Which is an equivalent expression for 4 times d raised to the negative fifth power all over quantity 18 times d raised to the ninth power end quantity?

Answer:

The desired range is from 141 bpm to 157 bpm

Step-by-step explanation:

Given that the maximum heart rate = 175 bpm.

She plans an exercise program to reach the desired heart rate which is in the range of 80% and 90% of the maximum heart rate.

So, the lower limit of the desired heart rate = 80% of the maximum heart rate

=\frac{80}{100}\times 175= 140 bpm

and the upper limit of the desired heart rate = 90% of the maximum heart rate

=\frac{90}{100}\times 175= 157.5 bpm

So, mathematically, the desired range is between 140 bpm and 157.5 bpm.

The heart-beats per minute should be a counting number, so, round the upper limit to the lower integral value to be within the range.

Hence, the desired range is from 141 bpm to 157 bpm.

Answer:

6.8 + r

Step-by-step explanation:

increased means addition, so add r to 6.8:

6.8 + r

The width of the original piece of sheet metal is (w^2 - l^2)/(3w + 3l), and the length is (l^2 - w^2)/(3w + 3l).

To solve this problem, we can use the formula for the volume of a rectangular box, which is V = lwh, where l is the length, w is the width, and h is the height.

First, let's find the height of the box. Since we cut squares from each corner, the height of the box is the length of the square that was cut out. Let's call this length x.

The width of the box is the original width minus the lengths of the two squares that were cut out, which is w - 2x.

Similarly, the length of the box is the original length minus the lengths of the two squares that were cut out, which is l - 2x.

Now we can write the volume of the box in terms of x, w, and l:

V = (w - 2x)(l - 2x)(x)

Expanding this expression, we get:

V = x(4wl - 4wx - 4lx + 8x^2)

Simplifying further:

V = 4x^3 - 4wx^2 - 4lx^2 + 4wlx

To find the dimensions of the original piece of sheet metal, we need to maximize this volume. We can do this by taking the derivative of the volume with respect to x and setting it equal to zero:

dV/dx = 12x^2 - 8wx - 8lx + 4wl = 0

Solving for x, we get:

x = (2wl)/(3w + 3l)

Now we can use this value of x to find the width and length of the original piece of sheet metal:

w - 2x = w - 2(2wl)/(3w + 3l) = (w^2 - l^2)/(3w + 3l)

l - 2x = l - 2(2wl)/(3w + 3l) = (l^2 - w^2)/(3w + 3l)

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Answer:

not sure

Step-by-step explanation:

Answer:

226=p

Step-by-step explanation:

221+p=447

-221     -221

p=226

hope this helped :)

Answer:

$650

Step-by-step explanation:

Her hourly rate = $12.50 then

overtime rate = 2 × $12.50 = $25

For a 46 hour week she has 6 hours overtime , then

earnings = (40 × $12.50) + (6 × $25)

               = $500 + $150

               = $650

The patient can consume approximately 2 cans of 12 oz Coca Cola without exceeding the advised sugar limit.

To determine the number of 12 oz cans of Coca Cola the patient can consume, we need to convert the sugar limit provided by the doctor into grams and then calculate the amount of sugar in a 12 oz can of Coca Cola.

Provided:

Sugar limit: 8.5 × 10^(-2) kg

Coca Cola sugar content: 110 g/L

Volume of a 12 oz can: 12 oz (which is approximately 355 mL)

First, let's convert the sugar limit from kilograms to grams:

Sugar limit = 8.5 × 10^(-2) kg = 8.5 × 10^(-2) kg × 1000 g/kg = 85 g

Next, we need to calculate the amount of sugar in a 12 oz can of Coca Cola:

Volume of a 12 oz can = 355 mL = 355/1000 L = 0.355 L

Amount of sugar in a 12 oz can of Coca Cola = 110 g/L × 0.355 L = 39.05 g

Now, we can determine the number of cans the patient can consume by dividing the sugar limit by the amount of sugar in a can:

Number of cans = Sugar limit / Amount of sugar in a can

Number of cans = 85 g / 39.05 g ≈ 2.18

Since the number of cans cannot be fractional, the patient should limit their consumption to 2 cans of Coca Cola.

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Yes, the P-value is the probability, assuming H0 is true, of observing a value for the test statistic that is as extreme as or more extreme than the value actually observed.

The p-value is the probability of obtaining a statistic that is more or more extreme than that observed in experiment.

The p-value is calculated assuming the null hypothesis is true. Therefore, the lower the p-value, the stronger the evidence that the null hypothesis is false. That is, the lower the p-value, the stronger the evidence in favor of the alternative hypothesis.

The P-value is the observed test statistic (i.e., the data summary) that is as extreme as or more extreme than the currently observed test statistic under a statistical model that specifically assumes that the hypothesis is being tested. is the probability that It's true.

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Complete question

is the P-value is the probability, assuming H0 is true, of observing a value for the test statistic that is as extreme as or more extreme than the value actually observed.

By ordering the integers from least to greatest -8,2,-1,0,7. The integers in ascending order from least to greatest are -8, -1, 0, 2, 7.

To order the integers -8, 2, -1, 0, and 7 from least to greatest, we arrange them in ascending order based on their numerical value. Starting with the smallest value, we have -8. Next, we move to the next smallest value, which is -1. After that, we have 0, followed by 2, and finally, the largest value is 7.

Arranging them in order, we have -8, -1, 0, 2, and 7. This represents the integers from least to greatest.

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The Values of (a+b)ab are undefined.

Given that, a = 3an and db = -2We need to find the values of (a+b)

Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1

From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),

we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0

Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined

Therefore, the values of (a+b)ab are undefined.

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Work Shown:

1 full rotation = 1 year

1 year = 365.25 days (approximate)

1 day = 24 hours

1 hour = 60 minutes

Converting from 1 year to minutes gives

\(1 \text{ year} = \left(1 \text{ year}\right)*\left(\frac{365.25 \text{ days}}{1 \text{ year}}\right)*\left(\frac{24 \text{ hrs}}{1 \text{ day}}\right)*\left(\frac{60 \text{ min}}{1 \text{ hr}}\right)\\\\1 \text{ year} = \left(1*365.25*24*60\right)\text{ min}\\\\1 \text{ year} = 525,960 \text{ min}\\\\\)

So basically we just multiply out 365.25, 24, and 60 to get the answer.

The two random variables from this list that are continuous are: a) The average temperature in NYC during May. b) The compensation of a Top 500 CEO.

A continuous random variable is a variable whose values are any member of an uncountable set or any uncountable combination of such members. A continuous random variable has an infinite number of possible values, which are represented by an interval (a,b), where a and b can be any value on the real number line. A continuous random variable cannot take on individual values because there are an infinite number of values between any two points.For example, temperature, length, and weight are examples of continuous random variables.

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(a) By using the logistic equation P' = kP(1 - P/K), where P represents the fish population and K is the carrying capacity, we can determine the constant k. Given that the population tripled in the first year, we can set up the equation 3P = P(1 - kP/K) and solve for k. The value of k is approximately 0.0005833. We can then use this value to solve the logistic equation and find an expression for the population size after t years.

(b) To determine how long it will take for the population to increase to half of the carrying capacity, we set up the logistic equation P = 0.5K and solve for t. The solution to this equation gives us the time it takes for the population to reach half of the carrying capacity.

(a) To find the constant k, we set up the equation 3P = P(1 - kP/K) using the given information that the population tripled in the first year. By simplifying and solving for k, we find k ≈ 0.0005833. Now we can substitute this value of k into the logistic equation P' = 0.0005833P(1 - P/5100) and solve it to find an expression for the population size after t years.

(b) To determine the time it takes for the population to increase to half of the carrying capacity, we set up the equation P = 0.5(5100) using the logistic equation. By solving this equation, we can find the value of t that represents the time it takes for the population to reach half of the carrying capacity.

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Answer:

Step-by-step explanation:

cc

The most appropriate technique for the researcher to make this prediction would be multiple regression analysis, which would allow her to examine the relationship between the two predictor variables (high school grade-point averages and SAT scores) and the outcome variable (first semester college grade-point averages) while controlling for their effects on each other. This technique would help the researcher to determine the most accurate way to combine these two predictors in order to make the most accurate prediction possible.

A researcher aiming to predict first semester college grade-point averages (GPAs) using high school GPAs and SAT scores as predictor variables should use the Multiple Linear Regression technique. This technique allows the researcher to analyze the relationship between multiple predictor variables (high school GPAs and SAT scores) and a single continuous outcome variable (college GPAs), which can lead to more accurate predictions.

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Answer: The answer is B

Step-by-step explanation: Hope this helps xd

Answer:

y = 15x

Step-by-step explanation:

Given x and y are in direct variation then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition x = 2, y = 30, then

30 = 2k ( divide both sides by 2 )

15 = k

y = 15x ← equation of variation

The expression for the power delivered to a resistance in terms of csc^2 2 pi ft is P = I^2_0 R (csc^2 2 pi ft).

According to the given information, the power delivered to a resistance R when an alternating current of frequency f and peak current I_0 passes through it is represented by the equation P = I^2_0 R sin^2 2 pi ft.

To express this equation in terms of csc^2 2 pi ft, we can use the trigonometric identity csc^2 x = 1/sin^2 x. Substituting this identity into the equation, we get P = I^2_0 R (1/sin^2 2 pi ft).

Since csc^2 x is the reciprocal of sin^2 x, we can rewrite the equation as P = I^2_0 R (csc^2 2 pi ft). This expression represents the power delivered to the resistance in terms of csc^2 2 pi ft.

Therefore, the correct expression for the power delivered to the resistance in terms of csc^2 2 pi ft is P = I^2_0 R (csc^2 2 pi ft).

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Therefore, we cannot answer this question by giving a specific memory address or a specific value as the answer. However, we can state that the answer is unknown.

In this scenario, we are looking for the address of the machine instruction in decimal which follows the line of code, given that the values in LEGv8 registers are decimal numbers.

This means that we are looking for a memory address which is also a decimal number. Given that we do not have any additional information, we can assume that this machine instruction follows the line of code which includes the registers whose values are given.

Let us break down the registers:X1 = 7X2

= 13X3

= 2X4

= 20X5

= 9From the above registers, it appears that the machine instruction which follows the line of code that includes these registers, is not yet known or provided.

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Answer:

c.

Step-by-step explanation:

I go a slightly different route than the other answer.

let's see the side lengths of the triangle :

AB² = (7-4)² + (2-4)² = 3² + (-2)² = 9 + 4 = 13

AB = sqrt(13)

BC² = (1-7)² + (2-2)² = (-6)² + 0² = 36

BC = 6

CA² = (4-1)² + (4-2)² = 3² + 2² = 9 + 4 = 13

CA = sqrt(13)

it is an isoceles triangle (the legs have the same length).

so, we get the height via Pythagoras (for the right-angled triangle with height and BC/2 as legs) :

CA² = height² + (BC/2)²

13 = height² + 3² = height² + 9

height² = 4

height = 2

and the area of the triangle is then (baseline×height/2) :

6×2 / 2

and that is half of the area of a 6×2 rectangle.

Answer:

34%

Step-by-step explanation:

Answer:

A) 34%

Step-by-step explanation:

Lets say that the price of this object was $100.

Then, we know that each week the price is reducing by 10%, so therefore, we take 10% of $100, and we have $10

If we subtract that from $100, ($100-$10), we find that the price has come down to $90 after the first reduction in the first week. We will now do this process three more times to get to the four weeks total.

10% of $90 dollars is 9 dollars, so therefore the price reduces to $90-$9, $81 after the second reduction in the second week.

Then we take 10% of $81 and then get $8.1. We subtract that from $81 and get  $72.9

Then for the final reduction in the fourth week, we take 10% of $72.9, and we get $7.29. Take that from $72.9, and you get $65.61, which we can round to $66.

The question however asks how much was the approximate percantage in decresse over the 4 weeks. We see that the object went from $100 to $66, which is $34 decrease.

Now we simply find what percantage of $100 is $34, and that is 34%, which gives you option A.

Hope this helped.

The fundamental difference between a sample survey with nonresponse and a volunteer sample is the way participants are selected and the biases that may result from each approach. While nonresponse in a sample survey can lead to nonresponse bias, volunteer samples are more susceptible to selection bias.

The fundamental difference between a sample survey of human beings that may suffer from nonresponse and data using a volunteer sample is the way participants are selected and the potential biases that may arise.
In a sample survey, a random selection of individuals is chosen from the target population. However, nonresponse can occur when some of these selected individuals fail to participate or provide incomplete information. This can lead to nonresponse bias, which affects the representativeness of the sample and the accuracy of the results. To minimize nonresponse bias, researchers should ensure that their survey design and data collection methods encourage participation and provide clear instructions for respondents.
On the other hand, a volunteer sample consists of participants who willingly choose to participate in the study, usually in response to an open invitation. This approach is more prone to selection bias, as the individuals who volunteer may not be representative of the target population. They may have certain characteristics or attitudes that motivated them to participate, leading to biased results that may not generalize to the broader population. To address selection bias, researchers should carefully consider the recruitment method and the potential impact of volunteerism on their findings.
In summary, the fundamental difference between a sample survey with nonresponse and a volunteer sample is the way participants are selected and the biases that may result from each approach. While nonresponse in a sample survey can lead to nonresponse bias, volunteer samples are more susceptible to selection bias. Researchers must be mindful of these biases when designing and conducting their studies.

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The sample indicates that the data does not provide sufficient evidence to support the claim that 20% of plants are infected.

This given test is a test for single sample proportion

The test hypothesis are:

\(H_{o} :p=0.20\), null hypothesis

\(H_{1} :p\neq 0.20\), alternative hypothesis

The test statistic fallows a standard normal distribution and is given by:

\(Z=\frac{x-p}{{\sqrt{p(1-p)/n} } }\)

p=0.20

X=47 plants

Sample size, n=500

x, is the sample mean:

x=X/n=47/500

x=0.094

So, test statistic is calculated as:

\(Z=\frac{0.094-0.20}{\sqrt{0.20(1-0.20)/500} }\)

Z=-5.93

From the z-table, the p-value associated with Z=-5.93 is approximately 0

The decision rule based on p-vale, is to reject the null hypothesis if p-value is less than confidence level

In this case, the p-value is very small and less than confidence level of 0.20, we therefore reject the null hypothesis or the claim

So we conclude that the data does not provide sufficient evidence to support the claim that 20% of plants are infected.

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To prove two triangles are congruent, you can use one of the following methods: Side-Side-Side (SSS), Side-Angle-Side (SAS), Angle-Side-Angle (ASA), Angle-Angle-Side (AAS), or Hypotenuse-Leg (HL) for right triangles only.

To prove that two triangles are congruent, there are several methods, including:

Side-Side-Side (SSS) Congruence: If the three sides of one triangle are equal to the three sides of the other triangle, then the triangles are congruent.

Side-Angle-Side (SAS) Congruence: If two sides and the included angle of one triangle are equal to the two sides and the included angle of the other triangle, then the triangles are congruent.

Angle-Side-Angle (ASA) Congruence: If two angles and the included side of one triangle are equal to two angles and the included side of the other triangle, then the triangles are congruent.

Angle-Angle-Side (AAS) Congruence: If two angles and a non-included side of one triangle are equal to two angles and the corresponding non-included side of the other triangle, then the triangles are congruent.

Hypotenuse-Leg (HL) Congruence (for right triangles only): If the hypotenuse and one leg of one right triangle are equal to the hypotenuse and the corresponding leg of the other right triangle, then the triangles are congruent.

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a (n)=a1 × r^(n-1)

a1=5120

a2=1280

a3=320

a4=80

-->a2/a1=1280/5120=0.25

-->a3/a2=320/1280=0.25

-->a4/a3=80/320=0.25

ration(r) =0.25

■■■a(n)=a1 × r^(n-1)■■■

a (5)=5120×0.25^(5-1)

a (5)=5120 × 0.25 ^(4)

a (5) = 5120 × 0.00390625

a (5) = 20

Answer:

A, B, E

Step-by-step explanation:

The list that orders integers from greatest to least is: A. -8, -6, -3, 1, 3.

What are integers?

Integers are a set of whole numbers that includes both positive and negative numbers, as well as zero. Integers can be written without a fractional or decimal component, and they can be represented on a number line.

The list that orders integers from greatest to least is:

A. -8, -6, -3, 1, 3

To see why, we can simply compare the integers in each list from left to right. In list A, -8 is the smallest integer, followed by -6, -3, 1, and 3, which is the largest. Therefore, list A orders the integers from greatest to least.

In list B, we have 3 as the largest integer, followed by 1, -8, -6, and -3 as the smallest integer. Therefore, list B does not order the integers from greatest to least.

In list C, we have 1 as the largest integer, followed by 3, -8, -6, and -3 as the smallest integer. Therefore, list C does not order the integers from greatest to least.

In list D, we have 3 as the largest integer, followed by 1, -3, -6, and -8 as the smallest integer. Therefore, list D does not order the integers from greatest to least.

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Answer:

$110

Step-by-step explanation:

divide 330 by 3

$115 i think..........................