Which of the following is NOT soluble in the solution when NaOH and CuCl2 are mixed together?
A. NaOH
B. CuCl₂
C. NaCl
D. Cu(OH)2

Answer:

Specific gravity compares the density of a substance to the density of air.

Specific gravity is compared the density of a substance to the density of water.

Specific Gravity is a dimensionless quantity that can be defined as the ratio of the density of a substance to the density of the water at a particular temperature.

The mathematical formula of the specific gravity can be written as:

Specific gravity = density of substance / density of water

The density of water at 4°C is used as a reference point as water has the highest density of 1000 kg/m³.  Specific gravity or relative gravity does not have any dimension as it is a dimensionless quantity.

Specific gravity is the ratio of a substance’s density to that of water at a specific temperature. The temperature plays an important role in determining the specific gravity of a substance.

Therefore, specific gravity is a characteristic of the substance at a particular temperature and pressure that also affects the specific gravity.

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The initial pH of a 100.0 mL sample of 0.030 M HCl is 1.52.

To calculate the pH of a solution, we use the formula:

pH = -log[H+]

In the case of a strong acid like HCl, the concentration of hydrogen ions ([H+]) is equal to the molarity of the acid.

Therefore, we can plug in the given molarity of 0.030 M for [H+]:

pH = -log[0.030]

Using a calculator, we can solve for pH:

pH = 1.52

Therefore, the initial pH of a 100.0 mL sample of 0.030 M HCl is 1.52.

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The value of ΔH for the reaction CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g) is -1272 kJ.

To calculate the enthalpy change (ΔH) for the given reaction, we can use Hess's law, which states that the overall enthalpy change of a reaction is equal to the sum of the enthalpy changes of the individual reactions involved.

Given the enthalpy changes:

1. 2 C(s) + O₂(g) → 2 CO(g)... ∆H = -222 kJ

2. C(s) + O₂(g) → CO₂(g)... ∆H = -394 kJ

3. 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ

We need to manipulate these reactions to obtain the desired reaction:

1. Reverse reaction 2: CO₂(g) → C(s) + O₂(g)... ∆H = +394 kJ

2. Multiply reaction 2 by 2 to balance carbon atoms: 2 CO₂(g) → 2 C(s) + 2 O₂(g)... ∆H = -788 kJ

3. Leave reaction 3 unchanged: 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ

By adding reactions 2 and 3, we obtain the desired reaction:

CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g)... ∆H = -788 kJ + (-484 kJ) = -1272 kJ

Therefore, the value of ΔH for the given reaction is -1272 kJ.

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Answer:

C. It represents the heat involved in a reaction

Explanation: It would make sense since most of the time h in chemistry  

is the equivalent to heat.  

I hope this helped you!

The spontaneity of a reaction is determined by the Gibbs free energy change (∆G), which is a measure of the system's ability to do work.

The equation that links ∆G, ∆H, and ∆S is: ∆G = ∆H - T∆S, where T is the temperature in Kelvin and ∆H and ∆S are the enthalpy and entropy changes, respectively. The signs of ∆H and ∆S determine whether the reaction is exothermic or endothermic and whether it is entropy-driven or enthalpy-driven, respectively.

If ∆G is negative, the reaction is spontaneous, meaning it occurs without the input of energy.The given reaction has a ∆H of 23.25 kJ and a ∆S of 161.26 J/mol∙K.

First, we need to convert the units of ∆S from J/mol∙K to kJ/mol∙K by dividing by 1000.∆S = 161.26 J/mol∙K ÷ 1000 = 0.16126 kJ/mol∙K Substitute the values into the equation to determine the spontaneity of the reaction:

∆G = ∆H - T∆S∆G = (23.25 kJ) - (298 K) x (0.16126 kJ/mol∙K)∆G = 23.25 kJ - 48.02 kJ∆G = -24.77 kJ Since ∆G is negative, the reaction is spontaneous.

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There is 1.0 mole of KNO₃ in 500.0 mL of a 2.0 M KNO₃ solution.

To determine the number of moles of KNO₃ in 500.0 mL of a 2.0 M KNO₃ solution, we need to use the equation:

moles = concentration (M) × volume (L)

Since 1 liter is equal to 1000 milliliters, we divide 500.0 mL by 1000 to get 0.5 L.

Next, we substitute the values into the equation:

moles = 2.0 M × 0.5 L

The concentration of 2.0 M indicates that there are 2.0 moles of KNO₃ in 1 liter of the solution. Therefore, multiplying the concentration (2.0 M) by the volume (0.5 L) gives us the number of moles of KNO₃:

moles = 2.0 M × 0.5 L = 1.0 mol

Hence, there is 1.0 mole of KNO3 in 500.0 mL of a 2.0 M KNO₃ solution.

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Answer:

Atoms that are isotopes have the same number of protons.

Nitrogen is a diatomic molecule in the VA family on the periodic table. Nitrogen has five valence electrons, so it needs three more valence electrons to complete its octet. A nitrogen atom can fill its octet by sharing three electrons with another nitrogen atom, forming three covalent bonds, a so-called triple bond.

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The speed of a wave can be calculated using this formula:

v = f x λ

Where:

v is the wave speed in metres per second, m/s

f is the frequency in hertz, Hz

λ (lambda) is the wavelength in metres, m

Calculation:

Given:

f = 20 Hz

λ = 100m

Using the equation:

v = f x λ

v = 20 x 100

v = 2000 m/s

Therfore, the speed of the wave is 2000 m/s

A sound wave has a wavelength of 100 m and a frequency of 20 Hz. The wave's speed is 2× 10^3 m/s.

assuming frequency = 20 Hz and wavelength = 100 m

utilized concept: v= = 20×100 = 2×10³ m/s

The frequency in physics is the quantity of waves passing a fixed location in a unit of time. It also indicates how many cycles or vibrations a body in periodic motion experiences in a given unit of time.

A sort of energy created by vibrations is sound. The molecules of the air surrounding an item vibrate as a result.. These molecules vibrate because they collide with nearby molecules, which also vibrate as a result.

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Answer:

mass of the object and how much energy the object has

c. Easily Gain Electrons. Easily Gain Electrons belongs to metal elements.

Metal elements are characterized by having relatively low ionization energies and high electronegativities. This allows them to easily gain electrons from other elements in chemical reactions.Metals are chemical elements that are characterized by their ability to conduct electricity, have a metallic luster, and are malleable and ductile. They are divided into two main categories: ferrous metals, which contain iron, and non-ferrous metals, which do not.An atom can easily gain electrons by participating in a redox reaction. This is when electrons are transferred between two atoms, and the atom that receives the electrons gains them.

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The mass of aluminum produced per hour in the electrolysis of a molten aluminum salt by a current of 28 A is approximately 8.42 g.

To calculate the mass of aluminum produced per hour in the electrolysis of a molten aluminum salt, we need to consider Faraday's Law. Faraday's Law states that the mass of a substance produced by electrolysis is directly proportional to the amount of electrical charge passed through the electrolyte. The amount of electrical charge can be calculated using the formula:
Q = It
where Q is the electrical charge (in Coulombs), I is the current (in Amperes), and t is the time (in seconds).
In this case, we are given that the current is 28 A and we want to calculate the mass of aluminum produced per hour, which is equivalent to 3,600 seconds. Therefore, we can calculate the electrical charge as follows:
Q = 28 A x 3,600 s = 100,800 C
Now, we need to convert the electrical charge to the mass of aluminum produced using the formula:
mass = (Q x M) / (n x F)
where M is the molar mass of aluminum (27 g/mol), n is the number of electrons transferred in the reaction (3 for aluminum), and F is Faraday's constant (96,485 C/mol).
Substituting the values, we get:
mass = (100,800 C x 27 g/mol) / (3 x 96,485 C/mol) = 8.42 g
Therefore, the mass of aluminum produced per hour in the electrolysis of a molten aluminum salt by a current of 28 A is approximately 8.42 g.

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Answer:

The pressure cooker contains 0.000355 moles of air (to three significant figures).

Explanation:

To find the number of moles of air in the pressure cooker, we can use the ideal gas law.

\(PV=nRT\)

where:

Rearrange the equation to solve for n:

\(\implies n=\dfrac{PV}{RT}\)

As we have been given the volume in liters, we must first convert it to cubic meters. As 1 liter = 0.001 m³ then 5.68 liters = 0.00568 m³.

Therefore, the values to substitute into the formula are:

Substitute the values into the formula and solve for n:

\(\implies n=\dfrac{205 \cdot 0.00568}{8.3144626 \cdot 394}\)

\(\implies n=0.000355444...\)

\(\implies n=0.000355\; \sf mol\; (3\;s.f.)\)

Therefore, the pressure cooker contains 0.000355 moles of air (to three significant figures).

Answer: 0.000304 is the answer

Answer:

30400

Explanation:

I just think it's that i could be wrong

Acetanilide has a higher ratio of polar surface area (SA) to total SA compared to trans-cinnamic acid, which allows it to form stronger interactions with water molecules and be more soluble.

Acetanilide and trans-cinnamic acid have different solubility behaviors in warm water due to their molecular structures and the relative ratios of their polar surface area (SA) to total SA.

Acetanilide contains an amide functional group (-CONH2), which contributes to its polar nature. The amide group has a partial positive charge on the carbon and a partial negative charge on the oxygen and nitrogen atoms. This polar group increases the ratio of polar SA to total SA in acetanilide, allowing it to form stronger hydrogen bonds and interact more favorably with water molecules, making it soluble in warm water. On the other hand, trans-cinnamic acid contains a carboxylic acid functional group (-COOH), which is also polar but to a lesser extent compared to the amide group. The lower polar SA to total SA ratio in trans-cinnamic acid results in weaker interactions with water molecules, leading to lower solubility in warm water.

Thus, the differences in the ratios of polar SA to total SA between acetanilide and trans-cinnamic acid explain their contrasting solubility behaviors in warm water.

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The point in the titration curve is [A-] closest to twice that of [HA] is the T point.

A titration curve is a graphical representation depicting the variance in pH of a solution when a strong acid or base solution is intermittently incorporated.

Titration, a practiced laboratory approach accustomed to estimate the concentration of an unfamiliar liquid, necessitates the infusion of a set amount of standard solution. The occurrence of the titration process calls for the maintaining of the pH levels at uniform durations, and consequently, the creation of the titration curve.

Uniformly, the titration curve has a recognizable configuration based off the nature of either acid or base utilized for titration.

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Flame tests are used to identify the presence of a relatively small number of metal ions in a compound. Not all metal ions give flame colors. For Group 1 compounds, flame tests are usually by far the easiest way of identifying which metal you have got.

Answer:

3Mg(OH)2 + 2H3PO4 = Mg3(PO4)2 + 2H3O

Explanation:

Question:

Which lists the numbers of each atom the other half of the equation would contain?

Equation:

3Mg(OH)2 + 2H3PO4

Options:

Answer:

A) 3 Mg, 2 P, 14 O, 12 H

Explanation:

I just did the test on edge 2020 and got the answer right. Also, my dog said hi.

The International Astronomical Union (IAU) downgraded the status of Pluto to that of a dwarf planet because it did not meet the three criteria the IAU uses to define a full-sized planet.

Of the two molecules, HCo(CO)₃ is likely to oxidatively add H₂ faster.

This is because HCo(CO)₃ is a transition metal complex that can easily undergo oxidative addition reactions due to the presence of a metal center with empty d-orbitals. In contrast, Zr(CH₂CMe₃)₄ is a zirconium complex with a filled d-orbital, making it less likely to undergo oxidative addition reactions.

Additionally, the presence of the bulky CH₂CMe₃ ligands on the zirconium center may further hinder the oxidative addition process. Overall, HCo(CO)₃ is a more favorable candidate for oxidative addition of H₂ due to its transition metal center and lack of sterically hindered ligands.

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Iron (II) (Fe) oxidized, aluminium (Al) reduced. Hence, option D is correct.

An electrolytic cell converts electrical energy into chemical energy or vice versa.

Oxidation-reduction reactions are balanced by two half overall chemical equations into an oxidation equation and a reduction equation.

Iron (II) (Fe) oxidized, aluminium (Al) reduced of the following is an electrolytic cell.

Hence, option D is correct.

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Answer:

1. Polyethylene (PE)
2. Polypropylene (PP)
3. Polyvinyl chloride (PVC)
4. Polystyrene (PS)
5. Polytetrafluoroethylene (PTFE), also known as Teflon.

Answer:

D

Explanation:

Lamps

Answer:

44 g

Explanation:

hope this helps

Answer:

A fatty acid is made of a polar carboxylic acid functional group and a nonpolar hydrocarbon tail.

Explanation:

A fatty acid is made of fat-soluble components, that consists of a large (more than 4 carbon atoms) aliphatic chain of carbon atoms, with hydrogen atoms and a carboxyl group (-COOH). The named fatty acid is because of the -COOH group.

The chain can be made of carbon atoms with a single bond, (saturated) or with double or triple bonds (unsaturated). When the fatty acid has just one double bond the fatty acid is monounsaturated, and otherwise, if it has multiple double bonds it is polyunsaturated. Fatty acid chains can be different in their lengths and their degree of unsaturation.          

Mostly of the tail of the fatty acid is nonpolar and hence, hydrophobic, because the long-chain made of hydrocarbon atoms.

From all of the above, the correct answer is option b: A fatty acid is made of a polar carboxylic acid functional group and a nonpolar hydrocarbon tail.

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Answer:

i think is probably A

Explanation:

because at constant temperature, the product of the pressure and volume of a given mass of and ideal gass in a closed system is always constant

Answer:

I believe the answer is A or D

Explanation:

I hope this helps you out!

Nitroglycerin transdermal patches can be used in the management of angina and can deliver therapeutic dosages for up to 24 hours. These patches contain nitroglycerin and are applied to the skin to provide continuous delivery of nitroglycerin.

Nitroglycerin is a vasodilator that dilates blood vessels and helps improve blood flow. Nitroglycerin can help reduce the frequency and severity of angina attacks by dilating the arteries in the heart, which increases blood flow to the heart and reduces the workload of the heart.Due to the skin's characteristics, the nitroglycerin transdermal patch slowly releases nitroglycerin into the bloodstream over an extended period of time. The duration of the action of a nitroglycerin transdermal patch is usually 24 hours, and the drug is absorbed through the skin.The medication's therapeutic effect lasts for around 14 hours on average, with the remaining ten hours serving as a drug-free period. After removal of the nitroglycerin patch, the effect of the medication begins to wear off within hours, typically four to six hours.Because of its long duration of action, nitroglycerin transdermal patches are particularly beneficial for individuals who have angina symptoms that occur regularly and can cause discomfort throughout the day.

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