The centroid of the human body is typically located slightly below the navel in the lower abdomen.
The center of gravity of a body, on the other hand, is located at the midpoint of the body's weight distribution. Both are different points, and their relative positions can differ depending on the individual's body shape and size.
The centroid of the human body represents the geometric center of the body, whereas the center of gravity represents the point where the entire weight of the body is evenly distributed. If the body is uniform, the centroid and center of gravity coincide.
As a result, the center of gravity of the human body is not always located at the same point as the centroid.
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Q1. Describe the changes to energy stores that take place when the following happen:
a) A ball falls in the air
b) An electric heater is switched on
Answer:
Part A: kinetic energy
Part b: electrical energy
This is because "When the energy is stored it is called electric potential energy and when it is moving in an electric current it is a form of kinetic energy. Our most common form of electrical energy is found in our wall outlets. "(softschools.com)
The change in energy stores that take place when the following happen:
a) A ball falls in the air – kinetic energy.
b) An electric heater is switched on - electrical energy
What is kinetic and electrical energy?Kinetic energy is the energy used in the working of a body. Electrical energy is the energy from by the moving of charged electrons.
The energy that an object has as a result of movement is known as kinetic energy. Perhaps the most significant characteristic of kinetic energy is its capacity for work.
Electric potential energy is the title for the electricity that is stored, while kinetic energy is the word for the power that is traveling in an electric charge. Our wall outlets house the most prevalent type of electrical energy.
Thus, a = kinetic energy, b = electrical energy.
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A resistor, an inductor, and a capacitor are connected in series to an ac source. What is the phase angle between the voltages of the inductor and capacitor in this rlc circuit?.
If a resistor, an inductor and a capacitor are connected in series, the phase angle between the voltages of the inductor and capacitor in a RLC series circuit is 180 degrees.
A resistor , capacitor and inductor are key components of a RLC circuit. Resistor doesn't store energy but capacitor and inductor stores energy and that is the reason resistor is called a passive element and inductor and capacitors are called active element.
Inductor leads the current by a phase angle of 90 degrees and the voltage across the capacitor lags the current by 90 degrees, so the phase difference between the voltages of the inductor and the capacitor is 180 degrees in an RLC circuit.
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Which is a “big idea” for matter and change?
which of the following processes use mechanical energy as their principal energy source
The processes that use mechanical energy as the principal energy source are Conventional milling, Ultrasonic machining,Water jet cutting So option c,d & e are correct.
The processes that use mechanical energy as the principal energy source are:
Conventional milling: In conventional milling, mechanical energy is used to rotate the milling cutter, which removes material from the workpiece.
Ultrasonic machining: Ultrasonic machining utilizes mechanical vibrations to remove material from the workpiece. Ultrasonic energy is converted into mechanical energy to produce high-frequency vibrations that aid in material removal.
Water jet cutting: Water jet cutting employs high-pressure water streams to cut through various materials. The energy source is mechanical, as pumps are used to generate and propel the high-pressure water.
Therefore option c,d & e are correct.
1 Which of the following processes use mechanical energy as the principal energy source (three correct answers):
(a) electrochemical grinding
(b) laser beam machining
(c) conventional milling
(d) ultrasonic machining
(e) water jet cutting
(f) wire EDM
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1) what is the potential energy at the end of the loop?
2)what is the kinetic energy at the end of the loop(based upon photogate time?
release the car and record the time from the photogate at the bottom of the hill and answer the top questions:
i attached an image that shows the recorded time
The potential energy at the end of the loop is equal to 0.3407 Joules.
Given the following data:
Mass of rock = 102.16 g to kg = 0.10216 kilogram.Height of the loop = 34 cm to m = 0.34 meter.Acceleration due to gravity = 9.8 \(m/s^2\)What is potential energy?Potential energy (P.E) refers to the energy that is possessed by an object due to its position (height) above planet Earth.
Mathematically, potential energy (P.E) is given by this formula;
\(P.E = mgh\)
Where:
m is the mass of an object.g is the acceleration due to gravity.h is the height of an object.Substituting the given parameters into the formula, we have;
\(P.E = 0.10216 \times 9.81 \times 0.34\)
P.E = 0.3407 Joules.
What is kinetic energy?Kinetic energy (K.E) refers to an energy that is possessed by a physical object due to its motion.
Mathematically, kinetic energy (K.E) is given by this formula;
\(K.E = \frac{1}{2} MV^2\)
Note: You'll have to calculate the velocity from the distance traveled by the car and photogate time in your experiment.
Based on the law of conservation of energy, we can deduce the following points:
Potential energy (P.E) is highest at the top of the loop while kinetic energy (K.E) is lowest.Kinetic energy (K.E) is highest underneath the loop while potential energy (P.E) is lowest.Read more on potential energy here: https://brainly.com/question/8664733
A car travels 500m in 20 seconds. What is its speed?
sentence answers please
Answer:
Distance traveled by car =500m
Time taken =20s
Speed = distance/time = 500/20=25m/s
I Hope its help for you
Have a good day
Highway safety engineers build soft barriers along the sides of highways so that cars hitting them will slow down at a safe rate. Suppose a car traveling at 110 km/h hits the barrier, and the barrier decreases the car’s velocity at a rate of 32 m/s2. What distance would the car travel along the barrier before coming to a stop?
The distance the car would travel when it hit the barrier before coming to a stop is 14.6 m.
What is the distance travelled by the car?The distance travelled by the car before stopping is calculated by applying third kinematic equation as shown.
v² = u² - 2as
where;
v is the final velocity of the car u is the initial velocity of the cara is the acceleration of the cars is the distance travelled by the carwhen the car stops, the final velocity will zero, v = 0
0 = u² - 2as
2as = u²
s = u²/2a
The given parameter;
initial velocity of the car, u = 110 km/h = 30.56 m/s
a = 32 m/s²
s = (30.56²) / (2 x 32)
s = 14.6 m
Thus, when the car hits the soft barrier, it will slow down and travel a distance of 14.6 m before coming to rest.
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s the elastic potential energy stored in the pole of a pole vaulter the only the only type of potential energy involved in pole-vaulting? group startsyes or noyes, unselectedno, unselected
No, the elastic potential energy stored in the pole of a pole vaulter is not the only type of potential energy involved in pole-vaulting.
In pole-vaulting, there are multiple forms of potential energy involved. While the elastic potential energy stored in the pole plays a crucial role, other forms of potential energy include gravitational potential energy and kinetic energy.
1. Elastic Potential Energy: The pole used in pole-vaulting is typically made of flexible materials, such as fiberglass or carbon fiber, which store elastic potential energy when bent or compressed. This stored energy is then released, propelling the vaulter upwards.
2. Gravitational Potential Energy: As the vaulter reaches the highest point of their vault, they have gained gravitational potential energy due to their increased height above the ground. This potential energy is converted into other forms of energy as the vaulter descends.
3. Kinetic Energy: Throughout the vaulting process, the vaulter's body also possesses kinetic energy, which is the energy of motion. The vaulter's initial speed and subsequent acceleration contribute to their kinetic energy, allowing them to gain momentum and clear the bar.
Therefore, while the elastic potential energy stored in the pole is an important component, there are other forms of potential energy involved in pole-vaulting, namely gravitational potential energy and kinetic energy.
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a person experiences a sound of intensity of 0.25w/m^2 at a distance of 10m from a speaker. what is the power output of the speaker?
As we don't have the final distance, we can't determine the exact power output of the speaker.
To determine the power output of the speaker, we need to use the inverse square law for sound intensity. The inverse square law states that the intensity of sound decreases as the square of the distance from the source increases.
The formula for the inverse square law is: I₁ / I₂ = (r₂ / r₁)²
where:
I₁ = initial intensity (0.25 W/m²)
I₂ = final intensity (unknown, to be determined)
r₁ = initial distance (10 m)
r₂ = final distance (unknown, to be determined)
Rearranging the formula, we have:
I₂ = (r₂ / r₁)² * I₁
Plugging in the given values:
I₂ = (r₂ / 10)² * 0.25 W/m²
Since we don't have the final distance, we can't determine the exact power output of the speaker. The power output of the speaker is not solely dependent on the distance but also on other factors such as the speaker's efficiency and design
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A swing is moving. You find out that it takes two seconds for the storm to complete one cycle. What is the period of the swing? What is the frequency of the swing?
The period of the storm is 2s
The frequency of the storm is 0.5 Hz
What is the period?When we talk about the period, what we mean is the time that it would take to complete a cycle. In this case, we have to be looking at the question that we have. We are told that it takes two seconds for the storm to complete one cycle. This means that the period of the storm is 2s.
The frequency would be the inverse of the period so we can have that;
Frequency = 1/Period
Frequency = 1/2
= 0.5 Hz as shown
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If it takes two seconds for the swing to complete one cycle, the period of the swing is the time it takes to complete one cycle, which in this case is 2 seconds.
To find the frequency of the swing, you need to calculate the number of cycles completed in one second. Frequency is the reciprocal of the period, so to find the frequency, you can use the formula:
Frequency = 1 / Period
In this case:
Frequency = 1 / 2 seconds = 0.5 Hz (Hertz)
So, the period of the swing is 2 seconds, and the frequency of the swing is 0.5 Hz.
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Part A: Explain why x = 5 makes 4x − 1 ≤ 19 true but not 4x − 1 < 19. (5 points) Part B: What value from the set {6, 7, 8, 9, 10} makes the equation 5x + 2 = 47 true? Show your work. (5 points)
Answer:
A: ≤ means less than OR equal to. < only means less than
B: 9
Explanation:
A: Because it would equal 19, and 19 is EQUAL than 19. 4(5) - 1 would equal 19, which is equal to 19, and not less than. ≤ means less than or equal to. < means less than. So its not true.
B: 47 - 2, 45. Then 5 x 9 equals 45. So 5 x 9 equals 45, then add 2 would equal 47.
Hope this helps <3
The inequality 4x − 1 ≤ 19 has less than or equal sign but the inequality 4x − 1 < 19 has only less than sign. The equation 5x + 2 = 47 is satisfied, for x = 9.
What is inequality?Inequality is simply a type of equation that does not have an equal sign in it. Inequality is defined as a statement about the relative size as well as is used to compare two statements.
Part A: Explain why x = 5 makes 4x − 1 ≤ 19 true but not 4x − 1 < 19.
The inequality 4x − 1 ≤ 19 is satisfied by 5 because the inequality has less than or equal sign but the inequality 4x − 1 < 19 has only less than sign so for x = 5, the value is equal to 19 which is not true.
Part B: The value from the set {6, 7, 8, 9, 10} makes the equation 5x + 2 = 47 true.
By simplifying the equation, then we have
5x + 2 = 47
5x = 45
x = 9
The equation is satisfied, for x = 9.
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Size of the Milky Way The speed of light is about 186,000 miles per second. The Milky Way galaxy has an approximate diameter of 6×10¹⁷ miles. Estimate, to the nearest thousand, the number of years it takes for light to travel across the Milky Way. (Source: C. Ronan, The Natural History of the Universe.)
The time it takes for light to travel across the Milky Way galaxy is approximately 102,000 years (to the nearest thousand)
The speed of light is 186,000 miles per second. The Milky Way galaxy has an approximate diameter of 6 × 10¹⁷ miles. Therefore, we can estimate the time it takes for light to travel across the Milky Way by dividing the distance by the speed of light. Using this formula, we can say that:
Time taken for light to travel across the Milky Way galaxy= 6 × 10¹⁷ miles/186,000 miles per second= 3.23 × 10¹² seconds.1 year has 365.25 days, and each day has 24 hours, each hour has 60 minutes and each minute has 60 seconds.
So the number of seconds in one year = 365.25 days × 24 hours × 60 minutes × 60 seconds= 31,536,000 seconds.
Therefore, we can determine the time it takes for light to travel across the Milky Way in years by dividing the time taken by the number of seconds in a year, as follows:
3.23 × 10¹² seconds/31,536,000 seconds per year= 1.02 × 10⁵ years.
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An Amplitude Modulated signal comprised of the following two signals: v
i
(t)=90cos(2π500t)V v
c
(t)=100cos(2π100000t)V a) Find the modulation index (m) b) Find the carrier frequency, upper and lower-side band frequencies c) If v
i
(t)=120cos(2π500t)V, calculate the percentage modulation and explain the effects on the AM
A) The modulation index is undefined. B) The lower-side band (LSB) frequency is 99,500Hz. C) Percentage modulation = 20%
a) The modulation index (m) may be calculated through the usage of the formulation:
m = (Vmax - Vmin) / (Vmax + Vmin)
where Vmax and Vmin are the most and minimum amplitudes of the modulating signal, respectively.
In this case, the modulating sign is vi(t) = 90cos(2π500t) V. The most amplitude (Vmax) is 90 V, and the minimum amplitude (Vmin) is -90 V (for the reason that the cosine feature varies between -1 and 1).
Therefore, the modulation index is:
m = (Vmax - Vmin) / (Vmax + Vmin) = (90 - (-90)) / (90 + (-90)) = 180 / 0 = undefined
b) The carrier frequency is fc =100,000 Hz.
The higher-aspect band (USB) frequency is given via:
fUSB = fc + fm =100,000 Hz + 500 Hz = 100,500 Hz
The decrease-aspect band (LSB) frequency is given by way of:
fLSB = fc - fm = 100,000 Hz - 500 Hz = 99,500 Hz
c) If vi(t) = 120cos(2π500t) V, we will calculate the share modulation using the components:
Percentage modulation = (Vm - Vc) / Vc * 100%
in which Vm is the peak amplitude of the modulating sign and Vc is the peak amplitude of the service signal.
In this situation, Vm = 120 V and Vc = 100 V.
Percentage modulation = (Vm - Vc) / Vc * 100% = (120 - 100 ) / 100 * 100% = 20%
Increasing the modulation amplitude increases the percentage modulation. This outcome is in a larger version within the amplitude of the AM signal, which could result in extended sidebands and a more said modulation impact. The audio content of the modulating signal turns more distinguished, ensuing in a more potent modulation effect inside the AM signal.
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Question 5 of 10
Which option is an example of a conceptual model?
A. A clay ball with a slice cut out, showing the layers of Earth
B. A mental image of gas molecules as tiny balls
C. A diagram of a flagpole and its shadow with measurements
provided to calculate the length of the shadow
D. A weather map created by Doppler radar
Answer:
B. A metal image of gas molecules as tiny balls
Answer:
B. A mental image of gas molecules as tiny balls
Calculate the energy per photon (in J) associated with a frequency of 1260kHz Submit answer in scientific notation using the foat 0.00×10∧ 0(e.g.0.000123=1.23×10 ∧
−4). Omit units and spaces.
The energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.
To calculate the energy per photon, we can use the equation: E = hf, where E represents the energy, h is the Planck's constant (6.62607015 × 10^-34 J·s), and f is the frequency of the photon. Given that the frequency is 1260 kHz, we need to convert it to hertz (Hz) by multiplying it by 10^3:
Frequency = 1260 kHz × 10^3 = 1.26 × 10^6 Hz
Now, we can substitute the values into the equation:
E = (6.62607015 × 10^-34 J·s) × (1.26 × 10^6 Hz)
E = 8.33929859 × 10^-28 J
The answer is given in scientific notation as 8.34 × 10^-28 J. However, the question specifically asks for the answer in the format of 0.00×10^0. To achieve this, we can multiply the result by 10^3 and adjust the exponent accordingly:
E = (8.33929859 × 10^-28 J) × (10^3)
E = 8.33929859 × 10^-25 J
Thus, the energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.
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There is a bell at the top of a tower that is 40m high. The bell weighs 12kg. The bell has ___________________ energy. Calculate it.
Answer:
Potential
Explanation:
hope this helps
A speedy tortoise can run at 0.11 m/s, and a hare can run 19 times as fast. In a race, they start at the same time, but the hare stops to rest for 2 min, so the tortoise wins by a shell (20 cm). How long does the race take
The Time taken for the race is 36 minutes and 22 seconds.
Given the speed of tortoise is 0.11 m/s and the speed of hare is 19 times faster than that of tortoise. So the speed of hare is 19*0.11 = 2.09 m/s.At the start of the race both tortoise and hare start at the same time, so at the point where the hare stops to rest for 2 minutes, tortoise would be ahead of hare by a distance of (20/1000) km.Now hare resumes running and tries to overtake tortoise, let’s say it overtakes tortoise after t seconds. So we have:0.11t + 0.0209(t-120) = 0.2 km. Solving for t gives us t = 2176/1101 hours, which is approximately equal to 1.975 hours.The total time taken by the hare and tortoise is 1.975 hours + 2 minutes, which is equal to 36 minutes and 22 seconds.Thus, the race takes 36 minutes and 22 seconds.
The time taken for the hare and tortoise to complete the race is approximately 36 minutes and 22 seconds.
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A discordant igneous intrusion
Select one:
a.
cuts across bedding planes.
b.
will consist dominantly of pyroclasts.
c.
parallels sedimentary rock layering.
d.
produces deadly explosions.
A discordant igneous intrusion cuts across bedding planes. Here is the detailed explanation of the given question:Explanation:The Discordant igneous intrusion is the formation of an igneous rock mass when magma is injected into a host rock and cools there.
This form of igneous intrusion does not conform to the stratification or layering of the existing rock mass because it cuts across it.Therefore, a discordant igneous intrusion cuts across bedding planes.Option (a) is correct. It is the only option that describes the features of discordant igneous intrusion. Hence, the correct answer is option (a).
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compare and contrast nuclear fusion and nuclear fission. please use proper grammar and mechanics.
Answer:
The main difference between the two is - nuclear fusion results in fusing many smaller atoms into one, while in nuclear fission, the atom splits into two or more smaller ones.
Explanation:
Firstly, "fusion" generally means combining many things to one, while "fission" refers to breaking down one thing into different components. Also, nuclear fission is not common in nature, while nuclear fusion does (like in stars, for example).
In the arrangements A and B shown in figure, pins P and Q are fixed to a metal loopand an iron rod with the help of wax. In which case are both the pins likely to fall atdifferent times? Explain
Answer:
first one
Explanation:
A track and field athlete is competing in the hammer throw event. The athlete is 181cm tall, with an arm length of 90 cm and is using a standard ball and chain for the event which is 121cm long. As the athlete begins to spin , their body becomes the center of the motion, with both arms holding on to the ball and chain handleIf the initial linear ve locity of the ball and chain is 29m/s upon its release, how fast (total angular velocity rads) was the athlete spinning it
Total angular velocity is 13.7 rad/s.
Given that an object is moving in a circular motion, we can infer that the system involving the athlete, the ball, and the rope is also moving in a round fashion.
We are informed that the athlete is 181 cm tall, has a 90 cm arm span, and will be using a 121 cm long ball and chain for the competition. With both arms hanging on to the ball and chain handle as the athlete starts to spin, their body becomes the centre of the action. The ball and chain's initial linear velocity is 29 m/s when it is released.
The radius of the path= 90 cm + 121 cm
= 211cm or 2.11 m
Using;
linear velocity = radius * angular velocity
V = rω
ω = V/r
ω = 29m/s/2.11 m
ω = 13.7 rad/s
angular velocity of athlete is 13.7 rad/s
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when a student shines a 480 nm laser through this grating, how many bright spots could be seen on a screen behind the grating?
Depending on the spacing of the grating, there can be up to four bright spots seen on the screen behind the grating.
A grating is composed of multiple lines that are etched onto a surface, and when a light passes through these lines, it is split into its component wavelengths. Since the laser is 480 nm, the diffracted light will be composed of 480 nm light.
When light is shone through a grating, it diffracts and produces a pattern of bright spots and dark fringes on a screen placed behind the grating.
Depending on the spacing of the grating, there can be up to four bright spots seen on the screen behind the grating.
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a guitar string is 90.0 cm long and has a mass of 3.00 g . from the bridge to the support post (=ℓ) is 60.0 cm and the string is under a tension of 533 n .What are the frequencies of the fundamental and first two overtones?
to find the frequencies of the fundamental and the first two overtones for the guitar string with given parameters.
First, let's determine the linear density (μ) of the string:
μ = (mass of the string) / (length of the string)
μ = (3.00 g) / (90.0 cm)
μ = 0.0333 g/cm (convert to kg/m for SI units)
μ = 0.00333 kg/m
Next, we need to find the wave speed (v) on the string:
v = √(Tension / Linear Density)
v = √533 N / 0.00333 kg/m)
v = √(160060.060060 N/kg)
v = 400 m/s
Now we can calculate the frequencies of the fundamental (f1) and the first two overtones (f2 and f3) using the formula:
f = (n × v) / (2 × L)
For the fundamental (n = 1) and the effective length L=60.0 cm (0.6 m):
f1 = (1 × 400 m/s) / (2 × 0.6 m) = 333.33 Hz
For the first overtone (n = 2):
f2 = (2 × 400 m/s) / (2 × 0.6 m) = 666.67 Hz
For the second overtone (n = 3):
f3 = (3 × 400 m/s) / (2 × 0.6 m) = 1000 Hz
In conclusion, the frequencies of the fundamental and the first two overtones for the given guitar string are approximately 333.33 Hz, 666.67 Hz, and 1000 Hz, respectively.
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a man paddles a canoe in a long, straight section of a river. the canoe moves downstream with constant speed 4 m/s relative to the water. the river has a steady current of 1 m/s relative to the bank. the man's hat falls into the river. eight minutes later, he notices that his hat is missing and immediately turns the canoe around, paddling upriver with the same constant speed of 4 m/s relative to the water. how long does it take the man to row back upriver to reclaim his hat?
it takes the man 160 seconds or 2 minutes and 40 seconds to row back upriver to reclaim his hat.
The speed of the river's current is 1 m/s, and the canoe's speed relative to the water is 4 m/s downstream. Thus, the man paddles a canoe in a long, straight section of the river. The speed of the man relative to the bank is 4 - 1 = 3 m/s upstream.
The distance that the hat floats downstream during the eight-minute interval is equal to the product of the speed and time:
distance = speed x time= 1 m/s x (8 x 60 s) = 480 m.
The man must paddle back upstream to recover the hat. Since the distance to the hat is 480 meters, he will have to paddle 480 meters upstream. Let's use the formula for velocity and distance;
time = distance / velocity
In this instance, since he is paddling upstream, his velocity is the difference between the speed of the canoe relative to the water and the velocity of the river's current. Thus, his velocity is 4 - 1 = 3 m/s.
Using the formula, we obtain:
time = 480 m / 3 m/s
time = 160 s
Therefore, it takes the man 160 seconds or 2 minutes and 40 seconds to row back upriver to reclaim his hat.
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determine the total angular momentum of the two-disk system after the smaller disk is dropped on the larger one.
The total angular momentum of the two-disk system after the smaller disk is dropped on the larger disk is \(\omega _2 = (I_1\times \omega _1) / (I_1 + m_2 \times r^2)\).
The total angular momentum of the two-disk system after the smaller disk is dropped on the larger one will depend on the initial angular momenta of the two disks and any changes that occur when they collide.
Assuming the system is isolated, the total angular momentum before and after the collision must be conserved. Before the collision, we can assume that the smaller disk has an initial angular momentum of zero since it is not rotating, and the larger disk has an initial angular momentum given by:
\(L_1 = I_1 \times \omega_1\)
where \(I_1\) is the moment of inertia of the larger disk and ω₁ is its initial angular velocity.
When the smaller disk is dropped onto the larger one, there will be a transfer of angular momentum from the smaller disk to the larger one. The final angular velocity of the combined system will depend on the moment of inertia of the combined system, which can be approximated as:
\(I_2 I_1 + m_2 \times r^2\)
Where m_2 is the mass of the smaller disk and r is the distance from the center of the larger disk to the point where the smaller disk makes contact. We assume that the collision is elastic and that no external forces act on the system, so angular momentum is conserved:
\(L_1 = L_2\)
\(I_1 \times \omega _1 = (I_1 + m_2 \times r^2) \times \omega _2\)
Solving for ω₂, we get:
\(\omega _2 = (I_1\times \omega _1) / (I_1 + m_2 \times r^2)\)
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Part E
List several examples of drag, elastic force, and tension force that you've observed in your life.
Various examples of drag, elastic and tension forces are mentioned.
What is elastic and tension force?Elastic force is a type of force that occurs when an object is stretched or compressed, and it resists the deformation of the object. This force is proportional to the amount of stretching or compression, and it causes the object to return to its original shape when the force is removed.
Tension force is a type of force that is transmitted through a string, rope, wire or cable when it is pulled tight by forces acting at either end. This force acts to transmit the tension through the length of the string, keeping it taut and preventing it from breaking.
What is an example of drag that is observed in life?A person biking into a headwind experiences air resistance, which is a type of drag force.
What is an example of elastic force observed in life?A stretched rubber band or a compressed spring both exhibit elastic force.
What is an example of tension force observed in life?A person pulling a wagon by a rope exerts a tension force on the rope. Another example of tension force can be observed when a weight is hung from a rope or chain, creating tension within the rope or chain.
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What value of resistor R gives the circuit in the figure a time constant of 22 μs ?
The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.
The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:
RC = τ, where R is the resistance and C is the capacitance of the circuit.
Rearranging the above formula, we get:R = τ / C
Where τ is the time constant and C is the capacitance of the circuit.
From the figure, the capacitance is given as 0.1 μF
.Substituting the values of τ and C in the above formula, we get:
R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)
R = 220 Ω
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An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.
I suggest that the students move forward with option A.
Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.
If an object is dropped from 10 m above the ground, what is the height at which its kinetic energy and potential energy are equal?
potential energy is converted to kinetic energy as the ball drops.
they will be equal at the halfway point.
answer: 5 m
What is an effect of continental drift?
Answer: An effect of continental drift is causing tectonic plates resting upon the convecting mantle to move which results in natural disasters like earthquakes, volcanic eruptions, and more.