Which best describes a difference between laser light and regular light?
Laser light is less concentrated.
Laser light has a beam that spreads out.
O Laser light is made of one specific color.
O Laser light pumps out light particles one at a time.

Answer:

The reason that the nucleus of most atoms does not fall apart despite the oppositely charged protons exerting a repulsive force on each other is the strong nuclear force.

The strong nuclear force is one of the fundamental forces in nature that acts between protons and neutrons in the atomic nucleus. It is a short-range force that is much stronger than the electromagnetic force (which produces the repulsion between protons).

The strong nuclear force is responsible for holding the nucleus together.

Additionally, the ratio of protons to neutrons in a nucleus also affects its stability. Therefore, if there is an imbalance in this ratio, the repulsive force between the protons can become too strong, causing the nucleus to become unstable and undergo radioactive decay.

Overall, the nucleus remains stable due to the balance between the strong nuclear force and the repulsive force between the protons.

Answer:

Cyber Law is a generic term referring to all the legal and regulatory aspects of the internet. Everything concerned with or related to or emanating from any legal aspects or concerning any activities of the citizens in the cyberspace comes within the ambit of cyber laws.

Explanation:

The equivalent ratio in higher terms to eliminate decimals from the ratio 3.04 to 6 is 76 to 150.

To eliminate decimals from the ratio 3.04 to 6, we can multiply both terms of the ratio by a common factor that will result in whole numbers.

First, let's convert 3.04 to a fraction:

3.04 = 3 + 0.04 = 3 + 4/100 = 3 + 1/25 = 75/25 + 4/100 = 76/25

Now, the ratio 3.04 to 6 can be written as:

3.04/6 = 76/25 / 6

To eliminate the decimal, we can multiply both the numerator and denominator by 25:

(76/25) * 25 / (6 * 25) = 76 / 150

Therefore, the equivalent ratio in higher terms to eliminate decimals from the ratio 3.04 to 6 is 76 to 150.

By multiplying both terms by 25, we effectively scale up the ratio to eliminate the decimal and create whole numbers. This allows us to express the ratio in higher terms without decimals. The final ratio 76 to 150 represents the same relationship as the original ratio 3.04 to 6, but in whole number form.

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Answer:

2

Explanation:

kilogram and megagram is the larger unit

It is in charge of the variances in sound quality that individuals can detect.

The frequency of a sound wave that determines the pitch of the sound. High-frequency sound waves are thought to have a higher pitch than low-frequency sound waves.

The wavelength, amplitude, frequency, time period, and velocity of sound waves are their five primary characteristics. How far a sound wave will travel before repeating depends on its wavelength. The wavelength itself is a longitudinal wave that demonstrates how the sound wave is compressed and rarefied.

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The frequency is the inverse of time period of a wave and the time period of a wave is the time taken divided by number of cycles or wave.

A wave is a propagating dynamic disturbance of different quantities. Frequency is the number of waves which are passing by a specific point of time per second. And, time period is the time which the wave takes for one wave cycle to complete.

Frequency of a wave can be calculated by reciprocal of time taken.

Frequency of a wave = 1/ Time period

The time period is the time in which one wave.

9. The time period of the wave = Time taken/ Number of waves or cycles

Time period = 4/ 8

Time period = 1/2 or 0.5 sec

Frequency of a wave = 1/ T

Frequency of a wave = 1/ 0.5 = 2⁻¹

10. The time period of the pendulum's oscillations = 4/ 12 = 1/3 = 0.33 sec

The frequency of the pendulum's oscillations = 3.03 sec⁻¹

11. Speed of a wave = wavelength of a wave × frequency of the wave

Speed of a wave = 3 × 2

Speed of a wave = 6 meters per second

12. Wavelength of the wave will be the ratio of speed of the wave and frequency of the wave.

Wavelength (λ) = Speed of the wave (v)/ frequency of the wave (f)

Wavelength = 340/ 20

Wavelength = 170 meters

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Answer:

1.48×10⁻⁷ Newtons

Explanation:

From the question,

According to newton's law of universal gravitation.

F = Gmm'/r²........................ Equation 1

F = gravitational force, G = gravitational constant, m = mass of the first ball, m' = mass of the second ball, r = distance between the balls.

Given: m = m' = 8 kg, r = 17 cm = 0.17 m,

Constant : G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

F =  (6.67×10⁻¹¹×8×8)/(0.17²)

F = 1.48×10⁻⁷ N

Answer: TIR (total internal reflection) occurs

Explanation: TIR occurs because the angle of refraction reaches a 90-degree angle before the angle of incidence reaches a 90-degree angle. The only way for the angle of refraction to be greater than the angle of incidence is for light to bend away from the normal. Since light only bends away from the normal when passing from a more dense medium into a less dense medium, then this would be a necessary condition for total internal reflection.

A)The total mechanical energy of the two blocks prior to being released from rest can be found by adding the gravitational potential energy of mA and the pulley to zero.

B).The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J,where mp is the mass of the pulley.The total mechanical energy of the two blocks prior to being released from rest is54.33 J + 0 J = 54.33 J

C) The rotational kinetic energy of the pulley just before mA hits the ground is(0.178 mp) J.

D) The mass of the pulley ismp = (1/2)mpr²/R² =(1/2)(0.020 kg)(0.100 m)²/(0.200 m)² = 0.001 kg = 1 g.r = (1/2)R.

The Atwood's machine shown in Figure 1 consists of two masses mA = 6.50 kg and mB = 3.30 kg. The height of mA above the floor is 0.865 m. When mA hits the floor, its velocity is 1.89 m/s. The pulley has a moment of inertia (1/2)mpr². We have to find the total mechanical energy of the two blocks before they are released, the total mechanical energy when mA hits the ground, the rotational kinetic energy of the pulley just before mA hits the ground, and the mass of the pulley. Let's solve these one by one. Part A The total mechanical energy of the two blocks prior to being released from rest can be found by adding the gravitational potential energy of mA and the pulley to zero.

The equation for gravitational potential energy is mgh. The gravitational potential energy of mA and mB is mAg(h-hB)where h is the height of mA above the floor and hB is the height of mB above the floor. Since the pulley is at the same height as mB, its gravitational potential energy ismBg(h-hB).The gravitational potential energy of mA is6.50 kg × 9.81 m/s² × 0.865 m = 54.33 J.The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J,where mp is the mass of the pulley.The total mechanical energy of the two blocks prior to being released from rest is54.33 J + 0 J = 54.33 J.Part BThe total mechanical energy of the two blocks when mA hits the ground can be found by adding the kinetic energy of mA, the kinetic energy of mB, and the rotational kinetic energy of the pulley to the gravitational potential energy of mB and the pulley. The equation for kinetic energy is (1/2)mv². The kinetic energy of mA is(1/2) × 6.50 kg × (1.89 m/s)² = 11.54 J.The kinetic energy of mB is(1/2) × 3.30 kg × 0 m/s² = 0 J, since it is at rest.The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J.The rotational kinetic energy of the pulley is(1/2) × (1/2)mp × R² × ω²,where R is the radius of the pulley and ω is its angular velocity just before mA hits the ground. We can use the fact that the linear speed of the rope is the same on both sides of the pulley to find ω. The equation for linear speed is v = Rω. When mA hits the ground, its speed is 1.89 m/s. The speed of mB is zero. Since the rope is inextensible, the speed of the rope is also 1.89 m/s.

Therefore, the speed of the pulley is also 1.89 m/s. We can find the angular velocity of the pulley by dividing the linear velocity by the radius.ω = v/R = 1.89 m/s ÷ (0.200 m/2) = 18.9 rad/s.The rotational kinetic energy of the pulley is(1/2) × (1/2)mp × R² × ω² =(1/4)mpR²ω² =(1/4)mp(0.200 m)²(18.9 rad/s)² =(0.178 mp) J.The total mechanical energy of the two blocks when mA hits the ground is11.54 J + 0 J + 0 J + (0.178 mp) J = 11.72 J + (0.178 mp) J.Part CThe rotational kinetic energy of the pulley just before mA hits the ground is(0.178 mp) J.Part DWe can find the mass of the pulley by using the moment of inertia of a disk and the mass of the pulley. The moment of inertia of a disk is (1/2)mr². Therefore,(1/2)mpR² = (1/2)mpr²,where R is the radius of the pulley and r is the radius of gyration of the pulley. The radius of gyration of a disk is (1/2)R.

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Answer:

Electromagnetic waves that act like particles would be the violet light

If he does not use the lenses, his near point will be  66.7 cm. For him to read a material at 50 cm, he  has to use  a lens of 2.0D.

The near point is the nearest area which a person can see or have distinct vision. The focal length of the lens is f = 100/2.5 = 40cm

Then;

1/40 = -1/v + 1/25

1/v = 1/25 - 1/40

v = 66.7 cm

Also, for the purpose of reading at 50 cm

1/f = -1/50 + 1/25

1/f = 1/25 - 1/50

f = 50cm

The power of this lens is;

100/50 cm = 2 D

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Answer:

Well if X= -5, 1, 7, 10, 22 and if f(x)= 7, 2, 0, 1, 18 than there is your answer.

Explanation:

[X= 1]

The option that explains this observation is option E:

The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (or E-field). It can also refer to a system of charged particles' physical field.

Negatively charged electrons will be diverted in the direction of the positive electrode, or (+) plate. Positively charged protons will be diverted in the direction of the negative electrode, or (-) plate.

Therefore, Magnetic lines of force in space are bent by ferromagnetic materials in a static magnetic field. The distortion impact on the static magnetic field is disturbed by the material flaws.

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See full question below

Current Current is moving through a copper ribbon in the direction shown. The ribbon is suspended between the poles of a magnet as indicated. When the voltage is measured between A and B, it is observed that A is at higher potential than B. Which of the following explains this observation?

A The electrons in the ribbon behave like magnetic dipoles; thus, they align with the magnetic field of the magnet that deflects electrons in the ribbon toward point A.

B The electrons in the ribbon behave like magnetic dipoles; thus, they align with the magnetic field of the magnet that deflects electrons in the ribbon toward point B.

с Electrons moving through the magnetic field experience a magnetic force to the left that deflects electrons in the ribbon toward point A.

D Electrons moving through the magnetic field experience a magnetic force to the right that deflects electrons in the ribbon toward point B.

E The electric field in the ribbon is distorted by the magnetic field. This distortion creates an electric field component directed from point A to point B that deflects electrons in the ribbon toward point B.

Answer:

Explanation:

Let the spring constant of spring A and B be k₁ and k₂ . Mass of box X and Y be m₁ and m₂ .

Force created in spring which is stretched by d is kd where k is spring constant .

At her lab in Orlando, Florida,

k₁ x .0204 m = m₁ g where g is acceleration due to earth's gravity

k₁ = 49 m₁ g

At a research station on the moon

k₁ x .34 x 10⁻² m = m₁ g₁ where g₁ is acceleration due to gravity at moon

k₁  = 294 .11 m₁ g₁

49 m₁ g = 294 .11 m₁ g₁

g = 6.0022  g₁

At a research station on the moon

k₁ x .54 x 10⁻² m = m₂ g₁

k₁ = 185.18 m₂ g₁

294 .11 m₁ g₁ = 185.18 m₂ g₁

1.588 m₁ =  m₂

1 )

At her lab in Orlando, Florida,

k₁ x d  = m₂ g , where d is the new stretch that is to be calculated .

185.18 m₂ g₁ d =m₂ g

185.18 d  g₁ = g

185.18 d  g₁ = 6.0022  g₁

d = .03241 m

= 3.24 cm .

2 )

At a research station on the moon

when Block Y is hanging from Spring B

k₂ x .013   = m₂ g₁

k₂ = 76.92 m₂ g₁

At her lab in Orlando, Florida,

Spring B stretch when Block X is hanging from it

k₂ d₁ = m₁ g

76.92 m₂ g₁ d₁ = m₁ g

76.92 m₂ g₁ d₁ = m₁ 6.0022  g₁

76.92 m₂  d₁ = m₁ 6.0022  

12.815  x  1.588 m₁ x  d₁ = m₁

d₁ = .049 m

= 4.9 cm .

In this exercise we have to use the knowledge of springs to calculate the distance from it, that way:

A)d=3.24 cm

B)d=4.9 cm

So, before starting the calculations, we have to organize the values ​​and put everything in function of a single unknown such as:

\(k_1 * 0.34 * 10^{-2} m = m_1 g_1\\ k_1 = 294 .11 m_1 g_1\\49 m_1 g = 294 .11 m_1 g_1\\g = 6.0022 g_1\\k_1 *0 .54 * 10^{-2} m = m_2 g_1\\k_1 = 185.18 m_2 g_1\\294 .11 m_1 g_1 = 185.18 m_2 g_1\\1.588 m_1 = m_2\)

A) By calculating the distance we find that:

\(k1_1 * d = m_2 g\\185.18 m_2 g_1 d =m_2 g\\185.18 d g_1 = g\\185.18 d g_1 = 6.0022 g_1\\d = 0.03241 m= 3.24 cm\)

B) So now calculating the distance from the lab to the moon, so:

\(k_2* 0.013 = m_2 g_1\\k_2 = 76.92 m_2 g_1\\k_2 d_1 = m_1 g\\76.92 m_2 g_1 d_1 = m_1 g\\76.92 m_2 g_1 d_1 = m_16.0022 g_1\\76.92 m_2 d_1 = m_1 6.0022\\12.815 * 1.588 m_1 * d_1= m_1\\d_1 = 0.049 m = 4.9 cm\)

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Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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If the applied force is 20 N and the displacement is from X=0m to X=5.0m, the work done is 100 Joules.

To determine the work done by a force, you need to know the displacement and the component of the force parallel to the displacement.

In this case, if the force applied is 20 N and the displacement is from X=0m to X=5.0m, you need to determine if the force is parallel to the displacement.

If the force is parallel to the displacement, then the work done is simply the product of the force and the displacement, which is:

Work = Force x Displacement

Work = 20 N x (5.0 m - 0 m)

Work = 100 Joules

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The complete question is below:

What is the work done from X =0m to 5.0m? if the applied force is 20 N

Answer:

1.2703 km

Explanation:

The speed can be calculated using the formula;

Speed (m/s) = distance (m) ÷ time (s)

Based on the information in this question, it took 3.7 seconds for a sound with speed of 1236 km/h to reach John. The distance will be:

Distance = speed × time

However, we need to convert the time in seconds (s) to hour (hr).

1 second = 0.000277778 hour

3.7 seconds = 0.00102778 hours.

Hence,

distance = 1236 × 0.00102778

Distance = 1.2703 km

Answer:

2 m/s²

Explanation:

Note : -

g should be expresses in kg.

1 g = 0.001 kg

5000 g = 5 kg

Given,

Mass ( m ) = 5 kg

Force ( F ) = 10 N

To find : Acceleration ( a ) = ?

Formula : -

F = ma

a = F / m

a = 10 / 5

a = 2 m/s²

Therefore,

the acceleration is 2 m/s².

\(\text{Given that,}\\\\\text{Mass,}~m = 5000g = 5000 \times 10^{-3} =5~ \text{kg}\\\\\text{Force,} ~ F = 10~ N\\\\\text{Use newton's second law,}\\\\F =ma\\\\\implies a = \dfrac{F}{m} = \dfrac{10}{5} = 2 ~ \text{ms}^{-2}\)

Answer: endurance, strength, balance, flexibility

Explanation:

walking, jogging, swimming, biking

Answer:

The value  of  the function is  \(q__{t }} = 1.878 *10^{35}\)

Explanation:

From the question we are told that

     The temperature is  \(T = 1000 \ K\)

      The volume  is  \(V = 1 m^3\)

Generally the  transnational partition function is mathematically represented as

        \(q__{t }} = [\frac{2 * \pi * m * k * T }{ N_a * h} ]^{\frac{3}{2} } * V\)

Where  m is the molar mass of oxygen with a constant value of  \(m = 32 *10^{-3} \ kg/mol\)

 k  is the Boltzmann constant with a value  of  \(k = 1.38 *10^{-23 } \ J/K\)

\(N_a\) is the Avogadro Number with a constant value of  \(N_a = 6.022 *10^{23} \ atoms\)

h is  the Planck's  constant  with value   \(h = 6.626 *10^{-34 } \ J\cdot s\)

Substituting values

       \(q__{t }} = [\frac{2 * 3.142 * 32*10^{-3} * 1.38 *10^{-23} * 1000 }{ 6.022 *10^{23} * [6.626 *10^{-34}] ^2 }]^{\frac{3}{2} } * 1\)

       \(q__{t }} = 1.878 *10^{35}\)

Mona's conclusion that convection is the main way that energy escapes from the water when there is no lid may or may not be a good conclusion, depending on the context and information provided.

Convection is a process of heat transfer that involves the movement of fluids (in this case, the water) due to differences in temperature. It occurs when warmer portions of the fluid rise and cooler portions sink, creating a circulating flow.

To determine if Mona's conclusion is valid, additional information is needed. Factors such as the presence of other heat transfer mechanisms (such as radiation or evaporation), the specific setup of the experiment, and the conditions under which the observations were made are essential.

If Mona's experiment only considered convection as the primary mechanism for energy escape and excluded other factors, her conclusion might be incomplete or inaccurate. To draw a more comprehensive conclusion, it is necessary to consider other potential heat transfer mechanisms and perform further investigations or provide additional supporting data.

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Explanation:

13x - 26 + 39 = 0

13x=26-39

13x=-13

x= -1

\(13x-26+39=0\\\\\implies 13x +13 = 0\\\\\implies 13x = -13\\\\\implies x = -\dfrac{13}{13}\\\\\implies x = -1\)

Answer:

Trabajo = Δ E

Explanation:

Podemos escribir esta declaración como una ecuación que hace que sea muy fácil ver la relación: Trabajo = Δ E, donde E es energía, y la letra griega Delta significa ‘cambio en’. Entonces leemos esto como: trabajo = cambio de energía. Esto nos ayuda a comprender por qué no se realiza ningún trabajo en una pared que no se mueve.

The work- energy theorem states that the work done by the sum of  forces acting on an object is  equal to  the change in the kinetic energy of the object.

According to work -energy theorem, the force resulting in a work done which is equal to the change in kinetic energy of the object. When a force applied on a body results in a displacement of the body, it is said to be work done on the body.

Kinetic energy of an object is the energy generated by virtue of its motion. It related to the mass and velocity as written below:

Ke  = 1/2 mv²

Let, Vi be the initial velocity and Vf be the final velocity, then the change in kinetic energy is written as:

ΔKe =  1/2 mVf² -  1/2 mVi²

According to wok energy theorem, the work done is equal to the this kinetic energy change.

Hence, W = ΔKe.

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Answer:

a. 273 K b. 90.1 K c. 5.26 atm d. 0.33 atm

Explanation:

For isothermal expansion PV = constant

So, P₁V₁ = P₂V₂ where P₁ = initial pressure of gas = 1 atm (standard pressure), V₁ = initial volume of gas, P₂ = final pressure of gas and V₂ = final volume of gas,

So, P₁V₁ = P₂V₂

P₂ = P₁V₁/V₂

Since V₂/V₁ = 0.19,

P₂ = P₁V₁/V₂

P₂ = 1 atm (1/0.19)  

P₂ = 5.26 atm

For an adiabatic expansion, PVⁿ = constant where n = ratio of molar heat capacities = 5/3 for monoatomic gas

So, P₂V₂ⁿ = P₃V₃ⁿ where P₂ = initial pressure of gas = 5.26 atm, V₂ = initial volume of gas, P₃ = final pressure of gas and V₃ = final volume of gas,

So, P₂V₂ⁿ = P₃V₃ⁿ

P₃ = P₂V₂ⁿ/V₃ⁿ

P₃ = P₂(V₂/V₃)ⁿ

Since V₃ = V₁ ,V₂/V₃ = V₂/V₁ = 0.19

1/0.19,

P₃ = P₂(V₂/V₃)ⁿ

P₃ = 5.26 atm (0.19)⁽⁵/³⁾

P₃ = 5.26 atm × 0.0628

P₃ = 0.33 atm

Using the ideal gas equation

P₃V₃/T₃ = P₄V₄/T₄ where P₃ = pressure after adiabatic expansion = 0.33 atm , V₃ = volume after adiabatic expansion, T₃ = temperature after adiabatic expansion  P₄ = initial pressure of gas = P₁ = 1 atm , V₄ = initial volume of gas = V₁ and T₄ = initial temperature of gas = T₁ = 273 K (standard temperature)

P₃V₃/T₃ = P₄V₄/T₄

T₃ = P₃V₃T₄/P₄V₄    

T₃ = (P₃/P₄)(V₃/V₄)T₂

Since V₃ = V₄ = V₁ and P₄ = P₁

V₃/V₄ = 1 and P₃/P₄ = P₃/P₁

T₃ = (P₃/P₁)(V₃/V₄)T₂

T₃ = (0.33 atm/1 atm)(1)273 K  

T₃ = 90.1 K

So,

a. The highest temperature attained by the gas is T₁ = 273 K

b. The lowest temperature attained by the gas = T₃ = 90.1 K

c. The highest pressure attained by the gas is P₂ = 5.26 atm

d. The lowest pressure attained by the gas is P₃ = 0.33 atm

Answer:

The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.

Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:

Free Fall Velocity Graph

A car has an acceleration of 4m/s squared. If it started with a velocity of 30m/s, 38m/s is its final velocity.

Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight forward is accelerated when it accelerates or decelerates.

Even though the speed is constant, motion on a circle accelerates so because direction is always shifting. Both tangential to the acceleration for all other motions.

v = u + at

V= final velocity=?

U= initial velocity=  30m/s

a= acceleration = 4m/s²

substituting all the given values in the above equation, we get

v = 30+ 4× 2

V= 38m/s

Therefore,  38m/s  is its final velocity.

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B) A pendulum is a mass suspended on the bottom of a string.

A pendulum is a simple mechanical device that consists of a mass (known as the bob) suspended from a fixed point by a string, wire, or rod. When the bob is pulled to one side and released, it swings back and forth under the influence of gravity, forming a regular pattern of motion. The time it takes for the pendulum to complete one full swing (i.e., from one extreme position to the other and back again) is known as its period. The period of a pendulum is affected by the length of the string and the strength of gravity. The longer the string, the longer the period, and the stronger the gravity, the shorter the period.Pendulums have a wide range of practical applications, such as timekeeping, as seen in grandfather clocks. They are also used in scientific experiments to measure time intervals and gravitational acceleration.

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During an earthquake, it is important to take appropriate steps to ensure safety

(i) When you are in the classroom

Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.

Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.

Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.

(ii) When you are out of danger:

Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.

Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.

Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.

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