Which force pulls earth and the sun toward each other?

Answer:

If you know your gas laws, you have to utilise a certain gas law called Charles' Law:

V

1

T

1

=

V

2

T

2

V

1

is the initial volume,

T

1

is initial temperature,

V

2

is final volume,

T

2

is final temperature.

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

Normally in these types of problems (gas law problems), you are given all the variables but one to solve. In this case, the full setup would look like this:

2.75

291

=

V

2

318

By cross multiplying, we have...

291

V

2

= 874.5

Dividing both sides by 291 to isolate

V

2

, we get...

V

2

= 3.005...

In my school, we learnt that we use the Kelvin value in temperature to count significant figures, so in this case, the answer should have 3 sigfigs.

Therefore,

V

2

= 3.01 L

Explanation:

please mark me as the brainliest answer and please follow me

Answer:

6L im not completly sure but i wouldnt risk it

Explanation:

Answer:

1. Insulin

2. Keratin

Explanation:

Proteins are one of the four biological molecules found in living systems. They are polymeric molecules made up of monomeric units called AMINO ACIDS. Proteins perform a wide variety of functions in the body ranging from enzymatic functions to structural roles.

Two examples of proteins found in the body are keratin, insulin. Keratin is a structural protein located in the skin, hair and nails while insulin is an enzymatic protein that aids in digestion.

A polymer-based material can be characterized using various techniques and instruments.

Here's how to determine whether the polymer is a thermoset, the amount of filler present in it, what the filler is, and the quantity of antioxidants and UV absorbents present:

1. To determine if the polymer is a thermoset, heat it. Thermosets don't melt, but thermoplastics do.

2. To determine the amount of filler in the polymer, weigh a sample of the polymer and then burn it. The residue will be the filler. Subtract the residue's mass from the polymer's initial weight to determine the filler's weight.

3. To determine what filler is present, observe the residue after burning.

4. UV absorbents can be detected using UV-Vis Spectroscopy, while antioxidants can be determined using FTIR Spectroscopy.

5. To determine if the material has dye or pigment coloring, use colorimetry to measure its color, then compare it to the reference color of the polymer. If the color is different, it has dye or pigment coloring.

6. The polymer's thermoset can be identified using Differential Scanning Calorimetry (DSC) to examine the melting temperature, which is unique to each thermoset.

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If a nucleus gains a neutron and then undergoes beta emission, the correct answer is (d) its atomic number increases by one and its mass number is unchanged.

In the process described, the nucleus gains a neutron, which means its mass number (total number of protons and neutrons) increases by one. However, it undergoes beta emission, which is the process of a neutron transforming into a proton and emitting a beta particle (an electron or positron).

This transformation increases the atomic number (number of protons) by one. As a result, the correct answer is that the atomic number increases by one, while the mass number remains unchanged. Option (d) is the correct choice.

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By performing the necessary calculations and comparing the Q/K ratios, we can determine whether calcite or dolomite would form first in the given water sample with [Mg2+]∼0.10 mmol/L.

To determine which mineral, calcite or dolomite, would form first in the given water sample with [Mg2+]∼0.10 mmol/L, we need to calculate the saturation index (SI) for each mineral by comparing the Q/K ratios. The mineral with the higher SI will be more likely to precipitate first.

The saturation index (SI) is calculated by comparing the ion activity product (Q) with the equilibrium constant (K) for a particular mineral. In this case, we have the equilibrium reaction: CaMg(CO3​)2​⇌Ca2++Mg2++2CO3​2−.

For calcite, the Q/K ratio can be calculated using the concentration of Ca2+ and CO3​2− ions in the water sample. Since dolomite contains both Ca2+ and Mg2+ ions, we need to consider the concentration of Mg2+ as well.

By comparing the Q/K ratios for calcite and dolomite, we can determine which mineral has a higher saturation index (SI). The mineral with the higher SI will be more likely to precipitate first.

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CD4 and CD8 T-cell numbers are decreased after blunt trauma.

A body damage brought on by a strong collision with a dull item or surface is known as blunt trauma, also known as non-penetrating trauma or blunt force trauma. It differs from penetrating trauma, which occurs when an object or surface pierces the body and leaves an open wound. To stabilize and care for the patient, trauma hospitals need to use a coordinated, multidisciplinary approach. For instance, a Level I trauma center has well-established treatment protocols in place and specific sorts of healthcare specialists on call around-the-clock, seven days a week.

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The pKa of acetic acid is 4.8, the result of adding 1 mL of 0.1 M HCl to a 0.1 M acetate buffer at a pH of 5.0 is:

C. The pH would drop significantly.

Acetic acid (CH₃COOH) is a weak acid that partially dissociates in water, releasing hydrogen ions (H⁺). In an acetate buffer solution, acetic acid and its conjugate base, acetate (CH₃COO⁻), are present in equilibrium:

CH₃COOH ⇌ H⁺ + CH₃COO⁻

The equilibrium is governed by the acid dissociation constant, represented as Ka. The pKa of acetic acid is given as 4.8. The pKa is the negative logarithm of the Ka value.

When a strong acid, such as HCl, is added to the acetate buffer solution, it introduces a large concentration of additional H⁺ ions. This disturbs the equilibrium between acetic acid and acetate, shifting it towards the formation of more undissociated acetic acid. Consequently, the concentration of H⁺ ions increases, causing a significant drop in pH.

Since the initial pH of the acetate buffer is 5.0, which is higher than the pKa of acetic acid (4.8), the buffer is in a partially deprotonated state. Adding HCl, a strong acid, disrupts the balance between the acid and its conjugate base, resulting in a more acidic solution and a significant decrease in pH.

Therefore, option C, "The pH would drop significantly," is the likely result of adding 1 mL of 0.1 M HCl to the 0.1 M acetate buffer at a pH of 5.0.

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Answer:

When ice or any other solid melts, its potential energy increases. Indeed, this is the only increase in energy, since the thermal kinetic energy, or temperature, does not increase while melting. Potential energy is the latent energy that could be released by the water, and this increases because the water will release heat energy if it is frozen solid again.

Ice is the lowest energy state of water at normal Earth pressures. At each phase change of water, whether ice to liquid water or liquid water to water vapor, the potential energy decreases. This is due to the Law of Conservation of Energy. Materials undergoing a change of state absorb or release heat energy, but their temperatures do not change. This is because, while the state change is occurring, all the heat energy is converted into the potential energy of the new state of matter.

Water, in particular, has a very large change in potential energy during phase changes. It takes a great deal of energy to change water from one state to another. This is because of the strong hydrogen bonds that form between water molecules. The liquid phase allows water molecules to be in contact with each other, while the solid phase puts water molecules in an overall optimal configuration relative to each other.

Explanation:

In a low-spin situation for the d3 electron configuration in a tetrahedral field, there are no unpaired electrons.

In a low-spin situation for the d3 electron configuration in a tetrahedral field, there are 3 unpaired electrons. This is because the low-spin configuration occurs when the electrons occupy the available d-orbitals singly before pairing up, resulting in the maximum number of unpaired electrons. This is because in a tetrahedral field, the splitting of energy levels leads to a situation where all three d electrons are paired up in the lower energy levels, leaving no unpaired electrons in the higher energy levels.

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The specific heat capacity of the ring of mass 3.1 g is 753.3 J/kg.°C.

Specific heat capacity is defined as the amount of heat energy needed to increase the temperature of 1kg of a substance by 1°C.

To calculate the specific heat capacity of the the ring, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the specific heat capacity of the ring is 753.3 J/kg.°C.

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With this experiment, we can conclude that when ATP synthase binds to ATP and the ATP synthase rotates.

Definition of ATP Synthase Adenosine triphosphate (ATP) is produced by the enzyme ATP synthase during the process of cellular respiration. The primary source of energy used by cells is ATP.

a catalytic enzyme that uses inorganic phosphate and ADP to create ATP The big protein enzyme known as ATP synthase, which produces energy for the cell, is the location to which angiostatin binds.

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The chemical formulas cross method worksheet are listed below in the answer.

A chemical formula lists the constituent components of a compound together with how many atoms of each are present in the complex's smallest unit, whether it be a molecule or a formula unit. We can name simple compounds based on their chemical formulas by using the names of the elements and a few simple criteria.

Cations are positive-charged ion particles. Atoms or molecules that are ionic are charged. If an electron or more are lost from a balanced atom, it will change into a positively charged cation. When a balanced atom gains one or more electrons, an anion, a negatively charged atom, forms.

1. Na₂so₄

4.  Kcl,  , , K₃PO₄, KNO₃, K₂SO4

5.  Mg₂Cl₂, Mg₃ (Po₄)₂, Mg₃ (No₂)₂, Mgso₄

6. AlCl₃, AlPo₄, Al (No₃)₃, Al₂(so₄)₃

7. HCl, H₃PO₄, HNO₃, H₂SO₄

8. FeCl₂, Fe(PO₄)₂, Fe(NO₃)₂, FeSo₄

The chemical formulas cross cross method worksheet are listed above.

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The heat of solution (qsoln) for the neutralization reaction between NH3 and HCl depends on the specific conditions of the reaction, such as the concentrations of NH3 and HCl, the temperature, and the pressure.

In general, the neutralization of NH3 and HCl is an exothermic reaction, meaning it releases heat, and the value of qsoln is negative. The exact value of qsoln can be calculated using the heat of formation of NH3 and HCl and the enthalpy change of the reaction. However, without specific information about the reaction conditions, an accurate value for qsoln cannot be provided.

To find the heat of solution (qsoln) for the neutralization reaction between NH3 and HCl, follow these steps:

Step 1: Write the balanced chemical equation for the reaction:
NH3(aq) + HCl(aq) → NH4Cl(aq)

Step 2: Determine the molar enthalpy of the reaction (ΔH):
You can look up the molar enthalpy of the reaction in a reference table or calculate it using bond dissociation energies. For this reaction, the molar enthalpy is typically reported as -51.6 kJ/mol.

Step 3: Calculate the heat of solution (qsoln):
qsoln = n * ΔH

Where n represents the number of moles of NH3 and HCl reacting, and ΔH is the molar enthalpy of the reaction. To calculate n, you will need to know the volume and concentration of the NH3 and HCl solutions used in the reaction.

For example, if you have 0.1 moles of NH3 reacting with 0.1 moles of HCl, the calculation would be:
qsoln = 0.1 * (-51.6 kJ/mol) = -5.16 kJ

In this example, the heat of solution for the neutralization reaction between NH3 and HCl is -5.16 kJ.

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The procedure for the preparation you chose for each ester are: heat the reagents, add aqueous solution, heat and stir the mixture, cool it down, add sodium bicarbonate, the ester is separated by filtration and lastly crude ester can be purified by recrystallization.

The procedure for the preparation of an ester involves several steps which are in detail below:.

First, the reagents, which can include an acid, an alcohol, and a catalyst, must be combined in a round-bottom flask. Heat is then applied and the mixture is agitated, either manually or with a stirrer.

After the reaction is complete, the mixture is cooled, and an aqueous solution of a base, such as sodium bicarbonate, is added. This causes the ester to precipitate out and is separated from the aqueous layer by filtration.

The crude ester can then be purified, typically by recrystallization. The reagents used will depend on the ester to be prepared. For example, for the preparation of ethyl acetate, acetic acid, ethanol, and sulfuric acid can be used as the reagents.

To complete the reaction, the acid, alcohol, and catalyst are combined in the round-bottom flask, heated and stirred, and cooled. Then, the aqueous solution of sodium bicarbonate is added and the ester is separated by filtration. Finally, the crude ester can be purified by recrystallization.

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M is equal to (molar mass) (molar volume) (density).

Let's first translate the temperature into Kelvin:

T = 25°C + 273.15 = 298.15 K

The pressure will now be converted to an atm:

760 mm Hg equals 1 atm

Pressure is equal to 740 mm Hg times 760 mm Hg/atm, or 0.9737 atm.

Let's use the ideal gas law equation to determine the molar volume now:

PV = nRT

V is equal to (RT) / P is equal to (0.0821 L atm/mol K) (298.15 K) / (0.9737 atm).

V ≈ 24.93 L/mol

Now, using the provided density, let's get the molar mass:

M = (5.8 g/L) (24.93 L/mol) = (density) (molar volume)

M ≈ 144.394 g/mol

The gas's molar mass is therefore most closely associated with 144.394 g/mol.

The empirical formula for the gas, CH2, reveals the proportional proportion of hydrogen to carbon atoms in the gas. The computed molar mass, however, is considerably more than the molar mass of the empirical formula. This implies that the gas's true molecular composition must have more atoms.

We determine that the ratio is around 3.33 by comparing the molar mass of the empirical formula (14.03 g/mol) to the molar mass of the gas (46.61 g/mol). This suggests that a multiple of the empirical formula makes up the gas' molecular formula.

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Answer:

there are approximately 5.5 x 10^23 molecules in 16.5 grams of water

Explanation:

To calculate the number of molecules in a certain mass of a substance, you need to know the molar mass of the substance and convert the mass to moles.

The molar mass of water is 18.015 g/mol. To convert the mass of water to moles, we can use the equation:

moles = mass / molar mass

So, moles of water = 16.5 g / 18.015 g/mol = 0.916 mol

Avogadro's number is 6.022x10^23. To calculate the number of molecules, we can multiply Avogadro's number by the number of moles.

So the number of molecules = (6.022x10^23) * (0.916 mol) = 5.5x10^23 molecules

Therefore, there are approximately 5.5 x 10^23 molecules in 16.5 grams of water

Answer:

1s^22s^22p^63s^23p^64s^23d^104p^4

Answer:

1s2 2s2 2p6 3s2 3p6 4s2 3d10  p4

Explanation:

PLATO correct

The chromatography experiment, the solvent front traveled a distance of 8cm, while the blue, pink, and orange substances traveled distances of 6cm, 5cm, and 4cm.

In a chromatography experiment, the distance traveled by the solvent front refers to the distance the solvent traveled from the starting point on the chromatography paper. In this particular case, the solvent front traveled a distance of 8cm.

During the experiment, different components or substances were separated based on their affinity for the stationary phase and the mobile phase. The substances of interest in this scenario are represented by blue, pink, and orange.

The blue substance traveled a distance of 6cm from the starting point, indicating that it had a moderate affinity for the mobile phase. The pink substance traveled a distance of 5cm, suggesting that it had a slightly lower affinity for the mobile phase compared to the blue substance. Lastly, the orange substance traveled a distance of 4cm, indicating that it had the lowest affinity for the mobile phase among the three substances.

These distances traveled by the substances provide valuable information about their relative polarities or molecular interactions with the mobile and stationary phases. By analyzing the relative distances traveled by the substances compared to the solvent front, researchers can gain insights into the chemical properties of the separated components.

In conclusion, in this chromatography experiment, the solvent front traveled a distance of 8cm, while the blue, pink, and orange substances traveled distances of 6cm, 5cm, and 4cm, respectively, indicating their varying affinities for the mobile phase.

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Answer:

c. protons

Explanation:

A "proton" is a subatomic particle that is stable and is positively-charged. You will identify the number of protons that is present in the nucleus of a chemical element by its "atomic number." It gives us an identity of the element, therefore, every atom of the same element have the "same" number of protons. For example, the number of protons for "Hydrogen" is 1. This means that even if you have two atoms of Hydrogen, each of them has "1" as the number of proton.

Answer: 40.3

Explanation:

In the reaction, we see that for every 3 moles of oxygen gas consumed, 2 moles of rust are formed.

So this means that if 60.5 moles of oxygen gas are consumed, then (60.5/3)(2)=40.3 moles of rust can be formed.

Answer:

Calendar and periodic table both have repetitive patterns.

Explanation:

In calendar the days are arranged and divided into weeks whereas in the periodic table the elements are arranged in increasing atomic number and divided into groups

Answer:

Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.

What are the first two quantum numbers for the six electrons in the 2p subshell?

Explanation:

The principal quantum number represents the shell number in which the electron is present.

It is represented with "n".

The next quantum number is the azimuthal quantum number.

It represents the shape of the orbital.

It has values from 0 to (n-1).

Its value depends on the principal quantum number.

Chlorine has 17 total electrons with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^5.

For the six elecetrons in 2p subshell:

The first two quantum number values are the same and their values are:

n=2 , l=1.

Answer:

when organisms decompose, or burning fossil fuels and pollution and such

Explanation:

The speed of each atom just before the collision is 4.43 × \(10^{4}\)

n1 = 1, n2 =2

Wavelength is in UV region; thus n1 will be 1.
1/121.6 × \(10^{-9}\) = 1.097 × \(10^{7}\) × (1/1² - 1/n²)

n2 = 2

1/2 m\(v^{2}\)  = hc/λ

v =  4.43 × \(10^{4}\)

A chemical element's atom is a particular type of particle of substance. A positively charged electron or many negatively charged electrons encircle the central nucleus of an atom. Protons and neutrons, two relatively hefty particles that make up the positively charged nucleus, may be present.

The fundamental components of matter are atoms. Atoms are the building blocks of all mass and space-occupying objects. Positively charged particles are protons. The chemical element's atomic number is determined by how many protons are present in its nucleus. In the Periodic Table of Elements, different elements' atomic numbers can be found. For instance, sodium's atomic number is 11 and it possesses 11 protons. mp is the symbol for the rest mass of a proton.

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Answer:

When you bake a cake, the ingredients go through a chemical change. A chemical change occurs when the molecules that compose two or more substances are rearranged to form a new substance! When you start baking, you have a mixture of ingredients. The flour, egg, sugar,

Explanation:

Answer:

B

Explanation:

the less candy will be the smallest gerbil and the most candy will be the fatest

Answer:

A) The number of gerbils you feed

Explanation:

If you wanted to test whether eating candy made gerbils fat you would need to fluctuate the amount of candy each group receives to observe whether there was any differnce in weight

Considering the reaction, heat evolved are:

a. -286 kJ/mol

b. -572 kJ

c. -1666 kJ

d. -2.78 × 10⁹ kJ.

a. The given ΔH is for the production of 2 moles of H₂O. Therefore, for the production of 1 mole of H₂O, the amount of heat evolved will be half of the given value:

Heat evolved for 1 mole of H₂O = (-572 kJ/2) = -286 kJ/mol

b. Calculate the number of moles of hydrogen in 4.03 g:

n(H₂) = mass/molar mass = 4.03 g/2.016 g/mol = 2.00 mol

From the balanced chemical equation, 2 moles of H₂ produce 2 moles of H₂O. Therefore, 2.00 moles of H₂ will produce 2.00 moles of H₂O. So, the amount of heat evolved will be:

Heat evolved = 2.00 mol × (-572 kJ/2 mol) = -572 kJ

c. Similarly, calculate the number of moles of oxygen in 186 g:

n(O₂) = mass/molar mass = 186 g/32.00 g/mol = 5.81 mol

From the balanced chemical equation, 2 moles of H₂ react with 1 mole of O₂ to produce 2 moles of H₂O. Therefore, 5.81 moles of O₂ will react with 2.91 moles of H₂ to produce 5.81 moles of H₂O. So, the amount of heat evolved will be:

Heat evolved = 5.81 mol × (-572 kJ/2 mol) = -1666 kJ

d. The number of moles of H₂ needed to fill the Hindenburg can be calculated using the ideal gas law:

PV = nRT

n = PV/RT = (1.0 atm × 2.0 × 10⁸ L)/(0.0821 L·atm/(mol·K) × 298 K) = 9.75 × 10⁶ mol

From the balanced chemical equation, 2 moles of H₂ produce 2 moles of H₂O. Therefore, 9.75 × 10⁶ mol of H₂ will produce 9.75 × 10⁶ mol of H₂O. So, the amount of heat evolved will be:

Heat evolved = 9.75 × 10⁶ mol × (-572 kJ/2 mol) = -2.78 × 10⁹ kJ.

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