Which of the following compounds is formed by covalent bonding?
A. Na s
B. AICI
C. CHI
D. Lici
• What other way can be used to determine this besides using the END?

Answer:

The system can operate on a set level of parts per million (ppm) chlorine, where the set level is automatically maintained.

Answer:

motion

Explanation:

At absolute zero temperature, particles are expected to have no kinetic energy, and hence no motion.

The percent composition of oxygen in tripotassium phosphate is 30.15%.

Percent composition  is defined as a convenient way to record concentration of solution.It is a expression which relates mass of an element  to compound as,mass of element/mass of compound ×100.

In the given compound of tripotassium phosphate the molar mass is 212.27 g/mole, while that of oxygen is 16×4=64 g/mole.Thus, the percent composition of oxygen in tripotassium phosphate is 64/212.27×100=30.15%.

Thus, the percent composition of oxygen in tripotassium phosphate is 30.15%.

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Answer:

Dissolved minerals in the ground water precipitate (crystallize) from water in the pore spaces forming mineral crusts on the sedimentary grains, gradually cementing the sediments, thus forming a rock

Explanation:

We learned that k is adsorbed to negatively charged soil colloids by electrostatic attraction to three types of exchange sites or binding positions. The cation exchange sites are the most readily available to the soil solution.

The binding position that is readily available to the soil solution is the cation exchange sites. This is because the negatively charged soil colloids attract positively charged ions, known as cations, through electrostatic attraction. These cations are then exchanged with other cations in the soil solution, leading to the term "cation exchange sites."

The other two types of exchange sites are the anion exchange sites, which attract negatively charged ions, known as anions, and the inner sphere binding sites, which involve a direct bond between the metal ion and the soil colloid surface. However, the cation exchange sites are the most readily available to the soil solution.

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Answer:

1.B

2.C

Explanation:

Cell structure is represented by B is the ribosome.

The nucleus contains molecules of C, which store hereditary information.

Cells are the basic building blocks of all living things. The human body is composed of trillions of cells.

In a eukaryotic cell, ribosomes present in the cytoplasm synthesize proteins, which are required by the cell and the ribosomes present on the rough endoplasmic reticulum, synthesize secretory proteins.

Most of the enzymes are protein molecules and are synthesized on the ribosomes and the nucleus is contained with DNA that stores the hereditary information.

Hence, option B is correct for question 1 and option C is correct for question 2.

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Answer:

133.85 K

Explanation:

Initial pressure, P₁ = 635 torr

Initial temperature, T₁ = 67.0°C = 340 K

Final pressure, P₂ = 250 torr

We need to find the new temperature. The relation between temperature and pressure is given by :

\(\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\\T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{250\times 340}{635}\\\\T_2=133.85\ K\)

So, the new temperature is equal to 133.85 K.

By subjecting the two compounds to Jones reagent, you can observe the difference in their reactivity and determine the compound that undergoes oxidation (4-methyl-3-penten-1-ol) and the one that does not (1-methoxy-3-methyl-2-butene).

To distinguish between 1-methoxy-3-methyl-2-butene and 4-methyl-3-penten-1-ol, you can use an oxidizing agent that can react selectively with the alcohol group present in 4-methyl-3-penten-1-ol.

One suitable reagent for this purpose is Jones reagent (a mixture of chromic acid and sulfuric acid). Jones reagent is a strong oxidizing agent that can convert alcohols to their corresponding carbonyl compounds (aldehydes or ketones).

Here's what would happen with each compound:

Methoxy-3-methyl-2-butene does not have an alcohol group, so it would not react with Jones reagent.

4-Methyl-3-penten-1-ol has an alcohol group, and it can be oxidized by Jones reagent to form the corresponding aldehyde or ketone. The specific product obtained would depend on the reaction conditions.

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Answer:

Oil + alcohol -> glycerin

Explanation:

hope that this is what you meant

Answer: 15.56 L of oxygen gas reacts to produce 56.1 grams of magnesium oxide at STP.

Explanation:

The given chemical equation represents the reaction between magnesium (Mg) and oxygen (O2) to form magnesium oxide (MgO) with a stoichiometric ratio of 2:1 between Mg and O2. This means that for every 2 moles of Mg that reacts, 1 mole of O2 is consumed.

The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg + 16.0 g/mol for O). Therefore, the number of moles of MgO produced can be calculated as follows:

Number of moles of MgO = Mass of MgO / Molar mass of MgO

Number of moles of MgO = 56.1 g / 40.3 g/mol

Number of moles of MgO = 1.39 mol

Since the stoichiometric ratio of Mg to O2 is 2:1, we can calculate the number of moles of O2 consumed as follows:

Number of moles of O2 = (Number of moles of MgO) / 2

Number of moles of O2 = 1.39 mol / 2

Number of moles of O2 = 0.695 mol

At STP (standard temperature and pressure), one mole of any ideal gas occupies 22.4 L. Therefore, the volume of O2 consumed can be calculated as follows:

Volume of O2 consumed = Number of moles of O2 x 22.4 L/mol

Volume of O2 consumed = 0.695 mol x 22.4 L/mol

Volume of O2 consumed = 15.56 L

Therefore, 15.56 L of oxygen gas reacts to produce 56.1 grams of magnesium oxide at STP.

Answer:

Insecticides are not good for health. Their use is harmful to other animals, birds and humans. But, without their use, it is not possible to grow the required amount of food. So, "the use of insecticide is not an interest, but an obligation".

Answer:

B

Explanation:

hope it helps

To prepare a buffer solution of pH = 10.54, the relative masses of dimethyl amine and dimethyl ammonium chloride needed are 0.079 g and 0.067 g respectively.

A buffer solution is a solution that has the ability to resist changes in pH upon the addition of small amounts of acid or base. A buffer solution contains a weak acid and its conjugate base or a weak base and its conjugate acid. It can be prepared by mixing equal volumes of a weak acid and its conjugate base or a weak base and its conjugate acid.

Dimethyl amine is an organic compound with the formula (CH3)2NH. It is a weak base and can act as a proton acceptor. Dimethyl ammonium chloride is an organic compound with the formula (CH3)2NH2Cl. It is a salt of a weak base and a strong acid and can act as a proton donor.

Calculation of relative masses:

The pKa of dimethyl amine is 10.73.

To prepare a buffer solution of pH = 10.54,

the ratio of [A-]/[HA] should be 1/9.

Using the Henderson-Hasselbalch equation;

pH = pKa + log([A-]/[HA])10.54 = 10.73 + log([A-]/[HA])

log([A-]/[HA]) = -0.19[A-]/[HA] = 0.67/1.00

The sum of the masses of dimethyl amine and dimethyl ammonium chloride is 0.146 g. The ratio of their masses is 0.67:1.00.

So, the relative masses of dimethyl amine and dimethyl ammonium chloride needed are 0.079 g and 0.067 g respectively.

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Answer:

The cell theory claims these three components:

1. cell is the smallest functional unit of life: It can be observed under the microscope that cells have various type of molecules and organelles present and have adifferent functional role in the cell which explains that the cell is the smallest unit of life as its molecules or organelles can not carry the life process on their own.

2. All organisms are made up of cells: From bacteria and archaea to human and other life forms are made up of a single cell or organization of cells in a specific pattern it also can be observed by the microscopic of blood or other tissue or cell of an organism.

3. Arise from pre-existing cell: The cells are can be studied under a microscope during cell division where we can observe that new cells come from the pre existing cell by the cell division.

Answer:

it's the last one.

Explanation:

a compound reaction that occurs when one element within a compound is exchanged with another element.

The volume of 0.524 M RbOH(aq) to reach the half equivalence point in the titration of 20.85 ml of 0.348 M acetic acid(aq) is 6.92 ml.

\(M_1\) = initial concentration = 0.348 M

\(M_2\) = concentration after diluting = 0.524 M

\(v_1\) = initial volume = 20.85 ml

Half equivalence point it means the equivalence point divided by two. The volume of the equivalence point can be calculated using laws of dilution. So,

\(M_1v_1\) = \(M_2v_2\)

\(v_2\) = \(\frac{M_1v_1}{M_2}\)

= (0.348*20.85)/0.524

= 13.85 ml

Since we want to calculate the half of equivalence so,

= 13.85 / 2

= 6.92 ml

Thus, the volume in ml needed to reach the half equivalence is 6.92 ml.

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Answer:

C. 101.2 L

Explanation:

N2 + H2= NH3

Balancing it,

N2 + 3 H2 = 2.NH3

(1 mol) (3 mol) (2 mol)

which means

1 molecule of nitrogen reacts with 3 molecule of hydrogen to form ammonia.

Likewise,

50.6 l of nitrogen reacts with 50.6 × 3= 151.8 l of hydrogrn to form 50.6 × 2= 101.2 l of ammonia.

The strongest interparticle force present in the  sample of H₃PO₄ is the correct is  e. ion―dipole forces.

The intermolecular force of the attraction is the molecule H₃PO₄ that is phosphoric acid is the ion - dipole forces. The ion - dipole force is  the attractive force that will results from the electrostatic attraction in  between the ion and the neutral molecule that will have the dipole. The intermolecular force of attraction is the attractive and the repulsive forces that will arise in between the molecules of the substance.

Thus, the  H₃PO₄ that is phosphoric acid sample has the strongest ion - dipole forces of intermolecular attraction.

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The half life of 2n-71 is 2.4 minutes. if we started with 50g at the beginning, approximately 0.781 g grams would be left after 12 minutes.

Given that the half-life of N-71 is 2.4 minutes. Hence, T₁/₂=2.4 minutes.

Initial mass of N-71 is 50 g.

We need to find out the mass of N-71 left after 12 minutes. We know that half-life is the time required to reduce the initial quantity to half of its value.

Therefore, we can use the following formula: M(t) = Mo (1/2)^{(t/T1/2)}

Where, M(t) is the mass of the isotope at time 't'.

Mo is the initial mass of the isotope.

T₁/₂ is the half-life of the isotope.

t is the time at which the isotope mass is measured.

Substituting the given values in the above formula, we get:

M(12) = 50 (1/2)^{(12/2.4)}

= 50 (1/2)^{(5)}

= 50/32

= 1.5625 g.

Therefore, the number of grams left after 12 minutes would be approximately 0.781 g.

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Answer:

Inorganic compounds — simple molecules that usually consist of one or two different elements ; for example:

Water (H2O)

Carbon dioxide (CO2)

Bimolecular oxygen (O2)

Sodium chloride (NaCl)

Answer:

water (H2O)

Explanation:

water is the example of inorganic compound

A. The electronic configuration for the isotope we want is as follows:

\(1s^2 2s^2 2p^6 3s^2 3p^6\).

B. The element belongs to period 3 and group 18.

C.The last electron's four quantum numbers are:

m_s = +1/2 or -1/2 (since the electron can spin up or spin down)

D. With fluorine, the element will develop an ionic connection.

The positioning of electrons within an atom, molecule, or other physical structure, such as a crystal, is referred to as electronic configuration. It is typically represented by an array of numbers, letters, or superscripts that denote the number of electrons in each atom or molecule's shell or subshell.

Let the first isotope's mass number be x, the second isotope's mass number be y, and the third isotope's mass number be z. Also, let the first isotope's neutron number be a, the second isotope's neutron number be b, and the third isotope's neutron number be c. Using the information provided, we can construct two equations:

126 = x + y + z (equation 1)

a+b+c=60 (equation 2)

Because all three isotopes contain the same amount of protons, we can infer that their electrical configurations are the same. As a result, all that remains is to determine the electrical structure of one of the isotopes.

We can use the fact that the total of the mass numbers is equal to the amount of protons plus the number of neutrons. Let m be the isotope's mass number and z be the number of protons (the atomic number). Then:

m = z + n, where n is the number of neutrons.

The electrical arrangement of an element can also be used to calculate the atomic number. Assume if the isotope we're seeking for is a periodic table element. The element's electrical configuration can be written as:

\(1s^2 2s^2 2p^6 3s^2 3p^6\)

The configuration's last electron is in the (n+1)s or (n+1)p orbital. As a result, we may calculate the atomic number by counting the number of electrons in the arrangement. For example, the atomic number for the aforementioned electrical configuration is 18 (2 + 8 + 8).

Let's look for the electrical configuration of the isotope we're after. Because the element's electrical configuration is not specified, we can presume it is a noble gas. As an example, consider argon (Ar), which has the electrical configuration:

\(1s^2 2s^2 2p^6 3s^2 3p^6\)

Because argon belongs to period 3 and group 18 (also known as group 8A), the isotope we seek belongs to period 3 and group 18. This is due to the fact that atoms in the same class have the same amount of valence electrons and chemical characteristics.

As a result, the electrical configuration of the isotope we seek is:

\(1s^2 2s^2 2p^6 3s^2 3p^6\)

b) The element belongs to period 3 and group 18.

c) The last electron's four quantum numbers are:

Because the electron is in the 3p orbital, n = 3 l = 1.

Because there are three 3p orbitals, m_l = -1, 0, or 1.

m_s = +1/2 or -1/2 (since the electron can spin up or spin down)

d) With fluorine, the element will develop an ionic connection. Because the element belongs to group 18, it has 8 valence electrons, making it a stable noble gas configuration. It may gain one electron to make a 1- ion or lose eight electrons to form an 8+ ion to obtain this state. Fluorine has seven valence electrons and can gain one electron to produce.

Therefore, the electronic configuration for the isotope we want is as follows:

\(1s^2 2s^2 2p^6 3s^2 3p^6\)

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Your question is in Spanish, but the English translation of the question is:

The sum of the mass numbers of three isotopes is 126 and the sum of the neutron numbers is 60. Find the electronic configuration of one of the isotopes if its electric charge is

1- b) Determine group and period for said element.

c) Determine the four quantum numbers for the last electron.

d) If the element they found joins with the fluorine element, what type of bond will it form?

Answer:

Natural selection says that either they evolve differently and increase their biodiversity or they die. Both wouldn't have enough food to survive so animals with those traits would become less and less common. ... Natural Selection can also decrease the biodiversity.

Answer: Increase their biodiversity or they die

Explanation:

Both wouldn't have enough food to survive so animals with those traits would become less and less common. ... Natural Selection can also decrease the biodiversity.

Answer:

You can block me I don't care ;-; Ive actually been wanting to be blocked because I don't want my account on brainly anymore but they cant understand that I used my school email for this account and my school email doesnt reseave emails not from the school and I cant change the email to a different one so I cant reset my password so I cant delete my account..

Explanation:

An Earth-like exoplanet with active volcanoes and no oceans would have a different atmosphere than that of Earth's. In such a planet, gases like hydrogen and helium will not be as dominant as they are in our solar system.

Rather, the dominant gas in an Earth-like exoplanet's atmosphere with active volcanoes and no oceans would be carbon dioxide. Active volcanoes are a source of carbon dioxide and other greenhouse gases. Therefore, the carbon dioxide that the volcanoes would produce would build up in the planet's atmosphere, increasing its concentration in the atmosphere.

This increase in concentration of carbon dioxide would cause the planet's temperature to rise, making it hotter than Earth. Additionally, the high concentration of carbon dioxide would make the planet's atmosphere denser, resulting in a stronger greenhouse effect. As a result, the planet's surface would be warmer than Earth's.

Therefore, an Earth-like exoplanet with active volcanoes and no oceans would have a carbon dioxide-dominated atmosphere.

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Considering the Boyle's law, if the volume increases to 50 L, the new pressure is 0.4 atm.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: If the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Mathematically, Boyle's law states that if the amount of gas and the temperature remain constant, the product of the pressure and the volume always has the same value:

P× V= k

where

Considering an initial state 1 and a final state 2, it is fulfilled:

P₁× V₁= P₂× V₂

In this case, you know:

Replacing in Boyle's law:

2 atm× 10 L= P₂× 50 L

Solving:

(2 atm× 10 L)÷ 50 L= P₂

0.4 atm= P₂

Finally, the new pressure is 0.4 atm.

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Answer:

Ocean tides are caused by the gravitational pull of the moon and the sun. The moon has the greatest effect on the tides. When the Sun, moon, and earth are in a straight line, we have Neap tides. When the Sun, moon, and earth are at right angles we have spring tides. Spring tides are especially high tides while neap tides are especially low tides.

Explanation:

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