Whenever using a microscope slide, you should always:
A.
check for cracks or chips in the glass.
B.
make sure it is clean.
C.
handle it with care.
D.
all of these

Answer:

400 W

Explanation:

Ignoring the efficiency rating for the transformer we have to assume 100% .. Also, the power input to primary is equal to the power output in secondary.

This means that power input = 400 W = power output

Answer:

\(3.24\times 10^{-7}\ \text{m}\)

Explanation:

m = Mass of bullet = 4.8 g

v = Velocity of bullet = 170 m/s

B = Magnetic field of Earth = \(5\times 10^{-5}\ \text{T}\)

q = Charge of bullet = \(1.06\times 10^{-8}\ \text{C}\)

a = Acceleration

Time the bullet will be in the air for is \(t=\dfrac{1000}{170}=5.88\ \text{s}\)

Force is given by

\(F=ma\)

Magnetic force is given by

\(F=qvB\)

So

\(ma=qvB\\\Rightarrow a=\dfrac{qvB}{m}\\\Rightarrow a=\dfrac{1.06\times 10^{-8}\times 170\times 5\times 10^{-5}}{4.8\times 10^{-3}}\ \text{m/s}^2\)

From the linear equations of motion we have

\(s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0+\dfrac{1}{2}\times \dfrac{1.06\times 10^{-8}\times 170\times 5\times 10^{-5}}{4.8\times 10^{-3}}\times 5.88^2\\\Rightarrow s=3.24\times 10^{-7}\ \text{m}\)

The defelection of the bullet is \(3.24\times 10^{-7}\ \text{m}\)

Answer:

Below

Explanation:

a) To find the force of friction acting on the mass we can use this formula :

     friction = coefficientoffriction x normal force

First we need to find the normal force of this object :

     Fn = mg

          = (6.0)(9.8)

          = 58.8 N

Now we can find the force of friction acting on the object :

     friction = (0.20)(58.8N)

                 = 11.76 N

                 = 12 N (we round this to 2 sig figs)

b) To find the force needed to accelerate this object at 0.68 m/s^2 use this :

     F = ma

     0.68 = x - 11.76 / 6

     x = 15.84

     x = 16 N

Hope this helps! Best of luck <3

Answer:

thermometer A

Explanation:

The range of a thermometer is the difference between the minimum and maximum temperatures that the thermometer can read.

             ∴ Range of thermometer A = 110° - (-10)° = 120°

                Range of thermometer B = 50° - (-10)° = 60°

∴ Range of thermometer A is greatest.

Hope this helps!

Answer:

0 j

Explanation:

The work done by the employee on the box at the given zero displacement is 0 J.

The given parameters;

The work done by the employee on the box is calculated as follows;

W = Fd

where;

Since the employee sits on the box without moving it, the distance moved by the box = 0

W = 500 x 0

W = 0 J

Thus, the work done by the employee on the box is 0 J.

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Answer:

10⁴ Pa

Explanation:

When the tank is half filled ,

Also we know that ,

\(\longrightarrow \) Density = Mass/Volume

\(\longrightarrow \) 10³ kg/m³ = m/20m³

\(\longrightarrow \) m = 2 * 10⁴ kg

So that ,

\(\longrightarrow \) Weight = mg

\(\longrightarrow \) F = 2*10⁴ × 10 N

\(\longrightarrow \) F = 2 * 10⁵ N

And ,

\(\longrightarrow \) Pressure = Force/Area

\(\longrightarrow \) P = 2 *10⁵/ 5 * 4 Pa

\(\longrightarrow \) P = 10⁴ Pa

Answer:

1210 ohm

Explanation:

Given :

P=40 W

V=220 V

Now,

\(P=\frac{V^{2} }{R} \\40=\frac{(220)^{2} }{R} \\40R=48400\\R=\frac{48400}{40} \\R=1210 ohm\)

Therefore, resistance of bulb will be 1210 ohm

The block of mass m at point l is initially moving with velocity vı and collides with the block of mass n at point B.

Velocity is a vector quantity that measures the rate of change of an object's position. It is the speed of an object in a given direction. Velocity is expressed in units of length per unit time, such as miles per hour or kilometers per hour. Velocity can be determined by dividing the distance traveled by the time it took to travel that distance.

The collision is elastic, meaning that the total kinetic energy is conserved. The force of the spring between points B and C opposes the motion of the blocks and causes them to slow down as they move along the path l-C. The frictional force acts in the opposite direction of the motion and causes the blocks to slow down even more. Finally, when the blocks reach the end of the path l-C, the force of the spring is equal to the frictional force, and the blocks stop. The force constant of the spring is k, which is the amount of force required to stretch the spring a certain distance.

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Answer:

The position of the object at \(t = 5\,s\) is 130.167 meters.

Explanation:

Let \(a(t) = 5\cdot t\,\left[\frac{m}{s^{2}} \right]\) the acceleration experimented by the object along the x-axis. We obtain the equation for the position of the object by integrating in acceleration formula twice:

Velocity

\(v(t) = \int {a(t)} \, dt\) (1)

\(v(t) = 5\int {t} \, dt\)

\(v(t) = \frac{5}{2}\cdot t^{2}+v_{o}\) (2)

Where \(v_{o}\) is the initial velocity of the object, measured in meters per second.

Position

\(s(t) = \int {v(t)} \, dt\) (3)

\(s(t) = \frac{5}{2}\int {t^{2}} \, dt+v_{o}\int \, dt\)

\(s(t) = \frac{5}{6}\cdot t^{3}+v_{o}\cdot t + s_{o}\) (4)

Where \(s_{o}\) is the initial position of the object, measured in meters per second.

If we know that \(s_{o} = 6\,m\), \(v_{o} = 4\,\frac{m}{s}\) and \(t = 5\,s\), then the position of the object is:

\(s(5) = \frac{5}{6}\cdot (5)^{3}+\left(4\right)\cdot (5)+6\)

\(s(5) = 130.167\,m\)

The position of the object at \(t = 5\,s\) is 130.167 meters.

Answer:

Explanation:

Angular momentum of an object is given by L = Iω, where I is the moment of inertia and ω is the angular velocity.

To find the angular momentum of the car, we need to first find its moment of inertia about the axis of rotation (which in this case is the center of the curve).

The moment of inertia of a point mass m rotating around an axis at a distance r is given by I = mr^2.

The car can be thought of as a collection of point masses, so we need to integrate the moment of inertia of each point mass over the entire car.

Assuming the car is a uniform rectangular box with dimensions 4.5 m x 1.8 m x 1.5 m, we can divide it into smaller cubes of mass dm and volume dV. The moment of inertia of each cube is given by dI = dm(r^2), where r is the distance from the cube to the axis of rotation.

Integrating over the entire car, we get:

I = ∫(dm)(r^2) = ∫(ρdV)(r^2)

where ρ is the density of the car.

The volume of the car is V = (4.5 m)(1.8 m)(1.5 m) = 12.15 m^3, and assuming a density of 1000 kg/m^3 (typical for cars), the mass of the car is m = (1000 kg/m^3)(12.15 m^3) = 12150 kg.

We can express the distance r as the sum of the radius of the curve (120 m) and the distance between the center of mass of the car and the pivot point (which we can approximate as half the length of the car, or 0.75 m).

So, r = 120 m + 0.75 m = 120.75 m.

Substituting these values into the equation for I, we get:

I = ∫(ρdV)(r^2) = ρ∫dV(r^2) = ρV(r^2) = (1000 kg/m^3)(12.15 m^3)(120.75 m)^2 = 1.796 x 10^7 kg·m^2

To find the angular velocity of the car, we can use the formula v = ωr, where v is the linear velocity of the car and ω is the angular velocity.

The linear velocity of the car is given by v = 21 m/s, and the radius of the curve is 120 m. So,

ω = v/r = (21 m/s)/(120 m) = 0.175 rad/s

Finally, we can find the angular momentum of the car by multiplying the moment of inertia by the angular velocity:

L = Iω = (1.796 x 10^7 kg·m^2)(0.175 rad/s) = 3.145 x 10^6 kg·m^2/s

Therefore, the angular momentum of the car is 3.145 x 10^6 kg·m^2/s.

The angular momentum of the car in the given example is \(3,780,000 kg m^2/s.\)

The amount of rotational motion an object has around a certain axis is measured by its angular momentum. It is the result of an object's angular velocity and moment of inertia. It is a vector quantity with a direction and magnitude.

We need to apply the following calculation to determine the car's angular momentum:

L = I * ω

where L is angular momentum, I is the moment of inertia, and ω is the angular velocity.

We must apply the following formula to determine the moment of inertia:

\(I = m * r^2\)

where r is the curve's radius and m is the car's mass.

m = 1500 kg r = 120 m

\(I = m * r^2\)

\(I = 1500 kg * (120 m)^2\\I = 21,600,000 kg m^2\)

The following formula must be used to determine the angular velocity:

v = ω * r

where v denotes the car's speed.

v = 21 m/s r = 120 m

where,

v/r = 21 m/s/120 m = 0.175 rad/s

We can now determine the angular momentum:

L = I * ω

\(L = 21,600,000 kg m^2 * 0.175 rad/s\\L = 3,780,000 kg m^2/s\)

Therefore, the angular momentum of the car is \(3,780,000 kg m^2/s.\)

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When the acceleration is three times as large, the mass of the new block will be one-third the initial mass.

The acceleration of the block is the rate of change of velocity of the block with time.

The magnitude of the acceleration of each block can be obtained by applying Newton's second law of motion as follows;

F = ma

m = F/a

where;

When the acceleration is three times as large, the mass of the new block is calculated as;

m = F/3a

m = 1/3 (F/a)

new mass = one-third the initial mass

Thus, we can conclude that when the acceleration is three times as large, the mass of the new block will be one-third the initial mass.

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Answer:

0.5

Explanation:

Answer:

0.539

Explanation:

A) The approximate magnitude of the electric field between points A and B is 1.3 V/cm; B) The ranking from strongest to weakest electric field is B>A>C>D>E>F>P; C) The arrows indicating the electric field at points A, B, C, and D should be drawn perpendicular to the equipotential lines in the direction of decreasing potential.

Equipotential lines are imaginary lines that connect points in a space that have the same electric potential or voltage. They indicate areas of uniform electric potential in an electric field.

(A) To find the approximate magnitude of the electric field between points A and B, we need to use the formula:

E = ΔV / Δd

where ΔV is the potential difference between points A and B, and Δd is the distance between them. We can estimate ΔV by counting the number of equipotential lines between points A and B, which appears to be around 4. The distance Δd is approximately 3.0 cm. Therefore, the approximate magnitude of the electric field between points A and B is:

E = 4 / 3.0 ≈ 1.3 V/cm

(B) To rank the strength of the electric field at points ABCDEFP, we need to look at the spacing between the equipotential lines. The closer the lines are, the stronger the electric field. Based on the diagram, the ranking from strongest to weakest electric field is:

B > A > C > D > E > F > P

This ranking is determined by observing the spacing between the equipotential lines. The electric field is strongest at point B because the equipotential lines are closest together there, indicating a steep potential gradient.

(C) To draw arrows indicating the electric field at points A, B, C, and D, we need to draw the arrows perpendicular to the equipotential lines, in the direction of decreasing potential. The arrows should be longer where the equipotential lines are closer together. Based on the diagram, the arrows should be drawn as follows:

At point A, the arrow should point to the left, because the potential is decreasing in that direction.

At point B, the arrow should point to the left and be longer than the arrow at point A, because the potential gradient is steeper.

At point C, the arrow should point upward, because the potential is decreasing in that direction.

At point D, the arrow should point downward, because the potential is increasing in that direction.

Hence, The electric field between points A and B has an approximate magnitude of 1.3 V/cm; the order of the electric fields from strongest to weakest is B>A>C>D>E>F>P; and the arrows indicating the electric field at each of the four points should be drawn perpendicular to the equipotential lines in the direction of decreasing potential.

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Answer:82. Since you have a distance and a force, then the easiest principle to use is energy, i.e. work.

The work done by friction is F * d. This work cancels out the kinetic energy of the stone (1/2)mv^2

Fd = (1/2)mv^2

F = (1/2)mv^2/d.

Plug in m = 20 kg, v = 3 m/sec, d = 40 m.

83. With more mass, the kinetic energy is higher now. The work needed is higher. W = F * d and F is the same.

Explanation:Hope I helped :)

Answer: it is thin near the center and thick at the edges

Explanation: took the test on Plato :)

The sentences can be completed as follows: Runner A is is faster than Runner B. Runner B has a head start.

The position v/s time graph is very helpful to determine the position of an object with respect to time. The speed of the moving object can be easily calculated from the graph. If the graph is a straight line, then its slope be the speed.

In the given graph, the change in distance with change in time for runner A is greater than that of runner B. Therefore, the speed of runner A is greater than B.

The starting position of B is ahead of A and it is not from origin. . Hence, it can be said that, runner B has a head start.

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A straight piece of wire with a current I flowing through it is placed in a magnetic field

A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the string

A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the stringthere is a way

Answer:

Option B - The fringe spacing will increase

Explanation:

We are given;

Wavelength; λ = 532nm

slit separation; d = 20um

For double-slit experiment, the fringe width is given by the expression;

β = λD/d

Where;

β is the fringe width

λ is the wavelength

D is the distance between the screen and the slit

d is the slit separation

Now, when immersed in water, the slit separation distance will decrease.

Now, from the fringe width equation, when "d" decreases, it means that we will have a bigger value of fringe width.

Thus, as slit separation decreases, the fringe width increases.

The boy throws the ball horizontally. The initial velocity of the ball as it left the boy's hand was approximately 3.72 m/s.

Initial velocity, often represented as v0, is the velocity of an object at the beginning of a time interval or at the start of a motion.

Use the following kinematic equations to arrive at the answer:

Horizontal velocity (Vx) = Distance / Time

Vertical displacement (y) = V0y*t + (1/2)gt²

Vertical velocity (Vy) = V0y + g*t

Tan(theta) = Vy / Vx

where V0y is the initial vertical velocity, g is acceleration due to gravity (9.8 m/s²), and theta is the angle of inclination.

First, let's find the time it takes for the ball to hit the ground. We can use the vertical displacement equation and set y = 0:

0 = V0y*t + (1/2)gt²

Simplifying and solving for t, we get:

t = sqrt((2y) / g)

= sqrt((21.10 m) / 9.8 m/s²)

= 0.472 s

Now, we can use the horizontal velocity equation to find Vx. Since the ball was thrown horizontally, Vx is the same as the initial velocity (V0):

Vx = Distance / Time

= (horizontal distance travelled by ball) / t

We don't know the horizontal distance travelled by the ball, but we can find it using the vertical displacement equation. At the instant the ball hits the ground, its vertical displacement (y) is:

y = V0y*t + (1/2)gt²

= 0 + (1/2)gt²

= (1/2)*9.8 m/s² * (0.472 s)²

= 1.10 m

This means the ball travelled a total distance of:

distance = horizontal distance + vertical distance

= x + 1.10 m

where x is the horizontal distance travelled by the ball. We can find x using the angle of inclination and the vertical displacement:

Tan(theta) = Vy / Vx

Vy = V0y + g*t

Solving for V0y, we get:

V0y = Vy - g*t

Plugging in the numbers, we get:

V0y = Tan(theta) * Vx - g*t

= Tan(30 deg) * Vx - 9.8 m/s² * 0.472 s

= 0.577 * Vx - 4.62 m/s

Now, we can use the vertical displacement equation again to find x:

y = V0yt + (1/2)gt²

= (0.577Vx - 4.62 m/s) * 0.472 s + (1/2)*9.8 m/s² * (0.472 s)²

= 1.10 m

Simplifying and solving for Vx, we get:

Vx = (2y - 0.577V0t) / t

= (21.10 m - 0.577*(0.577*Vx - 4.62 m/s)*0.472 s) / 0.472 s

= 3.72 m/s

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Answer:

2.74

Explanation:

Answer: light from the object

Explanation:

When light is reflected off an object like a lamp or a door is travels in a straight line but in a new direction so if the light enters our eyes we will see the object because our eyes can detect light

Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

There are two correct answers:

A) A corporation leader makes direct payment to the candidate.

D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.

Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.

Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.

I hope this helps! Let me know if you have any other questions.

The centripetal force acting on the small piece of dried cement is 0.01 N   when mass 50 g stuck to the inside wall of mixer.

Any force that alters velocity in the direction toward the center of a circular motion is referred to as a centripetal force. The centripetal force is produced by the portion of the force that is perpendicular to the velocity.

The period of the cement mixer can be calculated as:

                                T = 50 sec/rev

                                     = 2πr/v,

where r is the radius of the mixer and

v is the velocity of the piece of dried cement.

Solving for v, we get v = 2πr/T.

Substituting the given values, we get

                               v = 2π(2.5 m)/(50 sec/rev)

                                         = 0.314 m/s.

The centripetal force acting on the piece of dried cement can be calculated using the formula :

                                     F = m v² / r,

where m is the mass of the cement,

v is the velocity, and

r is the radius of the mixer.

Substituting the given values, we get

                                 F = (0.05 kg)(0.314 m/s)²/(2.5 m)

                                                      = 0.01 N.

Therefore, the centripetal force acting on the small piece of dried cement is 0.01 N.

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Answer:

Explanation:

The work-energy theorem states that the net work done on an object is equal to its change in kinetic energy. Therefore, we can use this theorem to calculate the final kinetic energy of the ball in each case.

We know that the work done by a constant force is given by the equation W = Fd cos(theta), where F is the magnitude of the force, d is the displacement of the ball, and theta is the angle between the force and displacement vectors.

Using the work-energy theorem, we can write:

W = ΔK = Kf - Ki

where ΔK is the change in kinetic energy, Kf is the final kinetic energy, and Ki is the initial kinetic energy.

We can rearrange this equation to solve for Kf:

Kf = Ki + W = Ki + Fd cos(theta)

a) Kf = 150 J + (10 N)(15 m)cos(90°) = 150 J

b) Kf = 300 J + (200 N)(1.5 m)cos(180°) = 0 J

c) Kf = 200 J + (25 N)(4 m)cos(0°) = 300 J

d) Kf = 450 J + (15 N)(30 m)cos(150°) = 112.5 J

Ranking from greatest to least final kinetic energy:

c) Ki=200J F=25N d=4m theta=0 degrees

a) Ki=150J F=10N d=15m theta=90 degrees

d) Ki=450J F=15N d=30m theta=150 degrees​

b) Ki=300J F=200N d=1.5m theta=180 degrees

The work done by the force on the block is approximately 311.2 Joules.

To calculate the work done by the constant force of magnitude F = 45 N over a distance of 8 m at an angle of 30 degrees to the horizontal, we need to find the component of the force that acts parallel to the displacement.

The horizontal component of the force can be calculated using trigonometry:

F_horizontal = F * cos(angle)

            = 45 N * cos(30 degrees)

            = 45 N * (√3 / 2)

            ≈ 38.9 N

Now, we can calculate the work done by the force using the equation:

Work = Force * Distance * cos(theta)

where theta is the angle between the force and the displacement.

Work = F_horizontal * Distance * cos(0)

     = 38.9 N * 8 m * cos(0)

     = 38.9 N * 8 m

     = 311.2 Joules

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A current of a 6 flows through a light bulb for 12 s. The total charge that passes through the light bulb during the given time is 72 coulombs.

To calculate the total charge that passes through the light bulb, we need to use the formula Q = I * t, where Q represents the charge in coulombs, I represents the current in amperes, and t represents the time in seconds.

Step 1: Identify the known values:

Current (I) = 6 amperes

Time (t) = 12 seconds

Step 2: Calculate the charge using the formula:

Q = I * t

Step 3: Substitute the known values into the formula:

Q = 6 amperes * 12 seconds

Q = 72 coulombs

Therefore, the total charge that passes through the light bulb during the given time is 72 coulombs.

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given data

the mass of a hoop with a radius of 1.0m is 6.0kg.

it rolls across a horizontal surface with a speed of 10.0m/s

we know that,

Total energy of the hoop=Translational Kinetic energy+ Rotational Kinetic energy=21mv2+21Iω2

For hoop, I=mr2

Also v= r ω

Thus total energy=21mv2+21mr2(r v)2=mv2

Hence the work required to stop the hoop=Its total energy=mv2=100×0.1J=1J

1JOULE work is required stop to hoop.

What is translational energy?

translational energy (plural translational energies) (physics) The energy of the molecules of a fluid due to motion (translation rather than rotation or vibration).

What is an example of translational kinetic energy?

A train moving along a railroad track, an object in free fall due to gravity, a car driving on a road, the motion of a bullet fired from a gun, or the expansion of a galaxy are examples of translational kinetic energy.

rotational energy

Rotational energy, or angular kinetic energy, is the kinetic energy due to the rotation of an object and is a fraction of its total kinetic energy.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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