Which of the following phrases are equations?
4.23
B
b=9
с
7 + 19 = 26
O
a +9> 72
8
2 + y -
3

Answer:

use table B

Step-by-step explanation:

the perimeter of table A =

2×(96+42) = 2× 138 = 276 inches

the perimeter of table B =

2×3.14×45 = 282.6 inches

table B > table A

Answer:

2/3

Step-by-step explanation:

Your −3x + 3 −1 is not an equation and thus has no solution.

If, on the other hand, you meant

−3x + 3 = 1

then -3x = -2, and  x = 2/3

Answer:

  C

Step-by-step explanation:

If ∆MNP is equilateral, then each of the arcs MN, NP and PM will be 120°. An inscribed angle from anywhere that intercepts one of these arcs will have measure 60°. That is, angle MQP is 60°. We already know angle MOQ is 60° (half of arc MN), so ∆MOQ is equilateral, and MO=MQ=PO.

Points M and N were drawn using Q as a center, and PO as a radius.

Answer:

That is the simplest answer I'm pretty sure

Step-by-step explanation:

Answer:

it cannot be simplified further

Answer:

Volume V ≈ 1481.3269 cubic inches

Step-by-step explanation:

Volume V of a cylinder is given by the formula

V = πr²h  where r = radius of the base of the cylinder and h the height

Here we are given the diameter, d = 5.9375 inches

Radius r = d/2 = 5.9375/2 = 2.96875 in

Height h = 53.5 in

V = π x 2.9685² x 53.5 ≈ 1481.3269 cubic inches

Answer V ≈ 1481.3269 cubic inches

Answer: To find the image of a figure under a translation, you need to apply the same translation to every point in the figure.

In this case, the image of hexagon DEFGHI is hexagon D′E′F′G′H′I′. To find the image of each point, you can apply the translation that maps point D to point D′.

For example, to find the image of point E under the translation, you can apply the same translation that maps point D to point D′:

Point D is located at (2, 5).

Point D′ is located at (-6, -2).

The translation that maps point D to point D′ is a translation 6 units to the left and 2 units down.

To find the image of point E under this translation, you can apply the same translation to point E:

Point E is located at (5, 5).

The image of point E is located at (5 - 6, 5 - 2) = (-1, 3).

You can follow the same process to find the images of the other points under the translation.

Alternatively, you can use the coordinates of point D and point D′ to find the translation vector that describes the translation. The translation vector is a displacement that describes the change in position of a point under the translation.

In this case, the translation vector is given by the displacement from point D to point D′:

Point D is located at (2, 5).

Point D′ is located at (-6, -2).

The translation vector is given by the displacement (-6 - 2, -2 - 5) = (-8, -7).

To find the image of any point under the translation, you can add the translation vector to the coordinates of the point. For example, to find the image of point E under the translation, you can add the translation vector to the coordinates of point E:

Point E is located at (5, 5).

The translation vector is (-8, -7).

The image of point E is located at (5 - 8, 5 - 7) = (-3, -2).

You can follow the same process to find the images of the other points under the translation.

Step-by-step explanation:

The expression log₃(x²∛y²) using the laws of logarithms is 2log₃(x) + 2/3log₃(y)

From the question, we have the following parameters that can be used in our computation:

log₃(x²∛y²)

The product law of logarithms states that

log(ab) = log(a) + log(b)

Using the above as a guide, we have the following:

log₃(x²∛y²) =  log₃(x²) + log₃(∛y²)

The power law of logarithms states that

log(aᵇ) =  blog(a)

Using the above as a guide, we have the following:

log₃(x²∛y²) =  2log₃(x) + 2/3log₃(y)

This means that the values of A and B are A = 2 and B = 2/3

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Answer:

train a with traveling at 80 miles an hour where train be was traveling at 50 miles per hour.

Whwn the line of sight from the park ranger station, P, to the lifeguard chair, L, the length of PL is 0.76 miles.

It should be noted that since the line of sight from the park ranger station, P, to the lifeguard chair, L, on the beach of a lake is perpendicular to the path joining the campground, C, and the first aid station, F, then the path from the park ranger station to the lifeguard chair is the hypotenuse of a right triangle with legs of 0.35 miles and 0.65 miles.

The Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the legs. Therefore, the length of PL is equal to:

= ✓(0.35² + 0.65²)

= 0.76 miles.

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Answer:

  5

Step-by-step explanation:

The total cost per day is $20 +50 = $70. Then the number of days that expenditure can be made on a budget of $350 is ...

  $350/($70/day) = 5 days

Answer:

Step-by-step explanation:

let number of days =x

(20+50)x≤350

70 x≤350

x≤350/70

or x≤5

He can rent both at the most 5 days.

The height of the hill is approximately 25.73 ft. Where v0 is the initial velocity (108 ft/s), g is the acceleration due to gravity \((-32.2 ft/s^2)\),

To find the height of the hill, we can use the formula for the vertical position of an object under constant acceleration:

h = h0 + v0t + 1/2at^2

where h is the final height, h0 is the initial height, v0 is the initial velocity, t is the time, and a is the acceleration due to gravity (-32.2 ft/s^2).

In this case, we are given that the initial height h0 is 3 ft, the initial velocity v0 is 108 ft/s, and the time t is 9.5 s. We want to find the height of the hill, which we can denote as h_hill. The final height is the height of the plain, which we can denote as h_plain and assume is zero.

At the highest point of its trajectory, the arrow will have zero vertical velocity, since it will have stopped rising and just started to fall. So we can set the velocity to zero and solve for the time it takes for that to occur. Using the formula for velocity under constant acceleration:

v = v0 + at

we can solve for t when v = 0, h0 = 3 ft, v0 = 108 ft/s, and a = -32.2 ft/s^2:

0 = 108 - 32.2t

t = 108/32.2 ≈ 3.35 s

Thus, it takes the arrow approximately 3.35 s to reach the top of its trajectory.

Using the formula for the height of an object at a given time, we can find the height of the hill by subtracting the height of the arrow at the top of its trajectory from the initial height:

h_hill = h0 + v0t + 1/2at^2 - h_top

where h_top is the height of the arrow at the top of its trajectory. We can find h_top using the formula for the height of an object at the maximum height of its trajectory:

h_top = h0 + v0^2/2a

Plugging in the given values, we get:

h_top = 3 + (108^2)/(2*(-32.2)) ≈ 196.78 ft

Plugging this into the first equation, we get:

h_hill = 3 + 108(3.35) + 1/2(-32.2)(3.35)^2 - 196.78

h_hill ≈ 25.73 ft

If the arrow is launched at t0, the equation describing velocity as a function of time would be:

v(t) = v0 - gt

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Answer:

176π cm2

Step-by-step explanation:

Answer:

angle ced is a right ange

so the m angels debate =135 m angle aeb =35

so the answer is 135+35 =170

180 is a all side sim

=180-170=10 answer

Answer:

∠CED is a right angle.

∠CEA is a right angle.

m∠CEB = m∠BEA

m∠DEB = 135°

Answer:

Hope you understand not to sure but that's what I got

Answer: \(x+3, x \neq -6\)

Step-by-step explanation:

The denominator cannot equal 0, so \(x \neq -6\).

Simplfying,

\(\frac{x^2 +9x+18}{x+6}=\frac{(x+6)(x+3)}{x+6}=x+3\)

Answer: Bro there nothing to answer??? there is no problem below???

Step-by-step explanation:

Answer:

The variable n represents the number of times in a year in which we compound the interest rate

Step-by-step explanation:

The periodic compound interest formula is given as;

A = P( 1 + r/n)^nt

The variable n represents the number of times in a year in which the interest rate is compounded

The rational function graphed in this problem is defined as follows:

y = -2(x - 1)/(x² - x - 2).

The vertical asymptotes of the rational function for this problem are given as follows:

x = -1 and x = 2.

Hence the denominator of the function is given as follows:

(x + 1)(x - 2) = x² - x - 2.

The intercept of the function is given as follows:

x = 1.

Hence the numerator of the function is given as follows:

a(x - 1)

In which a is the leading coefficient.

Hence:

y = a(x - 1)/(x² - x - 2).

When x = 0, y = -1, hence the leading coefficient a is obtained as follows:

-1 = a/2

a = -2.

Thus the function is given as follows:

y = -2(x - 1)/(x² - x - 2).

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We have proved that the ray FE is parallel to the ray GC.

What is meant by parallel lines?

In geometry, parallel lines are coplanar straight lines that do not intersect at any point. Parallel planes are planes in the same three-dimensional space that never meet. Parallel curves are curves that do not touch each other or intersect and keep a fixed minimum distance.

Angle DEF intersects at B

which results in angle DEF corresponding to the angle  ACG.

As DEF = 45 so angle ACG = 45

So by the above discussion, we can say that the ray FE is parallel to the ray GC.

Hence, we have proved that the ray FE is parallel to the ray GC.

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Answer:

10.75

Step-by-step explanation:

2.5 x 4.3 = 10.75

Answer:

\({ \rm{2.5 \times 4.3 = 10.75}} \)

Answer:

The answer is D. 272

Step-by-step explanation:

All you need to do is find out how many people can be seated at each table, then add them together.

16 x 8 = 128

12 x 12 = 144

128 + 144 = 272

272 students can fit in the cafeteria at once.

Answer: It will be C, 5x + 2y = 6 is equivalent to y = -5/2x + 3

The equivalent equation for the given is y=-5/2x+3. Therefore, option A is the correct answer.

The general equation of a straight line is y=mx+c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis.

The given equation is 5x +2y=6.

The equivalent equation is 2y=-5x+6

y=-5/2x+6/2

y=-5/2x+3

Therefore, option A is the correct answer.

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Select the line that is equivalent to 5x +2y=6.

A) y=-5/2x+3

B) y=5/2x-3

C) y=-2/5x+6/5

D) y=2/5x-6/5

\(\qquad\qquad\huge\underline{{\sf Answer}} \huge♨\)

In the given figure, NQ acts as a diameter and since diameter subtends 90° at the arc of the circle, so we can conclude that ~

\(\qquad \sf  \dashrightarrow \:3y = 90 \degree\)

\(\qquad \sf  \dashrightarrow \:y = 90 \degree \div 3\)

\(\qquad \sf  \dashrightarrow \:y = 30 \degree \)

Now, Let's use Angle sum property of Triangle to solve for z :

\(\qquad \sf  \dashrightarrow \:4z + 3y + 50 \degree = 180 \degree\)

\(\qquad \sf  \dashrightarrow \:4z +90 \degree + 50 \degree = 180 \degree\)

\(\qquad \sf  \dashrightarrow \:4z = 180 \degree - (50 \degree + 90\degree)\)

\(\qquad \sf  \dashrightarrow \:4z = 180 \degree - (140\degree)\)

\(\qquad \sf  \dashrightarrow \:4z = 40 \degree\)

\(\qquad \sf  \dashrightarrow \:z = 40 \degree \div 4\)

\(\qquad \sf  \dashrightarrow \:z = 10 \degree \)

I hope you understood the procedure, you can ask me in comments if you have any doubts.

Answer: 4 pounds is equal to 16 four-ounce (1/4 pound) increments.

To find the number of 3/4 pound bags Ann needs to buy, we can convert 16 four-ounce increments to three-fourth pound increments:

16 four-ounce increments = 16 x 4 = 64 ounces

64 ounces = 64/16 = 40 three-fourth pound increments

Therefore, Ann will need to buy 40 bags of walnuts, each weighing 3/4 of a pound.

Step-by-step explanation:

I got (7x^11+4) but i would check with someone else just to be sure.

The sequence of transformations is:

Reflection across the x-axis followed by a translation of 5 units to the left.

We start with the red figure, the first thing we should apply is a reflection across the x-axis.

Doing this, we will see that both figures are in the same orientation, while in different positions.

At this point, we should do a translation to the left of 5 units, this will move the whole red figure 5 units to the left and that will map the red figure into the blue one.

Notice that if the transformations are applied in the other order (first the translation and then the reflection) we will get the same outcome.

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