Where on the x-axis can a third positive charge be placed so that the net electric force on it is zero?
Answers
A third positive charge \(x = \frac{2\sqrt{2}a }{1+\sqrt{2} }\) can be placed on the x-axis so that the net electric force on it is zero.
whilst -factor charges are in touch, there may be
\(F = k \frac{q_{1}q_{2} }{ r^{2} }\)
Where
\(k = 9 * 10^{9} Nm^{2}C^{-1}\) = the coulomb constant.
The charges' magnitudes are \(q_{1}\) and \(q_{2}\).
r is the separation of the charges.
Let,
The third charge equals Q at, x equals x from the source.
because there is no net force acting on the third charge.
Hence,
\(f_{1} + f_{2} = 0\)
⇒ \(k\frac{(2q)Q}{x^{2} }-k\frac{qQ}{(2a-x)^{2} } = 0\)
⇒ \(\frac{2}{x^{2} } - \frac{1}{(2a-x)^{2} } = 0\)
⇒ \(\frac{2}{x^{2} } = \frac{1}{(2a-x)^{2} }\)
⇒ \(\frac{\sqrt{2} }{x} = \frac{1}{2a-x}\)
⇒ \(2\sqrt{2}a - \sqrt{2} = x\)
⇒ \(x = \frac{2\sqrt{2}a }{1+\sqrt{2} }\)
handiest when forces resulting from previous prices cancel every different out will the pressure on a third fee be 0.
at the same time as the pressure between identical costs is repulsive and is interpreted as high-quality, the pressure between two opposing expenses is attracted and is interpreted as bad.
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Related Questions
four friends argued about why an apple on the ground eventually ros away and disappears. This is eventually what they said
Anna:"I think it's just something that happens over time
Selma: "I think small organisms use it for energy building material"
Felicia: I think the atoms and molecules in the Apple just break apart
Logan: I think wind and water soften it and it dissolves into the soil
Eli: I think water and air rot into it then small animals come and eat the rest
jack: I think it gets old and breaks apart into pieces too small to see
which student do you agree most with explain_________
Answers
Answer:
All but felicia are right I believe?
Explanation:
a tank is 10 m long, 4 m wide, 4 m high, and contains kerosene with density 820 kg/m3 to a depth of 3.5 m. (use 9.8 m/s2 for the acceleration due to gravity.) (a) find the hydrostatic pressure (in pa) on the bottom of the tank. incorrect: your answer is incorrect. pa (b) find the hydrostatic force (in n) on the bottom of the tank. n (c) find the hydrostatic force (in n) on one end of the tank. n
Answers
(a) The hydrostatic pressure is 28,490 Pa.
(b) At the bottom the force is 1,139,600 N.
(c) At the end the force is 1,621,200 N.
What is(a) The hydrostatic pressure (in pa) on the bottom of the tank(b) The hydrostatic force (in n) on the bottom of the tank. (c) The hydrostatic force (in n) on one end of the tank.(a) To find the hydrostatic pressure on the bottom of the tank, we can use the formula:
P = ρgh
where P is the pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the height of the liquid column.
The height of the liquid column is 3.5 m, and the density of kerosene is 820 kg/m3. The acceleration due to gravity is 9.8 m/s2. Therefore, we have:
P = 820 kg/m3 * 9.8 m/s2 * 3.5 m = 28,490 Pa
So the hydrostatic pressure on the bottom of the tank is 28,490 Pa.
(b) To find the hydrostatic force on the bottom of the tank, we can use the formula:
F = PA
where F is the force, P is the pressure, and A is the area. The area of the bottom of the tank is:
A = 10 m * 4 m = 40 m2
Using the pressure we found in part (a), we have:
F = 28,490 Pa * 40 m2 = 1,139,600 N
So the hydrostatic force on the bottom of the tank is 1,139,600 N.
(c) To find the hydrostatic force on one end of the tank, we need to first find the pressure on that end. The pressure on any point of the tank is given by:
P = ρgh
where h is the vertical distance from the point to the surface of the liquid.
The pressure on one end of the tank will depend on the distance of that end from the surface of the liquid. Let's assume that the end we are interested in is at the same level as the surface of the liquid. Then the pressure on that end is simply the atmospheric pressure, which we will assume is 101,325 Pa.
The area of one end of the tank is:
A = 4 m * 4 m = 16 m2
Using the pressure we found and the area of the end, we have:
F = 101,325 Pa * 16 m2 = 1,621,200 N
So the hydrostatic force on one end of the tank is 1,621,200 N.
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how would you change q1 (keeping q2 and q3 fixed) in order to make the electric field at point p equal to zero?
Answers
To make the electric field at point P equal to zero, you would need to change the charge of Q1 while keeping the charges of Q2 and Q3 fixed.
The electric field at point P is determined by the sum of the electric fields due to each charge. Therefore, if the charge of Q1 is changed so that the electric field due to it is in the opposite direction of the electric fields due to Q2 and Q3, then the total electric field at point P will be equal to zero.
An electric field is a vector field that is created by a charged particle or object. It is a measure of the force that the particle or object exerts on other charged particles or objects in its vicinity. Electric fields have both magnitude and direction, and they can be represented by lines of force. The electric field is proportional to the magnitude of the charge.
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The position of a point during the interval of time from t = 0 to t = 6 s is given by s = -2/3 t³ + 6t² +2t m. (a) What is the maximum velocity during this interval of time, and at what time does it occur? (b) What is the acceleration when the velocity is a maximum? {20 m/s, 0 m/s²}
Answers
The maximum velocity during this interval of time is approximately 20 m/s, and it occurs at t ≈ 3 + √10 seconds.
To find the maximum velocity and the time at which it occurs, we need to differentiate the position function with respect to time.
Given: s = -2/3 t³ + 6t² + 2t
(a) To find the maximum velocity, we differentiate the position function to get the velocity function: v = ds/dt
Taking the derivative of the position function, we have:
v = d/dt (-2/3 t³ + 6t² + 2t)
v = -2t² + 12t + 2
To find the maximum velocity, we set the derivative equal to zero and solve for t: -2t² + 12t + 2 = 0
We can solve this quadratic equation using the quadratic formula:
t = (-b ± √(b² - 4ac)) / (2a)
Substituting the values into the formula, we get:
t = (-12 ± √(12² - 4(-2)(2))) / (2(-2))
t = (-12 ± √(144 + 16)) / (-4)
t = (-12 ± √160) / (-4)
t = (-12 ± 4√10) / (-4)
t = 3 ± √10
Since we're looking for the time during the interval from t = 0 to t = 6 s, we discard the negative root: t = 3 + √10
So, the maximum velocity occurs at t = 3 + √10 seconds.
To find the maximum velocity, substitute the value of t into the velocity function: v = -2(3 + √10)² + 12(3 + √10) + 2
v ≈ 20 m/s
Therefore, the maximum velocity during this interval of time is approximately 20 m/s, and it occurs at t ≈ 3 + √10 seconds.
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Directions: Follow the steps below to help you understand electrical charges.
Materials
You will need: a plastic bag, two long rubber bands, a thin aluminum pie tin, a wool scarf or glove, and a friend or family member to assist you.
• STEP 1: Stretch the rubber bands across the pan-they should cross one another. Lay the bag flat on the table and rub it several times with the wool.
• STEP 2: With one hand, lift the pan by the rubber bands; be sure to keep your fingers from touching the pan,
• STEP 3: Bring the pan and the bag together. While they are together, ask someone to touch the pan quickly. What happens?
• STEP 4: Now take the pan away from the bag, still keeping your fingers from touching the pan. Right away, bring the pan up to your nose. What do you feel?
What do you hear?
• STEP 5: Now complete Steps 1-4 again, but do them in a dark room or closet. Ask a friend or family member to be in the room with you-what did he or she see
when you brought the pan to your nose?
Using the Text Editor, explain your observations and what happened during this experiment. What was happening to the electrical charges during the experiment and
why?
Answers
In this experiment, rubbing a plastic bag against wool allowed electrons to move back and forth between the two, creating a negative charge on the bag. When the negatively charged bag was brought close to the neutral PAN, the bag's negative charge attracted the PAN's electrons, separating the two charges and leaving the PAN with a positive charge. On touching the pan the surplus positive charge was neutralized, creating a spark.
When the pan was brought up to the nose a slight jolt was felt and a crackling sound was heard. This resulted in the excess charge in the pan being carried through the air to the nearest conductor, the person holding the pan.
The spark and shock were easy to see in a dark environment as there was no ambient light to obstruct the view. The blow was more pronounced and distinct, and the spark appeared as a bluish glow.
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A stuntman drives a car off of a parking garage. The car lands 68.38 meters away from the base of the garage. If the stuntman drove the car at 19 m/s, how tall is the parking garage?
Answers
Answer: 63.43 m
Explanation:
Given
Car lands 68.38 m away from the base of the garage
Stuntman drove the car with speed \(u=19\ m/s\)
Since there is no acceleration in the horizontal direction, so there is no change in velocity
\(\Rightarrow 68.38=19\times t\\\Rightarrow t=3.598\ s\)
time taken to cover 68.38 m is 3.598 s
In this time car travels a vertical distance of h
Such that we can write
\(\Rightarrow h=u_vt+\frac{1}{2}at^2\\\\\Rightarrow h=\frac{1}{2}gt^2\\\\\Rightarrow h=0.5\times 9.8\times (3.598)^2=63.43\ m\)
Calculate the direction cosines of a→+b→, given that a→=4i^+7j^-5k^ and b→=3i^+4j^+k^
Answers
The direction cosines of a→+b→, are
cos ∝ = 0.5232 cos β = 0.8065 cos γ = 0.2933Given data:
a = 4i^ + 7j^ - 5k^
b= 3i^ + 4j^ + k^
Calculate the direction cosines of a→+b→a→+b→ = 7i + 11j - 4k
( a→+b→ ) / | a→+b→ | = ( 7i + 11j - 4k ) / \(\sqrt{7^2 + 11^2 + 4^2 }\)
= ( 7i + 11j - 4k ) / 13.64
= 0.5232 i + 0.8065 j + 0.2933 k
Therefore the direction cosines are
cos ∝ = 0.5232
cos β = 0.8065
cos γ = 0.2933
Hence we can conclude that the direction cosines of a→+b→ are as listed above.
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You arrive in science class 45 seconds after leaving math which is 90 meters to the south. What is your velocity?
Answers
Explanation: Well, If you arrive in my class 45 seconds after leaving math, which is 90 meters away. you traveled 2m/s ( I hope this helped <3)
● Describe what Neptune needs to sustain life.
● Describe the current conditions of Neptune. How is it there?
● What is the final recommendation for the humans living on Neptune? Explain.
Answers
Answer:
1)the planet would need to have a source of energy that bacterial life can exploit, as well as a standing source of liquid water. At its surface, the temperature of Neptune dips down to 55 Kelvin. That's very cold, and there's no way liquid water could exist.
2)Neptune has the wildest and strangest weather in the entire Solar System. It has huge storms with extremely high winds. Its atmosphere has dark spots which come and go, and bright cirrus-like clouds which change rapidly. Neptune has an average temperature of -353 Fahrenheit (-214 Celsius).
3)To find life on Neptune, the planet would need to have a source of energy that bacterial life can exploit,
as you take a short canoe trip on the Brazos River you paddle your canoe 200 miles up the river in 420 seconds and then turn around and paddle 350 miles down the river in 280 seconds what was your average speed during your canoe trip in miles per second
Answers
350 mile/280 secs = 5/4
(5/4+10/21)/2= 145/168 miles per sec
or .86 miles/sec
g You have two small charges 1.00 m apart. Q1 is positive, on the left, and Q2, on the right, is negative. Their values are 3 uC and -4 uC. At what distance, in m, along the line between them from the left charge will the potential equal zero
Answers
The electric potential due to two charges is given by V = kq1q2/r where k = Coulomb constant = 9 × 109 Nm2/C2, q1 and q2 are charges of the two charges and r is the distance between them. Let the position of the point where electric potential is zero on the line joining two charges from the positive charge q1 is x.
Distance of positive charge from the point is d1 = x Distance of negative charge from the point is d2 = 1m - xPotential at this point is V = 0. We know the charges q1 and q2. Therefore, we can solve the above equation to get x, which is the distance of the point from the positive charge.
Hence, it is not possible to calculate the position of the point where the potential is zero as the result is undefined. Therefore, we can say that at any distance on the line between the charges, the electric potential due to them will not be zero.
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Need help asap! you are the star soccer player and you are late to your game. Everyone is happy to see you and wants you to jump in and play. The safest thing to do in this situation is to
avoid the coach since you were late
go back home to avoid injury and ridicule
jump in and play to make up for being late
warm up your muscles before playing
Answers
Answer:
c and d
what i would do is ask the coach if you could take a minute to stretch and as soon as posible jump into the game
Explanation:
i play soccer lol
Answer: i'm pretty sure its warm up your muscles before playing
Explanation:
if you don't u get hurt.
which group represents stars fusing hydrogen in their cores?
Answers
The group of stars that represents stars fusing hydrogen in their cores is known as the main sequence. This is the phase in a star's life cycle where the fusion of hydrogen into helium occurs in the stellar core.
Main sequence stars are the term used to describe the class of stars that fuse hydrogen in their centres. These stars, like our Sun, are in a stable stage of their evolution when the pressure from nuclear fusion reactions acting outside the star balances the gravitational pull coming from within. Protons unite to create helium nuclei during a process known as proton-proton fusion, which releases enormous amounts of energy in the form of heat and light.
Main sequence stars are distinguished by their hydrogen fusion in their cores, which is comparatively steady and persistent. The length of this phase varies with the star's mass, with more massive stars lasting less time during this phase because of their higher fusion rates. Depending on their mass, stars undergo several phases of evolution following the exhaustion of the hydrogen fuel in their cores, such as red giants or supernovae.
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The motion of a particle is defined by the relation x = 6t4 − 2t3 −12t2 + 3t + 3, where x and t are expressed in meters and seconds, respectively. Determine the time, the position, and the velocity when a = 0.
Answers
When the acceleration is 0, the time t is 1/3 and 2 seconds. The position and velocity at these two times are 6.24 and 4.50, and 63 and 39, respectively.
The motion of a particle is a critical aspect of physics that involves studying the movement of an object over a specific period of time. The motion of a particle is described by its position and velocity at a given time. In this case, the motion of a particle is defined by the equation \(x = 6t^4 - 2t^3 - 12t^2 + 3t + 3\), where x is the position of the particle and t is the time expressed in meters and seconds, respectively. To determine the time, position, and velocity of the particle when acceleration is 0, we need to perform some calculations based on the equation given.
First, let's find the velocity of the particle at a given time t. The velocity of a particle is the derivative of its position, which means that we need to find the first derivative of the equation \(x = 6t^4 - 2t^3 - 12t^2 + 3t + 3\). The derivative of the equation is\(v = 24t^3 - 6t^2 - 24t + 3\). This equation represents the velocity of the particle at any time t.
Next, let's find the acceleration of the particle at a given time t. The acceleration of a particle is the derivative of its velocity, which means that we need to find the first derivative of the equation \(v = 24t^3 - 6t^2 - 24t + 3\). The derivative of the equation is \(a = 72t^2 - 12t - 24\). This equation represents the acceleration of the particle at any time t.
Now, since we are looking for the time, position, and velocity when acceleration is 0, we can set the equation \(a = 72t^2 - 12t - 24\) equal to 0 and solve for t. By using the quadratic formula, we get two values for t, t = 1/3 and t = 2. These two values represent the time when the acceleration is 0.
To find the position and velocity at these two times, we can plug in t = 1/3 and t = 2 into the equation x = \(6t^4 - 2t^3 - 12t^2 + 3t + 3\) and\(v = 24t^3 - 6t^2 - 24t + 3\), respectively. When\(t = 1/3\), the position \(x = 6 * (1/3)^4 - 2 * (1/3)^3 - 12 * (1/3)^2 + 3 * (1/3) + 3 = 6.24\), and the velocity \(v = 24 * (1/3)^3 - 6 * (1/3)^2 - 24 * (1/3) + 3 = 4.50\). When t = 2, the position \(x = 6 * 2^4 - 2 * 2^3 - 12 * 2^2 + 3 * 2 + 3 = 63\), and the velocity \(v = 24 * 2^3 - 6 * 2^2 - 24 * 2 + 3 = 39\).
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What is the wavelength in nanometers of light with a frequency of 7. 8 × 1015 hz?.
Answers
38 nm A waveform signal that is carried in space or down a wire has a wavelength,
What is wavelength?A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).
The wavelength of the wave is the distance covered by it throughout a whole oscillation. A meter is the wavelength's SI unit (m).
*v=c/λ
v: 7.8 × 10^15 Hz c: 3.00*10^8 λ:?
7.8 × 10^15 Hz = 3.0010^8/λ
λ = 3.0010^8 m/s /7.8 × 10^15
λ = 3.8 10^-8
The calculated wavelength is in unit of meter. use the relationship between meter and nanometer to convert to the correct units.
3.8 10^-8 m (1nm/ 110^-9m )
= 38 nm
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If a mass is 1.5 m from the axis of rotation and makes one revolution in 10 seconds, what is its speed in m/s? If m = 0.1 kg and the values above still hold, what is the numerical value of the centripetal acceleration?
Answers
The speed of the mass is approximately 0.942 m/s.
The numerical value of the centripetal acceleration is approximately 0.591 m/s².
To find the speed of the mass, we need to know the circumference of the circular path it follows.
The circumference of a circle can be calculated using the formula:
Circumference = 2 * π * radius
Given that the mass is located 1.5 meters from the axis of rotation, the radius (r) is 1.5 meters.
Circumference = 2 * π * 1.5
Circumference ≈ 9.42 meters
Since the mass makes one revolution in 10 seconds, we can calculate its speed by dividing the circumference by the time taken:
Speed = Circumference / Time
Speed = 9.42 meters / 10 seconds
Speed ≈ 0.942 meters per second (m/s)
Therefore, the speed of the mass is approximately 0.942 m/s.
Now, let's calculate the centripetal acceleration.
The centripetal acceleration (ac) can be calculated using the formula:
ac = (v²) / r
Given:
m (mass) = 0.1 kg
r (radius) = 1.5 meters
v (velocity) = 0.942 m/s
Substituting the values into the formula, we can calculate the centripetal acceleration:
ac = (v²) / r
ac = (0.942 m/s)² / 1.5 meters
ac ≈ 0.591 m/s²
Therefore, the numerical value of the centripetal acceleration is approximately 0.591 m/s².
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A skydiver reaches terminal velocity. Then he opens his parachute.
What happens to the skydiver as the parachute opens?
Answers
Answer:
Explanation:
Remark
He's pulled upwards by the parachute. The formula is given below. Details are found searching for terminal velocity.
\(V_t=\sqrt\frac{2mg}{\rho A C_d}\)
Whatever that calculation turns out to be, a person has to be going a whole lot slower before he can safely hit the ground. The parachute is designed so that the person will be slowed very quickly to a safe velocity so when he hits the ground the impulse will not be as great as it could be. The force that the parachute delivers acts upward and opposes the force of gravity which is a downward force.
bulbs A, B, and C in figure Q32.11 are identical, and all are glowing.
a) Rank in order, from most to least, the brightness of the three bulbs. Explain
b) Suppose a wire is connected between points 1 and 2. What happens to each bulb? does it get brighter, stay the same, get dimmer, or go out? Explain.
Answers
a) The resistors in series have the same current.
b. The current through the resistor determines how much power passes through it
Ranking in order the brightnesses of the bulbs?a) A succession of resistors will share the same electricity. Therefore, the current going through light A is the same as the sum of the currents going through bulbs B and C. The brightness of light A is greater than that of bulbs C and B because the current is higher.
(b) When a wire is connected between 1 and 2, then the bulbs B and C are short circuited and no current pass through them. Then more current passes through the bulb A.
Bulb A: glows brighter ( due to more current )
Bulb B: go out ( due to no current )
Bulb C: go out ( due to no current )
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state the various use of a periscope
Answers
Answer:
the periscope is an instrument for observation over, around or through the object, obstacle or condition that prevents direct line-of-sight observation from the observer's current position.
Explanation:
the periscope is used to monitor the dangerous chemical reactions in the laboratory and they are used in observing the nuclear.
Answer:
A periscope is used to see objects over the heads of a crowd.It is used by soldiers sitting in a bunker to observe and view the opponents' activities over the ground.It is used by a navy officer sitting in a submarine to see ships over the surface of the water in the sea.It is also useful in submarines to determine the distance of the torpedo and decide the right time for an attack.A 16-cm-diameter circular loop of wire is placed in a 0. 64-t magnetic field. part a when the plane of the loop is perpendicular to the field lines> What is the magnetic flux through the loop?
Answers
128.72 Wb is the magnetic flux through the loop
A measurement of the total magnetic field that traverses a specific area is called magnetic flux.
It is a helpful tool for explaining how the magnetic force affects things inhabiting a certain area.
The precise area selected will determine how magnetic flux is measured.
Given,
Diameter of Circular Loop = 16 cm
The radius of Circular Loop = 8 cm
Area of Circular loop = πr² = 22/7 × 8 × 8
= 201.14 cm²
Magnetic field = 0.64 T
The angle between area vector and the field lines = 0°
Formula used :
Magnetic flux (Ф) = B.Acosθ
where B = Magnetic field of a circular loop of wire
A = Area of a circular loop of wire
θ = Angle between area vector and the field lines
Magnetic flux = 0.64 × 201.14 × 1
= 128.72 Wb
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Please answer
Which object wouldleast likely be used in an investigation of the relationship between magnetism and electric charge
Generator
Simple motor
Electromagnet
Simple machine
Answers
A 150 g sample of brass at 100 °C is placed in a Styrofoam cup of water containing 120 mL of water at 10 °C. No heat is lost to the cup or surroundings. What is the final temperature of the mixture? answer in celsius
Answers
Answer:
≈19.144°C.
Explanation:
all the details are in the attachment.
Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are the parameters of the sample of water.
P.S. change the provided design according Your requirements.
What do the initial momentsafter the Big Bang have incommon with the universeas it exists now?
Answers
The initial moments after the Big Bang and the current universe have a few things in common like Expansion; Radiation; Structure formation; etc.
Expansion: The universe has been expanding since the Big Bang, and this expansion is still happening. The initial moments after the Big Bang were characterized by a period of rapid inflation, and this expansion has continued to shape the structure of the universe we see today.
Radiation: The universe was filled with intense radiation in the initial moments after the Big Bang, and this radiation still exists in the form of the cosmic microwave background (CMB) radiation.
This radiation is thought to have been produced about 380,000 years after the Big Bang and has been traveling through space ever since, providing us with valuable information about the early universe.
Formation of structure: The initial moments after the Big Bang set the stage for the formation of the large-scale structure of the universe we observe today, such as galaxies, stars, and planets. The tiny fluctuations in the density of matter in the early universe were amplified by gravitational attraction over time, leading to the formation of these structures.
However, there are also many differences between the early universe and the universe as it exists now. For example, the universe was much hotter and denser in the early moments after the Big Bang, and there were no stars or galaxies yet.
The universe has also undergone many complex physical processes over billions of years, such as the formation of black holes and the evolution of stars, that were not present in the early universe.
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what is measurment ?
Answers
Answer:
Measurement is the act or the process of finding the size, quantity or degree of something.
Explanation:
We can measure the length, weight, and capacity (volume) of any given object.
Please help me Calculate the total energy stored in the capacitor
Answers
La fórmula: P = W/t ó W = P x t. donde:
P = potencia
W = trabajo
t = tiempo
Otra fórmula de potencia es: P= I x V
Proceso de carga de un capacitor - condensador
Una fórmula muy importante que también hay que tener en cuenta es: V = q/C que indica que el voltaje es proporcional a la carga que hay en un condensador.
De la fórmula de potencia P= I x V y considerando que la corriente es constante (corriente continua), entonces la potencia es proporcional al voltaje. Si el voltaje aumenta en forma lineal, la potencia aumentará igual. Ver el siguiente diagrama.
Como la potencia varía en función del tiempo, no se puede aplicar la fórmula W = P x t, para calcular la energía transferida. Pero observando el gráfico, se ve que esta energía se puede determinar midiendo el área bajo la curva de la figura.
Energía Almacenada en un Condensador - Capacitor
El área bajo la curva es igual a la mitad de la potencia en el momento “t”, multiplicada por “t”.
Entonces: W = (P x t) / 2. Pero se sabe que P = V x I. Si se reemplaza esta última fórmula en la anterior se obtiene: W = (V x I x t) / 2, y como I x t = CV = Q, entonces para saber cuanta energía (W) hay en un condensador usamos una de las siguientes fórmulas:
W = (CV2/2) julios
W = (QV/2) julios
W = (Q2/2C) julios
, donde:
W = Trabajo (Energía) en julios
C = Capacidad en faradios
V = voltaje en voltios en los extremos del condensador
Q = carga del condensador
Answer with the given explanations below: First the given formula that looks like this is: or where:
P = power
W = work
t = time
Next with another given power formula that looks like this is:
This is the charging process of a capacitor - capacitor #1.
Then it's a very important given formula that it must also be taken into account is: which it was indicated that the voltage is proportional to the charge on a capacitor.
In the following below, from the given power formula that looks like this is: and we are considering that the current is the constant (direct current), and then the power is proportional to the voltage. If the voltage increases linearly, the power will increase the same. See the following diagram. (I'm sorry, Yhungbabe, I don't have the diagram to show you in order to refer to the total energy stored in the capacitor because I havenèt learned the energy stored in the capacitor)
Anyway, since the power varies as a function of the time, the given formula that looks like this is: cannot be applied to calculate the energy transferred. But looking at the graph, it seems that this energy can also be determined by measuring the area under the curve of the figure.
This is The Energy Stored in a Capacitor - Capacitor #2.
The area under the curve is equal to the half of the power at time "t", being multiplied by "t".
Then with the given formula below that looks like this is:
But it's known that If this is the last given formula is being replaced in the previous one, we obtain the new given formula that looks like this is: and as another new given formula that looks like this is: there's so to find out how much energy (W) that there's in a capacitor that we use in one of the new given formulas that looks like in the listed below are:
joules
joules
joules
Now finally where:
W = Work (In The Energy) in Joules
C = Capacity in the farads
V = voltage in the volts at the ends of the capacitor
Q = a capacitor charge
I apologize for the late answer and the replies, so anyway, I use the online language translator in order to translate Spanish to English for you in order to understand my work given below, so, I hope my answer with the given explanation below here is very helpful to your own question about how to calculate the total energy stored in the capacitor with the image has been provided, please mark me as Brainliest and have a great rest of the day! :D
Sincerely,
Jason Ta,
The Ambitious of The Brainly And The Role of The TDSB And WHCI Student of The High School.
To maintain a higher temperature (in a thermotat), which way hould the control knob be moved?-to the right o that it move toward the contact, or to the left?
Explain why?
Answers
Turn the dial either clockwise to make the unit colder or anticlockwise to make the unit warmer to set the thermostat to any temperature.
A thermostat is a part of a regulating mechanism that senses the temperature of a physical system and takes action to keep it close to a desired setpoint.
Any system or gadget that heats or cools to a setpoint temperature uses a thermostat. Examples include central heating systems for buildings, air conditioners, HVAC systems, water heaters, kitchen appliances like refrigerators and ovens, and incubators for use in science and medicine.
To know more about the thermostat, here
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explain how the gravitational potential energy of an object can be changed.
Answers
Answer:
Change in Potential energy, pe = Final potential energy - Initial potential energy
Explanation:
∆p.e = Final p.e - Initial p.e
From the equation ∆p.e = (mgh) final - (mgh) initial
if the car travels thrice(3times) around the track,who much is the total distance covered?
Answers
A certain radioactive isotope has a half-life of approximately 1150 years. How
many years would be required for a given amount of this isotope to decay to
25% of that amount?
Answers
If the isotope has a half-life of 1150 years, this means that every 1150 years the amount of the isotope is halved. After one half-life, the amount is reduced to 1/2, after two half-lives it is reduced to 1/4, after three half-lives it is reduced to 1/8, and so on.
To determine how many years are required for the isotope to decay to 25% of its original amount, we need to determine how many half-lives it takes to get from 100% to 25%.
25% is the same as 1/4, so we need to determine how many times we need to halve the original amount to get to 1/4.
1/4 = (1/2)^n, where n is the number of half-lives
Solving for n:
n = log(1/4) / log(1/2)
n = 2
This means that it takes two half-lives for the isotope to decay to 25% of its original amount.
Since the half-life is approximately 1150 years, the time required for two half-lives is approximately:
2 x 1150 years = 2300 years
Therefore, it would take approximately 2300 years for a given amount of this isotope to decay to 25% of that amount.
N(t) = N0 * (1/2)^(t/T)
where:
N0 = the initial amount of the isotope
N(t) = the amount of the isotope remaining after time t
T = the half-life of the isotope
To find the time required for a given amount of the isotope to decay to 25% of that amount, we can set N(t) equal to 0.25N0 and solve for t:
0.25N0 = N0 * (1/2)^(t/T)
Taking the natural logarithm of both sides and solving for t, we get:
t = (ln 0.25) * T / (ln 2)
Substituting T = 1150 years, we get:
t = (ln 0.25) * 1150 / (ln 2) ≈ 287.5 years
Therefore, it would take approximately 287.5 years for a given amount of this isotope to decay to 25% of that amount.
An aerobatic airplane pilot experiences
weightlessness as she passes over the top of
a loop-the-loop maneuver.
The acceleration of gravity is 9.8 m/s^2
If her speed is 280 m/s at this time, find the
radius of the loop.
Answer in units of km.
Answers
For weightless object, gravity is equal to centripetal acceleration. The radius of the loop is calculated as 8 km.
What is centripetal acceleration?The property of the motion of an object traversing a circular path is known as centripetal acceleration. Any object that is moving in circle and has an acceleration vector pointed towards center of that circle is Centripetal acceleration.
As Centripetal Acceleration formula is;
a = v²/r
Given, V- velocity = 280 m/s
And we know that for weightless object,
Gravity = centripetal acceleration
So, a = g
given, g =9.8 m/s²
So,9.8 = 280²/r
r= 8000 m
Radius of the loop = 8 km
To know more about centripetal acceleration, refer
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