Which expression results in a sum or difference of four and nine thirty sixths?


Group of answer choices


eight and two thirds minus four and five twelfths


two and three twelfths plus two and one third


six and five ninths minus two and one fourth


three and one fourth plus one and four ninths

a) The Taylor series for f(x) centered at x = 0 can be written in summation notation as f(x) = Σ[(2^r)(x^r)]. The series starts from r = 0 and goes to infinity.

b) To calculate the limit lim(x→3) [f(x) + 3x - 7], we substitute the value x = 3 into the expression. If the limit approaches infinity, it needs to be specified whether it is positive infinity (oo) or negative infinity (-oo).

a) The Taylor series for f(x) centered at x = 0 can be expressed in summation notation as f(x) = Σ[(2^r)(x^r)]. Here, r represents the index of summation, starting from 0 and going to infinity. The terms of the series involve powers of x and coefficients of 2 raised to the power of r. This series represents the expansion of the function f(x) around x = 0.

b) To calculate the limit lim(x→3) [f(x) + 3x - 7], we substitute the value x = 3 into the expression. The result will depend on the behavior of f(x) as x approaches 3. If the limit approaches a finite value, it will be the value of the expression at x = 3. If the limit approaches infinity, it needs to be specified whether it is positive infinity (oo) or negative infinity (-oo) to provide a complete answer.

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Answer:

L(t)=5sin(πt)+7

Step-by-step explanation:

Khan

The smallest sample size for the 95% confidence interval for the mean of the population is 359 .

Given the standard deviation is 2.9 , hence  σ =2.9

Margin of error = E = 0.3

At 95% confidence level the z is ,

α = 1 - 95% = 1 - 0.95 = 0.05

α/2 = 0.05 / 2 = 0.025

Zα/2 = Z₀.₀₂₅ = 1.96

Now we know that the sample size is calculated using the formula:

\(n = (z_{\frac{\alpha}{2}} \times \frac{\sigma}{E})^2\)

n = [Z₀.₀₂₅ × σ / E] ²

n = ( 1.96×2.9  /0.3  )²

n = 358.976

n≈ 359

Sample size = n = 359

A confidence interval is a group of estimates for a parameter that is unknown (CI). Although occasionally other criteria, such as 90% or 99%, may also be used to generate confidence intervals. The average degree of confidence has increased to 95%.

The percentage of long-term associated CIs that contain the parameter's actual value is measured by the confidence level. For instance, the parameter's actual value should be present in 95% of all intervals generated at the 95% confidence level.

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Answer:

the anwser is c plz give brainlist

Answer:

Step-by-step explanation:

∠MKQ = 145°

∠PKQ = 20°

∠MKP = ∠MKQ - ∠PKQ = 145° - 20°

∠MKP = 125°

If angle measurement is more than 90°, then it is obtuse angle

So, 125° is obtuse angle

The mass of the radioactive sample at the beginning of the 11th day of the experiment is approximately 286 grams.

Since the mass is decreasing by 14% per day, we can find the mass at the beginning of each day by multiplying the previous day's mass by 0.86 (which is 100% - 14%).

At the beginning of the first day, the mass was 1300 grams.

At the beginning of the second day, the mass is:

1300 grams x 0.86 = 1118 grams (rounded to the nearest gram)

At the beginning of the third day, the mass is:

1118 grams x 0.86 = 962 grams (rounded to the nearest gram)

We can continue this pattern to find the mass at the beginning of the 11th day:

Mass at the beginning of the fourth day: 962 grams x 0.86 = 828 grams

Mass at the beginning of the fifth day: 828 grams x 0.86 = 711 grams

Mass at the beginning of the sixth day: 711 grams x 0.86 = 612 grams

Mass at the beginning of the seventh day: 612 grams x 0.86 = 526 grams

Mass at the beginning of the eighth day: 526 grams x 0.86 = 452 grams

Mass at the beginning of the ninth day: 452 grams x 0.86 = 388 grams

Mass at the beginning of the tenth day: 388 grams x 0.86 = 333 grams

Mass at the beginning of the eleventh day: 333 grams x 0.86 = 286 grams (rounded to the nearest gram)

Therefore, the mass of the radioactive sample at the beginning of the 11th day of the experiment is approximately 286 grams.

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The dot product of vectors a and b  || a |= 6,|| b ||= 4 and the angle between the vectors θ = π/3 is (c) 12.

The dot product of two vectors, we can use the formula:

a · b = ||a|| ||b|| cos(theta)

where ||a|| and ||b|| represent the magnitudes of vectors a and b, respectively, and theta is the angle between the vectors.

In this case, we are given that ||a|| = 6, ||b|| = 4, and the angle between the vectors is theta = π/3.

Substituting these values into the formula, we have:

a · b = 6 × 4 × cos(π/3)

To evaluate cos(π/3), we can use the fact that it is equal to 1/2. So we have:

a · b = 6 × 4 × 1/2

= 12

Therefore, the dot product of vectors a and b is 12.

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Answer:

C :)

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answer:

y = -8/3x + 33

Step-by-step explanation:

y2 - y1 / x2 - x1

9 - 1 / 9 -12

8 / -3

= -8/3

y = -8/3x + b

1 = -8/3(12) + b

1 = -32 + b

33 = b

The t times u is approximately equal to -139.7.

To find t times u, we use the formula for the dot product: t · u = |t||u|cosθ, where θ is the angle between the vectors. Since we are only given the vectors t and u, we need to find their magnitudes and the angle between them.

The magnitude of t is |t| = √(7^2 + (-3)^2) = √58, and the magnitude of u is |u| = √((-10)^2 + (-8)^2) = √164.

To find the angle between t and u, we use the formula cosθ = (t · u)/(|t||u|). Substituting the values we know, we get cosθ = ((7)(-10) + (-3)(-8))/((√58)(√164)) = -74/(2√1017). Using a calculator, we find that θ ≈ 131.5 degrees.

Now we can find t · u: t · u = |t||u|cosθ = (√58)(√164)(cos(131.5)) ≈ -139.7.

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Answer:

B.

Step-by-step explanation:

We answer that before thank you

To make the points in the scatterplot easier to find, the geom jitter() function method first builds a scatterplot and then adds a little amount of random noise to each point in the plot.

A scatterplot is produced using the ggplot2 function in R called geom jitter(). Each point in the plot receives a small bit of random noise to make them simpler to locate. The link between two variables in a dataset is visualised using this function.

The geom jitter() function can help to make data points easier to differentiate in a scatterplot by adding a small amount of random noise to each point. This is particularly useful when there is a lot of overlap between data points in the plot. The amount of jitter can be adjusted to ensure that the data points are still distinguishable, while still providing a more accurate representation of the data. Additionally, it can be used to adjust the size, color, and shape of the data points, allowing for a more customized visualization.

# Example of geom_jitter()

# Load ggplot2

library(ggplot2)

# Create data

x <- c(1,2,3,4,5,6,7,8,9,10)

y <- c(4,5,6,7,8,9,10,11,12,13)

# Plot data

ggplot(data = data.frame(x,y), aes(x, y)) +

geom_jitter()

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1 yard = 3 feet

3ft * 2 yards = 6 feet

$1.26 / 6ft = $0.21 / ft

Step-by-step explanation:

Area of trapezoid

= 1/2 × 4 × [6 + (5+8)]

= 1/2 × 4 × 19

= 38 cm²

The length of sides BC and XC in the triangle are 8.66 and 10 units respectively

An equation is an expression that contains numbers and variables linked together by mathematical operations of addition, subtraction, multiplication, division and exponents. An equation can either  be linear, quadratic, cubic, depending of the degree of the variable.

Trigonometric ratio is used to show the relationship between the sides and angles of a right triangle.

From the triangle shown, using trigonometric ratio:

sin(30) = 5/XC

XC = 10

Also:

tan(30) = 5/BC

BC = 8.66

The length of BC and XC are 8.66 and 10 units respectively

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A. To determine if an integral is convergent, we analyze the function's behavior, integrability, apply integration techniques, and examine its limits, ensuring they are finite, leading to a finite result.

B. To determine if an integral is divergent, we look for infinite limits, vertical asymptotes, and erratic behavior within the integration interval, indicating the lack of a finite value for the integral.

A. To determine if an integral is convergent, we need to consider several approaches. First, we check for basic convergence criteria such as infinite limits or vertical asymptotes.

Then, we examine integrability, ensuring the function is continuous or has a finite number of discontinuities. Next, we simplify the integral using integration techniques.

Finally, we analyze the behavior of the function at infinity and apply comparison tests if necessary to establish convergence.

B. To determine if an integral is divergent, we follow a series of steps. First, we check for basic divergence criteria such as infinite limits or vertical asymptotes.

Then, we examine integrability, looking for discontinuities that prevent integration. Next, we simplify the integral using integration techniques. Finally, if the integral does not converge, it is deemed divergent.

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Answer:

\(y = - ({x}^{2} - 6x + 9) + 1 \\ y = - {x}^{2} + 6x - 10\)

Answer:

I am deeply sorry.

Step-by-step explanation:

I am really sorry about how long it takes you to do "this". My best advice is to take a break and think it out slowly.

Answer:

0.3 miles

Step-by-step explanation:

Using Trigonometry ;

Height, h = 2 miles

First sighting :  

Horizontal distance h1 ;

h1 = 2tanθ

θ = 11°

h1 = 2 * 0.1943803

h1 = 0.3887606 miles

Second sighting ;

Horizontal distance h2 ;

h2 = 2tanθ

θ = 18°

h2 = 2 * 0.3249196

h2 = 0.6498393 miles

Horizontal difference :

0.6498393 miles - 0.3887606 miles

= 0.2610787 miles

= 0.3 miles

The regular expression is ^(a(aa)*b)$.

To create a regular expression for the language L = {w = {a,b}* | w has an odd number of 'a's and ends with 'b'}, we can use the following expression:

^(b|(a(aa)*b))$

Breaking it down:

^ indicates the start of the string.

(b|(a(aa)*b)) matches either 'b' or a sequence of 'a's followed by an odd number of 'a's and 'b'.

(aa)* matches zero or more pairs of 'a's.

$ indicates the end of the string.

This regular expression ensures that the string starts with 'b' or a sequence of 'a's, followed by an odd number of 'a's, and ends with 'b'. Any additional characters or sequences in between are not allowed.

Please note that regular expressions can have different notations and conventions depending on the context or programming language you're using. The expression provided here follows a general pattern that should work in most cases.

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Answer:

x = 115 , y = 40

Step-by-step explanation:

in a trapezoid

• each lower base angle is supplementary to the upper base angle on the same side.

∠ ART = 40° + 25° = 65°

then

∠ PAR = 180° - ∠ ART = 180° - 65° = 115° , so

∠ PAR = x = 115

the sum of the 3 angles in Δ PAR = 180° , that is

x + y + 25 = 180

115 + y + 25 = 180

140 + y = 180 ( subtract 140 from both sides )

y = 40

Answer:

The answer for A is 2.5/1 and B is wrong. The answer would be $2.50 for 1 pound of beets.

Step-by-step explanation:

Just have to figure out slope, then you get B

Answer:

The slope is 5/2

m=y²-y¹/x²-x¹

m=10-5/4-2

m=5/2

Stack parameters and register parameters are different ways of passing function arguments in a programming language.

Each approach has its advantages, and the choice between them depends on various factors such as platform architecture, optimization goals, and calling conventions. However, some advantages of stack parameters over register parameters include:

Flexibility: Stack parameters allow for more flexibility in function calls, as they can accommodate a larger number of arguments compared to registers. Registers have limited availability, and if there are more arguments than available registers, the stack can be used to pass the remaining parameters.

Function Call Conventions: Many calling conventions dictate the use of the stack for passing parameters, making stack parameters more compatible with standard calling conventions across different platforms and compilers. Register parameters, on the other hand, may have stricter limitations or variations depending on the specific architecture or calling convention.

Function Composition: Using the stack for parameter passing allows for easier function composition and chaining. When functions call other functions, the stack-based parameter passing mechanism allows the callee function to easily access the arguments passed by the caller function, as they are stored in a well-defined and accessible location.

Optimized Register Usage: Register parameters are generally preferred when optimizing for performance, as they can provide faster access to the arguments due to the reduced memory access required. However, stack parameters can free up registers for other critical uses, such as storing frequently accessed variables or intermediate results.

Language Portability: Stack parameters are generally more portable across different programming languages, as register usage and availability can vary significantly. Using the stack for parameter passing ensures compatibility and consistency in function calls, regardless of the programming language used.

It's worth noting that the specific advantages may vary depending on the programming language, compiler, and target platform. Therefore, it is essential to consider the specific context and requirements when choosing between stack parameters and register parameters.

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In right triangle ABC with C = 90°, the missing parts can be solved as follows: A = 11° 54', b = 5.712 cm. The missing parts are a = 6.728 cm, c = 8.078 cm, and CH = 4.373 cm.

To solve for the missing parts of the right triangle, we can use trigonometric ratios. Since we know the angle A and the side b, we can use the tangent ratio to find side a. The tangent of angle A is equal to the ratio of side opposite to angle A (a) to the side adjacent to angle A (b). So, we have tan(A) = a/b. Substituting the given values, we can solve for a and find that a ≈ 6.728 cm.

To find side c, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides. Thus, we have c^2 = a^2 + b^2. Substituting the known values, we can solve for c and find that c ≈ 8.078 cm.

Finally, to find the length of the altitude CH, we can use the sine ratio. The sine of angle A is equal to the ratio of the side opposite to angle A (CH) to the hypotenuse (c). Therefore, sin(A) = CH/c. Substituting the known values, we can solve for CH and find that CH ≈ 4.373 cm.

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The hierarchical database model is based on a tree structure, where data is organized in a parent-child relationship. Each parent segment can have multiple child segments, but each child segment has only one parent.

In this model, data access is typically navigated from the top-level parent segment to its child segments in a hierarchical manner. The parent-child relationships provide a clear structure for organizing and representing data. However, it also means that a lack of a parent segment or a child segment is not allowed in this model.

Compared to a matrix structure, where segments can have relationships with multiple other segments, the hierarchical model is more rigid in its one-to-many relationship between parent and child segments.

However, it may pose challenges when dealing with complex or interrelated data that doesn't fit neatly into a hierarchical structure.

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Answer:

12^2 + 4x

Step-by-step explanation:

We need to solve the area of these two rectangles separately.

Equation: 4x(3x+1) --> 12x + 4

Area: 12x^2 + 4x

Hope this helps.

Answer:

Nominal decisions can be broken into two distinct categories: dichotomous decisions and polychotomous decisions.