Which of these is NOT correct?1. Kinases are enzymes that phosphorylate other molecules.2. Cyclic AMP binds to calmodulin.3. Ion channels are found on both the plasma membrane and the endoplasmic reticulum.4. Tyrosine-kinase receptors consist of two polypeptides that join when activated by a signal molecule.5. Phospholipase C catalyzes the formation of IP3.

Answer:

Cu(NO3)2 (aq) + K2CO3 (aq) => CuCO3 (s) + 2KNO3 (aq)

Explanation:

I interpret your question is how to balance the above reaction, right?

Cu(NO3)2 (aq) + K2CO3 (aq) => CuCO3 (s) + 2KNO3 (aq)

Cu: 2

NO3: 2

K: 2

CO3: 2

Answer: Pentane C5H12

Explanation:

The boiling point of a substance is simply defined as the temperature whereby a liquid's vapor pressure is equal to the pressure that is surrounding the liquid and hence, the liquid will changes into vapor.

The likely molecular formula for this compound is Pentane i.e C5H12 due to the fact that its boiling point is between Butane with formula C4H10 and Hexane with formula C6H14 boiling points.

The molecular formula of the of the substance is \(\bold {C_5H_1_0}\) (pentane).

Boiling point:

It is the temperature at which liquid's vapor pressure is equal to the pressure that is surrounding the liquid and hence, the liquid start to into vaporize.

The boiling point of the given compound is 309 K which is between Butane  and Hexane.

Therefore, the molecular formula of the of the substance is \(\bold {C_5H_1_0}\) (pentane).

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When a cylinder is filled to a volume of 3.50 L at 760 mmHg with chlorine gas. The volume of the gas if the pressure is changed to 50.0 kPa is 7.0924 L.

Boyle's law is generally a gas law which states that "a gas's pressure and volume are inversely proportional when the temperature is kept constant, as volume increases, pressure falls and vice versa".

Mathematically,

P₁V₁ = P₂V₂

P₁ = 760 mmHg = 101.32 kPa

V₁ = 3.50 L

P₂ = 50 kPa

V₂ = ?

Substituting the values we get,

101.32 × 3.50 = 50 × V₂

⇒ V₂ = (101.32 × 3.50)/50

⇒ V₂ = 7.0924 L

Hence, the volume of the gas if the pressure is changed to 50.0 kPa is 7.0924 L.

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Life will come out to be 10 days. This is the required value of half life.

what is radioactive isotope?

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Answer:

A. Loam soil is best for planting

Thank you....

Have a good day....

Answer:

Explanation:

Step 1: Data given

The equilibrium constant, Kc, for the following reaction is 4.76 * 10^-4 at 431 K

The equilibrium concentration of Cl2(g) is  0.233 M

Step 2: The balanced equation

PCl5(g)  ⇄ PCl3(g) + Cl2(g)

Step 3: The initial concentration

[PCl5]= Y M

[PCl] = 0M

[Cl2] = 0M

Step 4: Calculate the concentration at equilibrium

[PCl5] = Y + X M = Y - 0.233 M

[PCl]= XM = 0.233 M

[Cl2]= XM = 0.233 M

Step 5: Define Kc

Kc =  [Cl2]* [PCl3] / [PCl5]

4.76 * 10^-4 = 0.233² / (Y -0.233)

0.000476 = 0.05429 / (Y - 0.233)

Y - 0.233 = 0.05429 / 0.000476

Y - 0.233 = 114.05 M

Y = 114.283 M = the initial concentration

The concentration of PCl5 at the equilibrium is 114.05 M

Answer:

you can identify an unknown substance by measuring its density and comparing your results to a list of known densities. Density=mass/volume. Assume that you have to identify an unknown metal. You can determine the mass of the metal on a scale.

Step 1

Data provided:

The reaction: 4Al + 3O2 => 2Al2O3 (balanced)

The limiting reactant Al (it is said that Al reacts completely)

Mass of Al = 42.6 g

The actual yield = 57.8 g Al2O3

-----------------------

Step 2

Data needed: the molar mass of Al (26.9 g/mol) and Al2O3 (101.9 g/mol)

The theoretical yield:

4 x 26.9 g Al ------- 2 x 101.9 g Al2O3

42.6 g Al ------- X = 80.7 g Al2O3 = theoretical yield

---------------------

Step 3

% yield = (actual yield/theoretical yield) x 100 = (57.8 g/80.7 g) x 100 = 71.6 %

(this is the closest value for one of the options, 71.8 %)

Answer: 71.8 %

The correct fraction that  can be used for the mole ratio to determine the mass of Cl2 from a known mass of AlCl3 is 2/2.

The mole ratio is a way of expressing the ratio of the number of moles of one substance in a chemical reaction to the number of moles of another substance in the same reaction.

Mole ratio is determined by the stoichiometry of the reaction, which is the quantitative relationship between the amounts of reactants and products in a chemical equation. The coefficients in a balanced chemical equation represent the mole ratios of the reactants and products in the reaction.

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Missing parts;

Read the following chemical equation.

Al + Cl2 → AlCl3

Which of the following fractions can be used for the mole ratio to determine the mass of Al from a known mass of AlCl3?

A. 2/1

B. 3/2

C. 2/2

D. 2/3

Answer:

lone pair of electrons form covalent bonds

Explanation:

To answer your question, we will need to utilize the given information and perform calculations using the provided terms, such as the IPA-cyclohexane mixture, countercurrent extraction unit, mass ratio, and ideal number of racks.

First, let's find the initial composition of the mixture:
- 40% IPA (isopropanol)
- 60% Cyclohexane

Now, using the given mass ratio of water to oil (5.25), we can calculate the amounts of water and oil in the feed. Since we don't have exact values for the amounts, let's assume there are 100 units of the mixture.

- Water: (5.25 * 100) / (5.25 + 1) ≈ 84.0 units
- Oil: 100 units

The countercurrent extraction unit uses water to extract the IPA from the mixture. The objective is to achieve a final raffinate containing 20% IPA.

To determine the ideal number of racks and the composition of the first extract, we would need the provided balance data figure, which is not available in the question. However, by following the steps below, you can determine the values using the balance data figure:

1. Locate the initial point on the balance data figure, corresponding to the 40% IPA composition in the mixture.
2. Draw a tie line connecting the initial point to the mass ratio line (5.25) on the figure.
3. Identify the intersection point of the tie line with the mass ratio line, which represents the composition of the first extract.
4. Calculate the number of ideal racks by drawing a series of tie lines and steps from the initial point towards the final raffinate point (20% IPA) on the balance data figure.

By following these steps and using the provided balance data figure, you can determine the ideal number of racks required for the countercurrent extraction unit and the composition of the first extract.

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Answer:Deep ocean currents (also known as Thermohaline Circulation) are caused by: ... The sinking and transport of large masses of cool water gives rise to the thermohaline circulation, which is driven by density gradients due to variations in temperature and salinity. The earth's rotation also influences deep ocean currents.

Explanation:

Answer:

element ; oxygen and iron

ionic compound ; cao ,fe2o3

molecular compound; N2H4

Answer:

the process by which green plants and some other organisms use sunlight to synthesize foods from carbon dioxide and water. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a byproduct.

Explanation: You can put this in your own words. How? Well, try to find the most important stuff in your own words and write it down.

Answer:

C. Burning wood

Explanation:

BURNING. Burning is a non-reversible chemical change. When you burn wood, the carbon in the wood reacts with oxygen in the air to create ash and smoke, and energy in the form of light and heat. This is a permanent change that cannot be undone – you cannot turn ashes back into wood.

The moles of Cl₂(g) will be present at equilibrium is 3.94 × 10⁻⁴ mol

To determine the number of moles of Cl₂(g) at equilibrium, we need to use the given equilibrium constant (Kₑ) and the initial concentrations of CO(g) and COCl₂(g).

Given:

[CO(g)] = 0.3500 mol

[COCl₂(g)] = 0.05500 mol

Kₑ = 1.2 × 10²

The balanced equation for the reaction is:

CO(g) + Cl₂(g) ⇌ COCl₂(g)

Let's denote the number of moles of Cl₂(g) at equilibrium as x. At the start, we have [Cl₂(g)] = 0 mol, but it will change by x at equilibrium.

Using the equilibrium expression, we can write:

Kₑ = [COCl₂(g)] / ([CO(g)] * [Cl₂(g)])

Plugging in the values:

1.2 × 10² = [COCl₂(g)] / (0.3500 * [Cl₂(g)])

To solve for [Cl₂(g)], we need to isolate it on one side of the equation:

[Cl₂(g)] = [COCl₂(g)] / (0.3500 * Kₑ)

Now, let's substitute the given values:

[Cl₂(g)] = 0.05500 / (0.3500 * 1.2 × 10²)

[Cl₂(g)] ≈ 3.94 × 10⁻⁴ mol

Therefore, approximately 3.94 × 10⁻⁴ moles of Cl₂(g) will be present at equilibrium.

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The question was Incomplete, Find the full content below:

Starting with 0.3500 mol CO(g) and 0.05500 mol COCl₂(g) in a 3.050-L flask at 668 K, how many moles of Cl₂(g) will be present at equilibrium

CO(g) + Cl₂(g) ⇄ COCl₂(g)  Ke 1.2 x 10^{2} at 668 K

The stoichiometry calculation involves the ratios of atoms within a compound, and ratios of substances in a chemical reaction.

The stoichiometry calculation involves the relationship between the product and the reactants in the chemical rection. stoichiometry is the measurement of the element. the steps follows the stoichiometry calculation is :

1) balance the chemical reaction.

2) convert the substance units to moles.

3) by using the moles ratio to calculate the yield of the substances in the reaction.

4) convert the moles of the needed elements to the required units.

The stoichiometry calculation is mostly based on the chemical formulas of the compound.

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Answer:

11

Explanation:

Answer:

billions

hope this helps :)

Answer:

If there are more products than reactants, that means the reaction has shifted towards the left, which is the backward direction. If there are more reactants than products, that means the reaction has shifted towards the right, which is the forward direction.

The mass of 63 ml sample : 79.38 g

Given

20 ml and 25.2 g of glycerol

Required

The mass of 63 ml sample

Solution

Density is the ratio of mass per unit volume

Density formula:

\(\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}\)

Density of glycerol :

= m : V

= 25.2 g : 20 ml

= 1.26 g/ml

Mass of 63 ml sample :

= density x volume

= 1.26 g/ml x 63 ml

= 79.38 g

Acetone has a concentration of 0.74 Mm.

Acetone is an organic chemical that is colorless, combustible, volatile, and has a distinctively strong odor. It is a solvent that is frequently used in a variety of commercial and domestic settings. It also serves as a starting point for the synthesis of other chemicals. Acetone has the chemical formula CH3COCH3 and a molecular weight of 58.08 g/mol.

We must first determine how many moles of acetone are present in the solution.

Per kilogram of solvent, one molal equals one mole of solute.

Since 1 kilogram is equivalent to 1000 milliliters of ethanol, it is possible to compute the number of moles of acetone as follows:

1000 mL/kg times 1.00 mol/kg is 1.00 mol.

The mass of acetone in the solution can then be determined using the molar mass of acetone (58.08 g/mol):

1 mole * 58.08 g/mol = 58.08 g

The volume of acetone can then be calculated by dividing the mass by the density:

58.08 g/0.788 g/mL equals 73.56 mL.

Finally, the molality of acetone can be determined as follows:

0.0074 mol/L (1.00 mol)/1.00 mol/(73.56 mL + 1000 mL) = 0.74 mM.

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Answer:

A.- maintaining a positive attitude

Explanation:

The answer is very obvious you need to maintain a positive attitude while studying.

Answer:

A: maintaining a positive attitude

Explanation:

I myself have personal experience with all of these, and B,C,D just don´t seem like reasonable answers. If you wait until the last minute to start an assignment, chances are you won´t get it done. Listening to the television while studing is a pretty bad idea because you might get distracted. Never study when tired because if you´re tired the information might not stick in your head. The only answer left is A.

Answer:

Potassium  

Explanation:

The mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

The half-life of a radioactive isotope is the amount of time it takes for one-half of the radioactive isotope to decay.

The half-life of a specific radioactive isotope is constant; it is unaffected by conditions and is independent of the initial amount of that isotope.

The number of half lives in 27 days;

n = 27 days/14 days

n = 1.929

The mass of P-32 remaining after 27 days, if the initial mass is 40g;

mass remaining = 40 g / (2^1.929)

mass remaining = 40 g / 3.808

mass remaining = 10.5 g

Thus, the mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

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