Which of the following is a solution to the function shown below?A) (0,4)B) (4,0)C) (-2,4)D) (2,-3)

Answer:

PROOF FOR THE "PROVE" SECTION:

As linear pairs, angle 2 and 3 are supplementary to each other. Angle 1 is equal to angle 2, as they are both same-side interior angles. Therefore, angle 1 and angle 3 are also supplementary.

Filling in the missing blanks:

S1. Angle 1, Angle 2, Angle 3

S2. Angle 1 and Angle 2

R3. Congruent (___)

R5. supplementary angles

S7. Angle 1 = Angle 2, so Angle 1 can be substitued in for Angle 2 in any equation, and Angle 2 can be substitued for Angle 1 in any equation as well (they can replace each other, like x=y & y=x or a=b & b=a)

Hope this helped! Have a great day (pls mark brainliest)!!

the graphing system of linear inequalities of two variables are bounded by solid line or dashed line.

The linear inequalities of two variables are the mathematical expressions denoted by greater than > or less than< or combination of ≤ or ≥ between two algebraic terms.

the way we solve linear inequalities are same as the way in how we solve linear equation. The graph of linear inequalities of two variables are bounded by solid line or dashed line depending on the unequal sign presented.

hence, there is a difference between the graph of linear equation and linear inequalities.

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Answer:

c i think

Step-by-step explanation:

Answer:

C.) x7      ;)

Step-by-step explanation:

:))))))))))))))

Answer:

The word "inverse" in the question is ambiguous, since x usually has inverses under both addition and multiplication. ... If the question is asking about the additive inverse (opposite), then the sum is always 0 for any x . So the sum takes its maximum value for any x .

Step-by-step explanation:

Answer:

Zero

Step-by-step explananation:

An inverse is the opposite of another number, so if you add them together it would equal zero.

Here are a few examples.

5+-5=0

9+-9=0

150+-150=0

-220+220=0

-476+476=0

The inverse is simply the originall number, but on the opposite side of the number line. Meaning you add or take away the negative sign, depending on the original number.

Hope I explained well:)

Answer:15

I know Bc I got it wrong that was the answer

Which table shows a proportional relationship between x and y? x 2 4 5 6 y 6 12 18 21 x 1 3 4 5 y 50 150 200 250 x 3 5 7 8 y 1.5 2.5 3 4.5 x 1 2 3 6 y 1.5 3 6 9 the graph of a proportional relationship passes through (12,16) and (1,y) find y. can someone please walk me through this?

Answer:

Hey there!

The reciprocal of a number, n, is 1/n.

Thus, the answer is n+7(1/n)

Let me know if this helps :)

Answer:

Adam payed $4.25 for 5 lbs of walnuts.  The equation for this is 5.75p-4.50

Step-by-step explanation:

The reason this is the eqaution is because 5.75 is the price per pound. "p" represents how many pounds and -4.50 is the coupon.

Answer:

hola bb cote ayudomo esta  enu

Step-by-step explanation:

Answer:

Step-by-step explanation:

B

y + X - 1 = 0 is an implicit solution to the differential equation on the interval (x, 1) and the derivative(s) of the explicit solution(s) is (cos x - X sin x)/5.

To show that y + X - 1 = 0 is an implicit solution to the differential equation on the interval (x, 1), we need to find the derivative of the implicit solution and compare it to the differential equation.

First, we will find the derivative of the implicit solution using the chain rule:

dy/dx + 1 = 0

dy/dx = -1

Next, we will compare the derivative to the differential equation:

cosx sinx = 5(x - X sinx)

-1 = 5(x - X sinx)

Solving for x, we get:

x = (1 + 5X sinx)/5

Since the derivative of the implicit solution is equal to the differential equation on the interval (x, 1), we can conclude that y + X - 1 = 0 is an implicit solution to the differential equation on the interval (x, 1).

For part (b), we will follow the same process to show that xys xy" sin x = 0 is an implicit solution to the differential equation on the interval (2, ∞).

First, we will find the derivative of the implicit solution using the chain rule:

x(dy/dx)s + ys + xy"(s-1) sin x + xys cos x = 0

Next, we will compare the derivative to the differential equation:

xys xy" sin x = 0

x(dy/dx)s + ys + xy"(s-1) sin x + xys cos x = 0

Since the derivative of the implicit solution is equal to the differential equation on the interval (2, ∞), we can conclude that xys xy" sin x = 0 is an implicit solution to the differential equation on the interval (2, ∞).

To find the derivative(s) of the explicit solution(s), we will need to use the quotient rule:

d/dx [(1 + 5X sinx)/5] = (5 cos x - 5X sin x)/(5^2)

d/dx [(1 + 5X sinx)/5] = (cos x - X sin x)/5

Therefore, the derivative(s) of the explicit solution(s) is (cos x - X sin x)/5.

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Answer:

The boys are 36, the girls 48

Answer:

9.4

Step-by-step explanation:

The distance formula is d=√((x₂-x₁)²+(y₂-y₁)²)

d=√((8-0)²+(0-5)²)

d=√((8²)+(-5²))

d=√(64+25)

d=√(89)

d=9.433981

d=9.4

Hope this helps :-)

Answer: 9.4 units

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

(a+c)^2 = t

(a+c) = sqrt t

c = sqrt(t) - a

The set corresponding to the event that exactly one of the five flips comes up heads is {htttt, thttt, tthtt, tttht, tttth}.

In a single coin flip, there are two possible outcomes: heads (H) or tails (T). Since we are flipping the coin five times, we have a total of 2^5 = 32 possible outcomes.

To form the strings of length 5 from {H, T}, we can use the following combinations where exactly one flip results in heads:

{htttt, thttt, tthtt, tttht, tttth}

Each string in this set represents a unique outcome where only one flip results in heads.

Therefore, the set corresponding to the event that exactly one of the five flips comes up heads is {htttt, thttt, tthtt, tttht, tttth}.

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Answer:

10

Step-by-step explanation:

Answer:-3

Step-by-step explanation:

The distance between the two points. (-1, 6). (2.8) is 3.61 units

The points are given as: (-1,6) and (2,8)

The distance is calculated using:

\(d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}\)

This gives

\(d = \sqrt{(-1 -2)^2 + (6 -8)^2}\)

Evaluate the sum of squares

\(d = \sqrt{13}\)

Evaluate the exponent

d = 3.61

Hence, the distance between the two points. (-1, 6). (2.8) is 3.61 units

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this is:

x g(x)

-3 8

-2 5

-1 2

0 -1

1 -4

2 -7

3 -10

then this value we locate them in the graph, each ordered pair

then we have the coordinate (-1, 2) and place it on the Cartesian plane

we have the coordinate (0, -1)

we have the coordinate (1, -4)

A two-digit number 23 is written with its place values. The digit 2 is at tens place and stands for 20 and digit 3 is at ones place and stands for 3.

A two-digit number is a two-digit number that starts with 10 and ends with 99. We  can't start from scratch. In that case, it is assumed to be a single digit. The tens digit can be any number from 1 to 9. For example, 45, 78, 12 are two digit numbers.

The digit value is the position of each digit in the number. When talking about single-digit numbers, there is only one place value. When it comes to two-digit numbers, there are two digit values, 1 and 10.

For example:

a.) 33 ⇒ 3 tens + 3 ones = (3 × 10) + (3 × 1) = 30 + 3 = 33

b.) 18 ⇒ 1 tens + 8 ones = (1 × 10) + (8 × 1) = 10 + 8 = 18

c.) 27 ⇒ 2 tens + 7 ones = (2 × 10) + (7 × 1) = 20 + 7 = 27

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The probability of success, p, is the same for each trial. Each outcome is either a success (P) or a failure (Q). The correct option is A.

Independence is a fundamental notion in probability theory, as in statistics and the theory of stochastic processes.

You should perform x trials until you observe a success.

We have given that,

There are exactly two possible outcomes success and failure.

We have to determine the following is NOT a common characteristic of a binomial distribution.

By process of elimination:-

A binomial experiment is a statistical experiment that must meet certain requirements

All trials are independent.

There are a fixed number of n trials.

The probability of success, p, is the same for each trial.

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Answer:

192π m²

Step-by-step explanation:

V = πr²h

r = d/2 = 8 m / 2 = 4 m

V = π × (4 m)² × 12 m

V = π × 16 m² × 12 m

V = 192π m²

a) To obtain the potential pressure drop in the wellbore, we can use the hydrostatic pressure equation.

The potential pressure drop is equal to the pressure gradient multiplied by the length of the wellbore. The pressure gradient can be calculated using the equation: Pressure gradient = (density of oil × acceleration due to gravity) × sin(θ), where θ is the deviation angle of the wellbore from horizontal flow. In this case, the pressure gradient would be (48 lbm/ft^3 × 32.2 ft/s^2) × sin(15°). Multiplying the pressure gradient by the wellbore length of 6,000 ft gives the potential pressure drop.

b) To determine the frictional pressure drop in the wellbore, we can use the Darcy-Weisbach equation. The Darcy-Weisbach equation states that the pressure drop is equal to the friction factor multiplied by the pipe length, density, squared velocity, and divided by the pipe diameter. However, to calculate the friction factor, we need the Reynolds number. The Reynolds number can be calculated as (density × velocity × diameter) divided by the oil viscosity. Once the Reynolds number is known, the friction factor can be determined. Finally, using the friction factor, we can calculate the frictional pressure drop.

c) To calculate the in-situ oil velocity, we need to consider the total volume of the pipe, including both oil and gas. The total pipe volume is calculated as the pipe cross-sectional area multiplied by the wellbore length. Subtracting the gas volume from the total volume gives the oil volume. Dividing the oil volume by the total time taken by the oil to flow through the pipe (converted to seconds) gives the average oil velocity.

d) The flow regime of the two-phase flow can be determined based on the oil and gas mixture properties and flow conditions. Common flow regimes include bubble flow, slug flow, annular flow, and mist flow. These regimes are characterized by different distribution and interaction of the oil and gas phases. To determine the specific flow regime, various parameters such as gas and liquid velocities, mixture density, viscosity, and surface tension need to be considered. Additional information would be required to accurately determine the flow regime in this scenario.

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Given point, P = (-2,-6) lies on the circle x² + y² = r², and also on the terminal side of an angle θ in standard position. We have to find the values of sinθ, cosθ, tanθ, cscθ, secθ and cotθ.

We know that point P lies on the circle x² + y² = r² i.e. (-2)² + (-6)² = r² ⇒ r² = 40
Now, as the point P lies on the terminal side of angle θ, it lies in the III quadrant and we know that cosθ and sinθ are negative in the III quadrant.
We can find the values of sinθ and cosθ using the coordinates of the point P as follows:
sinθ = y/r = -6/√40 = -3/√10
cosθ = x/r = -2/√40 = -1/√10
We can find the values of other trigonometric ratios using the above obtained values of sinθ and cosθ as follows:
tanθ = sinθ/cosθ = (-3/√10)/(-1/√10) = 3
cosecθ = 1/sinθ = √10/-3 = -√10/3
secθ = 1/cosθ = -√10
cotθ = 1/tanθ = 1/3
Hence, the values of the given trigonometric ratios for the point P are:
sinθ = -3/√10
cosθ = -1/√10
tanθ = 3
cscθ = -√10/3
secθ = -√10
cotθ = 1/3The required values of the trigonometric ratios for the point P are as follows: sinθ = -3/√10, cosθ = -1/√10, tanθ = 3, cscθ = -√10/3, secθ = -√10, cotθ = 1/3.

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There are 25 students in the class and 3 students are undecided about the type of party they want.

We know that 20% (percent)of the students want an ice cream party. Let's call the total number of students in the class "x." Then we can set up an equation:

0.2x = 5

Solving for x, we get:

x = 5 / 0.2

x = 25

So there are 25 students in the class. We also know that 5 want an ice cream party, 7 want a movie party, and 10 want a costume party. That adds up to 22 students. So the rest of the students must be undecided:

25 - 22 = 3

Therefore, 3 students are undecided about the type of party they want.

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Complete Question

Mrs. Conley asks her class what kind of party they want to have to celebrate their excellent behavior. Out of all the students in the class, 5 want an ice cream party, 7 want a movie party, 10 want a costume party, and the rest are undecided. If 20%, percent want an ice cream party, how many students are in the class?

Answer:

Explanation:

Parameters:

Principal, P = $78,000

Interest rate, R = 9%

Time, T = 2 months OR 2/12 = 1/6 years

Interest = ?

The formula for simple interest is:

I = PRT/100

The equivalent expression of the expression is 128x^5y^6/2x^7y^5

The expression is given as:

128x^5y^6/2x^7y^5

Divide 128 by 2

64x^5y^6/x^7y^5

Apply the law of indices

64y^(6-5)/x^(7-5)

Evaluate the differences

64y/x^2

Hence, the equivalent expression of the expression is 128x^5y^6/2x^7y^5

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Complete question

Select the correct answer. which expression is equivalent to 128x^5y^6/2x^7y^5 , if x > 0 and y > 0

Answer:

1.61

Step-by-step explanation:

Just subtract 4.7 by 3.09