Which of the following statements are right and which are wrong? 1. The value of a stock variable can only be changed, during a simulation, by its flow variables. R-W 2. An inflow cannot be negative. R - W 3. The behavior of a stock is described by a differential equation. R - W 4. If A→+B, both variables A and B were increasing until time t, and variable A starts to decrease at time t, then variable B may either start to decrease or keep on increasing but at a reduced rate of increase. R - W 5. If a potentially important variable is not reliably quantifiable, it should be omitted from a SD model. R - W 6. SD models are continuous models: a model with discrete functions cannot be called a SD model since it is not continuous. R - W 7. It is possible that the same real-world system element-for various levels of aggregation and time horizons of interest-is modeled as a constant, a stock, a flow, or an auxiliary. R-W 8. One should also test the sensitivity of SD models to changes in equations of soft variables, table functions, structures and boundaries. R - W 9. SD validation is really all about checking whether SD models provide the right output behaviors for the right reasons. R - W 10. If a SD model produces an output which almost exactly fits the historical data of the last50 years, , it is certainly safe to use that model to predict the outputs 20 years from today. R-W

FALSE. Due to their significant study of requirements engineering, the majority of requirements analysts are recent graduates of software engineering.

Engineering is the use of scientific concepts in the design and construction of equipment, structures, and other items including bridges, tunnels, roads, cars, and buildings. There are other more specialized fields within the engineering discipline, each of which focuses a stronger emphasis on particular areas of applied mathematics, applied science, and application types. There is a glossary for engineering. The Latin terms ingenui, which means "cleverness," and ingeniare, which means "to contrive, devise," are the origin of the English word engineering. Engineering is the creative application of scientific principles to design or develop structures, machines, apparatus, or manufacturing processes, or works utilizing them separately or in combination; or to construct or operate the same while fully cognizant of their design, according to the American Engineers' Council for Professional Development

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The pavement will last between 41 and 50 years with a reliability of 90%.

A road surface, also known as pavement, is a durable surface material that is laid down on an area intended to support vehicular or pedestrian traffic, such as a road or walkway.

First, calculate the number of equivalent single axle loads (ESALS):

ESALS = 600*30 + 1400*20 = 55600.

Next, calculate the design life (L) using the formula: L =

(ESALS/18000)^(1/TSI) * (Ec/PSI)^(-1/2*SD).

Plugging in the values,

L = (55600/18000)^(1/2.5) * (5.5 x 10^6/4.5)^(-1/0.7) = 41.8.

Lastly, calculate the reliability (R) using the formula:

R = (1-LT^(-1/2))*100.

Calculating for a pavement life of 41 years and 50 years gives a reliability of 90% for both values.
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Answer: Three examples of activities that I can perform on a daily basis that involves both metric units (SI units) and customary units include: measuring the length of a door using a tape measure, which includes both SI units and customary units (like feet, inches, and centimeters); baking a cake that requires one teaspoon (customary unit) of baking soda, which could also be converted into four grams (SI unit); weighing myself on a weighing scale, which can be measured by pounds (customary unit) or kilograms (metric unit).

Explanation: I big brain :) (Not Really I Just Wanted To Help) I hope this helped! ;)

Three activities that I can do on a daily basis that involve both metric units (SI units) and customary units are: measuring the length of a door with a tape measure, which includes both SI units and customary units (like feet, inches, and centimeters); baking a cake that calls for one teaspoon (customary unit) of baking soda, which can also be converted to four grams (SI unit); and weighing myself on a weighing scale, which can be measured in pound and kilogram (metric unit).

Answer:Size reduction

Cooling

Mixing

Explanation:

Note that dosage of coagulants is based on viscosity of water. (Option D)

The dosage of coagulants that is administered must always be based on  various factors. Some of them are:

Note that temperature may also affect the dosage because if the water is cold or the lower the temperature, the higher the dosage required.

Thus, it is correct to state that that dosage of coagulants is based on viscosity of water. (Option D)

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Answer:

"Physical" would be the right approach.

Explanation:

So the answer here is just the perfect one.

Before entering the vehicle, you should check for the following things:

1. Check for any obstacles or hazards around the vehicle: Before entering the vehicle, make sure to check for any obstacles or hazards around the vehicle, such as other cars, pedestrians, or objects on the ground.

2. Check the tires: Make sure that the tires are properly inflated and do not have any punctures or other damage.

3. Check the lights: Check that all the lights on the vehicle are working properly, including headlights, taillights, and turn signals.

4. Check the mirrors: Make sure that the mirrors are properly adjusted and free of any obstructions or damage.

5. Check the doors: Make sure that all the doors are properly closed and locked before entering the vehicle.

By checking for these things before entering the vehicle, you can ensure that you are safe and prepared for your journey.

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Tech B is correct it's a verified fact that some auto parts may contain asbestos.

Do auto parts contain asbestos?

Asbestos has been used in a wide range of automotive products, including brakes, clutches, hood liners, gaskets, heat shields, and many others.

Drum and disc brakes were traditionally made with 35% to 60% asbestos. It is still legal in the United States to sell asbestos-containing auto parts, and many brake and clutch parts contain up to 35% asbestos.

Contaminated parts have been found in vehicles of all types, including cars, trucks, motorcycles, buses, trains, and military vehicles. Elevators and other types of transportation machinery also used asbestos brakes.

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Technician A and Technician B are correct in their assessments. A restricted vacuum feed hose can cause loss of Braking assistance after several quick brake applications, and brake fluid in the vacuum feed hose can indicate a leaking master cylinder seal.

Technician A is correct in saying that a restricted vacuum feed hose may cause a loss of assist after several quick brake applications. This is because the vacuum feed hose provides necessary vacuum pressure to the brake booster, which assists in braking. If the hose is restricted, the brake booster may not receive adequate vacuum pressure, leading to a decrease in braking assistance after multiple quick brake applications.
Technician B is also correct in stating that brake fluid in the vacuum feed hose can indicate a leaking master cylinder seal. The master cylinder contains brake fluid and is responsible for converting the driver's input through the brake pedal into hydraulic pressure. A leaking master cylinder seal can allow brake fluid to enter the vacuum feed hose, which is not designed to handle such fluids. This can be an indication that the master cylinder needs repair or replacement.
In conclusion, both Technician A and Technician B are correct in their assessments. A restricted vacuum feed hose can cause loss of braking assistance after several quick brake applications, and brake fluid in the vacuum feed hose can indicate a leaking master cylinder seal.

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The capacitive reactance of a DC series circuit increases when its capacitance decreases and vice-versa.

A DC series circuit can be defined as a type of circuit in which all of its resistive components are connected end to end, so as to form a single path for the flow of current.

This ultimately implies that, the same amount of current flows through a direct current (DC) series circuit.

Mathematically, the capacitive reactance of a DC series circuit is given by this formula:

\(X_C = \frac{1}{2\pi fC}\)

Where:

From the above formula, we can deduce that the capacitive reactance of a DC series circuit is inversely proportional to both frequency and capacitance. Thus, the capacitive reactance of a DC series circuit increases when its capacitance decreases and vice-versa.

In conclusion, a capacitor would influence a simple DC series circuit by blocking the flow of direct current (DC) through it.

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Suppose cond1 and cond2 are two boolean expressions. When both cond1 and cond2 are true, the if condition will be true.

Alternatively, if only one of the conditions (either cond1 or cond2) is true, the if condition will still be false. Therefore, both cond1 and cond2 must be true for the if condition to be true. It's important to note that the order of the conditions does not matter. Additionally, if cond1 or cond2 are not boolean expressions, an error will occur. It's also possible to use logical operators such as "and" or "or" to combine multiple boolean expressions in a more complex if statement.

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Answer:

The correct answer is "1341.288 W/m".

Explanation:

Given that:

T₁ = 300 K

T₂ = 500 K

Diameter,

d = 0.2 m

Length,

l = 1 m

As we know,

The shape factor will be:

⇒ \(SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}\)

By putting the value, we get

⇒       \(=\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}\)

⇒       \(=3.7258 \ l\)

hence,

The heat loss will be:

⇒ \(Q=SF\times K(T_2-T_1)\)

       \(=3.7258\times 1\times 1.8\times (500-300)\)

       \(=3.7258\times 1.8\times (200)\)

       \(=1341.288 \ W/m\)

The relative velocity is defined as the velocity of an object with respect to another observer. It is the time rate of change of relative position of one object with respect to another object.

The relative velocity of A with respect to B= velocity of the body A – velocity of the body B.

The relative velocity formula is expressed as. V → = V A B → + V B C → Where. VAB is the velocity with respect to A and B, VBC is the velocity with respect to B and C and VAC is the velocity with respect to A and C.

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Answer:

See attachment

Explanation:

The attached picture shows a problem identical to this one except the diameter of the balloon is defined. The provided problem can be solved in terms of the balloon's diameter using the same procedure.

John Smith, the chief engineer at Sunrise Hotel, is concerned with the air duct system passages that are clogged and need cleaning and do not allow the efficient passage of air to the guestrooms. This concern is related to the ventilation load.

What is a ventilation load? A ventilation load is the air that enters and exits a building due to the required need to ventilate the building. There are three main types of ventilation loads, namely natural ventilation, mechanical ventilation, and mixed-mode ventilation. The goal of ventilation is to regulate the air movement inside the building, especially in the air duct system passages and air conditioning unit. The proper functioning of the air duct system passages is essential for the efficient passage of air in the building.

For instance, air duct systems are responsible for supplying air to an HVAC unit, distributing air throughout the building, and returning the air to the air handler for further processing before being redistributed throughout the building. If the air duct system passages are clogged and need cleaning, it means that they do not allow efficient passage of air to the guestrooms. Therefore, John Smith, the chief engineer at Sunrise Hotel, is concerned about the ventilation load due to the clogged air duct system passages.

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Answer:

a) 4160 V

b) 12 kW and 81 kVAR

c)  54 kW and 477 kVAR

Explanation:

1) The phase voltage is given as:

\(V_p=\frac{3810.5}{\sqrt{3} }=2200 V\)

The complex power S is given as:

\(S=560.1(0.707 +j0.707)+132=660\angle 36.87^o \ KVA\)

\(where\ S^*\ is \ the \ conjugate\ of \ S\\Therefore\ S^*=660\angle -36.87^oKVA\)

The line current I is given as:

\(I=\frac{S^*}{3V}=\frac{660000\angle -36.87}{3(2200)} =100\angle -36.87^o\ A\)

The phase voltage at the sending end is:

\(V_s=2200\angle 0+100\angle -36.87(0.4+j2.7)=2401.7\angle 4.58^oV\)

The magnitude of the line voltage at the source end of the line (\(V_{sL}=\sqrt{3} |V_s|=\sqrt{3} *2401.7=4160V\)

b) The Total real and reactive power loss in the line is:

\(S_l=3|I|^2(R+jX)=3|100|^2(0.4+j2.7)=12000+j81000\)

The real power loss is 12000 W = 12 kW

The reactive power loss is 81000 kVAR = 81 kVAR

c) The sending power is:

\(S_s=3V_sI^*=3(2401.7\angle 4.58)(100\angle 36.87)=54000+j477000\)

The Real power delivered by the supply = 54000 W = 54 kW

The Reactive power delivered by the supply = 477000 VAR = 477 kVAR

Answer:

A-personal income in a year this is the answer

Solution :

import \($\text{java}.$\)util.*;

public \($class$\) currency{

  public static \($\text{void}$\) main(String\($[]$\) args) {

      Scanner input \($=$\) new Scanner(System\($\text{.in}$\));

      System\($\text{.out.}$\)print("Enter \($\text{number of}$\) quarters:");

      int quarters = input.nextInt();

      System.out.print("Enter number of dimes:");

      int \($\text{dimes =}$\) input.nextInt();

      System\($\text{.out.}$\)print("Enter number of nickels:");

      int nickels = input.nextInt();

      System\($\text{.out.}$\)print("Enter number of pennies:");

      int \($\text{pennies = }$\) input.nextInt();

      // computing dollors

      double dollars = (double) ((quarters*0.25)+(dimes*0.10)+(nickels*0.05)+(pennies*0.01));

      System\($\text{.out.}$\)format("You have : $%.2f",dollars);

  }

}

Answer:

Explanation:

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Rosie Milojevic, Business Development at iComplied

Answered 3 years ago

For those who run or work in a business that handles food, you understand the importance of food safety and regulation compliance as it pertains to not only to certification and licensing of a company, but also the life or death of those who consume the products. Because food safety is such an important issue, we want to ensure that all companies who work in the production, preparation, or processing of food have the tools and information they need to ensure they are in full compliance 100% of the time. One slip in food safety compliance could cost someone their health or life, and this information spreads mistrust in the general public toward the company who sold the product, and also the entire product across companies throughout an entire country and beyond. So how does each company working with food ensure they comply with each and every food safety regulation? Through excellent auditing tools.

Auditing in Food Safety Must Change

Auditing in food safety compliance is essential in ensuring that all regulations are being complied with. Most auditing practices for major companies are severely out of date. Many rely on several different forms, stacks of paperwork, and data stored on multiple different computers and databases. This is incredibly inefficient, as it can be easy to miss something when comparing one sheet to the next, and paper can easily be lost or destroyed. It is also time consuming for companies to share audits over separate computers and databases, as it must be passed down from one employee to the next. Technology has granted all food safety compliance managers a simple solution. Auditing apps are the new wave solutions for companies who want all of their data stored on one cloud database that is instantly accessible with real-time data for all employees. This means that no one ever gets left out of the loop, and no new information will fall through the cracks.

The rooftop solar is a form of solar energy that can be installed on the roof of a home or business. It is cost-effective, environmentally friendly, and provides many benefits to homeowners and businesses.

The rooftop solar has many advantages over other forms of solar energy. One of the main advantages is that it provides 100% clean electricity from renewable sources. In addition, it can be combined with other sources such as wind power and geothermal power for even more benefits.

There are also many uses for rooftop solar panels in homes and businesses. One example is using it to heat water for hot water systems or heating swimming pools.

For me Bluebird Solar Private Limited is the best website in India for rooftop solar panels in India.

Answer:

a) Irreversible, b) Reversible, c) Irreversible, d) Impossible.

Explanation:

Maximum theoretical efficiency for a power cycle (\(\eta_{r}\)), no unit, is modelled after the Carnot Cycle, which represents a reversible thermodynamic process:

\(\eta_{r} = \left(1-\frac{T_{C}}{T_{H}} \right)\times 100\,\%\) (1)

Where:

\(T_{C}\) - Temperature of the cold reservoir, in Kelvin.

\(T_{H}\) - Temperature of the hot reservoir, in Kelvin.

The maximum theoretical efficiency associated with this power cycle is: (\(T_{C} = 400\,K\), \(T_{H} = 1200\,K\))

\(\eta_{r} = \left(1-\frac{400\,K}{1200\,K} \right)\times 100\,\%\)

\(\eta_{r} = 66.667\,\%\)

In exchange, real efficiency for a power cycle (\(\eta\)), no unit, is defined by this expression:

\(\eta = \left(1-\frac{Q_{C}}{Q_{H}}\right) \times 100\,\% = \left(\frac{W_{C}}{Q_{H}} \right)\times 100\,\% = \left(\frac{W_{C}}{Q_{C} + W_{C}} \right)\times 100\,\%\) (2)

Where:

\(Q_{C}\) - Heat released to cold reservoir, in kilojoules.

\(Q_{H}\) - Heat gained from hot reservoir, in kilojoules.

\(W_{C}\) - Power generated within power cycle, in kilojoules.

A power cycle operates irreversibly for \(\eta < \eta_{r}\), reversibily for \(\eta = \eta_{r}\) and it is impossible for \(\eta > \eta_{r}\).

Now we proceed to solve for each case:

a) \(Q_{H} = 900\,kJ\), \(W_{C} = 450\,kJ\)

\(\eta = \left(\frac{450\,kJ}{900\,kJ} \right)\times 100\,\%\)

\(\eta = 50\,\%\)

Since \(\eta < \eta_{r}\), the power cycle operates irreversibly.

b) \(Q_{H} = 900\,kJ\), \(Q_{C} = 300\,kJ\)

\(\eta = \left(1-\frac{300\,kJ}{900\,kJ} \right)\times 100\,\%\)

\(\eta = 66.667\,\%\)

Since \(\eta = \eta_{r}\), the power cycle operates reversibly.

c) \(W_{C} = 600\,kJ\), \(Q_{C} = 400\,kJ\)

\(\eta = \left(\frac{600\,kJ}{600\,kJ + 400\,kJ} \right)\times 100\,\%\)

\(\eta = 60\,\%\)

Since \(\eta < \eta_{r}\), the power cycle operates irreversibly.

d) Since \(\eta > \eta_{r}\), the power cycle is impossible.

Transformers are used in electrical distribution systems to safely and efficiently increase or decrease voltage.

What is Transformer ?

           A transformer is a passive component that transfers electrical energy from one circuit to another, or from multiple circuits. A changing current in any of the transformer's coils causes a changing magnetic flux in the core, which induces a changing electromotive force (EMF) across any other coils wound around the same core. Without a metallic connection between the two circuits, electrical energy can be transferred between separate coils. Faraday's law of induction, discovered in 1831, describes the induced voltage effect in any coil caused by a changing magnetic flux that surrounds the coil.

              Transformers are used to change AC voltage levels, with step-up and step-down transformers used to increase and decrease voltage levels, respectively. Transformers can also be used to provide galvanic isolation between circuits and to couple signal-processing circuit stages. Transformers have been essential for the transmission, distribution, and utilisation of alternating current electric power since the invention of the first constant-potential transformer in 1885.

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Answer:

true

Explanation:

Answer:

A) True

Explanation:

Answer:

A. true

Explanation:

cause if they dont they could possibly get sgut down for safety hazards and violations of its' employee. And there could be a asccident because there was no safety.

Answer:

A

Explanation:

Answer:

Hello your question is incomplete attached below is the complete question

answer :

a) 95.80°C

b) 8.23 MW

Explanation:

Convection heat transfer coefficient = 860 W/m^2 . k

a) Calculate for the temp of sheet metal when it leaves the oil bath

first step : find the Biot number

Bi = hLc / K  ------- ( 1 )

where : h = 860 W/m^2 , Lc = 0.0025 m ,  K = 60.5 W/m°C

Input values into equation 1 above

Bi = 0.036 which is < 1  ( hence lumped parameter analysis can be applied )

next : find the time constant

t ( time constant ) = h / P*Cp *Lc  --------- ( 2 )

where : p = 7854 kg/m^3 , Lc = 0.0025 m , h = 860 W/m^2, Cp = 434 J/kg°C

Input values into equation 2 above

t ( time constant ) = 0.10092 s^-1

Determine the elapsed time

T = L / V = 9/20 = 0.45 min

∴   temp of sheet metal when it leaves the oil bath

= (T(t) - 45 ) / (820 - 45)  = e^-(0.10092 * 27 )

T∞ =  45°C

Ti = 820°C

hence : T(t) = 95.80°C

b) Calculate the required rate of heat removal form the oil

Q = mCp ( Ti - T(t) ) ------------ ( 3 )

m = ( 7854 *2 * 0.005 * 20 ) = 26.173 kg/s

Cp = 434 J/kg°C

Ti =  820°C

T(t) = 95.80°C

Input values into equation 3 above

Q = 8.23 MW

Answer:

A power supply unit (PSU) converts mains AC to low-voltage regulated DC power for the internal components of a computer. Modern personal computers universally use switched-mode power supplies

Answer:

Volt is the SI (Standard International) unit of electrical potential of the..

Explanation:

Example 21.17 shows that a 3.3 μF capacitor is charged to 300 V and is then connected to a 5.6 μF capacitor through a switch S. The charge sharing between the two capacitors and the final voltage are to be determined.The original voltage across the 3.3 μF capacitor isQ = CV = (3.3 × 10-6 F)(300 V) = 0.99 mCWhen S is closed, the charge on each capacitor will be equal and given byQ = CV1 = CV2where V1 and V2 are the voltages across the 3.3 μF and 5.6 μF capacitors, respectively.

The equivalent capacitance of the two capacitors in series is

Ceq = (C1C2)/(C1 + C2)

= (3.3 × 10-6 F)(5.6 × 10-6 F)/(3.3 × 10-6 F + 5.6 × 10-6 F)

= 2.105 × 10-6 F

The final voltage across the capacitors is then

V = Q/Ceq

= (0.99 mC)/(2.105 × 10-6 F)

= 471.54 V

If the dielectric constant of the slab that is slid between the plates of the capacitor had been 5 rather than 3.3, the capacitance of the 3.3 μF capacitor would have increased by a factor ofκ = 5/3.3 = 1.5151

The original capacitance isC1 = 3.3 μFThe new capacitance is

C1' = κC1

= (1.5151)(3.3 × 10-6 F)

= 4.9983 μF

The equivalent capacitance of the two capacitors in series is

Ceq' = (C1'C2)/(C1' + C2)

= (4.9983 × 10-6 F)(5.6 × 10-6 F)/(4.9983 × 10-6 F + 5.6 × 10-6 F)

= 2.4289 × 10-6 F

The final voltage across the capacitors is then

V' = Q/Ceq'

= (0.99 mC)/(2.4289 × 10-6 F)

= 407.73 V

Therefore, if the dielectric constant of the slab that is slid between the plates of the capacitor had been 5 rather than 3.3, the final voltage across the capacitor would have been 407.73 V instead of 471.54 V.

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