Answer:
I'm thinking Distillation
Explanation:
I'm not sure, but convection and conduction are insulators. It's between radiation and distillation if im not mistaking.
While charging the capacitor, as charge builds up onto the capacitor which of the following is true?
A. the electrostatic attraction resists the addition of more charges onto the capacitor
B. the electrostatic repulsion resists the addition of more charges onto the capacitor
C. the electrostatic repulsion increases the removal of more charges onto the capacitor
D. the electrostatic attraction increases the removal of more charges onto the capacitor
The electrostatic repulsion resists the addition of more charges onto the capacitor. A capacitor consists of two conductive plates separated by an insulating material, or dielectric.
When a voltage is applied across the plates, it causes an electric field to form between them. This electric field causes charges to accumulate on each plate, with one plate gaining a positive charge and the other gaining a negative charge. The voltage across the capacitor is directly proportional to the amount of charge stored on the plates.
It is also important to note that as charge builds up on the capacitor, the electrostatic potential energy stored in the electric field between the plates increases. This potential energy is proportional to the square of the voltage across the capacitor, and it represents the amount of work that could be done by the charges if they were allowed to flow through a circuit. When the capacitor is discharged, this potential energy is converted into kinetic energy as the charges flow through the circuit.
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Kieran ran 8 laps of the track in 18 minutes. Jevon ran 6 laps of the track. Who had a greater average speed
Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.
We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.
Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.
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Put the waves in order from shortest to longest wavelength
Answer:
b, a, c
Explanation:
The middle one has the shortest wavelength, then it's the top one and the last one has the longest wavelength.
Alejandro Kirk is the catcher for the Blue Jays’ baseball team. He exerts a forward force on the 0.145-kg baseball to bring it to rest from a speed of 38.2 m/s. During the process, his hand recoils a distance of 0.135 m.
Determine is the acceleration of the ball.
Determine the force applied by Alejandro.
The kinematics and Newton's second law allow to find the results for the questions about the motion of the ball are:
The acceleration is: a = 5.4 10³ m / s² The force is: F = 7.84 10² N
Given parameters
Mass of the ball m = 0.145 kg Ball starts speed vo = 38.2 m / s Setback distance x = 0.135 mTo find
Acceleration The force
Kinematics studies the movement of bodies, looking for relationships between the position, speed and acceleration of bodies.
v² = v₀² - 2 ax
Wher vo es la initial veloicity, a the acceleration y x is the distance,
When the ball stops the velocity is zero.
0 = v₀² - 2ax
a = \(\frac{v_o^2}{2x}\)
Let's calculate
a = \(\frac{38.2^2}{2 \ 0.135}\)
a = 5.4 10³ m / s²
Newton's second law establishes a relationship between force, mass, and acceleration of the body.
F = ma
F = 0.145 5.4 10³
F = 7.84 10² N
In conclusion using kinematics and Newton's second law we can find the results for the questions about the motion of the ball are:
The acceleration is: a = 5.4 10³ m / s² The force is: F = 7.84 10² N
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What’s the name of the muscle indicated on the image below?
1.Tricep
2.Oblique
3.Quadricep
4.Trapezius
Answer:
Oblique
Explanation:
I think that's the answer I was told this but forgot if this is the right answer if not then sorry
A musical note has a frequency of 512 Hz. If the wavelength of the note is 0.685 m, what is the speed of the sound of that note?
Answer:
350.72 m/s
Explanation:
Formula for velocity of wave is;
v = fλ
Where;
v is speed
f is frequency
λ is wavelength
We are given;
f = 512 Hz
λ = 0.685 m
Thus;
v = 512 × 0.685
v = 350.72 m/s
A cable car is being pulled up a mountain at 7.5 meters per second. Usually, the car takes 120 seconds to move all the way up the mountain. If its velocity stays constant, how much time will it take the cable car to move 39 meters?
Answer:
5.2 s
Explanation:
From the question given above, the following data were obtained:
Velocity = 7.5 m/s
Displacement = 39 m up
Time =?
The time taken for the cable cab to get to 39 m can be obtained as follow:
Velocity = Displacement / Time
7.5 = 39 / time
Cross multiply
7.5 × time = 39
Divide both side by 7.5
Time = 39 / 7.5
Time = 5.2 s
Thus, the time taken for the cable cab to get to 39 m up is 5.2 s
if you are told that a 20 kilogram object is raised by 10 meters, you know that?a the force of gravity on the object is 20 kilograms. b the mass of the object is 20 kilograms. с the force of gravity on the object is 10 meters. d the mass of the object is 10 meters. e the acceleration of the object is 200 kilogram-meters
The correct answer is (b) the mass of the object is 20 kilograms. When an object is raised to a certain height, work is done on the object against the force of gravity, and the object gains potential energy.
When a 20 kilogram object is raised by 10 meters, it gains gravitational potential energy, which is given by the formula:
Potential energy = mgh
where m is the mass of the object, g is the acceleration due to gravity, and h is the height that the object is raised.
Substituting the given values, we get:
Potential energy = (20 kg) x (9.81 m/s^2) x (10 m) = 1962 J
This means that 1962 J of work was done on the object against the force of gravity to raise it to a height of 10 meters. The force of gravity on the object remains constant at 20 kg (mass) x 9.81 m/s^2 (acceleration due to gravity) = 196.2 N, regardless of its height.
Since the object is lifted vertically and is at rest at the top of its ascent, no work is done against horizontal forces. Therefore, the force of gravity on the object remains constant at 20 kg (mass) x 9.81 m/s^2 (acceleration due to gravity) = 196.2 N.
Thus, the correct statement is that the mass of the object is 20 kilograms.
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A kid drives 4 miles to the mall. If the speed limit is 45 miles/hr and the kid makes the trip in .03 hours. Is the kid breaking the speed limit? a. No, he is going 1 mile/hr. b. Yes, he is going 133 miles/hr, C. No, he is going 40 miles/hr. d. Yes, he is going 150 miles/hr.
Answer:B
Explanation:
.03 of an hr is 2 mins and if it takes 2 mins to drive 4 miles enter it in pace calulator you are going 120mph so the closest to 120 is 133mph
The kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.
Speed is the ratio of distance travelled to time taken. It is given by:
Speed = distance / time
Since the distance to the mall is 4 miles, the time taken is 0.03 hours, hence the speed is:
Speed = distance / time
Speed = 4 miles / 0.03 hours
Speed = 133.3 miles/hr
Hence the kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.
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A duck is 12 m from the edge of a pond. A student stands in the middle of the pond
and creates ripples that travel past the duck and towards the edge of the pond. The
ripples are produced uniformly at 2 ripples per second. The student determines that
the ripples take 3.0 seconds after they pass the duck to reach the edge of the pond.
Determine the wavelength of the ripples.
Answer:
The wavelength is 2 meters
Explanation:
The relationship between the frequency, the speed and the wavelength is given by the relation;
v = f × λ
The given parameters are;
The distance of the duck from the edge of the pond = 12 m
The number of ripples produced per second = Frequency, f = 2 Hz
The time it takes the ripple to reach the edge of the pond after travelling past the duck = 3 seconds
Therefore, speed of the wave, v = Distance/time = 12 m/(3 s) = 4 m/s
The wavelength, λ, is therefore;
λ = v/f = (4 m/s)/(2 Hz) = 2 meters.
A very light rope is wrapped around a wheel of radius r and does not slip. The wheel is mounted with frictionless bearings on an axle through its center. A block of mass 20 kg is suspended from the end of the rope. When the system is released from rest it is observed that the block descends 10 meters in 3 seconds. What is the mass of the wheel?.
The mass of the wheel is 400/3s² divided by the square of the radius.
What is mass?Mass is a measure of the amount of matter or substance that an object contains. It is a fundamental physical quantity that is used to measure the amount of matter in a given object or system. It is measured in kilograms (kg) or grams (g). Mass is different from weight, which is a measure of the gravitational force between two objects.
At the start, all the energy is potential energy:
\(PE_{initial\) = mgh + Iω²/2
At the end, all the energy is kinetic energy:
\(KE_{final\) = mv²/2 + Iω²/2
Since the system is released from rest, we know that the initial angular velocity ω is 0, and the final velocity v is 10m/3s.
Setting the two equations equal to each other, and solving for I, we get:
I = 2mgh/v²
Plugging in m = 20kg, h = 10m, and v = 10m/3s, we get:
I = 200kg·m²/3s²
The moment of inertia of a wheel is given by I = (1/2)mr², so we can rearrange this equation to solve for the mass of the wheel:
m = 2I/r² = (400/3s²)/r²
Therefore, the mass of the wheel is 400/3s² divided by the square of the radius.
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As shown in the figure below, a squirrel is looking for nuts. It first runs rishtward 3 m and runs leftwards
another 10m to a second nut, and then runs 3 m leftward to a third nut. The total time spent running was
125
3 m
3 m
10 m
As shown in the figure below, a squirrel is looking for nuts. It first runs rightward 3 m and runs leftwards another 10 m to a second nut, and then runs 3 m leftward to a third nut. The total time spent running was 12 s.
Answer:
What is the squirrel's average velocity to reach the third nut?
Answer: =-0.83 m/s
What is the squirrel's average speed to reach the third nut?
Answer: 1.3 m/s
It first runs rightward 3 m and runs leftwards another 10 m to a second nut, and then runs 3 m leftward to a third nut. The total time spent running was 12 s.
What is speed?The average velocity required for squirrels is 0.83 m/s. The average speed required for squirrels is 1.3 m/s.
Speed, which is a scalar quantity, is the "speed at which an object is moving." The rate at which an object travels a distance can be thought of as its speed.
A fast-moving object travels at a high speed and completes a significant distance in a brief period of time. This is in contrast to an object travelling slowly, which travels a relatively short distance in the same length of time.
Therefore, It first runs rightward 3 m and runs leftwards another 10 m to a second nut, and then runs 3 m leftward to a third nut. The total time spent running was 12 s.
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We have an Atwood device, two blocks connect by a string strung over a pulley, but the twist this time is that both blocks are on perfectly smooth inclines. The upper block is on an incline 15 degrees to the horizontal and has a mass of 7kg. The lower block is on an incline of 65 degrees to the horizontal and has a mass of 11kg. Find the acceleration of the system?
The Acceleration of the system is 6.41 m/s².
Given,
α= 15°, m₁ = 7kg
β= 65°, m₂ = 11 kg
Let, a be the acceleration and T is the tensions at the end it's the cord.
Let, the mass m₂ be coming down along the inclined plane along the inclined surface towards downward m₂g sin β and the tension in the upward direction,
Resultant force, m₂a=m₂g sin β -T
11a=((11) ×g sin 65°) -T ...(i)
Now, considering the motion of m₁ which moves downwards, the forces are m₁g sinα, and T both are acting downwards.
Resultant force m₁a = m₁g sin α+T
7a =7g sin 15°+T ...(ii)
Solving both the equations by adding them,
18a=11gsin 65°+7g sin 15°-T+T
18a=11gsin 65°+7g sin 15°=115.45
a=115.45/18=6.41 m/s²
Hence, the Acceleration of the system is 6.41 m/s².
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A hollow metal sphere of radius 12.62 cm carries a charge of 1.58 uC. What is the electric field strength, E, in N/C on its surface
Given, radius of hollow metal sphere, r = 12.62 cmCharge on hollow metal sphere, q = 1.58 μC = 1.58 × 10⁻⁶ CWe need to find out the electric field strength E at the surface of the hollow metal sphere.
Using Gauss's law, the electric field outside a charged hollow sphere is same as that due to point charge placed at center of sphere and is given asE = kq / r²Where,E = Electric field strengthk = Coulomb's constant = 9 × 10^9 Nm^2C^-2q = Charge on sphere at center of the spherer = Radius of the hollow metal sphere
Therefore, electric field strength at the surface of hollow metal sphere isE = (9 × 10^9 × 1.58 × 10⁻⁶) / (12.62 × 10⁻²)²= 141628.7 N/C≈ 1.4 × 10⁵ N/CTherefore, the main answer is the electric field strength, E, in N/C on the surface of the hollow metal sphere is approximately 1.4 × 10⁵ N/C.
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a soil has a bulk density of 1.38 g/cm3. calculate the pounds (lbs) of dry soil in the top 6 inches of an acre of this soil. (454 g = 1 lb; 30.48 cm = 1 ft; 1 acre = 4,3560ft2)
There are 188,487.68 lbs of dry soil in the top 6 inches of an acre of this soil.
How to calculate dry soilTo calculate the pounds of dry soil in the top 6 inches of an acre of this soil, we can use the following steps:
1. Convert the bulk density of the soil from g/cm3 to lbs/ft3: 1.38 g/cm3 * (454 g / 1 lb) * (1 ft / 30.48 cm)3 = 86.56 lbs/ft3
2. Convert the depth of the soil from inches to feet:
6 inches * (1 ft / 12 inches) = 0.5 ft
3. Calculate the volume of the soil in the top 6 inches of an acre:
0.5 ft * 1 acre * (4,3560 ft2 / 1 acre) = 2,178 ft3
4. Calculate the pounds of dry soil in the top 6 inches of an acre: 86.56 lbs/ft3 * 2,178 ft3 = 188,487.68 lbs
Therefore, there are 188,487.68 lbs of dry soil in the top 6 inches of an acre of this soil.
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Imagine a player throwing a football. Explain the action of what is happening to the hand and ball, as well as describe the action force and the reaction force
Answer:
Explanation:
When a player throws a football , he applies force on the ball , due to which ball accelerates in forward direction . This is the action force .
The ball also applies a force on the hand of the player . Due to it the player experiences a pushing force in backward direction . This is reaction force .
Due to this force , the player does not move in backward direction because of frictional force of the ground . The frictional force keeps him stationary .
16. Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10^24 kg, the mass of Jupiter is 1898.6 x 10^24 kg and the closest distance is abou
The gravitational force of attraction between the Earth and Jupiter is approximately 1.32 x 10²⁸ N.
The gravitational force of attraction between two objects can be calculated using Newton's law of universal gravitation, which states that the force (F) is proportional to the product of their masses (m₁ and m₂) and inversely proportional to the square of the distance (r) between their centers. Mathematically, the formula is expressed as:
F = (G * m₁ * m₂) / r²
where G is the gravitational constant.
m₁ = 6 x 10²⁴ kg (mass of Earth)
m₂ = 1898.6 x 10²⁴ kg (mass of Jupiter)
r = 5.88 x 10¹¹ m (distance between Earth and Jupiter)
Plugging in the values into the formula, we have:
F = (6.67 x 10⁻¹¹ N m²/kg²) * (6 x 10²⁴ kg) * (1898.6 x 10²⁴ kg) / (5.88 x 10¹¹ m)²
Calculating the expression, we find:
F ≈ 1.32 x 10²⁸ N
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THE COMPLETE QUESTION IS:
Determine the gravitational force of attraction between the Earth and Jupiter given the mass of the earth is 6 x 10²⁴ kg the mass of Jupiter is 1898.6 x 10²⁴ kg and the closest distance is about 5.88 x 10¹¹
The lengths of the Mercury thread in a thermometer at 30。C and 0。C are 6.0cm and 2.5cm respectively.What is the length of the Mercury thread when the thermometer is placed in pure boiling water at a pressure at 1 atmosphere.
Answer:
C yes susialoas
Explanation:
Yes they c is bkookkkakaksk
What is the total distance, side to side, that the top of the building moves during such an oscillation
The total side to side distance at the top of the building, covered during such an oscillation is 8.4 cm.
Solution:
The height of building is, h = 152 m.
The frequency on windy days is, f = 0.17 Hz.
The acceleration on the top of building is, a = 2/100g (Here g is gravitational acceleration).
\(a = A \times \omega ^{2}\)
\(a = A \times (2\pi f) ^{2}\)
\(\frac{2}{100} \times g = A \times (2\pi \times 0.17) ^ 2\)
A = 0.042m
hence the total distance is twice the distance
that is 0.084m
What is oscillation?The recurrent or periodic change of a quantity around a central value (often an equilibrium point) or between two or more different states is known as oscillation.Alternating current and a swinging pendulum are two common examples of oscillation. Physics can employ oscillations to approximate complicated interactions, like those between atoms.To learn more about Oscillation with the given link
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Question:
The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.17 Hz, and the acceleration of the top of the building can reach 2.0% of the free-fall acceleration, enough to cause discomfort for occupants. What is the total distance, side to side, that the top of the building moves during such an oscillation?
A roller coaster is traveling at 80m/hr until the emergency breaks turn on, causing it to come to a complete stop in 10s. What is the acceleration of the roller coaster?
This means that the roller coaster is decelerating at a rate of 8m/s² until it comes to a complete stop.
What is decelerating?Decelerating is the process of slowing down or decreasing the speed of a vehicle, person, or object. It is the opposite of accelerating, which is the process of increasing speed. Deceleration can be caused by the force of friction from the road or other surfaces, or by reducing the amount of engine power or braking. Deceleration is necessary to safely slow down and stop a vehicle and to negotiate turns or curves in the road.
The acceleration of the roller coaster can be calculated using the equation
a = (Vf - Vi)/t, where Vf is the final velocity, Vi is the initial velocity, and t is the time taken for the change in velocity to occur.
In this case, Vf = 0m/hr, Vi = 80m/hr, and t = 10s.
Therefore, the acceleration of the roller coaster is -8m/s².
This means that the roller coaster is decelerating at a rate of 8m/s² until it comes to a complete stop.
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One Newton is equivalent to
A. 1 kg/s2
B. 1 kg*m/s
C. 1 kg*m/s2
D. 1 kg/s
Answer:
B
Explanation:
2. How are electromagnets different from other magnets?
The electric field 0.385 m from a very long uniform line of charge is 810 N/C
How much charge is contained in a section of the line of length 2.50 cm?
The charge contained in a section of the line of length 2.50 cm is 8.87 × 10⁻¹⁰ C.
The formula for electric field intensity of a line charge is given by:E= λ/2πε₀rwhere,λ is the linear charge density of the line.ε₀ is the permittivity of free space.r is the perpendicular distance of the point from the line charge.
Electric field intensity, E = 810 N/CandDistance, r = 0.385 mUsing the above formula, we can find the value of linear charge density of the line.λ = 2πε₀Erλ = 2 × π × 8.85 × 10⁻¹² × 810 × 0.385λ = 3.55 × 10⁻⁸ C/mLength of the section of the line, L = 2.5 cm = 0.025 mWe need to find the charge present in a section of the line of length 2.50 cm.Since the linear charge density of the line is 3.55 × 10⁻⁸ C/m,Charge in a section of the line of length 0.025 m = λLq = λLq = 3.55 × 10⁻⁸ × 0.025q = 8.87 × 10⁻¹⁰ C
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the video discusses four potential models of how the expansion of the universe changes with time. drag the correct model description from the left-hand column to the appropriate blank in the sentences in the right-hand column.
There are 4 potential models of how the expansion of the universe changes with time. The correct model description to fill in the blanks is as follows:
“Only the coasting model” --> sentence (1).“All four models” --> sentence (2).“Only the recollapsing model” --> sentence (3).“Only the critical model” --> sentence (4).“Only the accelerating model” --> sentence (5).What are the 4 potential models of universe expansion?Since the beginning of the Big Bang, scientists believe the universe always expands. Every element of a galaxy slowly moves away from each other. There are 4 potential models for how the universe changes with time, which:
The coasting model stated the universe expands at a constant rate.The recollapsing model stated the galaxies would begin to get closer at some point.The critical model stated the universe expands in equilibrium.The accelerating model stated the universe expands faster compared to the beginning.This question is incomplete. The complete query to this question is as follows:
“All four modelsOnly the accelerating modelOnly the coasting modelOnly the critical modelOnly the recollapsing model”Meanwhile, the blank sentences are as follows:
“(1) _____ assumes(s) that the expansion rate of the universe always stays the same.(2) _____ predict(s) that the universe is expanding today.(3) _____ predict(s) that the universe will someday contract.(4) _____ predict(s) that the average universe's mass density is exactly the critical density.(5) _____ predict(s) that the universe is expanding faster now than it was in the distant past.”Learn more about the universe here https://brainly.com/question/29576511
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What is an alpha particle?
a complete helium atom
a complete helium atom, ,
the nucleus of a beta particle
the nucleus of a beta particle
a rogue valence electron
, , a rogue valence electron
two protons and two neutrons
Answer:
two protons and two neutrons
it's the answer. hope it helps
Alpha particles have two protons and two neutrons. Therefore, option (D) is correct.
What is an alpha particle?Alpha particles can be defined as positively charged particles released from the decay of several radioactive materials. The mass of the Alpha particle is because of the presence of two protons and two neutrons. Therefore, the Alpha particles nucleus is very similar to the nucleus of the Helium atom and are denoted by the Greek alphabet α.
An alpha particle or ray is also known as doubly ionized helium nuclei (He²⁺). The alpha particle's mass is equal to 6.64 × 10⁻²⁷ Kg. Alpha particles are generally generated during the standard radioactive decay of atomic nuclei.
Alpha particles contains the kinetic energy of 5MeV and a speed of 5 % of that of the speed of light. They are also formed in high-energy particle accelerators and are highly ionized particles with low penetration depth compared to other particles.
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Label the tectonic plates
The Labels for the tectonic plates are;
1. Juan de Fuca 2. Rivera 3. Cocos 4. Caribbean 5. North Andean 6. Panama 7. 8. Easter 9. Juan Fernández 10. Scotia 11. South Shetland 12. South Sandwich 13. Aegean 14. Anatolian 15. Indian 16. Burmese 17. Amur 18. Okhotsk 19. Yangtze 20 Philippine 21. Mariana 22. Okinawa 23. North Bismarck 24. Molucca 25. Banda 26. Timor 27. Bird's Head 28. Woodlark 29. South Bismarck 30. New Hebrides 31. Balmoral Reef 32. Conway Reef
What are tectonic plates?
Tectonic plates are large, solid pieces of Earth's outermost layer, that move and interact with each other. These plates can be oceanic or continental.
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A woodpecker’s brain is specially protected from large decelerations by tendon-like attachments inside the skull. While pecking on a tree, the woodpecker’s head comes to a stop from an initial velocity of 0.600 m/s in a distance of only 2.00 mm. (a) Find the acceleration in m/s2 and in multiples of g(g=9.80m/s2). (b) Calculate the stopping time. (c) The tendons cradling the brain stretch, making its stopping distance 4.50 mm (greater than the head and, hence, less deceleration of the brain). What is the brain’s deceleration, expressed in multiples of g?
Answers:
(a) a = -90 m/s² or 9.18g
(b) t = 0.00667 s
(c) a = -40 m/s² or 4.08g
Explanation:
When the acceleration is constant, we can use the following equation:
\(x=\frac{1}{2}(v_0+v_f)t\)Where x is the distance, v0 is the initial velocity, vf is the final velocity and t is the time. So, replacing x by 2 mm (0.002 m), v0 by 0.6 m/s, and vf by 0 m/s, we can solve for t as:
\(\begin{gathered} 0.002=\frac{1}{2}(0.6+0)t \\ 0.002=\frac{1}{2}0.6t \\ 0.002=0.3t \\ \frac{0.002}{0.3}=\frac{0.3t}{0.3} \\ 0.00667\text{ = t} \end{gathered}\)Therefore, the stopping time is 0.00667 s.
With this time we can calculate the acceleration using the following equation:
\(a=\frac{v_f-v_0}{t}=\frac{0m/s-0.6m/s}{0.00667s}=-90m/s^2\)Then, to know the acceleration as a multiple of g, we need to divide 90 m/s² by 9.8 m/s² to get:
\(\frac{90}{9.8}=9.18\)So, 90 m/s² is equivalent to 9.18g
In the same way, we can calculate the acceleration when the distance is 4.5 mm (0.0045 m). So, the stopping time is equal to:
\(\begin{gathered} 0.0045=\frac{1}{2}(0.6+0)t \\ 0.0045=0.3t \\ \frac{0.0045}{0.3}=\frac{0.3t}{0.3} \\ 0.015\text{ s = t} \end{gathered}\)Then, the acceleration is equal to:
\(a=\frac{v_f-v_0}{t}=\frac{0\text{ m/s - 0.6 m/s}}{0.015\text{ s}}=-40m/s^2\)Since 40/9.8 = 4.08g, we can say that -40m/s² is equivalent to 4.08g.
The kettle is filled with 5.0 kg of water at 20 °C. The specific heat capacity of water = 4 200 J/Kg °C. Calculate the energy needed to raise the temperature of the water to 100 °C. Give your answer to 2 s.F.
Answer:
17 * 10^5 J
Explanation:
From;
H= mcΘ
where;
m = mass of water = 5.0 Kg
c = heat capacity of water = 4 200 J/Kg °C
Θ = temperature rise = 100 °C - 20 °C = 80°C
Substituting values;
H = 5 * 4 200 * 80
H = 17 * 10^5 J
Lucy took 3 hours to cover 2/3 of a journey. She covered the
remaining 60 miles in 2 hours. What was the average speed
for the whole journey?
mph
Deleted this answer, sorry for any inconveniences that it may have caused.
PLEASE HELP!! WILL MARK THE BRAINLIEST! HIGH SCHOOL PHYSICAL SCIENCE
Using what you know about the periodic table, list some patterns that organize the elements in terms of atomic number, atomic mass and valence electrons? What do the periods (horizontal rows) and groups (vertical columns) of the periodic table indicate to us about the elements that are categorized within them?
Answer:
Periods indicate that a new period at a new principal energy level which is filled with electrons. Groups indicate that the elements share similar properties because their shells are filled with the same number of valence electons.
Explanation:
e see that starting at period 2 Li has a +1 charge , He has +2 charge, B has +3 charge, C has the potential to have a +4 charge or -4 charge (because it can gain or loose electrons) and N has a -3 charge, etc. Groups however, have similar properties and every element in a 1A - 8A has the same number of valence electrons. All except the noble gases in which He only needs 2 electrons to be in a perfect state. This is its octet as it would be a completely different element if it had more than 2 electrons in its shell. An example of the groups sharing similar properties is if we were to look at group 1A. In group 1A we find H, Na, K, etc. These are all highly unstable elements when alone (not in a compound) and they are very reactive. If you were to put Na for instance in water, it would light up and you'd see a flame sitting on top of the water. A scientist could do that with the rest of the elements in the group and they would see this increasing in reactivity as you go down the periods. Francium isn't visible long enough to be able to see this happen though. It's more of that kind of element that scientists prove that it exists, but not a very common element to get to learn much about.