Answer:
A and D
b and C are false
Answer:
D. Animals migrate for various reasons.
Explanation:
Got it right on Edge 2023. : )
You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?
A. The average speed you can use to pull the safe is 1.02 m/s
B. The time needed to pull the safe up is 17.65 s
A. How do i determine the velocity?First, we shall obtain the force. This is shown below:
Mass of safe (m) = 60 KgAcceleration due to gravity (g) = 9.8 m/s² Force (F) =?F = mg
F = 60 × 9.8
F = 588 N
Finally, we shall obtain the average speed. Details below:
Power = 600 WForce = 588 NAverage speed =?Power = force × average speed
600 = 588 × average speed
Divide both sides by 588
Average speed = 600 / 588
Average speed = 1.02 m/s
B. How do i determine the time?The time needed to pull the safe up can be obtained as follow:
Average speed = 1.02 m/sTotal distance = 18 mTime = ?Time = Total distance / average speed
Time = 18 / 1.02
Time = 17.65 s
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Complete question:
You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?
Part B
What is the time needed to pull the safe up?
soulve the plane polare eqestion in circular
Answer:
Explanation:
u
I
Suppose you have an electrical device that needs a steady current of
10 milliamperes. You need to greatly increase the length of the wire
between the battery pack and the appliance. What changes will you
need to make in your circuit to keep a steady current?
main answer- by keeping resistance constant,voltage should be increased
supporting answer-For keeping the current constant we must keep the resistance constant so that the current will stay constant
When the length of the conductor is going to be increased then the voltage should also be increased as there is a resistance increase due to the length increase at the conductor because it goes by the formula r is equal to raw l by a where is the resistivity of the conductor and length of the conductor by divided by area of the conductor
To keep the following current constant reverse increase the voltage supply to the circuit
final answer-by keeping resistance constant,voltage should be increased
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You will need to increase the cross-sectional area of the wire in order to keep the current steady.
What is wire?
A wire is a thin, malleable metal strand. The most common way to make wire is to draw the metal through a hole in a draw plate or die. When expressed in terms of a gauge number, wire gauges are available in a variety of common sizes. Mechanical loads are carried by wires, frequently in the form of wire rope. A "wire" can refer to an electrical cable in the context of electricity and telecommunications signals. This type of cable may have a "solid core" made up of a single wire or multiple strands woven together in stranded or braided forms. While wire is often cylindrical in shape, it can also have alternative cross-sections, such as square, hexagonal, flattened rectangular, or other shapes, for both aesthetic and technical uses, such as high-efficiency voice coils in loudspeakers.
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When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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You push your friend, whose mass is 54kg, down a hill so she can go sledding. Her acceleration is 3m/s2. Calculate the amount of force you applied to your friend.
Answer:
18 newtons
Explanation:
Divide weight by speed
Which of the following best decribes the velocity of an object?
a
30 m/s
b
30 m east
С
30 m/s east
d
30 m
The graph describes the motion of an object.
The object moves with
CBD.
from A to B. It
from B to C. It moves with
from
The graph describes the motion of an object.
The object moves with CBD
From A to B It is moving in a straight line it means it's velocity is constant
From B to C it is not changing it's position with respect to time so velocity is zero because initial and final position are same so there is no displacement
From C to D it is again moving in a straight line it means it's velocity is constant
What is Position time graph ?An object's distance from its beginning position at any given moment since it began moving is displayed on a position-time graph. The greater the slope of the line and the faster the object's speed changes, the steeper the line is.
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A mass of 0.24 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic motion of the mass is described by x) (0.46 m)cos (12 rad/s)t. Determine the following (a) Amplitude of oscillation for the oscillating mass (b) Period of the oscillation for the oscillating mass (c) Force constant (spring constant) for the spring. (d) Position of the mass after it has been oscillating for one half a period. (e) Time, it takes the mass to get to the position x=-010 m.
a) Amplitude A of oscillation for the oscillating mass = 0.46 m
b) Period of the oscillation for the oscillating mass is 0.52 s
c) Spring constant k is 34.56 N/m
d) The mass's position is zero after oscillating for half a time.
e) Time, it takes the mass to get to the position x= - 0.10 m is 0.1125 s.
The mass attached to the spring is 0.24 kg.
The simple harmonic motion of the mass is given as x = (0.46 m) [cos(12 rad/s)t]
The general equation of x(t) is known to be,
x(t) = A cos ωt
where,
A is amplitude
ω is angular frequency
t is time
Following that, let's compare the presented equation to the general equation:
(a) The amplitude of oscillation:
A = 0.46 m
(b) The period of oscillation is,
T = 2π √(m/k) = 2π √(0.24/34.56) = 2π √(0.0069) = 2π ×0.08 = 0.52 s
(c) Spring constant k is given by,
ω = √(k/m)
ω² = k/m
So, k = m ω² = 0.24 × 12² = 34.56 N/m
(d) After one half of the period, position is
x(t) = 0.46 cos(π/2) = 0.
(e) Time required at x = - 0.10 m
-0.10 = 0.46 cos 12t
cos 12t = -0.217
12t = cos⁻¹(-0.217)
t = 1.35/12 = 0.1125 s
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A boy stands between two vertical walls and fires a rifle. Under what condition will he hear a single echo from both walls? Calculate the distance between the walls if the single echo is heard six seconds later.
Answer:
d = 1,029 m
Explanation:
When the young man shoots the rifle the sound travels in all directions, if the young man is at the same distance from the two walls, as the speed of the wave is constant, he takes the same time to go to the wall and return for which he hears a single echo.
To calculate the distance let's use the uniform motion relationships
v = d / t
d = v t
As the speed is constant, the time to reach the wall is the same as it takes to go from the wall to the young man,
t = to / 2
t = 6/2
t = 3 s
d = 343 3
d = 1,029 m
using the image provided, which moon phase is next?
Answer:
Waning Crescent
Answer: waxing crescent
Explanation:
If a wave has a frequency of say 10 Hz, that means something is oscillating times per second. What is this property that is oscillating for light, described by its frequency?
The property that is oscillating would be the electric and magnetic fields.
Oscillating properties of lightFor light, the property that is oscillating or vibrating at a particular frequency is the electric and magnetic fields.
Light is an electromagnetic wave, which means that it consists of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of wave propagation.
The frequency of the wave corresponds to the number of complete oscillations of the electric and magnetic fields that occur per second, and is measured in hertz (Hz).
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Which of the following is NOT true about the mass of an object?
A)
Mass is measured in kilograms.
B)
Mass is a measurement of force.
C)
Mass is a measurement of the amount of matter in an object.
D)
Mass does not change based on your location.
Answer:
B) Mass is a measurement of force
Explanation:
Mass is not a measurement of force, mass is a measurement of the amount of matter in an object.
what is the resultant force when a 7 N force acts in the same direction as 6 N force
The resultant force when a 7 N force acts in the same direction as the 6 N force is 13 N.
What is resultant force?When an object is subject to several forces, the resultant force is the force that act alone and produces the same acceleration as all those forces.
When two or more forces act in the same direction, their resultant force is the sum of all the forces.
To calculate the resultant force, we use the formula below,
Formula:
F' = F₁+F₂............ Equation 1Where:
F' = Resultant force F₁ = 7 NF₂ = 6 NSubstitute these values into equation 1
F' = 7+6F' = 13 NHence the resultant force is 13 N.
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The sun produces energy via nuclear fusion at the rate of 4×1026 J/s . Based on the proposed overall fusion equation, how long will the sun shine in years before it exhausts its hydrogen fuel? (Assume that there are 365 days in the average year.)
Answer:
2 x 10^10 years.
Explanation:
Given that the sun produces energy via nuclear fusion at the rate of 4×1026 J/s . Based on the proposed overall fusion equation, how long will the sun shine in years before it exhausts its hydrogen fuel? (Assume that there are 365 days in the average year.)
Let us first calculate energy from hydrogen gas.
4(1.007825) + 2(0.00549) - 4.002603 = 0.029795 amu
Since 4.0313 amu H+ > 0.029795 amu = ratio of 1 to 0.00739
dE = ((2*10^30 kg) x 0.8 x 0.25)(3.00x10^8 m/s)^2 = 3.6x10^46 kg x m^2/s^2
3.6x10^46 kg x m^2/s^2 x 0.00739 = 2.6604 x 60^44 kg x m^2/s^2
4x10^26 J/s x s = 2.6604x10^44 kg x m^2/s^2 solve for s.
s = 6.651x10^17 seconds
6.651x10^17 seconds x 1 min/60 s x 1 hr/ 60 min x 1 day/ 24 hr x 1 yr / 365 days = 2.1x10^10 years
Based on the proposed overall fusion equation, it will therefore take the sun shine 2 x 10^10 years before it exhausts its hydrogen fuel.
Group B[1] 12 State Huygens's Principle [2] b) In a Young's double slit experiment, the fringe width obtained is 0.6 cm. When light of wave length 4500 Aº is used if the distance between the screen and the slit is reduced in half, what should be the wavelength of light used to obtain fingers 0.0045 m wide? [3]
The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.
Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.
Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.
Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.
We can use the formula for fringe width in Young's double-slit experiment:
w = (λ * D) / d
Where:
w is the fringe width,
λ is the wavelength of light,
D is the distance between the screen and the double slits, and
d is the distance between the two slits.
Let's calculate the value of D/d using the given information:
D/d = w / λ
= 0.006 m / 4500 Å (1 m = 10^10 Å)
= 0.006 * 10^10 / 4500 m^-1
Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:
(D'/d) = (0.006/2) * 10^10 / 4500 m^-1
Now, we can rearrange the equation to solve for the new wavelength (λ'):
(λ' * D') / d = (D/d)
λ' = (D/d) * d / D
= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å
= 0.0045 m * 10^10 / 2 Å
= \(0.00225 * 10^{10\) Å
=\(2.25 * 10^7\)Å
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The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.
The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.
The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).For more questions on thermometer
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When a 0.22 kg air-track cart is attached to a spring, it oscillates with a period of 0.84 s. What is the force constant for this spring
Answer:
Explanation:
ω = 2π/Τ = √(k/m)
4π²/T² = k/m
k = 4π²m/T²
k = 4π²(0.22)/0.84²
k = 12.3090304...
k = 12 N/m
The force constant for the spring (K) when a 0.22 kg air-track cart is attached and it oscillates with a period of 0.84 s is 12.30 N/m.
What is force?
A force is an influence that can cause an object's motion to change. A force can cause a mass object to change its velocity, or accelerate. It is a vector quantity because it has both magnitude and direction. The force required or exerted to compress or stretch a spring against any object attached to it is referred to as spring force.
Given,
Mass of the air track cart (m) =0.22 kg
Time period of oscillation (T)= 0.84s
The force constant of the spring is calculated as:-
The time period of the spring is given by :
T = 2π√m/K
K = 4π²m/T²
K = 4π²× 0.22kg/(0.84s)²
= 12.30N/m
Therefore, the force constant of the spring is 12.30 N/m.
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The deep interior of the Earth cannot be mapped using seismic waves . true or false ?
Answer: The answer is false.
How can motion be measured?
Motion can be measured in several ways, depending on the context and the specific parameters that need to be quantified.
What is Motion?
Motion is a fundamental concept in physics and is described by the laws of motion formulated by Sir Isaac Newton. These laws state that an object at rest tends to remain at rest and an object in motion tends to remain in motion with the same velocity . The study of motion is important in many fields, including physics, engineering, and astronomy.
Motion can be measured in several ways, depending on the context and the specific parameters that need to be quantified. Some common methods of measuring motion include:
Displacement: Displacement is the change in position of an object over a certain period of time. It can be measured using a ruler, tape measure, or other distance-measuring tools.
Speed: Speed is the rate at which an object moves, and it can be measured using a stopwatch or other timing device to determine the time it takes for an object to travel a certain distance.
Velocity: Velocity is similar to speed, but it takes into account both the speed and direction of motion. It can be measured using a velocity sensor or other motion-tracking tools.
Acceleration: Acceleration is the rate at which an object's speed or velocity changes over time, and it can be measured using an accelerometer or other motion-tracking tools.
Gyroscopic sensors: Gyroscopic sensors can be used to measure the rotational motion of an object, such as the rotation of a wheel or the movement of a drone.
Video analysis: Video analysis software can be used to track the movement of an object or a person, using visual markers or other reference points to determine motion.
Inertial measurement units (IMUs): IMUs are electronic sensors that can measure motion, acceleration, and rotation in three-dimensional space, and are commonly used in robotics, virtual reality, and other applications.
These are just a few examples of methods used to measure motion, and there are many other tools and techniques that can be used depending on the specific context and requirements.
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6. A ball is dropped vertically downward with a velocity of 15m/s from te roof of a building that is 22m high. How long does it takes to hit the ground below? How fast was it going when it hit
Answer:
3.03 seconds, 29.51 m/s
Explanation:
To solve this problem, we can use the kinematic equations of motion. The equation we will use is:
y = vi * t + 0.5 * a * t^2
where y is the displacement (height), vi is the initial velocity, a is the acceleration due to gravity (9.81 m/s^2), and t is the time.
At the top of the building, the displacement is 22 m (the height of the building), the initial velocity is 15 m/s (downward), and the acceleration is -9.81 m/s^2 (due to gravity, and negative because it is acting in the opposite direction to the initial velocity).
We can rearrange the equation to solve for time:
y = vi * t + 0.5 * a * t^2
22 = 15t - 0.5 * 9.81 * t^2
0.5 * 9.81 * t^2 - 15t + 22 = 0
Solving for t using the quadratic formula, we get:
t = (-(-15) ± sqrt((-15)^2 - 4 * 0.5 * 9.81 * 22)) / (2 * 0.5 * 9.81)
t = 3.03 s (rounded to two decimal places)
Therefore, it takes approximately 3.03 seconds for the ball to hit the ground.
To find the velocity of the ball when it hits the ground, we can use the equation:
v = vi + a * t
where v is the final velocity (unknown), vi is the initial velocity (15 m/s downward), a is the acceleration due to gravity (-9.81 m/s^2 downward), and t is the time (3.03 s).
Substituting the values, we get:
v = 15 - 9.81 * 3.03
v = -29.51 m/s
The negative sign indicates that the final velocity is in the opposite direction to the initial velocity (upward). However, since we were only asked for the speed (not velocity), we can take the absolute value of the answer to get:
|v| = 29.51 m/s
Therefore, the ball is going approximately 29.51 m/s when it hits the ground below.
1. A train is moving north at 5 m/s on a straight track. The engine is causing it to accelerate northward at 2 m/s^2.
How far will it go before it is moving at 20 m/s?
A) 83
B) 43
C) 39
D) 94
E) 20
Answer:
(D) x = 93.8 m
Explanation:
v^2 = v0^2 + 2ax
(20 m/s)^2 = (5 m/s)^2 + 2(2 m/s^2)x
Solving for x,
x = 93.8 m
1. Wha' is the relationship between potential and kinetic energy?
As potential energy increases, kinetic energy increases.
b. As potential energy increases, kinetic energy decreases.
C. As potential energy decreases, kinetic energy decreases.
d. Potential and kinetic energy are two separate things and have no
relationship.
Answer:
B
Explanation:
The kinetic energy in an object is converted into potential energy. This makes the kinetic decrease, while the potential increases.
A 1400-N crate rests on the floor.
How much work is required to move it at constant speed 5.0 m
vertically.
Express your answer to two significant figures and include the appropriate units.
The work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
To determine the work required to move the crate vertically, we need to calculate the gravitational potential energy change. The work done is equal to the change in potential energy.
The formula for gravitational potential energy is given by:
Potential energy = mass * acceleration due to gravity * height
In this case, the mass of the crate is not provided, but we can use the given weight of the crate to find the mass. Weight is equal to mass multiplied by the acceleration due to gravity (W = mg).
Given:
Weight of crate (W) = 1400 N
Acceleration due to gravity (g) = 9.8 m/s^2
Vertical distance (height) = 5.0 m
First, calculate the mass of the crate:
1400 N = m * 9.8 m/s^2
m = 1400 N / 9.8 m/s^2 ≈ 143 kg
Now we can calculate the work:
Work = Potential energy = mass * g * height
Work = 143 kg * 9.8 m/s^2 * 5.0 m ≈ 7000 J
Therefore, the work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).
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speed distance time calculator; if you travel 10 miles in 5 minutes, what is your speed; speed calculator; average speed calculator; speed increase calculator; how to calculate average speed; how to calculate average speed in meters per second; miles per hour calculator
The average speed of an object which travels 10 miles in 5 minutes is 120 miles/hour
The total distance traveled = 10 miles
The total time taken = 5 minutes
The speed can be calculated using the formula,
s = d/t
where s is the speed
d is the distance
t is the time taken
Let us substitute the known values in the above equation, we get
s = 10/5
= 2 miles/min
But, we need the speed in terms of miles per hour so, we can convert it by
s = 2 x 60 miles/hour
= 120 miles/hour.
Therefore, the average speed is 120 miles/hour
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Anyone help me do this am giving the brainliest
Explanation:
The first step is to write the 1st condition of equilibrium, which states that the net force acting on the beam is zero:
\(F_{net} = 5\:\text{kN} + N_L + N_R - 40\:\text{kN} - 60\:\text{kN} = 0\)
where \(N_L\) and \(N_R\) are reaction forces at the beam supports on the left and right, respectively.
Next, the 2nd condition of equilibrium states that the net torque about a pivot point is zero. Let's choose the location of the left beam support as our pivot point, which will make the torque due to \(N_L\) is equal to zero. Let us also assume that the counterclockwise direction produces positive torque. So we can write
\(\tau_{net} = (40\:\text{kN})(2\:\text{m}) + (5\:\text{kN})(5\:\text{m}) \\+ N_R(7\:\text{m}) - (60\:\text{kN})(8\:\text{m}) = 0\)
\(\Rightarrow 80\:\text{kN-m} + 25\:\text{kN-m} + N_R(7\:\text{m}) \\= 480\:\text{kN-m}\)
Solving for \(N_R,\) we see that
\(N_R = 53.6\:\text{kN}\)
Putting this value into our 1st equation, we find that the reaction force \(N_L\) is
\(N_L = 100\:\text{kN} - 5\:\text{kN} - N_R\)
\(\:\:\:\:\:\:\:\:= 41.4\:\text{kN}\)
What is the potential gravitational energy of a 2 kg ball thrown up in the air to a height of 7 m?
Answer:
PE = 137.2931 J
Explanation:
PE = 137.2931 J
Two forces, one four times as large as the other, pull in the same direction on a 10kg mass and impart to it an acceleration of 2.5 m/s2. If the smaller force is removed, what is the acceleration of the mass?
Answer:
The acceleration of the mass is 2 meters per square second.
Explanation:
By Newton's second law, we know that force (\(F\)), measured in newtons, is the product of mass (\(m\)), measured in kilograms, and net acceleration (\(a\)), measured in meters per square second. That is:
\(F = m\cdot a\) (1)
The initial force applied in the mass is:
\(F = (10\,kg)\cdot \left(2.5\,\frac{m}{s^{2}} \right)\)
\(F = 25\,N\)
In addition, we know that force is directly proportional to acceleration. If the smaller force is removed, then the initial force is reduced to \(\frac{4}{5}\) of the initial force. The acceleration of the mass is:
\(\frac{25\,N}{20\,N} = \frac{2.5\,\frac{m}{s^{2}} }{a}\)
\(a = 2\,\frac{m}{s^{2}}\)
The acceleration of the mass is 2 meters per square second.
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Which statements accurately describe sound waves? Check all that apply.
Sound waves are transverse waves.
Sound waves require a medium to transfer energy.
Sound is heard when a vibration strikes the ear.
Sound waves can only travel through liquids and gases.
When particles of a medium interact, part of the wave’s energy is lost.
A wave’s energy can be distinguished from other movements of the medium.
The statements that accurately describe sound waves are:
2,3,4,6
1. Sound waves require a medium to transfer energy. Unlike electromagnetic waves, such as light, sound waves cannot propagate through a vacuum. They need a material medium, such as air, water, or solids, to transfer their energy.
2. Sound is heard when a vibration strikes the ear. Sound is a mechanical wave that is produced by vibrations or oscillations of objects. When these vibrations reach our ears, they are detected by the auditory system, which allows us to perceive sound.
3. When particles of a medium interact, part of the wave's energy is lost. Sound waves experience energy losses due to factors like friction, absorption, and scattering. As the wave propagates through a medium, some of its energy is converted into other forms, such as heat, resulting in a decrease in the wave's intensity.
4. A wave's energy can be distinguished from other movements of the medium. Sound waves carry energy in the form of vibrations or oscillations of particles within a medium. These movements are distinct from other random or uncorrelated motions of the medium's particles that do not contribute to the propagation of the sound wave.
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an electron and a proton are placed close to each other. what is the direction of the electric field due to these charges at some point a great distance from them
A force perpendicular to the electric field will be felt by the proton, and an opposing force will be felt by the electron.
What takes place when an electron and a proton are placed adjacent to one another?
However, a proton and an electron are drawn to one another. Another way to describe it is that similar or "like" charges repel one another, whereas opposite charges attract one another. Because opposing charges are attracted to one another, the negatively charged electrons are drawn to the positively charged protons.
How are electrons created?
a microscopic, negatively charged component found in every atom. Electron streams generated by specialist equipment can be utilized in radiation therapy.
What exactly is a proton?
Each atom's nucleus contains a proton, a subatomic particle. The particle possesses a positive electrical charge that is opposite and equal to that of the electron.
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