Which of these is an example of heat transfer by conduction?

cooking carrots in hot water


drying hair with a blow dryer


pressing a shirt with an iron


warming water with sunlight

When air drag affects the motion of projectiles, they don't travel B. as far.

This is because air drag acts as a force that opposes the motion of the projectile, slowing it down as it moves through the air. This effect is more pronounced at higher speeds and for objects with larger surface areas, such as a basketball or a feather. The force of air resistance increases as the projectile's speed increases, and eventually, it will reach a point where the force of air resistance is equal to the force of gravity pulling the object down.

At this point, the object will no longer accelerate and will reach its maximum range. This means that the projectile will not travel as far as it would if there were no air resistance. However, the effect of air resistance on the height of the projectile is minimal, so projectiles affected by air drag will still travel at similar heights to those not affected by air drag. Therefore, the correct answer to the question is B) as far.

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Answer:

Point a

Explanation:

The potential energy of an object is given by :

P = mgh

m is mass, g is acceleration due to gravity, h is height above ground level.

Potential energy is directly proportional to the position of an object.

In the attached figure, the maximum height is shown at point (a). It means it will have maximum potential energy at a as compared to b,c and d.

The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.

In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.

The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.

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Using the equilibrium equation, we find that the tension, T1, is approximately 253.49 N.

The tension, T1, in the given scenario is calculated using the equations of equilibrium. When solving for T1, we consider the forces acting on the cement bag along the vertical direction.

The vertical component of the tension T1 can be equated to the weight of the cement bag. The weight of an object is given by the product of its mass and the acceleration due to gravity (9.8 m/s^2):

T1 * sin(θ1) = m * g

Substituting the values:

T1 * sin(75.00°) = 25.0 kg * 9.8 m/s^2

Calculating the right side of the equation:

T1 * sin(75.00°) = 245.0 N

Now, solving for T1:

T1 = 245.0 N / sin(75.00°)

Using a calculator to find the sine value:

T1 = 245.0 N / 0.9659

T1 ≈ 253.49 N

Therefore, the tension, T1, is approximately 253.49 N.

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Answer:

6.58×10⁻¹⁸ J

Explanation:

Applying

E = kq²/r.................. Equation 1

Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.

From the question,

Given: r = 3.5×10⁻¹¹ m,

Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)

E = 6.58×10⁻¹⁸ J

\(\large\mathrm{A. Power\:\: will \:\:Increase }\)

We know that,

\(\large \mathrm{ \boxed{P = I²R}}\)

where,

And when resistance is constant, the power of the circuit will change proportionally with the change in electric current. therefore, if current increases then the electric power of the circuit will increase too.

\(\large\mathfrak{{\pmb{\underline{\orange{hope \: \: i t \: \: helps \: \: you}}{\orange{.....}}}}}\)

The speaker most likely think about the wall that The wall protects his orchard. Hence option A is correct.

The term wall is derived from the Latin word vallum, which denotes "...an earthen wall or rampart set with palisades, a row or line of stakes, a wall, a rampart, fortification...", whereas murus is a defensive stone wall. The same word is used in English to refer to an exterior wall and the inside sides of a room, but this is not ubiquitous. Many languages differentiate between the two. Some of this contrast may be observed in German between Wand and Mauer, and in Spanish between pared and muro.The wall protects his orchard.

Hence option A is correct.

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It is possible to have a non-zero electric field even when the velocity is zero, and it is possible to have a non-zero velocity even when the electric field is zero.

The relationship between the electric field (E) and the magnetic field (B) is given by Maxwell's equations. In particular, one of Maxwell's equations states that a changing magnetic field induces an electric field, and a changing electric field induces a magnetic field. This means that the electric and magnetic fields are intertwined and can affect each other.

Therefore, if v (velocity) is zero at a point in space, it does not necessarily mean that E (electric field) is zero at that point. For example, in a static electric field produced by a charged particle, the electric field at a point can be non-zero even if the velocity of the particle producing the field is zero.

On the other hand, if E is zero at some point, it does not necessarily mean that v is zero at that point. For example, in a uniform magnetic field, the electric field is zero, but charged particles moving through the field experience a force that causes them to move in a circular path, resulting in non-zero velocity. Similarly, in a vacuum, the electric field is zero, but particles moving with non-zero velocity will still have kinetic energy.

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Answer:

The trains will be 435 miles apart

Explanation:

Distance covered by the two trains can be obtained by multiplying their speeds with the time frame under consideration - in this our case, it is  3hours.

For Train A

Distance covered = 80mph X 3 hours = 240miles

For train B

Distance covered = 65mph X 3 hours = 195 miles.

The total distance between the two trains after 3 hours will be

240 + 195 = 435 miles

a) The weight of the box of textbooks can be calculated as follows;

Weight of

box= mass × acceleration due to gravity

Where mass= 55 kg

Acceleration due to

gravity= 9.8 m/s²Thus, the weight of the box of textbooks is given by;

Weight of

box= 55 kg× 9.8 m/s²= 539 N

the weight of the box of textbooks is 539 N.

b) The coefficient of friction can be calculated using the formula;Coefficient of friction= frictional force/ Normal forceWhere, frictional force is the force required to keep the box moving at constant velocity and normal force is the force acting on the box perpendicular to the surface on which the box is resting.

The force F of the student pushing the box can be resolved into its horizontal and vertical components as follows;

F_x= 320 N (this is the horizontal component of the force)F_y=

(This is the vertical component of the force)Thus, the normal force on the box is given by;

F_y= Normal forceNormal force= weight of box= 539 NThe frictional force is given by.

F_f= F_x= 320 NThe coefficient of friction is given by;Coefficient of friction= frictional force/ Normal forceCoefficient of friction= F_f/ F_yCoefficient of friction= 320 N/ 539 NCoefficient of friction= 0.593Therefore, the coefficient of friction is 0.593.

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Our atmosphere is transparent to solar radiation, but it traps the energy that causes the greenhouse effect because the solar energy absorbed by Earth is reradiated as longer-wavelength radiation.

The atmosphere is transparent to incoming solar radiation, which is mostly visible light and short-wavelength radiation. However, the Earth absorbs some of this solar radiation and heats up.

The Earth then radiates this heat energy back out to space as longer-wavelength radiation, mostly in the form of infrared radiation. The greenhouse gases in the atmosphere, such as carbon dioxide and water vapor, are able to absorb this longer-wavelength radiation and trap some of the heat energy in the atmosphere, causing the greenhouse effect.

Hence, this is why the atmosphere is transparent to solar radiation but traps the energy that causes the greenhouse effect.

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The Earth-Sun system consists of the Earth and the Sun, with the Earth orbiting around the Sun due to the gravitational attraction between the two bodies. The center of mass of the Earth-Sun system is located at a point called the barycenter, which is inside the Sun but not at its exact center.

The Earth-Sun system is a celestial system where the Earth and the Sun interact gravitationally. The Sun is a star located at the center of our solar system, while the Earth is a planet that orbits around the Sun. This orbit is elliptical, meaning that the Earth's distance from the Sun varies over the course of its orbit.

According to Newton's law of universal gravitation, both the Earth and the Sun exert gravitational forces on each other. These forces cause the Earth to move in an orbit around the Sun. The center of mass of a system is the point around which the masses of the objects in the system are evenly distributed. In the Earth-Sun system, the center of mass is called the barycenter. Due to the Sun's much larger mass compared to the Earth, the barycenter is located within the Sun, but not exactly at its center. It is slightly offset towards the Earth. This means that while the Earth orbits around the Sun, both objects actually orbit around the common center of mass, or barycenter, of the system.

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Explanation:

what is time in this question

An object's thermal energy and temperature rise as a result of heat flow into the thing. Three factors determine the amount of temperature increase: 1) The amount of heat added, 2) the object's size, and 3) the substance used to create the object.

The average kinetic energy of an object's particles rises as its temperature rises. The thermal energy of the object grows as the average kinetic energy of its constituent particles rises. Therefore, when an object's temperature rises, so does its thermal energy.

Thermal energy is added to a substance during heating. As a result, its temperature increases and its particle motion accelerates. When a substance cools, thermal energy is lost, which slows down the movement of its particles and lowers the substance's temperature.

When heat enters an object, both its temperature and thermal energy rise. There are three factors that affect how much the temperature rises: The amount of heat added, the object's size, and the material it is made of are the first three variables.

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Answer:

momentum is a vector, KE is scalar. Bodies moving in opposite directions have offsetting momentum, but the KE does not offset.

Explanation:

Answer:

E₀ = 5.97 10⁸ N / C

Explanation:

Coulomb's law in a material medium is written

       \(F = \frac{1}{4\pi \epsilon } \frac{q_{1} q_{2} }{r^{2} }\)

ε is the electrical permittivity of the material

Electric field and force are related        

          F = q E

in dielectric materials such as mica there is an electric field inside the material that decreases the external field

           E = E₀ /ε

where ε is the electrical permittivity of the material; in general it is tabulated in the form

           \(\epsilon _{r} =\frac{\epsilon}{\epsilon_{o}}\)

          \(\epsilon = \epsilon_{r} \ \epsilon_{o}\)

we substitute

          F = q E₀ /  \epsilon_{r}  \epsilon_{o}

         \(E_{o} = \frac{F \ \epsilon_{r} \ \epsilon_{o} }{q}\)

for the case of mica it is equal to er = 5.4 and suppose a test charge equal to the charge of the electron

we calculate

          E₀ = 2  5.4  8.85 10⁻¹² / 1.6 10⁻¹⁹

          E₀ = 59.74 10⁷

          E₀ = 5.97 10⁸ N / C

The momentum conservation allows to find the final speed of the cars together are:

The momentum is defined by the product of the mass and the speed of the body.

        p = m v

Where the bold letters indicate vector, p is the moment, m is the mass and v the velocity.

If we define the system as formed by the two bodies, the forces during the collision are internal and the momentum is preserved, let's find the moment in two instants.

Initial instant. Before crash.

       p₀ = m v₀₀₀+ m v₀₂

Final moment. After the crash.

      \(p_f = 2m \ v\)

The moment is preserved.

      \(p_o =p_f \\m v_o + m v_o_2 = 2m \ v\)  

     \(v = \frac{m v_o + v_o_2}{2m}\\ v = \frac{1}{2} \ ( v_o + v_o_2)\)

We have two cases:

       v = v₀ / 2

       v = 0

In conclusion using the momentum conservation we can find the final velocity of the cars together are:

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The angle necessary to keep a 10 kg box motionless, given a coefficient of static friction of 0.55 between the box and the ramp, is 33.4°, which corresponds to Option A.

To determine the angle, we can use the relationship between the coefficient of static friction, the angle of the incline, and the gravitational force acting on the box. The maximum static friction force can be calculated using the formula:

Friction force = coefficient of static friction * Normal force

The Normal force can be found by decomposing the gravitational force acting on the box into components parallel and perpendicular to the incline. The perpendicular component (Normal force) is equal to the weight of the box (mass * gravitational acceleration).

Since the box is motionless, the friction force must be equal to the component of the gravitational force acting parallel to the incline:

Friction force = Component of weight parallel to incline

By substituting the given values and solving for the angle, we find:

coefficient of static friction = tan(angle)

angle = arctan(coefficient of static friction)

angle = arctan(0.55) ≈ 33.4°

Therefore, the correct answer is Option A, 33.4°.

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The distance of the test charge from the source charge is 1.1 m. Option A is correct.

It states that the electric flux across any closed surface is directly proportional to the net electric charge enclosed by the surface.\(R= \sqrt \dfrac {Qk^}E\)

Where,

\(E\) = electric force = 3. 93 × 10⁵  N/C

\(k\) = Coulomb constant = \(8.99 \times 10^9 \rm\ N m ^2 /C ^2\)

\(Q\\ \)     = charges =  5.0 µC

\(r\) = distance of separation =?

Put the values in the formula,

\(R= \sqrt \dfrac {5\times 10^{-6}8.99 \times 10^9}{3. 93 \times 10^5}}\\\\ R = 1.1 \rm \ m\)

Therefore, the distance of the test charge from the source charge is 1.1 m.

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The answers is 30 miles per hour, the driver is speeding the car up,     section-H, 12 minutes, section-D, and 65 miles per hour.

If the first thing that the goslings saw was a dog, they would have followed the dog as a mother.

Imprinting refers to the process of training an animal to bond with anything it sees after birth even if it is not its real mother. Lorenz first achieved imprinting in 1935 using geese which followed him as their mother shortly after they were born.

If the geese were exposed to a dog, they could also have seen the dog as their mother and followed it accordingly shortly after birth.

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The force felt by the larger test charge would be twice as large as the force felt by the original test charge.

This is because the force felt by a test charge in an electric field is directly proportional to the magnitude of the test charge. The electric field is a vector field and the force experienced by a test charge is given by the product of the charge of the test particle and the electric field at that point.

So, when the magnitude of the test charge is doubled, the force experienced is also doubled. Therefore, if a test charge of magnitude twice as large as the original test charge were placed at point a, it would feel twice the force that the original test charge felt when it was placed at that same point.

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Part A: To determine the rate at which heat is discarded to the environment by the power plant, we need to calculate the heat input to the power plant and then subtract the useful work output.

Given:

Power output of the steam turbine = 518 MW

Thermal efficiency of the power plant = 40% or 0.40

The thermal efficiency is defined as the ratio of the useful work output to the heat input:

Thermal efficiency = (Useful work output) / (Heat input)

Rearranging the equation, we can solve for the heat input:

Heat input = (Useful work output) / (Thermal efficiency)

Calculations:

Heat input = (518 MW) / (0.40) = 1295 MW

Since the thermal efficiency represents the fraction of the heat input that is converted into useful work, the remaining fraction is the heat discarded to the environment:

Heat discarded = Heat input - Useful work output

Heat discarded = 1295 MW - 518 MW = 777 MW

Therefore, the rate at which heat is discarded to the environment by this power plant is approximately 777 MW.

Part B: To determine the rate at which heat must be supplied to the power plant by burning coal, we use the thermal efficiency and the heat input calculated in Part A.

Heat input = 1295 MW

Therefore, the rate at which heat must be supplied to the power plant by burning coal is approximately 1295 MW.

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The speed of the coin just before it hits the ground dropped from a height of 80 m will be 40 m / s

The total PE at the greatest height = The K.E just before it touches the ground

PE = m g h

KE = 1 / 2 * mv²

PE = Potential energy

KE = Kinetic energy

m = Mass

g = Acceleration due to gravity

h = Height

v = Final velocity

h = 80 m

g = 10 m / s²

PE = KE

m g h = 1 / 2 * mv²

m * 10 * 80 = 1 / 2 * m * v²

v² = 800 * 2

v = √ 1600

v = 40 m / s

Potential energy is the energy at rest and kinetic energy is the energy in motion. Potential energy is maximum at rest and when the object starts to move, it potential energy drops and it kinetic energy rises.

Therefore, the speed of the coin just before it hits the ground is 40 m / s

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The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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The current flowing through each wire is the experiment's independent variable because it is the one that the experimenter is actively manipulating and controlling.

The resistance is influenced by the wire's thickness, so the thicker the wire, the lower the resistance. Because less water can flow through a narrower pipe in a given length, there is more resistance in a narrower pipe.

Due to the alloy composition of nichrome wire, its resistance is quite high. Because of this, it generates a lot of heat when current flows through it, making it extremely hot to the touch.

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Answer:

38 years old.

Explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this particular Question;

1=> The three children are A, B and C respectively.

2=> "the present age of husband is 5 years more than the wife's age."

3=> " the wife's age is twice the present age of A"

4=> the present age of A is 12 years more than the present age of B "

5=> B's present age is one and a half times the present age of C .

6=> "if C is 12 years old at present "

7=> "husband's friend Ram who is 15 years younger than the husband"

We will start from point 5 above that is to say;

B = C × 3/2. = 12 × 3/2 = 6 × 3= 18.

Also, A = 12 + B = 12 + 12= 24.

From the point 3 Above; the wife's age= 2 × A= 2 × 24 = 48 years of age.

From the point 2, we have that the husband's age = 5 + 48 = 53 years of age.

Thus, the present age of husband's friend, Ram who is 15 years younger than the husband = 53 - 15 = 38 years old

Answer:

To describe motion accurately and completely, a frame of reference is necessary. frame of reference ( or reference frame) consists of an abstract coordinate system and the set of physical reference points that uniquely fix ( locate and orient ) the coordinate system and standardize measurements within that frame.

Explanation:

The different observations occur because the two observers are in different frames of reference. A frame of reference is a set of coordinates that can be used to determine positions and velocities of objects in that frame; different frames of reference move relative to one another.

The coefficient of kinetic friction between ice and puck is 0.01867. To solve for the coefficient of kinetic friction between ice and puck, we need to use the equation below. μk = (2m(g+ax))/ρACf

μk = (2m(g+ax))/ρACf , Where μk = coefficient of kinetic friction, m = mass of puck, g = acceleration due to gravity (9.8 m/s²), ax = acceleration due to kinetic friction, ρ = density of ice (917 kg/m³), A = area of contact between puck and ice

Cf = drag coefficient

The area of contact between the puck and ice can be calculated by A = πr², and

the radius of a hockey puck is 2.54 cm

= 0.0254 m.

Substituting the given values in the above equation,

we have; 0.0254²π

= 0.0005069 m²,

m = 0.16 kg

g = 9.8 m/s²

a = (v₂² - v₁²)/2d

= (10.39² - 10.50²)/2(-43)

= 0.0002819 m/s²ax

= -a = -0.0002819 m/s²ρ

= 917 kg/m³

Cf = 0.5 (for a smooth sphere),

μk = (2m(g+ax))/ρACf

= (2 * 0.16 * (9.8 - 0.0002819))/(917 * 0.0005069 * 0.5)

= 0.01867

So, the coefficient of kinetic friction between ice and puck is 0.01867.

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