The material that is most likely to get warmest when placed in the sun is black cloth.
The material that is most likely to get warmest when placed in the sun is black cloth. The reason for this is that black is a good absorber of radiant energy, which is why it appears black. When the sun's radiant energy falls on black cloth, it absorbs the maximum amount of heat and gets hot. Light colors, on the other hand, do not absorb heat as well as black colors do. As a result, they appear cooler. As the sun's energy falls on the material, the heat is absorbed, and the temperature of the material rises. The temperature increases until the material has absorbed all of the radiant energy that it can, and then the temperature stabilizes. This is why black cloth, which absorbs more energy from the sun than any other color, feels the warmest.
Black cloth is most likely to become hot when placed in the sun because it absorbs the maximum amount of radiant energy. The color black is known for its heat-absorbing properties, while light colors reflect sunlight and appear cooler.
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A merry-go-round moves in a circle at a constant speed. Is the merry-go-round accelerating? Explain your answer.
Uniform Circular Motion:
Uniform Circular motion is the motion of a body that moves at constant angular velocity. Some examples of bodies that move at uniform circular motion are the blades of a fan set at a constant setting and the motion of a compact disc while the player is on.
The merry-go-round is accelerating since it is moving in a circle despite the fact that it is moving at a constant speed. The fact that an object moves in a circle does not always imply that it is moving at a constant speed. When an object moves in a circle, it changes direction, and this alteration of direction implies that the object is accelerating.
Even if the speed remains constant, it is still accelerating because the velocity is changing. This is referred to as centripetal acceleration. Centripetal acceleration is the acceleration caused by a force that pulls an object towards the center of the circle. Centripetal force is required for a body to move in a circle. A merry-go-round moves in a circle at a constant speed. This implies that the speed of the merry-go-round does not vary. However, the direction of motion changes continuously, indicating that the merry-go-round is constantly accelerating. Therefore, the merry-go-round is accelerating despite the fact that it is moving at a constant speed.
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Please help will give brainleast
How long will your trip take (în hours) if you travel 350 km at an average speed of 80 km/h
A platinum resistance thermometer measures temperature by the change in the electrical resistance of a platinum wire. The coefficient of resistivity for platinum is 3.92×10
−3
∘
C
−1
. At a temperature of 20.0
∘
C, the thermometer has a resistance of 50.0Ω; when immersed in a crucible containing melting indium its resistance is 76.8Ω. What is the melting point of indium? Question 9 An electric fire has a heating element rated at 1 kW when operating at 230 V. (a) what is its resistance? (b) what will be the power dissipation if the mains voltage drops to 210 V, assuming that the element obeys Ohm's Law?
From the calculation;
1) Melting point of indium = 171.4°
2) The resistance is 52.9 ohm
3) The power dissipated is 834 W
Temperature coefficient of resistanceThe temperature coefficient of resistance is a measure of how much the resistance of a material changes with temperature. It quantifies the relationship between the change in resistance and the change in temperature.
We have that;
R1/R2 = (1 + αt1)/(1 + αt2)
50/76.8 = (1 + (3.92 * \(10^-3\) * 20))/(1 + (3.92 *\(10^-3\) * t))
0.65 = 1.0784/1 + 0.00392t
0.65(1 + 0.00392t) = 1.0784
0.65 + 0.0025t = 1.0784
t = 171.4°
P = \(V^2\)/R
R = \(V^2\)/P
R = \(230^2\)/1000
R = 52.9 ohm
The new power is;
P =\(210^2\)/52.9
P = 834 W
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What do these two changes have in common? your breath becoming visible on a cold day building a tower out of magnetic blocks
(a) find the far point of an eye for which a prescribed lens has an optical power of -0.65 d.
The far point of the eye is approximately 1.54 meters.
To find the far point of an eye follow these steps:
1. Determine the focal length of the lens: The optical power (P) of a lens is the inverse of its focal length (f) in meters. So, P = 1/f or f = 1/P.
2. Calculate the focal length: Given the optical power of -0.65 D, the focal length can be calculated as f = 1/-0.65 ≈ -1.54 meters. A negative sign indicates that the lens is a diverging lens, which is commonly prescribed for myopia or nearsightedness.
3. Find the far point: For a person with myopia, the far point is the distance at which they can see clearly without any corrective lenses. The far point can be found using the lens formula, which is 1/f = 1/u + 1/v, where 'f' is the focal length, 'u' is the object distance (distance of the object from the lens), and 'v' is the image distance (distance of the image formed from the lens).
Since the far point is the maximum distance at which the person can see clearly without corrective lenses, the image formed by the lens should be at infinity (v = ∞). So the formula becomes:
1/f = 1/u + 1/∞
1/f = 1/u
4. Calculate the object distance (u): Since we know the focal length (f), we can calculate the object distance (u) using the formula:
u = 1/(1/f) = 1/(1/-1.54) ≈ -1.54 meters
So, the far point of the eye is approximately 1.54 meters. Note that the negative sign indicates that the far point is a virtual point located behind the lens.
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A liquid finds its own ....
Answer:
water seeks its own level
Answer:
water
Explanation:
A 46.4 kg wolf is running at 12.2 m/s what is the wolfs kinetic energy
The 46.4 kg wolf moving at a speed of 12.2 m/s has a kinetic energy of 3,456.98 J.
What establishes an object's entire amount of kinetic energy?The amount of work done on an item and its acceleration following a moment of inertia caused by external forces are two aspects that affect the overall kinetic energy of an object.
The formula: gives the kinetic energy (KE) of an item.
KE = (1/2) × mass × velocity²
where velocity is measured in meters per second (m/s) and mass is measured in kilograms (kg).
Plugging in the following numbers will allow us to determine the wolf's kinetic energy:
KE = (1/2) × 46.4 kg × (12.2 m/s)²
= (1/2) × 46.4 kg × 148.84 m²/s²
= 3,456.98 joules (J)
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A man pushes a heavy box. if the man exerts a force of 200 N on the box to keep it moving at a constant velocity what is the frictional force between the box and the ground? is this kinetic friction or static friction?
Answer:
Kinectic friction is the answer to the lower part of the question
A 5000kg freight car moving at 2 m/s East collides with a 10,000kg freight car at rest. Upon collision, they got stuck and moved with same velocity. Find their final velocity after collision
Answer:
A
Explanation:
If stormy weather were approaching, the pressure tendency would probably be ______. answer choices. falling. rising. steady. none of these.
Option A - Falling is the pressure tendency ,If stormy weather were approaching .
Stormy weather, namely when it includes components like dark clouds, strong winds, thunder, lighting, and rain, is defined as weather that has generated storms or that indicates storms are imminent. It's frequently used in sentences that refer to stormy weather. Low pressure causes active weather. As a result of air rising because it is lighter than the air masses around it, the atmosphere becomes unstable. When the air pressure increases, vapour in the condenses, creating clouds and rain, among other things. Both violent storms and active weather, such as wind and rain, are produced by low pressure systems.
Low-pressure areas have relatively thin atmospheres. Inward winds are a factor in these locations. Low-pressure storms are frequently well-organized.
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see attached, thanks !
Answer:
B = Frictional force
a car reaches the speed limit, and the driver engages cruise control, keeping the car at a constant speed. provided the driver remains on cruise control and drives in a straight line, which statements are correct about the car's motion?
When a car is on cruise control, the system is designed to maintain a specific, constant speed by automatically adjusting the throttle. This ensures that the car's motion remains steady, with no increase or decrease in speed, as long as the driver keeps the car in a straight line.
Since there is no change in velocity, the acceleration remains zero, which is a direct result of using cruise control at the speed limit in a straight line.
When a car reaches the speed limit and the driver engages cruise control, keeping the car at a constant speed in a straight line, the following statements about the car's motion are correct:
1. The car's velocity is constant: Since the car is moving in a straight line at a constant speed, its velocity (which includes both speed and direction) is also constant. This is because cruise control maintains the speed limit without any fluctuations, and the car is moving in a straight path.
2. The car's acceleration is zero: Acceleration refers to the change in velocity over time. As the car's velocity is constant, there is no change in its speed or direction, which means the acceleration is zero.
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What is the elastic potential energy of spring with k = 144 N/m that is compressed by 16.5
cm?
The elastic potential energy of spring with k = 144 N/m that is compressed by 16.5 cm is 0.58968 J.
The elastic potential energy of a spring can be calculated using the equation:
Elastic Potential Energy = 1/2 × k × x²
where k is the spring constant and x is the displacement from the equilibrium position.
In this case, the spring constant is given as k = 144 N/m and the spring is compressed by x = 16.5 cm = 0.165 m.
Plugging these values into the equation, we get:
Elastic Potential Energy = 1/2 × 144 N/m × (0.165 m)²
= 1/2 × 144 N/m × 0.027225 m²
= 0.58968 J (joules)
Therefore, the elastic potential energy of the spring with k = 144 N/m that is compressed by 16.5 cm is 0.58968 J.
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A transformer for a laptop computer converts a 220-V input to a 10-V output. Write down the equations that show that the primary coil has twenty two times as many turns as the secondary coil.
The transformer operates based on the principle of electromagnetic induction this equation shows that the primary coil has twenty-two times as many turns as the secondary coil.
Let's denote the number of turns in the primary coil as Np and the number of turns in the secondary coil as Ns.
The transformer operates based on the principle of electromagnetic induction, which states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the input voltage to the output voltage. Mathematically, this can be expressed as:
Np / Ns = Vin / Vout
In this case, the input voltage (Vin) is 220 V and the output voltage (Vout) is 10 V. Substituting these values into the equation, we get:
Np / Ns = 220 / 10
Simplifying further:
Np / Ns = 22
This equation shows that the primary coil has 22 times as many turns as the secondary coil.
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Mike was driving 30km/hr and slowed to 20km/hr in 10 seconds what is his acceleration? (number only)
Answer:
-0.28 m/s²
Explanation:
acceleration, a = (v - u)/t where u = initial velocity = 30 km/hr = 30 × 1000/3600 = 8.33 m/s and v = final velocity = 20 km/hr = 20 × 1000/3600 = 5.56 m/s and t = time = 10 s.
Substituting the values of the variables into the equation, we have
a = (v - u)/t
= (5.56 m/s - 8.33 m/s)/10 s
= -2.77 m/s ÷ 10 s
= -0.277 m/s²
≅ -0.28 m/s²
RESPIRATION the exchange of gases between your body and your environment.
TRUE OR FALSE
true
Explanation:
because in physiology, respiration is the movement of oxygen from the outside environment to the cells within tissues, and the removal of carbon dioxide in the opposite direction.
4
Diagram 2 shows the scale of a microammeter.
Rajah 2 menunjukkan skala sebuah mikroammeter
140 60
20
SO 100
wala
Diagram 2
Rajah 2
What is the sensitivity of the microammeter?
Berapakah kepekaan mikroammeter itu?
Answer:
100 micro-ampere
Explanation:
The sensitivity of an ammeter is the current required for the ammeter to reach its maximum reading or to cause maximum deflection of the ammeter.
As the relative amount of current required to cause maximum deflection of an ammeter is lesser, the sensitivity of the ammeter is said to be higher or the ammeter is said to be more sensitive
Therefore, given that the maximum reading on the given microammeter is 100 μA, the current required to cause the maximum deflection an thus the sensitivity of the ammeter is 100 micro-ampere.
57. A red ball (m= 10 kg) is moving at 3 m/s. A green ball (m = 8 kg) is moving at 3.5 m/s. Which ball has more
energy and by how much (2)
Answer:
the green ball has 4J more energy
Explanation:
The kinetic energy is given by the formula
K = 0.5 m v^2
the kinetic energy of the red ball:
K(red) = 0.5*10*3^2= 45J
of the green ball:
K(green)=0.5*8*3.5^2 = 49J
therefore the green ball has more energy by 4 Joules
A relief plane flying horizontally at 65.0 m/s is delivering a
food package to people stranded on an island. If the
island is a horizontal distance of 789 m away,
how high is the plane?
(Unit = m)
22000
Ay (m)
mily
The height of the plane delivering a food package to people stranded on an island is 722.2 m.
Time of motion of the food package
The time taken for the food package to hit the ground level is calculated as follows;
X = vt
where;
X is horizontal distance traveled by the food packagev is horizontal distancet is time of motiont = X/v
t = 789/65
t = 12.14 seconds
Height of the planeh = ¹/₂gt²
where;
h is height of fall of the food package which is height of the planet is time of motion of food packageg is acceleration due to gravityh = (0.5)(9.8)(12.14²)
h = 722.2 m
Thus, the height of the plane delivering a food package to people stranded on an island is 722.2 m.
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Answer:
722.2
Explanation:
An angry rhino with a mass of 3000 kg charges directly toward you with a speed of 4.10 m/s. Before you start running, as a distraction, you throw a 0.180 kg rubber ball directly at the rhino with a speed of 8.69 m/s. Determine the speed of the ball (in m/s) after it bounces back elastically toward you.
The speed of the ball, after it bounces back elastically toward you, is approximately 68333.33 m/s.
Initially, the rhino and the ball are moving in opposite directions, so their total momentum is zero. After the collision, the ball bounces back, and the rhino continues moving forward.
Let's calculate the momentum of the rhino before the collision:
Momentum of the rhino = mass of the rhino × velocity of the rhino
= 3000 kg × 4.10 m/s
= 12300 kg·m/s
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Since the rhino continues moving forward, the ball's momentum must be equal in magnitude but opposite in direction.
Let's denote the final velocity of the ball as v:
Total momentum after the collision = momentum of the rhino + momentum of the ball
= 0 + (mass of the ball × final velocity of the ball)
= 0.180 kg × v
Setting the initial and final momenta equal, we have:
12300 kg·m/s = 0.180 kg × v
Solving for v, we find:
v = 12300 kg·m/s / 0.180 kg
v ≈ 68333.33 m/s speed of ball
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Emma travels at a speed of 23 miles per hour for 3.5 hours. How far has she travelled?
Answer: 80.5 miles
Explanation:
3.5 x 23 = 80.5
Compare the events in the life of the Sun with those of a star that starts with less
mass than the Sun.
A star with greater mass will die out faster than the Sun.
What factors star is dependent on?A star's future relies upon its mass. For the most part, the more huge the star, the quicker it consumes its fuel supply, and the more limited its life. The most huge stars can wear out and detonate in a cosmic explosion after two or three million years of combination.
Our Sun is a typical estimated star: there are more modest stars and bigger stars, even up to multiple times bigger. Numerous other planetary groups have different suns, while our own simply has one. The Sun is made for the most part out of hydrogen and helium gas.
In this manner, one correlation in the occasions in the existence of the Sun with those of a star that beginnings with a mass multiple times more prominent than the Sun's is a star that has a more noteworthy mass will vanish quicker.
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How does the line energy of an object change if the objects speed doubles?
Answer:
A
Explanation:
The kinetic energy decreases to half its original value.
Un atleta tiene en un instante dado una velocidad de 4 m/s. Si a partir de ese instante y durante 2 s adquiere un MRUA con una aceleración de 3 m/s2. Calcula la velocidad que alcanza al cabo de esos 2 s.
Answer:
Velocidad final, V = 8 m/s
Explanation:
Dados los siguientes datos;
Velocidad inicial, u = 4 m/s
Aceleración, a = 2 m/s²
Tiempo, t = 2 segundos
Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;
V = u + at
Sustituyendo en la fórmula, tenemos;
V = 4 + 2*2
V = 4 + 4
Velocidad final, V = 8 m/s
Please help!!!!
A student reads that the Mid-Atlantic ridge is growing wider every year as the North American and Eurasian plates move apart. Why is the separation between the two plates of little concern?
a. the separation occurs slowly at the rate of only a few centimeters a year
b. the magnetic force acting between the two plates remains strong
c. the seafloor between the two plates continues to hold them together
d. a landmass bridges the gap that is created by the separation of the two plates
Answer:
I think its D.....
How do i get the o's 7x+69
The Complete Question:
How do I get one solution of 7x + 69 = 1 ?
Value of x in 7x + 69 = 1 is ( - 9.71 ).
Since the degree of variable is 1, the equation will have only one solution.
The degree of variable is defined at the value of power of the variable.
Using Algebra Equation,
= 7x + 69 = 1
= 7x = 1 - 69
= 7x = ( - 68)
= x = ( - 68) / 7
= x = ( - 9.71 )
Thus, the value of x in 7x + 69 = 1 is ( - 9.71 ) and this is the only solution to single degree algebraic equation.
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PLS HURRY IM TAKING THE TEST! THX
Particles q1 = -75.8 uC, q2 = +90.6 uC, and 93 = -84.2 uC are in a line. Particles q1 and q2 are separated by 0.876 m and particles q2 and q3 are separated by 0.432 m. What is the net force on particle q3?
The net force on particle q3 is -3.49 x 10^-3 N.
What is net force on q3?The net force on particle q3 can be calculated by considering the electric forces between q3 and each of the other particles, and then adding them vectorially. The electric force between two charged particles can be calculated using Coulomb's law:
\(F = k * |q1 * q2| / r^2\)
where k is Coulomb's constant (8.9875 x 10^9 N * m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the separation between the charges.
First, let's calculate the electric force between q3 and q2:
\(F12 = k * |-84.2 uC * 90.6 uC| / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 uC^2) / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 x 10^-6 C^2) / (0.432 m)^2\\= 3.05 x 10^-3 N\)
Next, let's calculate the electric force between q3 and q1:
\(F13 = k * |-84.2 uC * -75.8 uC| / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 uC^2) / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 x 10^-6 C^2) / (0.876 m)^2\\= -6.54 x 10^-3 N\)
Finally, the net force on particle q3 is given by the vector sum of the individual forces:
Fnet = \(F12 + F13 = 3.05 x 10^-3 N - 6.54 x 10^-3 N = -3.49 x 10^-3 N\)
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What is the weight of a 328N emperor penguin?
Answer:
Weight = 3217.68
Explanation:
N times Gravity = weight
Gravity= 9.81
The weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons.
What is Weight ?
Weight is the force exerted by the earth on an object at the surface of the earth. Mathematically -
W = m x g
where -
[m] is the mass of object
[g] is acceleration due to gravity
Given is the mass of an emperor penguin as 328 Kg.
We can write -
Mass [m] = 328 kg
Acceleration due to gravity [g] = 9.8 m/s²
Therefore, the weight of the emperor penguin will be
W[P] = m x g = 328 x 9.8 = 3214.4 Newtons
Hence, the weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons
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What's the free body diagram for:
Mr. Seifert needs to push a cardboard box down the hallway for Ms. Wang. The box has a mass of 40 kg and he is pushing it with an acceleration of 2 m/s/s. Because the cardboard does not slide easily, there is a friction force of 25 Newtons acting on the box to the LEFT. How much force is Mr. Seifert applying to the box to move it forward to the RIGHT?
(a) The free body diagram for representing all the forces acting on an object.
(b) The force Mr. Seifert is applying to the box to move it forward to the RIGHT is 105 N.
What is free body diagram?
A free body diagram is a graphical illustration of all the forces acting on an object.
The force applied by Mr Seifert is calculated by applying Newton's second law of motion as follows;
F - Ff = ma
where;
F is the applied forceFf is the force of frictionm is the mass of the cardboarda is the acceleration of the cardboardThe given parameters include;
mass of the cardboard = 40 kg
force of friction = 25 N
acceleration of the cardboard = 2 m/s²
The force applied by Mr Seifert is calculated as follows;
F = Ff + ma
F = 25 N + (40 kg x 2 m/s²)
F = 105 N
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