The correct order of how sound waves are sensed and perceived is: pinna, auditory canal, eardrum, ossicles, cochlea, auditory nerve, temporal lobe.
The process begins with the pinna, which collects and funnels sound waves into the auditory canal. The sound waves then travel through the auditory canal and reach the eardrum, causing it to vibrate.
These vibrations are then transmitted to the ossicles, a group of three small bones in the middle ear. The ossicles amplify and transfer the vibrations to the cochlea, a fluid-filled, snail-shaped structure in the inner ear. The cochlea contains tiny hair cells that convert the vibrations into electrical signals, which are then transmitted to the auditory nerve.
Finally, the auditory nerve carries these electrical signals to the temporal lobe of the brain, where they are interpreted as sound. This entire process allows us to sense and perceive the various sounds we encounter in our daily lives, enabling us to communicate and navigate the world around us.
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What is the mass of the ball that was hung to the spring if the period is 4 sec and the spring constant is 80 N/m.
Answer:
Approximately 32 kg
Explanation:
What we know are period (T) = 4 seconds and spring constant (k) = 80 N/m (Newton/meter)
Therefore, from the formula of:
\( \displaystyle{T = 2\pi \sqrt{ \dfrac{m}{k}} }\)
Substitute in known values:
\( \displaystyle{4 \: \text{seconds} = 2\pi \sqrt{ \dfrac{m}{80 \: \text{N/m}} }}\)
Divide both sides by 2π:
\( \displaystyle{ \dfrac{4 \: \text{seconds} }{2\pi}=\sqrt{ \dfrac{m}{80 \: \text{N/m}} }} \\ \\ \displaystyle{ \dfrac{2 \: \text{seconds} }{\pi}=\sqrt{ \dfrac{m}{80 \: \text{N/m}} }}\)
Square both sides:
\( \displaystyle{ \left( \dfrac{2 \: \text{seconds} }{\pi} \right)^{2} = \left(\sqrt{ \dfrac{m}{80 \: \text{N/m}} } \right)^{2} } \\ \\ \displaystyle{ \dfrac{4 \: \text{s}^2 }{ {\pi}^{2} } = \dfrac{m}{80 \: \text{N/m}}}\)
Then move 80 N/m to multiply left side:
\( \displaystyle{ \dfrac{4 \: \text{s}^2 }{ {\pi}^{2} } \cdot 80 \: \text{N/m}= m} \\ \\ \displaystyle{ \dfrac{320 }{ {\pi}^{2} } \: \text{kg}= m}\)
Since you didn't specify which digit of π to use so I will go with what most people use, π ≈ 3.14
\( \displaystyle{ \dfrac{320}{ {(3.14)}^{2} } \: \text{kg} = m}\)
3.14*3.14 = 9.8596 but rounded to 9.86 through significant figure rule:
\( \displaystyle{ \dfrac{320}{9.86} \: \text{kg} = m}\)
320 can be converted to scientific notation which is 3.2*10². Therefore, this has 2 figures. Hence, the result must be in 2 digits after division:
\( \displaystyle{32 \approx m}\)
Therefore, the mass is around 32 kg.
The maximum speed around a level curve is 30. 0 km/h. What is the maximum speed around a curve with twice the radius? (assume all other factors remain unchanged. ).
The maximum speed around a level curve is 30. 0 km/h. What is the maximum speed around a curve with twice the radius is 42.4 km/h.
Meaning of the maximum speed curve:
You might travel at a maximum speed of around 1.4 times as fast on a curve with a radius of 60 meters (twice as much), according to the equation, which also states that your maximum speed is proportional to the square root of the curve's radius.
According to that,
30 km/hr is the maximum speed.
New radius equals 2 r
In all scenarios, the centripetal force will be the same.
Calculating the new top speed around a curve is necessary.
Using the centripetal force formula:
\(\frac{mv^{2} }{r} = \frac{mv^{2}}{r}\)
Fill out the formula with the value
\(\frac{v^{2} }{2r} = \frac{30^{2} }{2r}\)
\(v= 30\sqrt{2} \ Km/h\)
\(v = 42.4 Km/h\)The maximum speed around a curve is therefore 42.4 km/h.
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round-nosed bullets with low velocities are specifically designed for
Round-nosed bullets with low velocities are specifically designed for improved accuracy and safety in target shooting and hunting scenarios. The round-nosed shape reduces air resistance, allowing for stable trajectory and accuracy at lower velocities. They are also safer for shooting in close quarters and reduce the risk of over-penetration.
Round-nosed bullets with low velocities are specifically designed for certain purposes in firearms. These bullets are commonly used in target shooting and hunting scenarios. The round-nosed shape of the bullet helps to reduce air resistance, allowing it to maintain a stable trajectory and accuracy at lower velocities. This makes them suitable for shooting at shorter distances or when precision is required.
Additionally, the low velocity of these bullets reduces the risk of over-penetration, making them safer for shooting in close quarters or in situations where there may be a risk of unintended collateral damage. The round-nosed design also helps to transfer energy more efficiently upon impact, which can be beneficial for hunting applications.
Overall, round-nosed bullets with low velocities offer improved accuracy and safety in specific shooting scenarios.
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joe and tom are competing in a 100 m race. partway through the race, joe is 50 m from the finish line and moving at 10 m/s and tom is 51 m from the finish line and moving at 9.75 m/s. if joe maintains his speed and tom begins accelerating, what magnitude of constant acceleration must tom have so that they finish the race in a dead heat
Tom must accelerate at a constant rate of 0.25 m/s2 in order to finish the race in a dead heat with Joe.
What is accelerate?Accelerate is an action or process of speeding up or increasing in rate or amount. It is commonly used to describe an increase in the rate of change of velocity, or the rate of change of a variable such as time, speed, or distance. Acceleration can be generated by a variety of forces and factors, such as gravity, electrical current, centrifugal force, friction, and aerodynamic drag.
Tom must have a constant acceleration of 0.25 m/s2 in order to finish the race in a dead heat with Joe. This can be calculated using the equation for average velocity, vavg = (v1 + v2)/2, where v1 is Joe's velocity and v2 is Tom's velocity. If Joe and Tom both have the same final velocity, then their average velocity must be equal.
50 m / 10 m/s + 51 m / (9.75 m/s + a) = (10 m/s + a)
Solving for a, we get a = 0.25 m/s2. Therefore, Tom must accelerate at a constant rate of 0.25 m/s2 in order to finish the race in a dead heat with Joe.
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Planet A has a tilt of five degrees. What seasonal changes would be expected on this planet? Extreme temperature changes between seasons Little to no change in temperatures between seasons Seasonal changes along the equator only Seasonal changes at the poles only
Answer:
Little to no change in temperatures between seasons.
Reason: because i got it right on the test, and i smart
Answer:
Little to no change in temperatures between seasons.
Explanation:
I can confirm this is right
a 70-kg person rides in a 30-kg cart moving at 12 m/s at the top of a hill that is in the shape of an arc of a circle with a radius of 40 m. (a) what is the apparent weight of the person as the cart passes over the top of the hill? (b) determine the maximum speed that the cart may travel at the top of the hill without losing contact with the surface. does your answer depend on the mass of the cart or the mass of the person? explain.
The apparent weight of the person as the cart passes over the top of the fill for question A is 470N.
The maximum speed that the cart may travel at the top of the hill without losing contact with the surface from question B is 19.8 m/s.
Based from the question above, we will approach using centripetal force to answer question A, and centripetal acceleration to answer question B.
It is a force that makes a body follow a curved path. Its direction is always orthogonal to the motion of the body and towards the fixed point of the instantaneous center of curvature of the path.
Now, let's calculate question A about the apparent weight of the person as the cart passes over the top of the hill.
Given from the question
mass of the person = 70kg
weight of the person will be = mass * earth gravity
= 70 * 9.8
= 686N
Radius of the circle of which the arc is a part = r = 40m
speed of the cart = 12 m/s
The centripetal force on the person =
Fc = mass * ((cart speed (v))^2 / radius of the circle (r))
= 75 * (12^2/50)
= 216N
from here, apparent weight can be calculate below :
R (apparent weight) = weight - centripetal force (Fc)
= 686 - 216
= 470N
Therefore, the answer of question A, the apparent weight of the person as the cart passes over the top of the hill is 470N
Now, moving on to question B. The person can have a maximum speed when the centripetal acceleration is equal to the acceleration due to gravity.
Vmax = √r (radius) * g (gravity)
= √40 * 9.8
= √392
= 19.8 m/s (rounded)
Therefore, the maximum speed of the cart at the top of the hill without losing contact with the surface is 19.8m/s. This answer also depends on the radius of the circular path and velocity of the cart.
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At the instant when the speed of the loop is 3. 00 m/s and it is still partially in the field region, what is the magnitude of the force that the magnetic field exerts on the loop?.
The magnitude of the force that the magnetic field exerts on the loop can be determined using the equation F = BIL, where B is the magnetic field strength, I is the current, and L is the length of the wire in the magnetic field. Since the loop is partially in the field region, we can assume that only a portion of the loop is experiencing the magnetic field. Therefore, we need to calculate the length of wire that is in the field region.
Once we know the length of wire in the field region, we can calculate the current using the equation I = q/t, where q is the charge and t is the time. Since we are not given any information about the charge or the time, we cannot calculate the current directly.
However, we are given the speed of the loop, which is 3.00 m/s. This can be used to calculate the emf (electromotive force) induced in the loop using the equation emf = BLv, where B is the magnetic field strength, L is the length of the wire in the field region, and v is the speed of the loop. The emf is equal to the rate of change of magnetic flux through the loop.
Once we know the emf, we can use Ohm's law to calculate the current, since the loop has some resistance. Once we know the current, we can use the equation F = BIL to calculate the magnitude of the force that the magnetic field exerts on the loop. Therefore, an explanation of the calculation of the magnitude of the force would require additional information about the length of wire in the field region, the charge, and the time.
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The magnitude of the force that the magnetic field exerts on the loop is F = qvB, where q is charge, v is velocity (3.00 m/s), and B is magnetic field strength.
To find the force exerted by the magnetic field on the loop, we must first identify the variables involved. The equation we use is F = qvB, where F is the force, q is the charge of the moving particle, v is the velocity of the particle (3.00 m/s in this case), and B is the magnetic field strength.
For this question, we must be given the values for the charge (q) and the magnetic field strength (B) to find the exact magnitude of the force (F).
However, the formula F = qvB shows the relationship between the variables and helps understand how the force depends on the velocity, charge, and magnetic field strength. Once you have the values for q and B, you can plug them into the equation along with the given velocity to find the magnitude of the force exerted by the magnetic field on the loop.
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a flywheel, initially at rest, has a constant angular acceleration. after 9 s the flywheel has rotated 450 rad. its angular acceleration in rad/s2 is:
A flywheel, initially at rest, has a constant angular acceleration. after 9 s the flywheel has rotated 450 rad . Its angular acceleration in rad/s2 is 11.11 \(rad/s^{2}\)
theta = u*t + 1/2 * α * \(t^{2}\)
450 = 0 + 1/2 * α * \((9)^{2}\) (initially the flywheel is at rest , u =0)
α = 450 / 81
= 11.11 \(rad/s^{2}\)
Its angular acceleration in rad/s2 is 11.11 \(rad/s^{2}\)
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the first successful attempt to establish the size of earth is credited to
The first successful attempt to establish the size of Earth is credited to the ancient Greek mathematician and astronomer Eratosthenes.
Eratosthenes noticed that at noon on the summer solstice, the sun was directly overhead in Syene, a city in southern Egypt, casting no shadow. However, in Alexandria, which was located about 500 miles north of Syene, the sun cast a shadow of approximately 7.2 degrees. Eratosthenes realized that the difference in the shadow length was caused by the curvature of the Earth's surface, and he used his knowledge of geometry to calculate the circumference of the Earth.
Eratosthenes' estimate was remarkably accurate, coming within about 2% of the Earth's actual circumference. His achievement laid the groundwork for future studies of Earth's size and shape and cemented his legacy as one of the greatest scientists of antiquity.
So,the first successful attempt to establish the size of Earth is credited to the ancient Greek mathematician and astronomer Eratosthenes. He was born in Cyrene, a Greek colony in present-day Libya, in 276 BCE and was the chief librarian at the Library of Alexandria in Egypt.
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Gless has a hardness that is in the middle of the hardness scale. What is the hardness of Glass?
Answer:
5.5 to 7 Mohs
Explanation:
Glass ranks around 5.5 to 7 Mohs, but sapphire crystal has a hardness of 9 Mohs, making it only slightly less hard than diamond.
Answer: 5.5
Explanation:
Several hardness scales have been developed to catalog the materials (specifical minerals), being the Mohs scale the best known. This scale, proposed by the German geologist Friedrich Mohs in 1825, consists of a ratio of ten minerals numbered in increasing order by hardness, from least to greatest.
the ostringstream member function ____ returns the contents of an ostringstream buffer as a string.
The ostringstream member function "str" returns the contents of an ostringstream buffer as a string. Here's how you can use it:
1. Create an ostringstream object:
ostringstream oss;
2. Write data to the ostringstream buffer using the insertion operator (<<):
oss << "Hello";
oss << " World";
3. Retrieve the contents of the buffer as a string using the "str" member function:
string result = oss.str();
The variable "result" will now contain the string "Hello World".
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Inelastic collisions do not conserve kinetic energy. Does
this violate the Law of Conservation of Energy?
Answer:
No. Because undefined amounts of energy are also released in deformation of the objects, heat released, etc.
a tennis ball bounces on the floor three times. if each time it loses 22% of its energy due to heating, how high does it rise after the third bounce, provided we released it 3.1 m from the floor?
To calculate the height of a tennis ball after three bounces, consider the energy loss due to heating and the initial height. After the first bounce, the ball loses 22% of its energy, retaining 78%. After the second bounce, it loses 22% and retains 78%, reaching 1.88484 m.
To calculate how high the tennis ball rises after the third bounce, we need to consider the energy loss due to heating and the initial height from which it was released.
Let's start by determining the initial height the ball reaches after the first bounce. If the ball loses 22% of its energy each time it bounces, it retains 100% - 22% = 78% of its energy after each bounce.
Since the ball is released from a height of 3.1 m, it rises to a height of 3.1 m * 78% = 2.418 m after the first bounce.
Now, let's calculate the height the ball reaches after the second bounce. Again, it loses 22% of its energy, so it retains 78% of the energy it had after the first bounce.
The height after the second bounce is 2.418 m * 78% = 1.88484 m.
Finally, let's find the height the ball reaches after the third bounce. It loses another 22% of its energy and retains 78% of the energy it had after the second bounce.
The height after the third bounce is 1.88484 m * 78% = 1.46995 m.
Therefore, after three bounces, the tennis ball rises to a height of approximately 1.46995 m.
In summary:
- After the first bounce: 2.418 m
- After the second bounce: 1.88484 m
- After the third bounce: 1.46995 m
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please help me on the 1st bullet point for brainliest!
Answer:
thermal energy
Explanation:
1. There is a group of kids playing tee ball in front of your house. If the bat is 5kg traveling with a velocity
of 8m/s, with what velocity will the 1.5 kg ball travel after it is hit by the bat?
Answer: tug vi
Explanation:
Because
How does this product most likely need to be improved before doctors can report that the new technological design is successful? the product needs to better solve the problem for which it was designed. the product needs to become available to the public more quickly. the product needs to become more time effective when it is being built. the product needs to make better use of available building materials.
The item must more effectively address the issue for which it was created first-hand. After the new technology was put to the test on patients, it had a 25% success rate ( very low success rate).
Conclusion: "The new technological design must better handle the issue for which it was intended (i.e., increase in success rate to > 50%) before doctors can declare it effective.
Because a procedure must record a success rate of more than 50% of the test patients in order to be regarded as successful for deployment.
Why are medical devices important?
Medical equipment ranges from straightforward bedpans and tongue depressors to sophisticated pacemakers with programmable features and closed-loop artificial pancreas systems.
Additionally, IVD items including reagents, test kits, and blood glucose meters are included in the category of medical devices.Medical devices also include some radiation-emitting electronic gadgets with a medical application or that make medical claims.These include, for instance, x-ray machines, x-ray equipment, and medical lasers.Searching for current product classifications that might apply to your product can be helpful in evaluating whether your product is regulated as a medical device.
A solid indication that your product might be a medical device is finding an existing classification that describes the intended application or design of your product.Learn more about medical devices here,
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what is the period of an object in uniform circular motion with an angular velocity of 3.14 radians/sec?
The answer to your question is that the period of an object in uniform circular motion with an angular velocity of 3.14 radians/sec is approximately 2 seconds.
Angular velocity is the rate at which an object rotates or moves around a central point, usually measured in radians per second (rad/s). On the other hand, the period refers to the time it takes for one complete rotation or revolution of the object.
In the case of an object in uniform circular motion, its angular velocity is constant, which means it is moving at a constant speed in a circular path. To determine the period of this motion, we can use the formula:
T = (2π)/ω
where T is the period, ω is the angular velocity, and π is the mathematical constant pi (approximately equal to 3.14).
Substituting the given value of ω = 3.14 rad/s into the formula, we get:
T = (2π)/3.14
T ≈ 2 seconds
Therefore, the long answer to your question is that an object in uniform circular motion with an angular velocity of 3.14 radians/sec has a period of approximately 2 seconds.
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A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/s velocity. The car uniformly accelerates to the velocity 35m/s in 20 seconds, the moves at a constant speed for 5 seconds. How long will it take for the car to catch up to the truck.
Answer:
At \(t = (70 / 3) \; {\rm s}\) (approximately \(23.3 \; {\rm s}\).)
Explanation:
Note that the acceleration of the car between \(t = 0\; {\rm s}\) and \(t = 20\; {\rm s}\) (\(\Delta t = 20\; {\rm s}\)) is constant. Initial velocity of the car was \(v_{0} = 0\; {\rm m\cdot s^{-1}}\), whereas \(v_{1} = 35\; {\rm m\cdot s^{-1}}\) at \(t = 20\; {\rm s}\!\). Hence, at \(t = 20\; {\rm s}\!\!\), this car would have travelled a distance of:
\(\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}\).
At \(t = 20\; {\rm s}\), the truck would have travelled a distance of \(x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}\).
In other words, at \(t = 20\; {\rm s}\), the truck was \(400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m}\) ahead of the car. The velocity of the car is greater than that of the truck by \(35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}\). It would take another \((50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s}\) before the car catches up with the truck.
Hence, the car would catch up with the truck at \(t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}\).
An 80.0 N force accelerates a 6.0 kg object from 4.0 m/s to 8.0 m/s. What is the
impulse?
0 24 N"s
0 3.33 Nºs
30 N's
0 -30 N's
0-24 N's
Answer:
24kgm/s
Explanation:
Given parameters:
Force = 80N
Mass of object = 6kg
Initial velocity = 4m/s
Final velocity = 8m/s
Solution:
Impulse = ?
Solution:
The impulse on a body is its change in momentum.
Impulse = m (v - u )
m is the mass
v is the final velocity
u is the initial velocity
Now insert the parameters and solve;
Impulse = 6 (8 - 4) = 24kgm/s
A cue ball of mass 0.11 kg is moving to the right at a speed of 6 m/s and collides with a 7 ball of mass 0.1 kg, initially at rest. If the 7 ball moves to the right with a speed of 3 m/s after the collision, how fast is the cue ball moving after the collision
A cue ball of mass 0.11 kg is moving to the right at a speed of 6 m/s and collides with a 7 ball of mass 0.1 kg, initially at rest. If the 7 ball moves to the right with a speed of 3 m/s after the collision, after the collision, the cue ball is moving to the right with a speed of approximately 3.27 m/s.
We can use the principle of conservation of momentum. The total momentum before the collision must equal the total momentum after the collision.
Step 1: Calculate the initial momentum of both balls before the collision.
Initial momentum of cue ball = mass x initial speed = 0.11 kg x 6 m/s = 0.66 kg m/s
Initial momentum of 7 ball = mass x initial speed = 0.1 kg x 0 m/s = 0 kg m/s
Total initial momentum = 0.66 kg m/s
Step 2: Calculate the final momentum of the 7 ball after the collision.
Final momentum of 7 ball = mass x final speed = 0.1 kg x 3 m/s = 0.3 kg m/s
Step 3: Determine the final momentum of the cue ball after the collision.
Since the total initial momentum must equal the total final momentum, the final momentum of the cue ball = total initial momentum - final momentum of 7 ball = 0.66 kg m/s - 0.3 kg m/s = 0.36 kg m/s
Step 4: Calculate the final speed of the cue ball after the collision.
Final speed of cue ball = final momentum / mass = 0.36 kg m/s / 0.11 kg ≈ 3.27 m/s
So, after the collision, the cue ball is moving to the right with a speed of approximately 3.27 m/s.
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Question 5
Joan wants to decrease her BMI number. How can she achieve her goal?
A. Joan can lose some weight
B. Joan can stretch and get taller
C. Joan can have her blood pressure checked.
D. Joan can take medication
Part Two: Criteria, Constraints, and Prioritizations
1. Choose one sub-problem that you will investigate further and explain which one you chose here.
o
2. List two realistic criteria for the sub-problem.
o
o
3. Explain why it is important for these criteria to be met in order to solve the problem.
o
4. List two constraints for the sub-problem.
o
o
5. Explain why these constraints exist. (How do they limit solutions to the problem?)
o
6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
PLEASE HELP ME I DONT UNDERSTAND<333
Answer:
Usually, a solution can have several criteria and constraints. Even though all are important, some criteria are more important than others. The same holds true for constraints. But what do you do if it's impossible for a solution to cover every criterion while avoiding every constraint? In cases like this, you can use prioritization. Listing criteria and constraints based on priority shows the relative importance of each. You will need to prioritize the criteria and constraints for each sub-problem so that you can design a solution for each one individually. Prioritization can help you compare two different possible solutions. For example, the criterion that cars travel at 15 mph through the neighborhood might be a higher priority than the constraint that homeowners are only willing to spend $10,000 on this issue. If this is the case, you would want to generate solutions that also follow the priority in mind. All criteria are important, but engineers must sometimes make a trade-off, which is a compromise or change in one or more criteria or constraints so that they can be met at the same time. This is where prioritization comes in handy as it helps determine the trade-offs. A solution that is doing a better job of meeting one criterion may result in not completely meeting another criterion. Prioritization will help you choose which solution to go with.
Explanation:
I got this from quizlet :)
The first car has twice the mass of a second car, but only half as much kinetic energy. When both cars increase their speed by 5.0 m/s , they then have the same kinetic energy. Part A What were the original speeds of the two cars
Thus, the initial speeds of both the cars were zero. The increase in speed is the same for both cars, i.e., 5 m/s.
Part A: Original speed of the two cars
Given that the first car has twice the mass of the second car, but only half as much kinetic energy. When both cars increase their speed by 5.0 m/s, they then have the same kinetic energy.
In mathematical form, the given data can be expressed as follows:
m1 = 2m2 (mass of the first car is twice that of the second car)
m1(v1^2/2) = 1/2 m2(v2^2)
(the kinetic energy of the first car is half that of the second car)
After increasing their speeds by 5.0 m/s, they have the same kinetic energy.
Thus,
1/2 m1(v1+5)^2 = 1/2 m2(v2+5)^2
Now we will substitute the value of m1 from the first equation into the second equation.
1/2 (2m2) (v1+5)^2 = 1/2 m2(v2+5)^2
This simplifies to:
(v1+5)^2 = (v2+5)^2
Thus,
(v1+5) = ±(v2+5)
We will consider the negative sign because the first car has to be going slower than the second car to begin with.
Thus,
v1+5 = -v2+5v1 + v2 = 0v1 = -v2
Now substituting this value of v1 in terms of v2 into the equation
1/2 m1(v1^2) = 1/2 m2(v2^2),
we get:
1/2 (2m2)(-v2)^2 = 1/2 m2(v2^2)⇒ 2v2^2 = v2^2⇒ v2^2 = 0⇒ v2 = 0 m/s (initial speed of the second car)
Now, v1 = -v2 = -0 = 0 m/s (initial speed of the first car).
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What does the word apparent mean in apparent visual magnitude
The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.
What is visual magnitude?
The brightness of a celestial body is determined by eye estimation with or without optical aid or by other instrumentation equivalent to the eye in spectral sensitivity.
Apparent magnitude:
Apparent magnitude is a measure of how bright the star appears when viewed from Earth.It is a measure of the brightness of a star or other astronomical object observed from Earth. An object's apparent magnitude depends on its intrinsic luminosity and its distance from Earth.Hence,
The word 'apparent' mean in apparent visual magnitude is, how bright the star appears when viewed from Earth.
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The sum of two component vectors is referred to as the
vector.
Addition
Quantitative
Subtraction
Resultant
Which are true of the cosmic microwave background radiation (CMB), and which are false? True False Answer Bank fills the entire Universe has blackbody or thermal spectrum today has temperature of ~300O K discovered in the [990s with the Hubble Space Telescope comes from all direclions
True: The cosmic microwave background radiation (CMB) fills the entire Universe, has a blackbody or thermal spectrum today, and comes from all directions.
False: The cosmic microwave background radiation (CMB) was not discovered in the 1990s with the Hubble Space Telescope. The CMB was actually discovered in 1964 by Arno Penzias and Robert Wilson using a microwave antenna at the Bell Telephone Laboratories in New Jersey. The discovery of the CMB was a key piece of evidence for the Big Bang theory.
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What is the proper unit for gravitational potential energy?Question 16 options:gravitonsjoulesnewtonsmeters
Answer:
Joules
Explanation:
The unit for Energy is Joules, which is equal to kg m²/s².
The gravitational potential energy is calculated as:
\(Ep=\text{mgh}\)Where m is mass (kg), g is gravity (m/s²) and h is the height (m). So, the unit of the potential energy is:
\(kg\cdot\frac{m}{s^2}\cdot m=kg\cdot\frac{m^2}{s^2}=\text{Joules}\)Therefore, the answer is joules.
Your friend wants to join the school track team, and has asked for your help to determine how fast she can run. What kind of information would you need to collect to help your friend???
Answer:
how long she can run how fast she can run
A tone i thrown traight up. After three econd it reache the dropping point again. Find out how high it wa yeterday
H=132.3m and U=29.4ms−1 are height and velocity respectively.
What is motion?
Motion is a change in position of an object over time. It occurs when an object moves from one point to another. Motion can be described in terms of displacement, distance, speed, velocity, and acceleration. Motion can also be described using Newton's laws of motion which state that an object in motion will remain in motion unless acted upon by an external force. Motion also describes the motion of particles in a fluid or gas, as well as the motion of waves in a medium. Motion is an essential part of the physical world and is essential for understanding the fundamental laws of nature.
Motion in a straight line
Let,
u = Initial velocity of stone
H = Maximum height attained by the stone
v = final velocity at maximum height = 0
t = time taken to attain maximum height = 3s
a=−g= acceleration due to gravity
a. We know that,
V=u+at
0=u−g×3
U=3g=3×9.8ms−2
U=29.4ms−1
b. From the equations of motion, we know that,
S=ut+ ½ a t2
H=29.4×3+½ * 9.8 *32
H=88.2+44.1
H=132.3m
To learn more about motion,
https://brainly.com/question/29571846
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The ethical guidelines related to animal research dictate that
animals are not harmed under any circumstance
animals are treated as humanely as possible
animals are used even when there are other ways to test a hypothesis
O animals are used to test any substance that might harm humans
O animals are excluded from participation in any psychological research
Question 10 Multiple Choice Worth 3 points)
(01.04 MC)
Answer:
Animals are treated as humanely as possible.
Explanation:
Ethical guidelines relating to animals are laid down principles or laws that guide against the maltreatment of animal in any way during or for a research. As the use of some animals for various researches can not be over emphasized, because of the close proximity between their body tissues to that of humans.
The ethical guidelines enforce treating animals as humanly as possible or achievable. This ensure appropriate handling and treatment of the animals.