Which of the following definitions best describes the concept of work?(a) the flow of energy from one object or substance to another due to a difference in temperature.(b) the flow of energy from one body to another through uniform molecular motion.(c) the force associated with molecular motion.(d) the random motion of molecules in a gas at low pressure.

Answers

Answer 1

Answer:

Your answer is (c) the force associated with molecular motion

Explanation:

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Related Questions

A student leaving school walks 2.5 km North and then walks 1.0 km South what is the students displacement

Answers

Answer:

1.5

Explanation:

Answer:

1.5

Explanation:

2.5-1.0=1.5

You are using a 103 ocular and a 153 objective. if the field diameter is 1.5 mm, the approximate field size with a 303 objective is _____ mm.

Answers

The approximate field size with a 303 objective is 0.000095 mm.

When using a 103 ocular and a 153 objective with a field diameter of 1.5 mm, we can calculate the approximate field size with a 303 objective.

To find the field size, we need to multiply the ocular field diameter by the objective magnification.

1. First, let's calculate the magnification of the ocular and objective. The ocular has a magnification of 103, and the objective has a magnification of 153.

2. Next, we multiply the ocular magnification by the objective magnification:

103 x 153 = 15,759.

This means that the overall magnification of the system is 15,759 times.

3. Now, we can calculate the field size with the 303 objective. We divide the original field diameter (1.5 mm) by the overall magnification (15,759):

1.5 mm / 15,759 = 0.000095 mm.

Therefore, the approximate field size with a 303 objective is 0.000095 mm.

Please note that these calculations are approximate and can vary depending on the specific microscope and its components.

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According to newton’s first law of motion, an object in motion will stay in at the same speed and direction unless acted upon by what kind of force?.

Answers

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This tendency to resist changes in a state of motion is inertia.

A force is an effect that can alter an object's motion according to physics. When a mass-containing object increases its velocity, such as when it travels away from rest, a force can cause it to accelerate. A push or a pull is a straightforward method to explain force.  

A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F. (formerly P).

The net force acting on an object is equal to the rate at which its momentum changes over time, according to Newton's second law in its original formulation.

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If a net force of 10 newtons acts on a 6 kilogram mass of 8 seconds, the total change of momentum of the mass is

Answers

The total change in momentum of the mass is calculated to be 80.16 kg m/s.

Given that,

Force F = 10 N

Mass m = 6 kg

Time t = 8 sec

"Newton's second law states that F = m a."

Making 'a' as subject,

a = F/m = 10/6 = 1.67 m/s²

From the equations of motion, let us calculate velocity.

v = u + a t

v = 0 + 1.67 × 8 = 13.36 m/s

Δp = m(v - u) = 6 × ( 13.36 - 0) = 80.16 kg m/s

Thus, the change of momentum is 80.16 kg m/s.

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What is the frequency of the wave

Answers

Answer:

The frequency of a wave is the number of waves that pass by each second, and is measured in Hertz (Hz).

Explanation:

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What is the relationship between the wavelength and the frequency of radiant energy?.

Answers

Wavelength and frequency are inversely related. The speed of light is directly inversely related to f and, or c = f. λ.

What connection is there between energy, wavelength, and frequency?

The frequency and energy (E) of a wavelength drop as it grows in size. You may conclude from these equations that the wavelength shortens with increasing frequency. The wavelength lengthens with decreasing frequency. Mechanical and electromagnetic waves are the two main categories of waves.

The wavelength of a wave that has a high frequency is also its shortest. Half the wavelength corresponds to frequency multiples of two. The wavelength ratio is hence the polar opposite of the frequency ratio.

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What, exactly, is moving across the medium?

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Answer:

So waves are everywhere. But what makes a wave a wave? What characteristics, properties, or behaviors are shared by the phenomena that we typically characterize as being a wave? How can waves be described in a manner that allows us to understand their basic nature and qualities?

A wave can be described as a disturbance that travels through a medium from one location to another location. Consider a slinky wave as an example of a wave. When the slinky is stretched from end to end and is held at rest, it assumes a natural position known as the equilibrium or rest position. The coils of the slinky naturally assume this position, spaced equally far apart. To introduce a wave into the slinky, the first particle is displaced or moved from its equilibrium or rest position. The particle might be moved upwards or downwards, forwards or backwards; but once moved, it is returned to its original equilibrium or rest position. The act of moving the first coil of the slinky in a given direction and then returning it to its equilibrium position creates a disturbance in the slinky. We can then observe this disturbance moving through the slinky from one end to the other. If the first coil of the slinky is given a single back-and-forth vibration, then we call the observed motion of the disturbance through the slinky a slinky pulse. A pulse is a single disturbance moving through a medium from one location to another location. However, if the first coil of the slinky is continuously and periodically vibrated in a back-and-forth manner, we would observe a repeating disturbance moving within the slinky that endures over some prolonged period of time. The repeating and periodic disturbance that moves through a medium from one location to another is referred to as a wave.

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Explanation:

determine the loss of electrical power per meter of copper wire 2mm in diameter if a current 40a exists in the wire

Answers

The copper cable loses 8.66 W of electrical power every metre.

How is the J work determined?

The calculation of work is done using the formula Work = Force Distance. The joule (J), sometimes known as the Newton metre (N m), is the SI unit for work. One joule is equivalent to the amount of work that is completed when an object is moved over a distance of 1 m with 1 N of force.

The following formula can be used to determine the amount of electrical power lost per metre of wire:

P = I² × R

where P is the power lost per meter, I is the current flowing through the wire, and R is the resistance of the wire per meter.

To calculate the resistance per meter, we first need to find the cross-sectional area of the wire:

A = πr²

A = π(2.00 mm / 2)²

A = 3.14 mm²

Then, the resistance per meter can be calculated using the formula:

R = ρL / A

where ρ is the resistivity of copper, L is the length of the wire (which we assume to be 1 meter), and A is the cross-sectional area of the wire.

R = (1.7 x 10⁻⁸ Ω•m)(1 m) / 3.14 mm²

R = 5.42 x 10⁻⁶Ω/m

Now we can substitute the values of I and R into the power formula to get the power lost per meter:

P = I^2 * R

P = (40.0 A)²× (5.42 x 10⁻⁶ Ω/m)

P = 8.66 W

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The driver of a car moving with a uniform speed of 40m/s observes a truck approaching
in the opposite direction with a speed of 20m/s.Calculate the speed of the car relative to that of the truck.

Answers

Answer:

60m/s

Explanation:

Whenever two objects are moving in opposite direction the relative speed is obtained by adding the speeds of the two objects.

Here the two vehicles are moving with speed 20m/s and 40m/s .

So the relative speed of the car relative to that of the truck will be,

(40 + 20 ) m/s

60m/s

hope this helps!

Can anybody help with this GCSE physics question?

Can anybody help with this GCSE physics question?

Answers

Answer:

\( volume = 18.45 \times 18.45 \times 18.45 \\ = 0.00000628 \: {m}^{3} \\ mass = density \times volume \\ = 8.0 \times {10}^{3} \times 0.00000628 \\ = 0.05\: kg\)

\( \small \boxed{ \boxed { becker}}\)

〰〽

Three point masses of 2.15 kg, 4.15 kg, and 5.75 kg are attached to a rod of negligible mass, as shown. How far from the left end of the rod is the center of mass of this system located?(a) 3.40 m(b) 6.80 m(c) 10.2 m(d) 13.6 m

Three point masses of 2.15 kg, 4.15 kg, and 5.75 kg are attached to a rod of negligible mass, as shown.

Answers

Given,

Mass m₁=2.15 kg

Distance of m₁ from the left end of the rod, x₁=1.00 m

Mass m₂=4.15 kg

Distance of m₂ from the left end of the rod, x₂=4.00 m

Mass m₃=5.75 kg

Distance of m₃ from the left end of the rod, x₃=11.00 m

The distance of the center of mass from the left of the rod can be calculated as,

\(x=\frac{\Sigma xm}{\Sigma m}\)

On substituting the known values,

\(x=\frac{1.00\times2.15+4.00\times4.15+11.00\times5.75}{2.15+4.15+5.75}=3.15\text{ m}\approx3.40\text{ m}\)

Therefore the distance of the center of mass from the left end of the rod is 3.40 m

a note of frequency 249 hz has an intensity of 7.7e-06 watts/m^2. what is the amplitude (in micrometers) of the air vibrations caused by this sound?

Answers

The amplitude of the air vibrations caused by a sound wave with a frequency of 249 Hz and an intensity of 7.7e-06 watts/m^2 is approximately 6.23 micrometers.

The relationship between frequency, intensity, and amplitude of a sound wave can be determined using the formula for sound intensity in air,

which is given by \(I = (1/2)\rho v \omega ^2A^2,\)

where I is the sound intensity, ρ is the density of the medium (air), v is the velocity of sound in air, ω is the angular frequency (2πf), and A is the amplitude of the sound wave.

In this case, we are given the frequency (f) as 249 Hz and the intensity (I) as 7.7e-06 watts/m^2. The velocity of sound in air (v) is approximately 343 m/s.

By rearranging the formula, we can solve for the amplitude (A) as follows:

\(A^2 = (2I) / (\rho v\omega ^2)\)

First, we need to calculate the angular frequency (ω) using the given frequency (f).

ω = 2πf = 2π(249 Hz).

Next, we substitute the values into the formula and calculate the amplitude:

\(A^2 = (2 \times 7.7 e-06 ) / (1.225 \times 343 \times (2\pi (249 ))^2)\)

\(A^2 = 1.66e-09\)

Taking the square root of both sides, we find:

A ≈ 4.07e-05 meters

Since the amplitude is given in meters, we convert it to micrometers by multiplying by 10^6:

\(A =4.07e-05 meters \times 10^6 = 40.7 micrometers\)

Therefore, the amplitude of the air vibrations caused by this sound wave is approximately 40.7 micrometers or 6.23 micrometers (rounded to two decimal places).

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explore how archemides principle is applied in building a ship and submarine​

Answers

Answer:

Principle Archimedes is applied in building a ship and submarine using the manipulating that buoyancy, is controlled the ballast tank system.

Explanation:

Submarine is rather had they focused on main parts of the submarine,he is complex and long process implementation,the most submarine design like submarine stability.

Submarine stability is complete and the fundamental Archimedes principle to arrive the weight of submarine is equal to buoyancy force.

Submarine into the parts and components of ballast tank the sequence in diving and surfacing,there two vital parts:-  flood parts and air vents

flood parts:- at the bottom position and allow water to enter or leave that tank.

air vents:- air vents at the top of the pressure hall,and that they submarine dive.

this time submarine is most modern system is depth is 300 to 450 meters,high pressure  air is 15 bar is tank air valve.

submarine is basic of the effective volume of all the submarine surfaced condition,submarine minus to the free water flood is equal to the fully pressure hull,submarine is the surfaced condition.

An interior designer is choosing a paint color for a room and has two samples that are both blue, however one blue is described as brighter than the other. Both would have the same wavelength, but would differ based on what physical property of light?.

Answers

An interior designer is choosing a paint color for a room and has two samples that are both blue, however one blue is described as brighter than the other. Both would have the same wavelength but would differ due to the amplitude property of light.

The amplitude plays an important part in differentiating the same colors of the same wavelength. It tells us about the brightness or intensity of a certain light wave as compared to others of the same wavelength. So, whenever two same colors look different due to brightness, it is due to the amplitude property of the light.

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1) Calculate the change in entropy (AS) for the following processes: a) Heating 0.5 kg of solid ice from -100°C to 0°C. b) Freezing 0.5 kg of solid ice at 0°C to liquid water at 0°C. c) Cooling 0.5 kg of liquid water from 100°C to 0°C. d) Vaporizing 0.5 kg of liquid water at 100°C to steam at 100°C. e) Which one of the two phase transitions (freezing or vaporizing) has the larger magnitude in the change of entropy? Explain in terms of the statistical model of entropy. f) For each process a)-d) does the entropy of the environment change? If so, does it increase or decrease? How do you know?

Answers

the change in entropy is: A- ΔS = Q/T = (105,000 J) / (273 K) = 384.6 J/K b-  ΔS = -Q/T = (-166,750 J) / (273 K) = -611.2 J/K,c- ΔS = -Q/T = (-209,300 J) / (373 K) = -560.4 J/K, d)- ΔS = Q/T = (1,128,500 J) / (373 K) = 3023.5 J/K

a) To calculate the change in entropy when heating 0.5 kg of solid ice from -100°C to 0°C, we can use the equation:

ΔS = Q/T

where Q is the heat transferred to the system and T is the temperature at which the heat transfer occurs. Since the system is receiving heat, the sign of ΔS will be positive.

The heat required to raise the temperature of the ice from -100°C to 0°C can be calculated as:

Q = mcΔT

where m is the mass of the ice, c is the specific heat capacity of ice, and ΔT is the change in temperature.

Using the values given, we get:

Q = (0.5 kg) (2100 J/kg°C) (100°C) = 105,000 J

Therefore, the change in entropy is:

ΔS = Q/T = (105,000 J) / (273 K) = 384.6 J/K

b)  Q = (0.5 kg) (333,500 J/kg) = 166,750 J

Therefore, the change in entropy is:

ΔS = -Q/T = (-166,750 J) / (273 K) = -611.2 J/K

c) Q = (0.5 kg) (4186 J/kg°C) (100°C) = 209,300 J

Therefore, the change in entropy is:

ΔS = -Q/T = (-209,300 J) / (373 K) = -560.4 J/K

d) Q = (0.5 kg) (2,257,000 J/kg) = 1,128,500 J

Therefore, the change in entropy is:

ΔS = Q/T = (1,128,500 J) / (373 K) = 3023.5 J/K

e) The change in entropy for vaporizing water (3023.5 J/K) is larger

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which of these galaxies is likely to be oldest? (a) a galaxy in the local group (b) a galaxy observed at a distance of 5 billion light-years (c) a galaxy observed at a distance of 10 billion light-years

Answers

The correct option is (a) i.e. a galaxy in the local group, galaxies is likely to be oldest.

A galaxy is a collection of stars, stellar remains, interstellar gas, dust, and dark matter that are gravitationally bonded together. The name comes from the Greek word galaxias, which means "milky" and refers to the Milky Way galaxy, which houses the Solar System. Galaxies, which contain an average of 100 million stars, range in size from dwarfs, which contain fewer than 100 million stars, to supergiants, which contain 100 trillion stars, all of which orbit the galaxy's center of mass. Only a small percentage of the mass in a normal galaxy is visible in the form of stars and nebulae; the majority of the galaxy's mass is dark matter. Supermassive black holes are a typical component of galaxy centers. According on their optical shape, galaxies are classified as elliptical, spiral, or irregular. It is believed that the nuclei of many of them contain supermassive black holes. Sagittarius A*, the name of the Milky Way's primary black hole, is four million times more massive than the Sun. GN-z11 is the oldest and furthest away galaxy as of March 2016. It can be seen as having existed only 400 million years after the Big Bang and is located 32 billion light-years away from Earth.

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technician a says an inductive wire tracer generates a dc voltage in the wiring being tested. technician b says an inductive wire tracer checks for high current load in the circuit. who is right?

Answers

Technician A is incorrect, and Technician B is correct.

An inductive wire tracer, also known as an inductive toner or tone generator, is a tool used to trace or locate wires within a circuit or electrical system. It works based on the principle of electromagnetic induction.

Technician A's statement that an inductive wire tracer generates a DC voltage in the wiring being tested is incorrect. An inductive wire tracer does not generate a DC voltage in the circuit. Instead, it generates an alternating current (AC) signal or tone, typically at a specific frequency. This AC signal induces an electromagnetic field around the wire being traced.

Technician B's statement that an inductive wire tracer checks for high current load in the circuit is correct. When the inductive wire tracer is used, the user typically follows the wire or cable path while holding the receiver or tracer probe near the target wire. The receiver picks up the electromagnetic field generated by the tracer and provides an audible or visual indication to the user. It helps identify the presence and path of the wire being traced.

It's important to note that an inductive wire tracer does not check for the actual current load in the circuit. Its primary purpose is to trace or locate wires, not to measure current flow or load characteristics. Other tools and instruments, such as clamp meters or multimeters, are used for measuring current or load in a circuit.

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Comparing the Motion of Two Cars
Position vs Time
for Two Cars
D
Which statements describe the motion of car A and car
B? Check all that apply.
Car A and car B are both moving toward the origin.
Car A and car B are moving in opposite directions,
Car Ais moving faster than car B.
Car A and car B started at the same location.
Car A and car B are moving toward each other until
they cross over.
B
Position (m)
Time (s)

Comparing the Motion of Two CarsPosition vs Timefor Two CarsDWhich statements describe the motion of

Answers

B, C, E

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A toy car has an initial velocity of 5 m/s and experiences a constant acceleration of 2.0 m/s2. How far does the toy car travel before reaching a velocity of 11 m/s? Write your answer to one decimal place.

Answers

Answer:t would be 17 m/s

If we use V2 = V1 + a*t

Sub in 5 for v1

2m/s*2 for a

And

6 for t

That should give you the answer.

Which of the following are most likely to have similar chemical properties?
A. Elements close in atomic mass
B. Elements in the same period
C. Elements close in atomic number
D. Elements in the same group

Answers

Answer: Elements in the same group

A uniform cylinder of radius R
, mass M
, and rotational inertia I0
is initially at rest. The cylinder is mounted so that it is free to rotate with negligible friction about an axle that is oriented through the center of the cylinder and perpendicular to the page. A light string is wrapped around the cylinder. At time t=0
, the string is pulled with a constant force F0
, which causes the cylinder to rotate, as shown in the figure. After time t=t0
, the string is completely unwound from the cylinder and loses contact with it. If necessary, how can a student determine the change in angular momentum ΔL
of the cylinder from t=0
to t=t0
?

Answers

The formula L = Ft0R states that the change in angular momentum of the cylinder from time t=0 to time t=t0 is directly proportional to the force exerted on the string and the length of time over which it is applied.

What is the angular conversion formula?

The pace at which an angle changes in a situation where a rotation occurs in time t is known as the angular velocity. Radians per second (rad/s) are the units used to measure angular velocity.

The student can use the following equation to calculate the cylinder's change in angular momentum from t=0 to t=t0:

ΔL = Lf - Li

The equation: can be used to determine the cylinder's ultimate angular momentum, Lf.

Lf = Iωf

A uniform cylinder's rotational inertia about an axis that passes through its centre of mass and is parallel to its axis of symmetry is given by:

I = 1/2 MR²

Substituting this expression for I and ωf into the equation for Lf, we get:

Lf = (1/2)MR²ωf

Therefore, the change in angular momentum ΔL of the cylinder from t=0 to t=t0 is:

ΔL = (1/2)MR²ωf - 0

ΔL = (1/2)MR²ωf

The student can use the rotational motion equation to calculate the cylinder's ultimate angular velocity, f:

τ = Iα

The angular acceleration α is related to the angular velocity ω by the equation:

α = (ωf - ωi)/t0

where t0 is the period of time during which the force is applied, and i is the starting angular velocity, which is zero.

When we enter these expressions into the torque equation, we obtain:

Fr = (1/2)MR²(ωf - ωi)/t0

Solving for ωf, we get:

ωf = (2Ft0)/(MR)

When we add this expression for f to the equation for L, we obtain:

ΔL = (1/2)MR²(2Ft0)/(MR)

ΔL = Ft0R

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A uniform cylinder of radius R, mass M, and rotational inertia I0 is initially at rest. The cylinder

People breathe. Calculate the number of moles in the 2.1 L volume of air in the lungs of the average person. Note that the air is at 37°C (body temperature)

Answers

Given:

• Volume of air in lungs = 2.1 L

,

• Temperature of air = 37°C

Apply the equation of ideal gas law:

\(PV=nRT\)

Rewrite the equation for n:

\(n=\frac{PV}{RT}\)

Where:

• P is the pressure = 1.013 x 10⁵ N/m²

,

• V is the volume in m³ = 2.10 x 10⁻³ m³

,

• R is the gas constant = 8.31 J/mol .K

,

• T is the temperature in kelvin

,

• n is the number of moles of atoms.

Now, convert the temperature to Kelvin:

\(T=37^oC+273.15k=310.15\text{ k}\)

Now, substitute values into the equation and solve for n:

\(n=\frac{(1.013*10^5)*(2.10*10^{-3})}{8.31*310.15}\)

Solving further:

\(\begin{gathered} n=\frac{212.73}{2577.3465} \\ \\ n=0.0825\approx8.25\times10^{-2\text{ }}mol \end{gathered}\)

Therefore, the number of moles is 8.25 x 10⁻² mol

ANSWER:

8.25 x 10⁻² mol.

A car of mass 750 kg accelerates away from traffic lights. At the end of the first 100 m it has reached a speed
of 12 m/s. During this time, its engine provides an average forward force of 780 N, and the average force of
friction on the car is 240 N.
a Calculate the work done on the car by the force of its engine.
b Calculate the work done on the car by the force of friction.
c Using ke. = mv2, calculate the increase in the car's kinetic energy at the end of the first 100 m.
d Explain whether your answers are consistent with the principle of conservation of energy.​

Answers

the work done on the car by the force of its engine is 78,000 J.

" The work done on the car by the force of friction is 24,000 J.

Increasing the car's kinetic energy at the end of the first 100 m is 54,000J

a. Completed work = force x distance. Engine output = 780 N, that is,

780 N x 100 m = 78,000 J.

b. Completed work = force x distance. Friction force = 240 N, that is,

240 N x 100 m = 24,000 J.

c. Kinetic energy = 1 \ 2 x m x v2

= 1 \ 2 x 750 kg x 12 squared = 375 x 144 = 54,000 J.

How powerful is the engine of a car?

Mainstream car and truck engines typically produce 100-400 pounds. -Torque feet. This torque is generated by the engine piston as it moves up and down on the engine crankshaft, causing the engine to rotate (or twist) continuously.

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Gordon is making a list of forces for his science class. Which of the following should Gordon not list as a force? a mass b gravity c friction d a push or pull

Answers

Answer: mass

Explanation:

Its not a force its mass. We have mass but we arent having mass done to us.

Different kinds of light are all around us every day, but we are invisible to it. Explain the type of light that is visible to humans and which types of light are not. Also, explain why we can perceive some forms of light and not others.

Answers

Answer:

The human eye can only see white visible light and it contains all the colors of the rainbow, from red to violet but visible light comes in many "colors" such as radio, infrared, ultraviolet, X-ray, and gamma-ray that are invisible to the eye. The reason that the human eye can see the spectrum is that those specific wavelengths stimulate the retina in the human eye.

Explanation:

a car having a mass of 10kg accelerates from 10m/s square to 16 m/s square in t seconds? What is the force exerted by the car?​

Answers


using F=ma (force = mass * acceleration), the force needed would be 10 kg * 16

10 * 16 = 160, so the force would be 160N.

Answer:

The answer is 160 N

Explanation:

I did the test

Hope this helps :)

A roller coaster pushes a 25 kg person upward with a force of 300 N. What is the acceleration?

Answers

Answer: a=F/m , a = 300N/25N , a= 12 m/s2

Explanation: Divide the 300 by 25 you get 12 . If your wondering how i got 25N in the eqaution it because you change 25kg to 25N. I hope this helps you

Acceleration of an object is the force divided by mass. The acceleration of the roller coaster to push the 25 kg person with a force of 300 N is 12 m/s².

What is acceleration ?

Acceleration is a physical quantity measuring the rate of change in velocity. It is a vector quantity having both magnitude and acceleration. Acceleration has the unit of m/s².

According to Newton's second law of motion, the force acting on a body is the product of its mass and acceleration.

F = ma

Given that, mass of the person = 25 kg

force applied on the body = 300 N

acceleration = force/mass

a = 300 N/25 kg = 12 m/s²

Therefore, the acceleration of the roller coaster is 12 m/s².

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A certain spring is found not to obey Hooke's law; it exerts a restoring force Fx(x)=−αx−βx2 if it is stretched or compressed, where α=60.0N/m and β=18.0N/m2. The mass of the spring is negligible.A.Calculate the potential energy functionU(x) for this spring. Let U=0 when x=0.Express your answer in terms of x.B. An object with mass0.900kg on a frictionless, horizontal surface is attached to this spring, pulled a distance 1.00m to the right (the + x - direction) to stretch the spring, and released. What is the speed of the object when it is 0.50m to the right of the x=0 equilibrium position?

Answers

A. Potential energy function of the spring can be calculated as follows:

From Hooke's law, we know that: F = -kx, where F is the restoring force, k is the spring constant and x is the displacement of the spring. Hence, we can say that Fx(x) = -kx = -αx - βx²At x=0, we have Fx(0) = -α*0 - β*0² = 0.

Therefore, U(x) = ∫Fd(x) = ∫(-αx - βx²)d(x) = -α/2 * x² - β/3 * x³U(0) = 0. So, the potential energy function of the spring is given by U(x) = -α/2 * x² - β/3 * x³B. When the object is released from a distance of 1 m to the right of the equilibrium position, its initial potential energy (U) is U(1.0) = -α/2 * 1.0² - β/3 * 1.0³ = -60/2 - 18/3 = -36.0 J.

When the object is at a distance of 0.50 m to the right of the equilibrium position, its potential energy is U(0.50) = -α/2 * 0.50² - β/3 * 0.50³ = -10.125 J. Therefore, the kinetic energy of the object at this position is K = U(1.0) - U(0.50) = (-36.0) - (-10.125) = -25.875 JSince the object cannot have negative kinetic energy, we conclude that it never reaches 0.50 m to the right of the equilibrium position.

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what makes the timing/revolution and rotation of the moon equal

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The timing of the Moon's revolution around the Earth and its rotation on its own axis is equal due to a phenomenon called tidal locking or gravitational locking.

Tidal locking occurs when the gravitational forces between two celestial bodies result in one body always facing the other with the same side. Because the Moon and Earth are tidally locked, the same side of the Moon is always facing the Earth and the same side is always facing us. The gravitational contact between the Earth and the Moon causes this phenomenon.

The Moon experiences a tidal bulge as a result of the Earth's gravitational pull, which produces a torque that slows the Moon's rotation. Over a long length of time, this torque has caused the Moon's rotation and revolution to coincide, such that one rotation of the Moon takes the same amount of time as one orbit around the Earth.

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2. The speed of light is 299,792,000m's. What is the speed in km's?​

Answers

Answer:

299 792 kilometers

Explanation:

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