When vectors B+A=5i-j and B-A=i-7j, what is the magnitude and direction of vector A?

The average blood pressure in the brain will be higher than the average blood pressure in the feet. the average blood pressure in the brain will be lower than the average blood pressure in the feet.

When the elevator accelerates upward at \(10 ms^{-2}\), the blood pressure in the brain and feet of a person changes.

Similarly, when the elevator accelerates downward with the same acceleration, the blood pressure in the brain and feet of a person changes.

Let's discuss them one by one:Blood Pressure When Elevator Accelerates Upward at \(10 ms^{-2}\)

When the elevator accelerates upward at \(10 ms^{-2}\),  the blood pressure in the brain of a person increases, while the blood pressure in the feet of a person decreases.

This happens due to the gravitational force acting on the body.

Since the gravitational force on the head is greater than the gravitational force on the feet, the blood pressure in the brain increases while the blood pressure in the feet decreases.

Therefore, the average blood pressure in the brain will be higher than the average blood pressure in the feet.

Blood Pressure When Elevator Accelerates Downward at  \(10 ms^{-2}\) When the elevator accelerates downward at \(10 ms^{-2}\), the blood pressure in the brain of a person decreases, while the blood pressure in the feet of a person increases.

This also happens due to the gravitational force acting on the body. Since the gravitational force on the head is less than the gravitational force on the feet, the blood pressure in the brain decreases while the blood pressure in the feet increases.

Therefore, the average blood pressure in the brain will be lower than the average blood pressure in the feet.

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The car that has the greater acceleration magnitude is car B

Torricelli's theorem can be used to calculate the magnitude of an object's acceleration when the value of time is not known:

                                            \(v^{2} = v_{0}^{2} + 2a\Delta S\)

Note that \(v\\\) is the final velocity value, \(v_{0}\) is the initial velocity value, \(a\) is the acceleration value, and \(\Delta S\) is the displacement.

Substituting the values ​​given by the question in the formula, we have:

                                           \(10^{2}= 0^{2}+2\times a \times 50\)

                                                    \(100 = 100a\)

                                                     \(a = 1m/s^{2}\)

    2. CAR B

                                               \(20^{2} = 10^{2} + 2\times a \times 50\)

                                                   \(400 = 100 + 100a\)

                                                        \(100a=300\)

                                                         \(a = 3m/s^{2}\)

So, comparing the two acceleration calculated above,  it is assumed that the car has the greater acceleration magnitude is car B with \(3m/s^{2}\)  comparing to \(1m/s^{2}\)  of the car A.

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Answer:

yea yes they can they lose their retina but they can dream

A car travels 200 km in the first 2.5 hour then stop for half hour then travels the final speed of 200 km in 2 hours. The average speed of the car is 80 km/hour.

To find the average speed of the car, we need to calculate the total distance traveled and the total time taken.

In the first 2.5 hours, the car travels 200 km.

Then, it stops for half an hour.

After that, the car travels another 200 km in 2 hours.

So the total distance traveled is 200 km + 200 km = 400 km.

The total time taken is 2.5 hours + 0.5 hours + 2 hours = 5 hours.

Therefore, the average speed of the car is:

Average speed = total distance / total time

= 400 km / 5 hours

= 80 km/hour.

So the average speed of the car is 80 km/hour.

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Answer:

Remote Sensing

Explanation:

One of the conclusion about the history of sports that can be drawn from the movie "Champions" is that sports have a long and rich history that is intertwined with the history of human civilization.

From the ancient Olympic Games to the modern-day Olympics, sports have been a way for people to come together and compete in a spirit of sportsmanship and competition. Sports have also been a way for people to express themselves, to build community, and to achieve personal goals.

The movie "Champions" tells the story of a group of young men who come together to form a football team. The team is made up of boys from different backgrounds and with different abilities. However, they are all united by their love of football and their desire to win.

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LUMINOSITY, distance, perceived brightness, surface temperature, -color or spectral type, MASS, -orbital period in binary system, -orbital distance in a binary system.

In physics, mass is a quantitative measure of inertia, a basic characteristic of all matter. It is essentially the resistance a body of matter gives to a change in its speed or location as a result of the application of a force.

A measurement of the volume of material that makes up or is contained within a physical body. Newton's laws of motion are based on classical mechanics, which relates an object's mass to the force needed to accelerate it and, consequently, to its inertia.

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The net force on particle q₂ is 1.05 x 10¹³ N, directed towards particle q1.

To find the net force on particle q₂, we need to calculate the force between q₁ and q₂, and the force between q₂ and q₃, and then add these two forces together.

The force between two point charges can be calculated using Coulomb's law, which states that

F = k × q₁× q₂ / r²

where F is the force, k is Coulomb's constant (9.0 x 10⁹ N m² / C²), q₁ and q₂ are the magnitudes of the charges, and r is the distance between the charges.

The force between q₁ and q₂ is

F₁ = k × q₁ × q₂ / r₁²

where r₁ = 0.10 m.

Substituting the values, we get

F₁ = 9.0 x 10⁹ N m² / C²  × 8.0 C  × 3.5 C / (0.10 m)² = 2.52 x 10¹³ N

The force between q₂ and q₃ is

F₂ = k  × q₂  × q₃ / r₂²

where r₂ = 0.15 m.

Substituting the values, we get

F₂ = 9.0 x 10⁹ N m² / C²  × 3.5 C  × (-3.5 C) / (0.15 m)² = -1.47 x 10¹³ N

Note that the negative sign indicates that the force is attractive, since q₂ and q₃ have opposite signs.

The net force on q₂ is the vector sum of F₁ and F₂

\(F_{net}\) = F₁ + F₂ = 2.52 x 10¹³ N - 1.47 x 10¹³ N = 1.05 x 10³ N

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The coefficient of friction between the two blocks is 0.194.

The problem involves finding the coefficient of friction between two blocks of equal mass attached by a string that moves over a sloped ramp with an angle of 30 degrees. The blocks start from rest and are allowed to move freely. The distance traveled by the blocks is 0.50 m, and the time taken to travel this distance is 0.935 s. To solve the problem, we need to consider the forces acting on the system of blocks. The forces acting on the blocks are the gravitational force, the tension in the string, and the frictional force. As the blocks are moving up the ramp, the force of gravity is pulling them down. The tension in the string is pulling the blocks up the ramp. The frictional force is opposing the motion of the blocks and is acting in the opposite direction to the tension in the string.

To determine the coefficient of friction, we can use the equations of motion to find the acceleration of the blocks. Once we have the acceleration, we can use Newton's Second Law to find the net force acting on the blocks. We can then use the force of friction to find the coefficient of friction. Using the equations of motion, we can find the acceleration of the blocks:

a = 2d/t^2

where d is the distance traveled by the blocks and t is the time taken to travel the distance. Plugging in the given values, we get:

a = 2(0.50 m)/(0.935 s)^2 = 1.15 m/s^2

Next, we can use Newton's Second Law to find the net force acting on the blocks:

ΣF = ma

where ΣF is the sum of the forces acting on the blocks. Plugging in the known forces, we get:

T - mg sin θ - μmg cos θ = ma

where T is the tension in the string, m is the mass of the blocks, g is the acceleration due to gravity, θ is the angle of the ramp, and μ is the coefficient of friction.

We can simplify this equation by substituting mg sin θ for the component of the weight of the blocks that is acting down the ramp and mg cos θ for the component of the weight that is acting perpendicular to the ramp:

T - mg sin θ - μmg cos θ = ma

T - mg(1/2) - μmg(√3/2) = ma

We can also use the equation for the tension in the string:

T = 2mg sin θ

Substituting this into the equation for net force, we get:

2mg sin θ - mg(1/2) - μmg(√3/2) = ma

Simplifying and solving for μ, we get:

μ = (2gsinθ - a)/(2gcosθ)

Substituting the given values, we get:

μ = (2(9.81 m/s^2)sin 30° - 1.15 m/s^2)/(2(9.81 m/s^2)cos 30°) = 0.194

Therefore, the coefficient of friction between the two blocks is 0.194.

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we can calculate pressure if we have mass, acceleration and area.

Answer:

10m above initial height

Explanation:

let acceleration due to gravity = 9.8 m/s/s

v final = v initial - time • gravity

0 = 14m/s - t • 9.8m/s/s

t = 1.43 seconds to reach max height

distance = 1/2 • acceleration • time^2

distance = 1/2 • 9.8 • 1.43^2

distance = 10 meters above initial height

Answer:

y_e = 2A sin kx

y_t = cos wt

Explanation:

A standing wave is produced by the reflection of a traveling wave in an obstacle, let's write the initial traveling wave

        y₁ = A sin (kx -wt)

let's write the reflected wave

       y₂ = A sin (kx + wt)

we find the sum of these two waves

       y = y₁ + y₂

       y = A sin (kx -wt) + A sin (kx + wt)

let's develop the double angles

       y = A [sin kx cos wt - cos kx sin wt + sin kx cos wt + cos kx sin wt]

       y = A [2 sin kx cox wt]

we can write this resulting wave

       y_e = 2A sin kx

       y_t = cos wt

Answer: ITS 1 TRUST ME MAN BYE K

Explanation: OK BYE TRUST YEAH

Answer:

b

Explanation:

Answer:

 x₂ = 4.455 m

Explanation:

The average speed is defined as the displacement traveled between the time interval

         v_average =  \(\frac{\Delta x}{\Delta t}\)

in this case we have a first stop walking west at speed v = 3.10 m / s a ​​distance of x = 5.96 km = 5.96 10³ m

Let's find the time it takes on this tour

          v = x / t

          t = x / v

          t₁ = 5.96 10³ / 3.10

          t₁ = 1.9226 10³ s

in a second to walk east at a speed of v₂ = 0.744 m / s

           v₂ = x₂ / t₂

           t₂ = x₂ / v₂

for full movement

let's assume that the eastward movement is positive

         v =\(\frac{- x_1 + x_2}{t_1 +t_2}\)

         v = \(\frac{-x_1 +x_2}{t_1 + \frac{x_2}{t_2} }\)

the only unknown term is the distance to the east. We replace and resolve

         1.19 = \(\frac{-5.96 \ 10^3 + x_2}{1.92 \ 10^3 + \frac{x_2}{0.744} }\)

         1.19 (1.92 10³ + \(\frac{x_2}{0.744}\)) = x₂ 1.92 10³ - 5.96 10³

          2.2848 10³ + 1.599 x₂ = 1.92 10³ x₂ - 5.96 10³

          x₂ (1.92 10³ - 1.599) = 2.2848 10³ + 5.96 10³

          x₂ = 8.5448 10³ / 1.918 10³

          x₂ = 4.455 m

Therefore, the mass of each item is 0.00260 kg.

A body on the surface of the earth experiences gravitational force equal to mass times gravitational acceleration, or 10 kg times 9.8 ms-2, or 98 N. Q.

The equation: gives the gravitational force between two objects.

\(F = G * (m1 * m2) / r^2\)

In order to solve for one of the objects' mass, we can first rearrange the equation as follows:

\(m1 = F * r^2 / (G * m2)\)

Since the two objects have equal masses, we can use this equation to solve for m1, and then we can use that information to determine each object's mass individually.

Plugging in the values we know, we get:

m1 =\((0.0104 N) * (0.00500 m)^2 / [(6.6743 × 10^-11 N m^2 / kg^2) * m2]\)

Simplifying, we get:

m1 = 0.00260 kg / m2

Since the two objects have equal mass, we can say that:

m1 = m2 = 0.00260 kg

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Explanation:

formula for force is:

force=mass × acceleration

but in case of friction

force =coefficient of friction × Normal Reaction

F. = u × R

U = F/R

but when placed horizontally

R= M×G

M=mass=60kg

G=Gravity(10m/s or 9.8m/s)

F=140N

U=140/60×10

U=140/600

U=0.2333333333

approximately to 3 significant figures

U=0.233

if i am correct rate it 5 star

Answer:

μ = tanθ = tan30 = 0.58

Explanation:

μ = force parallel/force perpendicular = mgsinθ/mgcosθ = tanθ

Answer:

2.55 rad/sec

Explanation:

Use conservation of angular momentum

The merry go round has

I = ½mr²

I = ½ * 135 * 2.93²

I = 579 kgm²

the person has

I = mr²

I = 62.4 * 2.93²

I = 536 kgm²

Converting 0.621 rev/sec to rad/sec we have 0.621 * 2π

0.621 * 2 * 3.14 rad/sec

3.9 rad/sec

for the person v/r = w

w = 3.21 / 2.93

w = 1.10 rad/sec

So

579 * 3.9 + 536 * 1.1 = (579+536)*w

2258 + 589.6 = 1115w

2847.6 = 1115w

solve for w

w = 2847.6 / 1115

w = 2.55 rad/sec

Thus, the final angular speed of the merry go round is 2.55 rad/sec

Acceleration = (change in velocity) / (time for the change)

change in velocity = (velocity after) - (velocity before)

change in velocity = (51 m/s north) - (43 m/s south)

that's the same thing as (51 m/s north) + (43 m/s north)

change in velocity = 94 m/s north

Acceleration = (94 m/s north) / (1 second)

Acceleration = 94 m/s² north

The direction of the acceleration is North.

Answer:

6s

Explanation:

Assume it is dropped from rest and the gravitational acceleration is 10

By the equation of motion under constant acceleration:

\(s=ut+\frac{1}{2} at^2\)

180 = (0)t+10(t^2)/2

t = 6 or -6 (rejected)

t = 6 s

Answer:

B

Explanation:

Fermium is a synthetic element with the symbol Fm and atomic number 100. It is an actinide and the heaviest element that can be formed by neutron bombardment of lighter elements, and hence the last element that can be prepared in macroscopic quantities, although pure fermium metal has not yet been prepared.[3] A total of 19 isotopes are known, with 257Fm being the longest-lived with a half-life of 100.5 days.

It was discovered in the debris of the first hydrogen bomb explosion in 1952, and named after Enrico Fermi, one of the pioneers of nuclear physics. Its chemistry is typical for the late actinides, with a preponderance of the +3 oxidation state but also an accessible +2 oxidation state. Owing to the small amounts of produced fermium and all of its isotopes having relatively short half-lives, there are currently no uses for it outside basic scientific research.

Answer:

since -6 lasted for 5 seconds, multiplying both would result in -30

3 lasted for 10 seconds, so multiplying both would give +30

average = ( 30 + (-30) ) / 2

30 -30 is already equal to zero, so the answer should be 0

The momentum of the zombie is 535.3 kg m/s.

Momentum is a fundamental concept in physics that describes the amount of motion that an object has. It is defined as the product of an object's mass and its velocity.

Here,

The momentum (p) of an object is defined as the product of its mass (m) and velocity (v)

p = m * v

In this case, the mass of the zombie is 101 kg and its velocity is 5.3 m/s. So, the momentum of the zombie can be calculated as:

p = 101 kg * 5.3 m/s

p = 535.3 kg m/s

Therefore, the momentum of the zombie is 535.3 kg m/s.

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Answer: Mass= 13.6 kg

Explanation:

F = m * a

34 = m (2.5)

m = 34 / 2.5

m = 13.6 kg

Answer:

momentum = mass × velocity = 6× 20 =120 kg.ms-1

Explanation:

not sure if this is right

Answer:

20 kg

Explanation:

The kinetic energy (KE) of an object is given by:

KE = (1/2) * m * v^2

Where m is the mass of the object, and v is its velocity.

We can rearrange this formula to solve for the mass:

m = 2 * KE / v^2

Plugging in the values given:

m = 2 * 1000 J / (10 m/s)^2

m = 20 kg

Therefore, the mass of the Puffin flying at 10 m/s with 1000 J of KE is 20 kg.

The water flow rate from the faucet, assuming a steady flow, is approximately 0.0001608 cubic meters per second.

The phenomenon of a water stream "necking down" as it falls can be explained by the principle of conservation of mass. According to this principle, the flow rate of water remains constant throughout the system.

In the given figure, the water stream emerges from a faucet with an initial cross-sectional area of 1.8 cm² (Area one). As the water falls, it narrows down to a smaller cross-sectional area of 0.3 cm² (Area two) at a height of 25 cm.

To calculate the water flow rate assuming steady flow, we can use the formula:

Flow rate = A₁√(2gh) / A₁² - A₂²

Where A₁ and A₂ are the initial and final cross-sectional areas, respectively, g is the acceleration due to gravity, and h is the height of the water column.

Plugging in the given values, we have:

Flow rate = 1.8 cm² √(2 × 9.8 m/s² × 25 cm) / (1.8 cm²)² - (0.3 cm²)²

Converting the units to match, we get:

Flow rate = 0.018 m² √(2 × 9.8 m/s² × 0.25 m) / (0.018 m²)² - (0.003 m²)²

Simplifying the expression, we find:

Flow rate ≈ 0.0001608 m³/s

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