When energy is changed from one form to another, _____.

all of the energy is changed to a useful form

a physical change occurs

all of the energy can be accounted for

some of the energy is lost entirely

Answer:

Atomic Number = 3.

Explanation:

The number of protons determines the atomic number. Basically the number of protons is the exact same as the atomic number.

Protons 3 = Atomic number 3

Standard temperature and pressure are the conditions that are considered standard when compared to experimental measurement. At STP, 6680 mL of oxygen will have 0.3 moles.

STP is the abbreviated form standard temperature and pressure that is a definitive condition of the reaction system that is used for the comparative analysis.

Given,

Volume of oxygen = 6680 mL = 6.680 L

At STP,

1 mol = 22.4 L

Substituting values to calculate the moles as

1 mol = 22.4 L

X mol = 6.680 L

Solving for X:

X = 6.680 L × 1 mol ÷ 22.4 L

= 0.298 moles

Therefore, 6680 mL of oxygen sample contains 0.3 moles of oxygen.

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The metal has a specific heat of 0.390 J/g°C.

What is Specific Heat ?

Specific heat is an important concept in thermodynamics and is used to determine the amount of heat required to raise the temperature of a material, or conversely, the amount of heat that is released when a material cools. Different materials have different specific heats, which means that they require different amounts of heat to change their temperature. For example, water has a very high specific heat, which means that it takes a lot of heat energy to raise its temperature, while metals have much lower specific heats and require much less heat energy to change their temperature.

We can use the formula for the heat absorbed or released by a material:

Q = m * c * ΔT

where Q is the heat absorbed or released, m is the mass of the material, c is the specific heat, and ΔT is the change in temperature.

In this case, the metal absorbs 57.2 J of heat, and the temperature of the sample rises 32°C. The mass of the metal is 4.70 g. When these values are added to the formula, we obtain:

57.2 J = 4.70 g * c * 32°C

Solving for c, we get:

c = 57.2 J / (4.70 g * 32°C)

= 0.390 J/g°C

Therefore, the specific heat of the metal is 0.390 J/g°C.

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Since ethanol has a more symmetrical structure than methanol and iso-propanol, it would be expected to have a lower heat of vaporization than the other two molecules.

At one of the temperatures used in the Clausius Clapeyron plot, the calculation of the heat of vaporization is as follows:

At 80°C (352 K), the heat of vaporization of ethanol is 41.9 kJ/mole.

The normal boiling point of ethanol is 78.3°C (351.45 K), which is higher than methanol (64.7°C, 337.85 K) but lower than iso-propanol (82.5°C, 355.65 K). This can be attributed to the fact that the molecules of ethanol have a more symmetrical structure than methanol and iso-propanol, which makes them more stable and thus easier to vaporize. This is because the forces of attraction between the molecules of ethanol are weaker than those between the molecules of methanol and iso-propanol, making it easier for ethanol molecules to escape from the liquid

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Answer: C, negative

Explanation: Electrons give a negative charge, so having more electrons then postiivley charged protons would result in a negative charge.

To determine the pressure of the ammonia gas at a new volume and temperature, we can use the combined gas law, which states that the ratio of the initial pressure, volume, and temperature is equal to the ratio of the final pressure, volume, and temperature.

Using the combined gas law equation: (P1 * V1) / T1 = (P2 * V2) / T2

Given:

P1 = 585 torr (initial pressure)

V1 = 20.0 ml (initial volume)

T1 = 20.0 °C + 273.15 = 293.15 K (initial temperature)

V2 = 50.0 ml (final volume)

T2 = 50.0 °C + 273.15 = 323.15 K (final temperature)

We need to solve for P2 (final pressure).

Rearranging the equation, we have:

P2 = (P1 * V1 * T2) / (V2 * T1)

Substituting the given values into the equation:

P2 = (585 torr * 20.0 ml * 323.15 K) / (50.0 ml * 293.15 K)

Calculating this expression gives us the final pressure (P2) of the ammonia gas at the new volume and temperature.

In summary, using the combined gas law equation, we can determine the pressure of the ammonia gas at a new volume and temperature. By substituting the given values into the equation and performing the calculation, we can find the final pressure of the gas.

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Answer:

Mechanical energy is basically the energy of movement

For example, if I am running, im using Mechanical energy

The ideal gas law, which relates the pressure, volume, temperature, and number of moles of an ideal gas, can be applied to real-world situations. By considering a specific scenario and applying the ideal gas law, we can analyze the behavior of gases and make predictions about their properties.

Let's consider a situation where a scuba diver is exploring underwater at a depth of 30 meters. We can apply the ideal gas law, specifically the form known as Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Question: How does the pressure of the gas in the scuba tank change as the diver descends to a depth of 30 meters, assuming the temperature remains constant?

To answer this question, we can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. By keeping the temperature constant, we can observe the relationship between pressure and volume as the diver descends and calculate the change in pressure based on the change in volume.

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Catalytic Cracking: Catalytic cracking is a process used to break down heavier hydrocarbon molecules into lighter fractions such as gasoline.

Hydrocracking: Hydrocracking is a process that combines catalytic cracking with hydrogenation. It is used to convert heavy hydrocarbons into lighter, more valuable products. Catalysts, such as metal sulfides or noble metals supported on a porous material, are employed to promote the cracking reactions and enable the addition of hydrogen to saturate unsaturated hydrocarbons.

Catalytic Reforming: Catalytic reforming is a process used to convert low-octane naphtha into high-octane gasoline blending components. Catalysts based on platinum or platinum-rhenium are utilized to promote the isomerization, dehydrogenation, and cyclization reactions that enhance the octane rating of the naphtha.

Hydrotreating: Hydrotreating is a process that removes impurities, such as sulfur, nitrogen, and metals, from petroleum feedstocks. Catalysts containing metals like nickel or molybdenum supported on alumina or other materials are used to promote the hydrogenation of these impurities, resulting in cleaner and more environmentally friendly fuels.

Desulfurization: Desulfurization is a specific type of hydrotreating that focuses on the removal of sulfur compounds from petroleum products, particularly diesel fuel. Catalysts based on metals such as cobalt and molybdenum are employed to facilitate the hydrodesulfurization reaction, which converts sulfur compounds into hydrogen sulfide.

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Answer: to copy itself during cell division

Explanation:

Answer:

Explanation:

Suppose a solution contains calcium,

C

a

2

+

, ions.

According to solubility rules, which other ion should be added to form a precipitate?

CO3-(carbonate ion) negatively charged can be added to make insoluble(not dissolving=forming a precipitate) CaCO3(Calcium Carbonate)= common word "Limestone"

The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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The binding energy for copper-63 is approximately 0.2447 kJ/mol nucleons.

To calculate the binding energy per nucleon for copper-63, we need to know the total mass defect of the nucleus and the number of nucleons in copper-63.

First, we need to find the total mass defect. The total mass of copper-63 can be calculated by multiplying the molar mass of copper-63 by the molar mass constant:

Total mass of copper-63 = molar mass of copper-63 * molar mass constant

= 62.92980 g/mol * 1 g/mol

= 62.92980 g

Next, we need to calculate the total mass of the individual nucleons (protons and neutrons) in copper-63. We can do this by multiplying the number of protons by the molar mass of hydrogen-1 and the number of neutrons by the molar mass of neutron-1, then summing these two values:

Total mass of nucleons = (number of protons * molar mass of hydrogen-1) + (number of neutrons * molar mass of neutron-1)

Copper-63 has 29 protons and 34 neutrons, so we can substitute these values:

Total mass of nucleons = (29 * 1.00783 g/mol) + (34 * 1.00867 g/mol)

= 58.23207 g + 34.30278 g

= 92.53485 g

Now we can calculate the mass defect:

Mass defect = Total mass of nucleons - Total mass of copper-63

= 92.53485 g - 62.92980 g

= 29.60505 g

Finally, we can calculate the binding energy per nucleon using Einstein's mass-energy equivalence equation (\(E = mc^2\)), where c is the speed of light:

Binding energy per nucleon = (Mass defect * \(c^2\)) / (number of nucleons)

Let's convert the masses from grams to kilograms and use the speed of light (\(c = 2.998 \times 10^8 m/s\)) to calculate the binding energy per nucleon:

Mass defect = 29.60505 g = 0.02960505 kg

Number of nucleons = number of protons + number of neutrons = 29 + 34 = 63

Speed of light (c) = \(2.998 \times 10^8 m/s\)

Binding energy per nucleon = (0.02960505 kg * (\(2.998 \times 10^8 m/s)^2\)) / 63

≈ \(15.28 \times 10^6 kg m^2/s^2\)

To convert this value to kilojoules per mole (kJ/mol), we can use the conversion factor \(1 J = 1 kg m^2/s^2\) and Avogadro's number (\(6.022 \times 10^23 mol^{-1})\):

Binding energy per nucleon = \(\[(15.28 \times 10^6 \, \text{kg m}^2/\text{s}^2) \times (1 \, \text{J} / 1 \, \text{kg m}^2/\text{s}^2) \times (1 \, \text{kJ} / 1000 \, \text{J}) \times (6.022 \times 10^{23} \, \text{mol}^{-1})\]\)

≈ 0.2447 kJ/mol nucleons

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Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

From the question

mass = 35 g

volume = 7 cm³

The density is

\(density = \frac{35}{7} \\ \)

We have the final answer as

Hope this helps you

1. The creature is the Porcupine

2. He lived in Sri Lanka

3. The temple in Manish Gandir

4. It is in the excited state

5. Carbon can share four electrons

6. Alcohol is soluble in water.

Nascent hydrogen is the term used to describe hydrogen atoms or molecules that are created during specific chemical reactions and are in a highly reactive condition. The word "nascent" refers to something that is new or just created, implying that the hydrogen is in a highly reactive state right away.

Nascent hydrogen is often produced by processes like the electrolysis of water or the interaction of a metal with an acid.

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Answer:

Explanation:

The sketch of the curve for two Br atoms can be seen in the image attached below. From the image below, we can deduce the following:

On the periodic table, the Bromine (Br) atom is the fourth member in the halogen family group. The atomic size increases from top to bottom down the group, thus Br atom posses a larger atomic size than Cl atom. As a result of that, the bond length formation between the two Br atoms will be larger compared to that of the two Cl atoms.

In this question, we have photons with 0.237 J and 659 nm, now we need to find out how many photons there are in this situation, we can do that by looking at the energy of one single photon with the following formula:

E = h*f, since we don't have the f (frequency), we can use the relationship of frequency with speed of light and wavelength

E = h * c/λ

h is Planck's constant = 6.626*10^-34 J*s

c is the speed of light = 3.0*10^8 m/s

λ is the wavelength = 659*10^-9 m

E = 6.626*10^-34 * (3.0*10^8/659*10^-9)

E = 3.02*10^-19 J, this is the energy of a single photon

Now we can take the total energy, 0.237 J and check how many photons we have:

0.237/3.02*10^-19 = 7.85*10^17 photons

The compound is formed by 1 atom of gold and 3 atoms of chlorine.

In this case, the gold atom must have a charge of +3 in order to have a compound with a net charge of zero because the molecule Cl3 has a charge of -3. This is why the name of the compound is Gold(III) Chloride.

Answer:

There are 2 answers.  A and C

Explanation:

Si is Silicon, which is a metalloid,

Br2 is Bromine, which is a metalloid

Answer:

H20

Explanation:

Answer:

hope it helped you

Explanation:

H2O (u have to write ✍️no 2 below H.

The bond enthalpy of the N-N triple bond is 418kj/mol. The correct statement about the N2 molecule is correct is that It requires less energy to break the bonds in molecule A than it does in molecule B.

A molecule is described as a group of two or more atoms held together by attractive forces known as chemical bonds

In chemistry, bond energy (E) or bond enthalpy (H) is the measure of bond strength in a chemical bond which means that the higher the bond enthalpy, the more energy is needed to break the bond and the stronger the bond.

The lower the bond enthalpy, the lesser energy is needed to break the bond and the weaker the bond.

So we can say that the e correct option is A. Since A has a lower energy value compared to B, it would take a lesser amount of energy to break the bonds in A.

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#completye question:

The bond enthalpy of the N-N triple bond is 418kj/mol. Which statement about the N2 molecule is correct?​

A. It requires less energy to break the bonds in molecule A than it does in molecule B.

B.It requires more energy to break the bonds in molecule A than it does in molecule B.

C. Molecule A is more stable than molecule B.

D. Molecule A has stronger bonds than molecule B.

Answer:

30 moles of CO₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Al₂(CO₃)₃ —> Al₂O₃ + 3CO₂

From the balanced equation above,

1 mole of Al₂(CO₃)₃ decomposed to produce 3 moles of CO₂.

Finally, we shall determine the number of mole of CO₂ produced from the decomposition of 10 moles of Al₂(CO₃)₃. This can be obtained as follow:

From the balanced equation above,

1 mole of Al₂(CO₃)₃ decomposed to produce 3 moles of CO₂.

Therefore, 10 moles of Al₂(CO₃)₃ will decompose to produce = 3 × 10 = 30 moles of CO₂.

Thus, 30 moles of CO₂ were obtained from the reaction.

30 moles of CO₂ will be produced by the decomposition of 10 moles of  \(\rm Al_2(CO_3)_3\).

Carbon dioxide is a gas made up of two elements, carbon, and oxygen.

It is the gas that is used by plants to make their food.

The % of this gas on Earth is 0.03%

The balanced equation is

\(\rm Al_2(CO_3)_3 \longrightarrow Al_2O_3 + 3CO_2\)

1 mole of \(\rm Al_2(CO_3)_3\) decomposes to produce 3 moles of CO₂.

If 1 mole of \(\rm Al_2(CO_3)_3\) produce 3 moles of CO₂, then decomposition of 10 moles of \(\rm Al_2(CO_3)_3\) will produce

3 × 10 = 30 moles of CO₂.

Thus, 30 moles of CO₂ will be produced by the decomposition of 10 moles of  \(\rm Al_2(CO_3)_3\).

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in the classical free electron model, the neglect of electron-ion interaction is referred to as the free electron approximation. The correct option is (ii) Only.

This approximation assumes that the interaction between electrons and ions can be ignored, treating the electrons as free particles moving in a periodic potential without any significant influence from the ions. The independent electron approximation, on the other hand, assumes that the behavior of each electron can be considered independently of the others. The Drude electron-ion approximation incorporates electron-ion interactions and is not part of the classical free electron model. Therefore, the correct option is (ii) Only.

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Answer:

Explanation:

Isotopes differ in the number of neutrons; in ions the number of electrons is different from the number of protons. Isotopes are atoms that have the same number of protons but different numbers of neutrons.

To determine the two half-reactions that will produce the largest voltage under standard conditions, we must consider the standard reduction potentials for each half-reaction.

The half-reaction with the more positive reduction potential will be the reduction half-reaction, while the half-reaction with the more negative reduction potential will be the oxidation half-reaction. This is because the reduction half-reaction is where the electrons are gained, while the oxidation half-reaction is where the electrons are lost.

Under standard conditions, the standard reduction potential for the reduction half-reaction must be higher than the standard reduction potential for the oxidation half-reaction. This creates a larger potential difference between the two half-reactions, resulting in a larger overall voltage.

In general, the half-reaction with a metal as the reactant tends to have a more negative reduction potential, while the half-reaction with a non-metal tends to have a more positive reduction potential.

Therefore, to answer the question, we must compare the standard reduction potentials for various half-reactions and select the two that have the largest potential difference. This will result in the largest voltage under standard conditions.

Overall, the selection of the two half-reactions will depend on the specific conditions of the galvanic cell, such as the type of electrodes and electrolytes used. It is important to consider the conditions carefully when selecting the appropriate half-reactions for a given galvanic cell.

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A LOAEL is defined as the lowest dose that demonstrates a significant increase in an observable adverse effect. The term LOAEL stands for "Lowest Observed Adverse Effect Level."

When testing chemicals and other substances for toxicity, the goal is to determine the concentration or dose at which adverse effects begin to appear. The LOAEL is the lowest dose at which an adverse effect is observed. This value can be used to establish a safe level of exposure to a substance.
To determine the LOAEL, a series of tests are conducted in which different doses of the substance being tested are administered to test animals. The animals are observed for any adverse effects, such as changes in behavior, weight loss, or organ damage. The lowest dose at which an adverse effect is observed is the LOAEL.
It is important to note that the LOAEL is a relative measure of toxicity. It only provides information on the dose at which an adverse effect is first observed and not on the severity of the effect. In addition, the LOAEL may vary depending on the species tested and other factors.
In summary, the LOAEL is the lowest dose at which an observable adverse effect is detected. This value is used to establish a safe level of exposure to a substance.

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Answer:

Explanation:

Solubility of KNO₃ at 20° C = 32 g / 100g of water

that means , per 100 g of water maximum of 32 g of  KNO₃ can be dissolved at 20° C .

Solubility of KNO₃ at 40° C = 62 g / 100g of water

that means , per 100 g of water maximum of 62 g of  KNO₃ can be dissolved

40° C.

So when a saturated solution in which maximum KNO₃ has been dissolved is cooled from  40° C to 20° C , due to decrease in solubility at lower temperature some KNO₃ will come out of the solution . Per 100 gram of saturated solution , 62 - 32 = 30 g of KNO₃ will precipitate out or come out of water . They can be filtered out .