Which is the main task of a sewage treatment plant?

A. to prevent flooding in a watershed
B. to neutralize chemicals in the water
C. to restore the water to 100% purity
D. to remove organic matter and kill germs

HELP ME PLEASE!​

Answers

Answer 1
D, my friends mom works in one

Related Questions

Which of these refers to the strength of an acid?a measure of the quantity of acid dissolved in water designated by molarityan intrinsic characteristic of a particular acid, not related to concentrationthe amount of hydrogen ions present in the acidthe amount of hydroxide ions present in a solution

Answers

Explanation:

Acids are substances that release positive hydrogen ions or protons (cations or anions) in an aqueous solution; for this reason, they are known as “proton donors”. In addition, acids react with bases, forming salts and water in a reaction called the “neutralization reaction”.

The more the number of hydrogen ions present in the acid, stronger it is.

Answer: the amount of hydrogen ions present in the acid

how do you balance this equation
2h2s+3o2+so2

Answers

The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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How is steel made from the raw product of the blast furnace known
as "pig iron"? What are the advantages of using steel?

List references used (if any were used) to answer this question.

Answers

Steel is produced from pig iron through a process known as steelmaking or iron and steel production.

The pig iron obtained from the blast furnace contains high amounts of carbon, impurities, and other elements. To convert pig iron into steel, the carbon content needs to be reduced to desired levels, and impurities must be removed.One common method of steelmaking is the basic oxygen process (BOP). In this process, pig iron is placed in a vessel called a converter, where oxygen is blown through the molten metal. The oxygen reacts with the carbon and impurities, causing them to oxidize and form gases that are released. Alloying elements and desired additives can be added at this stage to achieve specific steel properties. Another method is the electric arc furnace (EAF), where an electric arc is used to heat and melt the pig iron, allowing impurities to be oxidized and removed.The advantages of using steel are numerous. Steel is strong, durable, and versatile, making it suitable for a wide range of applications. It has high tensile strength, which means it can withstand heavy loads and pressures. Steel is also resistant to corrosion, making it ideal for construction, infrastructure, and transportation projects. It is a recyclable material, contributing to sustainability and reducing environmental impact. Additionally, steel can be fabricated into various shapes and sizes, allowing for customization and flexibility in design.References:

A. Ghosh and A. Chatterjee, Ironmaking and Steelmaking: Theory and Practice, PHI Learning, 2008.

R.H. Tupkary and V.R. Tupkary, An Introduction to Modern Iron Making, Khanna Publishers, 2010.

J.R. Davis, ed., ASM Specialty Handbook: Carbon and Alloy Steels, ASM International, 1995.

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6. Cross-cuts are best made with which of the following types of knife? A. Utility knife B. Scaler C. Paring knife D. Chef's knife

Answers

Answer:

A

Explanation:

Utility knife

Answer:

Utility knife

Explanation:

HELP ME OUT PLEASE!!!!!!!!!

Compare and contrast model A with model C. How are they alike: How are they different?

A) They are composed of different elements in the same ratio.

B) They are composed of the same elements in different ratios.

C) They are composed of different elements in different ratios

D) The are composed of the same elements but the bond types differ​

Answers

Answer:

Model C has more double the oxygen than A. I think it is B

Explanation:

B I had got this on my chemistry test before and it was right

Explain factor affecting stability of alkene

Answers

Answer:

Alkenes have substituents, hydrogen atoms attached to the carbons in the double bonds. The more substituents the alkenes have, the more stable they are. Thus, a tetra substituted alkene is more stable than a tri-substituted alkene, which is more stable than a di-substituted alkene or an unsubstituted one.

Answer:

Explanation:

The more substituents the alkenes have, the more stable they are. Thus, a tetra substituted alkene is more stable than a tri-substituted alkene, which is more stable than a di-substituted alkene or an unsubstituted one.

Suppose you are provided with a 30.86 g sample of potassium chlorate to perform this experiment. What is the mass of oxygen you expect
to release upon heating?

Answers

Answer:

The mass of oxygen is 12.10 g.

Explanation:

The decomposition reaction of potassium chlorate is the following:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

We need to find the number of moles of KClO₃:

\( \eta_{KClO_{3}} = \frac{m}{M} \)

Where:

m: is the mass = 30.86 g

M: is the molar mass = 122.55 g/mol

\( \eta_{KClO_{3}} = \frac{30.86 g}{122.55 g/mol} = 0.252 moles \)                                      

Now, we can find the number of moles of O₂ knowing that the ratio between KClO₃ and O₂ is 2:3

\( \eta_{O_{2}} = \frac{3}{2}*0.252 moles = 0.378 moles \)

Finally, the mass of O₂ is:

\( m = 0.378 moles*32 g/mol = 12.10 g \)

Therefore, the mass of oxygen is 12.10 g.

I hope it helps you!

How do you identify a redox reaction?

Answers

Answer:

I think you have to calculate the oxidation number of each atom in the reaction.

Explanation:

Hope that helped! ^u^

Convert 100.6 Kelvin to degrees C.

°C = K - 273
[?] °C ​

Answers

Answer:

  -172.6 °C

Explanation:

You want to know the Celsius equivalent of the temperature 100.6 K.

Conversion

The relation is ...

  C = K - 273.15

  C = 100.6 -273.15 = -172.55

The temperature is -172.55 °C, about -172.6 °C.

__

Additional comment

We have rounded to tenths, because that is precision of the temperature given. If you use 273 as the conversion constant, you will get -172.4.

What doesn’t change the resistance of a wire

Answers

The factor that  doesn’t change the resistance of a wire is pressure. option A.

What is resistance of a wire?

Resistance is a conductor's capacity to thwart the passage of current. It is controlled by the interplay of the applied voltage and the electric current passing through it. The amount of opposition any object applies to the flow of electric current is referred to as resistance.

The ohm, a unit of measurement for resistance, is represented by the Greek letter omega. According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them.

Hence option A is correct.

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missing part;

The pressure

The length of the resistor.

The thickness of the resistor.

The temperature of the conductor.

3. A Wilkinson’s catalyst is widely used in the hydrogenation of alkenes. Show a catalytic cycle, including: i. chemical structure of the catalyst, with complete stereochemistry ii. molecular geometry of catalyst iii. type of reactions involved iv. the appropriate starting material, reagent and solvent v. major and minor end-products vi. all intermediates, for each reaction stated in (iii)

Answers

We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

What are the steps involved?

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

Oxidative addition: The rhodium center undergoes oxidative addition, reacting with molecular hydrogen (H2) to form a dihydride intermediate.Alkene coordination: The alkene substrate coordinates to the rhodium center, forming a π-complex.Hydrogenation: The coordinated alkene undergoes hydrogenation, resulting in the addition of hydrogen atoms to the double bond and formation of a metal-alkyl intermediate.Reoxidation: The metal-alkyl intermediate reacts with a hydrogen molecule to regenerate the rhodium dihydride species.

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

Rhodium dihydride complex: [RhH2(PPh3)3]Alkene-Rhodium π-complex: [Rh(η2-alkene)(PPh3)3]Metal-alkyl intermediate: [Rh(alkyl)(PPh3)3]

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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give reason why using a seperate dropper for each stock solution in reagent bottle

Answers

The reason why a separate dropper is used for each stock solution in reagent bottle is so as to prevent contamination of the reagents.

What is a Dropper?

This is referred to as a short glass or plastic tube fitted with a rubber bulb which are found in reagents and is used to measure liquids by drops in the laboratory.

It is best for a separate dropper to be used for each stock solution in reagent bottle so as to prevent contamination of the reagents. This helps to ensure that the experiments which are performed are very accurate which is therefore the reason why it was chosen as the correct choice.

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Determine if the particle undergoes alpha, beta or gamma

Determine if the particle undergoes alpha, beta or gamma

Answers

The particle decay process described as 226 88 Ra → 222 Rn + He 86 involves the emission of a helium nucleus (He), which consists of two protons and two neutrons. This type of emission is known as alpha decay. Option A.

Alpha decay occurs when a radioactive nucleus releases an alpha particle, resulting in the emission of high-energy helium nuclei. In this case, the radium-226 (Ra) nucleus decays into radon-222 (Rn) by emitting an alpha particle. The resulting helium nucleus (He) is the emitted alpha particle.

Alpha particles have a positive charge and are relatively large and heavy. They are composed of two protons and two neutrons, which gives them a helium-like structure. Due to their size and charge, alpha particles have limited penetrating power and are typically stopped by a few centimeters of air or a sheet of paper.

Therefore, the correct answer A.  alpha radiation.

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State the number of neutrons in an atom of Ne-20 and the number of neutrons in an atom of Ne-22. choose two answers * 1 point Ne 20: 10 Ne 20: 11 Ne 22: 12 Ne 22: 13

Answers

Answer:

Ne 20: 10

and

Ne 22: 12

Explanation:

Ne-20:

N = A - Z = 20 - 10 = 10 neutrons

Ne-22:

N = A - Z = 22 - 10 = 12 neutrons

N: number of neutrons

A: mass number

Z: atomic number

A tank contains 15 kg of dry air and 0.17 kg of water vapor at 30°C and 100 kPa total pressure. Determine
(a) the specific humidity, (b) the relative humidity, and (c) the volume of the tank.

Answers

The volume of the tank is approximately 130.75 m³.

To solve this problem, we need to use the concept of air and water vapor mixture. The given data includes the mass of dry air and water vapor, temperature, and total pressure. We can calculate the specific humidity, relative humidity, and volume of the tank using the following steps:

(a) Specific humidity:

The specific humidity (ω) is defined as the ratio of the mass of water vapor (m_w) to the total mass of the air-water vapor mixture (m_t):

ω = m_w / m_t

Given that the mass of water vapor is 0.17 kg and the total mass of the mixture is 15 kg + 0.17 kg = 15.17 kg, we can calculate the specific humidity:

ω = 0.17 kg / 15.17 kg ≈ 0.0112

So, the specific humidity is approximately 0.0112.

(b) Relative humidity:

Relative humidity (RH) is the ratio of the partial pressure of water vapor (P_w) to the saturation vapor pressure of water (P_ws) at the given temperature, multiplied by 100:

RH = (P_w / P_ws) * 100

To find the relative humidity, we need to determine the saturation vapor pressure at 30°C. Using a vapor pressure table or equation, we can find that the saturation vapor pressure at 30°C is approximately 4.246 kPa.

Given that the total pressure is 100 kPa, the partial pressure of water vapor is 0.17 kg / 15.17 kg * 100 kPa = 1.119 kPa.

Now we can calculate the relative humidity:

RH = (1.119 kPa / 4.246 kPa) * 100 ≈ 26.34%

So, the relative humidity is approximately 26.34%.

(c) Volume of the tank:

To find the volume of the tank, we can use the ideal gas law equation:

PV = nRT

Where P is the total pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to calculate the number of moles of dry air and water vapor in the tank. The number of moles (n) can be obtained using the equation:

n = m / M

Where m is the mass and M is the molar mass.

The molar mass of dry air is approximately 28.97 g/mol, and the molar mass of water vapor is approximately 18.015 g/mol.

For dry air:

n_air = 15 kg / 0.02897 kg/mol ≈ 517.82 mol

For water vapor:

n_water = 0.17 kg / 0.018015 kg/mol ≈ 9.43 mol

Now we can calculate the volume using the ideal gas law:

V = (n_air + n_water) * R * T / P

Given that R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (30°C + 273.15 = 303.15 K), and P is the total pressure (100 kPa), we can calculate the volume:

V = (517.82 mol + 9.43 Mol) * 8.314 J/(mol·K) * 303.15 K / (100,000 Pa) ≈ 130.75 m³

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What is the density of the cube below if
the mass is 45g7
h=16m
L=5cm
W=3cm

Answers

0.1875grams/cm3 is the density of the cube below if

the mass is 45g7.

A material substance's density is its mass per unit volume. D is density, M is mass, and V is volume, therefore the formula for density is d = M/V. In terms of grammes per cubic centimeter, density is frequently expressed. As an illustration, the density of water is 1 g/cc, whereas the density of the Earth is 5.51 g/cc.

As kilos per cubic metre, density can also be calculated (in metre-kilogram-second or SI units). As an illustration, air has a density of 1.2 kilograms per cubic metre. Textbooks and manuals contain lists of the densities of common solids, liquids, and gases. The mass of a body can be calculated from its volume using density, and vice versa. The mass is equal to the volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). You may calculate a body's weight by multiplying its mass by the acceleration of gravity, which is typically of more practical significance than its mass.

Derive the mass and volume of this sugar cube

Mass = 45 grams

sides are h=16m

                L=5cm

               W=3cm

ρ = m/V

ρ = density, kg/m3, or g/(cm)3

m = mass, in kg or g

V = volume, in m3 or (cm)3

Here, ρ = density, m = mass, and v = volume.

ρ = 45/16×5×3

Density of the cube is 0.1875grams/cm3

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Will measuring the melting point of your product tell you that your product is relatively pure?

Answers

Answer and Explanation:

Yes. The determination of melting point is used to analyze if a solid compound is pure or impure. The melting point of a pure solid product does not vary in a narrow range, whereas if impurities are present the solid melts in a broad range of temperatures. For this reason, this technique is generally used to determine the identity and purity of the products obtained in chemical reactions.

describe two sources of energy and explain how they work

please help me (50points)​

Answers

Solar energy:-

In this way the energy generated through sun light with the help of solar panels and to be used in many works.

Wind energy:-

This is generated by moving turbines with windmills .It is used to create electric energy

The element least likely to obey the octet rule in forming chemical bonds is

Answers

Answer:

The two elements that most commonly fail to complete an octet are boron and aluminum; they both readily form compounds in which they have six valence electrons, rather than the usual eight predicted by the octet rule.

I think it will help you.

How many particles are there in 0.057 moles of lithium bromide made

Answers

There are 3.44 x 10^{22} particles in 0.057 moles of lithium bromide.

What chemical compound is lithium bromide known by?

The lithium bromide formula also known as the lithium monobromide formula or Bromo lithium formula is explored. It is a counterion bromide-based salt of lithium.

we have to use Avogadro's constant,

Avogadro's constant, is approximately equal to 6.022 x 10^{22} particles per mole.

we can use the following formula:

number of particles = moles x Avogadro's constant

Substitute the values,

number of particles = 0.057 moles x 6.022 x 10^{23} particles/mol

Simplifying the equation

number of particles = 3.44 x 10^{22} particles

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The big bang theory states that the Universe began by expanding from a small point nearly 14 billion years ago. Since that time, the Universe has continued to expand, and it is still expanding today.

In 1964, two scientists, Arno Penzias and Robert Wilson, were studying electromagnetic radiation emitted from space. During their research, they detected background radiation coming from all directions in the sky. This background radiation was found to be microwaves created during the big bang.

What does this information demonstrate?
A.
Most scientific theories of the Universe's origin remain the same even if scientific data fails to support them.
B.
Scientific data can be used to help support a theory of the origin of the Universe.
C.
The origin of the Universe should be explained by stating a theory is correct before collecting data.
D.
Scientific data can be used to help show that theories of the Universe's origin should always remain the same.

Answers

The information provided demonstrates that Option B. Scientific data can be used to help support a theory of the origin of the Universe.

The discovery of background radiation coming from all directions in the sky by Penzias and Wilson supports the big bang theory, which proposes that the Universe began expanding from a small point nearly 14 billion years ago. This discovery of cosmic microwave background radiation was predicted by the big bang theory, providing strong evidence in favor of the theory.

This example also highlights the importance of empirical evidence in scientific theories. The big bang theory was proposed based on observations of the redshift of distant galaxies, and the discovery of the cosmic microwave background radiation provided further empirical support for the theory. As more data is collected and analyzed, scientific theories can be modified or replaced if the evidence does not support them. This is the essence of the scientific method, which involves formulating hypotheses based on observations and then testing them through experimentation and observation.

Therefore, scientific data plays a crucial role in supporting or disproving theories, and theories should be continually tested and modified based on new evidence. The big bang theory remains one of the most widely accepted explanations of the origin of the Universe, and it is continually being refined and modified as new data becomes available. So, Option B is Correct.

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A student performs an experiment to determine the molar mass of magnesium oxide. The student repeats the experiment five times and collects the following data: 40.220gmol, 40.654gmol, 40.314gmol, 40.165gmol, and 40.554gmol. What is the relative standard deviation (RSD) for this set of data?

Answers

The relative standard deviation for the set of data obtained by the student is 0.470%

The formula for calculating the relative standard deviation is given below as:

Relative standard deviation (RSD) = (S * 100)/x

where S stands for the standard deviation and x is the mean of the data set.

The following are the steps to calculate to determine the relative standard deviation using the given formula:

Step 1: Calculate the mean of the numbers in the data set.

mean, x = sum of numbers / number of numbers

(40.220 + 40.654 + 40.314 + 40.165 + 40.554)/5

mean = 40.381 g/mol

Step 2: Subtract the mean from each number in the data to determine the deviation for each number and then square the deviations.

(40.220 - 40.381)² = 0.0259

(40.654 - 40.381)² = 0.0745

(40.314 - 40.381)² = 0.00449

(40.165 - 40.381)² = 0.0466

(40.554 -40.381)² = 0.0299

Step 3: Sum the squared deviations.

0.0259 + 0.0745 + 0.00449 + 0.0466 + 0.0299 = 0.181

Step 4: Determine the variance by dividing the sum of the squared deviations by the total number of values.

Variance = 0.181/5 = 0.0362

Step 6: Determine the standard deviation of the data by taking square root of the variance.

Standard deviation, S = √0.0362 = 0.190

Step 7: Determine the relative standard deviation by inserting the values in the formula, (RSD) = (S * 100)/x

RSD = (0.190 * 100)/40.381

RSD = 0.470%

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What is the pressure in bar of a 4.50 L tank with 3.35 moles of oxygen at 39.3 °C? R = 0.08314 L・bar/mol・K.

Answers

Answer:

19.3 bar

Explanation:

The ideal gas law allows us to calculate different characteristics of gases.

Ideal Gas Law

One way to calculate different values of gases we can use the ideal gas law. This law was named for the fact that it assumes gases behave "ideally." This means that the gases have perfectly elastic collisions and experience no intermolecular forces (IMFs). In equation form, this law is:

PV = nRT

In the equation, P is pressure, V is volume, n is moles, R is the gas constant, and T is the temperature in Kelvin. It is important to ensure that the units of the gas constant match the units of pressure that you are solving for.

Finding Pressure

To find pressure, we need to plug in the information we know and solve for P. The units of the gas constant we are given already match the pressure, so we do not need to convert. However, the temperature is given in °C not K. This means we need to convert; to do this, add 273 to °C.

39.3 °C + 273 = 312.3K

Now, we can plug all of our information into the ideal gas law.

P · 4.50L =  3.35mol · 0.08314L・bar/mol・K · 312.3K

To find P, divide both sides by 4.50.

P = 19.33 bar

Since the question is based on measured values, we need to round according to significant figure rules. The measured values in the question have 3 sig figs, so our answer should also have 3. This means the pressure is 19.3 bar.

A tank of hydrogen gas has a volume of 22.9L and hold 12 mol of gas at 12°C what is the pressure of the gas in atmospheres?

Answers

Answer:

P = 14.3 atm

Explanation:

PV = nRT

T = 12 C + 273 = 285K

P = nRT/V

P = 14.0 mol H(0.08205 L * atm/mol * K)(285 K) / 22.9 K

mol, L, and K cancels out

P = 14.3 atm

Helpppp me pleaseeee now I’ve been struggling so bad w this

Helpppp me pleaseeee now Ive been struggling so bad w this

Answers

Answer:

I don't know what the passage says, but I feel like the most logical conclusion is D or the last one.

Explanation:

Answer:

D! Hope this helps! Figured id help with all of ur questions!

Explanation:

Im a wiz at science! ;)

The pH of a solution is 3.81. What is the OH concentration in the solution?​

Answers

Answer:

6.46 × 10⁻¹¹ M

Explanation:

Step 1: Given data

pH of the solution: 3.81

Step 2: Calculate the pOH of the solution

We will use the following expression.

pH + pOH = 14.00

pOH = 14.00 - pH = 14.00 - 3.81 = 10.19

Step 3: Calculate the concentration of OH⁻ ions

We will use the definition of pOH.

pOH = -log [OH⁻]

[OH⁻] = antilog -pOH = antilog -10.19 = 6.46 × 10⁻¹¹ M

A solid keeps its shape due to which of the following factors? (3 points)
а
Space between particles
Attractive forces between particles
b
Ос
The type of element in the solid
Od
The container it is placed in

Answers

Answer: Attractive forces between particels

Explanation:

Draw the structures of the following molecules.
1. 1-chloro-1-butyne
2. (Z)-4-Bromo-3-methyl-3-penten-1-yne
3. 4-Hexyn-1-ol

Draw the structures of the following molecules. 1. 1-chloro-1-butyne 2. (Z)-4-Bromo-3-methyl-3-penten-1-yne

Answers

The structures of the compounds have been found in the image attached.

What is the structures?

We know that the structure of a molecule would have to do with the way and the manner in which a compound can be written in on paper. It is a kind of a visible representation of the compound.

As such all of the atoms in the compound as well as the groups that we find in the molecule can well be represented in the structure of the compound when it has been shown as we have in the images that are attached to the answer below.

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Draw the structures of the following molecules. 1. 1-chloro-1-butyne 2. (Z)-4-Bromo-3-methyl-3-penten-1-yne
Draw the structures of the following molecules. 1. 1-chloro-1-butyne 2. (Z)-4-Bromo-3-methyl-3-penten-1-yne
Draw the structures of the following molecules. 1. 1-chloro-1-butyne 2. (Z)-4-Bromo-3-methyl-3-penten-1-yne

Calculate the number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water.

Answers

The number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water is 0.025 moles.

The reaction of potassium with an excess amount of water is:

2K + 2H\(_2\)O \(\rightarrow\) 2KOH + H\(_2\)

To calculate the moles of hydrogen gas first we need to calculate moles of potassium in 2.00g

No. of moles = (mass) / (molecular mass)

The mass given is 2.00 g and the Molecular mass is 39.09 units

∴ No. of moles = (2) / (39.09) = 0.05

From the above reaction, we get that 2 moles of potassium give 1 mole of hydrogen gas. Thus, 0.05 moles of potassium gives 0.025 moles of hydrogen gas.

Therefore, the no. of moles of hydrogen gas produced is 0.025 moles.

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Electron Identify the type of charge of the following particles in an
atom
Electron
Neutron
Proton

Answers

Answer:

Electron charge: -1

Neutron charge: 0

Proton charge: +1

Other Questions
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