Which of these refers to the strength of an acid?a measure of the quantity of acid dissolved in water designated by molarityan intrinsic characteristic of a particular acid, not related to concentrationthe amount of hydrogen ions present in the acidthe amount of hydroxide ions present in a solution
Explanation:
Acids are substances that release positive hydrogen ions or protons (cations or anions) in an aqueous solution; for this reason, they are known as “proton donors”. In addition, acids react with bases, forming salts and water in a reaction called the “neutralization reaction”.
The more the number of hydrogen ions present in the acid, stronger it is.
Answer: the amount of hydrogen ions present in the acid
how do you balance this equation
2h2s+3o2+so2
The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.
The unbalanced equation is:
2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)
Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)
Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:
2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:
2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)
To remove the fractional coefficient, we can multiply all coefficients by 2:
4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:
4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)
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How is steel made from the raw product of the blast furnace known
as "pig iron"? What are the advantages of using steel?
List references used (if any were used) to answer this question.
Steel is produced from pig iron through a process known as steelmaking or iron and steel production.
The pig iron obtained from the blast furnace contains high amounts of carbon, impurities, and other elements. To convert pig iron into steel, the carbon content needs to be reduced to desired levels, and impurities must be removed.One common method of steelmaking is the basic oxygen process (BOP). In this process, pig iron is placed in a vessel called a converter, where oxygen is blown through the molten metal. The oxygen reacts with the carbon and impurities, causing them to oxidize and form gases that are released. Alloying elements and desired additives can be added at this stage to achieve specific steel properties. Another method is the electric arc furnace (EAF), where an electric arc is used to heat and melt the pig iron, allowing impurities to be oxidized and removed.The advantages of using steel are numerous. Steel is strong, durable, and versatile, making it suitable for a wide range of applications. It has high tensile strength, which means it can withstand heavy loads and pressures. Steel is also resistant to corrosion, making it ideal for construction, infrastructure, and transportation projects. It is a recyclable material, contributing to sustainability and reducing environmental impact. Additionally, steel can be fabricated into various shapes and sizes, allowing for customization and flexibility in design.References:
A. Ghosh and A. Chatterjee, Ironmaking and Steelmaking: Theory and Practice, PHI Learning, 2008.
R.H. Tupkary and V.R. Tupkary, An Introduction to Modern Iron Making, Khanna Publishers, 2010.
J.R. Davis, ed., ASM Specialty Handbook: Carbon and Alloy Steels, ASM International, 1995.
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6. Cross-cuts are best made with which of the following types of knife? A. Utility knife B. Scaler C. Paring knife D. Chef's knife
Answer:
A
Explanation:
Utility knife
Answer:
Utility knife
Explanation:
HELP ME OUT PLEASE!!!!!!!!!
Compare and contrast model A with model C. How are they alike: How are they different?
A) They are composed of different elements in the same ratio.
B) They are composed of the same elements in different ratios.
C) They are composed of different elements in different ratios
D) The are composed of the same elements but the bond types differ
Answer:
Model C has more double the oxygen than A. I think it is B
Explanation:
Explain factor affecting stability of alkene
Answer:
Alkenes have substituents, hydrogen atoms attached to the carbons in the double bonds. The more substituents the alkenes have, the more stable they are. Thus, a tetra substituted alkene is more stable than a tri-substituted alkene, which is more stable than a di-substituted alkene or an unsubstituted one.
Answer:
Explanation:
The more substituents the alkenes have, the more stable they are. Thus, a tetra substituted alkene is more stable than a tri-substituted alkene, which is more stable than a di-substituted alkene or an unsubstituted one.
Suppose you are provided with a 30.86 g sample of potassium chlorate to perform this experiment. What is the mass of oxygen you expect
to release upon heating?
Answer:
The mass of oxygen is 12.10 g.
Explanation:
The decomposition reaction of potassium chlorate is the following:
2KClO₃(s) → 2KCl(s) + 3O₂(g)
We need to find the number of moles of KClO₃:
\( \eta_{KClO_{3}} = \frac{m}{M} \)
Where:
m: is the mass = 30.86 g
M: is the molar mass = 122.55 g/mol
\( \eta_{KClO_{3}} = \frac{30.86 g}{122.55 g/mol} = 0.252 moles \)
Now, we can find the number of moles of O₂ knowing that the ratio between KClO₃ and O₂ is 2:3
\( \eta_{O_{2}} = \frac{3}{2}*0.252 moles = 0.378 moles \)
Finally, the mass of O₂ is:
\( m = 0.378 moles*32 g/mol = 12.10 g \)
Therefore, the mass of oxygen is 12.10 g.
I hope it helps you!
How do you identify a redox reaction?
Answer:
I think you have to calculate the oxidation number of each atom in the reaction.
Explanation:
Hope that helped! ^u^
Convert 100.6 Kelvin to degrees C.
°C = K - 273
[?] °C
Answer:
-172.6 °C
Explanation:
You want to know the Celsius equivalent of the temperature 100.6 K.
ConversionThe relation is ...
C = K - 273.15
C = 100.6 -273.15 = -172.55
The temperature is -172.55 °C, about -172.6 °C.
__
Additional comment
We have rounded to tenths, because that is precision of the temperature given. If you use 273 as the conversion constant, you will get -172.4.
What doesn’t change the resistance of a wire
The factor that doesn’t change the resistance of a wire is pressure. option A.
What is resistance of a wire?Resistance is a conductor's capacity to thwart the passage of current. It is controlled by the interplay of the applied voltage and the electric current passing through it. The amount of opposition any object applies to the flow of electric current is referred to as resistance.
The ohm, a unit of measurement for resistance, is represented by the Greek letter omega. According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them.
Hence option A is correct.
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missing part;
The pressure
The length of the resistor.
The thickness of the resistor.
The temperature of the conductor.
3. A Wilkinson’s catalyst is widely used in the hydrogenation of alkenes. Show a catalytic cycle, including: i. chemical structure of the catalyst, with complete stereochemistry ii. molecular geometry of catalyst iii. type of reactions involved iv. the appropriate starting material, reagent and solvent v. major and minor end-products vi. all intermediates, for each reaction stated in (iii)
We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.
What are the steps involved?Here's an overview of the catalytic cycle, including the necessary details:
i. Chemical structure of the catalyst:
Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]
ii. Molecular geometry of the catalyst:
The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.
iii. Type of reactions involved:
The catalytic cycle involves several reactions, including:
Oxidative addition: The rhodium center undergoes oxidative addition, reacting with molecular hydrogen (H2) to form a dihydride intermediate.Alkene coordination: The alkene substrate coordinates to the rhodium center, forming a π-complex.Hydrogenation: The coordinated alkene undergoes hydrogenation, resulting in the addition of hydrogen atoms to the double bond and formation of a metal-alkyl intermediate.Reoxidation: The metal-alkyl intermediate reacts with a hydrogen molecule to regenerate the rhodium dihydride species.iv. Starting material, reagent, and solvent:
The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).
v. Major and minor end-products:
The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.
vi. Intermediates:
The intermediates in the catalytic cycle include:
Rhodium dihydride complex: [RhH2(PPh3)3]Alkene-Rhodium π-complex: [Rh(η2-alkene)(PPh3)3]Metal-alkyl intermediate: [Rh(alkyl)(PPh3)3]These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.
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give reason why using a seperate dropper for each stock solution in reagent bottle
The reason why a separate dropper is used for each stock solution in reagent bottle is so as to prevent contamination of the reagents.
What is a Dropper?This is referred to as a short glass or plastic tube fitted with a rubber bulb which are found in reagents and is used to measure liquids by drops in the laboratory.
It is best for a separate dropper to be used for each stock solution in reagent bottle so as to prevent contamination of the reagents. This helps to ensure that the experiments which are performed are very accurate which is therefore the reason why it was chosen as the correct choice.
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Determine if the particle undergoes alpha, beta or gamma
The particle decay process described as 226 88 Ra → 222 Rn + He 86 involves the emission of a helium nucleus (He), which consists of two protons and two neutrons. This type of emission is known as alpha decay. Option A.
Alpha decay occurs when a radioactive nucleus releases an alpha particle, resulting in the emission of high-energy helium nuclei. In this case, the radium-226 (Ra) nucleus decays into radon-222 (Rn) by emitting an alpha particle. The resulting helium nucleus (He) is the emitted alpha particle.
Alpha particles have a positive charge and are relatively large and heavy. They are composed of two protons and two neutrons, which gives them a helium-like structure. Due to their size and charge, alpha particles have limited penetrating power and are typically stopped by a few centimeters of air or a sheet of paper.
Therefore, the correct answer A. alpha radiation.
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State the number of neutrons in an atom of Ne-20 and the number of neutrons in an atom of Ne-22. choose two answers * 1 point Ne 20: 10 Ne 20: 11 Ne 22: 12 Ne 22: 13
Answer:
Ne 20: 10
and
Ne 22: 12
Explanation:
Ne-20:
N = A - Z = 20 - 10 = 10 neutrons
Ne-22:
N = A - Z = 22 - 10 = 12 neutrons
N: number of neutrons
A: mass number
Z: atomic number
A tank contains 15 kg of dry air and 0.17 kg of water vapor at 30°C and 100 kPa total pressure. Determine
(a) the specific humidity, (b) the relative humidity, and (c) the volume of the tank.
The volume of the tank is approximately 130.75 m³.
To solve this problem, we need to use the concept of air and water vapor mixture. The given data includes the mass of dry air and water vapor, temperature, and total pressure. We can calculate the specific humidity, relative humidity, and volume of the tank using the following steps:
(a) Specific humidity:
The specific humidity (ω) is defined as the ratio of the mass of water vapor (m_w) to the total mass of the air-water vapor mixture (m_t):
ω = m_w / m_t
Given that the mass of water vapor is 0.17 kg and the total mass of the mixture is 15 kg + 0.17 kg = 15.17 kg, we can calculate the specific humidity:
ω = 0.17 kg / 15.17 kg ≈ 0.0112
So, the specific humidity is approximately 0.0112.
(b) Relative humidity:
Relative humidity (RH) is the ratio of the partial pressure of water vapor (P_w) to the saturation vapor pressure of water (P_ws) at the given temperature, multiplied by 100:
RH = (P_w / P_ws) * 100
To find the relative humidity, we need to determine the saturation vapor pressure at 30°C. Using a vapor pressure table or equation, we can find that the saturation vapor pressure at 30°C is approximately 4.246 kPa.
Given that the total pressure is 100 kPa, the partial pressure of water vapor is 0.17 kg / 15.17 kg * 100 kPa = 1.119 kPa.
Now we can calculate the relative humidity:
RH = (1.119 kPa / 4.246 kPa) * 100 ≈ 26.34%
So, the relative humidity is approximately 26.34%.
(c) Volume of the tank:
To find the volume of the tank, we can use the ideal gas law equation:
PV = nRT
Where P is the total pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to calculate the number of moles of dry air and water vapor in the tank. The number of moles (n) can be obtained using the equation:
n = m / M
Where m is the mass and M is the molar mass.
The molar mass of dry air is approximately 28.97 g/mol, and the molar mass of water vapor is approximately 18.015 g/mol.
For dry air:
n_air = 15 kg / 0.02897 kg/mol ≈ 517.82 mol
For water vapor:
n_water = 0.17 kg / 0.018015 kg/mol ≈ 9.43 mol
Now we can calculate the volume using the ideal gas law:
V = (n_air + n_water) * R * T / P
Given that R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (30°C + 273.15 = 303.15 K), and P is the total pressure (100 kPa), we can calculate the volume:
V = (517.82 mol + 9.43 Mol) * 8.314 J/(mol·K) * 303.15 K / (100,000 Pa) ≈ 130.75 m³
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What is the density of the cube below if
the mass is 45g7
h=16m
L=5cm
W=3cm
0.1875grams/cm3 is the density of the cube below if
the mass is 45g7.
A material substance's density is its mass per unit volume. D is density, M is mass, and V is volume, therefore the formula for density is d = M/V. In terms of grammes per cubic centimeter, density is frequently expressed. As an illustration, the density of water is 1 g/cc, whereas the density of the Earth is 5.51 g/cc.
As kilos per cubic metre, density can also be calculated (in metre-kilogram-second or SI units). As an illustration, air has a density of 1.2 kilograms per cubic metre. Textbooks and manuals contain lists of the densities of common solids, liquids, and gases. The mass of a body can be calculated from its volume using density, and vice versa. The mass is equal to the volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). You may calculate a body's weight by multiplying its mass by the acceleration of gravity, which is typically of more practical significance than its mass.
Derive the mass and volume of this sugar cube
Mass = 45 grams
sides are h=16m
L=5cm
W=3cm
ρ = m/V
ρ = density, kg/m3, or g/(cm)3
m = mass, in kg or g
V = volume, in m3 or (cm)3
Here, ρ = density, m = mass, and v = volume.
ρ = 45/16×5×3
Density of the cube is 0.1875grams/cm3
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Will measuring the melting point of your product tell you that your product is relatively pure?
Answer and Explanation:
Yes. The determination of melting point is used to analyze if a solid compound is pure or impure. The melting point of a pure solid product does not vary in a narrow range, whereas if impurities are present the solid melts in a broad range of temperatures. For this reason, this technique is generally used to determine the identity and purity of the products obtained in chemical reactions.
describe two sources of energy and explain how they work
please help me (50points)
Solar energy:-
In this way the energy generated through sun light with the help of solar panels and to be used in many works.
Wind energy:-
This is generated by moving turbines with windmills .It is used to create electric energy
The element least likely to obey the octet rule in forming chemical bonds is
Answer:
The two elements that most commonly fail to complete an octet are boron and aluminum; they both readily form compounds in which they have six valence electrons, rather than the usual eight predicted by the octet rule.
I think it will help you.
How many particles are there in 0.057 moles of lithium bromide made
There are 3.44 x 10^{22} particles in 0.057 moles of lithium bromide.
What chemical compound is lithium bromide known by?The lithium bromide formula also known as the lithium monobromide formula or Bromo lithium formula is explored. It is a counterion bromide-based salt of lithium.
we have to use Avogadro's constant,
Avogadro's constant, is approximately equal to 6.022 x 10^{22} particles per mole.
we can use the following formula:
number of particles = moles x Avogadro's constant
Substitute the values,
number of particles = 0.057 moles x 6.022 x 10^{23} particles/mol
Simplifying the equation
number of particles = 3.44 x 10^{22} particles
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The big bang theory states that the Universe began by expanding from a small point nearly 14 billion years ago. Since that time, the Universe has continued to expand, and it is still expanding today.
In 1964, two scientists, Arno Penzias and Robert Wilson, were studying electromagnetic radiation emitted from space. During their research, they detected background radiation coming from all directions in the sky. This background radiation was found to be microwaves created during the big bang.
What does this information demonstrate?
A.
Most scientific theories of the Universe's origin remain the same even if scientific data fails to support them.
B.
Scientific data can be used to help support a theory of the origin of the Universe.
C.
The origin of the Universe should be explained by stating a theory is correct before collecting data.
D.
Scientific data can be used to help show that theories of the Universe's origin should always remain the same.
The information provided demonstrates that Option B. Scientific data can be used to help support a theory of the origin of the Universe.
The discovery of background radiation coming from all directions in the sky by Penzias and Wilson supports the big bang theory, which proposes that the Universe began expanding from a small point nearly 14 billion years ago. This discovery of cosmic microwave background radiation was predicted by the big bang theory, providing strong evidence in favor of the theory.
This example also highlights the importance of empirical evidence in scientific theories. The big bang theory was proposed based on observations of the redshift of distant galaxies, and the discovery of the cosmic microwave background radiation provided further empirical support for the theory. As more data is collected and analyzed, scientific theories can be modified or replaced if the evidence does not support them. This is the essence of the scientific method, which involves formulating hypotheses based on observations and then testing them through experimentation and observation.
Therefore, scientific data plays a crucial role in supporting or disproving theories, and theories should be continually tested and modified based on new evidence. The big bang theory remains one of the most widely accepted explanations of the origin of the Universe, and it is continually being refined and modified as new data becomes available. So, Option B is Correct.
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A student performs an experiment to determine the molar mass of magnesium oxide. The student repeats the experiment five times and collects the following data: 40.220gmol, 40.654gmol, 40.314gmol, 40.165gmol, and 40.554gmol. What is the relative standard deviation (RSD) for this set of data?
The relative standard deviation for the set of data obtained by the student is 0.470%
The formula for calculating the relative standard deviation is given below as:
Relative standard deviation (RSD) = (S * 100)/x
where S stands for the standard deviation and x is the mean of the data set.
The following are the steps to calculate to determine the relative standard deviation using the given formula:
Step 1: Calculate the mean of the numbers in the data set.
mean, x = sum of numbers / number of numbers
(40.220 + 40.654 + 40.314 + 40.165 + 40.554)/5
mean = 40.381 g/mol
Step 2: Subtract the mean from each number in the data to determine the deviation for each number and then square the deviations.
(40.220 - 40.381)² = 0.0259
(40.654 - 40.381)² = 0.0745
(40.314 - 40.381)² = 0.00449
(40.165 - 40.381)² = 0.0466
(40.554 -40.381)² = 0.0299
Step 3: Sum the squared deviations.
0.0259 + 0.0745 + 0.00449 + 0.0466 + 0.0299 = 0.181
Step 4: Determine the variance by dividing the sum of the squared deviations by the total number of values.
Variance = 0.181/5 = 0.0362
Step 6: Determine the standard deviation of the data by taking square root of the variance.
Standard deviation, S = √0.0362 = 0.190
Step 7: Determine the relative standard deviation by inserting the values in the formula, (RSD) = (S * 100)/x
RSD = (0.190 * 100)/40.381
RSD = 0.470%
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What is the pressure in bar of a 4.50 L tank with 3.35 moles of oxygen at 39.3 °C? R = 0.08314 L・bar/mol・K.
19.3 bar
Explanation:The ideal gas law allows us to calculate different characteristics of gases.
Ideal Gas Law
One way to calculate different values of gases we can use the ideal gas law. This law was named for the fact that it assumes gases behave "ideally." This means that the gases have perfectly elastic collisions and experience no intermolecular forces (IMFs). In equation form, this law is:
PV = nRTIn the equation, P is pressure, V is volume, n is moles, R is the gas constant, and T is the temperature in Kelvin. It is important to ensure that the units of the gas constant match the units of pressure that you are solving for.
Finding Pressure
To find pressure, we need to plug in the information we know and solve for P. The units of the gas constant we are given already match the pressure, so we do not need to convert. However, the temperature is given in °C not K. This means we need to convert; to do this, add 273 to °C.
39.3 °C + 273 = 312.3KNow, we can plug all of our information into the ideal gas law.
P · 4.50L = 3.35mol · 0.08314L・bar/mol・K · 312.3KTo find P, divide both sides by 4.50.
P = 19.33 barSince the question is based on measured values, we need to round according to significant figure rules. The measured values in the question have 3 sig figs, so our answer should also have 3. This means the pressure is 19.3 bar.
A tank of hydrogen gas has a volume of 22.9L and hold 12 mol of gas at 12°C what is the pressure of the gas in atmospheres?
Answer:
P = 14.3 atm
Explanation:
PV = nRT
T = 12 C + 273 = 285K
P = nRT/V
P = 14.0 mol H(0.08205 L * atm/mol * K)(285 K) / 22.9 K
mol, L, and K cancels out
P = 14.3 atm
Helpppp me pleaseeee now I’ve been struggling so bad w this
Answer:
I don't know what the passage says, but I feel like the most logical conclusion is D or the last one.
Explanation:
Answer:
D! Hope this helps! Figured id help with all of ur questions!
Explanation:
Im a wiz at science! ;)
The pH of a solution is 3.81. What is the OH concentration in the solution?
Answer:
6.46 × 10⁻¹¹ M
Explanation:
Step 1: Given data
pH of the solution: 3.81
Step 2: Calculate the pOH of the solution
We will use the following expression.
pH + pOH = 14.00
pOH = 14.00 - pH = 14.00 - 3.81 = 10.19
Step 3: Calculate the concentration of OH⁻ ions
We will use the definition of pOH.
pOH = -log [OH⁻]
[OH⁻] = antilog -pOH = antilog -10.19 = 6.46 × 10⁻¹¹ M
A solid keeps its shape due to which of the following factors? (3 points)
а
Space between particles
Attractive forces between particles
b
Ос
The type of element in the solid
Od
The container it is placed in
Answer: Attractive forces between particels
Explanation:
Draw the structures of the following molecules.
1. 1-chloro-1-butyne
2. (Z)-4-Bromo-3-methyl-3-penten-1-yne
3. 4-Hexyn-1-ol
The structures of the compounds have been found in the image attached.
What is the structures?We know that the structure of a molecule would have to do with the way and the manner in which a compound can be written in on paper. It is a kind of a visible representation of the compound.
As such all of the atoms in the compound as well as the groups that we find in the molecule can well be represented in the structure of the compound when it has been shown as we have in the images that are attached to the answer below.
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Calculate the number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water.
The number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water is 0.025 moles.
The reaction of potassium with an excess amount of water is:
2K + 2H\(_2\)O \(\rightarrow\) 2KOH + H\(_2\)
To calculate the moles of hydrogen gas first we need to calculate moles of potassium in 2.00g
No. of moles = (mass) / (molecular mass)
The mass given is 2.00 g and the Molecular mass is 39.09 units
∴ No. of moles = (2) / (39.09) = 0.05
From the above reaction, we get that 2 moles of potassium give 1 mole of hydrogen gas. Thus, 0.05 moles of potassium gives 0.025 moles of hydrogen gas.
Therefore, the no. of moles of hydrogen gas produced is 0.025 moles.
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Electron Identify the type of charge of the following particles in an
atom
Electron
Neutron
Proton
Answer:
Electron charge: -1
Neutron charge: 0
Proton charge: +1