Answer:
B.The amount of energy absorbed during the reaction is different
Explanation:
I just took the test
what is the distance time how can we find the speed of an object from its distance time graph
Answer:
speed is the gradient of the graph
Answer:
Speed is the slope of a distance time graph.
Explanation:
Speed= d/t
Slope is equal to rise/run
If the rise of the graph is the distance and the run is the time, calculating slope is the equivalent of calculating average speed.
xác định quỹ của chất điểm chuyển động với phương trình chuyển động sau đây
Answer:
pls English
Explanation:
plsss,ಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠ
A meter 0.0525 m from a wire measures a magnetic field of 7.14 x 10-6 T. How much current flows through the wire?
the answer is 1.87
Answer:
1.9
Explanation:
Trial 1: Get a textbook and put a sheet of paper on top of it. Fold the paper as needed to keep the paper from sticking over the edge of the book.Hold the textbook with the paper on top, horizontally about waist high.Drop the book and paper so that they hit the floor flat. Record your observations.Trial 2: With the book in one hand and the paper in the other, drop the book and paper simultaneously from the same height. Record your observations.
Answer:
1) the two objects reach the floor at the same time.
2)the book reaches the floor much earlier than the foil
In conclusion, the difference in motion between the two systems subjected to the same acceleration depends on the weight of the body and friction force, when the body has less weight, the friction of the air affects it more
Explanation:
This interesting experiment has the following results
1) first case. Sheet on top of book
In this case the two objects reach the floor at the same time.
This shows that the acceleration in the two objects is the same and we call it the acceleration of gravity.
The speed of the body increases as it goes down linearly.
This occurs because the book that receives air resistance is much heavier, so the resistance has almost no effect on its movement, the sheet does not have the air resistance because it goes down next to the book.
2) second case. Book and sheet next to each other.
In this case the book reaches the floor much earlier than the foil.
This is because the resisting force of the air has almost no effect on the book and its movement is little affected by this force.
In the case of the blade, it has very little weight, therefore as its speed increases, the resistance force of the air rapidly equals the weight of the blade.
W_sheet - fr = 0
so after this, since the acceleration is zero, it goes down at constant speed, this speed is called the terminal velocity.
In conclusion, the difference in motion between the two systems subjected to the same acceleration depends on the weight of the body and friction force, when the body has less weight, the friction of the air affects it more.
Enter a curve slower than the posted speed if your vehicle has a high center of gravity or if surface _____________ is less than ideal.
a. traction
b. speed
c. energy
d. maneuvers
a. traction
If your vehicle has a high center of gravity or if the surface traction is less than ideal, it is important to enter a curve slower than the posted speed. This is because vehicles with a high center of gravity or poor surface traction are more prone to instability and are more likely to roll over or lose control when negotiating sharp turns or curves at high speeds.
Traction refers to the friction or grip between the tires of a vehicle and the road surface. Poor surface traction can be caused by a variety of factors, such as wet or slippery roads, loose gravel or debris, or worn or damaged tires. When surface traction is poor, it becomes more difficult for the tires to maintain contact with the road and to transmit the forces of acceleration, braking, and steering to the road.
By entering a curve slower than the posted speed, you can reduce the lateral forces acting on your vehicle and give your tires more time to grip the road. This can help you maintain control and stability, and reduce the risk of accidents or injuries. It is important to always adjust your speed and driving style to suit the conditions of the road and the capabilities of your vehicle.
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For this assignment, you should mathematically solve and record a video testing your solution for the following prompt: Two rolls of toilet paper, of equal mass and radius, are dropped from different heights so that they hit the ground at the same time. One roll of toilet paper is dropped normally while the other is dropped while a person holds onto a sheet of toilet paper such that the roll unravels as it descends. Determine the ratio of heights h1/h2, where h1 represents the height of the toilet paper dropped normally and h2 represents the height of the toilet paper that unravels, so that both rolls hit the ground at the same time.
Answer:
h1/h2 = \(\frac{2R^2}{3R^2 + h^2}\)
Explanation:
Using two rolls of tissue paper : One roll dropped normally while the other drops as some holds onto a sheet of the toilet paper ( I.e. the tissue paper drops rotating about its axis )
Determine the ratio of heights h1/h2
mass of tissues = same
radius of tissues = same
h1 = height of tissue 1
h2 = height of tissue 2
For the first tissue ( Tissue that dropped manually )
potential energy = kinetic energy
mgh = 1/2 mv^2
therefore the final velocity ( v^2 ) = 2gH ----- ( 1 )
second tissue ( Tissue that dropped while rotating )
gh = \(\frac{v^2}{u}\) ( 3 + \(\frac{u^2}{R^2}\) ) ------ ( 2 )
To determine the ratio of heights we will equate equations 1 and 2
hence :
gh = \(\frac{2gH}{u}\) ( 3 + \(\frac{u^2}{R^2}\) )
∴ h1/h2 = \(\frac{2R^2}{3R^2 + h^2}\)
how many moles in 3.4x10^24 atoms calcium chloride
The diagram below shows three kettles with their powers and the time they take to boil 500cm3 of water. If electricity costs 9p per unit, how much does it cost to boil 500cm3 of water using the 1.4kW kettle?
NOTE IF YOU ARE RIGHT YOU WILL GET A BRAINLY!!
The cost of boiling 500 cm³ of water using 1.4kW kettle is 0.945 p
How do I determine the cost of boiling water using 1.4 KW kettle?We shall begin our calculation by obtaining the energy consumed when using 1.4 KW kettle. This is shown below:
Power (P) = 1.4 KW Time (t) = 4.5 minutes = 4.5 / 60 = 0.075 hoursEnergy (E) =?E = Pt
E = 1.4 × 0.075
E = 0.105 KWh
Finally, we shall determine the cost of boiling the water using the 1.4 KW kettle. Details below
Cost per KWh = 9 pEnergy (E) = 0.105 KWhCost of boiling =?Cost = energy × Cost per KWh
Cost of boiling = 0.105 × 9
Cost of boiling = 0.945 p
Thus, we can conclude that the cost of boiling is 0.945 p
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Examine the image and assess the relationship of the atoms shown by
The reactants in the given chemical equation are methane (CH₄) and oxygen (O₂), while the products are carbon dioxide (CO₂) and water (H₂O).
During a chemical reaction, the atoms of the reactants reorganize to form new compounds in the products. A chemical change is this atomic rearrangement.
What is a change in chemistry?A chemical change is the transformation of one or more substances into new ones with distinct chemical and physical properties. New substances are created when the original substances' atoms are rearranged and new chemical bonds are formed during a chemical change.
Typically, a transfer of energy in the form of heat, light, or sound occurs in conjunction with this kind of change. Reactions like combustion, oxidation, decomposition, and synthesis are all examples of chemical changes. Physical changes, on the other hand, involve alterations in a substance's physical properties without altering its chemical composition.
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1. A string generates 120 vibrations every second.
a. What is its frequency?
b. What is its period?
Answer:
a:120hz
Explanation:
frequency=1 vibration per second so 120 seconds=120 vibrations
A grassland ecosystem (ecosystem X) supports 13 different grass species. A different grassland ecosystem (ecosystem Y) supports just one species of grass. Bison graze on all of the grass species in both of these ecosystems. Ecosystem X 13 species of grass Ecosystem Y 1 species of grass A drought strikes both ecosystem X and ecosystem Y, but the bison in ecosystem X are better able to survive it. Which of the following is a likely explanation? A. The bison in ecosystem X only eat one species of grass. B. Ecosystem Y has a greater amount of biomass. C. Ecosystem X has a greater amount of biodiversity. D. Ecosystem Y has a greater amount of biodiversity.
Answer:
Explanation:
Choices are:
A. The bison in ecosystem X only eat one species of grass.
B. Ecosystem Y has a greater amount of biomass.
C. Ecosystem X has a greater amount of biodiversity.
D. Ecosystem Y has a greater amount of biodiversity.
If grass species are drought-resistant, then they will allow the bison to continue feeding on them. X has more species (13) so it is more likely to have some drought-resistant grass.
Answer is C. Ecosystem X has a greater amount of biodiversity.
The bison in ecosystem X are better able to survive the drought because ecosystem X has a greater amount of biodiversity. Option (C) is correct.
What is biodiversity?Biodiversity is the variety of living things found in various habitats, such as terrestrial, marine, and desert ones, as well as the ecological groups to which they belong.
The variety of creatures present in an ecosystem, as well as their relative abundances, is referred to as biodiversity. It also depicts the various stages of organismal organization.
In ecosystem X, 13 different grass species present and in ecosystem Y 1 species of grass present, that is, ecosystem X has a greater amount of biodiversity. So, during the drought, the bison in ecosystem X are better able to survive.
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A kid with a mass of 35 kg is standing on roller blades and is holding an 11 kg medicine ball.If he throws the medicine ball horizontally to the right, which statement below is true?a. The kid will move to the left at the same speed that the ball moves to the right.b. The kid will move to the left at a higher speed than the ball moves to the right.C. The kid will move to the left at a lower speed than the ball moves to the right.d. The kid will not move at all.
Using conservation of momentum:
\(\begin{gathered} m1v1+m2v2=0 \\ _{\text{ }}Where\colon \\ m1=35\operatorname{kg} \\ m2=11\operatorname{kg} \\ v1=_{\text{ }}speed_{\text{ }}of_{\text{ }}the_{\text{ }}kid \\ v2=_{\text{ }}speed_{\text{ }}of_{\text{ }}the_{\text{ }}ball \\ so\colon \\ v1=-\frac{11}{35}v2 \\ _{\text{ }}where\colon \\ \frac{11}{35}<1 \\ so\colon \\ v2>v1 \end{gathered}\)We can conclude that the answer is:
C. The kid will move to the left at a lower speed than the ball moves to the right.
Two objects a distance apart are experiencing 40 N of force. How much force wouldthere be if you DOUBLED ONE of their masses?
Newton's universal law of gravitation
F = (G * m1* m2)/d^3
Where:
F = force
G= universal gravitation constant
M1= mass 1
M2 = mass2
d = distance
The force of attraction is directly proportional to the product of their masses.
40 x 2 = 80 N
If the mass of one object is doubled, then the force is doubled.
What fraction of the total kinetic energy is rotational for the following objects rolling without slipping on a horizontal sur- face? (a) a uniform solid cylinder; (b) a uniform sphere; (c) a thin- walled, hollow sphere; (d) a hollow cylinder with outer radius R and inner radius R>2.
The ratio of their rotational kinetic energies is 4/5 or 0.8.
Let's denote the mass and radius of the cylinder and sphere as "m" and "r", respectively. At the top of the incline, both objects have only potential energy, which is then converted to kinetic energy. At the bottom of the incline, both objects have both translational and rotational kinetic energy.
For a uniform solid cylinder, the rotational inertia is\(1/2 * m * r^2\). For a uniform sphere, the rotational inertia is\(2/5 * m * r^2\). Therefore, the ratio of their rotational kinetic energies is:
(rotational kinetic energy of sphere) / (rotational kinetic energy of cylinder)
\(= (2/5 * m * r^2 * (v/r)^2) / (1/2 * m * r^2 * (v/r)^2)\)
= (4/5)
Therefore, rotational kinetic energy of sphere is 80% of rotational kinetic energy of the cylinder at bottom of the incline.
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--The complete Question is, A uniform solid cylinder and a uniform sphere with the same mass and radius are released from rest at the top of an incline. They both roll without slipping down the incline and reach the bottom with the same translational speed. What is the ratio of their rotational kinetic energies at the bottom of the incline?--
What is the velocity of a plane that traveled 1500 miles from New York City to Orlando in 10.0 hours?
Answer:
v = (1500/10) = 150 [miles/h]
Explanation:
The velocity can be easily calculated using the following kinematics expression:
v = x/t
where:
v = velocity [miles/h]
t = time = 10 [hr]
x = distance = 1500 [miles]
v = (1500/10) = 150 [miles/h]
. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)
a}The work is done by the piston in the process is 199 cal.
b) The increase in internal energy of the gas is 703 cal
c) The heat was supplied to the gas is 3771 J
(a) To calculate the work done by the piston, we can use the formula:
Work = P * ΔV
Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:
Work = P * (\(V_2 - V_1\))
Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:
PV = nRT
\(V_1 = (nRT_1) / P_1\)
\(V_2 = (nRT_2) / P_2\)
Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).
Substituting the values into the equation, we have:
V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal
V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal
Therefore, the work done by the piston is:
Work = 1 atm * (796 cal - 597 cal) = 199 cal
(b) The increase in internal energy of the gas can be calculated using the equation:
ΔU = n * C * ΔT
Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).
Substituting the values into the equation, we have:
ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal
(c) The heat supplied to the gas can be calculated using the equation:
Q = ΔU + Work
Substituting the values calculated in parts (a) and (b), we have:
Q = 703 cal + 199 cal = 902 cal
Since 1 cal = 4.184 J, the heat supplied to the gas is:
Q = 902 cal * 4.184 J/cal ≈ 3771 J
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What is the kinetic energy of a 633.0-kg car moving at a speed of 11.2 m/s?
Answer:
39.7 kJ
Explanation:
The kinetic energy formula applies:
KE = (1/2)mv^2 = (1/2)(633.0 kg)(11.2 m/s)^2 = 39,701.76 J
The kinetic energy is about 39.7 kJ.
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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A tennis ball has a mass of 57 g. A tennis player hits the tennis ball with a tennis racket. The tennis ball has a velocity of 25 m / s when it hits the racket. The velocity of the tennis ball when it leaves the player’s racket is 15 m / s in the opposite direction from its approaching direction. The average force exerted by the tennis racket on the ball is 35 N. For how long is the tennis ball in contact with the tennis racket?
Answer:
0.065 seconds
Explanation:
i) Change in momentum is equal to impulse so, m(v-u) = ft (Where f is force and t is time)
ii) Since we know the mass of the ball, we change grams to the SI unit of kilograms, kg so 0.057kg
iii) We are also told that the ball CHANGES direction, so we know that the new velocity is the negative value of the initial one,
iv) Putting this all together we get 0.057(25--15) which is the same as 0.057(25 + 15)
v) We get an impulse of 2.28 Ns
vi) We take this value and divide it by 35 as we want the Force alone and not the time,
vii) To which we get 0.065 seconds,
Hope this was helpful!!
classify the following as a type of potential or kinetic energy
1. Rolling down a hill
2. A cat sitting on a chair
3. A basketball stuck in the hoop
4. Driving a go cart
5. A cat chasing a mouse
6. A rat running away with the teachers apple
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A variety of mature plants and trees indicates this level of ecological succession:
Responses
opportunists
pioneer species
climax community
primary succession
A hiker enters an area where there are large mature trees and a diverse population of other mature plants and shrubs.
Which statement best describes this ecosystem?
It is a climax community.
It is populated with pioneer plants.,
It features many opportunists.,
A hiker approaches a region with many enormous, mature trees and just a variety of other mature bushes and plants. The ecosystem is best describe by the "climax community."
Explain the term climax community?In ecology, the term "climax" refers to the last stage that biotic succession that a plant community can reach in a region depending on the environmental factors in place at the time.
For instance, in the eastern United States, cleared forests develop from fields to older fields with migrating trees and plants to forests among these early colonists, and finally towards climax communities comprising longer-lived tree species. The climax community's species composition doesn't change since all of the existing species are able to reproduce, whereas invasive species are unable to establish a presence. The climax stage isn't really entirely permanent since ecological processes, evolutionary processes, and climate changes all alter the environment over extremely long stretches of time.A hiker approaches a region with many enormous, mature trees and just a variety of other mature bushes and plants.
Thus, this ecosystem is best describe by the "climax community."
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The correct question is-
A hiker enters an area where there are large mature trees and a diverse population of other mature plants and shrubs.
Which statement best describes this ecosystem?
It is a climax community.
It is populated with pioneer plants.,
It features many opportunists.,
Answer: c
Explanation:
Explain why the subatomic particle that is not a part of the nucleus stays bound to the atom. For full credit, you must include the charges of all subatomic particles in your explanation.
The subatomic particle that is not a part of the nucleus which stays bound to the atom is the electron and is to maintain relative stability.
What is Electron?This is defined as a sub atomic particle which is negatively charged and revolve around the nucleus. In an atom the number of electron is usually equal to the number of the proton which is positively charged and present in the nucleus.
The electron not being in the nucleus is a a result of it wanting to maintain stability because its presence will produce a wavelength which will break the nucleus apart.
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Gọi E là trường vécto cò tính chất bảo toàn (hay con gọi là trường không rota). Trường E có những tinh chất nào sau đây
jawaban: what is languange???
Question 81 point)
Ms. Vetter has not worked out in a long time. She is trying to lift her pet bunny cage off the ground to put into her car for their trip to Bunnyville
to visit some of her pet bunnies ancestors. If Ms. Vetter does not have enough _____ _____ she can use a simple machine to help her lift the cage off the ground and into her car.
A.craft supplies
B.big muscles
C.mechanical force
D.mechanical advantage
Answer:
(C) Mechanical Force
Explanation:
Which type of force causes an object to stop sliding along a surface?
A. Compression
B. Tension
C. Electric
D. Friction
Answer:
D. Friction is the type of force
define Brownian motion
Answer:
Brownian motion, or pedesis, is the random motion of particles suspended in a medium.
Explanation:
of motion typically consists of random fluctuations in a particle's position inside a fluid sub-domain,
Answer:
The erratic random movement of microscopic particles in a fluid, as a result of continuous bombardment from molecules of the surrounding medium is called Brownian motion. Hope it helps you.
what happens as result of weight and buoyant force
The figure above shows Case 1 of an experiment, in which the following events occur.
At time t1
, block A slides to the right along a horizontal surface toward identical block B, which is at rest.
At time t2
, block A collides elastically with block B and block A comes to rest.
At time t3
, the right side of block B reaches an ideal, horizontal spring with negligible mass and spring constant k1
. The spring is initially at its relaxed (uncompressed) length and fixed to a wall.
At time t4
, the spring is compressed a maximum distance d1
and block B is instantaneously at rest.
Assume there is negligible friction between each block and the surface. For parts (a)-(d), consider the system consisting of block A, block B, and the spring.
(a) Indicate whether the linear momentum of the two-block–spring system is either constant or not constant during the time interval from t1
to immediately before t3
, and explain why.
Over the time period from t₁ to just before t₃, the two-block-spring system is linear momentum does not change because there are no external forces acting on the system to change its momentum.
Explain why the linear momentum of the two-block–spring system is either constant or not during the time period between t₁ and the time just before t₃?
The linear momentum of the two-block-spring system remains constant from t₁ until just before t₃.
Prior to the collision at time t₂, block A has a momentum to the right that is Pa = ma ×va, whereas block B has a momentum that is Pb = 0 because it is at rest. Because there is no external force acting on the system, its overall momentum is conserved.
All out Ptotal = Dad + Pb = mama × va
Expect there is immaterial erosion between each block and the surface. Take into consideration the spring, block A, and the system for parts (a) to (d).
Following the collision at time t₂, block B experiences a velocity of vb to the right and comes to a stop. Because the collision is elastic, all of the system's kinetic energy is conserved, but momentum is still conserved:
The two-block system is moving to the right at a constant velocity vb from time t₂ to just before time t₃, so the momentum of the system is constant. Ptotal = ma₀ plus mbvb plus mb ×vb
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How does clothing and body language affect a job interview?
Answer:
please give me brainlist and follow
Explanation:
Whilst first impressions can be important, your body language during the interview can make or break your overall performance. With experts saying that between 75-90% of communication is non-verbal, it is important to think about what your body is saying about you during an interview.
The same amount of thermal energy was added to two equal masses of Aluminum and Iron. The specific heat of Aluminum is double the specific heat of iron. If the temperature of the Aluminum's mass changes by /\T, what is the change in the Iron's mass temperature?
Answer:
it is double the temperature change of iron