m which isnt 90 degrees. And even if you multiply them 12 times 5 is 60 times 13 that is 780 m :)

Answer:

4 cm

Step-by-step explanation:

v=a³

a=v⅓ =64⅓ =4cm

hope it helps

The width of the rectangle is, 2.5 inches.

What is rectangle?

A rectangle is a quadrilateral with four right angles in the Euclidean plane. It may alternatively be described as a parallelogram with a right angle or an equiangular quadrilateral, where equiangular denotes that all of its angles are equal. A square is a rectangle with four equally long sides.

Given:  The length of a rectangle is 16.8 inches ,  with an area of 42 square inches.

Since Area is 2- dimensional, it has length and width.

Area of Rectangle in square unit is given by multiplying the length by width.

The formula is given by:

Area of rectangle(A) = Length *width....(1)

Substitute the value of Area (A) = 42 square inches and length  = 16.8 inches in equation [1], to solve for width(w).

42 = 16.8*w

w= 2.5 inches

Therefore, the width of rectangle is, 2.5 inches.

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x+ 32 = 90

x= 58°

y + x = 90°

y= 90-58

y =32°

The simplified form of the given trigonometric expression is √6/2·( cos(5π/12) + i·sin(5π/12)).

Given that, 12(cos(7π)/6 +isin(7π)/6))/(4√6(cos(3π/4) +isin(3π/4)).

= (12((-0.866)+i(-0.5))/(4√6(-0.7071+i0.7071)

= 12(-0.866-0.5i)/(4√6(-0.7071+i0.7071))

= (-10.392-6i)/9.8(-0.7071+i0.7071)

= (-10.392-6i)/(-6.9+9.8i)

If you have a problem such as   a·cos(A) / b·cos(B)

you can solve it as (a/b)·cos(A - B)

For this problem a = 12 and b = 4√(6) so a/b =√6/2

and A = 7π/6 and B = 3π/4 so A - B = 5π/12

Therefore, the simplified form of the given trigonometric expression is √6/2·( cos(5π/12) + i·sin(5π/12)).

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The probability that the waves are turbulent given that the water is cold is approximately 0.112 (rounded to the nearest millionth).

Given that the water is cold, the probability that the waves are turbulent needs to be found. Let's apply the Bayes' Theorem to find the probability of the waves being turbulent given that the water is cold.

The formula for Bayes' Theorem is as follows:

P(B|A)={P(A|B)\ P(B)} * {P(A)}

Where, P(B|A) is the probability of event B given that event A has occurred, P(A|B) is the probability of event A given that event B has occurred, P(A) is the probability of event A, and P(B) is the probability of event B. The question requires us to find the probability of the waves being turbulent given that the water is cold. So, the conditional probability we need to find is P(T|C), where T represents the event of waves being turbulent and C represents the event of the water being cold. The given probabilities are:

P(T)=0.36

P(T^C)=0.64

P(C|T)=0.21

P(C|T^C)=0.51

By the complement rule, P(C)=1-P(C^C)

P(C)=1-0.15=0.85

Let's substitute the given probabilities into the Bayes' Theorem formula and solve for

P(T|C) :

(T|C)={P(C|T)\ P(T)} * {P(C|T)\P(T)+P(C|T^C)\ P(T^C)}={0.21\ 0.36} * {0.21\0.36+0.51\ 0.64} = 0.112

Therefore, the probability that the waves are turbulent given that the water is cold is approximately 0.112 (rounded to the nearest millionth).

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Answer:

240000000 times bigger.

If we solve 3x10^8 we get 300000000

Then if we solve for 6x10^7 we get 60000000

Subtract those two using long subtraction to evaluate and we get 240000000

Answer:

7

Step-by-step explanation:

Answer: I believe it's correct. Good Job! :D

Answer:

The term simplifies to \(8a^6\).

Step-by-step explanation:

When we cube a number, we are multiplying it by itself three times.  So, we can think of \((2a^2)^3\) as \(2a^2*2a^2*2a^2\).  Multiplying \(2*2*2\) gets us 8, so the coefficient of our final term will be 8.  Now we have the variables.  When multiplying variables with exponents, all we have to do is add the exponents of all the terms together.  So, we add \(2+2+2\) and get 6.  Thus, the variable a is raised to the \(6^t^h\) power.  Adding this to the coefficient yields the answer \(8a^6\).

Step-by-step explanation:

The slope-intercept form of the equation of a line is:

y = mx + b

where m is the slope of the line and b is the y-intercept.

We are given that the line has a slope of –9 and passes through the point (1,–3). We can use this information to find the value of b.

First, we can use the point-slope form of the equation of a line to write the equation:

y - y1 = m(x - x1)

where x1 and y1 are the coordinates of the given point.

Substituting the values we know, we get:

y - (-3) = -9(x - 1)

Simplifying:

y + 3 = -9x + 9

Subtracting 3 from both sides:

y = -9x + 6

This is now in the slope-intercept form, with a slope of –9 and a y-intercept of 6.

Therefore, the equation of the line is y = -9x + 6.

Answer:

63 degrees

Step-by-step explanation:

Side by side angles, I believe are called supplementary. So, they are equal to 180 when added together. 180-117 is 63.

~theLocoCoco

The Answer is:

63°

Step-by-step explanation:

The angle 117° is the key information. Across the line, the angle 117° is part of the 180° across the line. Angle RMN is equal to 180° - 117° =  63°

Answer:

no idea what the answer is

Answer:

I will assume the equation is supposed to be f(x) = x^2 – 5x + 12 since it is said to be a quadratic equation.

Step-by-step explanation:

See attached graph.

The value of f(–10) = 82     False

      f(-10) = (-10)^2 - 5*(-10) + 12

       f(-10) = (100) +50 + 12

      f(-10) = 162

The graph of the function is a parabola.  True

The graph of the function opens down.   False

The graph contains the point (20, –8).      False

The graph contains the point (0, 0).          False

Answer:

24 + 121

Step-by-step explanation:

w=wristband.

h=headband

Total wristbands:-

\(\\ \sf\longmapsto 12(2)=24\)

You get a quadratic equation when the square of the expression that comes after b plus b times that same expression not squared plus c equals 0.

Any equation in algebra that can be written in standard form as

ax^2+bx+c=0,

where x stands for an unknown integer and a, b, and c are known quantities, where a 0, is considered a quadratic equation.

The coefficients of the equation are the numbers a, b, and c, which can be separated by naming them, respectively, the quadratic coefficient, the linear coefficient, and the constant coefficient or free term.

Due to the fact that the solutions lie where the parabola crosses the x-axis, quadratic equations frequently have two solutions.

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