When the pressure above a liquid is reduced (like in a vacuum), the boiling point of the liquid is

The work done by the force is 64 kJ , The angle between F and d is 42.46 degree.

A vector is an object that has both  magnitude and direction.

It is given that  

force F→=(8.0i^+9.6j^+11.2k^)kN

mass = 95 g

If the displacement of the object is d→=(3.8i^+3.5j^)m,

work done = ?

Work Done = (Force ) * Distance

Work done =  (8.0i^+9.6j^+11.2k^)*(3.8i^+3.5j^)

Work Done = 64 kJ

Work Done is a scalar quantity

The angle between F and d is

cos \(\rm \theta\) = (vector Fd)/(Magnitude of Fd)

\(\rm F = \sqrt{8^2+9.6^2+11.2^2}\\\\\\F= 16.78\\\\\\d = \sqrt{3.8^2+ 3.5^2}\\\\\\d = 5.17\)

cos \(\rm \theta\)  = 64 / (16.78*5.17)

cos \(\rm \theta\)  = 0.7377

\(\rm \theta\)  = 42.46 degree

The angle between F and d is 42.46 degree.

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Given

distance of the object  u = -40 cm.

radius of curvature of the refracting surface  R = -20 cm.

The height of the object  h = 1 cm.

To Find

The size of the image

Solution

We will now write the following data using the sign convention:

The object's distance is u = -40 cm.

The refracting surface has a radius of curvature of R = -20 cm.

The object's height is h = 1 cm.

We know that the lens maker formula is: n2vn1u=n2n1R.

v denotes the image formation distance.

The refractive index of the second medium is n2=1.33, and the refractive index of the first medium is n1=1.

In the preceding equation, we will now substitute the known values.

1.33v−1−40cm=1.33−1−20cmv=32.05cm

We know that the magnification ratio can be expressed as vu=Hh.

H denotes the height of the created image.

We'll now swap the given and obtained values.

⇒32.05cm divide by 40cm=H divide by 1cm

⇒H=0.6cm

As a result, the best choice is (B).

Further information: The rules of reflection apply to reflection from a concave mirror. The normal to the point of incidence is drawn along the radius of the mirror, that is, by connecting the point of incidence to the centre of curvature.

The development of an image in a concave mirror is mostly determined by the distance between the object and the mirror. The concave mirror produces both real and virtual images.  A virtual and magnified picture is generated when the object is placed very close to the mirror.

The complete question is -

Find the size of the image formed in the situation shown in figure.

photo

A) 0.5 cm

B) 0.6 cm

C) 1.2 cm

D) 1 cm

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If the speed of the magnet is doubled, the induced voltage is twice as great

Faraday's law of induction states that whenever relative motion exists between a coil and magnetic field, a voltage will induce in the circuit and this voltage is proportional to the rate of change of the flux. The expression for the motional emf is as follows:

ε=Blv

Here, ε is the motional emf, B is the magnetic field, l is the length of the conductor, and v is the velocity at which the magnetic field changes.

The induced voltage by the moving magnet is directly proportional to the speed of the magnet. Therefore, an increase in the speed of the magnet will increase the induced voltage.

If the speed of the magnet is doubled, the induced voltage is twice as great

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Answer:

B) meteoroids.  The key word here is "generally."  Not when it enters the atmosphere or hits the surface of the Earth.  

Explanation:

Answer:

b more painful is correct

Explanation:

:)

Answer:

the direction is Southly west

The conservation of energy allows finding the result of the velocity of the body 2 when it reaches the ground is:

          v = 6.32 m / s

Given parameters

To find

The conservation of energy is one of the most important principles of physics, it establishes that if there is no friction force, the mechanical energy is conserved at all points, where the mechanical energy is the sum of the kinetic energy plus the different potential energies.

Let's write the energy at two points before we drop the system.

     Em₀ = U₁ + U₂

Where potential energy is

    U = m g y

They indicate that body 1 is on the ground and body 2 is at a height .

      y₂ = 8 m

      Em₀ = m₂ g y₂

Let's write the energy of the system for when body 2 is reaching the ground

       \(Em_f\) = K₂ + K₁ + U₂ + U₁

At this moment body 2 is reaching the ground, its height is zero and the height of body 1 is y₁ = 8 m. Since the two bodies are joined by the rope, they must have the same speed..

      \(Em_f\) = ½ (m₁ + m₂) v² + m₁ g y₁

As there is no friction, the energy is conserved.

      Em₀ = Em_f

      m₂ g y₂ = ½ (m₁ + m₂) v² + m₁ g y₁

The rope is inextensible, the heights are equal.

       y₁ = y₂ = y = 8.0 m

      v² = \(\frac{m2-m1}{m2+m1} \ 2g y\)  

Let's calculate.

       \(v^2 =\frac{22.9-13.6}{ 22.9+13.6} \ 2 \ 9.8 \ 8 \\ v = \sqrt{39.95}\)

      v = 6.32 m / s

In conclusion using the conservation of energy we can find the result of the velocity when the body 2 reaches the ground is:

          v = 6.32 m / s

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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The rumble feature on a video game controller is driven that turns electrical energy into mechanical energy. This device is best referred to as a motor.

An electric motor converts electrical energy into mechanical energy.

Thus, the option (D) is correct.

Answer:

.04 kg

Explanation:

The equation for simple harmonic motion is x = A*cos(ωt), where A is the amplitude, ω is the angular frequency, and t is the time.

Comparing the given equation x = 2.0cos(50t) with the equation for simple harmonic motion, we see that A = 2.0 meters and ω = 50 radians/second.

The angular frequency is related to the spring constant and mass by the equation ω = sqrt(k/m), where sqrt denotes the square root.

Substituting the values given, we get:

50 = sqrt(100/m)

Squaring both sides and solving for m, we get:

m = 100/2500 = 0.04 kg

Explanation:

You can just use Pythagorean theorem to find the resultant mag

20^2 + 100^2 = R^2

mag of R = 102 m/s

Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.

1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.

This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.

2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.

The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.

Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.

However, the thrust force continues to be the dominant force propelling the rocket upward.

It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.

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Answer:

Explanation:

que paso cuz

Answer:

60mph=26.8224meters per second

Explanation:

The passage below was published by Montesquieu in 1748. They decided to separate the powers of government into three branches. Option D

This is further explained below.

Generally, Montesquieu was a French judge, a man of letters, historian, and political philosopher.

His full name was Charles Louis de Secondat, Baron de La Brède et de Montesquieu, although he is most often known by his nickname, Montesquieu.

He is the primary originator of the notion of the separation of powers, which is incorporated into the constitutional framework of numerous countries around the globe.

In conclusion, The following text was written by Montesquieu and first appeared in print in the year 1748. They came to the conclusion that the powers of the government should be divided into three distinct branches. The D Option

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cq

The passage below was published by Baron de Montesquieu in 1748. How did these ideas influence the Founding Fathers of the United States?

answer choices

They decided to establish a constitutional monarchy.

They decided to establish a representative form of government.

They decided to separate the powers of government into three branches.

They decided each branch of government should be able to check the other branches.

Option A) 3.9 km is the correct answer. the magnitude of Rhea's displacement vector is approximately 3.92 km.

In order to find out the magnitude of Rhea's displacement vector, we have to add up all of the displacement vectors.

Then we can use the Pythagorean theorem to calculate the magnitude of the resultant vector.

Since Rhea is first driving north for 2.4 km and then west for 3.1 km, we can represent her displacement vectors as follows: Δx = 0 km and Δy = 2.4 km for the first vector, and Δx = -3.1 km and Δy = 0 km for the second vector.

We can then add these vectors together by adding their components: Δx = 0 km + (-3.1 km) = -3.1 km and Δy = 2.4 km + 0 km = 2.4 km.

This gives us a resultant vector of -3.1 km east and 2.4 km north.

Using the Pythagorean theorem, we can find the magnitude of this vector: \(\sqrt{(\(-3.1 km)^{2} + (2.4 km)^{2} ) } = \sqrt{(9.61 + 5.76) km^{2} } = \sqrt{15.37 km^{2} } \approx 3.92 km.\)

Therefore, the magnitude of Rhea's displacement vector is approximately 3.92 km.

Therefore, option A) 3.9 km is the correct answer.

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C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

If an 8m long string is in its twelfth harmonic, the wavelength of standing waves on the string will be 1.33cm approximately.

The harmonics on the 12th fret are one octave above the open strings, while the harmonics on the 5th fret are two octaves above the open strings.

To arrive at the above answer, we deploy the "harmonic" wavelength principle which states that the "nth" wavelength is equal to the fundamental wavelength divided by n. That is:

λn = λ1/n

Where:

Hence,

λn = (2 x 8)/12

λn = 1.33333333333

λn \(\approx\) 1.33cm.

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The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .

According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.

According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.

Therefore, option C is correct.

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Answer:

D:#2 African Plate

Explanation:

The African Plate is flanked by the Red sea rift and the minor African plate.

The Red sea rift is a small part of a greater line of rifts known as the Great African Rift Valley. The rift valley is making several small lakes all through Africa and it will eventually split up the African continent.

The Red sea lift is the divergent boundary between the African plate and the Arabian plate. It means that the two plates are moving apart or spreading apart.

The answer is option C. A baseball is heading upward after being thrown at an angle.

Kinetic energy is a type of energy associated with motion. It is defined as the energy an object possesses due to its motion, and is dependent on both the object's mass and its velocity. The formula for kinetic energy is KE = 1/2 mv^2, where m is the mass of the object and v is its velocity.

Kinetic energy can be transferred between objects, and is often involved in collisions and other interactions. For example, when a moving object collides with another object, some of its kinetic energy may be transferred to the second object. Kinetic energy is an important concept in physics and is used in many real-world applications, such as in the design of vehicles, machines, and athletic equipment.

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The wavelength of the wave in the spring is 0.357 m.

Wavelength is the length of a complete revolution of a wave.

To calculate the wavelength of the wave in the spring, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for λ

Hence, the wavelength is 0.357 m.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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The amount of force required to lift the helicopter of mass 10000 kg moving with an acceleration of 3 m/s² is 30000 N.

Force is the product of mass and acceleration.

To calculate the amount of force it will take to lift the helicopter, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the amount of force required to lift the helicopter is 30000 N.

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The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

For a spacecraft is traveling with a velocity of Vox-5690 m/s:

To solve this problem, use the equations of motion to calculate the final velocity and the vertical component of the velocity. Assume that the initial velocity in the y-direction is zero.

Given:

Initial velocity in the x-direction (V₀ₓ) = -5690 m/s

Time of engine firing (t) = 865 s

Acceleration in the x-direction (ax) = 1.45 m/s²

Acceleration in the y-direction (ay) = -8.66 m/s²

(a) To calculate the final velocity (v), use the equation:

v = V₀ₓ + ax × t

Substituting the values:

v = -5690 m/s + 1.45 m/s² × 865 s

v = -5690 m/s + 1254.25 m/s

v ≈ 685.25 m/s

Therefore, the final velocity (v) is approximately 685.25 m/s.

(b) To calculate the vertical component of the velocity (vy), use the equation:

vy = ay × t

Substituting the values:

vy = -8.66 m/s² * 865 s

vy = -7484.9 m/s

Therefore, the vertical component of the velocity (vy) is -7484.9 m/s.

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Explanation:

The distance is the length of the path, or 400 m.

The displacement is the difference between the final position and the initial position.  Since the track is a circle and the end back where they started, the displacement is 0 m.

If a person runs around a 400 m track,then the distance covered by the person would be 400 meters, while the displacement covered by the person would be zero meters.

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.

Displacement describes this shift in location.

As given in the problem If a person runs around a 400 m track, then we have to find the distance and the displacement covered by him,

The distance is 400 meters, which is how long the path is.

The distance between the end location and the starting position is known as displacement. The displacement is 0 m since the track is round and ends where it began.

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Answer:

25N

it will float since the water displaced is less than the weight. buoyancy = 25n down

Explanation:

40 newtons - 25 newtons = 25 newtons

The buoyant force on the ball is 25 Newton and the ball will float.

From the information given, we're informed that a hollow ball weighs 40 newtons and a water tank displaces 15 newtons of water.

Therefore, the buoyant force on the ball will be:

= 40N - 15N = 25N

Since we got a positive value, it means that the ball will float on water.

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