when separated by electrophoresis normal hemoglobin migrates the furthest from the origin then

Mauna Loa, a volcano in Hawaii, is an excellent example of a shield volcano.

The correct option is a shield volcano.

A shield volcano is a sort of volcano characterized by a broad, flat shape with low gradients.

Shield volcanoes are formed by low-viscosity basaltic lava, which forms a shield-like structure.

This kind of volcano can grow to a height of many kilometers and extend for tens of kilometers.

The Hawaiian Islands are a well-known location for shield volcanoes.

Kilauea and Mauna Loa, for example, are shield volcanoes that have created the Big Island of Hawaii.

On the other hand, the Piton de la Fournaise in Reunion Island and Mount Etna in Italy are well-known shield volcanoes outside of Hawaii.

Know more about a volcano here:

https://brainly.com/question/25121802

#SPJ11

Answer:

9882.516J

Explanation:

49kg*9.8m/s2*2.1m=9882.516 J

If not held together by electromagnetic forces, it would take approximately 2.52 x 10¹³ seconds for a person to grow 3 centimeters because of the expansion of the universe.

Hubble's Law describes the expansion of the universe, which states that the further away a galaxy is from us, the faster it is receding from us. The Hubble "constant" (H) is the proportionality factor between the recessional velocity of a galaxy and its distance from us.

Assuming a person's height is 170 cm and H is approximately 70 km/s/Mpc (the latest estimated value), we can calculate the velocity between a person's head and feet due to the expansion of the universe using v=Hd, where d is the person's height.

Therefore, v = 70 km/s/Mpc x 1.7 m =1.19 x 10⁻¹⁸ km/s.

We can convert this velocity to centimeters per second by multiplying it by 10⁵, giving us 1.19 x 10⁻¹³ cm/s. To grow 3 centimeters, a person would need to travel at this velocity for 3/1.19 x 10⁻¹³ = 2.52 x 10¹³ seconds.

To know more about velocity, refer here:

https://brainly.com/question/31479424#

#SPJ11

Answer:

The electric field strength is dependent upon the quantity of charge on the source charge (Q) and the distance of separation (d) from the source charge.

If the separation of the plates is reduced to d/2, the magnitude of the electric field halfway between the plates will be twice as strong as the original electric field and will be equal to 2E.

The electric field between two parallel plates that are a distance d apart and have a charge Q on one plate and a charge -Q on the other is given by: E = (1/2ε0)(Q/d)Where ε0 is the permittivity of free space. If the separation between the plates is reduced to d/2, the charge Q remains the same, and therefore the electric field between the plates will be twice as strong. Thus, the magnitude of the electric field halfway between the plates will be 2E.

According to Coulomb's Law, two charges Q and -Q, separated by a distance d, create an electric field between them. If the charges are distributed uniformly on two large, flat, horizontally oriented insulating plates, the electric field is perpendicular to the plates and is equal to the electric field produced by the charges at any point between the plates.The electric field between two parallel plates that are a distance d apart and have a charge Q on one plate and a charge -Q on the other is given by: E = (1/2ε0)(Q/d)Where ε0 is the permittivity of free space. Thus, if the separation of the plates is reduced to d/2, the electric field will become E' = (1/2ε0)(Q/(d/2)) = (1/2ε0)(2Q/d) = E + E where E is the electric field when the separation between the plates is d/2. Therefore, the magnitude of the electric field halfway between the plates when the separation between the plates is d/2 is 2E.

The electric field between two parallel plates that are a distance d apart and have a charge Q on one plate and a charge -Q on the other is given by E = (1/2ε0)(Q/d). If the separation of the plates is reduced to d/2, the magnitude of the electric field halfway between the plates will be twice as strong as the original electric field and will be equal to 2E.

To know more about Coulomb's Law visit

brainly.com/question/506926

#SPJ11

The highly eccentric orbits of comets in our solar system are primarily influenced by their origin in distant regions, gravitational interactions with planets, and the outgassing effects that occur as they approach the Sun.

In contrast, Earth follows a more circular orbit due to its proximity to the Sun and its relatively stable gravitational environment, which is less affected by significant perturbations from nearby objects. The eccentricity of an orbit refers to how elongated or flattened the shape of the orbit is. A perfectly circular orbit has an eccentricity of 0, while higher eccentricities indicate more elongated or elliptical orbits.

Comets in our solar system often have highly eccentric orbits compared to the relatively circular orbit of Earth. There are a few reasons for this difference:

1. Origin: Comets are believed to originate from two main regions in our solar system: the Kuiper Belt and the Oort Cloud. These regions are located far beyond the orbit of Neptune. When comets are perturbed or influenced by the gravitational forces of nearby objects, such as planets or passing stars, their orbits can become highly elliptical. These gravitational interactions can result in comets being flung into eccentric paths that bring them closer to the Sun before swinging them back into the outer regions of the solar system.

2. Gravitational Interactions: Planets, such as Jupiter and Saturn, have significant gravitational influence due to their large masses. These giant planets can perturb the orbits of comets when they come close. The gravitational interactions with these massive bodies can alter the shape and eccentricity of a comet's orbit. As comets approach these planets, they can experience gravitational slingshot effects, either increasing or decreasing their eccentricity depending on the specific interaction.

3. Outgassing and Volatile Substances: Comets are composed of ice, dust, and other volatile substances. As a comet approaches the Sun, the heat causes the ice to sublimate, releasing gas and dust particles. The outgassing process generates a "tail" that can push against the comet, potentially altering its orbit. This outgassing effect can contribute to the variations in a comet's eccentricity over time as it repeatedly approaches and recedes from the Sun.

To know more about solar system, please click on:

https://brainly.com/question/18365761

#SPJ11

Newton's second equation of motion, which states that the net force acting on an item is equal to its mass times its acceleration, can be used to compare the acceleration of the two crates.

The only forces acting on both crates are the applied force, f, and the gravitational force, mg, where m is the mass of each container and g is the acceleration brought on by gravity. This is because both crates are resting on a frictionless surface.Crate A will suffer a greater net force and, thus, a greater acceleration than Crate B since the applied force, f, is being applied just to Crate A. Due to its greater mass, crate B's acceleration will be less. The following formula can be used to determine the two crates' acceleration: Where m is the mass of each container, an is equal to f / m.Crate A will move more quickly and Crate B will trail behind because Crate A's acceleration is larger than Crate B's acceleration.

learn more about gravity here:

brainly.com/question/14874038

#SPJ4

The magnitude of the maximum acceleration is 100 m/s². We can find the value of  acceleration use the harmonic oscillator formula.

The equation for the position of a simple harmonic oscillator is given by:

x(t) = A cos(ωt + φ)

where A is the amplitude, ω is the angular frequency, and φ is the phase angle.

Taking the second derivative of x(t) with respect to time gives the acceleration:

a(t) = -Aω² sin(ωt + φ)

For the given equation, x(t) = 0.5 cos(20t), we can see that the amplitude A = 0.5, and the angular frequency ω = 20 rad/s.

Therefore, the maximum acceleration is:

a_max = Aω² = (0.5)(20)² = 100 m/s².

You can learn more about The Acceleration in the link below:

https://brainly.com/question/12550364

#SPJ11

If a 1300 kg truck starts at rest and speeds up from 0 to 20 m/s in 4.1 seconds, the power of the truck's engine will be 6.34 x \(10^{4}\).

We have,

Initial velocity = 0

Final vel0city = 20 m/s

Time taken = 4.1s

Power can be calculated as change in kinetic energy per unit time.

Since initial velocity is zero, change in kinetic energy will be equal to final kinetic energy.

Therefore, power = 1/2 mv²/t = 1/2 x 1300 x 20 x 20/ 4.1 = 6.34 x \(10^{4}\) W

Hence, the power of the truck's engine = 6.34 x \(10^{4}\) W

To learn more about power of engine visit:

brainly.com/question/4047180

#SPJ1

A resume is usually read for less than C. 30 seconds by an employer.

A resume is a document that presents your educational qualifications, experiences, and achievements that have taken place throughout your academic career and professional life. This document is crucial in a job application process, and it plays a key role in determining whether an employer is interested in interviewing you or not. Thus, it is necessary to write a well-written and a concise resume that catches the employer's attention in less than 30 seconds. This is because most employers go through many job applications and they do not have much time to read every resume thoroughly.

Therefore, it is essential to organize and format the resume in such a way that the key information and skills stand out. In addition, it is necessary to customize the resume to fit the job requirements of each job application, this can be done by researching the company and the job position to determine what skills and qualifications the employer is looking for. In conclusion, it is crucial to ensure that the resume is well-written, organized, and customized to fit the employer's requirements. So the correct answer is C. 30.

Learn more about employer at:

https://brainly.com/question/31920624

#SPJ11

6000×60 (1 minute)=360000 (the power of the motor)

To find the kilowatt-hours your motor consumes, multiply the kilowatt use by the number of hours.

Answer:

If a ball dropped from a tower reaches the ground after 3.5 seconds, the height of the tower is 60.025 m.

Explanation:

How to calculate the height of the tower?

       s = ut + 1/2 at²

       where s = displacement,

       u = initial velocity

       t = time traveled

       a = acceleration

Solution :

It is given that :

Putting the values in the equation,

s = ut + + 1/2 at²

  = 0 + 1/2 x (-9.8) x 3.5² m

  = - 60.025 m.  

The negative sign signifies that the displacement has occurred in the downward direction, along the direction of g.

Thus the height of the tower is 60.025 m.

To know more about displacement under gravity, visit:

https://brainly.com/question/18829004

Answer:

0.84m

Explanation:

0.51+0.43=0.93

πr can be 22/7 or 3.14

radius is 2x2= 4

3.14 divide0.93divide 4

=0.84m/s

Answer:

0.605 m (approx.)

Explanation:

We know, given the radius and the circular velocity we can yield the centripetal acceleration using this equation,

\(a = \frac{v^2}{r}\)

From this equation, we can solve for \($r$\) like this,

\(r = \frac{v^2}{a}\\r = \frac{0.51^2}{0.43} m \\ = 0.605 m\)

A rock climber stands on the top of a 53 m high cliff overhanging a pool of water, so for 3.1 seconds, after which the second stone hit the water.

The overall distance the object covers in a given amount of time is its average speed. The scalar quantity represents the average speed. It does not have direction; it is represented by magnitude.

Average Speed= \(Total\ Distance/ Total\ time\)

According to the question, the given values are :

v₁ = 1.5 m/s

y₂ = 52 m

y₁ = 0 m

Acceleration, a = 9.8 m/s²

Use Formula :

y₂ = y₁ + v₁t + 0.5 at²

52 = 0 + 1.5t + 0.5 (9.8)t²

4.9 t² + 1.5 t - 52 = 0

\(t=-b\frac{+}\ \sqrt{b^2-4ac}/2a\)

t = -1.5 + \(\sqrt{2.25+1019.2}\)/9.8

t = (-1.5 + 31.9)/9.8

t = 3.10 seconds.

Hence, the time period will be 3.10 seconds.

To get more information about Average Speed :

https://brainly.com/question/9834403

#SPJ1

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

To know more about power station:

https://brainly.com/question/32772374

#SPJ4

Answer:

Glucose diffuse from the blood plasma, across the capillary walls to the tissue fluid, and then to the cell.

Glucose diffuse from the blood plasma, across the capillary walls to the tissue fluid, and then to the cell. The waste product urea diffuse from the cells of the liver to the tissue fluid, and then across the capillary walls into the blood plasma.

Answer:

10 N

Explanation:

Given that,

A man pushes against a tree with a force of 10 newtons.

We need to find the amount of force exerted by the tree on the man.

The force exerted by the tree on the man will be equal to the force that the man exert on the tree as per Newton's third law of motion.

It means the tree exert 10 N force on the man. Hence, the correct option is (c) i.e. 10 N.

Answer:

A) \(\frac{P}{p} + \frac{1}{2} v^2 + gh = k\\\)

B )  53.9 kN/m^2

Explanation:

a) Bernoulli's equation and continuity equation  for a pipe flow

\(\frac{P}{p} + \frac{1}{2} v^2 + gh = k\)

\(\frac{P}{p}\)  = pressure head

\(\frac{1}{2}v^2\) = velocity head

gh = potential head

k = constant

p = density

b) determine the air pressure that must be maintained

Given data :

Discharge rate( R ) = 20 liters/sec ≈ 0.02 m^3

Bore diameter ( d ) = 0.06 m

first we calculate the velocity in the 6 cm  bore

v = \(\frac{R }{\frac{\pi }{4} *d^2}\)   ------- (2)

R = 0.02

d = 0.06

insert the given values into equation 2

V = 7.07 m/s

next we apply the Bernoulli's equation by rewriting it as follows

\(\frac{P}{pg} + \frac{1}{2g} v^2 + h = k\)

\(\frac{1}{2g}v^2\) ( velocity head ) = \(\frac{7.07^2}{2*9.81}\)  = 2.55

next  we will apply the use of energy conservation law on the surface of water  in tank and that on the roof :

Note : H1(frictional head loss ) = 45cm = 0.45 m , g = 9.81

applying the energy conservation  law

\(\frac{P1}{pg} + \frac{1}{2g} v_{1} ^2 + h1 =\) \(\frac{P2}{pg} + \frac{1}{2g} v_{2} ^2 + h2\)

\(\frac{P1}{pg}\)  = 0 + 2.55  + 2.5 + 0.45

therefore ; P1 = 9.81 * 5.55 = 53.9 kN/m^2

Objects 1 and 2 attract each other with an electrostatic force of 2 units. If the charge of Object 1 is multiplied by 3, then the new electrostatic force will be 6 units.

F1 = k * (q1 * q2) / \(r^{2}\)

2 = k * (q1 * q2) / \(r^{2}\)

if charge of object 1 is multiplied by 3

F2 = k * (3 q1 * q2 )/  \(r^{2}\)  

F2/3      =  k * (q1 * q2) / \(r^{2}\)

since ,  k * (q1 * q2) / \(r^{2}\) = 2 unit

substituting the value , we get

F2/3 = 2

F2 = 6 units

To learn more about electrostatic force here :

https://brainly.com/question/9774180

#SPJ1

Here are the answers to the questions:1. Three main orbital changes that the earth undergoes and their time periods are:A. Precession- every 26,000 years B. Obliquity- every 41,000 years C. Eccentricity- every 100,000 yearsThese changes in the earth's orbit, together, have an impact on the amount of solar radiation that reaches the Earth's surface, which then affects climate change. Three cyclical orbital changes and their times associated with Milankovitch are:A. Eccentricity - every 100,000 yearsB. Obliquity - every 41,000 yearsC. Precession - every 26,000 years2. All EMR in order of wavelength are:- Gamma rays- X-rays- Ultraviolet radiation- Visible light- Infrared radiation- Microwave- Radio wavesForms of EMR from the sun that are reaching right now are UV radiation, visible light, and infrared radiation.

The number of forms of EMR reaching the moon right now is two, UV radiation, and visible light.The ozone layer is present in the stratosphere and is formed through a series of complex chemical reactions. The primary function of the ozone layer is to protect the earth from the harmful effects of UV radiation by absorbing it. The balance of EMR plays a critical role in the greenhouse effect. As the amount of greenhouse gases increases, the amount of energy that is absorbed by the Earth's surface also increases. Carbon dioxide and other greenhouse gases can absorb and emit infrared radiation, which plays a crucial role in climate change.3. The four forms of heat transfer to and on planet earth are:- Conduction- Convection- Radiation- AdvectionThese four forms of heat transfer are responsible for weather on planet Earth.

For example, when the sun heats the ground, it results in conduction, which then results in convection as the air heats up and rises. This can lead to cloud formation and precipitation.4. The time it takes for EMR from the University of Delaware to reach:A. Moon - About 1.28 secondsB. Jupiter - About 33.75 minutesC. Closest star (not the sun) - About 4.37 yearsD. Your mother - This question is not clear, please provide more context.

To know more about Eccentricity visit:-

https://brainly.com/question/31912136

#SPJ11

A distracted driver may not perceive important traffic events such as stop signs, red lights, pedestrians crossing the street, other vehicles changing lanes or braking suddenly, and road hazards. Their attention is diverted away from the road, which can lead to delayed or completely missed reactions to potentially dangerous situations. This can increase the risk of accidents and harm to themselves and others on the road.

For more question like distracted driver visit the link below:

https://brainly.com/question/15455496

#SPJ11

Answer:

Mac’s Speed = 2.5 m/s

Tosh’s Speed = 4 m/s

Tosh moves 1.5 m/s faster than Mac.

Explanation:

Tosh starts from an initial position of 12m and in a span of 3 seconds, (1.00 seconds to 4.00 seconds) he moves 12 meters.

So his speed is distance / time

s = 12 / 3

s = 4 m/s

Mac starts from an initial position of 2m and in a span of 4 seconds, he traveled 10m (2.00m to 12.00m).

Speed = Distance / time

s = 10 / 4

s = 2.5 m/s

The total magnification will be 200x.

It quantifies the comparison of the image's size to that of the object's size. In terms of how big or little the picture is produced, it informs us about the image. The height of the picture divided by the height of the object is known as magnification. m=hiho.

Objective lens - An essential component of the microscope's optics is the objective lens. The sample, specimen, or item being examined is situated close to the microscope's objective. It plays a crucial part in imaging since it creates the initial magnified picture of the sample.

Ocular lens - The component of the microscope known as the eyepiece, or ocular lens, is responsible for enlarging the picture created by the objective so that it can be viewed by the human eye.

20x objective lens was used by specimen

10x ocular lens was also used by him.

we have to find the total magnification.

For calculating the total magnification we 'll simply do multiplication

Total Magnification = 20 × 10x

Total Magnification = 200x

So , the total magnification will be 200x .

To learn more about the Magnification refer to:

brainly.com/question/21370207

#SPJ4

Given what we know, we can confirm that the tensional force of a system can in theory be changed without diminishing its force through the use of an ideal pulley.

Therefore, we can confirm that the only known way to change the direction of a force without diminishing its value would be through the use of a frictionless and massless pulley system otherwise known as an ideal pulley.

To learn more about Friction visit:

https://brainly.com/question/13357196?referrer=searchResults

Answer:

a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.

b) Liquid P - \(Q = 3840\,J\), Liquid Q - \(Q = 5500\,J\), Liquid R - \(Q = 7800\,J\), Liquid S - \(Q = 2856\,J\)

Explanation:

a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.

b) Let suppose that heat transfer rates between liquids and surroundings are stable. The quantity of the heat released is determined by the following expression:

\(Q = m\cdot c\cdot (T_{r} - T_{f})\) (1)

Where:

\(m\) - Mass of the liquid, in kilograms.

\(c\) - Specific heat capacity, in joules per kilogram-degree Celsius.

\(T_{r}\) - Initial temperature of the sample, in degrees Celsius.

\(T_{f}\) - Freezing point, in degrees Celsius.

Liquid P (\(m = 1\,kg\), \(c = 160\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 6\,^{\circ}C\))

\(Q = (1\,kg)\cdot \left(160\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 6\,^{\circ}C)\)

\(Q = 3840\,J\)

Liquid Q (\(m = 1\,kg\), \(c = 220\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 5\,^{\circ}C\))

\(Q = (1\,kg)\cdot \left(220\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 5\,^{\circ}C)\)

\(Q = 5500\,J\)

Liquid R (\(m = 1\,kg\), \(c = 300\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 4\,^{\circ}C\))

\(Q = (1\,kg)\cdot \left(300\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 4\,^{\circ}C)\)

\(Q = 7800\,J\)

Liquid S (\(m = 1\,kg\), \(c = 102\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 2\,^{\circ}C\))

\(Q = (1\,kg)\cdot \left(102\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 2\,^{\circ}C)\)

\(Q = 2856\,J\)

Answer:

3 × 10 to the power minus 6 milliseconds

When we convert 3 x 10⁻⁹ s into milliseconds it would be 3 x 10⁻⁶milliseconds

In positional notation, significant figures refer to the digits in a number that is trustworthy and required to denote the amount of something, also known as the significant digits, precision, or resolution.

If a number describing the result of a measurement (such as length, pressure, volume, or mass) includes more digits than the number of digits permitted by the measurement resolution, only the digits allowed by the measurement resolution can be significant figures.

As given in the problem we have to convert 3 x 10⁻⁹ s into milliseconds

1 second = 1×10³ milliseconds

3 x 10⁻⁹ seconds =  (3 x 10⁻⁹)  ×  (1×10³ )

                            = 3 x 10⁻⁶milliseconds

Thus, 3 x 10⁻⁹ s converted into milliseconds it would be 3 x 10⁻⁶ milliseconds

Learn more about significant figures here

brainly.com/question/14359464

#SPJ2

The ka of unknown weak acid ha, at 25°c, if the pH of a 2.5 × 10-2 m solution of the acid was measured and found to be 4.94 is 52.9 * \(10^{-10}\)

pH = 4.94

[ H+ ] = \(10^{-4.94}\)

[ H+ ] = 1.15 * \(10^{-5}\) M

HA ⇄ H+ + A-

H+ = A- = 1.15 * \(10^{-5}\) M

Since 0.1 >> 1.15 * \(10^{-5}\),

[ HA ] = 0.025 M

Ka = Acid dissociation constant

Ka = [ H+ ] [ A- ] / [ HA ]

Ka = [ H+ ]² / [ HA ]

Ka = ( 1.15 * \(10^{-5}\) )² / 0.025

Ka = 52.9 * \(10^{-10}\)

Therefore, the Ka of the weak unknown acid is 52.9 * \(10^{-10}\)

To know more about Acid dissociation constant

https://brainly.com/question/4363472

#SPJ4

If Bill is traveling at v mi/h, Daemon's speed in mi/h if he was traveling 30mi/h faster can be represented as (v + 30) mi/h. This is because if Bill is traveling at v mi/h and Daemon is traveling 30 mi/h faster than him, then Daemon's speed will be v + 30 mi/h.

How to represent Daemon's speed in mi/h if he was traveling 30mi/h faster?

If Bill is traveling at v mi/h, then his speed can be represented as v mi/h. Now, if Daemon is traveling 30 mi/h faster than Bill, then we add 30 to Bill's speed and get the speed at which Daemon is traveling. Therefore, the speed at which Daemon is traveling can be represented as (v + 30) mi/h.

Learn more about speed from :

https://brainly.com/question/13943409

#SPJ11

Answer:

W'=125.44 N

Explanation:

The weight of a person on the surface of Earth is 784 N

Weight is given by :

W = mg

m is mass of the person and g is acceleration due to gravity on the surface of Earth (10 m/s²)

\(m=\dfrac{W}{g}\\\\m=\dfrac{784}{10}\\\\m=78.4\ kg\)

The acceleration due to gravity on the surface of Moon, g' = 1.6 m/s²

Weight of the person on the moon is :

W'=mg'

\(W'=78.4\ kg\times 1.6\ m/s^2\\\\W'=125.44\ N\)

Hence, the person would weigh 125.44 N on the Moon.

Answer:

129 N

Explanation:

The answer you're looking for is 129 N

Weight on Earth, divide by Earth's gravity (≈9.80), multiplied by the gravity of the Moon (≈1.60).