When observed in an inertial frame of reference, all objects that experience no forces will appear to

Answer:

m = 100[gram]

Explanation:

In order to solve this problem, we must remember the definition of the density of matter, which is the relationship between mass and volume. The density can be calculated by means of the following formula.

\(Ro=m/V\)

where:

Ro = density = 1 [gramm/cm³]

m = mass [gramm]

V = volume = 100 [cm³]

Now replacing:

\(m=Ro*V\\m=(1\frac{grm}{cm^{3} } )*100cm^{3} \\m=100[gram]\)

Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

To find the light speed in the glass, we can use the formula:

v = c / n

where v is the speed of light in the glass, c is the speed of light in a vacuum (approximately 3.00 x 10^8 m/s), and n is the refractive index of the glass.

Let's assume the refractive index of the glass is 1.50 (a typical value for glass).

v = (3.00 x 10^8 m/s) / 1.50 = 2.00 x 10^8 m/s

So, the speed of light in the glass is 2.00 x 10^8 m/s.

To find the number of wavelengths of the light inside the slide, we can use the formula:

n = d / λ

where n is the number of wavelengths, d is the thickness of the slide, and λ is the wavelength of the light.

Given:

d = 2 mm = 2 x 10^-3 m

λ = 510 nm = 510 x 10^-9 m

n = (2 x 10^-3 m) / (510 x 10^-9 m)

n = 3.92

So, approximately 3.92 wavelengths of the light are inside the slide.

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Answer:

D. Fats

Explanation:

they are the long term energy storing nutrient carbohydrates are a quick way for energy minerals dont contain any energy and neither do proteins

fats

Explanation:

it is nutrient kept in the body

a)Velocity vector of child can be expressed as v = v_parallel + v_perpendicular. b) Velocity vector of child is v = v_parallel + v_perpendicular. c)Net force acting on the child is approximately -20.7 kg m/s in the direction opposite to direction of  velocity vector.

An influence that causes motion of an object with mass to change its velocity is called force.

(a) The child is moving in a circle with radius 5.7 m, so the circumference of the circle is 2π(5.7) ≈ 35.8 m. The child completes one revolution every 10.3 seconds, so their speed is 35.8/10.3 ≈ 3.48 m/s. The velocity vector of child can be expressed as v = v_parallel + v_perpendicular.

dp/dt = m(dv_parallel/dt), m is the mass of child. As magnitude of the velocity is constant, dv/dt = 0, so dv_parallel/dt = -v_perpendicular/r, where r is radius of the circle. Therefore, dp/dt = -mv_perpendicular/r = -(34 kg)(3.48 m/s)/5.7 m ≈ -20.7 kg m/s. Direction of dp/dt is opposite to direction of v_perpendicular, which is perpendicular to radius vector.

(b)The child is moving in a circle, so their acceleration is given by a = v²/r, where v is the speed of the child and r is the radius of the circle. Therefore, a = (3.48 m/s)^2/5.7 m ≈ 2.14 m/s².

a_perpendicular = dv_perpendicular/dt,  v_perpendicular is constant velocity vector perpendicular to radius vector. As a_perpendicular = 0. Therefore,  perpendicular component of dp/dt is zero.

(c) The net force acting on the child is given by F = dp/dt. From part (a), we know that parallel component of dp/dt is approximately -20.7 kg m/s. From part (b), we know that the perpendicular component of dp/dt is zero. Therefore, the net force acting on the child is approximately -20.7 kg m/s in the direction opposite to the direction of the velocity vector.

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The equation of the normal line is y = - 2x + 3

We know that,

The equation of normal line given of the curve is given by

( y - \(y_{1}\) ) = m ( x - \(x_{1}\) )

Given that,

Equation of curve is y = \(\sqrt{x}\)

Equation of the line parallel to the normal line of curve is 2x + y = 1

The slope of normal is same as that of the line parallel to it. So,

2x + y = 1

y = - 2x + 1

On differentiating both sides by x,

dy / dx = - 2

which is the slope of normal line

To find slope of the curve,

y = \(\sqrt{x}\)

y = \(x^{1/2}\)

dy / dx = 1/2 x

which is the slope of the curve.

Since the curve and its normal line is perpendicular,

\(m_{1} m_{2}\) = -1

-2 * 1/2 x = -1

x = 1

At x = 1,

y = \(\sqrt{1}\) = 1

The point is ( 1 , 1 )

The equation of normal line given of the curve is

( y - \(y_{1}\) ) = m ( x - \(x_{1}\) )

y - 1 = - 2 ( x - 1 )

y = - 2x + 3

Therefore, The equation of the normal line is y = - 2x + 3

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Answer:

the first one i think

Explanation:

Answer:

So the people in the ring don't get hurt or break anything on impact once they hit the floor

Answer:

C

Explanation:

Z = 84, A = 218

trust, got a 100 :)

Answer:

Explanation:

Volume = Length x width x height

Multiply the length, width and, height to get the volume of the question.

Linguists call small units of sound that carry meaning on their own "morphemes".

Actually, phonemes are the smallest units of sound in a language that can distinguish meaning. They are abstract units of sound that differentiate one word from another word in a language. For example, in English, the sounds /p/ and /b/ are phonemes because they distinguish words like "pat" and "bat".

Morphemes, on the other hand, are the smallest units of language that carry meaning. They can be made up of one or more phonemes. For example, the word "cats" has two morphemes: "cat" and "-s" (which indicates plurality), and each of these morphemes is made up of phonemes.

So while phonemes are important in distinguishing meaning, morphemes are the smallest units of language that carry meaning on their own.

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Answer:

When the compass is placed below the wire, and the electric current switched on, the needle deflects in the opposite direction. If an electric current is passed through a long coil of wire (a solenoid ) a magnetic field is produced which is the same shape as that of a bar magnet.

Explanation:

Answer:

a changing electric field creates a magnetic field.

Explanation:

if you have a circuit and you send AC current through (AC = Alternating current) so that the electrons move back and forth, they will create a changing electric field.

This produces a magnetic field (because that's what the universe does).

In physics and engineering, a free frame diagram (FBD; also referred to as a force diagram) is a graphical instance used to visualize the applied forces, moments, and ensuing reactions on a frame in a given situation.

A free-body diagram is a sketch of an item of interest with all the surrounding items stripped away and all of the forces acting on the frame shown. The drawing of an unfastened-body diagram is a critical step in the solving of mechanics issues because it helps to visualize all the forces appearing on an unmarried object.

A free-body diagram is a graphic, dematerialized, symbolic representation of the body (structure, element, or segment of an element) wherein all connecting "pieces" have been removed. An FBD is a convenient method to model the structure, structural detail, or phase that is under scrutiny.

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13.The color with the longest wavelength is option A. Red.

14.The sky appears blue due to option D. Scattering of light.

Red light has a longer wavelength compared to yellow and blue light.The color that has the longest wavelength is red. The color of the sky appears blue due to scattering of light. The distance between one peak and the next in a series of waves, particularly electromagnetic waves traveling through space or along a wire is referred to as wavelength.

The wavelength of light, for example, determines its color. Red light has the longest wavelength, followed by orange, yellow, green, blue, and purple, with violet light having the shortest wavelength. When light is reflected off a surface or passes through a medium, it can be deflected in various directions, a phenomenon known as scattering of light.

The Earth's atmosphere scatters sunlight in all directions, but the shorter blue wavelengths are scattered more than the longer wavelengths. As a result, we perceive the sky as blue during the day.  The light becomes scattered when it interacts with particles in the atmosphere, causing the sky to appear blue during the day and red during sunset or sunrise. The scattering of light is the process that causes the sky to appear blue.

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Answer:

B: 28m/s

Explanation:

Use the speed formula

Speed =distance / time

Answer:

\(\boxed {\boxed {\sf B. \ 28 \ m/s}}\)

Explanation:

If we want to know how fast the cheetah is running, we need to calculate its speed. This is the rate at which an object moves and the formula is distance divided by time.

\(s=\frac{d}{t}\)

The cheetah ran 112 meters in 4 seconds.

Substitute the values into the formula.

\(s=\frac{112 \ m}{ 4\ s}\)

Divide.

\(s= 28 \ m/s\)

The cheetah's speed is 28 meters per second and choice B is correct.

Answer:

traping

Explanation:

Answer:

B. Trapping

Explanation:

The force required to move the 90 Kg object at a constant speed of 8.10 m/s is 138.94 N

The force required to keep an object moving in a circle is called Centripetal force. This is defined according to the following equation:

F = mv²/r

With the above formula, we can obtain the force required to move the 90 Kg object. Details below:

F = mv²/r

F = (90 × 8.10²) / 42.5

F = (90 × 65.1) / 42.5

F = 5904.9 / 42.5

F = 138.94 N

Thus, the force required is 138.94 N

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Answers to part A and B are as follows:

A: At  0.352941 m/s Chloe travels toward the spaceship.

B: The time it takes Chloe to reach the ship is 42.5 s.

A) After Chloe tosses the camera, the momentum of the system (Chloe + Camera) must be conserved. The momentum of Chloe before she tosses the camera is:

p_before = m_chloe * v_before = 68 kg * 0 m/s = 0 kg m/s

The momentum of Chloe and the camera after she tosses the camera is:

p_after = m_chloe * v_after + m_camera * v_camera = 68 kg * v_after + 2.0 kg * 12 m/s

Since momentum must be conserved, we have:

p_before = p_after

0 = 68 kg * v_after + 2.0 kg * 12 m/s

Solving for v_after:

v_after = -2.0 kg * 12 m/s / 68 kg = -0.352941 m/s

B) To find the time it takes Chloe to reach the ship, we can use the kinematic equation:

d = v_0 * t + 0.5 * a * t^2

where d is the distance from Chloe to the ship, v_0 is her initial velocity, t is time, and a is acceleration due to gravity.

We know that the distance from Chloe to the ship is 15 m, her initial velocity is -0.352941 m/s, and acceleration due to gravity is 9.8 m/s^2.

Substituting these values into the kinematic equation:

15 = -0.352941 * t + 0.5 * 9.8 * t^2

Solving for t using the quadratic formula:

t = (-0.352941 +/- sqrt(0.352941^2 - 4 * 0.5 * 9.8 * 15)) / (2 * 0.5 * 9.8)

The time it takes Chloe to reach the ship is the positive value of t:

t = (0.352941 + sqrt(0.352941^2 + 4 * 0.5 * 9.8 * 15)) / (2 * 0.5 * 9.8)

t = 42.5 s

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Answer:

:c: H* : A: :C: H* :A: :C: H* :A:

Answer:

4a. –2.5 m/s²

4b. 375 m

5. 7.5 s

Explanation:

4. The following data were obtained from the question:

Initial velocity (u) = 50 m/s

Final velocity (v) = 25 m/s

Time (t) = 10 s

Acceleration (a) =?

Displacement (s) =?

4a. Determination of the acceleration of the car.

Initial velocity (u) = 50 m/s

Final velocity (v) = 25 m/s

Time (t) = 10 s

Acceleration (a) =?

a = (v – u) /t

a = (25 – 50)/10

a = –2.5 m/s²

The negative sign indicate that the car is decelerating.

4b. Determination of the displacement of the car.

Initial velocity (u) = 50 m/s

Final velocity (v) = 25 m/s

Time (t) = 10 s

Displacement (s) =?

s = (v + u)t / 2

s = (25 + 50) × 10 / 2

s = (75 × 10) / 2

s = 750 / 2

s = 375 m

Thus, the displacement of the car is 375 m

5. The following data were obtained from the question:

Initial velocity (u) = 30 m/s

Final velocity (v) = 0 m/s

Acceleration (a) = – 4m/s²

Time (t) =?

The time taken for the car to stop can be obtained as follow:

v = u + at

0 = 30 + (–4 × t)

O = 30 – 4t

Collect like terms

0 – 30 = –4t

–30 = –4t

Divide both side by –4

t = –30 / –4

t = 7.5 s

Thus, it will take 7.5 s for the car to completely stop.

The expressions for the magnitude of the electrical field strength inside the cylinder, r is,

E = λ/2ε₀πr

What is electric field?

The electric field is the field, which is surrounded by the electrical charged. the electrical field is the electric force per unit charge. Here an extended , thin straight wire with linear charge density λ runs down the middle of a thin, hollow metal cylinder of radius R.

As the electric flux is the product of electric flux and the area of the cylinder. Thus,

                    φ = E(2πrL)   .................1

This electric flux also can be given as,

                            φ = λL/ε₀ ......................2

Where, ( λ) is that the linear charge density. On comparing both the equation, we get,

Ε(2πrL) = λL/ε₀

E = λ/ 2ε₀πr

The cylinder features a net linear charge density 2λ where λ is positive. Thus for this hollow cylinder, the electrical filed can be given as,

                   E = λ/2ε₀πr

For charge inside the cylinder, where r < R, are often expressed with the following expression,

                           E = λ/2ε₀πr

The charge density is that the measure of electric charge per unit area of a surface, or per unit volume of a body or field. The charge density tells us what proportion charge is stored in a particular field. Charge density are often determined in terms of volume, area, or length.

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Answer:

Atmospheric pressure is commonly measured with a barometer. In a barometer, a column of mercury in a glass tube rises or falls as the weight of the atmosphere changes. Meteorologists describe the atmospheric pressure by how high the mercury rises.

Explanation:

Answer:

Atmospheric pressure is commonly measured with a barometer. In a barometer, a column of mercury in a glass tube rises or falls as the weight of the atmosphere changes. Meteorologists describe the atmospheric pressure by how high the mercury rises.

Atmospheric Pressure

The air around you has weight, and it presses against everything it touches. That pressure is called atmospheric pressure, or air pressure.

GRADES

6 - 12+

SUBJECTS

Earth Science, Meteorology, Geography, Physical Geography, Physics

\(4 \times {10}^{ - 5} \\ = 4 \times 0.00001 \\ = 0.00004\)

This is ur answer.

Answer:

Volt metre (Vm)

or Newton/Coulomb x (Metre)^2       (N/C x m^2)

Answer: 7.25 * 10^5

Explanation:

1. The equation simplifies to (7*10 + 2.5) 10000.

2. Simplify in the parenthesis. 72.5 * 10000.

3. In scientific notation, the answer is 7.25* 10^5.

Answer:

It would lift the object to the same height than before you move it 3 centimeters to the left. You see, the height doesn't change if you move the inclined plane horizontally, because height is a vertical variable.

Therefore, if the inclined plane has a height of 1 meters, then the object will be lifted 1 meters up, no matter if you move the inclined plane 50 meters horizontally, it won't change its height.

the ratio of the mass of the A string to that of the E string is  0.653.

the equation for the frequency of a vibrating string is given as :

f = (1/2L) * √(T/μ)

f_ = frequency of the string,

L=  length of the string,

T= tension in the string, and

μ=  linear mass density of the string

We know that  the strings are all the same length and under essentially the same tension,

f1/√μ1 = f2/√μ2

f1=  frequency of the A string,

μ1 = linear mass density of the A string,

f2=  frequency of the E string, and

μ2=  linear mass density of the E string.

440/√(m1/L) = 639/√(m2/L)

440/√m1 = 639/√m2

(440 * √m2)² = (639 * √m1)²

m2 = (639/440)² * m1

In conclusion, we have that  the ratio of the mass of the A string to that of the E string is:

m1/m2 = 1/[(639/440)²]

m1/m =  0.653

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The ground-state energy of the electron in the given rectangular box is approximately 1.46 eV.

The ground-state energy of an electron in a three-dimensional rectangular box is given by the equation:

E = (π²ħ²)/(2m)(1/Lx² + 1/Ly² + 1/Lz²)

where ħ is the reduced Planck constant, m is the mass of the electron, and Lx, Ly, and Lz are the dimensions of the box in the x, y, and z directions, respectively.

Substituting the given values, we get:

E = (π² x 1.054 x 10^-34 J s / 2 x 9.109 x 10^-31 kg) x (1 / (898 x 10^-12 m)² + 1 / (1680 x 10^-12 m)² + 1 / (422 x 10^-12 m)²)

E ≈ 1.46 eV

Therefore, the ground-state energy of the electron in the given rectangular box is approximately 1.46 eV.

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