Which has the events in the right order, from early to late?

a. Quark soup
b. protons form
c. nucleosynthesis
d. atoms form
e. estar formation.

A) The total charge of the system is negative. Therefore, option A is correct.

B) The total charge of the system is -2.88 × 10⁻¹⁸ C.

The total charge of a system consisting of 58 electrons and 40 protons is negative.

Charge is a fundamental physical quantity that indicates whether matter has an excess or a deficit of electrons. As a result, charge plays an important role in the interaction between objects. A positively charged object has a net excess of protons, while a negatively charged object has a net excess of electrons.

Let's find out the number of electrons and protons in this system of electrons and protons. 40 protons are present in the system. The number of electrons in the system is 58.

A) Therefore, the net charge of the system, Q, can be calculated as follows:

Q = (number of electrons) × (charge per electron) − (number of protons) × (charge per proton)

Q = (58 electrons) × (1.60 × 10⁻¹⁹ C/electron) − (40 protons) × (1.60 × 10⁻¹⁹ C/proton)

Q = 9.28 × 10⁻¹⁸ C − 6.40 × 10⁻¹⁸ C

Q = 2.88 × 10⁻¹⁸ C

The total charge of the system is negative. Therefore, option A is correct.

B) The charge of the system can be calculated as follows:

Q = (58 electrons) × (1.60 × 10⁻¹⁹ C/electron) − (40 protons) × (1.60 × 10⁻¹⁹ C/proton)Q = 9.28 × 10⁻¹⁸ C − 6.40 × 10⁻¹⁸ CQ = 2.88 × 10⁻¹⁸ C

Therefore, the total charge of the system is -2.88 × 10⁻¹⁸ C.

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From what we know, we can confirm that water must gain or lose large amounts of energy when its temperature changes due to its high specific heat.

This is another term used to describe heat or thermal capacity. These terms describe the amount of energy needed to change the temperature of a substance. Due to this, water requires a high amount of energy to raise its temperature by one degree.

Therefore, we can confirm that water must gain or lose large amounts of energy when its temperature changes due to its high specific heat.

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The cost of using 50 W for one day or 24 hours is  dollar 0.12. The cost of using 800 W for 1 hour is 0.08 dollar.

Power is the rate of work done energy of  an object. Given that the cost of using 1 KWhr energy is dollar 0.10.

Then cost of using 50 W  or 0.05 KW in 24 hours is

0.05 × 24 ×  0.10  = 0.12 dollar

Cost of using 800 W or 0.08 KW per hour is 0.08 KWhr × 0.10 = dollar 0.08

Similarly, the cost of using 150 W in one month is find as follows:

150 W = 0.15 KW

energy used  = 0.15 × 30 × 24 hrs

cost = 0.15 × 30 × 24 hrs × 0.10 = dollar 10.8

The energy causing a cost of 2.5 dollar is 2.5/0.10 = 25 KWhr

power = 25 KWHr/24 hrs = 1.04 KW.

The energy causing a cost of 4 dollars is 4/0.10 = 40 KWhr

power =40 KWHr/24 hrs = 1.6 KW.

The energy causing the cost of 3 dollars  = 3/0.10 = 30 KWhr

then time = 30/100 W = 0.3 hr.

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the acceleration when the velocity is 0 m/s is 6 m/s².

a) Find the velocity and acceleration as functions of t.The equation of motion of a particle is given as s = t³ - 3t, where s is in meters and t is in seconds. We can find the velocity and acceleration by differentiating the displacement equation with respect to time t:

Velocity, v(t) = s'(t) = (d/dt)(t³ - 3t)

                     = 3t² - 3

Acceleration, a(t) = v'(t)

                            = (d/dt)(3t² - 3)

                            = 6t

b) Find the acceleration after 35 seconds.

The equation for acceleration as a function of time t is a(t) = 6t.

Therefore, we need to evaluate the acceleration function at t = 35. Substituting t = 35 in the acceleration function, we get:a(35) = 6(35) = 210 m/s²c)

Find the acceleration when the velocity is 0.Since the velocity is zero, we can equate the velocity equation to zero and solve for the time:

0 = 3t² - 3t

⇒ 3t(t - 1) = 0

So, t = 0 s or t = 1 s.

However, we're interested in the acceleration when the velocity is zero.

Therefore, we differentiate the velocity function with respect to time to obtain the acceleration function and evaluate the acceleration function at t = 1 s.

Differentiating the velocity function, we get:a(t) = 6tTherefore, a(1) = 6(1) = 6 m/s²

Therefore, When the velocity is 0 m/s, the acceleration is 6 m/s2.

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The time it takes for the commuter to reach a speed of 2.00 m/s is approximately 1.43 seconds.

To calculate the time, we use the equation t = (v - u) / a, where v is the final velocity (2.00 m/s), u is the initial velocity (0 m/s), and a is the acceleration (1.40 m/s^2). By substituting the values into the equation, we find that it takes approximately 1.43 seconds for the commuter to reach a speed of 2.00 m/s. Speed is a scalar quantity that represents how fast an object is moving. It is defined as the distance traveled per unit of time. In other words, it tells us how quickly an object is changing its position.

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Answer: 1.15 s

Explanation:

Given

Height of rock h=6.5 m

The horizontal speed of tiger u=3.5 m/s

In the vertical direction, there is no initial speed

Using the equation of motion

\(\Rightarrow h=ut+\frac{1}{2}at^2\\\\\Rightarrow 6.5=0+\frac{1}{2}\times 9.8\times t^2\\\\\Rightarrow t=\sqrt{\dfrac{13}{9.8}}=1.15\ s\)

Time taken is 1.15 s

Answer:

I THINK option A is correct

Explanation:

because the electrostatic force is directly proportional to product of charges

now if the force between two electron is F charge on electron is same so their product is positive now the charge on proton is +ve and on electron is -ve so their product is -F

Based on the given informations, the orbital period of the outer edges of the primordial disk was calculated to be approximately 1515 years.

Assuming that the mass of Neptune is 17 times that of the Earth and that the distance of Neptune from the Sun is about 30 astronomical units (AU), we can use Kepler's third law of planetary motion to solve for the period of the outer edges of the primordial disk.

Using the equation P² = (4π²/GM) x a³, where P is the period, G is the gravitational constant, M is the mass of the Sun, and a is the semi-major axis of the orbit, we can rearrange the equation to solve for P:

P = sqrt((4π²/GM) x a³)

Since the matter that made up the planetesimals was spread out evenly on the edges of the primordial disk, we can assume that the semi-major axis of their orbit was about 35.5 AU (the radius of the disk).

Plugging in the values, we get:

P = sqrt((4π²/6.6743 x 10⁻¹¹ x 1.9885 x 10³⁰) x (35.5 x 1.496 x 10¹¹)³)

P = 1515 years (approx.)

Therefore, the orbital period of the outer edges of the primordial disk was approximately 1515 years.

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The following are true about Halogens.

Halogens refer to non metallic elements that are found on group 7A of the periodic table and period 3. Examples of Halogens are chlorine, flourine, iodine, bromine, astatine and so on.

Some of the characteristics of Halogens are;

Therefore, The following are true about Halogens.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{100}{80} = \frac{5}{4} \\ \)

We have the final answer as

Hope this helps you

Answer:

1. 2 N to the left

2. To the left.

Explanation:

1. Determination of the net force.

Force applied to the right (Fᵣ) = 18 N

Force applied to the left (Fₗ) = 20 N

Net force (Fₙ) =?

The net force acting on the book can be obtained as follow:

Fₙ = Fₗ – Fᵣ

Fₙ = 20 – 18

Fₙ = 2 N to the left

Thus, the net force acting on the book is 2 N to the left

2. Determination of the direction.

From 1 above, the net force acting on the book is 2 N to the left. This simply means that the book will move to the left direction.

There are no true statements on the list.

Answer:

E=mc△T

E=0.012(4200)(99-98)

E=50.4J

50.4 joules of heat is used

Answer:

the second law of thermodynamics. that some energy is destroyed in every energy conversion.

Explanation:

According to the second law of thermodynamics, energy conversion is never 100% efficient. Some energy is always lost as it is being converted from one form to the other.

The fact that a steer must eat at least 100 pounds of grain to gain less than 10 pounds of muscle tissue shows that not all the energy taken up from the grain is channelled towards building the muscle tissue. Some energy from the grains are lost on the way according to the second law of thermodynamics.

The velocity of the bodies immediately after the collision is 2.8 m/s.

The conservation of momentum equation for an inelastic collision can be expressed as:

m₁v₁ + m₂v₂ = (m₁+ m₂)\(v_f\)

where m₁ and m₂ are the masses of the two objects, v₁ and v₂ are their initial velocities, and \(v_f\) is their final velocity after the collision.

In this case, the initial velocity of the 4-kg body is zero, and its final velocity just before collision can be calculated using the conservation of energy equation:

mgh = (1/2)mv²

where m is the mass of the body, g is the acceleration due to gravity, h is the vertical height, and v is the velocity just before the collision.

After collision, the two bodies stick together, so their final velocity can be calculated using the conservation of momentum equation above, where m₁ = 4 kg, v₁ is the velocity just before the collision, m₂ = 6 kg, and v₂ = 0 m/s (as the second body is at rest initially). The resulting velocity \(v_f\) is the final velocity of the 10-kg combined mass after the collision.

Therefore, the equation for the conservation of momentum can be written as:

(4 kg) v₁ + (6 kg) (0 m/s) = (4 kg + 6 kg) \(v_f\)

Simplifying this equation gives:

4v₁ = 10\(v_f\)

\(v_f\) = (4/10) v₁

To find v₁, we can use the conservation of energy equation above, where m = 4 kg, g = 9.8 m/s², h = 500 cm = 5 m:

(4 kg) (9.8 m/s²) (5 m) = (1/2) (4 kg) v₁²

Solving for v1 gives:

v₁ = √[(2 x 4.9 x 5) / 4] = 7 m/s

Substituting this value of v₁ into the equation for \(v_f\) above, we get:

\(v_f\) = (4/10) (7 m/s) = 2.8 m/s

Therefore, the velocity of the 10-kg combined mass immediately after the collision is 2.8 m/s.

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The first step is to find the frequency heard by each aircraft as they approach each other. Let's call the frequency heard by each aircraft.

According to the Doppler effect formula for sound, the frequency heard by an observer moving towards a stationary source is given by:

f' = (v + vs) / (v + vd) * f

where f is the emitted frequency, v is the speed of sound, vs is the speed of the source (aircraft in this case), and vd is the speed of the observer (also an aircraft in this case).

Since both aircraft are approaching each other at the same speed, we can assume that their speeds are equal and call it v_a. Therefore, we have:

f' = (v + v_a) / (v - v_a) * f

We are given that the frequency heard by each aircraft is 2 times the emitted frequency, so we can write:

2f = (v + v_a) / (v - v_a) * f

Simplifying this equation, we get:

2 = (v + v_a) / (v - v_a)

2(v - v_a) = v + v_a

v = 3v_a

Now we can substitute this value of v into the speed of sound formula to get the speed of each aircraft:

343 m/s = (3v_a + v_a)

v_a = 343 / 4 = 85.75 m/s

Finally, we can convert this speed to km/hr:

85.75 m/s * 60 s/min * 60 min/hr / 1000 m/km = 308.7 km/hr

Therefore, each aircraft must have a speed of approximately 308.7 km/hr in order for the pitch they both hear to be 2 times the emitted frequency.

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Answer:

\(1.2\times 10^{10}\ kg\)

Explanation:

Given that,

The energy of the nuclear plant, \(E=10^{27}\ J\)

We need to find how much mass wast lost.

The relation between energy and mass is given by :

\(E=mc^2\)

Where

c is speed of light

\(m=\dfrac{E}{c^2}\\\\m=\dfrac{10^{27}}{(3\times 10^8)^2}\\\\m=1.2\times 10^{10}\ kg\)

So, \(1.2\times 10^{10}\ kg\) of mass was lost.

If we know the frequency or wavelength of a wave, we can use this equation to calculate its speed or vice versa.

The correct relationship between the frequency of the incident radiation (ν), its wavelength (λ), and speed (c) is:

A. ν = λ/c

This equation is known as the wave equation and describes the relationship between the frequency, wavelength, and speed of a wave. It states that the frequency of a wave is inversely proportional to its wavelength and directly proportional to its speed. The speed of light (c) is a constant in a vacuum and its value is approximately 3.0 x 10^8 m/s.

Therefore, if we know the frequency or wavelength of a wave, we can use this equation to calculate its speed or vice versa.

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As the mass passes through the equilibrium positions the force of the spring is increasing.

Simple harmonic motion is a specific kind of periodic motion of a body that arises from a dynamic equilibrium between an inertial force that is proportional to the body's acceleration away from the static equilibrium position and a restoring force on the moving object that is directly proportional to the magnitude of the object's displacement and acts towards the object's equilibrium position. Oscillating spring perform SHM.

as the mass passes through the equilibrium position, at the equilibrium position the force is zero and it increases with increase in displacement x according to the relation F = kx.

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The optical effect that can occur when one stares at the top of the artwork and then looks at the bottom half is an afterimage effect.

Optical is a term that describes the use of light to transfer information, perform tasks, and form images. It is commonly used in the field of telecommunications, where it refers to the transmission of information using light waves. It is also used in the field of optics, which deals with the study of light and its behavior. Optical technology is used in various applications, such as in optical microscopes, telescopes, and cameras. Optical technology is also used in fiber-optic communication, which transmits data over long distances with minimal loss of signal.

When staring at the top half of the artwork, the cells in the eyes become fatigued from the bright light, which causes the cells to become less sensitive to the same color. This results in the opposite color being seen in the bottom half of the artwork when looking away from the top half. For example, if the top half of the artwork is a bright yellow, then when looking at the bottom half, one may experience an afterimage effect of a dark blue.

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Answer:

Find the given attachments

In an experiment using charged rods, one in a cradle and the other held close to the tip of the cradled rod, the physics model that governs the interaction between the rods is Coulomb's Law. Coulomb's Law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

When the rods have the same charge (both positive or both negative), the force between them will be repulsive, causing the cradled rod to move away from the held rod. This is because like charges repel each other.

When the rods have different charges (one positive and one negative), the force between them will be attractive, causing the cradled rod to move towards the held rod. This is because opposite charges attract each other.

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The effect that changing plate separation and surface area has on your capacitor is that if the distance between the plates is increased then the capacitance of the capacitor will decrease. If the distance between the plates is decreased, then the capacitance of the capacitor will increase.

Similarly, if the surface area of the plates is increased, the capacitance of the capacitor will increase. If the surface area of the plates is decreased, the capacitance of the capacitor will decrease.The addition of a dielectric effect the capacitance by increasing the capacitance of the capacitor by a factor equal to the dielectric constant. The capacitance of the capacitor is given by the formula C = Kε0A/d  Therefore, the capacitance of the capacitor increases.Charge Q is stored on a capacitor in such a way that there is an equal and opposite charge on each plate. If the magnitude of the charge on one plate is q, then the magnitude of the charge on the other plate is -q.

The capacitance of a parallel-plate capacitor is given by the formula:C = ε0A/dWhere:C = capacitance of the capacitorε0 = permittivity of free spaceA = area of the platesd = distance between the platesIf the distance between the plates is increased, then the capacitance of the capacitor will decrease. If the distance between the plates is decreased, then the capacitance of the capacitor will increase.If the voltage across the equivalent capacitor is 3V, the charge on the equivalent capacitor is given by:Q = CeqV = (0.2F)(3V) = 0.6CIf the charge on the equivalent capacitor is 0.6C, the charge on capacitor C2 is given by:q2 = C2V = (0.05F)(3V) = 0.15CIf the charge on the equivalent capacitor is 0.6C, the charge on capacitor C3 is given by:q3 = C3V = (0.15F)(3V) = 0.45CTherefore, the capacitor that stores less charge is capacitor C2, because its capacitance is smaller than the capacitance of capacitor C3.

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The top layer is the zone in which the greatest total mass of co2 is absorbed from the atmosphere.

The exosphere is the uppermost layer of Earth's atmosphere, located between 700 and 10,000 kilometers above the surface and merging with the solar wind at its summit.

The  exosphere is a narrow, ambience space that surrounds a planetary  contains particles that are gravitational forces connected to that body yet have such a low density that they are effectively collisionless.

Hence, the top layer is the zone in which the greatest total mass of co2 is absorbed from the atmosphere.

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The Sun appears brighter than all the other stars because it is the closest star to Earth and also because of its relatively large size and brightness.

While the Sun is an average-sized star, it is much closer to Earth than any other star, with an average distance of 93 million miles. This proximity means that the Sun's light reaches Earth with much greater intensity than the light from more distant stars, making it appear much brighter. Additionally, the Sun's surface temperature of around 5,500 degrees Celsius makes it much brighter than most other stars, which have much cooler surface temperatures.

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It is more likely that the storm you observed, which passed over you after an hour, was a mesoscale convective system (MCS) rather than an air mass thunderstorm.

Air mass thunderstorms typically form and dissipate within the boundaries of a single air mass. They are generally short-lived and do not typically travel large distances. Therefore, it is less likely for an air mass thunderstorm to travel from a location far to the west to your current location within just an hour.

On the other hand, mesoscale convective systems are larger-scale weather systems that can cover hundreds of miles and persist for several hours or even longer. They often have organized structures, such as squall lines or clusters of thunderstorms, and can move over significant distances. It is more plausible for a mesoscale convective system to travel from a distant location to your area within the span of an hour.

Considering the time and distance covered, the fact that the storm passed over you after an hour suggests that it was likely a mesoscale convective system.

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