Answer:
B
Step-by-step explanation:
An isoceles triangle has two equal sides. Based on the picture, sides AC and AB have equal length (as given by the lines in the middle of sides AC and AB).
The triangle is also a right triangle (usually the square in the top-left corner is the dead giveaway that whether it is a right triangle).
Solve dy/dx=1/3(sin x − xy^2), y(0)=5
The general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is: y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5
To solve this differential equation, we can use separation of variables.
First, we can rearrange the equation to get dy/dx on one side and the rest on the other side:
dy/dx = 1/3(sin x − xy^2)
dy/(sin x - xy^2) = dx/3
Now we can integrate both sides:
∫dy/(sin x - xy^2) = ∫dx/3
To integrate the left side, we can use substitution. Let u = xy^2, then du/dx = y^2 + 2xy(dy/dx). Substituting these expressions into the left side gives:
∫dy/(sin x - xy^2) = ∫du/(sin x - u)
= -1/2∫d(cos x - u/sin x)
= -1/2 ln|sin x - xy^2| + C1
For the right side, we simply integrate with respect to x:
∫dx/3 = x/3 + C2
Putting these together, we get:
-1/2 ln|sin x - xy^2| = x/3 + C
To solve for y, we can exponentiate both sides:
|sin x - xy^2|^-1/2 = e^(2C/3 - x/3)
|sin x - xy^2| = 1/e^(2C/3 - x/3)
Since the absolute value of sin x - xy^2 can be either positive or negative, we need to consider both cases.
Case 1: sin x - xy^2 > 0
In this case, we have:
sin x - xy^2 = 1/e^(2C/3 - x/3)
Solving for y, we get:
y = ±√[(sin x - 1/e^(2C/3 - x/3))/x]
Note that the initial condition y(0) = 5 only applies to the positive square root. We can use this condition to solve for C:
y(0) = √(sin 0 - 1/e^(2C/3)) = √(0 - 1/e^(2C/3)) = 5
Squaring both sides and solving for C, we get:
C = 3/2 ln(1/25)
Putting this value of C back into the expression for y, we get:
y = √[(sin x - e^(x/2)/25)/x]
Case 2: sin x - xy^2 < 0
In this case, we have:
- sin x + xy^2 = 1/e^(2C/3 - x/3)
Solving for y, we get:
y = ±√[(e^(2C/3 - x/3) - sin x)/x]
Again, using the initial condition y(0) = 5 and solving for C, we get:
C = 3/2 ln(1/25) + 2/3 ln(5)
Putting this value of C back into the expression for y, we get:
y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x]
So the general solution to the differential equation dy/dx = 1/3(sin x − xy^2), y(0)=5 is:
y = ±√[(sin x - e^(x/2)/25)/x], if sin x - xy^2 > 0 and y(0) = 5
y = -√[(e^(2/3 ln 5 - x/3) - sin x)/x], if sin x - xy^2 < 0 and y(0) = 5
Note that there is no solution for y when sin x - xy^2 = 0.
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Suppose the commute times for employees of a large company follow a
normal distribution. If the mean time is 22 minutes and the standard
deviation is 5 minutes, 95% of the employees will have a travel time within
which range?
A. 17.25 minutes to 26.75 minutes
B. 12 minutes to 32 minutes
C. 7 minutes to 37 minutes
D. 17 minutes to 27 minutes
Answer:
12 minutes to 32 minutes
Step-by-step explanation:
just took exam
If the mean time is 22 minutes and the standard deviation is 5 minutes, 95% of the employees will have a travel time within 12 minutes and 32 minutes.
What is Statistics?Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.
We know that the mean travel time is 22 minutes (µ = 22) and the standard deviation is 5 minutes (σ = 5).
Using the empirical rule, we know that 95% of the data will fall within 2 standard deviations of the mean.
Therefore, we need to find the interval that is 2 standard deviations away from the mean in both directions.
The lower end of the range would be:
µ - 2σ = 22 - 2(5) = 12 minutes
The upper end of the range would be:
µ + 2σ = 22 + 2(5) = 32 minutes
Therefore, 95% of the employees will have a travel time between 12 minutes and 32 minutes.
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Using Stokes theorem, evaluate \int \ints curl FdS where F =(-y,x,xyz) and S is the part of the sphere x2+y2+z2 = 25 lying below plane z = 4 w/ positive orientation.
Main Answer: The integral ∬(curl F) · dS = 0.
Supporting Question and Answer:
What is Stokes' theorem and how is it used to evaluate line integrals over closed surfaces?
Stokes' theorem relates a line integral of a vector field around a closed curve to a surface integral of the curl of that vector field over the region bounded by the curve. It states that the line integral of a vector field around a closed curve C is equal to the surface integral of the curl of the vector field over the surface S bounded by C. Mathematically, it can be expressed as ∮C F · dr = ∬S (curl F) · dS. This theorem provides a convenient way to evaluate line integrals over closed surfaces by converting them into surface integrals using the curl of the vector field.
Body of the Solution:To evaluate the integral using Stokes' theorem, we first need to compute the curl of the vector field F = (-y, x, xyz).
The curl of F is given by: curl F = (d/dx, d/dy, d/dz) × (-y, x, xyz)
Let's calculate the individual components of the curl:
(d/dx) × (-y, x, xyz) = (0, 0, (d/dx)(-y) - (d/dy)(x))
= (0, 0, 0 - 1) = (0, 0, -1)
(d/dy) × (-y, x, xyz) = (0, 0, (d/dy)(-y) - (d/dx)(x))
= (0, 0, -1 - 1) = (0, 0, -2)
(d/dy) × (-y, x, xyz) = (0, 0, (d/dy)(-y) - (d/dx)(x))
= (0, 0, -1 - 1) = (0, 0, -2)
(d/dz) × (-y, x, xyz)= ((d/dz)(x) - (d/dx)(xyz), (d/dz)(y) - (d/dy)(xyz), 0)
= (0 - yz, 0 - xz, 0)
= (-yz, -xz, 0)
Now, we have the curl of F as curl F = (0, 0, -1) + (0, 0, -2) + (-yz, -xz, 0)
= (-yz, -xz, -3)
Next, we need to find the surface S, which is the part of the sphere x^2 + y^2 + z^2 = 25 lying below the plane z = 4. To determine the orientation, we consider the outward-pointing normal vector.
The equation of the sphere can be written as z = sqrt(25 - x^2 - y^2). Since the plane is z = 4, we have sqrt(25 - x^2 - y^2) = 4. Solving for z, we get z = 4.
So, the surface S is given by S: x^2 + y^2 + z^2 = 25, z = 4.
To apply Stokes' theorem, we need to calculate the surface area vector dS. For a sphere, the surface area vector is simply the outward-pointing normal vector, which is (0, 0, 1) for our surface S.
Finally, we can evaluate the given integral using Stokes' theorem:
∬(curl F) · dS = ∭(div(curl F)) dV
Since the curl of F is (0, 0, -3), the divergence of curl F, div(curl F), is 0.
Thus, the integral ∬(curl F) · dS = ∭(div(curl F)) dV = 0.
Final Answer:Therefore, the value of the given integral is 0.
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The integral ∬(curl F) · dS = 0.
What is Stokes' theorem and how is it used to evaluate line integrals over closed surfaces?
Stokes' theorem relates a line integral of a vector field around a closed curve to a surface integral of the curl of that vector field over the region bounded by the curve. It states that the line integral of a vector field around a closed curve C is equal to the surface integral of the curl of the vector field over the surface S bounded by C. Mathematically, it can be expressed as ∮C F · dr = ∬S (curl F) · dS. This theorem provides a convenient way to evaluate line integrals over closed surfaces by converting them into surface integrals using the curl of the vector field.
To evaluate the integral using Stokes' theorem, we first need to compute the curl of the vector field F = (-y, x, xyz).
The curl of F is given by: curl F = (d/dx, d/dy, d/dz) × (-y, x, xyz)
Let's calculate the individual components of the curl:
(d/dx) × (-y, x, xyz) = (0, 0, (d/dx)(-y) - (d/dy)(x))
= (0, 0, 0 - 1) = (0, 0, -1)
(d/dy) × (-y, x, xyz) = (0, 0, (d/dy)(-y) - (d/dx)(x))
= (0, 0, -1 - 1) = (0, 0, -2)
(d/dy) × (-y, x, xyz) = (0, 0, (d/dy)(-y) - (d/dx)(x))
= (0, 0, -1 - 1) = (0, 0, -2)
(d/dz) × (-y, x, xyz)= ((d/dz)(x) - (d/dx)(xyz), (d/dz)(y) - (d/dy)(xyz), 0)
= (0 - yz, 0 - xz, 0)
= (-yz, -xz, 0)
Now, we have the curl of F as curl F = (0, 0, -1) + (0, 0, -2) + (-yz, -xz, 0)
= (-yz, -xz, -3)
Next, we need to find the surface S, which is the part of the sphere x^2 + y^2 + z^2 = 25 lying below the plane z = 4. To determine the orientation, we consider the outward-pointing normal vector.
The equation of the sphere can be written as z = sqrt(25 - x^2 - y^2). Since the plane is z = 4, we have sqrt(25 - x^2 - y^2) = 4. Solving for z, we get z = 4.
So, the surface S is given by S: x^2 + y^2 + z^2 = 25, z = 4.
To apply Stokes' theorem, we need to calculate the surface area vector dS. For a sphere, the surface area vector is simply the outward-pointing normal vector, which is (0, 0, 1) for our surface S.
Finally, we can evaluate the given integral using Stokes' theorem:
∬(curl F) · dS = ∭(div(curl F)) dV
Since the curl of F is (0, 0, -3), the divergence of curl F, div(curl F), is 0.
Thus, the integral ∬(curl F) · dS = ∭(div(curl F)) dV = 0.
Therefore, the value of the given integral is 0.
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Does anyone know 12 x 25 in distributive property?
Answer:
5(2.4*5)
Step-by-step explanation:
You can divide each of those numbers by any numbers then put it outside the parenthesis
HELP ME ASP PLEASE thank you
Nick bought a new car.
each year the car depreciates in value by 12%.
work out the number of years it takes for the car to half in value.
?
After 5.4 years, the value of the car will be half the initial value.
How many years take for the car to be half in value?
We know that the value decreases by 12% each year.
Then the value of the car can be modeled with an exponential decay, written as:
\(V(t) = A*(1 - 12 \% /100 \%)^t = A*(1 - 0.12)^t = A*(0.88)^t\)
Where A is the initial value, and t is the number of years.
The value will be halved when:
\((0.88)^t = 0.5\)
We need to solve that, to do it, we can apply the natural logarithm to both sides, so we get:
\(Ln(0.88^t) = Ln(0.5)\\\\t*Ln(0.88) = Ln(0.5)\\\\t = Ln(0.5)/Ln(0.88) = 5.4\)
This means that after 5.4 years, the value of the car will be half the initial value.
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A. 58
B. 110
C. 45
D. 51
Answer:
A. 58
Step-by-step explanation:
70° + m<3 + 52° = 180°
m<3 = 58°
Answer:
A. 58°
Step-by-step explanation:
here's your solution
==> 70° + 52° + angle 3 = 180°. [linear pair]
==> angle 3 + 122° = 180°
==> angle 3 = 180° - 122°
==> angle 3 = 58°
hope it helps
Please help me- please-
a team played 7 games. In those games the team won by 7points,lostby10,won by 8, won by 11,lostby2 and won by 10. What was the mean difference in game scores in the six games
The mean difference in game scores over the six games is 12
What is mean difference?The mean difference, or difference in means, measures the absolute difference between the mean value in two different groups.
Given the points by which a basketball team either won or lost 6 games.
- Won by 7 points = +7
- Lost by 10 points = -10
- Won by 8 points = +8
- Won by 11 points = +11
- Lost by 2 points = -2
- Won by 10 points = +10
Thus;
Mean difference of the 6 games is;
= (+7 - 10 + 8 + 11 - 2 + 10)/6
= 24/6
= 12
Hence, the mean difference in game scores over the six games is 12
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13
n is a positive whole number.
(a) What type of positive whole number is 2n - 1?
(1)
(6) Write down an expression for the nth multiple of 5
(1)
Alan has 4 boxes of cakes.
There is the same number of cakes in each box.
Alan has a total of t cakes.
(c) Write down an expression, in terms of t, for the number of cakes in each box.
(1)
Answer:
use the Microsoft world language to define noun phrases and figure of speech
PLS HELP REALLY NEED HELP!!!!!!!!!!!!!!!
Answer:
the answer is A
Step-by-step explanation:
Answer:
A. - ∞ < x < ∞
Step-by-step explanation:
Harmony earns a $42,000 salary in the first year of her career. Each year, she gets a 4%, percent raise.
Which expression gives the total amount Harmony has earned in her first n years of her career?
Answer:
42000*1.04^(n-1)
Step-by-step explanation:
4% is equal to 0.04, a raise is 1+0.04=1.04
1.04 is now the number we are multiplying by to get a new yearly salary for Harmony.
42000*1.04^(n-1) since n is how many years after she has the job you have to raise it to the power and subtract one.
Solve for X
(I have no idea what I'm doing and my calculator is dead)
The required value of x is 8 in the given right triangle.
What is the right triangle?A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.
The triangle given in the question is a right triangle.
According to the given figure, the required solution would be as:
In triangle Δ ABD,
Side BD = x
Side AB = 8 units
∠B = 45° (As per the given figure 90°/2 = 45°)
To find side BD,
We know that tan B = AB/BD
⇒ tan B = AB/BD
⇒ tan 45° = 8 / x
∵ tan 45° = 1
⇒ 1 = 8 / x
⇒ x = 8
Thus, the required value of x is 8 in the given right triangle.
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I need the answer
Please
Answer:
c
Step-by-step explanation:
Answer:
C is corect answer to this exercice
What inequality matches the statement : A number is at most 40
Answer:
N ( a number) \(\leq\) 40
Step-by-step explanation:
Or just say
N \(\leq\) 40
Answer:
x≤40
Step-by-step explanation:
x (x is number in this case)
x≤40
The special sign used has the line under it because it includes 40 as well (at most is used not less than).
:) Hope this helps :)
At a school carnival, the diameter of the mat of a trampoline is 16 feet and the diameter of its metal frame is 18 feet. What is the length, in feet, of the metal frame that surrounds the trampoline? Use 3. 14 for π and round your answer to the nearest tenth. 50. 2 feet 56. 5 feet 100. 5 feet 113. 0 feet.
Answer:
(b) 56.5 ft
Step-by-step explanation:
The circumference of a circle of diameter d is given by ...
C = πd
For the given diameter, the circumference of the frame is ...
C = (3.14)(18 ft) ≈ 56.52 ft
The length of the outside edge of the frame is about 56.5 feet.
George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and the cover extends 12 inches beyond the edge of the pool. A rope runs along the edge of the cover to secure it in place.
a. What is the area of the pool cover?
b. What is the length of the rope?
You must show all of your work to receive credit
Answer:
The cover has diameter of:
20 feet + 2*12 inches = 20 feet + 2 feet = 22 feeta.
Area of the pool cover:
A = πd²/4 = 3.14*22²/4 = 379.94 ft²b.
The length of the rope:
C = πd = 3.14*22 = 69.08 ftAnswer:
346.19ft65.94ftStep-by-step explanation:
Add the length of the pool and the extent the pool cover [ 12in = 1ft ] has over the pool.
20 + 2 = 22ft
Part A:
The formula for the area of a circle is πr².
To find the radius just divide by two; 22 / 2 = 11ft
= π(11)²
= 121π
≈ 379.94ft
Part B:
We can use the circumference formula [ dπ ] to find how long the rope is.
= 22(3.14)
= 69.08ft
Best of Luck!
A cone has a base with a radius of 9 mm and a height of 13 mm. What is the volume of the cone?
Approximate volume:
mm
(Round to the hundredths place.)
\(\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}\)
Given - a cone with base radius 9mm and height 13 mmTo calculate - volume of the coneWe know that ,
\(Volume \: of \: cone = \frac{1}{3}\pi \: r {}^{2} h \\ \)
substituting the values in the formula ,
\(Volume = \frac{1}{3} \times 3.14 \times 9 \times 9 \times 13 \\ \\ \implies \: 1.05 \times 81 \times 13 \\ \\ \implies \: 1105.65 \: mm {}^{3} \)
hope helpful ~
50 dividido 11 con la explicación
Marcy and Meredith are tracing the rectangular swimming pool at 92nd Street YMCA. Marcy uses a scale 3 inches to 4 feet. The width of the swimming pool is 26 feet. Meredith’s width is 14 inches. What is the height of Meredith’s tracing?
the height of Meredith's tracing is approximately 223.09 inches. To find the height of Meredith's tracing, we need to use the scale that she is using to draw the rectangular swimming pool.
We know that Marcy's scale is 3 inches to 4 feet, which means that 1 inch represents 4/3 feet. Let's convert the width of the pool from feet to inches using Marcy's scale:
Width of pool in inches = 26 feet * (3 inches/4 feet) = 19.5 inches
Now, we can use Meredith's width of 14 inches to find the scale that she is using. Since the width of the pool on Meredith's tracing is 14 inches, we can set up the following equation:
1 inch on Meredith's scale = 19.5 inches on Marcy's scale
Solving for the scale factor, we get:
1 inch on Meredith's scale = (19.5 inches)/(14 inches) = 1.3929
This means that 1 inch on Meredith's scale represents 1.3929 feet. Now, we can use this scale to find the height of Meredith's tracing. We know that the length of the pool is not given, but since it is a rectangular pool, the height should be proportional to the width. Specifically, the height should be:
Height of pool in feet = (height/width) * 26 feet
We can use Meredith's scale to convert this to inches:
Height of pool in inches = (height/width) * 26 feet * (12 inches/foot) * (1 inch/1.3929 feet)
Simplifying this expression, we get:
Height of pool in inches = 22.243 * (height/width)
Now, we can use the given width of Meredith's tracing (14 inches) and the scale factor (1.3929) to find the height of her tracing:
Height of Meredith's tracing = 14 inches * (22.243/1.3929) = 223.09 inches
Therefore, the height of Meredith's tracing is approximately 223.09 inches.
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Nico buys an item that is $15.00, and uses a 10% off coupon. How much does he save by using the coupon? *
Answer:
$1.5
Step-by-step explanation:
10% = 0.10
$15.00 x 0.10 = $1.5
Nico pays $13.50 and saves $1.50
A section of a copper porphyry ore body is as shown. Determine the most profitable final pit outline using Lerchs-Grossman 2D given that the cut-off grade of 0.45% Cu. 1 block has dimensions of 16m x 16m x 16m (HxLxW). The cost of mining a block waste is $50 and that a value of a block of ore is approximated to be $100 x (grade expressed in %). Keep the pit angle at 45 degrees.
Lerchs-Grossman algorithm is a pit optimization software that helps in the determination of the most profitable final pit outline. The section of a copper porphyry ore body given has a cut-off grade of 0.45% Cu. Each block has dimensions of 16m x 16m x 16m (HxLxW).
The cost of mining a block of waste is $50, and the value of a block of ore is approximated to be $100 x (grade expressed in %). Firstly, we have to calculate the net present value (NPV) for all the blocks that are above the cut-off grade. NPV is calculated using the formula given below:
NPV = ((grade*100)*100)-50
Here, the cost of mining a block of waste is $50 and the value of a block of ore is approximated to be $100 x (grade expressed in %).
1. Firstly, the net present value (NPV) of each block above the cutoff grade is calculated.2. The blocks are then sorted in descending order of their NPVs.
3. Next, the algorithm calculates the limits of the pit at a sequence of levels, starting with the block of highest NPV.
4. It is assumed that the pit will extend downwards through the blocks from the highest NPV downwards.
5. If the pit reaches the edge of the ore body before reaching a certain level, it is truncated and the lower level is tried.
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find f '(0.4) for f of x equals the integral from 0 to x of the arcsine of t, dt. 0.081 0.412 0.389 1.091
The task is to find f '(0.4) for the function f(x) = ∫[0 to x] arcsin(t) dt. The possible answers are: 0.081, 0.412, 0.389, and 1.091. The closest value to 0.4115 is 0.412. Thus, the answer is 0.412.
To find f '(0.4), we need to differentiate the function f(x) with respect to x. Applying the Fundamental Theorem of Calculus, we have f '(x) = arcsin(x). Therefore, to find f '(0.4), we substitute x = 0.4 into the derivative expression: f '(0.4) = arcsin(0.4). Evaluating this trigonometric function, we find that arcsin(0.4) is approximately 0.4115. Among the given options, the closest value to 0.4115 is 0.412. Thus, the answer is 0.412.
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Dora bought a bottle of nail polish that was marked down by 20 percent from its original price of $4.50. Including a 9 percent sales tax, what is the final cost of the bottle of nail polish?
Answer:
Hey there!
Marked down by 20 percent is equal to 80 percent of the original value.
4.5(0.8)=3.6
9 percent sales tax
3.6(1.09)=3.92
Hope this helps :)
Answer:
$3.92
Step-by-step explanation:
I took the test
X
3
7
+
Simplify:X-3 X+4 x²+x-12
Rewrite the expression using the LCD:
Ox(x+4)-3(x-3)+7
(x-3)(x+4)
O x(x+4)+3(x – R+7
(x-3)(x+4)
x(x+4)+3(x-3) -7
(x-3)(x+4)
Answer: it’s a
Step-by-step explanation:
Answer: A for the first part and B for the second part
Step-by-step explanation:
*URGENT* I need help with 5,6,7 please answer correctly and quickly
Answer:
Step-by-step explanation:
(5). ( \(x_{1}\) , \(y_{1}\) )
y - \(y_{1}\) = m( x - \(x_{1}\) )
~~~~~~~~~~~~~~~~~
( 4 , 8 )
y = \(\frac{1}{7}\) x - 5 ; slope m = \(\frac{1}{7}\)
Slope of line ⊥ to the given line is opposite reciprocal to \(\frac{1}{7}\) and equal to ( - 7)
y - 8 = - 7( x - 4 )
(6).
( \(x_{1}\) , \(y_{1}\) )
( \(x_{2}\) , \(y_{2}\) )
m = \(\frac{ y_{2} -y_{1} }{ x_{2} -x_{1} }\)
y = mx + b
~~~~~~~~~~~~
( 4 , 3 )
( 5 , 1 )
m = \(\frac{1-3}{5-4}\) = - 2
y - 3 = - 2( x - 4 )
y = - 2x + 11
(7). y = - \(\frac{1}{2}\) x + 2
7. Assume that when you take a bath, you fill a tub to the halfway point. The portion that you fill measures 6 feet by 2 feet by 2.2 feet. When you take a shower, your use a shower head with a flow rate of 2.23 gallons per minutes and you typically spend 8 minutes in the shower. There are 7.5 gallons in one cubic foot. a. Calculate the cubic feet of water for the bath. b. Calculate the cubic feet of water for the shower. C. How many minutes do you need in the shower to use as much water as the bath?
The volume of water filled in the bath tub is 6 feet × 2 feet × 2.2 feet = 26.4 cubic feet. You need 11.83 minutes in the shower to use as much water as the bath.
The volume of water filled in the bath tub is 6 feet × 2 feet × 2.2 feet = 26.4 cubic feet.
The amount of water used in shower = flow rate × time = 2.23 gallons/minute × 8 minutes = 17.84 gallons
Let's convert gallons to cubic feet: 1 cubic foot = 7.5 gallons
17.84 gallons = 17.84/7.5 cubic feet = 2.378 cubic feet
The volume of water used in the shower is 2.378 cubic feet. The volume of water used for taking a bath is 26.4 cubic feet.
To calculate how many minutes one would need in the shower to use as much water as the bath, divide the volume of water used in taking a bath with the amount of water used per minute in the shower as shown:
26.4/2.23=11.83 min
Therefore, one needs 11.83 minutes in the shower to use as much water as the bath.
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What is the equation of the line that passes through the point (-4,-3)(−4,−3) and has a slope of -3/4
The equation of the line is y = -(3/4)x - 6.
What is a line?A line is a perfectly straight, one-dimensional shape that extends endlessly in both directions and has no thickness.
Given that, the line passes through the points (-4,-3) and has a slope of -3/4.
The equation of the line in point-slope form is:
y - y₁= m (x -x ₁)
Substitute (x₁,y₁) = (-4,-3) and m = -3/4 into the above equation,
y - (-3) = -3/4 (x - (-4))
y + 3 = -3/4 (x + 4)
y = -(3/4)x -3 -3
y = -(3/4)x - 6
Hence, the equation of the line is y = -(3/4)x - 6.
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Part 1 #1: Polygon ABCD is similar to polygon PQRS. Which proportion must be true?a. AC:AD=PQ:PSb. BC:CD=QR:RSc. AB:BD=PQ:QRd. CD:AB=PQ:RS
In a similar polygon, corresponding sides are proportional. Therefore, the proportion that must be true when polygon ABCD is similar to polygon PQRS is d. CD:AB = PQ:RS.
This means that the ratio of the length of side CD to the length of side AB in polygon ABCD should be equal to the ratio of the length of side PQ to the length of side RS in polygon PQRS. It is important to note that the order of the sides matters in the proportion.
In this case, CD corresponds to PQ, and AB corresponds to RS. By setting up this proportion, we can compare the lengths of corresponding sides in similar polygons and establish the relationship between them.
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Without using a calculator, estimate the value of the expression below. Show your work and explain how you found your answer.
2-3√5
We get - 4.69 as a final resultant from the given expression.
What is Algebraic expression ?
Algebraic expression can be defined as the combination of variables and constants.
Given expression ,
2-3√5
we know that √5 = 2.23
So,
by substituting the given value
we get,
= 2 - 3 * 2.23
so the value of 3 * 2.23 = 6.69
By substituting the given value
we get,
= 2 - 6.69
= -4.69
So the value we get = -4.69
Therefore, We get - 4.69 as a final resultant from the given expression.
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