The mixture of option (C) - 30 mol H₂SO₄ + 0.70 kg H₂O represents a solution with a concentration that is closest to 30% by mass H₂SO₄.
To determine the mixture that represents a solution with a concentration closest to 30% by mass H₂SO₄, we need to compare the mass ratios of H₂SO₄ to the total mass of the mixture.
In option (A), we have 30 g H₂SO₄ + 100 g H₂O. However, the percentage by mass of H₂SO₄ in this mixture is (30 g / 130 g) * 100 ≈ 23.08%, which is lower than the desired 30%.
In option (B), we have 1 mol H₂SO₄ + 200 g H₂O. Since molar mass is not provided for H₂SO₄, we cannot determine the exact mass ratio.
In option (C), we have 30 mol H₂SO₄ + 0.70 kg H₂O. By converting 0.70 kg to grams (700 g), the mass ratio of H₂SO₄ to the total mass of the mixture is (30 mol / (30 mol + 700 g)) * 100 ≈ 4.11%. This is the closest to the desired 30% concentration.
Option (D) contains mole ratios, which do not directly relate to mass ratios and therefore cannot be used to determine the concentration by mass.
Based on the provided options, option (C) is the mixture that represents a solution with a concentration closest to 30% by mass H₂SO₄.
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The complete question is:
Which mixture of water and H2SO4 represents a solution with a concentration that is closest to 30% by mass H2SO4?
(A) 30 g H2SO4 + 100 g H2O (B) 1 mol H2SO4 + 200 g H2O (C) 30 mol H2SO4 + 0.70 kg H2O (D) 0.30 mol H2SO4 + 0.70 mol H2Owhat makes one of your cells you ?
002 (part 1 of 2) 10.0 points For :393 g of butadiene (C,11,) calculate the number of moles. Answer in units of mol.
Answer:
7.27 mol C4H6
Explanation:
To calculate moles, divide the molar mass by the grams given
To find molar mass, add the atomic mass of the elements
12.011*4 + 1.008*6 = 54.092 g/mol
393 g * 1 mol/54.092 g = 7.265 mol
what's the relationship between the number of atoms attached to the center atoms and the resulting molecular shape
The relationship between the number of atoms attached to the central atom and the resulting molecular shape can be described by VSEPR theory.
The valence-shell electron-pair repulsion theory (VSEPR) suggests that the geometric arrangement of atoms around a central atom in a molecule is determined by the electrostatic repulsion between the valence electron pairs in the atoms forming the molecule.
What is the VSEPR theory?Valence Shell Electron Pair Repulsion (VSEPR) theory is a model used to predict the three-dimensional geometry of a molecule, which is essential for understanding the molecule's properties and reaction mechanisms.
According to this theory, the arrangement of atoms around a central atom is determined by minimizing the repulsion between the pairs of valence electrons. In other words, the geometry of a molecule is determined by the arrangement of electron pairs surrounding the central atom.
Therefore, the number of atoms connected to the central atom and the position of these atoms (i.e., lone pair or bonding pair) determine the geometry of the molecule.
For example, the linear molecule of carbon dioxide has two oxygen atoms attached to the central carbon atom, resulting in a linear arrangement of atoms. The tetrahedral arrangement of four atoms is produced by a central carbon atom bonded to four hydrogen atoms in methane.
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Why does platinum metal make a good catalytic surface for reactant molecules?
It causes reactant molecules to be less reactive.
It strengthens bonds between reactant molecules.
It prevents products from breaking away from the surface.
It holds reactant molecules in a good position for them to react.
Answer:
it holds reactant molecules in a good position for then to react
Answer:
D. It holds reactant molecules in a good position for them to react.
Explanation:
Got a 100 on e2020.
2. Al(OH),(s) + 3 HCl(aq) à 3 H2O(l) + AlCl3(aq). This reaction shows how aluminum hydroxide
in antacid tablets neutralizes hydrochloric acid in the stomach. A tablet containing 0.25 g of
aluminum hydroxide is ingested by a patient with 0.88 g of hydrochloric acid in their stomach. Is
this tablet sufficient to neutralize the acid in the patient's stomach? Explain using stoichiometric
calculations. [4 marks]
I
This tablet insufficient to neutralize the acid in the patient's stomach
Further explanationReaction
Al(OH)₃(s) + 3HCl(aq) ⇒ 3 H₂O(l) + AlCl₃(aq)
0.25 g of Aluminum hydroxide-Al(OH)₃ , mol (MW=78 g/mol) :
\(\tt \dfrac{0.25}{78}=0.00321\)
mol HCl : mol Al(OH)₃ = 3 : 1
\(\tt mol~HCl=3\times 0.00321=0.00963\)
mass HCl (MW=36,46 g/mol) :
\(\tt 0.00963\times 36.46=0.351\)
0.351 < 0.88⇒this tablet insufficient to neutralize the acid
Next to a shallow cylindrical lake with a radius of 4km and an average water height of 5m, a type A exhaust basin has been installed, which recorded a total water loss of 4.5cm during a summer month. It is requested to calculate the evaporation of the lake and the volume of the lake water in cubic meters for the specific time period if the coefficient of the evaporation basin is equal to 0.7
In a shallow cylindrical lake with a radius of 4 km and an average water height of 5 m, a type A exhaust basin recorded a total water loss of 4.5 cm during a summer month.
The task is to calculate the evaporation of the lake and the volume of lake water in cubic meters for that specific time period, assuming an evaporation coefficient of 0.7. To calculate the evaporation of the lake, we first convert the recorded water loss from centimeters to meters. The total water loss is 4.5 cm, which is equal to 0.045 meters.
The evaporation from the lake can be determined by multiplying the water loss by the evaporation coefficient. In this case, the evaporation coefficient is given as 0.7. So, the evaporation from the lake is calculated as:
Evaporation = Water loss * Evaporation coefficient
Evaporation = 0.045 m * 0.7 = 0.0315 m
Therefore, the evaporation of the lake during the specified time period is 0.0315 cubic meters.To calculate the volume of lake water, we need to consider the shape of the lake, which is a shallow cylinder. The formula for the volume of a cylinder is:
Volume = π * radius^2 * height
Given that the radius of the lake is 4 km (4000 m) and the average water height is 5 m, we can calculate the volume of the lake as:
Volume = π * (4000 m)^2 * 5 m = 251,327,412 m^3
Therefore, the volume of lake water for the specific time period is approximately 251,327,412 cubic meters.
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The sodium atom loses an electron to form a sodium ion (Na+). Which statement is correct with respect to its atomic radius? A. The sodium ion has a larger radius than the atom. B. The sodium ion has a smaller radius than the atom. C. The sodium ion and the sodium atom radii are the same size. D. The sodium ion has twice the radius of the sodium atom.
Answer:B. The sodium ion has a smaller radius than the atom.
Explanation:
Because size of cation is less than neutral atom
Rank each of the bonds identified in order of increasing wavenumber: Hint : Stronger bonds (triple bonds > double bonds single bonds) vibrate at higher frequencies:
The order of increasing wavenumber for the bonds is: single bonds < double bonds < triple bonds. This reflects the relative strengths of the bonds, with triple bonds being the strongest and single bonds being the weakest.
The wavenumber of a bond in a molecule is directly proportional to the frequency of its vibration. Stronger bonds vibrate at higher frequencies, and weaker bonds vibrate at lower frequencies.
Using this information, we can rank the bonds identified in order of increasing wavenumber as follows:
1. Single bonds: These bonds are the weakest and vibrate at the lowest frequency, so they have the lowest wavenumber.
2. Double bonds: These bonds are stronger than single bonds and vibrate at a higher frequency, so they have a higher wavenumber.
3. Triple bonds: These bonds are the strongest and vibrate at the highest frequency, so they have the highest wavenumber.
Therefore, the order of increasing wavenumber for the bonds is single bonds < double bonds < triple bonds. This order reflects the relative strengths of the bonds, with triple bonds being the strongest and single bonds being the weakest.
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A ninja motorbike travelling at 55 m/s takes 10 sec to come to rest . What is its deceleration rate ?
Answer:
Speed=Distance
Time
Explanation:
Which of the following solutions of strong electrolytes contains the largest number of moles of chloride ions: 100.0 mL of 0.30 M AlCl3, 50.0 mL of 0.60 M MgCl2, or 200.0 mL of 0.40 M NaCl?
The largest number of moles of chloride ions are in 100ml of 0.3M AlCl3.
The moles is calculated as
molarity= moles/ molecular weight×100
moles of AlCl3= 0.1×0.3×133.34
= 4 mole where there are 3 chloride ion so it will be 12 moles.
Moles of MgCl2= 0.05× 0.6× 95.21
= 2.85 equivalent to 3moles where 2 chloride ion so it will be
Moles of NaCl =0.2× 0.4 ×58.5
= 4.67 where there are 1 chloride ion so it will be 4.67.
Mole is a measure of the number of substances and molarity is a measure of concentration. Molarity indicates the amount of substance present in a mixture. Molarity is given as the moles of substance in the volume of solvent. A mole is a unit, but a molarity is not.
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Imagine that 500 mL of a 0.100 M solution of HOAc(aq) is prepared. What will be the [OAc.) at equilibrium in this solution if the acid dissociation constant Ka(HOÀc) = 1.79 x 10-5? 1.33 x 10-3 M Oa. Ob.4.23 x 10-3M 9.46 x 10-4 M Oc. 0.100 M od e. not enough information to tell
The equilibrium concentration of OAc-, if 500 mL of a 0.100 M solution of HOAc(aq) is prepared, is approximately 1.33 x 1\(0^{-3}\) M.
To determine the equilibrium concentration of OAc- in the solution, we can use the acid dissociation constant (Ka) and an ICE (Initial, Change, Equilibrium) table. The reaction for the dissociation of HOAc is:
HOAc(aq) ⇌ \(H^{+}\)(aq) + OAc-(aq)
Initially, the concentrations are [HOAc] = 0.100 M, [\(H^{+}\)] = 0, and [OAc-] = 0. Let x be the change in concentration for dissociation. At equilibrium, we have:
[HOAc] = 0.100 - x
[\(H^{+}\)] = x
[OAc-] = x
Now, using the given Ka value (1.79 x 1\(0^{-5}\)):
Ka = ([\(H^{+}\)][OAc-])/[HOAc] = (x * x) / (0.100 - x)
Solving the quadratic equation, x ≈ 1.33 x 1\(0^{-3}\) M, which represents the equilibrium concentration of both H+ and OAc-. Therefore, the equilibrium concentration of OAc- is approximately 1.33 x 1\(0^{-3}\) M.
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Which nuclide below is most likely to decay by electron capture? a. 468 Y6 b. 470 Y6 c. 174Y6 d. 178Yb Od . Oa Ос Ob
The nuclide most likely to decay by electron capture is 174Yb. Option (c)
Electron capture is a type of radioactive decay in which an atomic nucleus captures an electron from its inner electron shell, combining it with a proton to form a neutron. This process occurs when the nucleus has a relatively low neutron-to-proton ratio and can stabilize itself by increasing the neutron count.
Ytterbium (Yb) is the element in the options provided, and 174Yb has a lower neutron-to-proton ratio compared to the other isotopes listed. Therefore, 174Yb is more likely to undergo electron capture as it seeks to increase the neutron count and achieve a more stable configuration.
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Which detail supports the main idea Bats are useful to humans?
Bats often live in large colonies in caves and under bridges.
Bats are the only mammal that truly flies.
Bats eat hundreds of mosquitoes and other annoying insects at night.
Some bats carry rabies, a deadly virus.
Answer:
Bats eat hundreds of mosquitoes and other annoying insects at night.
A hydrogen atom is excited from its ground state to the n= 4 state. The atom subsequently emits three photons, one of which has a wavelength of 1882 nm. What are the wavelengths of the other two photons?
The wavelength of the first line (n=4 to n=3) in the Balmer series is 656.3 nm. The wavelength of the second line (n=4 to n=2) in the Balmer series is 486.1 nm. The wavelength of the third photon, calculated above, is 594.1 nm.
The hydrogen atom has a single electron in its shell. Electrons in a hydrogen atom have a set of allowed energy levels. The ground state has the lowest energy level, and n represents the electron's energy level in the hydrogen atom.
Electrons gain energy and rise to a higher energy level when they are stimulated by energy from an external source such as an electric current or a photon beam.The hydrogen atom is said to be excited when its electron absorbs energy and rises to a higher energy level.
The excited atom then emits the energy in the form of electromagnetic radiation, which includes visible light and other wavelengths.The hydrogen atom has a characteristic spectrum due to the transitions between its energy levels. The wavelengths of photons absorbed or emitted when electrons in a hydrogen atom move between energy levels are determined by the following equation:
E=(hc)/λ whereE = energy of the photonh = Planck's constanctc = speed of lightλ = wavelength of the photonLet us now determine the wavelengths of the other two photons. When a hydrogen atom is excited from its ground state to the n=4 state, it emits a series of spectral lines known as the Balmer series.
The Balmer series is a series of lines in the visible light region of the spectrum. The wavelength of the first line (n=4 to n=3) in the Balmer series is 656.3 nm. The wavelength of the second line (n=4 to n=2) in the Balmer series is 486.1 nm.The third photon's wavelength can be calculated as follows
:Energy of the photon = (hc)/λEnergy of the photon = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (1882 x 10^-9 m) = 3.328 x 10^-19 JThe wavelength of the third photon is calculated as follows: Energy of the photon = (hc)/λ3.328 x 10^-19 J = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / λλ = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (3.328 x 10^-19 J)λ = 594.1 nmThe first two wavelengths are given by the Balmer series.
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State the worded equation for the reaction that occurred in a beaker when copper is placed in a beaker of silver nitrate.
The reaction of silver nitrate with copper is a substitution reaction. We have copper in its free state, Cu, and we have silver nitrate which has the formula AgNO3. The copper replaces the silver obtaining the following reaction:
\(2AgNO_{3(aq)}+Cu_{(s)}\rightarrow Cu(NO_3)_{2(aq)}+2Ag_{(s)}\)The products obtained are copper nitrate and silver.
The word equation will be:
\(SilverNitrate+Copper\rightarrow Copper(II)Nitrate+Silver\)How many moles of Al(NO3)3 are produced when 15.87 grams of HNO3 are reacted with excess Al(OH)3? Round your answer to three digits after the decimal point.
Al(OH)3 + 3 HNO3 à Al(NO3)3 + 3 H2O
* thank you so much! in advance
Calculating the amounts of reactants and products in chemical equations using stoichiometry is a key idea in chemistry. We employ the ratios from the balanced equation in this situation. Here the moles of Al(NO₃)₃ produced from the given reaction is 0.084.
Calculating the products and reactants in a chemical reaction is known as stoichiometry. Essentially, statistics are what it is about. The quantity of molecules involved in the reaction is known as the stoichiometric coefficient or stoichiometric number.
The number of moles of Al(NO₃)₃ formed is:
15.87 g HNO₃ × 1 mole HNO₃ / 63.01 g × 1 mole Al(NO₃)₃ / 3 moles of HNO₃ = 0.084 moles Al(NO₃)₃
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Find the valance shell and valance electron nitrogen
Answer:
The number of valence electrons is the number of electrons in the outer shell, that the atom uses for bonding. Nitrogen has 5 electrons in its n=2 (outer) shell. There is a quick way of identifying the number of valence electrons - it is the same as the Group number.
Explanation:
How many acetals are present in Acarbose? A) 1 acetal B) 2 acetals C) 3 acetals D) 4 acetals
Acarbose contains a single acetal linkage within its structure. Therefore, option (A) is correct.
The diabetes medicine acarbose, which is used to treat the disease diabetes, contains one acetal. An acetal is a functional group made up of a single carbon atom linked to either two oxygen atoms or two alkyl or aryl groups and either two oxygen atoms or two alkyl or aryl groups.
Acarbose has a circular structure, and at its centre is a carbon atom that, when joined with two oxygen atoms and an alkyl group, makes an acetal. This structure is what makes the medicine stop certain enzymes from breaking down carbs, which helps keep blood sugar levels in check. Therefore, option (A) is correct.
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Vectors A, B, and C, have the following components: Ax=1.0,Ay=2.0Bx=3.5,By=−4.0Cx=−5.0.Cy=6.0 Find the combination of these components where: AV/2−2By+5CV= ? 3.5 23 18.5 39 4.0
The combination of the given components yields -16.5.
To find the combination AV/2 - 2By + 5CV,
We need to substitute the given components of vectors A, B, and C into the expression.
Given:
Ax = 1.0
Ay = 2.0
Bx = 3.5
By = -4.0
Cx = -5.0
Cy = 6.
Substituting these values into the expression:
AV/2 - 2By + 5CV = (Ax/2) - 2(By) + 5(Cx)= (1.0/2) - 2(-4.0) + 5(-5.0)
= 0.5 + 8.0 - 25.0
= -16.5
Therefore, the combination of the given components yields -16.5.
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N2(g) + 3H2 (g)→2NH3(g) The reaction rate is measured as 0.032 M NH3/s. Determine the rate of disappearance of N2 and the rate of disappearance H2. Explain how you arrived at your answers.
The rate at which N\(_{2}\) disappears is 0.016 M/s, while the rate at which H\(_{2}\) disappears is 0.0213 M/s.
In the balanced chemical equation N\(_{2}\)(g) + 3 H\(_{2}\) (g) → 2NH\(_{3}\)(g), the stoichiometric coefficients represent the mole ratios between the reactants and products.
Since the reaction rate is given for NH\(_{3}\), we can determine the rates of disappearance of N\(_{2}\) and H\(_{2}\) by comparing their stoichiometric ratios in the reaction.
The stoichiometric ratio between N\(_{2}\) and NH\(_{3}\) is 1:2, meaning for every mole of N\(_{2}\) consumed, 2 moles of NH\(_{3}\) are produced. Therefore, the rate of disappearance of N\(_{2}\) is half of the rate of formation of NH\(_{3}\).
Similarly, the stoichiometric ratio between H\(_{2}\) and NH\(_{3}\) is 3:2. This means that for every 3 moles of H\(_{2}\) consumed, 2 moles of NH\(_{3}\) are produced. Therefore, the rate of disappearance of H\(_{2}\) is (2/3) times the rate of formation of NH\(_{3}\).
Given the rate of formation of NH\(_{3}\) as 0.032 M/s, the rate of disappearance of N\(_{2}\) would be 0.016 M/s (0.032 M/s ÷ 2), and the rate of disappearance of H\(_{2}\) would be approximately 0.0213 M/s (0.032 M/s × 2/3).
Therefore, the rate of disappearance of N\(_{2}\) is 0.016 M/s, and the rate of disappearance of H\(_{2}\) is 0.0213 M/s.
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The ozonization of pentene in carbon tetrachloride solution at 25∘C C5H10+O3→C5H10O3 is first order in C5H10 and first order in O3. Complete the rate law for this reaction in the box below. Use the form k[ A]m[ B]n, where '1' is understood for m,n… (don't enter 1 ) and concentrations taken to the zero power do not appear. Rate = In an experiment to determine the rate law, the rate constant was determined to be 1.24×105M−1 s−1. Using this value for the rate constant, the rate of the reaction when [C5H10]=0.190M and [O3]=0.0359M would be
The rate law for the ozonization of pentene in carbon tetrachloride solution at 25°C, C5H10 + O3 → C5H10O3, is given by Rate = k[C5H10][O3], where k is the rate constant.
In this reaction, the rate law expresses the relationship between the rate of the reaction and the concentrations of the reactants. The given rate law, Rate = k[C5H10][O3], indicates that the reaction is first order with respect to both C5H10 and O3. This means that the rate of the reaction is directly proportional to the concentrations of C5H10 and O3, each raised to the power of 1.
The rate constant, k, represents the proportionality constant in the rate law equation. It is experimentally determined and depends on various factors such as temperature, presence of a catalyst, and molecular collision frequency. In this case, the rate constant was found to be 1.24×105 M−1 s−1.
To calculate the rate of the reaction when [C5H10] = 0.190 M and [O3] = 0.0359 M, we substitute these values into the rate law equation. Therefore, the rate of the reaction can be calculated as:
Rate = k[C5H10][O3]
= (1.24×105 M−1 s−1)(0.190 M)(0.0359 M)
= 8.43 M s−1
So, the rate of the reaction when [C5H10] = 0.190 M and [O3] = 0.0359 M would be 8.43 M s−1.
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What is an atom?
Hshshdgwbdhwjshdhshshsbsh
The empirical formula for the compound having the formula H₂C₂O4 is
C₂O₂H₂
COH
COH ₂
CO₂H
C₂H₂
Answer:
CO₂H
Explanation:
The empirical formula gives the smallest whole number ratio of atoms of each element in a compound.
The ratio of hydrogen, carbon and oxygen in H₂C₂O₄ is:
H : C : O
2 : 2 : 4
They have a common factor of 2, so we can divide the atoms of each element by 2:
H : C : O
1 : 1 : 2
This gives us HCO₂ or CO₂H
Which type of mixture contains particles that are NOT spread out
evenly?
Select one:
heterogeneous mixture
alloy
homogeneous mixture
solution
In a heterogeneous mixture the substances are not evenly distributed (chocolate chip cookies, pizza, rocks) Page 2 Within the categories of homogeneous and heterogeneous mixtures there are more specific types of mixtures including solutions, alloys, suspensions, and colloids.
Ammonia gas can be prepared by the reaction of a metal oxide such as calcium oxide with ammonium chloride.
CaO(S) + 2 NH4Cl(s) 2 NH3(g) + H2O(g) + CaCl2(s)
If 139 g of CaO and 245 g of NH4Cl are mixed, what is the maximum possible yield of NH3?
What mass of the excess reactant remains after the maximum amount of ammonia has been formed?
24.7 g of NH4Cl will remain as excess reactant after the maximum amount of NH3 has been formed.
What is Reactant?
In a chemical reaction, a reactant is a substance that undergoes a chemical change or reaction with other substances to form a product. Reactants are typically written on the left side of a chemical equation and are used to represent the starting materials in a chemical reaction. The reactants are consumed during the reaction, and the resulting products are formed.
To determine the maximum possible yield of NH3, we first need to calculate the limiting reactant of the reaction, which is the reactant that is completely consumed and determines the maximum amount of product that can be formed.
The balanced chemical equation for the reaction is:
CaO(S) + 2 NH4Cl(s) → 2 NH3(g) + H2O(g) + CaCl2(s)
The molar mass of CaO is 56.08 g/mol, and the molar mass of NH4Cl is 53.49 g/mol.
To find the limiting reactant, we can use the mole ratio of CaO and NH4Cl in the balanced equation.
Number of moles of CaO = 139 g / 56.08 g/mol = 2.476 mol
Number of moles of NH4Cl = 245 g / 53.49 g/mol = 4.588 mol
The mole ratio of CaO to NH4Cl is 1:2, which means that 1 mole of CaO reacts with 2 moles of NH4Cl.
Therefore, the amount of NH4Cl required to react with all the CaO is:
2.476 mol CaO × (2 mol NH4Cl / 1 mol CaO) = 4.952 mol NH4Cl
Since we have only 4.588 mol of NH4Cl available, it is the limiting reactant. This means that all the NH4Cl will be consumed in the reaction and the amount of NH3 produced will be limited by the amount of NH4Cl.
The maximum possible yield of NH3 can be calculated using the mole ratio of NH4Cl and NH3 in the balanced equation:
4.588 mol NH4Cl × (2 mol NH3 / 2 mol NH4Cl) × (17.03 g NH3 / 1 mol NH3) = 155 g NH3
Therefore, the maximum possible yield of NH3 is 155 g.
To determine the mass of the excess reactant remaining, we can use the amount of NH4Cl consumed in the reaction and subtract it from the initial amount of NH4Cl:
245 g NH4Cl - (4.588 mol NH4Cl × 53.49 g/mol) = 24.7 g NH4Cl
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Ammonia, NH3, is made in the direct reaction between nitrogen and hydrogen. If 280. grams of nitrogen are used,
how many grams of hydrogen are also used?
Answer:
The answer is 60 grams of hydrogen.
Explanation:
Assuming hydrogen is a non-limited substance, we can calculate the number of mols of nitrogen that are used.
Molar mass of N = 14 grams/mole
280g of N / (14 g / mol) = 20 mols of N
They react in a 1 to 3 ratio. For every 1 nitrogen atom, there are 3 hydrogen atoms.
The molar mass of hydrogen is 1 g / mol.
Because we have 20 mols of Nitrogen and we know we need three times the amount of hydrogen as we do nitrogen, there must be 60 mols of hydrogen.
60 * 1 = 60
The answer is 60 grams of hydrogen.
18 points Which identifies an oxidation-reduction reaction?
a double replacement reaction
a neutralization reaction
a reaction in which oxidation numbers change
a reaction in which no electrons are transferred
Answer:
a reaction in which oxidation numbers change
Explanation:
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when many excess hydrogen ions accumulate in the blood, what happens to serum ph? the ph:
When many excess hydrogen ions accumulate in the blood, the serum pH decreases, leading to a more acidic blood environment.
What happens when Serum pH decreases?When excess hydrogen ions (H+) accumulate in the blood, it causes an increase in H+ concentration leads to a more acidic environment. Serum pH is a measure of the acidity or alkalinity of blood. As H+ concentration increases, the serum pH value decreases. A decrease in serum pH indicates a more acidic blood condition.
This condition is known as acidosis. The body has mechanisms to regulate pH levels and prevent acidosis, such as the release of bicarbonate ions and the removal of excess hydrogen ions through the kidneys. However, if acidosis persists, it can lead to serious health complications.
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Calculate the number of moles of 2.00g of K2SO4
A demand o2 delivery system utilizes a _________________ to trigger o2 flow.
A demand O2 delivery system utilizes a "pressure drop" mechanism to trigger oxygen flow.
In a demand oxygen delivery system, the flow of oxygen is triggered by a pressure drop that occurs when the user initiates inhalation. When the user takes a breath, the drop in pressure in the system activates the mechanism that releases oxygen.
This mechanism can be a valve or regulator that opens to allow oxygen to flow from the source to the user.
The pressure drop required to trigger the oxygen flow depends on the specific design of the system and can vary. Generally, the pressure drop is set at a level that ensures the user's inhalation effort is sufficient to activate the oxygen flow while maintaining a safe and reliable operation.
The pressure drop is typically calibrated and adjusted during the manufacturing process to meet the desired specifications and requirements of the system.
In summary, a demand oxygen delivery system relies on a pressure drop mechanism to initiate the flow of oxygen. This mechanism ensures that oxygen is released when the user inhales, providing them with the required oxygen supply.
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