when seventeen is reduced by two-thirds of a number, the result is 11

Note that as x gets larger, y gets smaller, but the product xy remains constant at 192.

In mathematics, a function is a relationship between two sets, called the domain and the range, such that each element of the domain corresponds to exactly one element of the range. A function takes an input value (or values) and produces an output value (or values) according to a specific rule or formula. The input values are the domain of the function, and the output values are the range of the function. Functions can be represented using equations, graphs, tables, or verbal descriptions. They are used to model relationships between variables in various fields of mathematics, science, engineering, economics, and many other areas.

Here,

If x and y vary inversely, this means that their product is a constant. We can use this fact to find the constant of proportionality k as follows:

k = xy

If we know that y is 24 when x is 8, we can substitute these values into the equation above to solve for k:

k = xy

= 8(24)

= 192

Now we can use this value of k to write the inverse variation function:

xy = 192

or

y = 192/x

To sketch a graph of this function for x > 0, we can plot a few points and connect them with a smooth curve. Here are some points we can use:

(x, y)

(1, 192)

(2, 96)

(4, 48)

(8, 24)

(16, 12)

(24, 8)

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Answer:

4.5:87

Step-by-step explanation:

First, we can set up an equation because 1.5:29 is equal to 4.5:x

\(\frac{1.5}{29} = \frac{4.5}{x}\)

Now, we can solve for x by:

1.5x = 4.5 * 29

1.5x = 130.5

x = 87

The ratio will be 4.5:87

ANSWER:

x = 10

EXPLANATION:

Given:

Recall that the Midpoint Theorem states that the line segment joining the midpoints of any two sides of a triangle is parallel to the third side and equal to half of the third side.

We can go ahead and solve for x as seen below;

Therefore, the value of x is 10

The cost of each pound of grass seed is $6.

A graph of the solution for the cost of each pound of grass seed is shown below.

In order to determine the cost of each pound of grass seed, we would assign a variable to the cost of each pound of grass seed and then translate the word problem into an algebraic linear equation.

Let the variable x represent the cost of each pound of grass seed.

Since Lori bought 3.6 pounds of grass seed and she was charged $22.90, including a tax of $1.30, an algebraic linear equation that best represent this situation is given by;

3.6x + 1.30 = 22.90

3.6x = 22.90 - 1.30

3.6x = 21.60

x = 21.60/3.6

x = $6.

In conclusion, we would sue an online graphing calculator to plot the solution for the cost of each pound of grass seed as shown in the image attached below.

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The method that determines the volume of the prism is simply multiply the area of the base by the height, and the result is 12.5 cm³. (option-a)

To determine the volume of the prism shown in the diagram, we need to multiply the area of the base by the height.

The base of the prism is a rectangle with dimensions 5 cm by 2 cm. Therefore, the area of the base is:

A = length x width = 5 cm x 2 cm = 10 cm²

The height of the prism is 2-¹ cm, which is equivalent to 5/4 cm.

Therefore, the volume of the prism is:

V = A x h = 10 cm² x 5/4 cm = 12.5 cm³

The expressions involving unit cubes and one-quarter cubes are not relevant to this problem and do not provide a method for finding the volume of the prism.

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Answer:

no

Step-by-step explanation:

your beatiful just the way you are

dont change anything about yourself

Answer:

When it's negative when it goes to the other side it becomes a positive.....

Y=(x-4)(x-1)

Make y 0 when your calculating for x

Make x 0 when your calculating for y

0=(x-4)(x-1)

Therefore x=4 or x=1

The radius of curvature of the curve \(a^{2y\)=x³-a³ at the point where the curve intersects the x-axis is 27\(a^{\frac{3}{2}\).

To find the radius of curvature of the curve \(a^{2y\)=x³-a³ at the point where the curve intersects the x-axis, we need to first find the equation of the curve and then determine the value of y and its derivative at that point.

When the curve intersects the x-axis, y=0. Therefore, we have:

a⁰ = x³ - a³

x³ = a³

x = a

Next, we need to find the derivative of y with respect to x:

dy/dx = -2x/(3a²√(x³-a³))

At the point where x=a and y=0, we have:

dy/dx = -2a/(3a²√(a³-a³)) = 0

Therefore, the radius of curvature is given by:

R = (1/|d²y/dx²|) = (1/|d/dx(dy/dx)|)

To find d/dx(dy/dx), we need to differentiate the expression for dy/dx with respect to x:

d/dx(dy/dx) = -2/(3a²(x³-a³\()^{\frac{3}{2}\)) + 4x²/(9a⁴(x³-a³\()^{\frac{1}{2}\))

At x=a, we have:

d/dx(dy/dx) = -2/(3a²(a³-a³\()^{\frac{3}{2}\)) + 4a²/(9a⁴(a³-a³\()^{\frac{1}{2}\)) = -2/27a³

Therefore, the radius of curvature is:

R = (1/|-2/27a³|) = 27\(a^{\frac{3}{2}\)

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Inequalities are used in various branches of mathematics, as well as in real-world applications such as economics, physics, and social sciences, to describe relationships, make comparisons, and analyze data.

Inequalities are mathematical statements that describe a relationship between two values or expressions, indicating that one is greater than, less than, or not equal to the other. Inequalities are used to compare quantities and express their relative sizes or order.

The most common symbols used in inequalities are:

">" (greater than): indicates that the value on the left side is larger than the value on the right side.

"<" (less than): indicates that the value on the left side is smaller than the value on the right side.

"≥" (greater than or equal to): indicates that the value on the left side is greater than or equal to the value on the right side.

"≤" (less than or equal to): indicates that the value on the left side is less than or equal to the value on the right side.

"≠" (not equal to): indicates that the values on both sides are not equal.

Inequalities can be represented using variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. Solutions to inequalities are often expressed as intervals or sets of values that satisfy the given inequality.

Inequalities are used in various branches of mathematics, as well as in real-world applications such as economics, physics, and social sciences, to describe relationships, make comparisons, and analyze data.

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Answer:

83/117

Step-by-step explanation:

For the denominator, it would be the total of marbles. So I added all the numbers and got 117.

For the numerator, it would be how many marbles are not black. So how many total marbles minus the black marbles. So 117 minus 34.

The limit of the difference quotients for f(x) = x^2 + 2x + 1 as x approaches -1 is indeterminate.

To find the limit of the difference quotients for the function f(x) = x^2 + 2x + 1 as x approaches -1, we need to evaluate the following expression:

lim(x→-1) [f(x) - f(-1)] / (x - (-1))

First, let's substitute the values into the expression:

lim(x→-1) \([(x^2 + 2x + 1) - (-1^2 + 2(-1) + 1)] / (x + 1)\)

Simplifying further:

lim(x→-1) \([(x^2 + 2x + 1) - (1 - 2 + 1)] / (x + 1)\)

lim(x→-1)\([x^2 + 2x + 1 - 0] / (x + 1)\)

lim(x→-1) \((x^2 + 2x + 1) / (x + 1)\)

Now, we can directly substitute x = -1 into the expression:

\((-1^2 + 2(-1) + 1) / (-1 + 1)\)

(1 - 2 + 1) / (0)

0 / 0

We have obtained an indeterminate form of 0/0. This indicates that we need to further simplify the expression or use other techniques, such as L'Hôpital's rule, to evaluate the limit. However, without additional information or simplification, we cannot determine the precise value of the limit at x = -1.

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Answer:

A and C

Step-by-step explanation:

N/A

Answer:

84

Step-by-step explanation:

We simply plug in 1.75 for x into y = 48x, and when we do so we get y = 48 * 1.75 = 84 cups of coffee. Hope this helps!

Answer:

B) 84

Step-by-step explanation:

48 times x is the cups of coffee sold in x hours.

if x = 1.75, then you times 48 by 1.75

48 x 1.75 = 84

The art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper for proper distribution.

To determine the largest number of identical kits the art teacher can make using all the crayons and drawing paper, we need to find the greatest common divisor (GCD) of the quantities.

The GCD represents the largest number that can divide all the quantities without leaving a remainder.

The GCD of the quantities of crayons can be found by considering the prime factorization:

72 = 2³ × 3²

48 = 2⁴ × 3

48 = 2⁴ × 3

48 = 2⁴ × 3

The GCD of the crayons is 2³ × 3 , which is 24.

Now, we need to find the GCD of the quantity of drawing paper:

120 = 2³ × 3 × 5

The GCD of the drawing paper is also 2³ × 3 , which is 24.

Since the GCD of both the crayons and drawing paper is 24, the art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper.

Each kit would contain an equal distribution of crayons and drawing paper.

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An expression that can be used to find the cost of an n-minute long distance call, where n is at least 5 minutes is (0.55 + (n - 5) x 0.07) dollars.

Given:

Long Distance Rates Time (minutes) Cost5 $0.556 $0.627 $0.698 $0.769 $0.8310 $0.90We need to find an expression that can be used to find the cost of an n-minute long-distance call, where n is at least 5 minutes.

The cost of making a long-distance call is given for 5 minutes, 6 minutes, 7 minutes, 8 minutes, 9 minutes, and 10 minutes.

We can observe from the above table that for every increase of 1 minute, the cost increases by $0.07.

We can conclude that the cost of n minutes long-distance call is given by: (0.55 + (n - 5) x 0.07) dollars when n is at least 5 minutes.

Therefore, the required expression is: (0.55 + (n - 5) x 0.07) dollars when n is at least 5 minutes. The above expression is based on the pattern in the table provided for long-distance call rates. We can use this expression for values of n greater than or equal to 5.

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Note that the roots of the equation Unequal and rational (Option D)

The roots of the equation   (x - 3)² = 4 can be found by taking the square root of both sidesof the equation.

x - 3 = ±√4

⇒ x - 3 = ±2

Solve for x

For the positive square root.

x - 3 = 2

x = 2 + 3

x = 5

For the negative square root.

x - 3 = -2

x = -2 + 3

x = 1

Since the equation has two roots, x = 5 and x = 1. These roots are unequal and rational. (Option D)

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Full Question:

Although part of your question is missing, you might be referring to this full question:

The roots of the equation (x - 3)² = 4 are

A.Unequal and irrational.

B.Equal and rational.

C.  Equal and irrational.

D.  Unequal and rational.

Answer:

Yes, Kevin skied twice as long as Lori without falling.

Step-by-step explanation:

Kevin's time was 223 sec and Lori's was 110 sec.

110 x 110 = 220

Since Lori's time was 110 seconds and twice that is less than Kevin's, which was 223.

Thus we have our answer:

Yes, Kevin skied twice as long as Lori did without falling.

Hope it helps!!

The function f(x) = -2(4)ˣ⁺¹ +140 represents the number of tokens a child has x hours after arriving at an arcade. The practical domain and range of the function are x ≥ 0 and The practical range of the situation is [140, ∞).

The given function is f(x) = -2(4)ˣ⁺¹+ 140, which represents the number of tokens a child has x hours after arriving at an arcade.

To determine the practical domain and range of the function, we need to consider the constraints and limitations of the situation.

For the practical domain, we need to identify the valid values for x, which in this case represents the number of hours the child has been at the arcade. Since time cannot be negative in this context, the practical domain is x ≥ 0, meaning x is a non-negative number or zero.

Therefore, the practical domain of the situation is x ≥ 0.

For the practical range, we need to determine the possible values for the number of tokens the child can have. Looking at the given function, we can see that the term -2(4)ˣ⁺¹represents a decreasing exponential function as x increases. The constant term +140 is added to shift the graph upward.

Since the exponential term decreases as x increases, the function will have a maximum value at x = 0 and approach negative infinity as x approaches infinity. However, due to the presence of the +140 term, the actual range will be shifted upward by 140 units.

Therefore, the practical range of the situation will be all real numbers greater than or equal to 140. In interval notation, we can express it as [140, ∞).

To summarize:

- The practical domain of the situation is x ≥ 0.

- The practical range of the situation is [140, ∞).

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Answer:

Chicken nuggets from mcdonalds are good

Step-by-step explanation:

I had the same question and put that in and got it right ;)

Answer:

2cm

Step-by-step explanation:

vbjufdxcvhjjkknvxzdhjkbcxdf

Answer:

the answer is 22

Answer: 22

Step-by-step explanation:

This is the answer because if you work backwards then number minus five is actually 9-5, so you're left with 4. And then you need to do 6 times he difference of 9-5, which is 4. So, 6 X 4 would equal 24. And then you need to do 2 less than that answer. So 24-2 would equal 22.  

Answer:

0.03

Step-by-step explanation:

Hope this helps.

Answer:

Im not sure if this is correct

x=7

y=8/3

z=16/3

Step-by-step explanation:

The three equations are

x+y+z=15

x+3y=15

y+z=8

you can use substitution for the first and third equation so it would be

x+8=15

x=7

then use sub for the second equation

7+3y=15

3y=8

y=8/3

and you can finish by using sub for the third equation

8/3+z=8

3z=16

z=16/3

I hope this is correct

If you don't know the value of sigma (population standard deviation), then you must use the T distribution instead of the Z distribution. However, if the sample size n is greater than 30, then the T distribution is approximately the same as the Z distribution.

This means that even if you don't know sigma, you can use the Z distribution if n > 30.

-----------------------------------

In short, you use T over Z if you don't know sigma and n = 30 or smaller

To verify if the relation is a function, it must be verified if from each value of x only one arrow departs.

A relation represents a function when each input value is mapped to a single output value.

In mapping notation, with the arrows, it must be verified if there is no input from which more than one arrow departs.

The problem is incomplete, hence the general procedure to verify if the relation is a function was presented.

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