which group contains most elements
Answers
Answer:
group 8 (group 0)
just take a look at the periodic table
Related Questions
An unknown substance dissolves in water but separates and floats in oil.
Answers
Answer:
Any polar substance
Explanation:
We know that non polar substances wont dissolve in water because they do not react properly with water molecules, any polar substance would dissolve in water and float in oil.
An unknown substance dissolves in water but separates and floats in oil is any polar substance.
What are polar substances?Polar substance are defined as those whose bonding with atoms like nitrogen, oxygen, or sulfur has resulted in discrete positive and negative charge areas.
It can also be defined as an electrical pole is typically created when a molecule has more positive charges on one end than negative charges on the other, forming an electrical pole.
Non polar substances are defined as a molecule that lacks charges at the ends because its electrons are evenly distributed and those that cancel one another out symmetrically.
It is can also be defined as in covalent compounds, there is no change in electronegativity.
Thus, an unknown substance dissolves in water but separates and floats in oil is any polar substance.
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The pressure inside of a sealed syringe of hydrogen gas is 80.0KPa with a volume of 250 Liters. What is the pressure inside
of the syringe after the plunger is pulled back far enough to make final volume of the syringe 0.750 Liters? (assume the
temperature and amount of gas in the container are held constant)
Answers
Answer:
26666.67 kPaExplanation:
The new pressure can be found by using the formula for Boyle's law which is
\(P_1V_1 = P_2V_2\)
Since we are finding the new pressure
\(P_2 = \frac{P_1V_1}{V_2} \\\)
From the question we have
\(P_2 = \frac{80000 \times 250}{0.75} = \frac{20000000}{0.75} \\ = 26666666.6666 \\ = 26666667\)
We have the final answer as
26666.67 kPaHope this helps you
Help me please ????
Answers
Answer:
I think it is more that one is correct, so sorry if I'm wrong, if it isn't, it is one of the electron bonding ones
Predict the products of a reaction between Ba(NO 3
) 2
(aq) and K 2
SO 4
(aq). A) Ba(s),KNO 3
(aq) and K 2
SO 3
(aq) B) BaSO 3
(s) and KNO 2
(aq) C) BaSO 3
(s) and KNO 3
(aq) D) BaSO 4
(s) and KNO 3
(aq) 19. In the reaction AgNO 3
(aq)+HI(qq)→AgI (s)
+HNO 3
(aq) the spectator ions are A) Ag+ and NO 3
B) Ag +
and I− C) H +
and I −
D) H +
and NO 3
−
Answers
The correct answers are: Predicted products of the reaction between Ba(NO3)2(aq) and K2SO4(aq): D) BaSO4(s) and KNO3(aq)
In the reaction AgNO3(aq) + HI(aq) → AgI(s) + HNO3(aq), the spectator ions are:
C) H+ and I−
Explanation:
For the first question, we need to identify the products formed when Ba(NO3)2(aq) and K2SO4(aq) react. To determine the products, we need to consider the combination of the cations and anions in the reactants.
Ba(NO3)2 contains the Ba2+ cation and the NO3− anion.
K2SO4 contains the K+ cation and the SO42− anion.
When these ions combine, a double displacement reaction occurs. The Ba2+ cation will combine with the SO42− anion to form an insoluble salt, BaSO4, which precipitates out of the solution as a solid. The K+ cation will combine with the NO3− anion to form KNO3, which remains in the solution as an aqueous compound.
Therefore, the correct answer is D) BaSO4(s) and KNO3(aq) as the predicted products of the reaction.
For the second question, the reaction between AgNO3(aq) and HI(aq) produces AgI(s) and HNO3(aq). The Ag+ and I− ions combine to form a solid AgI precipitate, which is insoluble and falls out of solution. The H+ and NO3− ions, on the other hand, remain in the solution as spectator ions and do not participate in the formation of the precipitate.
Therefore, the correct answer is C) H+ and I− as the spectator ions in the reaction.
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1. Imagine doing the same virtual experiment using wood as the bottom material, instead of glass or water. Predict how the light would interact with the wood.
Answers
The wood can't do the same function as done by the water and glass in the same virtual experiment due to its different chemical composition.
The light will not pass through the wood due to its translucent behaviour that prevents light to pass through it as compared to water and glass which are transparent materials and light can easily pass through it.
So using wood as a bottom material instead of glass and water will not perform the same function as perform by water and glass in the same virtual experiment so we can conclude that wood can't perform the same function in the experiment.
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In a labeled beaker, you obtain about 50 mL of stock solution of sodium hydroxide. The sodium hydroxide stock solution was standardized to 0. 019 M. You rinse your buret three times with the solution before filling the buret with the sodium hydroxide. You then obtain a 5. 00 mL volumetric pipet and pipet 5. 00 mL of vinegar into a clean 125 mL Erlenmeyer flask. You add two drops of phenolphthalein indicator and swirl the contents in the flask. You add about 10 mL of deionized water to wash the inside walls of the flask. The solution at this point is colorless. Your initial buret reading is 23. 24 mL. You titrate your acetic acid sample with sodium hydroxide until the first appearance in the flask of a faint pink color that persists when the solution is swirled. At this point you record the final buret reading to be 43. 22 mL
Answers
To calculate the concentration of acetic acid (vinegar) in the given sample, we can use the concept of titration and the balanced chemical equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH):
CH3COOH + NaOH → CH3COONa + H2O
Given:
Volume of sodium hydroxide used (VNaOH) = Final buret reading - Initial buret reading = 43.22 mL - 23.24 mL = 19.98 mL
Volume of acetic acid sample (Vsample) = 5.00 mL
Molarity of sodium hydroxide (MNaOH) = 0.019 M
Using the balanced chemical equation, we can see that the molar ratio between acetic acid and sodium hydroxide is 1:1. Therefore, the moles of sodium hydroxide used will be equal to the moles of acetic acid present in the sample.
1. Calculate the moles of sodium hydroxide used:
Moles of NaOH = Molarity of NaOH * Volume of NaOH used (in liters)
Moles of NaOH = 0.019 M * (19.98 mL / 1000 mL/L)
2. Calculate the moles of acetic acid:
Moles of CH3COOH = Moles of NaOH
3. Calculate the concentration of acetic acid in the sample:
Concentration of CH3COOH = Moles of CH3COOH / Volume of sample (in liters)
Concentration of CH3COOH = Moles of CH3COOH / (5.00 mL / 1000 mL/L)
Calculating the expressions:
Moles of NaOH = 0.019 M * (19.98 mL / 1000 mL/L) = 0.00037962 moles
Moles of CH3COOH = 0.00037962 moles
Concentration of CH3COOH = 0.00037962 moles / (5.00 mL / 1000 mL/L) = 0.075924 M
Therefore, the concentration of acetic acid (vinegar) in the given sample is approximately 0.075924 M.
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What is the first stage of a lunar eclipse?
Answers
The first stage of a lunar eclipse:
Penumbral eclipse.
There are 7 stages of a total lunar eclipse. The first one is when the Penumbral eclipse begins. his begins when the penumbral part of Earth's shadow starts moving over the Moon. This phase is usually not feasible to be seen with the naked eye.
what does the zebra mussel do to affect the ecosystem
Answers
Answer:
The explanation of the type of situation would be characterized below.
Explanation:
Zebra mussels, therefore, have a direct as well as indirect (significant) impact on natural ecosystems. The much more significant impact is on the feed intake interaction including its mussel. Zebra mussels seem to be opportunistic feeders that analyze approximately one gallon of liquid or more per mussel.What is the final temperature of the gas that expands from a volume of 22.4 l at 278k to a volume of 38.3 l?
Answers
The final temperature of the gas that expands from a volume of 22.4 l at 278k to a volume of 38.3 l will be 475 K.
The volume as well as Kelvin temperature will be directly proportional whenever the pressure on even a sample of such a dry gas remains held constant. PV = k would be the law's equation.
Charle's law give the relation between the temperature and volume is shown as:
\(V_{1} / T_{1} = V_{2} / T_{2}\)
where. V is volume and T is temperature.
Given data :
\(V_{1} =22.4 l\\V_{2} = 38.3 l\\T_{1} = 278 K\\T_{2} = ?\)
Put the value of given data in above equation.
22.4 l / 38.3 l = 278k / \(T_{2}\)
\(T_{2}\) = 475 K.
Therefore, the final temperature will be 475 K.
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how much is the mass of a man if
he has to do 2500 joules of work in
climbing a tree 5 meters tall
Answers
Answer:
50kg
Explanation:
Using the formula for potential energy, which is the amount of energy due to position;
P.E = m × g × h
Where;
m = mass (kg)
g = acceleration due to gravity (10m/s²)
h = height (metres)
According to the information provided in this question, m = ?, P.E = 2500J, h = 5m
Using P.E = m × g × h
m = P.E/gh
m = 2500/(5 × 10)
m = 2500/50
m = 50kg
The mass of the man is 50kg.
Non-ferrous metal is NOT hardenable by heat treatment; it must
gain strength through a process such as tempering. Is this
statement TRUE or FALSE?
Group of answer choices
True
False
Answers
The statement is FALSE. Non-ferrous metals can be hardened by heat treatment, although the mechanisms and processes involved may differ from ferrous metals.
Heat treatment techniques such as precipitation hardening can be used to increase the strength of non-ferrous metals. Non-ferrous metals are metals or alloys that do not include iron (or iron allotropes, such as ferrite, etc.) in significant quantities. Non-ferrous metals are employed because they have desired qualities like reduced weight (for example, aluminium), greater conductivity (for example, copper), non-magnetic characteristics, or corrosion resistance (for example, zinc), even though they are often more expensive than ferrous metals. In the iron and steel sectors, several non-ferrous materials are also employed. Bauxite, for instance, is used as a flux in blast furnaces, whereas wolframite, pyrolusite, and chromite are utilised to create ferrous alloys.
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What is the name for the compound with the formula ch 3ch 2ch 2ch 2oh? butanol propanol pentane propane pentanol
Answers
The compound given is an alcohol with 4 carbons, hence, it is butanol.
What are alcoholic carbons?An alcohol may be seen as having a tetrahedral oxygen atom that is sp³ hybridized, with nonbonding pairs of electrons occupying two of the four sp³-hybrid orbitals. (Hybrid orbitals are discussed in chemical bonding.) However, because alkyl groups are often thicker than hydrogen atoms, alcohols typically have a wider R–O–H bond angle than water, which has a 104.5° H–O–H link angle. For instance, the methyl group, which is bigger than the hydrogen atom in water, has an impact as seen by the 108.9° bond angle in methanol.
An alcohol's common name combines the term alcohol with the name of the alkyl group. The IUPAC term should be used instead of the popular name if the alkyl group is complex. In the nomenclature of the alkyl group, common names typically utilize archaic terminology; for instance, amyl is usually used in place of pentyl for a five-carbon chain.
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What do you notice when you get into a car that has been sitting in the sun for a while?
Answers
When you get into a car that has been sitting in the sun for a while, there are several noticeable things that may occur. Here are some of the common observations:
1. Heat: One of the first things you'll notice is the intense heat inside the car. This is because the sun's rays have been absorbed by the car's exterior and trapped inside, creating a greenhouse effect. The temperature inside the car can become significantly higher than the temperature outside.
2. Hot Surfaces: The surfaces inside the car, such as the seats, dashboard, steering wheel, and metal parts, can become extremely hot to the touch. This is due to the absorption of heat from the sun. It's important to be cautious and avoid direct contact with these hot surfaces to prevent burns or discomfort.
3. Odor: The interior of the car may have a distinct smell when it has been sitting in the sun for a while. This is often referred to as the "hot car smell." It is caused by the combination of materials, such as upholstery, plastic, and carpet, heating up and emitting a specific odor.
4. Fading or Discoloration: Prolonged exposure to sunlight can cause fading or discoloration of materials inside the car. For example, the upholstery, dashboard, and other surfaces may gradually lose their original color and become faded or discolored over time.
5. Glare: When you first enter a car that has been sitting in the sun, you may notice a strong glare from the sunlight reflecting off the windshield and other glass surfaces. This glare can make it difficult to see clearly and may require the use of sunglasses or adjusting the sun visors to minimize the brightness.
It's important to note that these observations may vary depending on factors such as the intensity of the sunlight, the duration the car has been in the sun, and the materials used in the car's interior. Regular maintenance and taking precautions, such as using sunshades or parking in shaded areas, can help minimize some of these effects.
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Consider the following single-molecule set up: Dye: N-(6-tetramethylrhodaminethiocarbamoyl)-1,2-dihexadecanoyl-sn-glycero-3phosphoethanolamine, triethylammonium salt (TRITC DHPE; T-1391, Molecular Probes) Excitation/emission:
540 nm/566 nm
Quantum yield: 0. 5 Objective oil index of refraction: 1. 5 Numerical aperture: 1. 3 Excitation light:
514 nm,57 kW/cm 2
Exposure time:
5 ms
Transmittance Information Objective:
40%
Dichroic:
90%
Emitter:
99%
Tube lens:
90%
Camera detection efficiency:
40%
One-photon absorption cross section for hodamine:
σ=10 −16
cm 2
α
, the light bending angle for the objective The sample emits light in all directions (area of sphere:
4π 2
). A conical section of this light is captured by the objective (defined by
2π 2
(1−cosα)
). What is the percentage of total fluorescence captured by the objective?
a. 37. 5%
b. 25%
c. 50%
d. 75%
Answers
The correct option is A, The percentage of total fluorescence captured by the objective is 37.5%,
% fluorescence captured = (excitation light power x fluorescence emitted x transmittance) / (2π x objective NA x oil refractive index x area of sphere x one-photon absorption cross section x exposure time)
Plugging in the given values, we get:
% fluorescence captured = (57 kW/cm x 0.5 x 0.4 x 0.9 x 0.99 x 0.9 x 0.4) / (2π x 1.3 x 1.5 x 4π x \(10^{-16}\) cm² x 5 ms)
% fluorescence captured = 37.5%
Fluorescence is a phenomenon that occurs when a substance absorbs light of a specific wavelength and then emits light of a longer wavelength. This emission of light is known as fluorescence. Fluorescence is commonly observed in certain chemicals, dyes, and biological molecules, such as proteins and nucleic acids.
When a molecule is excited by absorbing light of a specific wavelength, it enters an excited state. The excited state is unstable, and the molecule quickly returns to its ground state by releasing the excess energy as light of a longer wavelength. The emitted light can be detected using a fluorometer, which measures the intensity and wavelength of the emitted light.
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100 POINTS PLEASE HELP (PHOTOS INCLUDED)
Answers
Answer:
Explanation:
3.
Knowns: 100mL of solution; concentration of 0.7M
Unknown: number of moles
Equation: number of moles = volume * concentration
Plug and Chug: number of moles = 100/1000 * 0.7 = 0.07 mole
Final Answer: 0.07mole
2.
Knowns: 5.50L of solution; concentration of 0.400M
Unknown: number of moles
Equation: number of moles = volume * concentration
Plug and Chug: number of moles = 5.5 * 0.4 = 2.20 mole
Final Answer: 2.20 mole
Moles of solute be x
#1
Volume of solution=100mL=0.1mLMolarity=0.7M\(\\ \rm\Rrightarrow Molarity=\dfrac{Moles\:of\:solute}{Volume\:of\'solution}\)
\(\\ \rm\Rrightarrow 0.7=\dfrac{x}{0.1}\)
\(\\ \rm\Rrightarrow x=0.1(0.7)\)
\(\\ \rm\Rrightarrow x=0.07mol\)
#2
Same like before
Volume of solution=5.5LMolarity=0.4M\(\\ \rm\Rrightarrow \dfrac{x}{5.5}=0.4\)
\(\\ \rm\Rrightarrow x=5.5(0.4)\)
\(\\ \rm\Rrightarrow x=2.20mol\)
need help to solve it
Answers
Answer:
Divide by the molar mass to get moles
Explanation:
wuuutttttt....help me
Answers
identify the conditions for a standard electrochemical cell. select one or more: pressure of 1 atm temperature of 298 k solution concentrations of 1 m pressure of 5 atm solute masses of 1 g temperature of 273 k
Answers
The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.
The electrochemical cell is the cell that is capable of generating the electrical energy from the chemical reactions or by the use of the electrical energy to cause the chemical reaction. The conditions for a standard electrochemical cell. select one or more : pressure of 1 atm temperature of 298 k solution concentrations of 1 M.
There are the two types of the electrochemical cells is as follows : the galvanic called the electrolytic cells. the galvanic cell is also called as the voltaic cell.
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How much energy is released if a sample loses 0.001 kg mass through radioactive decay?
Answers
Explanation:
because the energy it can't be calculated
Tartaric acid is found in many fruits, including grapes, and is partially responsible for the dry texture of certain wines. Calculate the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid, for which the acid-dissociation constants. Did you have to make any approximations or assumptions in your calculation?
Answers
No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid.
The pH and the tartrate ion 1C4H4O6 2-2 concentration of a 0.250 M solution of tartaric acid can be calculated using the acid-dissociation constants and the Henderson-Hasselbalch equation. The acid-dissociation constants (Ka1 and Ka2) of tartaric acid are 1.14x10-2 and 5.01x10-5, respectively.
The pH of the solution can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([base]/[acid]) where [base] is the concentration of the conjugate base (the tartrate ion) and [acid] is the concentration of the acid (tartaric acid). Since the solution is 0.250 M in tartaric acid, [acid] = 0.250 M and [base] = 0.250 M - [tartrate ion], which can be calculated using the Ka1 and Ka2 values.
For Ka1, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 1.14x10-2 = 0.249 M. For Ka2, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 5.01x10-5 = 0.249 M.
Using the Henderson-Hasselbalch equation, the pH of the solution can be calculated as pH = pKa + log([base]/[acid]). The pKa values of tartaric acid are 3.92 and 5.63 respectively. Therefore, for Ka1, the pH of the solution can be calculated as pH = 3.92 + log(0.249/0.250) = 3.91, and for Ka2, the pH of the solution can be calculated as pH = 5.63 + log(0.249/0.250) = 5.63.
No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid, as the Henderson-Hasselbalch equation and the acid-dissociation constants of tartaric acid can be used.
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A scientist wants to investigate the effect of concentration of nutrient agar to the growth of bacteria. He created 3 set ups: A) 30 g nutrient agar powder in 1 L H2O B) 40 g nutrient agar power in 1L H2O C) 50 g nutrient agar powder in 1 L H2O
1) Based from the given scenario, CREATE a testable hypothesis using IF-THEN- BECAUSE statements.
2) Using your hypothesis, IDENTIFY the dependent and the independent variables.
Answers
what is an organelle-
A. A leaf cell that is responsible for performing photosynthesis
B. A structure inside the cell that performs a specific function
C. A group of cells that performs a task
D.A type of unicellular organism that can carry out life functions
Answers
Answer:
B
Explanation:
it's on the internet and I just know because I did this before too
This biome has extremely cold winters and short, mild summers. It has no trees, only low-growing plants with short root systems because of its frozen soil
called the permafrost. It is covered by snow for most of the year. Animals that live here must have wide paws or hooves to walk through the frozen mushy.
soil. This biome is known as the_________
A. Tropical rainforest
B. Taiga
C. Deciduous Forest
D. Desert
E. Grassland
F. Tundra
Answers
ammonia burns in the presence of a platinum catalyst to give nitric oxide, . in an experiment, is burned and evolves kj of heat. is the reaction endothermic or exothermic? what is the value of ?
Answers
The reaction of ammonia burning in the presence of a platinum catalyst to give nitric oxide is exothermic, but the exact value of heat evolved (kJ) cannot be determined.
The reaction being described is the burning of ammonia in the presence of a platinum catalyst to give nitric oxide. The experiment also mentions that the reaction evolves a certain amount of heat, measured in kilojoules (kJ).
To determine if the reaction is endothermic or exothermic, we need to consider the sign of the heat evolved. If heat is released (negative value), the reaction is exothermic, meaning it releases energy. If heat is absorbed (positive value), the reaction is endothermic, meaning it requires energy.
Since the question states that the reaction "evolves" heat, we can assume that the value of heat evolved (kJ) is negative. This indicates that the reaction is exothermic and releases energy.
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according to the video raw to ready: bombardier, what was added to sand by the phoenician sailors to accidently produce glass
Answers
Sand was accidentally turned into glass by the Phoenician seafarers by the use of natron.
What is the glass's chemistry?SiO2 is the primary component of flat glass (silica sand). This has a high melting point of around 1700 degrees Celsius, and in this form it resembles syrup on a very cold day.
What makes glass useful in chemistry?Glass composed of borosilicate is a leader in general analytical applications due to its straightforward composition, excellent chemical resistance, and strong thermal shock capabilities. The advantages of borosilicate glass are all present in 96% silica glass, which also has outstanding thermal shock resistance and high service temperature characteristics.
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How many moles of AgCl can form from 6.5 moles of Ag and abundant HCl in the equation: 2Ag + 2HCl -> 2AgCl + H2
Answers
6.5 moles of AgCl can be formed from 6.5 moles of Ag.
STOICHIOMETRY:
According to this question, silver reacts with hydrochloric acid to form silver chloride and hydrogen gas as follows:
2Ag + 2HCl → 2AgCl + H2
Based on this balanced equation, 2 moles of silver (Ag) produces 2 moles of silver chloride (AgCl).
This means that 6.5 moles of Ag will produce (6.5 × 2)/2 = 6.5 moles of AgCl.
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Does this chemical equation satisfy the Law of Conservation of Mass? CS 2 +O 3 -->CO 2 +SO 2
Yes or no
Answers
Answer:
No it doesn't satisfy the Law of Conservation of Mass.
Explanation:
A balanced chemical equation obeys the law of conservation of mass.
Fiona is trying to describe the location of some of the brightest set of stars in the
Northern Sky, Betelgeuse and Rigel, to a friend. What could she have her friend look
for to help find the stars?
(1 point)
Sirius's dog collar
Leo's mane
Orion's belt
Ursa Major's claws
Answers
The brightest star in our sky is Sirius. We can infer so because it has the smallest apparent magnitude (most negative).
The correct option is (a) Sirius's dog collar
What is the sky's brightest star?Sirius, sometimes referred to as the "Dog Star" or, more formally, Alpha Canis Majoris due to its location in the constellation Canis Major, is the brightest star in the sky. Greek for "glowing," the name refers to the star's brightness, which is only surpassed by a few planets, the full moon, and the International Space Station.The main sequence star Sirius A, which has an apparent magnitude of -1.46, is the brighter of the two stars that make up Sirius. Due to both its close closeness and innate luminosity, which is 20 times greater than the Sun's, Sirius A seems to be quite bright. The seventh closest star to Earth is Sirius, which is only 8.7 light years distant.Learn more about the Sirius star with the help of the given link:
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Select all that apply. Which of the following are limitations to ocean exploration? a lack of interest problems with breathing O intense pressure o few technological advances too many marine organisms
Answers
Answer:
ABintense pressure and breathin
Explanation:
because scientist never have the tech to go deeper
Answer:
B. Problems with breathing
C. Intense pressure
Now that the lab is complete, it’s time to write your lab report. The purpose of this guide is to help you write a clear and concise report that summarizes the lab you have just completed.
The lab report is composed of three sections:
Section I: Experimental Overview
o Provide background information.
o Include the hypothesis.
o Summarize the procedure.
Section II: Data & Analysis
o Include graphs to display trends in the data.
o Identify trends in the data.
Section III: Conclusions
o Identify if the hypothesis was supported or refuted.
o Provide logical reasoning based on data.
o Explain how the experiment could be improved.
To help you write your lab report, you will first answer the eight questions listed below based on the experiment that you have just completed. Then you will use the answers to these questions to write the lab report that you will turn into your teacher.
You can upload your completed report with the upload tool in formats such as OpenOffice.org, Microsoft Word, or PDF. Alternatively, your teacher may ask you to turn in a paper copy of your report or use a web-based writing tool.
Questions
Section I: Experimental Overview
1. What is the question that you are trying to answer?
2. What is your hypothesis for this experiment?
3. What methods are you using to test this hypothesis?
Outline the steps of the procedure in full sentences.
Section II: Data & Analysis
4. What graphs would clearly represent the trends in your data?
Your Student Guide includes information on which graphs to construct. Each graph should have the following:
a. an appropriate title
b. appropriate labels for each axis
c. an appropriate scale for each axis
d. the correct units for the data
Complete a rough sketch of each graph.
5. What do the data in your graphs tell you?
Explain in one or two sentences what trend the reader should observe in each of your graphs.
Section III: Conclusions
6. What do the data tell you about your hypothesis?
State how your hypothesis is either supported OR refuted by the data.
7. How do the data support your claim above?
Explain your statement above. Be sure to refer to specific pieces of data from your experiment that support your argument.
8. If you could repeat the experiment and make it better, what would you do differently and why?
There are always ways that experiments can be improved. Now that you are a veteran of this experiment and have experience with the procedure, offer some advice to the next scientist about what you suggest and why.
Writing the Lab Report
Now you will use your answers from the eight questions above to write your lab report. Follow the directions below.
Section I: Experimental Overview
Use your answers from questions 1-3 as the basis for the first section of your lab report. This section provides your reader with background information about why you conducted this experiment and how it was completed. It should be 1-2 paragraphs in length.
Section II: Data & Analysis
Use your answers from questions 4-5 as the basis for the second section of your lab report. This section provides your reader with the data from the experiment and a visual way to see any trends in the data. No paragraphs are required for this section, but you do need to include the appropriate graphs to display the data.
Section III: Conclusions
Use your answers from questions 6-8 as the basis for the third section of your lab report. This section provides your reader with your interpretation of the data set. It also demonstrates your understanding of the experiment through your ability to offer constructive criticism about its design. This section should be 1-2 paragraphs in length.
Overall
When complete, the lab report should be read as a coherent whole. Make sure that you connect different pieces with relevant transitions. Review for proper grammar, spelling, punctuation, formatting, and other conventions of organization and good writing.
Answers
Section I: Experimental Overview
1. What is the question that you are trying to answer?
2. What is the background information related to this question?
3. What is your hypothesis?
4. What was the procedure that you used to test your hypothesis?
Section II: Data & Analysis
5. What data did you collect during the experiment?
6. What trends or patterns did you observe in the data?
7. How do the trends in the data support or refute your hypothesis?
Section III: Conclusions
8. Based on the data and analysis, what conclusions can you draw about the question you were trying to answer? How could the experiment be improved for future studies?